Complete the following reaction: Li + S -->

Answers

Answer 1

Answer:

Li2S

Explanation:

Hope this helps.

Answer 2

Answer:

can u do an real answer pls so i can help u thanks


Related Questions

74.5 g C2H6O in 2.31 L of solution

Answers

Hi! Are you looking for molarity?

How do chemicals affect our lives? O A. Chemicals have made our lives much harder. B. Chemicals make our daily lives more dangerous. O C. Chemicals have made it possible for us to own less. O D. Chemicals have made many things easier.​

Answers

Answer:

the answer is d

Answer:

D

Explanation:

Because they are many different types of chemicals some are dangerous but some are applicable to use . chemicals help to wash germs away so we can live in a healthy environment.

The complex ion Cu(NH3)42+ is formed in a solution made of 0.0200 M Cu(NO3)2 and 0.300 M NH3. What are the concentrations of Cu2+, NH3, and Cu(NH3)42+ at equilibrium? The formation constant*, Kf, of Cu(NH3)42+ is 1.70 × 1013.

Answers

The concentrations  Cu(NH3)42+ at equilibrium is  [Cu(NH3)42+] = 1.70 × 1013 * (0.0200M) * (0.300M)^4.

The concentrations  of Cu2+ is [Cu(NH3)42+] + [Cu2+]

The concentrations  of NH3 is 4[Cu(NH3)42+] + 4[NH3]

What is concentration equilibrium?

Equilibrium concentration is described as a state when the rate of forward reaction in a chemical reaction becomes equal to the rate of backward reaction.

The equilibrium constant expression for the formation of the complex ion Cu(NH3)42+ is:

Kf = [Cu(NH3)42+] / [Cu2+] * [NH3]^4

where [Cu(NH3)42+], [Cu2+], and [NH3] are the molar concentrations at equilibrium.

The initial concentrations of Cu2+ and NH3 are 0.0200 M and 0.300 M respectively.

We have that Kf = 1.70 × 1013, we then  rearrange the equation to solve for [Cu(NH3)42+]:

1.70 × 1013 = [Cu(NH3)42+] / (0.0200M) * (0.300M)^4

[Cu(NH3)42+] = 1.70 × 1013 * (0.0200M) * (0.300M)^4

Therefore at equilibrium, the concentration of Cu(NH3)42+ is [Cu(NH3)42+] = 1.70 × 1013 * (0.0200M) * (0.300M)^4

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The diagram above represents four cations, all shown to the same scale. Which cation would be predicted by Coulomb's law to have the strongest ion dipole attraction to water and why?
A Li⁺, because it is the smallest group 1 metal ion.
B) Mg², because it has the largest charge to-size ratio.
c Na'', because it has the smallest charge to-sice ratio;
D) Ca²⁺, because it is the largest group 2 metal ion.

The diagram above represents four cations, all shown to the same scale. Which cation would be predicted

Answers

The cation that would be predicted by Coulomb's law to have the strongest ion-dipole attraction to water is Mg²⁺, because it has the largest charge-to-size ratio.

What are cations?

Cations are positively-charged ions that are formed when metal atoms lose electrons.

The size of the charge on a cation describes the number of electrons the metal ions loses.

The size of the charge of a cation will determine the strength of the attraction between the ion and another charged particle.

According to Coulomb's law, the strength of the attractive force is proportional to the charge and inversely proportional to the square of the distance between the charged particles.

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15 grams of copper (II) chloride react with 20 grams of sodium nitrate If 11.3 grams of sodium chloride are formed in the reaction, what is the percent yield of this reaction? CuCl2+2NaNO3=Cu(NO3)2+2NaCl

Answers

Answer

The percent yield for the reaction = 81.88%

Explanation

Given:

Mass of CuCl2 = 15 grams

Mass of NaNO3 = 20 grams

Actual yield of NaCl = 11.3 grams

Equation: CuCl₂ + 2NaNO₃ ----> Cu(NO₃)₂ + 2NaCl

What to find:

The percent yield for the reaction.

Step-by-step solution:

Step 1: Covert the given grams to moles.

Molar mass of CaCl₂ = 110.98 g/mol

Molar mass of NaNO₃ = 84.995 g/mol

The mass of the reactants can be converted to moles using the mole formula

\(Mole=\frac{Mass}{Molar\text{ }mass}\)

Moles of CaCl₂

\(Mole=\frac{15g}{110.98\text{ }g\text{/}mol}=0.1352\text{ }mol\text{ }CaCl_2\)

Moles of NaNO₃ is

\(Mole=\frac{20\text{ }g}{84.995\text{ }g\text{/}mol}=0.2353\text{ }mol\text{ }NaNO₃\)

Step 2: Determine the limiting reactant.

From the equation, 1 mole CaCl₂ required 2 moles NaNO

So 0.1352 moles CaCl₂ will require (0.1352 x 2)/1 = 0.2704 moles NaNO

Note that the moles present in 20 grams NaNO₃ is 0.2353 mol, but 0.2704 mol NaNO₃ is needed to consume all the 0.1352 mol CaCl₂. This implies NaNO is the limiting reactant and CaCl₂ is the reactant in excess.

Step 3: Calculate the theoretical yield for the reaction.

From the equation, 2 moles NaNO₃ produce 2 moles NaCl

Therefore 0.2353 moles NaNO₃ will produce

\(\frac{0.2353mol\text{ }NaNO_3\times2mol\text{ }NaCl}{2mol\text{ }NaNO_3}=0.2353\text{ }mol\text{ }NaCl_\)

Step 4: Convert 0.2353 mol NaCl to mass.

Molar mass of NaCl = 58.44 g/mol

So 0.2353 mol = Mass/58.44 g/mol

Mass = 0.2353 mol x 58.44 g/mol

Mass of NaCl = 13.8 grams

Step 3: Determine the percent yield of the reaction.

The percent yield of the reaction can be calculated using the formula

\(Percent\text{ }yield=\frac{Actual\text{ }yield}{Theoretical\text{ }yield}\times100\%\)

Actual yield of NaCl = 11.3 grams

Theoretical yield of NaCl = 13.8 grams

Thus,

\(Percent\text{ }yield=\frac{11.3\text{ }grams}{13.8\text{ }grams}\times100\%=81.88\%\)

The percent yield for the reaction = 81.88%

if you start with 55.5 mL of 1.30 M HG and you dilute it due to 188.5 mL what is the new molarity

Answers

Answer:

\(\huge\boxed{\sf M_2 \approx 0.38 \ M}\)

Explanation:

Given data:

Initial volume = \(V_1\) = 55.5 mL

Initial Molarity = \(M_1\) = 1.3 M

Final volume = \(V_2\) = 188.5 mL

Required:

Final Volume = \(V_2\) = ?

Formula:

\(M_1V_1 = M_2V_2\)

Solution:

Put the given data.

Finding new molarity.

\((55.5)(1.3)=(188.5)(M_2)\\\\72.15 = 188.5 (M_2)\\\\Divide \ both \ sides\ by \ 188.5\\\\72.15/188.5 = M_2\\\\M_2 \approx 0.38 \ M\\\\\rule[225]{225}{2}\)

What mass of NaCl is needed to produce a 26.4 mol/L with a 1.7 L volume?

Answers

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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[H+] [OH-] =

NEED HELP ASAP!!!

Answers

Hopes this helps:

Answer: h^2o

If this doesn’t help than I am so sorry that I couldn’t help.

The muscles of the body are part of the musculoskeletal system but would not operate without the
impulses that cause the muscles to act.
A cardiovascular
B. respiratory
C nervous
D reproductive

Answers

Answer:

C

Explanation:

The nervous system sends signals, or in this case, impulses to parts of your body that direct them to move.

If the student’s estimate of the balloon’s volume was incorrect and the actual volume was 620 ml, would the amount of glucose that actually reacted be more than or less than the amount calculated in part (c)? Explain your response.

( C answer ) only 1.9 g of glucose reacted and only .0211 mol of co2 was formed.

If the students estimate of the balloons volume was incorrect and the actual volume was 620 ml, would

Answers

The number of moles of CO2 produced is 0.021 moles

If the estimated volume of the balloon is wrong then the amount of glucose reacted must be more than is stated.

What is respiration equation?

The respiration equation represents the chemical process of aerobic cellular respiration, which occurs in the mitochondria of cells and is the primary way in which cells generate energy in the form of ATP (adenosine triphosphate).

The equation of the reaction is;

C6H12O6 + 6O2 → 6CO2 + 6H2O + ATP

We know that;

Number of moles of glucose = 10 g/180 g/mol

= 0.056 moles

PV = nRT

n = PV/RT

n = 1 * 0.55/318 * 0.082

n = 0.021

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Mining companies use this reaction to obtain iron from iron ore:
Fe2O3(s) + 3 CO(g) – 2 Fe(s) + 3 CO2(8)
The reaction of 167 g Fe2O3 with 85.8 g CO produces 72.3 g Fe. Determine the limiting reactant, theoretical yield, and
percent yield.

Answers

The limiting reactant, theoretical yield, and percent yield would be CO, 114.035 g, and 63.4% respectively.

From the balanced equation of the reaction:

\(Fe_2O_3_{(s)} + 3 CO_{(g)} ---> 2 Fe_{(s)} + 3 CO_2_{(g)}\)

1 mole of Fe2O3 requires 3 moles of CO

mole of Fe2O3 = mass/molar mass

                        = 167/159.69

                         = 1.046 moles

mole of CO = 85.8/28.01

                      = 3.063 moles

1 mole Fe2O3 = 3 moles CO

1.046 moles Fe2O3 = 3 x 1.046

                                = 3.138 moles of CO

3.138 moles of CO is required but only 3.063 is available. Thus, the limiting reactant is CO.

Theoretically,

1 mole Fe2O3 = 3 moles CO = 2 moles Fe

With only 3.063 moles of CO available, moles of Fe produced would be

  = 3.063x 2/3

         = 2.042 moles of Fe

Mass of 2.042 Fe = 2.042 x 55.845

                  = 114.035 g

Hence, theoretically, 114.035 g of Fe should be produced.

Percent yield = actual yield/theoretical yield x 100

                      = 72.3/114.035 x 100

                          = 63.4%

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Determine which of the following electron configurations are not valid:
1.) 1s²2s²2p 3s 3p 4s²4d¹04p5
2.) 1s²2s²2p 3s³3d5
3.) [Ra] 7s²5f8
4.) [Kr] 5s24d105p5

Answers

The electron configurations that are not valid among the options are 1s²2s²2p 3s 3p 4s²4d¹04p5 and 1s²2s²2p 3s³3d5. Options 1 and 2.

Electron configurations

The electron configuration of atoms using the various orbital levels follows the order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p.

Also, according to Afbau principle, orbitals with low energy levels are filled with electrons before orbitals with higher energy levels.

Using the above,  1s²2s²2p 3s 3p 4s²4d¹04p5 is incorrect for some reasons:

4d, a higher energy level orbital, comes before 4p. 3s and 3p, lower energy level orbitals have no electrons in them while higher energy level orbitals have electrons in them.

1s²2s²2p 3s³3d5 is incorrect because:

a lower energy level orbital, 2p is not filled before a higher energy orbital, 3s.3p and 4s orbitals should come before 3d orbital.

The remaining electron configurations are correct with correctly placed electrons in the various orbitals.

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You come across the following container while working in the lab: Answer the following questions in the space below: 1. Identify the WHMIS symbols. 2. What precautions should you take and why?​

Answers

Type #1 Flame symbols are among the WHMIS emblems.

Type 2: Symbols with a flame above a circle.

Exploding bomb symbols are of type 3.

Compressed gas symbols are of type 4.

Corrosion symbols are type #5.

Skull and water the water symbols are type #6.

Exclamation mark symbols are type #7.

Health hazard symbols are type #8.

Because workplaces require a defined technique to detect hazardous items, WHMIS labels are crucial.

What does the WHMIS stand for?

The national ’s hazard standard for Canada is the Health And Safety At work System (WHMIS). Hazard categorization, cautionary container labeling, the distribution of safety data sheets, and worker information and training programs are the system's main components.

What does WHMIS look like in the US?

The U.S. Ohs Hazard Identification Standard and WHMIS are quite similar.

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800 j of heat absorbed by 120 g of water at 25 c, what is the final temperature at equilibrium

Answers

The final temperature at equilibrium will be approximately 26.525 °C.

How to determine the final temperature

To find the final temperature at equilibrium, we can use the equation:

Q = m * c * ΔT

Where:

Q = heat energy absorbed or released

m = mass of the substance

c = specific heat capacity of the substance

ΔT = change in temperature

In this case, 800 J of heat is absorbed by 120 g of water at 25 °C. We need to find the final temperature at equilibrium.

Using the equation for water:

Q_water = m_water * c_water * ΔT_water

Rearranging the equation, we can solve for the change in temperature (ΔT_water):

ΔT_water = Q_water / (m_water * c_water)

Substituting the given values:

ΔT_water = 800 J / (120 g * 4.18 J/g°C)

Calculating:

ΔT_water ≈ 1.525 °C

To find the final temperature at equilibrium, we add the change in temperature to the initial temperature:

Final temperature = 25 °C + 1.525 °C

Final temperature ≈ 26.525 °C

Therefore, the final temperature at equilibrium will be approximately 26.525 °C.

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Please help fast
All four referenced Greek thinkers: Democritus, Aristotle, Archimedes, and Anaxagoras, observed Nature and argued for his theory of
the composition of matter and natural laws. Only one of them tested his hypothesis and proposed a natural laws based on reproducible
observations, controlled experiments, and mathematical reasoning. All others used logic and thought experiments, as philosophers do,
to support their theories. Who is the experimental scientist in this group?
O Democritus
O Aristotle
O Archimedes
O Anaxagoras

Answers

Answer:

Anaxagoras was perhaps the first literate person to attempt to explain physical phenomena rationally, basing his ideas upon careful observations and simple experiments. This is fundamental to modern science and is the sine qua non of environmental study.

A container with a volume 2.0L is filled with a gas at a pressure of 1.5 atm. By decreasing the volume of the container to 1.0 L, what is the resulting pressure? Type in your answer using the correct number of significant figures . Remember to use formula for Boyles law; P1V1=P2V2

Need help with this question!!!

Answers

Answer:

P2 = 3

Explanation:

u know that:

V1 = 2.0L

P1 = 1.5 atm

V2 = 1.0L

P2 = ?        (p1v1=p2v2)

1.5x2 = P2x1.0

3=P2x1.0    =>> 3.0 =P2

divided both side by 1.0 the remove 1.0 (left P2)

The pressure by decreasing the volume to 1 L will be  \(P_2=3 \ atm\)  

what will be a new pressure?

The given data is that

Volume    \(V_1=2 \ Litres\)

Pressure  \(P_1=1.5\ atm\)

When volume is reduced to

\(V_2=1\ liters\)

By using Boyles Law

\(P_1V_1=P_2V_2\)

\(P_2=\dfrac{P_1V_1}{V_2}\)

\(P_2=\dfrac{2\times 1.5}{1} =3 \ atm\)

Thus the pressure by decreasing the volume to 1 L will be  \(P_2=3 \ atm\)  

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What information do the reduction potentials of two elements give about a redox reaction between those elements

What information do the reduction potentials of two elements give about a redox reaction between those

Answers

The reduction potentials of two elements provide information about the redox reaction between those elements, specifically regarding the process of oxidation and reduction. Option C

C. The reduction potentials indicate which element will be oxidized and which element will be reduced. In a redox reaction, one element undergoes oxidation, where it loses electrons, and another element undergoes reduction, where it gains electrons.

The reduction potential values of the elements can determine the relative tendencies for oxidation and reduction. The element with a higher reduction potential is more likely to be reduced (gain electrons), while the element with a lower reduction potential is more likely to be oxidized (lose electrons).

A. The reduction potentials also indirectly provide information about whether electrons will be gained or lost by the oxidized atom. Since oxidation involves the loss of electrons, the element with the lower reduction potential, which is more likely to be oxidized, is associated with electron loss.

Conversely, the element with the higher reduction potential, which is more likely to be reduced, is associated with electron gain.

B. The reduction potentials do not directly indicate which element is more commonly found in nature. The abundance or occurrence of elements in nature is unrelated to their reduction potentials.

D. The reduction potentials are not related to the electronegativity difference between the two elements. Electronegativity is a measure of an atom's tendency to attract electrons in a chemical bond and is distinct from reduction potential, which focuses on the tendency to undergo reduction or oxidation in a redox reaction.

Option C

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Describes the subatomic parts of the atom.

Answers

Subatomic particles include "Electrons", and those include the "heavier" building blocks of the nucleus of an atom, the electrically neutral neutrons and positively charged protons

At noon on a clear day, sunlight reaches the earth's surface at Madison, Wisconsin, with an average intensity of approximately 5.00 kJ·s−1·m−2. If the sunlight consists of photons with an average wavelength of 510.0 nm, how many photons strike a 7.60 cm2 area per second?

Answers

There are 2.08 x 10¹⁸ photons/sec.

Wave energy:

E = nhc/λ

3000 = (n x 6.63 x 10⁻³⁴ x 3 x 10⁸)/(510 x 10⁻⁹)

n = 7.69 x 10²¹ photons/sec/m²

2.70 cm² = 2.70 /10,000 m²

= 2.7 x 10⁻⁴

photons/sec = 7.69 x 10²¹ x 2.7 x 10⁻⁴

= 2.08 x 10¹⁸ photons/sec.

Hitting a square meter solar panel at right angles requires about 30,000 photons per second producing 1 watt of energy at 100% efficiency. The numbers obtained without assuming constant spectral power distribution and photon energy will be dealt with in a later post, but for now, we assume that a daylight standard D bulb at 5300 K will work around 11,000 Suffice it to say. Chemical reactions in the body not only release energy and produce heat, but they also release small amounts of photons, the elementary particles of light.

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The kinetic energy of a 23.2-g object moving at a speed of 98.7 m/s is ________ J. The kinetic energy of a 23.2-g object moving at a speed of 98.7 m/s is ________ J. 0.950 145 113 1450 113000

Answers

The kinetic energy of a 23.2-g object moving at a speed of 98.7 m/s is  113.30 J. Option D

The kinetic energy of an object can be calculated using the formula: KE = (1/2)mv^2, where KE is the kinetic energy, m is the mass of the object, and v is the velocity or speed of the object.

Given:

Mass (m) = 23.2 g = 0.0232 kg

Speed (v) = 98.7 m/s

Substituting these values into the formula, we can calculate the kinetic energy:

KE = (1/2)(0.0232 kg)(98.7 m/s)^2

KE = (1/2)(0.0232 kg)(9756.09 m^2/s^2)

KE ≈ 113.30 J

Therefore, the kinetic energy of a 23.2-g object moving at a speed of 98.7 m/s is approximately 113.30 J.

It's worth noting that the question is repeated twice, but the answer remains the same. The kinetic energy of the object is determined by its mass and speed, and both calculations yield the same result. Option D

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Consider the following reaction: 2N2O5(g) → 4NO2(g) + O2(g) Calculate the volume N2O5 that must decompose completely to produce 9.64 L nitrogen dioxide.​

Answers

The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.

The given chemical equation is \(2N_2O_5(g) \rightarrow 4NO_2(g) + O_2(g)\) .The volume of \(N_2O_5\) that decomposes completely to form 9.64 L of \(NO_2\) is to be calculated. For this, we can use the concept of stoichiometry. Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in a balanced chemical equation.To calculate the volume of \(N_2O_5\) that is needed to produce 9.64 L of \(NO_2\), we will first determine the number of moles of NO2 produced in the reaction. For this, we can use the ideal gas equation, PV = nRT. Here, we have the volume of NO2 and we can assume the pressure and temperature to be constant. Thus, we have PV = nRT, where P = pressure, V = volume, n = number of moles, R = ideal gas constant, and T = temperature. Substituting the given values in the ideal gas equation, we get,n = PV/RT = (1 atm × 9.64 L)/(0.0821 L atm K-1 mol-1 × 300 K) = 0.404 molFrom the chemical equation, we see that 2 moles of \(N_2O_5\) give 4 moles of \(NO_2\). Thus, 0.404 mol of \(NO_2\) must have been produced from (0.404/2) = 0.202 mol of \(N_2O_5\). Using the ideal gas equation, we can also find the volume of 0.202 mol of \(N_2O_5\) at the given conditions. Thus, V = nRT/P = (0.202 mol × 0.0821 L atm K-1 mol-1 × 300 K)/1 atm = 4.97 L. Thus, the volume of \(N_2O_5\) that must decompose completely to produce 9.64 L nitrogen dioxide is 4.97 L.

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a student investigated heat transfer using a bottle of water

Answers

The result of the Heat Transfer experiment is given as follows:  "The molecule was increased in kinetic energy but in a random structure." (Option B)

What is Heat Transfer?

Heat transfer is a thermal engineering subject that deals with the creation, consumption, conversion, and exchange of thermal energy across physical systems.

Heat transmission is categorized into several methods, including thermal conduction, thermal convection, thermal radiation, and energy transfer via phase shifts.

At 3 p.m., the water temperature is raised. The average kinetic energy of an item is related to its temperature. As a result, as temperature rises, so does average kinetic energy.

Kinetic energy is created by the random movement of molecules. Hence, the correct answer is "The molecule was increased in kinetic energy but in a random structure."

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Full Question:

A student investigated heat transfer using a bottle of water. The student placed the bottle in a room at  20.50C. The student measured the temperature of the water in the bottle at 7 a.m. and again at 3 p.m.  The data from the investigation are shown in the table below.

[See attached image]

Question:How would you describe the average kinetic energy of the water molecules in the bottle at 7 a.m. to  the average kinetic energy of the water molecules in the bottle at 3 p.m.

The molecules were increased in kinetic energy but in a uniform structure. The molecules were increased in kinetic energy but in a random structure. The molecules were decreased in kinetic energy but in a uniform structure. The molecules were decreased in kinetic energy but in a random structure.
a student investigated heat transfer using a bottle of water

Place the following compounds in order of decreasing strength of intermolecular forces. I. CH3CH2CH2CH2CH2CH3 II. (CH3)3CCH3 IIL (CH3)3CCH2CH3 1) C) II >III> I 2) Identify the compound with the lowest boiling point. A) CH3CN B) CH3CHO C) CH3CH2CH3 D) (CH3)20 E) CH3OCH3 2) 3) Place the following substances in order of increasing vapor pressure at a given temperature SF6 SiH4 SF4 3) A) SiH4

Answers

The following compounds in order of decreasing strength of intermolecular forces is as follows :

CH₃CH₂CH₂CH₂CH₂CH₃ > (CH₃)₃CCH₂CH₃ > (CH₃)₃CCH₃

1) The following compounds in order of decreasing strength of intermolecular forces is as follows : as the surface are decreases the intermolecular force decrease or as branching increases intermolecular forces decreases.

CH₃CH₂CH₂CH₂CH₂CH₃ > (CH₃)₃CCH₂CH₃ > (CH₃)₃CCH₃

2)  the compound CH₃CH₂CH₃ have the weaker van der wall forces and having the lowest boiling point.

3) the following substances in order of increasing vapor pressure at a given temperature is as follows :

SF₄  < SF₆   <  SiH₄  

SF₄ is the polar molecular and hs the lowest vapor pressure.

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32. If
represents an oxygen atom and
below about the following equation:
+

represents a hydrogen atom, pick the correct statement
A. The model is correct because it shows the same number of atoms on each side.
B. The model is correct because it shows the correct composition of water.
C. The model is incorrect because the structure of oxygen is incorrect.
D. The model is incorrect because the structure of water is incorrect.

Answers

Answer:

B

Explanation:

it is the correct composition of water

the name of the acid present in milk

Answers

Answer:

lactic acid

The real acidity of milk is due to lactic acid. This is never found in milk when it is first drawn from the udder. It is produced by the action of the lactic acid organisms on the milk sugar. The so-called apparent acidity of milk is what gives fresh milk its acid reaction.

the name of the acid present in milk

If a gas occupies 79.5 mL at -1.4°C, what temperature, in Kelvin, would it
have if the volume was reduced to 35.3 mL and the pressure is held constant?
constant?

Answers

Answer:

121 K

Explanation:

Step 1: Given data

Initial volume (V₁): 79.5 mLInitial temperature (T₁): -1.4°CFinal volume (V₂): 35.3 mL

Step 2: Convert "-1.4°C" to Kelvin

We will use the following expression.

K = °C + 273.15 = -1.4°C + 273.15 = 271.8 K

Step 3: Calculate the final temperature of the gas (T₂)

Assuming ideal behavior and constant pressure, we can calculate the final temperature of the gas using Charles' law.

V₁/T₁ = V₂/T₂

T₂ = V₂ × T₁/V₁

T₂ = 35.3 mL × 271.8 K/79.5 mL = 121 K

2HCI + Na₂CO3 → H₂O + CO₂ + 2NaCl
He mixes exactly 235.0 mL of 0.600 M HCI
with 7.472 g Na2CO3.
8.24 g NaCl form. What is the molar
concentration of the salt in the solution?
A. 4.29 x 10-4 M
B. 0.600 M
C. 0.429 M
D. 3.00 x 10 4M

Answers

The molar concentration of the salt is  0.600 M. Option B

What is the molar concentration of the salt?

We know that the term molar concentration has to do with the number of moles of the salt that is present in one liter of the solution. We have been given the mass of the salt that is formed, we need to obtain the number of moles of the salt that has been formed and use the volume of the solution that have been given in the question to find the molar concentration of the salt.

Mass of the salt = 8.24 g

Molar mass of the salt = 58.5 g/mol

Number of moles of the salt = mass/molar mass

=  8.24 g/ 58.5 g/mol

= 0.14 moles

Volume of the solution = 235.0 mL or 0.235 L

Molar concentration =  0.14 moles/ 0.235 L

= 0.595 M or  0.600 M

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Pick the correct answer!
1. Why does the octet rule apply primarily to main-group elements, not to transition metals?
a. The octet rule states that main-group elements tend to react so that they attain a halogen electron configuration.
b. The octet rule states that transition metal-group elements tend to react so that they attain a noble gas electron configuration.
c. The octet rule states that main-group elements tend to react so that they attain a ionic electron configuration. d. The octet rule states that main-group elements tend to react so that they attain a noble gas electron configuration.​

Answers

Answer:

I think it would be b. The octet rule states that transition metal group elements tend to react so that they attain a noble gas electron configuration.

What two options are homogeneous mixture

Answers

Answer:

vinegar and soap

Explanation:

Answer:

vinegar and soap

Explanation: just took the test

28 °℃ = __? __K
help.

Answers

Answer:

301.15 K

Explanation:

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