compare intracellular fluid and extracellular fluid with respect to chemical composition and location.

Considering the phase diagram, the state of matter that exists in area B is gas.

The correct option is A.

A phase diagram is a graphical representation that shows the conditions of temperature and pressure at which different phases or states of a substance exist.

The axes of a phase diagram typically represent temperature (usually on the horizontal axis) and pressure (usually on the vertical axis). The diagram is divided into regions that correspond to different phases, and the lines separating these regions represent phase boundaries.

The point where three phase boundaries meet is known as the triple point, which represents the temperature and pressure at which all three phases can coexist in equilibrium.

Learn more about phase diagrams at: https://brainly.com/question/28097253

#SPJ1

The rate constant for the decomposition of ethanol on an alumina surface is 24.00 × 10²⁵ M.

The rate law is: rate = 24.00 × 10²⁵ M/s

The integrated rate law is: [C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

If the initial concentration of C₂H₅OH was 1.25 × 10²² M, the half-life is 2.60 × 10⁻⁵ s.

The time required for all the 1.25 × 10²² M C₂H₅OH to decompose is 5.21 × 10⁻⁵ s.

Let's consider the decomposition of ethanol on an alumina surface.

C₂H₅OH(g) ⇒ C₂H₄(g) + H₂O(g)

The plot of [A] vs time (t) resulted in a straight line, which indicates that the reaction follows zero-order kinetics.

The slope, 24.00 × 10²⁵ M/s, represents the rate constant, k.

It is a chemical reaction in which the rate of reaction is constant and independent of the concentration of the reacting substances

The rate law for zero-order kinetics is:

rate = 24.00 × 10²⁵ M/s

The integrated rate law for zero-order kinetics is:

[C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

Is the time for the amount of substance to decrease by half.

If the initial concentration of C₂H₅OH was 1.25 × 10²² M, we can calculate the half-life [t(1/2)] using the following formula.

t(1/2) = [C₂H₅OH]₀ / 2 × k

t(1/2) = (1.25 × 10²² M) / 2 × (24.00 × 10²⁵ M/s) = 2.60 × 10⁻⁵ s

We can calculate the time required for all the 1.25 × 10²² M C₂H₅OH to decompose using the integrated rate law.

[C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

0 M = 1.25 × 10²² M - 24.00 × 10²⁵ M/s × t

t = 5.21 × 10⁻⁵ s

The rate constant for the decomposition of ethanol on an alumina surface is 24.00 × 10²⁵ M.

The rate law is: rate = 24.00 × 10²⁵ M/s

The integrated rate law is: [C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

If the initial concentration of C₂H₅OH was 1.25 × 10²² M, the half-life is 2.60 × 10⁻⁵ s.

The time required for all the 1.25 × 10²² M C₂H₅OH to decompose is 5.21 × 10⁻⁵ s.

Learn more about zero-order kinetics here: https://brainly.com/question/13314785

The compound sodium carbonate is a strong electrolyte because it completely dissociates when placed in water into its component ions. The equation of the reaction can be expressed as:

\(Na_2CO_3_{(s)} ---> 2 Na^+_{(aq)} + CO_3^{(2+)}_{(aq)}\)

The dissociation leads to the formation of sodium and carbonate ions with the latter held together by its internal covalent bond.

This is unlike weak electrolytes that do not dissociate completely in water or aqueous solutions. Only a small fraction of the solute exists as ions in the solution.

More on strong and weak electrolytes can be found here: https://brainly.com/question/3410548

Answer: Na2CO3(s)  2Na+(aq) + CO32-(aq)

Explanation:

the carbonate has a -2 formal charge. not a +2 (as the previous answer stated)

Mass of the pure silver deposited on a metal object made into the cathode of the cell is calculated to be 0.0217 gm.

The process of using electrodeposition to coat an object in a layer of metal is called electroplating .

As we know that, Q = I * t

=0.270 * 72

= 19.44 C

Here Q is quantity of electricity , I is current in amperes = 0.270 A (given)

t is time in seconds (72.0 sec)

As 96500 Coulomb of electricity electrolyzes 1 mole of Ag

then,19.44 C of electricity deposits,

=1/96500 * 19.44

= 0.000201 moles of Ag

Mass of Ag is = number of moles * molar mass

= 0.000201 * 108

= 0.0217 gm

Thus, mass of pure silver deposited on a metal object made into the cathode of the cell is  0.0217 gm.

To know more about electroplating, refer

https://brainly.com/question/16266707

#SPJ4

Answer:

it leads to an incorrect high calculated surface tension

The number of photons is obtained from the calculation as 1.68 * 10^19 photons.

By definition, we know that energy is the ability to do work. Now we know that we have the wavelength of the radiation can be seen from the question and the values that are given to be 3.80 x 10-8 m.

Then energy = hc/λ

h = Plank's constant

c = speed of light

λ = wavelength

E = 6.6 * 10^-34 * 3 * 10^8/ 3.80 x 10^-8

E = 5.2 * 10^-18 J

Energy of the water = mcdT

= 4.48 * 4.2 * 4.65 = 87.5 J

Number of photons required =  87.5 J/5.2 * 10^-18 J

= 1.68 * 10^19 photons

Learn more about photons:https://brainly.com/question/20912241

#SPJ1

Answer:

                                                                2CO(g) + O2(g) ⇌ 2CO2(g)

Increasing the concentration of CO -         ↓         ↓                 ↑

Increasing the concentration of CO2 -       ↑         ↑                 ↓

Explanation:

The given reaction is

2CO(g) + O2(g) ⇌ 2CO2(g)

a) When the concentration of CO is increased, the stress is relieved as the reaction that consumes the added CO occurs more rapidly than its reverse reaction, for example., the forward reaction rate increases. The equilibrium will shift in favor of the product. However, the concentration of reactants (CO and O2) decreases and product concentration (CO2) increases.

b) When the concentration of CO2 is increased, the stress is relieved as the reaction that consumes the added CO2 occurs more rapidly than its reverse reaction, for example., the rate of backward reaction increases. The equilibrium will shift in favor of the reactant. Therefore, the concentration of reactants (CO and O2) increases, and the product concentration (CO2) decreases.

Hope this helps!

Answer: true

Explanation:

12 mol NH₃

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[RxN - Balanced] N₂ + 3H₂ → 2NH₃

[Given] 6 moles N₂

[Solve] moles NH₃

Step 2: Identify Conversions

[RxN] 1 mol N₂ → 2 mol NH₃

Step 3: Stoich

Answer:

Water has a chemical formula of H2O . In here, there are two hydrogen atoms and one oxygen atom, and so its mass will be 2+16=18 amu . There are two water molecules formed, and that means the total mass of the products is 18⋅2=36 amu .

Answer:

The activation energy is the amount of energy needed for a chemical reaction to occur.

Answer:

Activation energy, in chemistry, the minimum amount of energy that is required to activate atoms or molecules to a condition in which they can undergo chemical transformation or physical transport.

Strata are the layers of rock or soil that are distinguishable from other layers that have been laid down upon one another over the history of the earth.

A strata is the horizontal layer of rocks or sedimentary rocks that are laid upon another or arranged one on top of another that is separated by adjacent beds planes or layers.

Therefore, Strata are the layers of rock or soil that are distinguishable from other layers that have beenlaid down upon one another over the history of the earth.

Learn more about strata below.

https://brainly.com/question/25817019

Answer:

The correct answer to you your question is Potassium

Explanation:

Potassium is the most reactive

The true statements about catalysts are the statement 1,2 and 3.

1. Catalysts increase the rate of reaction: Catalysts facilitate chemical reactions by providing an alternative reaction pathway with lower activation energy. They enhance the rate of the reaction without being consumed in the process.

2. Catalysts behave as reactants in the reaction mixture: Catalysts participate in the reaction by interacting with the reactants. They form temporary bonds with the reactant molecules, leading to the formation of an intermediate complex that ultimately results in the desired products.

3. Catalysts decrease the activation energy of a reaction: Catalysts lower the energy barrier required for a reaction to occur by providing an alternative pathway with a lower activation energy. This enables the reactants to overcome the energy barrier more easily, thus increasing the reaction rate.

4. Catalysts show no physical change at the end of the reaction: Catalysts are not consumed or permanently altered in the reaction. They remain chemically unchanged and are available to participate in subsequent reaction cycles.

The statement "Catalysts are required in large concentrations in a reaction" is false. Catalysts work effectively even in small concentrations, as their role is to facilitate the reaction rather than being directly involved in the stoichiometry of the reaction.

For more questions on catalysts, click on:

https://brainly.com/question/12507566

#SPJ8

Answer:

I don't know because I don't know about chemistry

The concentration (M) of hydrogen fluoride is mathematically given as

HF= 0.095 M

Question Parameters:

A buffer solution contains 0.100 M fluoride ions and 0.126 M hydrogen fluoride.

after addition of 9.00 mL of 0.0100 M HCl to 25.0 mL of this buffer solution

Generally, the equation for the Chemical Reaction  is mathematically given as

F- + H+ > HF

Where

Initial moles of HF = molarity * volume

mi= 0.126 × 25

mi= 3.15

Hence

moles of F- = 2.5 milimoles

moles of H+ added  = 0.09mol

In conclusion

Total volume of Hf = 9 + 25

Total volume of Hf = 34 ml

Where

moles of HF after reaction

mr= 0.09 + 3.15

mr= 3.24

Hence

HF = 3.24 /34

HF= 0.0953 M

Read more about  Chemical Reaction

https://brainly.com/question/11231920

Chapter 1 of the Concise Chemistry 6 Revised Middle School SELINA book, titled "Introduction to Chemistry," provides an overview of the fundamental concepts and principles of chemistry. This chapter serves as a foundation for understanding the subject.

The back book exercises in this chapter aim to reinforce the students' comprehension and application of the introductory concepts. These exercises typically cover a range of topics such as the definition of chemistry, the branches of chemistry, the scientific method, and basic laboratory techniques.

Students may be asked to define key terms related to chemistry, such as matter, substance, element, compound, and mixture. They may also explore the different branches of chemistry, such as organic, inorganic, physical, analytical, and biochemistry. Additionally, students may be introduced to the scientific method and the steps involved in conducting scientific experiments.

The exercises in this chapter may also involve practical applications, such as identifying laboratory apparatus and understanding safety precautions. Students may be asked to differentiate between physical and chemical changes, as well as classify various substances based on their properties.

Overall, the exercises in Chapter 1 of the Concise Chemistry 6 Revised Middle School SELINA book aim to provide students with a solid foundation in the basic principles and terminology of chemistry, preparing them for more advanced topics in subsequent chapters.

Know more about scientific method here:

https://brainly.com/question/17216882

#SPJ11

Answer:

3p⁶ 4s² 3d²

Explanation:

From the question given above,

The electronic configuration of the element ends with 3p².

Another element having 8 more electrons will have the following electronic configuration as illustrated below:

Step 1:

Complete the 3p orbital by adding 4 electrons:

3p² + 4 electrons = 3p⁶

Step 2:

Fill the 4s orbital. This is so because 4s has a lower energy level compared to 3d.

4s²

Step 3:

Fill the 3d orbital with the remaining electrons i.e 2

3d²

Summary:

The continuation of the electronic configuration of the element with 8 more electrons is:

3p⁶ 4s² 3d²

Considering the electronic configuration, the electronic configuration of the element with 8 more electrons is:  3p⁶ 4s² 3d²

The Electronic Configuration of the elements is the arrangement of all electrons of an element in energy levels and sub-levels (orbitals).  

There are 7 energy levels, in which electrons are distributed, logically in order according to their energy level.

Each level is divided into sub-levels. These sub-levels into which each level is divided can be up to 4. These 4 sub-levels are called: s, p, d, f.

In the sub-level s there can only be a maximum of 2 electrons, in sub-level p there can be a maximum of 6 electrons, in the sub-level d 10 electrons and finally in the sub-level f there can be a maximum of 14 electrons.

In level 1 there is only 1 sub-level, which will be the s. In level 2 there are 2 sub-levels, the s and the p. At level 3 there are 3 sub-levels: s, p and d. And at level 4 there are 4 sub-levels, the s, the p, the d and the f.

Aufbau's principle is a principle of atomic physics, which explains how electrons are accommodated in their orbits around the nucleus of the atom. This principle states that the filling of these orbitals occurs in increasing order of energy, that is, from the orbitals of lower energy to those of higher energy.

In this case, the electronic configuration of the element ends with 3p².  Another element having 8 more electrons.

In first place, you need to complete the 3p orbital by adding 4 electrons:

3p² + 4 electrons = 3p⁶

Then, you need to fill the 4s orbital with 2 electrons. This is so because 4s has a lower energy level compared to 3d.

4s²

Finally, you fill the 3d orbital with the remaining 2 electrons.

3d²

In summary , the electronic configuration of the element with 8 more electrons is:  3p⁶ 4s² 3d²

Learn more about electronic configuration:

Answer:

Chemical change

Explanation: Chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances.

Answer:c

Explanation:c

Answer:

Polar covalent bond

Explanation:

as Ra only has two extra electrons on another outside ring is does not take much to switch over i believe thats how it works

Answer:

i would say the first one!

Answer:

A positive ion has fewer electrons, and importantly, fewer electron shells (since atoms usually lose electrons until they get down to an empty outer shell.) This makes it smaller than a neutral atom of that element.

A negative ion has more electrons, and importantly, greater electron-electron repulsion in its outer shell. This makes it larger than a neutral atom of that element.

The rate constant : b. 1/ M² · s

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.  

For A + B  ---> C + D

Can be formulated:

\(\large{\boxed{\boxed{\bold{v~=~k.[A]^a[B]^b}}}\)

where

v = reaction speed, M / s

k = constant, mol¹⁻⁽ᵃ⁺ᵇ⁾. L⁽ᵃ⁺ᵇ⁾⁻¹. S⁻¹

a = reaction order to A

b = reaction order to B

[A] = [B] = concentration of substances

Units of the rate constant - k depend on rate law, so it is unique for the specific reaction

So for the rate law :

Δ[C]/ΔT = k[A]²[B] , the units are :

\(\tt \dfrac{M}{s}=k\times M^2\times M\\\\k=\dfrac{M/s}{M^2\times M}\\\\k=\dfrac{1}{M^2.s}\)

Answer:

14.9 mol

Explanation:

To find the number of moles in a given mass of a sample of sodium chloride (NaCl), we can multiply the number of grams in the sample by the molar mass of sodium chloride, which is 58.44 g/mol.

871 g × (1 mol / 58.44 g)

= 871/58.44 mol

≈ 14.9 mol

Note that we rounded to 3 significant figures in the final answer because that is how many significant figures were given in the mass measurement of the sodium chloride sample.

Answer: Wax

Explanation:

Density is defined as the mass contained per unit volume.

\(Density=\frac{mass}{Volume}\)

Usually solids are more denser than liquid, as molecules in solid are more strongly packed and thus have more mass per unit volume.

Liquids on the other hand contain molecules which are less tightly bound and thus thus contain less mass per unit volume as compared to solid.

Example: Solid wax is more denser than liquid wax.