Consider the following ways of handling deadlock: (1) banker’s algorithm, (2) detect
deadlock and kill thread, releasing all resources, (3) reserve all resources in advance,
(4) restart thread and release all resources if thread needs to wait, (5) resource ordering, and (6) detect deadlock and roll back thread’s actions.
a. One criterion to use in evaluating different approaches to deadlock is which
approach permits the greatest concurrency. In other words, which approach allows
the most threads to make progress without waiting when there is no deadlock?
Give a rank order from 1 to 6 for each of the ways of handling deadlock just listed,
where 1 allows the greatest degree of concurrency. Comment on your ordering.
b. Another criterion is efficiency; in other words, which requires the least processor
overhead. Rank order the approaches from 1 to 6, with 1 being the most efficient,
assuming that deadlock is a very rare event. Comment on your ordering. Does
your ordering change if deadlocks occur frequently?


who can answer part B for me?

The standing pressure test for positive pressure medical gas piping is an important step to ensure the safety and effectiveness of the piping system. According to NFPA 99, the test shall be conducted with the source valve closed and the piping system subjected to a pressure of not less than 50 psi (345 kPa) for a minimum of 24 hours.

This pressure must be maintained within a range of plus or minus 5 psi (35 kPa) throughout the duration of the test. The purpose of the standing pressure test is to detect any leaks or weaknesses in the piping system before it is put into use. This is particularly important for medical gas piping, as any leaks or malfunctions could compromise patient safety and lead to serious health risks. By conducting the test with the source valve closed, the system is isolated from the gas source and any changes in pressure can be attributed to the piping system itself. It is also important to note that the standing pressure test should only be conducted by qualified personnel who have the necessary knowledge and experience to properly carry out the test. This includes ensuring that all valves and connections are properly sealed, and that the pressure gauge used for the test is accurate and calibrated. Overall, the standing pressure test is a critical step in ensuring the safety and reliability of positive pressure medical gas piping systems.

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b. False.

Inductors used in electrical and electronic equipment typically have tolerances of ±5%. This statement is false. The tolerance of an inductor refers to the range within which the actual value of the inductance can vary from its nominal value. While a tolerance of ±5% is common for resistors and capacitors, it is not typically the case for inductors.

Inductors often have higher tolerances, typically ranging from ±10% to ±20%. This wider tolerance range is due to the difficulty in manufacturing inductors with precise values. In certain cases, specialized or custom-made inductors may have tighter tolerances, but in general, a tolerance of ±5% is not commonly found in standard inductors used in electrical and electronic equipment.

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check photo solve

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the smallest allowable outer diameter (d) of the washers is approximately 50.82 mm, considering the average normal stress in the bolts and the bearing stress between the washers and the planks.

The average normal stress in the bolts is given as 36 MPa, which is equal to 36 N/mm².

So, σ_avg = 36 N/mm² = 36 MPa

The bearing stress between the washers and the planks must not exceed 8.5 MPa, which is equal to 8.5 N/mm².

So, σ_bearing = 8.5 N/mm² = 8.5 MPa

Now, using the relationship between the bearing stress and the average normal stress:

σ_bearing = σ_avg * (d_bolt / d_washer)

8.5 = 36 * (12 mm / d_washer)

Now, solve for d_washer:

d_washer = 36 * 12 mm / 8.5

d_washer =  50.82 mm

Since the washer's inner diameter is 16 mm, the difference between the inner and outer diameters of the washers is 2 * t (the thickness of the washers).

So, d_washer - 16 mm = 2 * t

t = (d_washer - 16 mm) / 2

t ≈ (50.82 mm - 16 mm) / 2

t ≈ 17.41 mm

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The free-body diagram of the beam which supports the 80-kg load and is supported by the pin at A can be seen in the image attached below.

The first image shows the diagram of the beam and the second image shows the free-body diagram of the beam.

The resolution of forces in the system is well understood by the principle of equilibrium where a stationary body will remain balanced when subject to parallel forces provided that the total sum of the overall external forces is zero.

The free-body diagram is a graphical representation used to visualize the forces applied to an object.

The equilibrium of forces on the x-axis is:

\(\mathbf{\sum F_x = 0}\)

The equilibrium of forces on the y-axis is:

\(\mathbf{\sum F_y = 0}\)

The equilibrium condition at any point is:

\(\mathbf{\sum M = 0}\)

From the free body diagram attached in the second image below,

Therefore, we can conclude that the free-body diagram of the beam which supports the 80-kg load and is supported by the pin at A can be seen in the image attached below.

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The correct answer is c. Both Technician A and B are correct, but Technician B's statement is not entirely complete.

Technician A is correct in stating that multiplexing is a way to add wires without increasing the weight of the vehicle. Multiplexing refers to a method of transmitting multiple signals over a single communication channel or wire. This reduces the number of wires required to transmit signals, thereby reducing the weight of the wiring harness and saving space. This is particularly important in automotive applications where space and weight are critical factors. Multiplexing also allows for better diagnostic capabilities as it simplifies the process of locating faults in the wiring system.

Technician B is partially correct in stating that multiplexing uses bus data links. A bus data link is a communication system that enables multiple devices to communicate with each other using a single communication channel. In automotive applications, multiplexing often uses a bus data link to transmit signals between different vehicle systems. However, multiplexing can also be achieved using other methods such as time-division multiplexing or frequency-division multiplexing.

Therefore, the correct answer is c. Both Technician A and B are correct, but Technician B's statement is not entirely complete.

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The process in question is referred to as the iterative design process. Engineers utilize this method by completing and repeating a sequence of steps in order to continually improve and refine their designs as they work towards achieving the project goal. This approach allows for flexibility and adaptability in the design process, as engineers can make adjustments and modifications based on feedback and testing, ultimately leading to a more successful outcome.

Answer:

To find the stress you need to know the applied load. Without that information, it is not possible to determine the axial stress in each of the three rods.

Explanation:

To determine the axial stress in each of the three rods, you would need to know the applied load and the cross-sectional area of each rod. The formula for axial stress is:

Stress (σ) = Load (F) / Area (A)

The area of a rod can be determined using the formula:

Area = π * (diameter/2)^2

Where diameter is the diameter of the rod in inches.

So,

For rod 1(aluminum rod)

Area = π * (2.00/2)^2 = 3.14 in^2

For rod 2(brass rod)

Area = π * (1.50/2)^2 = 1.77 in^2

For rod 3(steel rod)

Area = π * (3.00/2)^2 = 7.07 in^2

To find the stress you need to know the applied load. Without that information, it is not possible to determine the axial stress in each of the three rods.

Answer:

The head added by the pump is approximately 51.8 meters

Explanation:

The given parameters of the water are;

The initial diameter of the pump ≈ The final diameter of the pump

The inlet side pressure, p₁ = 30 kPa

The intended outlet side pressure, p₂ = 500 kPa

The power of the pump, P = ρ·g·Q·H

Where, the pressure added by the pump, Δp = p₂ - p₁ = ρ·g·H

ρ = The density of the water ≈ 997 kg/m³

g = The acceleration due to gravity ≈ 9.81 m/s²

H = The head added by the pump

Therefore, we have;

500 kPa - 30 kPa = 997 kg/m³ × 9.81 m/s² × H

H = (500 kPa - 30 kPa)/(997 kg/m³ × 9.1 m/s²) ≈ 51.8 m

The head added by the pump, H ≈ 51.8 meters.

Answer:

Anne is a mechanical engineer.

Explanation:

There are many different types of engineers (mechanical, industrial, electrical, chemical and civil) around the world. When a job involves designing machines, it falls under mechanical engineering. Such job requires a person to be as creative as possible, so he/she can come up with an innovative design that will be reasonable when used.

Designing machines includes spacecrafts. Therefore, Anne is a mechanical engineer working for NASA.

Correct option is d.estimate landing loading rate.The anteroposterior ground reaction force could be used to estimate landing loading rate.

The anteroposterior ground reaction force is a measure of the force exerted by the body on the ground during movement. It represents the component of the force that acts in the forward-backward direction. By analyzing the anteroposterior ground reaction force, it is possible to estimate the landing loading rate, which refers to the rate at which force is applied to the body upon landing.

During activities such as jumping, the landing loading rate is an important parameter to consider as it can affect the risk of injury. A higher landing loading rate indicates a rapid increase in force upon landing, which may result in greater stress on the joints and tissues of the body.

Conversely, a lower landing loading rate suggests a more gradual increase in force, which can be less detrimental to the body.

By using the anteroposterior ground reaction force, researchers and practitioners can assess the landing loading rate and make informed decisions regarding training, rehabilitation, and injury prevention strategies.

Monitoring and analyzing this parameter can help identify individuals who may be at a higher risk of injury due to excessive loading rates and enable the implementation of targeted interventions to reduce injury risk.

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In a job order costing system, direct labor costs are traced to specific jobs, while indirect labor costs are allocated to all jobs based on some predetermined allocation method.

The journal entry to record indirect labor costs in Oxford company would typically debit the Manufacturing Overhead account and credit the Wages Payable account. The amount of the debit would be equal to the total indirect labor costs for the period, which in this case is $6,000.

Manufacturing Overhead is an account used to accumulate all indirect manufacturing costs, such as rent, utilities, depreciation, and indirect labor. This account is then allocated to all jobs based on a predetermined overhead rate, which is calculated by dividing the estimated overhead costs for the period by the estimated amount of the allocation base (such as direct labor hours or machine hours).

It is important to note that the journal entry for indirect labor costs is not posted directly to a specific job, but rather to the Manufacturing Overhead account. This is because indirect labor costs are not directly attributable to any one job, but rather to the manufacturing process as a whole.

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Answer:

Maximum concentration for Pb is only 41%. we get 64.3% which exceeds the maximum concentration. Therefore it is not possible.

Explanation:

let's first determine the mass fraction of the phases as follows

\(W_{a}=\frac{m_{a} }{m_{a}+m_{p_{g2}p_{b} } }\)

Given that masses are \(m_{a}=7.39kg\) and \(m_{p_{g2}p_{b} }=3.81kg\)

Thus, \(W_{a} =\frac{7.39}{7.39+3.81}=0.659\)

\(W_{M_{g2Pb} } =1-W_{a}=1-0.659=0.341\)

Now determine the concentration

\(W_{a}=\frac{C_{0}-C_{a} }{C_{b}-C_{a} }\)

At 81% PB and 70% Pb only point at which \(M_{g2Pb}\) exists, we can solve

\(0.659=\frac{70-81}{C_{b}-81 }\)

\(C_{b}=\)64.3%

Refer text book page no. 326, figure 9.20, from figure we can say maximum concentration for Pb is only 41%. we get 64.3% which exceeds the maximum concentration.

Answer:

Technician A

Explanation:

Technician A is correct. Technician B is wrong, as different drive vehicles (FWD, RWD, AWD, 4WD) each require a certain rotation for optimal tire wear.

Answer: It is  a nominal rate per year

Answer:

Debido a los peligros que presenta un espacio confinado, se requiere que se utilice un sistema de permisos antes de entrar; en donde deberá incluir un listado de lo que hay que revisar y apuntar antes de entrar para controlar al personal y los riesgos posibles. La responsabilidad de sacar al personal, es de servicios de rescate, con equipo de  protección personal y de rescate, incluyendo  respiradores, y adiestramiento sobre cómo utilizarlo. El  personal de servicio de rescate también debe recibir el  adiestramiento de entrantes autorizados y ser  adiestrado para realizar los deberes de rescate asignados.

Answer:Referencing is a standardised method of acknowledging the sources of information and ideas you have used.

Explanation:Depending on the way in which they record sources, scholarly reference styles can be divided into three main categories: documentary notes styles, parenthetical (or author-date) styles, and numbered styles. Within each category there are several, slightly different reference styles.

Referencing allows you to acknowledge the contribution of other writers and researchers in your work. Any university assignments that draw on the ideas, words or research of other writers must contain citations. Referencing is also a way to give credit to the writers from whom you have borrowed words and ideas.

Answer:

E = 8.83 kips

Explanation:

First, we determine the stress on the rod:

\(\sigma = \frac{F}{A}\\\\\)

where,

σ = stress = ?

F = Force Applied = 1300 lb

A = Cross-sectional Area of rod = 0.5\(\pi \frac{d^2}{4} = \pi \frac{(0.5\ in)^2}{4} = 0.1963\ in^2\)

Therefore,

\(\sigma = \frac{1300\ lb}{0.1963\ in^2} \\\\\sigma = 6.62\ kips\)

Now, we determine the strain:

\(strain = \epsilon = \frac{elongation}{original\ length} \\\\\epsilon = \frac{0.009\ in}{12\ in}\\\\\epsilon = 7.5\ x\ 10^{-4}\)

Now, the modulus of elasticity (E) is given as:

\(E = \frac{\sigma}{\epsilon}\\\\E = \frac{6.62\ kips}{7.5\ x\ 10^{-4}}\)

E = 8.83 kips

As the temperature of the material increases, the potential energy of the molecules increases. Thermal expansion occurs due to changes in temperature, and interatomic distances increase as potential energy increases.

Thermal expansion is used in a variety of applications such as rail buckling, engine coolant, mercury thermometers, joint expansion, and others.

It is to be noted that an application of the concept of liquid expansion in everyday life concerns liquid thermometers. As the heat rises, the mercury or alcohol in the thermometer tube moves in only one direction. As the heat decreases, the liquid moves back smoothly.

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Answer:

when car vroom it go electric

Explanation:

i think then it goes to some spinny thing that spins and make the electric and the electic spins the spinny thing and the smoke comes outside the back

Answer:

For a Singular matrix, the determinant must be equivalent to 0.

Explanation:

A matrix is a rectangular array in which elements are arranged in rows and columns.

Each square matrix has a determinant. The determinant is a numerical idea that has a fundamental function in finding the arrangement just as investigation of direct conditions. For a Singular matrix, the determinant must be equivalent to 0.

Answer:

According to the Utilitarian approach, an engineer should attend to the needs of the visually impaired because doing so would result in the greatest overall happiness and well-being for the greatest number of people. By designing products and systems that are accessible and usable by the visually impaired, engineers can improve the quality of life for a significant portion of the population, which would result in increased happiness and well-being.

According to the Capabilities approach, an engineer should attend to the needs of the visually impaired because doing so would help to promote their capabilities and enable them to live fulfilling lives. By designing products and systems that are accessible and usable by the visually impaired, engineers can help to ensure that these individuals are not restricted in their ability to participate fully in society and to pursue their goals and aspirations. This would enable the visually impaired to develop and exercise their capabilities, which would contribute to their overall well-being and flourishing.

Explanation:

Given the electrical length of the line and its physical length, a short line model should be sufficient.

The electrical length is the product of the physical length of the line and the angular frequency (w) and is divided by the speed of light (c). It's generally represented by the parameter β, given by:

β = ωL / c

The line is considered short if its electrical length is much less than 1 (β << 1).

The short, medium, and long designations can also be made based on the line's length:

Short line: length is up to 50 miles (approx. 80 km), and the line voltage is relatively low.

Medium line: length is between 50-150 miles (80-240 km), and the line voltage is high.

Line length = 3.2 miles = 5.15 km = 5150 m

f = 60 Hz

We can calculate β as follows:

β = (2π * 60 Hz * 5150 m) / (3 * 10^8 m/s)

= 0.032 rad

Since β is much less than 1, a short line model should be sufficient.

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When an ordinarily elastic material cracks brittlely, there is little or no outward trace of material deformation prior to failure.

The plastic deformation that occurs before failure is minimal or nonexistent in brittle fractures. Glasses, ceramics, as well as various polymers and metals, frequently fracture in a brittle way.

When a material is exposed to forces below its yield limit, brittle fractures take place. A ductile material is typically the foundation for machine design, and the design criteria are intended to prevent plastic and, in some circumstances, elastic deformations.

Material that has undergone either no plastic deformation or very little plastic deformation prior to fracture is said to have fractured with brittleness. Since they all share this quality, brittle materials include rock, concrete, glass, and cast iron.

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Superconducting materials have a huge potential to bring about revolutionary advances in high-field magnet technology and electric power.

allowing for ultra-strong, tiny, light-weight electrical equipment, high-speed maglev transit, and electric power generator with excellent efficiency. The equipment can be drastically smaller because to the use of superconductivity in magnet applications. The drawback is that superconductive materials require extremely low temperatures—close to absolute zero—which raises the expense of operation. Only when kept below a specific temperature known as the transition temperature do superconducting materials truly superconduct. The temperature is significantly below 77 Kelvin, the temperature of liquid nitrogen, for currently understood practical superconductors.

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Answer:

Engineering Design Loop: The steps of the design process include: identify the need, research the problem, develop possible solutions, select the most promising solution, construct a prototype, test and evaluate the prototype, communicate the design, and redesign.

Explanation:

Answer:

  0.9104

Explanation:

Suitable technology can tell you the probability.

P(-1.5≤Z≤2) ≈ 0.9104

__

A phone app gives the probability as 0.9104426667829628.

In two dimensions, the equation for a line can be written as y = mx + h. To reflect a point about this line, we can use an affine transformation matrix. The matrix for reflection about a line is given by:
\($$ \begin{bmatrix} 1-2m^2 & 2mh & 2mh^2 \\ 2mh & 1-2h^2 & -2h(1+m^2) \\ 0 & 0 & 1 \end{bmatrix} $$\)

To reflect a point (x, y) about the line, we simply multiply the point by this matrix:
\($$ \begin{bmatrix} 1-2m^2 & 2mh & 2mh^2 \\ 2mh & 1-2h^2 & -2h(1+m^2) \\ 0 & 0 & 1 \end{bmatrix} \begin{bmatrix} x \\ y \\ 1 \end{bmatrix} = \begin{bmatrix} (1-2m^2)x + 2mhy + 2mh^2 \\ 2mhx + (1-2h^2)y - 2h(1+m^2) \\ 1 \end{bmatrix} $$\)This gives us the reflected point (x', y').

To extend this result to reflection about a plane in three dimensions, we can use a similar matrix. The equation for a plane in three dimensions is given by Ax + By + Cz + D = 0. The matrix for reflection about this plane is given by:
\($$ \begin{bmatrix} 1-2A^2 & -2AB & -2AC & -2AD \\ -2AB & 1-2B^2 & -2BC & -2BD \\ -2AC & -2BC & 1-2C^2 & -2CD \\ 0 & 0 & 0 & 1 \end{bmatrix} $$\)

To reflect a point (x, y, z) about the plane, we simply multiply the point by this matrix:
\($$ \begin{bmatrix} 1-2A^2 & -2AB & -2AC & -2AD \\ -2AB & 1-2B^2 & -2BC & -2BD \\ -2AC & -2BC & 1-2C^2 & -2CD \\ 0 & 0 & 0 & 1 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \\ 1 \end{bmatrix} = \begin{bmatrix} (1-2A^2)x - 2ABy - 2ACz - 2AD \\ -2ABx + (1-2B^2)y - 2BCz - 2BD \\ -2ACx - 2BCy + (1-2C^2)z - 2CD \\ 1 \end{bmatrix} $$\)
This gives us the reflected point (x', y', z').

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