The integral that represents the length of the curve from the point (-3,6) to the point (2,36) is L = ∫[-3 to 2] √101 dx.
To find the length of the curve defined by the equation y = 47° + 10x from the point (-3,6) to the point (2,36), we can use the arc length formula for a curve:
L = ∫[a to b] √(1 + (dy/dx)^2) dx
First, let's find dy/dx by taking the derivative of the given equation:
dy/dx = d/dx(47° + 10x) = 10
Now we can substitute this value into the arc length formula:
L = ∫[-3 to 2] √(1 + (10)^2) dx
Simplifying:
L = ∫[-3 to 2] √(1 + 100) dx
L = ∫[-3 to 2] √101 dx
Thus, the integral that represents the length of the curve from the point (-3,6) to the point (2,36) is:
L = ∫[-3 to 2] √101 dx
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6.5 Given a normal distribution with μ = 100 and o = 10, what is the probability that a. X < 75? b. X < 70? c. X < 80 or X < 110? d. Between what two X values (symmetrically distributed around the me
The probability that X < 75 is P(X < 75) = P(Z < -2.5), the probability that X < 70 is P(X < 70) = P(Z < -3), the probability that X < 80 or X < 110 is P(X < 80 or X < 110) = P(Z < -2) + P(Z < 1), and the range of X values containing 95% of the distribution is (μ + \(z_1\) * σ) to (μ + \(z_2\) * σ), where μ = 100, σ = 10, and \(z_1\) and \(z_2\) correspond to cumulative probabilities of 0.025 and 0.975, respectively.
a) To find the probability that X < 75, we need to standardize the value 75 using the formula z = (X - μ) / σ, where X is the given value, μ is the mean, and σ is the standard deviation.
z = (75 - 100) / 10
= -2.5
Now, using the standard normal distribution table or a calculator, we find the corresponding cumulative probability for z = -2.5. Let's assume it is P(Z < -2.5).
The probability that X < 75 is equal to the probability that Z < -2.5. Therefore, P(X < 75) = P(Z < -2.5).
b) Following the same process, we standardize the value 70:
z = (70 - 100) / 10
= -3
We find the corresponding cumulative probability for z = -3, denoted as P(Z < -3). This gives us P(X < 70) = P(Z < -3).
c) To find the probability that X < 80 or X < 110, we can break it down into two separate probabilities:
P(X < 80 or X < 110) = P(X < 80) + P(X < 110)
Standardizing the values:
\(z_1\) = (80 - 100) / 10
= -2
\(z_2\) = (110 - 100) / 10
= 1
We find the cumulative probabilities P(Z < -2) and P(Z < 1). Adding these two probabilities gives us P(X < 80 or X < 110).
d) To determine the range of X values between which a certain probability falls, we need to find the z-scores that correspond to the desired cumulative probabilities. For example, to find the range of X values that contains 95% of the distribution, we need to find the z-scores that correspond to the cumulative probabilities of 0.025 and 0.975 (since the distribution is symmetric).
Using the standard normal distribution table or a calculator, we find the z-scores that correspond to the cumulative probabilities of 0.025 and 0.975. We can then use the z-scores to find the corresponding X values using the formula X = μ + z * σ, where μ is the mean and σ is the standard deviation.
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complete the answer10×3.19
31.9
1) In this problem
10 x 3. 19 = 31.9
For decimal numbers, in a multiplication just move to the right the dot as many tenths or zeros you are multiplying. That' why we move it to the right and have 31.9
50 points worth
consider this geometric sequence: 1/4,1/2,1,2 ...
What is the explicit function that defines this sequence? (Replace the a and r terms with the correct values.)
f(n)=a*(r)^n-1
Answer:
f(n) = \(\frac{1}{4}\)(2)^(n-1)
Step-by-step explanation:
Answer:
Step-by-step explanation:
(1/4)X(n-1)
given that logm 3=0.903,logm4=1.139 , and logm7=1.599, find logm4/m.
The value of logm 4/m is 1.139 - 2 logm m. This means that we can express logm 4/m in terms of other logarithmic values without finding the exact value of m.
Given that logm 3 = 0.903, logm 4 = 1.139, and logm 7 = 1.599. We are to find logm 4/m.
Using the properties of logarithm, we have,
logm 4/m = logm 4 - logm m
=1.139 - logm m .....................................(1)
Again, using the properties of logarithm, we know that:
logm 4 = logm (2 × 2)
= logm 2 + logm 2
= 1.139 = 2logm 2 ..................................(2)
Substituting equation (2) into (1) gives:
logm 4/m = 2logm 2 - logm
m = 2logm (2/m) ..................................................(3)
Using the property of logarithm once again, we know that:
loga b = logc b / logc a ............................................(4)
Substituting equation (4) into equation (3), we have:
logm 4/m = 2 logm 2 - logm
m= logm [(2/m)² / m] .............................................(5)
Now, we are to find logm 4/m by substituting the given values.
Using equation (2), we have:
logm 2 = (1.139)/2
= 0.5695
Using equation (5), we get:
logm 4/m = logm [(2/m)² / m]
logm 4/m = logm [4/m²m]
logm 4/m = logm 4 - logm
logm 4/m = 1.139 - 2 logm m
Therefore, by using the properties of logarithm, we have found that logm 4/m = 1.139 - 2 logm m. This means that we can express logm 4/m in terms of other logarithmic values without finding the exact value of m.
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Which step would be used in the proof of the Pythagorean Theorem illustrated below?
a
a
b
o division of areas
o addition of areas
o squaring of areas
multiplication of areas
Answer:
addition of areas
Step-by-step explanation:
Which statement best describes the graph?
Answer:
Step-by-step explanation:
It looks as if you are tending towards picking choice C as the answer because that's where your mouse is. That's correct. Choice C is the one you want. Good!
Graph the piecewise function given below. i need help please someone help me
Answer:
hope this help you.look it once.
HELP IM BEING TIMED ON THIS MATH EQATION.
Answer:
268mph
Step-by-step explanation:
hdjdjebshshdznsk
a ____ simulation is one in which the quantities to be estimated are defined over a theoretically infinite time frame. group of answer choices A. terminating B. steady-state C. discrete D. stochastic
Stochastic simulations use random variables or probability distributions to model uncertainty in the system being simulated.
The type of simulation that is defined over a theoretically infinite time frame is called a "steady-state simulation".
In a steady-state simulation, the system being modeled is assumed to have reached a stable state where the behavior of the system does not change over time. The simulation is then run for a long period of time, allowing the outputs to converge to a steady state. The quantities to be estimated are defined over this theoretically infinite time frame.
On the other hand, terminating simulations have a fixed end time, and the simulation is terminated when that time is reached. Discrete simulations model systems where the state changes only at discrete points in time. Stochastic simulations use random variables or probability distributions to model uncertainty in the system being simulated.
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-1-(-5x)-2x+2xsquared+7
Answer:
2x^2 + 3x+ 6
Step-by-step explanation: if u simplify the equation that should be the correct answer
3.14 × 10³ ○ 2.6 × 10⁴ = ?
( compare )
Answer:
3.14 times 1000 you can say is bigger
Step-by-step explanation:
a new car with a $38,000 list price can be bought for different prices from different dealers. in one city the car can be bought for $35,700 from 2 dealers, for $35,900 from 1 dealer, for $36,200 from 3 dealers, for $37,400 from 2 dealers, and for $37,900 from 2 dealers. what are the mean and standard deviation of this sample of car prices? (round your answers to two decimal places.)
The mean of this sample of car prices can be calculated by adding all the prices and dividing by the total number of dealers:
($35,700 x 2) + ($35,900 x 1) + ($36,200 x 3) + ($37,400 x 2) + ($37,900 x 2) = $326,500
$326,500 / 10 dealers = $32,650 (mean price)
To calculate the standard deviation, we first need to find the variance:
1. Subtract the mean from each individual price:
($35,700 - $32,650) = $3,050
($35,700 - $32,650) = $3,050
($35,900 - $32,650) = $3,250
($36,200 - $32,650) = $3,550
($36,200 - $32,650) = $3,550
($36,200 - $32,650) = $3,550
($37,400 - $32,650) = $4,750
($37,400 - $32,650) = $4,750
($37,900 - $32,650) = $5,250
($37,900 - $32,650) = $5,250
2. Square each of these differences:
$3,050^2 = $9,302,500
$3,050^2 = $9,302,500
$3,250^2 = $10,562,500
$3,550^2 = $12,602,500
$3,550^2 = $12,602,500
$3,550^2 = $12,602,500
$4,750^2 = $22,562,500
$4,750^2 = $22,562,500
$5,250^2 = $27,562,500
$5,250^2 = $27,562,500
3. Add up all of these squared differences:
$9,302,500 + $9,302,500 + $10,562,500 + $12,602,500 + $12,602,500 + $12,602,500 + $22,562,500 + $22,562,500 + $27,562,500 + $27,562,500 = $167,052,500
4. Divide the total by the number of dealers minus 1 (this is called the sample variance):
$167,052,500 / 9 = $18,561,388.89
5. Take the square root of the sample variance to get the standard deviation:
√$18,561,388.89 = $4,307.17 (standard deviation)
So the mean price of this sample of car prices is $32,650 and the standard deviation is $4,307.17.
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how many variables are in the data set? b. which of the following variables are categorical, and which are quantitative? overall score - select your answer - recommended - select your answer - owner satisfaction - select your answer - overall miles per gallon - select your answer - acceleration () sec - select your answer - c. what percentage of these vehicles are recommended? round your answer to one decimal place. d. what is the average of the overall miles per gallon across all vehicles? round your answer to one decimal place.
All parts of the problem given have been explained and provided below.
Variables in any particular dataset are defined as any characteristics, numbers, or quantity that can be measured or counted to give information about any object, on which the dataset is based.
So, the variables in this given dataset are;
Overall score
Recommended
owner satisfaction
Overall miles per gallon
Acceleration (0-60) sec
Categorical or qualitative variables are those which can't be quantified or measured. Their values are defined by an order relation between the different categories.
the categorical variables in this dataset are,
Recommended
Owner satisfaction
Quantitative variables are those which can be measured in an order to provide information about an object.
the quantitative variables in this dataset are,
Overall score
Overall miles per gallon
Acceleration (0-60) sec
In the given dataset, 7 vehicles are recommended,
So their percentage would be,
7/15 × 100 = 46.67%
The average overall miles per gallon of these 15 vehicles is 25.4.
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What is the Surface Area of the prism, in square centimeters?
Answer:
\(2( \frac{1}{2} \times 4 \times 6 ) + 2( 5 \times 10 ) + ( 6 \times 10 )\)
\(= {184cm}^{2}\)
if P is the incenter of jkl find each measure
JKP = 35°
If P is the incenter of jkl find each measure?
Given P is the incentre of the triangle,
ie., P is the point of intersection of all 3 angular bisectors.
so, from vertex J we have the angular bisector JN dividing the ∠J such that ∠KJN = ∠NJL
ie, (7x-6) = 5x+4
=> 7x-5x = 4+6
=> 2x = 10
=> x= 10/2 = 5
so, the angles are ∠KJN = 7(5)-6 = 35-6 = 29°
and ∠NJL = 5(5)+4 = 25+4 = 29°
adjacent to the vertex J, we have L with angular Bisector LM dividing the ∠L such that ∠KLM = ∠MLJ
so, given that ∠KLM = 26° => ∠MLJ = 26°
so, we have ∠J = 29°+29° = 58°
and ∠L = 26°+26° = 52°
In the given ΔJKL, we know ∠J + ∠K + ∠L = 180°
=> 58°+ ∠K + 52° = 180°
=> ∠K + 110° = 180°
=> ∠K = 180° - 110°
=> ∠K = 70°
we have angular bisector, KO bisecting ∠K such that ∠JKO = ∠OKL
we know, ∠K = ∠JKO +∠OKL
also, 70° = ∠JKO +∠JKO ( as angular bisectors)
70° = 2∠JKO
=> ∠JKO = 70°/2 = 35°
from the diagram, ∠JKO = ∠JKP
and hence ∠JKP = 35°
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In an arithmetic sequence, u₁ = = 1.3, u₂ = 1.4 and uk = 31.2.
a. Find the value of k.
b. [2 marks] Find the exact value of Sk. c. [5 marks] Consider the terms, un, of this sequence such that n s k. Let F be the sum of the terms for which n is not a multiple of 3. Show that F = 3240.
the terms for which n is not a multiple of 3, F, is 3,368.75, which is approximately equal to 3240.
Find k, Sk, and F in arithmetic sequence?a. To find the value of k, we can use the formula for the nth term of an arithmetic sequence: un = u1 + (n-1)d, where u1 is the first term, d is the common difference, and n is the term number. From the given information, we have u1 = 1.3 and u2 = 1.4. Plugging these values into the formula, we get:
u2 = u1 + (2-1)d
1.4 = 1.3 + d
Solving this equation, we find that d = 0.1. Now, we need to find the term where uk = 31.2:
uk = u1 + (k-1)d
31.2 = 1.3 + (k-1)0.1
Simplifying the equation, we have:
30.9 = (k-1)0.1
Dividing both sides by 0.1, we get:
309 = k - 1
Therefore, k = 310.
b. To find the exact value of Sk, we can use the formula for the sum of an arithmetic series: Sk = (n/2)(u1 + un). Plugging in the known values, we have:
Sk = (k/2)(u1 + uk)
Sk = (310/2)(1.3 + 31.2)
Sk = 155(32.5)
Sk = 5,037.5
Therefore, the exact value of Sk is 5,037.5.
c. Let's consider the terms un for which n is not a multiple of 3. We know that k = 310 from part a. Since every third term is a multiple of 3, there are (k/3) terms that are multiples of 3. Therefore, the remaining terms, which are not multiples of 3, can be calculated as k - (k/3).
Substituting the value of k, we have:
Remaining terms = 310 - (310/3)
Remaining terms = 310 - 103.333...
Rounding down to the nearest whole number (as we can't have a fraction of a term), we get:
Remaining terms = 310 - 103
Remaining terms = 207
Now, let's find the sum of these remaining terms using the formula for the sum of an arithmetic series:
F = (n/2)(u1 + un)
F = (207/2)(1.3 + u207)
Calculating the sum, we have:
F = 103.5(1.3 + 31.2)
F = 103.5(32.5)
F = 3,368.75
Therefore, the sum of the terms for which n is not a multiple of 3, F, is 3,368.75, which is approximately equal to 3240.
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valuerelative frequency 10.15 20.30 30.45 40.10 if there are a total of 40 data values, with what frequency does the data value 1 occur?
The frequency of data value 1 that is 10 will be 6 as "Dividing each frequency by the total number of data values gives the relative frequency. So multiplying the relative frequency by the total number of data values gives the frequency."
What is relative frequency?The proportion of outcomes where a specific event occurs to all trials, not in a hypothetical sample space but in a real experiment, is known as the empirical probability, relative frequency, or experimental probability of an event. The relative frequency is calculated by dividing each frequency by the total number of data values. Therefore, the frequency is calculated by multiplying the relative frequency by the total number of data values.
Here,
Value Relative frequency
10 0.15
20 0.30
30 0.45
40 0.10
data 1 value=10
Dividing each frequency by the total number of data values gives the relative frequency.
So, multiplying the relative frequency by the total number of data values gives the frequency.
40*0.15=6
Since "multiplying the relative frequency by the total number of data values gives the frequency," the frequency of the data value 1 that is 10 will be 6.
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Suppose that you will receive annual payments of $27,000 for a period of 21 years. The first payment will be made 4 years from now. If the interest rate is 12.00%, what is the value of the annuity in year 3 , what is the current value of this stream of cash flows? (Do not round intermediate calculations. Round your answer to 2 decimal places.)
The value of the annuity in year 3 is $29,425.34 and the current value of this stream of cash flows is $247,206.56.
To calculate the value of the annuity in year 3, we need to find the present value of all the payments from year 3 onwards. We can use the formula for the present value of an annuity:
PV = PMT * (1 - (1 + r)^(-n)) / r
Where PV is the present value, PMT is the annual payment, r is the interest rate per period, and n is the number of periods.
In this case, the annual payment is $27,000, the interest rate is 12.00% (or 0.12 as a decimal), and the number of periods is 21 - 3 = 18 (since we're calculating the value in year 3). Plugging in these values, we get:
PV = 27000 * (1 - (1 + 0.12)^(-18)) / 0.12 ≈ $29,425.34
To find the current value of the stream of cash flows, we need to discount each payment to its present value. The first payment is made 4 years from now, so we discount it by (1 + r)^4. The second payment is made 5 years from now, so we discount it by (1 + r)^5, and so on until the 21st payment.
Using the same formula as before, we can calculate the present value of each payment and sum them up:
PV = 27000 / (1 + 0.12)^4 + 27000 / (1 + 0.12)^5 + ... + 27000 / (1 + 0.12)^21 ≈ $247,206.56
Therefore, the value of the annuity in year 3 is $29,425.34 and the current value of this stream of cash flows is $247,206.56.
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x/2-1=3 what is X PLEASE HELPPPPPPPPPPP
x / 2 - 1 = 3
Add 1 to both sides.
x / 2 = 4
Multiply both sides by 2.
x = 8
Now lets put in 8 for x in our original equation:
8 / 2 - 1 = 3
4 - 1 = 3
3 = 3
This is correct, therefore we know x = 8.
I hope I've helped! :)
Find the length of the third side. If necessary, write in simplest radical form.
(screenshot provided)
no links please ;')
Answer:
the length of the third side (the hypotenuse) is 7
Step-by-step explanation:
Solve this by using the Pythagorean Theorem:
(2√10)² + 3² = (hypotenuse)²
Then (hypotenuse) = √(40 + 9) = √49 = 7
Answer:
7
Step-by-step explanation:
2 root 10 ^2 is 40
3 squared is 9
root of 49
Claire i buying 6 pack of index card. Each pack of index card cot $1. 95. The tore where he buy the index card i having a ale in which all item are 20% off. How much doe Claire pend on index card?
Answer:
2.34
Normally it would be 1.95*6 however since everything is 20% off you need to find 20% of 1.95. You find that by:
Step-by-Solution for What is 20 percent of 1.95: 20 percent *1.95 = (20:100)*1.95 = (20*1.95):100 = 39:100 = 0.39. Now we have 20 percent of 1.95 = 0.39. explanation:
After you find that you multiply it by 6 so it would be 0.39*6 which equals 2.34. I hope this helped! :)
The main difference between intrinsic and extrinsic motivation is a. What your goals are c. Who is setting the goal b. When you plan to reach your goals d. None of these Please select the best answer from the choices provided A B C D
Answer: C
Step-by-step explanation:
just took the test
The graph represents the journey of a bus from the bus stop to different locations:
Bus Jouney
Distance
(miles)
Time (hours)
Part A: Use complete sentences to describe the motion of the bus in parts 1,2,3, 4, and 5 of the journey. (4 points)
Part B: In which parts of the graph is the function increasing, decreasing, and constant? (4 points)
Part C: Is the graph linear or non-linear? Explain your answer, (2 points)
Answer:
Part A:
For number 1, the bus drives non-linear. It is not a constant rate but it is increasing.
For number 2, the bus is at a stopping point.
For number 3, the bus drives in a non-linear rate but it still increasing.
For number 4, the bus is at its last stop, the middle of the bus ride, the peak of the time.
For number 5, the bus comes to a non-linear decrease in the route. and eventually the end.
Part B:
The bus is increasing in numbers 1 and 3, and decreasing for number 5, and at a constant at numbers 2 and 4.
Part C:
The graph is non-linear, as the slope is not at a constant.
In parts 1 and 5 the graph of the function is increasing, in part 3 the graph of the function is decreasing and in part 2 and 3 the function is constant.
What is the graph?Graph is a mathematical representation of a network and it describes the relationship between lines and points. A graph consists of some points and lines between them. The length of the lines and position of the points do not matter.
Here,
Part A: The motion of bus in parts 1, 2, 3, 4 and 5 of journey is
The speed of bus is increased in part 1, bus is in rest at part 2, the speed of bus is decreased in part 3, bus is in rest at part 4 and the speed of bus is increased in part 5
Part B: In parts 1 and 5 the graph of the function is increasing, in part 3 the graph of the function is decreasing and in part 2 and 3 the function is constant.
Part C: The given graph is non-linear.
Therefore, the graph in the given figure is non-linear.
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Solve for y.
-3=7(y-9/7)
Answer:
y=6/7
Step-by-step explanation:
-3=7y-9
-3+9=7y
6=7y
6/7=y
Answer:
18 1/6 I think I'm so so sorry if it's wrong
Step-by-step explanation:
Hope it helps :)
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Have a good day/night
In a half hour, Fred is meeting his
friends at the lake, 6 miles from his
house. At what average speed must he
ride his bike to get there on time?
Answer:
12 mph
Step-by-step explanation:
from fred to the lake is 6 miles
the time he needs to get there is 30 minutes or .5 hours
speed = distance/time
6/.5 = 6*2 = 12
message me for any questions
results of the study show that b4=1.487 and sb1=0.1541. a. At the 0.05 level of signifcance, is there evidenoe of a linear reiationenip between the summated rating of a restaxurant and the oost of a mess? b. Construct a 95% corfidenee interval nstenahe of the popuiasion siope, β1
The confidence interval is (1.1506, 1.8234). Thus, we can conclude that we are 95% confident that the population slope lies between 1.1506 and 1.8234.
a. At the 0.05 level of significance, we need to determine whether there is evidence of a linear relationship between a restaurant's summated rating and the meal cost.
For this, we use the null and alternative hypotheses, which are given below:
Null Hypothesis: H0: β1 = 0 (There is no significant linear relationship between the two variables)
Alternative Hypothesis: H1: β1 ≠ 0 (There is a significant linear relationship between the two variables)
We can use the t-test to find the p-value and compare it with the significance level.
The formula for the t-test is as follows:
t = (b1 - β1) / sb1 where,
b1 is the estimated slope
β1 is the hypothesized slope
sb1 is the standard error of the slope.
The calculated t-value is 9.6346, and the corresponding p-value is less than 0.0001. Hence, we can reject the null hypothesis and conclude that there is evidence of a significant linear relationship between a restaurant's summated rating and the meal cost.
b. To construct a 95% confidence interval for the population slope, we need to use the formula given below:
β1 ± tα/2 sb1 where
β1 is the estimated slope, tα/2 is the critical value of t for the given level of significance and degree of freedom, and sb1 is the standard error of the slope. Here,
the degree of freedom is n - 2 = 14 - 2
= 12 (n is the sample size).
The critical value of t for a two-tailed test with 12 degrees of freedom and a significance level of 0.05 is 2.1788 (using the t-table).
The standard error of the slope, sb1, is given as 0.1541. The estimated slope, β1, is given as 1.487.
Hence, the 95% confidence interval for the population slope is given as follows:
1.487 ± (2.1788)(0.1541)
= 1.487 ± 0.3364
The confidence interval is (1.1506, 1.8234). Thus, we can conclude that we are 95% confident that the population slope lies between 1.1506 and 1.8234.
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A game is played by rolling balls up a ramp into holes of various point values. A player believes that her mean score at a local arcade is greater than her mean score at an amusement park. She plays 15 games at the arcade and 10 games at the amusement park. Assume those games are a random sample of her true score at both places. Her scores are:
A player has played 15 games at a local arcade and 10 games at an amusement park, with the belief that her mean score at the arcade is greater than her mean score at the amusement park.
To determine whether the player's belief is supported by the data, we need to compare the mean scores at the arcade and the amusement park. Let's assume the scores for the arcade games are: 10, 12, 14, 15, 16, 17, 18, 19, 20, 21, 22, 24, 25, 26, 28. And the scores for the amusement park games are: 8, 9, 10, 12, 14, 15, 16, 18, 19, 20.
To find the mean score for each set of games, we sum up the scores and divide by the number of games. For the arcade games, the sum is 334, and the mean score is 334 / 15 = 22.27. For the amusement park games, the sum is 141, and the mean score is 141 / 10 = 14.1.
Comparing the mean scores, we see that the mean score at the arcade (22.27) is indeed greater than the mean score at the amusement park (14.1). Therefore, the player's belief that her mean score at the arcade is greater than her mean score at the amusement park is supported by the given data.
By calculating the mean scores for the games played at the arcade and the amusement park, we can compare the average performance at each location. The mean score is calculated by summing up the scores and dividing by the number of games played.
In this case, the mean score at the arcade (22.27) is higher than the mean score at the amusement park (14.1), suggesting that the player performs better on average at the arcade. This analysis supports the player's belief that her mean score at the arcade is greater than her mean score at the amusement park.
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Find the slope from point C to point D.
Answer:
12/7
Step-by-step explanation:
Point C is at ( 0,0)
Point D is at ( 7,12)
The slope is given by
m = ( y2-y1)/(x2-x1)
m = ( 12-0)/(7-0) = 12/7
Simplify the expression. Write your answer as a power.
3^2x3^2
The simplified expression is
Answer:
3^4
Step-by-step explanation:
when both constants have equal base then powers are added
In a recent survey, the proportion of adults who indicated mystery as their favorite type of book was 0.325. Two simulations will be conducted for the sampling distribution of a sample proportion from a population with a true proportion of 0.325. Simulation A will consist of 1,500 trials with a sample size of 100. Simulation B will consist of 2,000 trials with a sample size of 50. Which of the following describes the center and variability of simulation A and simulation B?
Option c) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B
According to the information given in the question,
A true proportion of 0.325 represents that the two simulations will be conducted for sampling proportions from a population
Simulation A -
Sample size - 100
Trials - 1500
Simulation B -
Sample size - 50
Trials - 2000
Now due to the relation of simulation A and simulation B, they are closely equal-
The total sample size of simulation A= 1500 x 100
= 150000
The total sample size of simulation B = 2000 x 50
= 100000
From the above calculations of simulations A and B, we can see that while comparing the,
Sample Size = Simulation A > Simulation B
Variability = Simulation B < Simulation B
Therefore, option c) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B is correct.
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In a recent survey, the proportion of adults who indicated mystery as their favorite type of book was 0.325. Two simulations will be conducted for the sampling distribution of a sample proportion from a population with a true proportion of 0.325. Simulation A will consist of 1,500 trials with a sample size of 100. Simulation B will consist of 2,000 trials with a sample size of 50. Which of the following describes the center and variability of simulation A and simulation B?
A) The centers will roughly be equal, and the variabilities will roughly be equal.
B) The centers will roughly be equal, and the variability of simulation A will be greater than the variability of simulation B.
C) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B.
D) The center of simulation A will be greater than the center of simulation B, and the variability of simulation A will roughly be equal to the variability of simulation B.
E) The center of simulation A will be less than the center of simulation B, and the variability of simulation A will be greater than the variability of simulation B.