Compare and contrast substrate level phosphorylation and oxidative phosphorylationSubstrate level phosphorylation is a direct type of phosphorylation in which a phosphate group is directly transferred to an ADP molecule. Oxidative phosphorylation is an indirect method of phosphorylation in which the energy liberated in the electron transport chain is used in generating ATP.

Answer:

1) As you move down a group, first ionization energy decreases. WHY? Electrons are further from the nucleus and thus easier to remove the outermost one. 2) As you move across a period, first ionization energy increases.

so i think it is b

Explanation:

Answer:

Volume of the reaction vessel is increased - shift to the left

The reaction is cooled down - shift to the right

H2 is added to the system - shift to the right

The pressure of the system is decreased - shift to the left

A catalyst is added to the system - no change

Water is removed from the system - shift to the right

Explanation:

When a constraint such as a change in temperature, pressure or volume is imposed on a reaction system in equilibrium, the equilibrium position will shift in such a way as to annul the constraint.

When the volume of a reaction system is increased, the equilibrium position shifts in the direction in which there is the highest total volume. This is the left hand side.

Since the reaction is exothermic (heat is given out) when the reaction is cooled down, the forward reaction is favoured.

Adding of reactants shifts the equilibrium position to the right hand side hence when H2 is added, the equilibrium position shifts to the right.

Decreasing the pressure shifts the equilibrium position to the direction of higher total volume hence the equilibrium shifts to the left when pressure is decreased.

A catalyst has no effect on the equilibrium position. It increases the rate of forward and reverse reaction to the same extent hence the equilibrium position is unaffected.

Removal of water from the system increases the rate of forward reaction since a product is being removed from the reaction system.

Answer:

11000 g/L

Explanation:

Since density is mass divided by volume, find the volume of the metal ball by subtracting the initial volume of water in the graduated cylinder from the ending volume. In this case, the volume would be 17.90 mL - 16.05 mL =  1.85 mL = 0.00185 L. Then using the formula for density, calculate 20.350 g / 0.00185 L = 11000 g/L.

Density is an intensive property as it does not depend on the quantity of the substances Whereas mass and volume are extensive property. Therefore, the density of the metal ball is 11000 g/L.

Density tells about the compactness of the substances, how much dense is the substances in other words. Object that is more denser than water they just sink in the water.

Mathematically,

Density = Mass of the metal ball ÷volume marked on the graduated cylinder

volume=ending volume- initial volume of water in the graduated cylinder            

            =17.90 mL - 16.05 mL

            =  1.85 mL

            = 0.00185 L.

substituting all the given values in the above equation, we get

density=  20.350 g / 0.00185 L

            = 11000 g/L.

Therefore, the density of the metal ball is 11000 g/L.

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Mendeleev sketched out the table he had in mind. Mendeleev created the so-called Periodic Law while assembling these atomic data cards.

Periodic law is defined as a rule that the elements fall into recurrent groupings when enumerated in order of their atomic numbers, causing elements with similar qualities to appear frequently. "The physical and chemical properties of the elements are periodic functions of their atomic numbers," is how the current Periodic law is best summarized.

Mendeleev found that when all the known chemical elements were arranged in order of increasing atomic weight, the resulting table revealed a periodicity, or repeated pattern, of characteristics within groupings of elements.

Thus, Mendeleev sketched out the table he had in mind. Mendeleev created the so-called Periodic Law while assembling these atomic data cards.

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Explanation:

They historically leading a migratory shabby chic life with respect to the experiences of humans in Ladakh and are genuine and trustworthy. About the profession of people in Ladakh, 90% of their rely for their subsistence on cultivation dependent on the River Indus. Corn, barley, bulgur, beans, canola and peanuts are their principal staple foods.

Answer: C

Explanation: hope this helps

The model of the solar system that is shown here is:

C. Geometric model

Model for description of earth and other entites

In astronomy, the geocentric model is a superseded description of the Universe with Earth at the center. Under the geocentric model, the Sun, Moon, stars, and planets all orbit Earth.

Characteristics:

Thus, option C is correct.

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Answer:

mechanical energy

Explanation:

I belive that the answer to your question is #4, "Light, sound, chemical, and thermal.

Answer:

malleable

Explanation:

physical properties of matter include colour, hardness, malleability, solubility, density etc

Answer:

what e said

Explanation:

The pH of the solution is approximately : 1.05

Given data :

volume of HCl = 68.00 mL = 0.068 L

concentration of HCl = 0.280 M

Volume of NaOH = 60 mL = 0.6 L

concentration of NaOH = 0.125 M

First step : determine the number of mol of HCl and NaOH

mol of HCl = 0.068 * 0.280  = 0.0190 mol HCl

mol of NaOH = 0.06 * 0.125 = 0.0075 mol NaOH volume of

excess moles of H⁺ after reaction  = 0.0190 - 0.0075 = 0.0115 mol

Next step : determine the pH value of the solution

Total volume of solution = 0.068 + 0.060 = 0.128

concentration of the solution [ H⁺ ] = excess moles / total volume

                                                         = 0.0115 / 0.128 = 0.0898

Therefore

pH = - log [ H⁺ ]

    = - log ( 0.0898 ) = 1.047 ≈ 1.05

Hence we can conclude that The pH of the solution is approximately : 1.05 .

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Answer:

1. B

2. C

3. B or D

6. A

7. D

8. A

9. A

Explanation:

Brainliest plz answered to the best of my abilitys

Mn(s) metal will spontaneously react with Zn²⁺(aq), but will not

spontaneously react with Mg²⁺ (aq)

The Eo value of an electrochemical cell determines its spontaneity. Positive Eo electrochemical cells are spontaneous, and vice versa.

The relevant Eo of the half-cell in this instance are as follows for Mn(s) metal

Zn2+/Zn = -0.763v for Eo

2.37v for Eo Mg2+/Mg.

Mn2+/Mn = -1.18v for Eo.

Consequently, the equation for an Eo cell (with Zn as one of the half-cells) is: Eo Zn2+/Zn - Eo Mn2+/Mn = -0.763 - (-1.18) = 0.417v.

On the other hand, the equation for an Eo cell (with Mg as one of the half-cells) is: Eo Mg2+/Zn - Eo Mn2+/Mn = -2.37 - (-1.18) = -1.19v.

As a result, Mn(s) metal will spontaneously react with Zn2+(aq), but not with Mg2+ (aq)

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Answer:

4 moles of H2SO4 are required

Explanation:

The reaction of H2SO4 with NaOH is:

H2SO4 + 2 NaOH → 2H2O + Na2SO4

That means, 2 moles of sulfuric acid reacts per mole of NaOH.

The moles of NaOH in 4L of a 2N NaOH are:

2N NaOH = 2 M = 2 moles of NaOH per liter.

4 liters are:

4L * (2 moles NaOH / L) = 8 moles NaOH.

That means you need to add:

8 moles NaOH * (1 mole H2SO4 / 2 moles NaOH) =

Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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Answer:

The balanced equation for the reaction of NH3 and O2 is: 4 NH3 + 5 O2 -> 4 NO + 6 H2O.

From the balanced equation, it can be determined that for every 4 moles of NH3, 5 moles of O2 are needed to react.

To convert 14.8 g of NH3 to moles, the following calculation can be used: 14.8 g NH3 / 17.03 g/mol = 0.87 moles NH3.

Therefore, the number of moles of O2 needed to react with 14.8 g of NH3 is: 0.87 moles NH3 * (5 moles O2 / 4 moles NH3) = 1.09 moles O2.

To convert moles of a substance to grams, the following calculation can be used: moles x molar mass (in g/mol)

Therefore, the number of grams of O2 needed to react with 14.8 g of NH3 is: 1.09 moles O2 * (32.00 g/mol) = 35.1 g O2

The theoretical yield of CO₂ from 5.03 mol of charcoal is 221.32 g.

The percent yield if the reaction gives 135.6 g of CO₂ is 61.2 %.

The following chemical equation

C(s) + O₂(g) → CO₂(g)

moles of carbon = 5.03 mol

1 mol of carbon produces 1  mol of CO₂

5.03 mol of carbon form5.03 mol of CO₂

mass of CO₂ = moles × molar mass

                     = 5.03 × 44

                     = 221.32 g

theoretical yield of CO₂ = 221 g

The percent yield  = (actual yield / theoretical yield ) × 100 %

                              = (135.6  / 221.32 )  × 100 %

                              = 61.2 %

Thus, The theoretical yield of CO₂ from 5.03 mol of charcoal is 221.32 g.

The percent yield if the reaction gives 135.6 g of CO₂ is 61.2 %.

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We are given that the concentration of NaOH is 0.0003 M and are asked to calculate the pH

We know that NaOH dissociates by the following reaction:

NaOH → Na⁺ + OH⁻

Which means that one mole of NaOH produces one mole of OH⁻ ion, which is what we care about since the pH is affected only by the concentration of H⁺ and OH⁻ ions

Now that we know that one mole of NaOH produces one mole of OH⁻, 0.0003M NaOH will produce 0.0003M OH⁻

Concentration of OH⁻ (also written as [OH⁻]) = 3 * 10⁻⁴

pOH of the solution:

pOH = -log[OH⁻] = -log(3 * 10⁻⁴)

pOH = -0.477 + 4

pOH = 3.523

pH of the solution:

We know that the sum of pH and pOH of a solution is 14

pH + pOH = 14

pH + 3.523 = 14                              [subtracting 3.523 from both sides]

pH = 10.477                        

Answer:

184478 qreo si si es es hola

Answer:

I believe it is a positive quantity such as water has 4.14 j/oC it is always positive it is the energy needed to raise the temperature by 1 degree celsius

Explanation:

Iron because it loses electrons

An electrochemical cell is a device that converts chemical energy into electrical energy, or vice versa, through the transfer of electrons between two electrodes.

The cell typically consists of two half-cells, each containing an electrode immersed in an electrolyte solution. The two half-cells are separated by a membrane or a porous barrier that allows the flow of ions between them.

Electrochemical cells have numerous applications, including batteries, fuel cells, corrosion protection, and electroplating, among others.

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Hexane, heptane, and octane have molar masses of Hexane (C6H14) has a molecular mass of 6 (12.01 g/mol) and 14 (1.00 g/mol) and heptane (C7H16) has a molecular mass of 7 (12.01 g/mol) and 16 (1.00 g/mol) and 100.21 g/mol.

The mass in grammes of one mole of a chemical is its molar mass.The quantity of atoms, molecules, and ions contained in a substance is measured in terms of moles. A mole of any substance contains 6.022 x 1023 molecules.

Use 100 g of the fuel mixture as an example. Then:

Hexane weight is 28.30 grammes.

15.75 g is the heptane mass.

Octane mass is equal to 100 g, 28.30 g, 15.75 g, and 55.95 g.

The molar masses of hexane, heptane, and octane are:

Molar mass of hexane (C6H14) = 6(12.01 g/mol) + 14(1.01 g/mol) = 86.18 g/mol

Molar mass of heptane (C7H16) = 7(12.01 g/mol) + 16(1.01 g/mol) = 100.21 g/mol

Molar mass of octane (C8H18) = 8(12.01 g/mol) + 18(1.01 g/mol) = 114.23 g/mol

The number of moles of each component in 100 g of the fuel mixture is:

Moles of hexane = 28.30 g / 86.18 g/mol = 0.3282 mol

Moles of heptane = 15.75 g / 100.21 g/mol = 0.1573 mol

Moles of octane = 55.95 g / 114.23 g/mol = 0.4899 mol

Therefore, the mole fractions of each component are:

Mole fraction of hexane = 0.3282 / (0.3282 + 0.1573 + 0.4899) = 0.3841

Mole fraction of heptane = 0.1573 / (0.3282 + 0.1573 + 0.4899) = 0.1838

Mole fraction of octane = 0.4899 / (0.3282 + 0.1573 + 0.4899) = 0.4321

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Anwser:

Research scientific principles involved in water availability.

Explanation:

Before building or investment you always want to see and know what your up against and what the best way to help or solve is. Researching why there's a problem in water availability or/and the principals to water availability will help you see what the problem is with what's happening to and around the process and it's environment.

There are approximately 1.62 x 10^25 water molecules in the 499.8 mL bottle of water.

To determine the number of water molecules in the given volume of water, we need to use the relationship between mass, volume, and molar mass of water.

First, we need to find the mass of water in the bottle:

Mass = Density * Volume

Mass = 0.967 g/mL * 499.8 mL = 483.9 g

Next, we need to convert the mass of water to moles using the molar mass of water. The molar mass of water (H2O) is approximately 18.015 g/mol.

Moles = Mass / Molar mass

Moles = 483.9 g / 18.015 g/mol = 26.88 mol

Finally, we can calculate the number of water molecules using Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules = Moles * Avogadro's number

Number of molecules = 26.88 mol * (6.022 x 10^23 molecules/mol) = 1.62 x 10^25 molecules

Therefore, there are approximately 1.62 x 10^25 water molecules in the 499.8 mL bottle of water.

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Answer:

B)11

Explanation:

The atomic number is the number of protons and electrons in an atom!!

HOPE THIS HELPS!!!!!!

Answer:

15. 2.5 M

16. 2.5 moles

17. 0.128 M

18. 56 g

Explanation:

15. Determination of the molarity of NaOH.

Mole of NaOH = 2.5 moles

Volume = 1 L

Molarity =?

Molarity = mole /Volume

Molarity of NaOH = 2.5 / 1

Molarity of NaOH = 2.5 M

16. Determination of the number of mole of solute.

Volume = 1 L

Molarity = 2.5 M

Mole of HCl =?

Molarity = mole /Volume

2.5 = mole of HCl /1

Mole of HCl = 2.5 moles.

17. Determination of the molarity of Na₂S

We'll begin by calculating the number of mole in 20 g of Na₂S. This can be obtained as follow:

Mass of Na₂S = 20 g

Molar mass of Na₂S = (23×2) + 32

= 46 + 32

= 78 g/mol

Mole of Na₂S =?

Molar = mass / molar mass

Mole of Na₂S = 20 / 78

Mole of Na₂S = 0.256 mole

Finally, we shall determine the molarity of Na₂S. This can be obtained as follow:

Mole of Na₂S = 0.256 mole

Volume = 2 L

Molarity of Na₂S =?

Molarity = mole /Volume

Molarity of Na₂S = 0.256 / 2

Molarity of Na₂S = 0.128 M

18. Determination of the mass of solute.

We'll begin by calculating the number of mole solute (CH₄) in the solution. This can be obtained as follow:

Volume = 1 L

Molarity of CH₄ = 3.5 M

Mole of CH₄ =?

Molarity = mole / Volume

3.5 = mole of CH₄ / 1

Mole of CH₄ = 3.5 moles

Finally, we shall determine the mass of the solute (CH₄). This can be obtained as follow:

Mole of CH₄ = 3.5 moles

Molar mass of CH₄ = 12 + (4×1)

= 12 + 4

= 16 g/mol

Mass of CH₄ =?

Mole = mass /Molar mass

3.5 = Mass of CH₄ / 16

Cross multiply

Mass of CH₄ = 3.5 × 16

Mass of CH₄ = 56 g

The temperature should be between 30 °F and 60 °F because the temperature outside is 39 °F, so the water in the pond should have a temperature range that includes this temperature.

Therefore, the answer is B.

Answer:

The speed of molecules in a gas is directly proportional to the square root of the temperature and inversely proportional to the square root of the molar mass.

Since both gases are at the same temperature, we only need to compare their molar masses.

The molar mass of carbon dioxide (CO2) is 44 g/mol and the molar mass of hydrogen (H2) is 2 g/mol.

Therefore, the square root of the molar mass of hydrogen is smaller than the square root of the molar mass of carbon dioxide.

This means that the speed of hydrogen molecules is greater than the speed of carbon dioxide molecules at the same temperature.

The amount of 0.303N NaOH needed to neutralize a 13.0 ml sample of acid is 37,3 ml. Acid is 0.823N normal, according to the standard.

The idea of neutralization, according to which an acid reacts with a base to create salt and water. By comparing the molarity of the base to the amount of base needed for neutralization, it is possible to calculate the molarity of the acid. Once the molarity and the acid's valence (or charge) have been multiplied, the acid's normalcy can be determined.

By deducting the volume of NaOH (37.3 ml) from the volume of the acid sample in Step 1, you can calculate the amount of acid that was utilized in the neutralization procedure (13.0 ml).

Consequently, 13.0 ml to 37.3 ml

= -24.3 ml

Use the equation moles = normality x volume to determine the number of moles of acid that were used in the process.

Consequently, moles equal 0.303N x -24.3 ml.

= -7.33 moles

Determine the acid's normality by multiplying the volume by the formula normalcy = moles.

As a result: normalcy = -7.33 moles / 13.0 ml

= -0.823N

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The original substance has undergone a transformation into a new substance with different properties, indicating a change in the chemical composition of the material.

An example of a change in substance is the process of combustion. When a substance, such as wood, is burned, it undergoes a chemical reaction with oxygen in the air, which produces a new substance: carbon dioxide gas, water vapor, and ash. This change in the chemical composition of the wood means that it has transformed into a completely new substance with different physical and chemical properties.

Another example is the process of electrolysis, where an electric current is passed through a solution containing ions. This can cause a chemical reaction to occur, resulting in the breakdown of the original substance into its component parts or the formation of a new substance.

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