Convert 0.25rev to degree

Answers

Answer 1

Answer: To convert 0.25 revolutions to degrees, we can use the conversion factor that 1 revolution is equal to 360 degrees.

So, 0.25 revolutions is equivalent to:

0.25 revolutions * 360 degrees/revolution = 90 degrees.

Therefore, 0.25 revolutions is equal to 90 degrees.


Related Questions

Alois is an astronomer. He is trying to find evidence that a galaxy has a supermassive black hole at its center. What should he look for?.

Answers

Scientists can search for numerous signs of a supermassive black hole at the heart of a galaxy. Here are a few of the typical techniques astronomers employ to research supermassive black holes:

What is the supermassive black hole?

The gravitational pull of it revealed it to be dense and unmoving. There is a supermassive black hole in the centre of the Milky Way, and this was the first proof of it.

Astronomers can monitor the motion of stars close to a galaxy's centre. Supermassive black holes are most likely located at the core of an invisible entity that has a very strong gravitational attraction and the stars are orbiting it.

A supermassive black hole's gravitational pull can cause it to bend the path of light around it if it is situated between Earth and a faraway light source.

This phenomenon is known as gravitational lensing. Astronomers may see this “lensing” phenomenon and utilize it to investigate the black hole.

Therefore, Astronomers may create a thorough picture of the characteristics of a supermassive black hole at the heart of a galaxy by examining these and other observational data.

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(Plzzzz help!!!) (50 points!!!)
1. Write the following quantities in scientific notation:
(1) 10130 Pa to 2 decimal places
(2) 978,15 m·s−2
to one decimal place
(3) 0,000001256 A to 3 decimal places

Answers

Answer:

YEAH THE PERSON ABOVE ME IS RIGHT MARK

THEM BRAINLIST

A charge of 3.947 nC is moved from a position on the y axis of 8.216 cm to a position on the x axis of 2.848 cm while there is a charge 35.083 nC located at the origin. How much work in micro-Joules did it take to move the charge?

Answers

Given:

The charge on the Y-axis is,

\(\begin{gathered} q_1=3.947\text{ nC} \\ =3.947\times10^{-9}\text{ C} \end{gathered}\)

The initial position of the charge is,

\(\begin{gathered} y=8.216\text{ cm} \\ =0.08216\text{ m} \end{gathered}\)

The final position of the charge is,

\(\begin{gathered} x=2.848\text{ cm} \\ =0.02848\text{ m} \end{gathered}\)

The charge at the origin is,

\(\begin{gathered} q_2=35.083\text{ nC} \\ =35.083\times10^{-9}\text{ C} \end{gathered}\)

To find:

The work to move the charge

Explanation:

The potential at the first point is,

\(\begin{gathered} V_1=\frac{kq_2}{y} \\ k=9\times10^9\text{ N.m}^2.C^{-2} \end{gathered}\)

The potential at the final point is,

\(V_2=\frac{kq_2}{x}\)

The work in this process is,

\(\begin{gathered} W=q_1(V_2-V_1) \\ =kq_1q_2(\frac{1}{x}-\frac{1}{y}) \\ =9\times10^9\times3.947\times10^{-9}\times35.083\times10^{-9}(\frac{1}{0.02848}-\frac{1}{0.08216}) \\ =2.86\times10^{-5} \\ =28.6\times10^{-6}\text{ J} \\ =28.6\text{ }\mu J \end{gathered}\)

Hence, the work is,

\(28.6\text{ }\mu J\)

Which of the following does not affect gas pressure

Answers

Answer:

I NEED OPTIONS

Explanation:

______________________________

A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. Determine The Depth of The Water Well.

N.B. The Correct Answer Will Receive 30 Points & The Brainliest Title.
______________________________​

Answers

A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. then The Depth of The Water Well is 56.6 m.

In terms of physics, sound is a vibration that travels through a transmission medium like a gas, liquid, or solid as an acoustic wave. Sound is the receipt of these waves and the brain's perception of them in terms of human physiology and psychology. Only acoustic waves with frequencies between about 20 Hz and 20 kHz, or the audio frequency range, may cause a human to have an auditory sensation. These correspond to sound waves in air with an atmospheric pressure of 17 metres (56 ft) to 1.7 centimetres (0.67 in) in wavelength. Ultrasounds are sound waves with a frequency higher than 20 kHz that are inaudible to humans. Infrasound refers to sound frequencies below 20 Hz. Animals of different species have different hearing ranges. Acceleration of the stone is 9.8 m/s²

according to kinematics,

s = ut + 1/2 at²

s =  1/2 ×9.8×3.4²

s = 56.6 m

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Definition of continental polar

Answers

cold, dry, and stable air masses .

how many stars are in our solar system?

Answers

Answer:

there are over 100 billion stars in our galaxy.

A ball is launched into the air at an angle of 32ᵒ with an initial speed of 18 m/s. Neglecting air resistance, determine how high the ball will go, how long it will be in the air, and how far it will travel.

Hiii Can somebody take their precious time to answer this question? ​

Answers

Answer:

557

A ball is launched into the air at an angle of 32ᵒ with an initial speed of 18 m/s. Neglecting air resistance, determine how high the ball will go, how long it will be in the air, and how far it will travel.

Hiii Can somebody take their precious time to answer this question?

Which direction do longitudinal waves travel?

Answers

Answer:

If the particles of the medium vibrate in a direction parallel to the direction of propagation of the wave, it is called a longitudinal wave. In longitudinal waves, the particle movement is parallel to the direction of wave propagation.

Explanation:

What energy conversions take place during these activities?
Riding uphill, the boy's work is converted into magnetic energy, riding on level ground, his work is converted into thermal energy
A
B
Riding uphill the boy's work is converted into thermal energy, riding on level ground, his work is converted into potential energy
c С
Riding uphill, the boy's work is converted into potential energy, riding on level ground, his work is converted into kinetic energy
D
Riding uphill, the boy's work is converted into kinetic energy, riding on level ground, his work is converted into magnetic energy

Answers

I'm pretty sure your answer should be

C. Riding uphill, the boy's work is converted into potential energy, riding on level ground, his work is converted into kinetic energy.

Steelhead trout migrate upriver to spawn. Occasionally they need to leap up small waterfalls to continue their journey. Fortunately, steelhead are remarkable jumpers, capable of leaving the water at a speed of 8.0 m/s. What is the maximum height that a steelhead can jump

Answers

Answer:

s = 3.26 m

Explanation:

Given that,

Water leaves at a speed of 8 m/s

We need to find the maximum height that steelhead can jump. Let it can jump to a height of h.

At maximum height, final speed is equal to 0. We can use third equation of motion to find the maximum height.

\(v^2-u^2=2as\)

a = -g

\(-u^2=-2gs\\\\s=\dfrac{u^2}{2g}\\\\s=\dfrac{(8)^2}{2\times 9.8}\\\\=3.26\ m\)

Hence, the maximum height is 3.26 m.

While an object is in projectile motion (with upward being positive) with no air resistance ct is in projectile motion (with upward being positive) with no air resistance, Group of answer choices the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g. the vertical component of its velocity remains constant and the vertical component of its acceleration is equal to -g the horizontal component of its velocity remains constant and the horizontal component of its acceleration is equal to -g the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to zero. the vertical component of both its velocity and its acceleration remain constant.

Answers

Answer:

The horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g.

Explanation:

This is because, the projectile has both vertical and horizontal components of velocity. But, its vertical component of velocity changes as the object moves whereas, its horizontal component of velocity remains constant.

Also, the projectile has only vertical component of acceleration and no horizontal component of acceleration since, its horizontal component of velocity remains constant. Thus, no change in the horizontal component of velocity.

The vertical component of acceleration is equal to -g since, the weight is the only vertical force acting on it.

So, the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g.

What is the force of a 1500 kg car accelerating at 45 m/s2 ?

Answers

Answer:

67500

Explanation:

F=ma

F = 1500 × 45

F = 67500

Highschool Physics
1. The driver of a car traveling at 9.0m/s is honking their horn. The horn has a frequency of 625 Hz. If the car is moving toward a person waiting at the crosswalk, what frequency of the horn does the person hear?
2. As the same car from question#1 passes the person, what frequency of the horn does the person hear as the car moves away from them?

Answers

The person waiting at the crosswalk hears a frequency of 609 Hz.As the car moves away from the person, they would still hear a frequency of 609 Hz.

Doppler effect

Using the formula for the Doppler effect:

f' = (v + vr) / (v + vs) * f

Given:

Source frequency (horn): f = 625 Hz

Speed of sound: v = 343 m/s (approximate value at room temperature)

The velocity of the receiver, vr, is zero because the person waiting at the crosswalk is stationary.

The velocity of the source, vs, is the speed of the car, which is given as 9.0 m/s.

Thus:

f' = (v + vr) / (v + vs) * f

= (343 m/s + 0) / (343 m/s + 9.0 m/s) * 625 Hz

= (343 m/s) / (352 m/s) * 625 Hz

≈ 609 Hz

Therefore, the person waiting at the crosswalk hears a frequency of approximately 609 Hz.

(2)Using the same Doppler effect formula:

f' = (v - vr) / (v - vs) * f

In this case, the velocity of the receiver, vr, is still zero because the person remains stationary.

The velocity of the source, vs, is now negative, indicating that the car is moving away from the person.

Thus:

f' = (v - vr) / (v - vs) * f

= (343 m/s + 0) / (343 m/s - (-9.0 m/s)) * 625 Hz

= (343 m/s) / (352 m/s) * 625 Hz

≈ 609 Hz

In other words, as the car moves away from the person, they would still hear a frequency of approximately 609 Hz.

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Giúp em câu này với ạ,em cảm ơn

Gip em cu ny vi ,em cm n

Answers

Ảnh lỗi hả bạn ơi, gửi lại ảnh đi

A car transports its passengers between 3 buildings. It moves from the first building to the second building, 4.76km away, in a direction 37° north of east. It then moves from second building to the third building in a direction 69° west of north. Finally, it returns to the first building, sailing in a direction 28° east of south. Calculate the distance between (a) the second and third buildings and (b) the first and third buildings.​

Answers

Answer:

1) a = 6.14 km

2) b = 4.69 km

Explanation:

Let the first building be A, second building be B and third building be C.

Now, bearing of A = 4.76 km in a direction 37° north of east

Bearing of B = 69° west of north

Bearing of C = 28° east of south

Thus if this 3 points form a triangle, we will have the following angles;

Angle at point A = 28 + (90 - 37) = 81°

Angle at point B = 28 + (90 - 69) = 49°

Angle at point C = 180 - (81 + 49) = 50°

Now, the distance between second and third building is "a" which is represented by BC in the triangle attached while the given distance of 4.76 represents side AB. Thus;

Using sine rule, we can find "a".

a/sin 81 = 4.76/sin 50

a = 6.14 km

B) distance between first and third building is AB in the triangle depicted by "b".

Similar to the first problem, we will use sine rule again.

b/sin49 = 4.76/sin 50

b = 4.69 km

A car transports its passengers between 3 buildings. It moves from the first building to the second building,

Jaime observes a bird sitting in a tree. Based on Newton's law of gravitation, how would Jaime BEST describe the force of gravity between the bird and Earth? A. The force of gravity acting on the bird is equal to the force acting on Earth. B. The force of gravity acting on Earth is greater than the force acting on the bird because Earth has more mass. C. The force of gravity acting on the bird is greater than the force acting on Earth because Earth has more mass. D. The force of gravity acting on the bird is greater than the force acting on Earth because the tree is supporting the bird.

Answers

Answer:

ofooffgggq

i am not

Explanation:

eeffffgggggg

Do field forces exist in nature?

Answers

Answer:

Yes, field forces exist in nature.

Explanation:

A field force is a force experience due to an interaction with fields. In this case, a contact is not required before the force can be felt.

The three major field forces are: magnetic field, electric field and gravitational field. The magnetic fields are produced due to the interaction between the north and south poles of a magnet, the electric field is one from charges, while gravitational field is a force of attraction due to gravity on the earth. All these fields occur in nature, therefore making field forces to exist in nature.

The corect phase sequence shown
Gas, Liguid, Solid
Lqud, Gas, Solid
Sold, Liguid, Gas
Gas, Solid, Liquid
above i

Answers

Answer:

Explanation:

gas, liquid, soild

liquid, Gas, solid

Gas, Solid, liquid

!GIVING BRAINLIST!


Calcium carbonate (CaCO3) is a white solid with no odor. When CaCO3 is heated, the resulting substances are calcium oxide (CaO) and carbon dioxide (CO2). CaO is a white to gray solid with no odor, and CO2 is a gas with no odor and color.


Which statement describes CaCO3?


A) It is a diatomic molecule that can’t be broken down by physical means.

B) It is a diatomic molecule that can’t be broken down by chemical means.

C) It is a compound that can be broken down by physical means.

D) It is a compound that can be broken down by chemical means.

Answers

Calcium carbonate is a compound that can be broken down by chemical means.

The given compounds;

reactant = CaCO₃

product = CaO + CO₂

In a chemical reaction called thermal decomposition, lime stone also known as calcium carbonate can be broken down when heat is applied to it. It is a chemical process because new substances such as quick lime (calcium oxide) and carbon iv oxide will be formed.

The overall reaction is given as;

CaCO₃  → CaO + CO₂

Thus, we can conclude that calcium carbonate is a compound that can be broken down by chemical means.

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Answer:

it's d (it is a compound that can be broken down by chemical means.)

Explanation:

right on edge

When dots are placed on a page from a laser printer, they must be close enough so that you do not see the individual dots of ink. To do this, the separation of the dots must be less than Raleigh's criterion. Take the pupil of the eye to be 3.2 mm and the distance from the paper to the eye of 42 cm; find the maximum separation (in cm) of two dots such that they cannot be resolved. (Assume the average wavelength of visible light is 550 nm.)

Answers

Answer:

 y <8 10⁻⁶ m

Explanation:

For this exercise, they indicate that we use the Raleigh criterion that establishes that two luminous objects are separated when the maximum diffraction of one of them coincides with the first minimum of the other.

 Therefore the diffraction equation for slits with m = 1 remains

             a sin θ = λ

in general these experiments occur for oblique angles so

             sin θ = θ

             θ = λ / a

in the case of circular openings we must use polar coordinates to solve the problem, the solution includes a numerical constant

           θ = 1.22 λ / a

The angles in these measurements are taken in radians, therefore

          θ = s / R

as the angle is small the arc approaches the distance s = y

          y / R = 1.22 λ / s

          y = 1.22 λ R / a

let's calculate

            y = 1.22 500 10⁻⁹ 0.42 / 0.032

            y = 8 10⁻⁶ m

with this separation the points are resolved according to the Raleigh criterion, so that it is not resolved (separated)

                 y <8 10⁻⁶ m

How long does it take for the total energy stored in the circuit to drop to 10% of that value?

Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.

Answers

The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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You are designing a flywheel. It is to start from rest and then rotate with a constant angular acceleration of 0.200 rev/s^2. The design specifications call for it to have a rotational kinetic energy of 330 J after it has turned through 30.0 revolutions.

What should be the moment of inertia of the flywheel about its rotation axis?
Express your answer with the appropriate units.

Answers

Answer: 1.14 kg*m/s

Explanation:

The first person explained everything right, they just forgot to convert the angular acceleration to rads/sec^2 from revs/sec^2. Once that is converted, your answer should come out right.

Another small thing, the answer there has an extra unnecessary step. It tells you to find the square root of w^2 to find w but that is unnecessary since the final equation asked for w^2. Hope this helps! :)

The moment of inertia I of the flywheel about its rotation axis is

\(1.39Kgm^2\)

Given

Angular displacement,

\(\theta = 30rev \\\\\theta = (30) * 2\pi rad \\\\\theta = 188.495rad\)

Therefore, Final angular velocity (w) will be:

\(w^2 = 2\alpha\theta\\\\w^2 = 2 * (0.200 * 2\pi) * (188.49)\\\\w^2 = 473.73\\\\w = 21.76 rad/s\)

Therefore,

moment of inertia

\(I = 2 * K / w^2\)

\(I = 2 * 330 / 473.73\)

\(I = 1.39kgm^2\)

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Problem
THE FLIGHT OF A BALL A ball is launched at 5.5 m/s at 76° above
the horizontal. It starts and lands at the same distance from the
ground. What are the maximum height above its launch level and the
flight time of the ball?

Answers

1. The maximum height above its launch level is 1.45 m

2. The time of flight of the ball is 1.1 s

1. How do I determine the maximum height?

From the question given above, the following data were obtained:

Initial velocity (u) = 5.5 m/sAngle of projection (θ) = 76 °Acceleration due to gravity (g) = 9.8 m/s²Maximum height (H) =?

The maximum height can be obatianed as follow:

H = u²Sine²θ / 2g

H = [5.5² × (Sine 76)²] / (2 × 9.8)

Maximum height = 1.45 m

How do I determine the time of flight?

The time of flight of the ball can be obtained as follow:

Initial velocity (u) = 5.5 m/sAngle of projection (θ) = 76 °Acceleration due to gravity (g) = 9.8 m/s²Time of flight (T) = ?

T = 2uSineθ / g

T = [2 × 5.5 × Sine 76] / 9.8

Time of flight = 1.1 s

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As the distance between the sun and earth decreases, the gravity force between them

a
Increases
b
decreases
c
stays the same

Answers

Answer:

a increases

Explanation:

as distance between two objects increases the gravitational force decreases so when distance decreases the gravitational force increases

What is the strength of the electric field at the position indicated by the dot in (Figure 1)?

What is the direction of the electric field at the position indicated by the dot in (Figure 1)? Specify the direction as an angle measured clockwise from the positive x
axis.

What is the strength of the electric field at the position indicated by the dot in (Figure 1)?What is

Answers

At the point indicated by the dot, the electric field vector would be at an angle of 45 degrees measured clockwise from the positive x-axis, since the x and y components of the electric field are equal at that point.

Assuming that the two charges are of equal magnitude and opposite sign and that the distance between them is d, the electric field at the point indicated by the dot can be found using Coulomb's law:

\(E = kq/r^2\)

where k is Coulomb's constant (\(8.99 *10^9 N m^2/C^2\)), q is the magnitude of the charge, and r is the distance between the charges.

Since the charges are of equal magnitude, the net charge at the point indicated by the dot is zero, so we only need to consider the electric field due to one of the charges. Let's assume that we want to find the electric field due to the positive charge.

The distance between the positive charge and the point indicated by the dot is r = d/2. Therefore, the electric field at that point is:

\(E = kq/(d/2)^2 = 4kq/d^2\)

The direction of the electric field is radial, pointing away from the positive charge and toward the negative charge. At the point indicated by the dot, the electric field vector would be at an angle of 45 degrees measured clockwise from the positive x-axis, since the x and y components of the electric field are equal at that point.

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suppose its initial speed of the block is 1.39 m/s but its mass can be varied what mass is required to give the maximum spring compression of 3.55 cm

suppose its initial speed of the block is 1.39 m/s but its mass can be varied what mass is required to

Answers

Answer:

m = 0.623 kg

Explanation:

By the conservation of energy, we can write the following equation

\(\begin{gathered} E_i=E_f \\ KE=PE \\ \frac{1}{2}mv^2=\frac{1}{2}kx^2 \end{gathered}\)

Where m is the mass, v is the speed, k is the constant of the spring and x is the compression.

Solving the equation for m, we get

\(\begin{gathered} 2^\cdot\frac{1}{2}mv^2=2\cdot\frac{1}{2}kx^2 \\ \\ mv^2=kx^2 \\ \\ m=\frac{kx^2}{v^2} \end{gathered}\)

Now, we can replace k = 955 N/m, x = 3.5 cm = 0.0355 m, and v = 1.39 m/s to get

\(\begin{gathered} m=\frac{(955\text{ N/m\rparen\lparen0.0355 m\rparen}^2}{(1.39\text{ m/s\rparen}^2} \\ \\ m=0.623\text{ kg} \end{gathered}\)

Therefore, the mass required is 0.623 kg

A sports car is accelerated from 0
car?
100 km per hour in 3 s. What is the acceleration of the?
A. 0.1g
100
B. 0.3 g
3s 1 1m 11h
160, 160m
C. 0.9 g
D. 3 g
23. [1 mark]

Answers

Answer: C, 0.9g

We know that 1 g = 9.8 m/s^2. So first we’ll need to convert 100 km/hr to m/s. So we can compare meters to meters and seconds to seconds (we’ll handle the s^2 soon).

100 km/hr * (1000 m)/(1 km) * (60 min)/(1 hr) * (60 sec)/(1 min) = 27.778 m/s.

We know that this car achieved this speed in 3 seconds. Since acceleration is change in velocity, and we know the velocity of the car changed from 0 to about 27.8 m/s in 3 seconds, we know that our acceleration is:
(27.8 m/s - 0 m/s) / (3 s) = 9.259 m/s^2.

Now to find how many g’s, we know that 1 g = 9.8 m/s^2. So we know that 9.259 m/s^2 / 9.8 m/s^2 = about 0.9. This will be 0.9 of 1 g, which is just 0.9 g.

who wants to be study partnerssss for math?

Answers

Sure, that sounds great! What kind of math are we studying? Do you have any specific topics you want to focus on?

What is topic?

A topic is a subject or issue that forms the basis of a discussion, paper, speech, or other form of communication. It is typically used to focus the ideas and facts presented in the communication, making it easier for the audience to understand and remember. It can be an essay, a research paper, a presentation, or any other type of communication that is intended to present and discuss a particular idea. By choosing a specific topic, the author is able to narrow down the scope of the discussion and focus on the main ideas more efficiently.

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28. hwan also wants to determine the depreciation balance for the first year and the last year of the useful life of the construction equipment. determine these amounts as follows: a. in cell b34, enter a formula using the syd function to calculate the depreciation balance for the first year.

Answers

The formula to calculate the depreciation balance for the first year is =SYD(B17, B18, B19, 1).

What is formula?

A formula is a set of mathematical instructions or equations that are used to solve a problem or calculate a desired result. Formulas are used extensively in science, engineering, statistics, economics, and other disciplines. Formulas can be simple or complex, involving algebraic equations and complex calculus. Formulas are often expressed in a concise and precise form, making them easy to use and remember.

The SYD function stands for Sum of Year's Digits and is used to calculate a declining-balance depreciation. In this case, B17 is the cost of the equipment, B18 is the salvage value, B19 is the useful life of the asset, and 1 represents the first year of the useful life.

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