Consider the equation 9x+7=7+9x

The corresponding likelihood of p(θ,y) is proportional to p(θ,w).

To show that the likelihoods are proportional, demonstrate that the likelihood function of θ given y, denoted as p(θ,y), is proportional to the likelihood function of θ given w, denoted as p(θ,w).

We'll start by applying the change of variables formula to the joint density of y and θ:

p(y, θ) = p(y,θ) p(θ)

Next, we'll use the inverse function theorem to express the joint density in terms of the transformed variables:

\(p(y, θ) = p(w(y),θ) p(θ) det(dy,dw)\)

where w(y) is the transformation function and det(dy, dw) is the determinant of the Jacobian matrix of the transformation.

Now, let's calculate the likelihood function of θ given y:

\(p(θ,y) = p(y, θ)p(y)\\= [p(w(y),θ) p(θ) det(dy, dw)] [p(w(y)) det(dw, dy)]\)

Here, we've also used the fact that p(y) = p(w(y)) det(dw/dy), which is the change of variables formula for the density of y.

Now, let's calculate the likelihood function of θ given w:

\(p(θ,w) = p(w, θ) p(w)\\= [p(w,θ) p(θ) det(dw, dy)] [p(w) det(dy, dw)]\)

We've used the same logic as before, but this time replacing y with w.

To show that p(θ,y) is proportional to p(θ,w), we need to demonstrate that the ratio of the two likelihood functions is constant:

\(p(θ,y) p(θ,w) = [p(w(y),θ) p(θ) det(dy, dw)] [p(w,θ) p(θ) det(dw, dy)]\\= [p(w(y),θ) det(dy, dw)] [p(w,θ) det(dw, dy)]\)

Notice that det(dy, dw) det(dw, dy) is the absolute value of the determinant of the Jacobian matrix of the inverse function, which is the inverse of the absolute value of the determinant of the Jacobian matrix of the original transformation.

Since this ratio is a constant, we conclude that p(θ,y) is proportional to p(θ,w).

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The answer you would be looking for is 7

The intervals where the graph is decreasing are given as follows:

The behavior of the function regarding increase or decrease depends on the orientation of the graph, as follows:

Hence the intervals describing the behavior of the function are given as follows:

The decreasing interval can be divided into two intervals, as follows:

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In an independent samples t-test, we will compare two sets of data that are from two different groups or conditions.

These two sets of data are known as "samples" and they are "independent" because they are not related to each other. The t-test is a "statistical" test that is used to determine if there is a significant difference between the means of the two samples. By comparing the two sets of data using the t-test, we can determine if the difference between the means of the two samples is statistically significant or not.

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Answer:

c = 11.46 yd

Step-by-step explanation:

Formula we use,

→ (AC)² = (BC)² + (AB)²

Now the value of a will be,

→ c² = (8.1)² + (8.1)²

→ c² = 65.61 + 65.61

→ c² = 131.22

→ c = √131.22

→ [ c = 11.46 yd ]

Hence, value of c is 11.46 yd.

The correct answer is c. the expected value. It is the sum of the product of each possible value and its corresponding probability.

The expected value of a random variable is the weighted average of all possible values that the variable can take on, where the weights are the probabilities of each value occurring.

The variance is a measure of the spread of a random variable, and is not related to the weighted average of the values.

The probable value is not a commonly used statistical term, but it may refer to the mode, which is the most frequently occurring value in a set of data.

The median value is the middle value when a set of data is arranged in order, and is also not related to the weighted average of the values.

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Answer:

\(\sin 2A + \csc 2A = 2.122\)

Step-by-step explanation:

Let \(f(A) = \sin A + \csc A\), we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

\(\csc A = \frac{1}{\sin A}\) (1)

\(\sin^{2}A +\cos^{2}A = 1\) (2)

Now we perform the operations: \(f(A) = 3\)

\(\sin A + \csc A = 3\)

\(\sin A + \frac{1}{\sin A} = 3\)

\(\sin ^{2}A + 1 = 3\cdot \sin A\)

\(\sin^{2}A -3\cdot \sin A +1 = 0\) (3)

By the quadratic formula, we find the following solutions:

\(\sin A_{1} \approx 2.618\) and \(\sin A_{2} \approx 0.382\)

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

\(\sin A \approx 0.382\)

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

\(A \approx 22.457^{\circ}\)

Then, the values of the cosine associated with that angle is:

\(\cos A \approx 0.924\)

Now, we have that \(f(A) = \sin 2A +\csc2A\), we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used:

\(\sin 2A = 2\cdot \sin A\cdot \cos A\) (4)

\(\csc 2A = \frac{1}{\sin 2A}\) (5)

\(f(A) = \sin 2A + \csc 2A\)

\(f(A) = \sin 2A + \frac{1}{\sin 2A}\)

\(f(A) = \frac{\sin^{2} 2A+1}{\sin 2A}\)

\(f(A) = \frac{4\cdot \sin^{2}A\cdot \cos^{2}A+1}{2\cdot \sin A \cdot \cos A}\)

If we know that \(\sin A \approx 0.382\) and \(\cos A \approx 0.924\), then the value of the function is:

\(f(A) = \frac{4\cdot (0.382)^{2}\cdot (0.924)^{2}+1}{2\cdot (0.382)\cdot (0.924)}\)

\(f(A) = 2.122\)

The the expression is in the required form. Thus, A = 211, B = 1, and C = 1. We use the properties of logarithms to rewrite the expression 21619 log 211 in a form with no logarithm of a product, quotient, or power. is in the required form. Thus, A = 211, B = 1, and C = 1. We use the properties of logarithms to rewrite the expression 21619 log 211 in a form with no logarithm of a product, quotient, or power.

To rewrite the expression 21619 log 211 in a form with no logarithm of a product, quotient or power using the laws of logarithms; it is best to express it in exponential form and then separate it into logarithms.21619 log 211Let's express this expression in exponential form.

We know that log a b = c if a = b.

Using this property, we can write,

\(21619 log 211 = 211^(21619)\)

Now let's separate this exponential expression into logarithms.

\(z1y19 log A log(z)+ Blog(y) + Clog(z) 211\)

Now, we have the value of

\(211^(21619)\)

so we can substitute this value in the above expression to get,

\(z1y19 log A log(z)+ Blog(y) + Clog(z) 211z1y19 log A + log(z^z1y19) + Blog(y) + log(z^C) 211\)

Now we use the property that

log a^n = nlog a to split the logs into their coefficients.

\(z1y19 log A + z1y19 log(z) + Blog(y) + Clog(z).\)

Now, the expression is in the required form. Thus, A = 211, B = 1, and C = 1. We use the properties of logarithms to rewrite the expression 21619 log 211 in a form with no logarithm of a product, quotient, or power.

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Answer:

B

Step-by-step explanation:

hope this helps with the work

Answer:

\(ED = 26\)

\(CF = 13\)

\(m \overset{\huge\frown}{ED} = 136\)

\(m \overset{\huge\frown}{HD} = 68\)

\(m \overset{\huge\frown}{CE} =88\)

Step-by-step explanation:

Given

\(JG = JF\)

\(GD = 13\)

\(m \overset{\huge\frown}{CD} = 136\)

See attachment for circle

Solving (a): Length ED

Line JD divides ED into two equal parts, EG and DG.

So:

\(ED = EG + GD\)

\(ED = GD + GD\)

\(ED = 13 + 13\)

\(ED = 26\)

Solving (b): Length CF

CF is a reflection of EG.

So:

\(CF = EG\)

\(EG = GD = 13\)

So:

\(CF = 13\)

Solving (c): \(m \overset{\huge\frown}{ED}\)

Since ED = CD;

Then:

\(m \overset{\huge\frown}{ED} = m \overset{\huge\frown}{CD}\)

So:

\(m \overset{\huge\frown}{ED} = 136\)

Solving (d): \(m \overset{\huge\frown}{HD}\)

Line HF divides CD to 2 equal parts

So:

\(m \overset{\huge\frown}{HD} = \frac{1}{2} * m \overset{\huge\frown}{CD}\)

\(m \overset{\huge\frown}{HD} = \frac{1}{2} * 136\)

\(m \overset{\huge\frown}{HD} = 68\)

Solving (e): \(m \overset{\huge\frown}{CE}\)

\(m \overset{\huge\frown}{CE}\) is a minor arc while \(m \overset{\huge\frown}{ED} = 136\) + \(m \overset{\huge\frown}{CD} = 136\) are the major arcs.

So:

\(m \overset{\huge\frown}{CE} + m \overset{\huge\frown}{ED} + m \overset{\huge\frown}{CD}= 360\)

\(m \overset{\huge\frown}{CE} + 136+136= 360\)

Collect like terms

\(m \overset{\huge\frown}{CE} =- 136-136+ 360\)

\(m \overset{\huge\frown}{CE} =88\)

Following are the calculated value " \(ED=26, CF=13\ , m \widehat{ED}=136^{\circ}\ , m \widehat{HD}=68^{\circ}\ , m \widehat{CE}=88^{\circ}\\\\\)", and its complete calculation can be defined as follows:

\(\bold{JG=JF,GD=13,} \\\\ m \widehat{CD}=136^{\circ}\\\\\)

When

\(m \widehat{CD}= m \widehat{ED}\\\\m \widehat{ED} = 136^{\circ}\)

\(HJ \perp CD \\\\IJ \perp ED\\\\\)

SO,

\(CF = FD \\\\EG=ED \\\\\)

\(m \widehat{HD} = m \widehat{CH} = \frac{1}{2} m \widehat{CD}\\\\\)

\(CF=13\\\\ ED = 13 \times 2 =26 \\\\ m \widehat{HD} = \frac{1}{2}\ m \widehat{CD} = 136^{\circ} \div 2 = 68^{\circ}\\\\m \widehat{CE} = 360^{\circ} -136^{\circ} - 136^{\circ} = 88^{\circ}\\\\\)

Using the Vertical theorem and Theorem of the length of tangent to calculate the value:

\(ED=26\\\\CF=13\\\\m \widehat{ED}=136^{\circ}\\\\m \widehat{HD}=68^{\circ}\\\\m \widehat{CE}=88^{\circ}\\\\\)

Note:

The given question is incomplete that's why we defined the question in the attached file and then solve it.

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Xenocentrism is the opposite of ethnocentrism. Xenocentrism is the belief or preference for the culture, values, or products of others over one's own culture.

It stands in contrast to ethnocentrism, which involves the belief in the superiority of one's own culture. While ethnocentrism can lead to cultural bias and the dismissal of other cultures, xenocentrism appreciates and values diversity, recognizing the merits and value in different cultural perspectives and practices.

Xenocentrism involves looking beyond one's own cultural norms and standards and acknowledging the worth of alternative ideas, customs, and products from different cultures. It encourages an open-minded and inclusive approach, promoting intercultural understanding and appreciation. However, it's important to note that extreme xenocentrism, similar to extreme ethnocentrism, can lead to the negation or devaluation of one's own culture.

In summary, xenocentrism represents a mindset that embraces cultural diversity and recognizes the value in cultures other than one's own. It serves as an alternative to ethnocentrism by fostering a more inclusive and open perspective towards different cultural experiences.

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The relative risk of being alive at 5-years after diagnosis associated between white men and black men is 2.03.

In the US, among a representative group of 6,006 white men and 1,126 black men, ages 70-79 years at diagnosis of stage IV prostate cancer: 2,337 white men and 344 black men were alive after 5 years of follow-up.

In order to calculate the relative risk of being alive at 5-years after diagnosis associated between white men and black men, we can use the following formula:

Relative risk = [ (number of white men alive after 5 years) / (total number of white men) ] ÷ [ (number of black men alive after 5 years) / (total number of black men) ]

Therefore, substituting the values given in the formula we get;

[ (2,337) / (6,006) ] ÷ [ (344) / (1,126) ] = 0.63 ÷ 0.31 = 2.03

Therefore, the relative risk of being alive at 5-years after diagnosis associated between white men and black men is 2.03.

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Answer:

What do u mean??

Step-by-step explanation:

Step-by-step explanation:

Can you write the questions carefully that we can understand

Answer:

Step-by-step explanation:

okay i will answer but i dont see the question

Answer:

$1425

Step-by-step explanation:

To find how much money you would make, we would first have to multiply the number of weeks worked by how many hours you work per week.

4 · 25 = 100

What this tells us is that in 4 weeks, you worked 100 hours in total. Now we can multiply total hours worked by how much you are paid per hour to get our answer.

14.25 · 100 = 1425

In the Subgame Perfect Equilibrium of a Stackelberg model, firm 1 chooses a number, and firm 2 chooses a function. Therefore, option (d) is the correct answer.

The Subgame Perfect Equilibrium (SPE) is a solution concept in game theory that analyzes strategic decision-making in sequential games. In a Stackelberg model, firm 1 acts as the leader and sets its output level first, followed by firm 2 as the follower, who observes firm 1's output before making its decision.

In the Subgame Perfect Equilibrium of this model, firm 1 chooses a number (output level) while firm 2 chooses a function (strategy). This implies that firm 1's decision is made independently as a quantity, and firm 2, observing firm 1's choice, formulates its strategy based on that information.

Therefore, option (d) is the correct answer: Firm 1 chooses a number, and firm 2 chooses a function in the Subgame Perfect Equilibrium of a Stackelberg model.

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For a 75% success percentage, she needs to hit 23 of her final 30 throws.

The rational function for a player's free throw percentage will be:

y = (21/30) * 100

A function that is the sum of polynomials is referred to as rational. If a function of one variable, x, can be written as :

\(f(x) = p(x)/q(x),\)

where p(x) and q(x) are polynomials with q(x) = 0,

then the function is said to be rational. The phrase f(x) = (x2 + x - 2) / (2x2 - 2x - 3) denotes a rational function; in this case, 2x2 - 2x - 3 = 0.

Every constant is a polynomial, thus we know that the numerators of rational functions may also be constants. A rational function would be f(x) = 1/(3x+1), for instance.

If the basketball player is making 70% successful throw rate by making 21 of last 30 free throws

so, for raising her throw rate to 75% she should throw:

x/30 * 100 = 75%

x = 75 * 3 / 10

x = 15 * 3 /2

x = 22.5 ≈ 23

therefore , she should make 23 of her last 30 free throws to raise her success rate to 75%

For this case what you should do is write the following function:

y = (a / b) * 100

Where,

A: amount of successful free throws

B: total amount of free throws

Substituting values we have:

y  = (21/30) * 100

The result is:

Y = 70% (as we expected)

a rational function that can model the player's free throw percentage is:

y = (21/30) * 100

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Answer:

C. c^2=a^2+b^2-2abcos(90°)

Step-by-step explanation:

This is the law of cosine.

Answer:

C, you're welcome :)

Step-by-step explanation:

The data we get from the question is a random experiment can result in one of the outcomes {a,b,c,d} with probabilities from that information, P(A U B U C) = 0.8.
         

The given probabilities of events and outcomes are:

       P({a}) = 0.4,P({b}) = 0.1,P({c}) = 0.3,P({d}) 0.2

 So the given events are:

        A = {a,b},B = {b,c,d},C = {d}

   We have to find P(A U B U C) Using the formula of the probability of the union of two events,

    we get:

          P(A U B U C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)

Now we will find the values of all probabilities:

                  P(A) = P({a}) + P({b})

                         = 0.4 + 0.1

                         = 0.5

                   P(B) = P({b}) + P({c}) + P({d})

                          = 0.1 + 0.3 + 0.2

                           = 0.6

                   P(C) = P({d})

                            = 0.2

                      P(A ∩ B) = P({b})

                                     = 0.1

                      P(A ∩ C) = P({d})

                                     = 0.2

                      P(B ∩ C) = P({d})

                                     = 0.2

               P(A ∩ B ∩ C) = 0

 (No common event) Put all the above values in the formula:

           P(A U B U C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) +

                                     P(A ∩ B ∩ C)

                                 = 0.5 + 0.6 + 0.2 - 0.1 - 0.2 - 0.2 + 0

                                 = 0.8

         Therefore, P(A U B U C) = 0.8 is the required probability.

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the domain is all the real numbers, or (-infinite <x<infinite)

the range is y>=-4

axis of symetry is x= -1

vertex is (-1,-4)

the parabola opens upwards

x intercepts (-3,0) and (1,0)

y intercepts (0,-3)

Answer:

1/36

Step-by-step explanation:

There's only 1 way to get the sum of 2.

1,1

The first derivatives for the given functions are:

For \(y = 3x^2 + 5x + 10,\) the first derivative is dy/dx = 6x + 5.

For  \(y = 100200x + 7x,\) the first derivative is dy/dx = 100207.

For \(y = ln(9x^4),\) the first derivative is dy/dx = 4/x.

To find the first derivative for each of the given functions, we'll use the power rule, constant rule, and chain rule as needed.

For the function\(y = 3x^2 + 5x + 10:\)

Taking the derivative term by term:

\(d/dx (3x^2) = 6x\)

d/dx (5x) = 5

d/dx (10) = 0

Therefore, the first derivative is:

dy/dx = 6x + 5

For the function y = 100200x + 7x:

Taking the derivative term by term:

d/dx (100200x) = 100200

d/dx (7x) = 7

Therefore, the first derivative is:

dy/dx = 100200 + 7 = 100207

For the function \(y = ln(9x^4):\)

Using the chain rule, the derivative of ln(u) is du/dx divided by u:

dy/dx = (1/u) \(\times\) du/dx

Let's differentiate the function using the chain rule:

\(u = 9x^4\)

\(du/dx = d/dx (9x^4) = 36x^3\)

Now, substitute the values back into the derivative formula:

\(dy/dx = (1/u) \times du/dx = (1/(9x^4)) \times (36x^3) = 36x^3 / (9x^4) = 4/x\)

Therefore, the first derivative is:

dy/dx = 4/x

To summarize:

For \(y = 3x^2 + 5x + 10,\) the first derivative is dy/dx = 6x + 5.

For y = 100200x + 7x, the first derivative is dy/dx = 100207.

For\(y = ln(9x^4),\) the first derivative is dy/dx = 4/x.

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Answer:9 ounces of flours

Step-by-step explanation:90:9 ratio or sugar to flour

Answer:

There's not really a FORMULA

Step-by-step explanation:

I don't understand what you mean, but I can tell you that 10x13 is 130.

Answer:

OK hiiiiiiiiiiiiiiiii.

Answer:

The best chart to show how your department's expenses compare to the total company's expenses, and hopefully save employee jobs, would be:

Pie Chart

Step-by-step explanation:

Probability that he will make the next free throw is 0.89% if larry bird made approximately 89% of all free throws during his nba career.

During nba career he made approximate 89% of all free throws.

To calculate the probability of the next 10 free throws given which will be

= No. of possible outcome / Total no. of outcome

= 89 / 100

= 0.89 %

Probability is simply how likely something is to happen. Whenever we're unsure about the outcome of an event, we can talk about the probabilities of certain outcome like how likely they are.

P(A) = (# of ways A can happen) / (Total number of outcomes)

which means that Probability that he will make the next free throw is 0.89 %

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\(\textit{we know that }\theta \textit{ contains the point }(\stackrel{x}{3}~~,~~\stackrel{y}{0})\textit{, let's find the hypotenuse} \\\\\\ \textit{using the pythagorean theorem} \\\\ r^2=a^2+b^2\implies r=\sqrt{a^2+b^2}\implies r=\sqrt{3^2+0^2} \qquad \begin{cases} r=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ r=\sqrt{3^2}\implies r=3\)

\(\rule{34em}{0.25pt}\\\\ sin(\theta)=\cfrac{opposite}{hypotenuse} =\cfrac{y}{r}\implies \cfrac{0}{3}\implies 0 \\\\\\ cos(\theta)=\cfrac{adjacent}{hypotenuse} =\cfrac{x}{r}\implies \cfrac{3}{3}\implies 1 \\\\\\ tan(\theta)=\cfrac{opposite}{adjacent} =\cfrac{y}{x}\implies \cfrac{0}{3}\implies 0\)

\(cot(\theta)=\cfrac{adjacent}{opposite} =\cfrac{x}{y}\implies \cfrac{3}{0}\implies und efined \\\\\\ csc(\theta)=\cfrac{hypotenuse}{opposite} =\cfrac{r}{y}\implies \cfrac{3}{0}\implies und efined \\\\\\ sec(\theta)=\cfrac{hypotenuse}{adjacent} =\cfrac{r}{x}\implies \cfrac{3}{3}\implies 1\)

Answer:

acute

Step-by-step explanation:

Helen deposited $1100 in a savings account with a 4.5% annual interest rate. After 7 years, if the account is compounded quarterly, weekly, or semi-annually, she would have $1614.53, $1617.92, or $1606.24, respectively.

a. To model the amount of money in Helen's savings account at the end of t years, compounded k times during the year, we can use the following formula:

A = P(1 + r/k)^(kt)

So the function to model the amount of money in Helen's savings account at the end of t years, compounded k times during the year is:

A = 1100(1 + 0.045/k)^(kt)

b. To determine the amount of money in Helen's account at the end of 7 years if it is compounded quarterly, weekly, and semi-annually, we can substitute the given values of k and t into the formula and simplify:

Compounded quarterly:

A = 1100(1 + 0.045/4)^(4*7)

A = 1100(1.01125)^28

A = 1614.53 (rounded to the nearest cent)

Compounded weekly:

A = 1100(1 + 0.045/52)^(52*7)

A = 1100(1.00086538)^364

A = 1617.92 (rounded to the nearest cent)

Compounded semi-annually:

A = 1100(1 + 0.045/2)^(2*7)

A = 1100(1.0225)^14

A = 1606.24 (rounded to the nearest cent)

Therefore, after 7 years, if Helen's account is compounded quarterly, she would have $1614.53; if it is compounded weekly, she would have $1617.92, and if it is compounded semi-annually, she would have $1606.24.

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