Combien y-a-t-il d'atomes grammes de zinc (Zn) dans 32,7 g de Zn?​

The kinetic energy of a 23.2-g object moving at a speed of 98.7 m/s is  113.30 J. Option D

The kinetic energy of an object can be calculated using the formula: KE = (1/2)mv^2, where KE is the kinetic energy, m is the mass of the object, and v is the velocity or speed of the object.

Given:

Mass (m) = 23.2 g = 0.0232 kg

Speed (v) = 98.7 m/s

Substituting these values into the formula, we can calculate the kinetic energy:

KE = (1/2)(0.0232 kg)(98.7 m/s)^2

KE = (1/2)(0.0232 kg)(9756.09 m^2/s^2)

KE ≈ 113.30 J

Therefore, the kinetic energy of a 23.2-g object moving at a speed of 98.7 m/s is approximately 113.30 J.

It's worth noting that the question is repeated twice, but the answer remains the same. The kinetic energy of the object is determined by its mass and speed, and both calculations yield the same result. Option D

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Vomiting, headaches, wooziness, blurred vision, and even liver injury are side effects of vitamin A. Vitamin D - Tiredness, headache, sickness, and vomiting. Vitamin C: Heartburn, diarrhea, vomiting, and nausea.

Yes, excessive amounts of some types of vitamin A can be dangerous. A strong headache, blurred vision, nausea, dizziness, muscular aches, and issues with coordination can result from taking too much preformed vitamin A, which is typically found in supplements or some medications.

Poisonous Substance. Any component in a multivitamin supplement can be toxic in large doses, but iron or calcium pose the biggest threat. Large or toxic doses of calcium, vitamin D, and vitamin A carry additional dangers.

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The mass, in grams of 1.16 mole of water, H₂O is 20.88 g

The mole of a substance is related to it's mass and molar mass according to the following equation

Mole = mass / molar mass

With the above formula, we can obtain the mass of H₂O

From the question given above, the following data were obtained:

The mass of 1.16 mole of water can be obtained as illustrated below:

Mole = mass / molar mass

Cross multiply

Mass = mole × molar mass

Mass of H₂O = 1.16 × 18

Mass of H₂O = 20.88 g

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Answer:

38.3 g

Explanation:

8) What mass of chlorine reacts with 20.0 g of iron to form iron(III) chloride?​

first write, then balance the equation

Fe + Cl2-------------> FeCl3

2Fe + 3Cl2----------> 2FeCl3

2 moles of Fe require 3 moles of Cl2

the atomic mass of Fe is 56

20/56= 0.36 moles of Fe

this requires o.36 X 3/2 = 0.54 moles of Cl2

Cl2 has a molar mass of 35.5 X 2=71

1 mole of Cl2 is 71g

0.54 moles is 0.54 X 71 g= 38.3 g

The mass of chlorine reacts with 20.0 g of iron to form iron(III) chloride is 38.3 g.

Mass is defined as a numerical representation of the fundamental characteristic of all matter, inertia.

It can also be defined as a dimensionless number used to describe the mass of a particle or item.

\(\rm 2Fe + 3Cl_2\rightarrow2FeCl_3\)

As per the reaction 3 mole of chlorine is required for 2 mole of fluorine.

Atomic mass of fluorine = 56

Moles of Fe = 20 / 56

                    =  0.36 moles

This require 0.36 x 3/2 = 0.54 moles of Cl₂

Molar mass of Cl = 35.5

So for Cl₂ = 2 x 35.5 = 71 moles

For 1 mole of Cl₂ = 71 moles is needed

So, for 0.54 moles = 71 x 0.54

                               = 38.3 g

Thus, the mass of chlorine reacts with 20.0 g of iron to form iron(III) chloride is 38.3 g.

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the sun cooks the clouds the clouds pee on the earth and all the water falls to earth, pushing all the wind down that's why we have earthquakes

Eruption triangulation is a method for locating an earthquake's epicenter.

The area right above the spot in the Earth's crust where an earthquake originates or begins is known as the epicenter. It marks the spot on the Earth's surface where the earthquake's seismic waves first touchdown.

The distance between the earthquake's epicenter and a number of seismograph stations is calculated using seismograms, which are records of the ground motion brought on by an earthquake.

The following are the steps to find an earthquake's epicenter:

A minimum of three separate seismograph stations should have data collected. The epicenter's distance from each station is determined by keeping track of the time the earthquake waves arrived at each station.

Map out the positions of each seismograph station.

Draw circles with an equal radius around each seismograph station using the distance information. Each circle's radius is equal to how far away the station is from the epicenter.

At the place where the circles converge, there is an epicenter.

It is crucial to keep in mind that determining the epicenter of an earthquake is not an exact science, and the precision of the position will vary depending on a number of variables, such as the caliber of the seismograms and the distance between the earthquake and the seismograph stations.

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Answer:

4.0

Explanation:

we have a buffer system formed by a weak acid (benzoic acid C₆H₅O₂H) and its conjugate base (benzoate ion C₆H₅O₂⁻, coming from sodium benzoate C₆H₅O₂Na). Given the acid dissociation constant (Ka) for benzoic acid is 6.5 × 10⁻⁵, we can calculate the pH of the buffer solution using the Henderson-Hasselbach equation.

pH =pKa + log [base]/[acid]

pH =-log Ka + log [C₆H₅O₂⁻]/[C₆H₅O₂H]

pH =-log 6.5 × 10⁻⁵ + log (0.15 M/0.25 M) = 4.0

Answer:

93.4 mL

Explanation:

Let's state the reaction:

2AgNO₃ +  Na₂CO₃  →   Ag₂CO₃  +  2NaNO₃

We determine the moles of sodium carbonate:

0.3572 g . 1mol / 105.98g = 3.37×10⁻³ moles

Ratio is 1:2. We say:

1 mol of sodium carbonate react to 2 moles of silver nitrate

Then, our 3.37×10⁻³ moles of carbonate may react to: 3.37×10⁻³ . 2

= 6.74×10⁻³ moles

If we convert to mmoles → 6.74×10⁻³ mol . 1000 mmol / mol = 6.74 mmol

Molarity is mol/L but we can use mmol /mL

6.74 mol / volume in mL = 0.07216 M

6.74 mol / 0.07216 M = volume in mL → 93.4 mL

Precision relates to the consistency and reproducibility of measurements, while accuracy reflects how close measurements are to the true value.

Precision and accuracy are two important concepts in the context of errors in measurements. While they both pertain to the quality of data, they refer to different aspects.

Precision refers to the degree of consistency or reproducibility in a series of measurements. It reflects the scatter or spread of data points around the average value. If the measurements have low scatter and are tightly clustered, they are considered precise. On the other hand, if the measurements have a high scatter and are widely dispersed, they are considered imprecise.

Accuracy, on the other hand, refers to the closeness of measurements to the true or target value. It represents how well the measured values align with the actual value. Accuracy is achieved when measurements have a small systematic or constant error, which is the difference between the average measured value and the true value.

Errors in measurements can be classified into two types: random errors and systematic errors.

Random errors are associated with the inherent limitations of measurement instruments or fluctuations in the measurement process. They lead to imprecise data and affect the precision of measurements. Random errors can be reduced by repeating measurements and calculating the average to minimize the effect of individual errors.

Systematic errors, on the other hand, are caused by consistent biases or inaccuracies in the measurement process. They affect the accuracy of measurements and lead to a deviation from the true value. Systematic errors can arise from factors such as instrumental calibration issues, environmental conditions, or experimental techniques. These errors need to be identified and minimized to improve the accuracy of measurements.

In summary, precision refers to the degree of consistency or reproducibility of measurements, while accuracy refers to the closeness of measurements to the true value. Random errors affect precision, while systematic errors affect accuracy. To ensure high-quality measurements, both precision and accuracy need to be considered and appropriate techniques should be employed to minimize errors.

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Answer:

Option D. atm, L, K, mole

Explanation:

To know which option is correct, do the following:

We shall use the standard value for each variable to obtain the gas constant. This can be obtained as follow:

Volume (V) = 22400 mL

Pressure (P) = 760 mmHg

Number of mole (n) = 1 mole

Temperature (T) = 273 K

Gas constant (R) =?

PV = nRT

R = PV / nT

R = (760 × 22400) / (1 × 273)

R = 62358.97 mmHg.mL/Kmol

Volume (V) = 22.4 L

Pressure (P) = 760 mmHg

Number of mole (n) = 1 mole

Temperature (T) = 273 K

Gas constant (R) =?

PV = nRT

R = PV / nT

R = (760 × 22.4) / (1 × 273)

R = 62.359 mmHg.L/Kmol

Volume (V) = 22400 mL

Pressure (P) = 1 atm

Number of mole (n) = 1 mole

Temperature (T) = 273 K

Gas constant (R) =?

PV = nRT

R = PV / nT

R = (1 × 22400) / (1 × 273)

R = 82.05 atm.mL/Kmol

Volume (V) = 22.4 L

Pressure (P) = 1 atm

Number of mole (n) = 1 mole

Temperature (T) = 273 K

Gas constant (R) =?

PV = nRT

R = PV / nT

R = (1 × 22.4) / (1 × 273)

R = 0.0821 atm.L/Kmol

From the above illustrations, we can see that the gas constant will have a value for 0.0821 as long as other variables are: atm, L, K, mole

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1) 2KCIO3=2kci+3o2

2)CH4 + 2O2 → CO2 + 2H2O

3)  2HCl + Ca(OH)2 → CaCl2 + 2H2O

I hope this helped!

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Answer:

D Flat Top Hills Can Be Plateaus or mesas

Explanation:

Answer:

recordando también que ** 1mL = 1cm ^ 3 **

(como ** 1 dm ^ 3 = 1 L **)

Answer:

radius = 16 in ; height = 27 in

Answer:

rhrhrhrhrhrhrrhrhrhrh

Explanation:

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The, new volume is 1200 L and new pressure is 25 kPa.

Given, temperature = 400 K

Pressure = 50 kPa

Volume = 3 L

V1/T1 = V2/T2

V2 = V1×T2 / T1

V2 = 400× 6/ 2

V2 = 1200 L

Hence, new volume is 1200 L.

P1/T1 = P2/T2

P2 = P1 × T2/ T1

P2 = 50 × 1000 × 200/ 400

P2 = 25000 Pa

Hence, new pressure is 25 kPa.

A gas is a set of molecules that do not cohere strongly sufficient to form a liquid or a strong. The quantity of a gas is, so long as the molecules fit into it, the extent of the container preserving the gas. In different phrases, the extent of a gas isn't always a belongings of the gas immediately, however a belongings of the box.

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Answer:

A. An atomic nucleus is positively charged because it is composed of neutrons.

Explanation:

Answer:

Back away from the situation and tell the supervisor/teacher

Scientific journals considered more reliable sources than web pages for information about science, because, they are read and openly criticized by many scientists and publish only after expert committee revision.

Scientific journals are books or magazines communicating the scientific inventions and discoveries conducted by a panel of scientists or research scholars through well designed experiments.

The communication of  results is the last step in the research methodology. It is published in a journal only after the strict revision of the results and explanations by a panel of experts. Hence, no guidelines are violated here and it is not possible to publish an erroneous result.

In the case of web pages, it can be opened or edited by many users and and not all web pages are following the guidelines of communications. Therefore, scientific journals considered more reliable sources than web pages.

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Answer:

What Affects Reaction Rate?

The purpose of this lab was to see how temperature and particle size affects reaction rate. The first hypothesis is if you increase the temperature of a reaction, then the reaction rate will increase because particles experience more collisions at higher temperatures.The second hypothesis is if you decrease the particle size of a reactant, then the reaction rate will increase because more of the reactants’ molecules will contact each other. The independent variables are particle size and temperature. The dependent variable is reaction rate.

Materials

250 mL graduated cylinder

Thermometer

Water

Timer

Four 250 mL beakers

Seven 1,000 mg effervescent tablets

Two pieces of filter paper

600 mL beaker

Ice

Hot plate

Procedure

Step 1:Gather Materials

Variation of Temperature

Step 2:Measure the Reaction Rate at ≈ 20°C (Room Temperature)

a) Using a graduated cylinder, fill a 250 mL beaker with 200 mL of water.

b) Measure the temperature of the water and record it in the correct row of Table A.

c) Reset the timer. Start the timer as you place a full tablet into the beaker.

d) Record the reaction time on the Data Sheet in the correct row of Table A.

e) Compute the reaction rate to the nearest mg/L/sec. Record it in the last column of Table A. Measure the Reaction Rate at ≈ 40°C

Step 3:Repeat Step 2, heating the water to approximately 40°C using a hot plate during sub-step a. Measure the Reaction Rate at ≈ 65°C

Step 4:Repeat Step 2, heating the water to approximately 65°C using a hot plate during sub-step a. Measure the Reaction Rate at ≈ 5°C

Step 5:Repeat Step 2, chilling the water to approximately 5°C inside an ice bath during sub-step a. (To create an ice bath, place 100 mL of ice and 100 mL of water in a 600 mL beaker of ice water and wait until the temperature reaches approximately 5°C. To save time, you may wish to set up the ice bath, using an additional 250 mL beaker, while working on Step 4.)

Variation of Particle Size

Step 6:Measure the Reaction Rate for a Full Tablet

a) Using a graduated cylinder, fill a 250 mL beaker with 200 mL of water.

b) Reset the timer. Start the timer as you place the tablet in the beaker.

c) Record the reaction time on the Data Sheet in the appropriate row of Table B.

d) Compute the reaction rate to the nearest mg/L/sec. Record it in the last column of Table B.

Step 7:Measure the Reaction Rate for a Partially Broken Tablet

Repeat Step 6, but this time break the tablet into eight small pieces on a piece of filter paper. Make sure to place all of the pieces into the beaker at the same time.

Step 8:Measure the Reaction Rate for a Crushed Tablet

Repeat Step 6, but this time crush the tablet into tiny pieces on a piece of filter paper. Make sure to place all of the pieces into the beaker at the same time.

Step 9: Dispose of all samples according to your teacher’s directions.

Measured Reaction Temperature (°C)

Mass of Tablet (mg)

Volume of Water (L)

Reaction Time (s)

Reaction Rate (mg/L/s)

≈20°C

24

1,000

0.2

34.2

146.2

≈40°C

40

1,000

0.2

26.3

190.1

≈65°C

65

1,000

0.2

14.2

352.1

≈5°C

3

1,000

0.2

138.5

36.1

Relative Particle Size (Small, Medium, Large)

Mass of Tablet (mg)

Volume of Water (L)

Reaction Time (s)

Reaction Rate (mg/L/s)

Full Tablet

large

1,000

0.2

34.5

144.9

Broken Tablet

medium

1,000

0.2

28.9

173.0

Crushed Tablet

small

1,000

0.2

23.1

216.5

The data in the first table show that as the temperature increases the reaction time decreases and in turn the reaction rate increases. The data supported the hypothesis that as temperature increases reaction rate will also increase. The second table shows that as the particle size decreases the reaction time increases because there is more surface area when the particles are smaller. The data in the second table supported the second hypothesis that as particle size decreases the reaction rate will increase because there will be more contact in the molecules. Possible source of error would be an error in stopping the timer in time or chips in the tablets. To improve this lab it could be done with different types of reactions or different temperature or different particle sizes.

Explanation:

Answer:

The person above is amazing and gave us all the answers!!

Explanation:

As the class is of 1 hour and  and each student uses for 6 minutes so in 1 hour 10 students will use the balance.

A scale or balance is a device used to measure weight or mass. These are also known as mass scales, weight scales, mass balances, and weight balances.

The traditional scale consists of two plates or bowls suspended at equal distances from a fulcrum. One plate holds an object of unknown mass (or weight), while known masses are added to the other plate until static equilibrium is achieved and the plates level off, which happens when the masses on the two plates are equal.

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The values of q = 0, ΔT = 50K, w= ΔU = 509.23J.

Adiabatic expansion is defined as the expansion in which there is no heat interaction of the system with the surroundings and work is done by the system at the expense of its internal energy.

Given,

Mass of Xe = 65g

Initial Pressure = 2 atm

T = 298K

Final pressure = 1 atm

Moles of Xe = mass ÷ molar mass

                    = 65 ÷ 131 = 0.49 moles

Since it is adiabatic, q = 0

Δ U = w

Cv = 5/2 R

nCv (T₂ - T₁) = \(\frac{nRT_{2} }{P_{2} }\) - \(\frac{nRT_{1} }{P_{1} }\)

Substituting the values as above, we get,

T₂ = 249 K

ΔT = 298 - 248 = 50K

ΔU = w = n Cv ΔT

= 0.49 × 20. 78 × 50

= 509.23 J

Therefore, the values of q = 0, ΔT = 50K, w= ΔU = 509.23J.

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4.2 × 10⁻²¹ moles Sn

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

2500 atoms Sn

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

4.15144 × 10⁻²¹ moles Sn ≈ 4.2 × 10⁻²¹ moles Sn

The relationship between tissues and organs is one of interdependence. Tissues work together to form organs, and organs rely on the different types of tissues to function properly.

The relationship between tissues and organs is an important one, and it is particularly exemplified in the case of the heart. The heart is an organ, and like all organs, it is made up of various types of tissues that work together to allow it to function properly. In the case of the heart, these tissues include muscle tissue, connective tissue, epithelial tissue, and nervous tissue.
Muscle tissue is particularly important in the heart, as it contracts to pump blood to the body. Without muscle tissue, the heart would not be able to perform its vital function. Connective and epithelial tissues are also important in the heart, as they hold the muscle cells together and in place in the chest. Without these tissues, the muscle cells would not be able to work together efficiently, and the heart would not be able to function properly.
Finally, nervous tissue plays a crucial role in the heart, as it coordinates how fast and hard the muscle cells contract. This coordination is essential for the heart to function properly and maintain the circulation of blood throughout the body.  In the case of the heart, the different types of tissues work together seamlessly to allow the heart to perform its vital function of pumping blood throughout the body.

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Answer: A

Explanation:

I got C wrong

ANSWER

Ground state

EXPLANATION;

Ground-state atom is an atom in which the total energy of the electrons cannot be lowered by transferring one or more electrons to different orbitals.

This implies that, in the ground-state atom all electrons are in their lowest possible energy level.

Hence, the correct answer is ground state.

Answer:

W is tungsten on the periodic table