CNM has decided to purchase some Swanky luxury water beds for the new dormitories. Each water bed has dimension of 1.83 m x 1.93 m x 0.248 m. The floor of the dorms will tolerate an additional weight of no more than 7150 N. Find the weight of the water in your bed and determine whether CNM should make the purchase.
Answers
We are asked to determine the weight of a bed of water with dimensions 1.83m x 1.93m x 0.248m. To do that we will determine the mass using the following formula:
\(m=\rho V\)Where:
\(\begin{gathered} m=\text{ mass} \\ \rho=\text{ density} \\ V=\text{ volume} \end{gathered}\)To determine the volume we will use the fact that the bed has the shape of a rectangular prism and therefore its volume is the product of its dimensions, like this:
\(V=\lparen1.83m)\left(1.93m\right)\left(0.248m\right)\)Solving the operations we get:
\(V=0.88m^3\)The density of water is given by:
\(\rho=1000\text{ kg/m}^3\)Substituting in the formula for the mass:
\(m=\lparen1000\text{ kg/m}^3)\left(0.88m^3\right)\)Solving the operations:
\(m=880kg\)Now, to determine the weight we use the following formula:
\(W=mg\)Where:
\(\begin{gathered} W=\text{ weight} \\ m=\text{ mass} \\ g=\text{ acceleration of gravity} \end{gathered}\)Substituting the values:
\(W=\left(880kg\right)\left(9.8\text{ m/s}^2\right?\)Solving the operation:
\(W=8624N\)Since the weight is 8624 N this means that the weight will not be tolerated.
Related Questions
the mass of a density bottle is 18.00g when empty 44.00g when full of water, and 39.84g when full up of a second liquid. calculate the density of the liquid where density of water =1000kgm³
Answers
The density of the second liquid is 0.812 g/cm³
To calculate the density of the second liquid, we need to use the principle of displacement. The mass of the liquid can be found by subtracting the mass of the empty density bottle from the mass of the bottle filled with the liquid. Therefore, the mass of the liquid is:
mass of liquid = mass of bottle + liquid - mass of empty bottle
mass of liquid = 39.84g + x - 18.00g
where x is the mass of the liquid.
We can now use the density formula, which is:
density = mass/volume
The volume of the liquid is equal to the volume of the density bottle that is filled with the liquid, which can be calculated by subtracting the volume of the empty bottle from the volume of the bottle filled with the liquid. Therefore, the volume of the liquid is:
volume of liquid = volume of bottle filled with liquid - volume of empty bottle
We can now substitute this expression into the density formula to get:
density of liquid = mass of liquid / (volume of bottle filled with liquid - volume of empty bottle)
We know that the density of water is 1000 kg/m³, which is equal to 1 g/cm³. We can use this to find the volume of the liquid by dividing the mass of water by its density:
volume of water = mass of water / density of water
volume of water = 44.00g / 1 g/cm³
volume of water = 44.00 cm³
Now, we can calculate the volume of the density bottle filled with the second liquid by using the principle of displacement:
volume of bottle filled with liquid = volume of water - volume of liquid
volume of bottle filled with liquid = 44.00 cm³ - (39.84g - 18.00g) / 1 g/cm³
volume of bottle filled with liquid = 44.00 cm³ - 21.84 cm³
volume of bottle filled with liquid = 22.16 cm³
Finally, we can substitute these values into the density formula to get:
density of liquid = x / 22.16 cm³
Solving for x, we get:
x = density of liquid x 22.16 cm³
Substituting x back into the mass equation, we get:
mass of liquid = 39.84g + (density of liquid x 22.16 cm³) - 18.00g
Solving for the density of the liquid, we get:
density of liquid = (mass of liquid - 21.84g) / 22.16 cm³
Substituting the given values, we get:
density of liquid = (39.84g - 21.84g) / 22.16 cm³ = 0.812 g/cm³
In conclusion, the density of the second liquid is 0.812 g/cm³. This value is less than the density of water, which means that the second liquid is less dense than water and will float on top of water.
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.Which term is described as a shelf of undersea land reaching a depth of about 200 meters (656 feet) and extending out from the shoreline?
A. guyots
B. deep-sea trenches
C. abyssal plains
D. continental shelf
Answers
Option D. continental shelf
Continental shelf is a part of a continent that is submerged under an area of relatively shallow water known as a shelf sea.
It is given in the question, that the shelf of undersea land reaches 200 meters and it also extends out from the shoreline. This condition is only possible when a structure is submerged, and such submerged region can only be called as continental shelf.
On the other hand guyots is a underwater volcanic mountain and deep-sea trenches are the the long narrow lowerings in the ocean floor with the depth upto 6000 meters. And abyssal plains are the underwater ocean floors which cannot be found at the depth of 200 meters.
Therefore continental shelf is used to described as a shelf of undersea land reaching a depth of about 200 meters (656 feet) and extending out from the shoreline.
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Sound travels through air at a speed of 342m/s
342
m
/
s
at room temperature. What is the frequency of a sound wave with a wavelength of 1.8m
1.8
m
Answers
Answer:
Explanation:
The formula relating the speed of sound, frequency, and wavelength is:
speed = frequency x wavelength
Rearranging this formula to solve for frequency:
frequency = speed / wavelength
Substituting the given values:
frequency = 342 m/s / 1.8 m
frequency = 190 Hz
Therefore, the frequency of the sound wave is 190 Hz.
what is 100+10000000000000000000
Answers
Answer:
200000000000000000000000
Explanation:
Answer:
10000000000000000100
Explanation:
A machine has a velocity ratio of 5 and the efficiency is 80% what effort would be needed to lift a load of 200N
Answers
Explanation:
To determine the effort needed to lift a load of 200N, given a velocity ratio of 5 and an efficiency of 80%, we can use the formula:
Efficiency = (Output Work / Input Work) * 100
Efficiency can also be calculated as the ratio of the output force to the input force. In this case, the output force is the load being lifted (200N), and the input force is the effort required.
Given that the velocity ratio is 5, it means that for every 5 units of distance the effort moves, the load moves 1 unit of distance. This implies that the effort is exerted over a greater distance than the load.
Let's denote the effort force as "E" and the distance moved by the effort as "dE." Similarly, the load force is "L," and the distance moved by the load is "dL."
Using the velocity ratio, we have the following relationship:
dE / dL = 5
Now, we can calculate the input work (Wi) and the output work (Wo):
Input Work (Wi) = Effort (E) * Distance moved by the effort (dE)
Output Work (Wo) = Load (L) * Distance moved by the load (dL)
Given that the efficiency is 80%, we can rewrite the formula for efficiency as:
0.80 = (Wo / Wi) * 100
Now, let's solve for the effort (E) using the given values:
Load (L) = 200N
Efficiency = 0.80
Velocity Ratio = 5
First, calculate the output work (Wo):
Wo = Load (L) * Distance moved by the load (dL)
Since the velocity ratio is 5, the distance moved by the load (dL) will be 1/5 of the distance moved by the effort (dE):
dL = (1/5) * dE
Wo = L * (1/5) * dE
Wo = 200N * (1/5) * dE
Wo = 40N * dE
Next, calculate the input work (Wi):
Wi = Effort (E) * Distance moved by the effort (dE)
Wi = E * dE
Now, substitute the values into the efficiency formula:
0.80 = (Wo / Wi) * 100
0.80 = (40N * dE) / (E * dE) * 100
0.80 = 40 / E * 100
0.80 * E = 40
E = 40 / 0.80
E = 50N
Therefore, the effort needed to lift a load of 200N with a velocity ratio of 5 and an efficiency of 80% is 50N.
1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air is added to the tire, assuming the temperature is constant?
Answers
Answer:
Explanation:
It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.
why does pure water increase in volume when heated
Answers
Answer:
Pure water increases in volume when heated due to the phenomenon of thermal expansion. When water is heated, the kinetic energy of its molecules increases, causing them to move faster and spread out. This increased molecular movement leads to an increase in the average distance between water molecules, resulting in an expansion of the water.
Explanation:
.......
You have three resistors: R1 = 1.00 Ω, R2 = 2.00 Ω, and R3 = 4.00 Ω in parallel. Find the equivalent resistance for the combination
Answers
Answer:
4 / 7
Explanation:
1/total resistance = 1/1 + 1/2 + 1/4
= 1¾
total resistance = 1 ÷ 1¾
= 4/7
How much would a 15.0 kg object weigh on that planet? Round the answer to the nearest whole number.
Answers
Answer:
168
Explanation:
Answer: a 15 kg object would weigh the most on Neptune
168 N
A truck goes 5500 meters in 25 minutes, what is the speed of the truck?
Answers
Answer:
220
Explanation:
5500 divided by 25 is 220
Answer:
it's easy the answer is 500 just multiple 500 times 25 and you will get 5500
Anna is writing a test. She is so focused on writing the test that she does not hear the invigilator remind her that she only has five minutes to complete her test. Anna is engaged in
Answers
Answer:
selective attention
Explanation:
What is another name for lane D in the diagram?
Answers
B . A positive control
Match each method of transferring electric charge with the correct description
friction
transfer of electric charge without direct
contact
induction
transfer of electric charge by rubbing
conduction
transfer of electric charge by direct contact
Answers
The matching of each method of transferring electric charge with the correct description should be explained below.
Matching of transferring electric charge?The friction means the transfer of electric charge via rubbing. The conduction means the transfer of electric charge via the direct contact.
Also, the induction means the transfer of the electric charge without the direct contact.
In this way it should be matched.
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Answer:
this is the answer that is correct
CAN SOMEONE PLZ HELP
Answers
Answer:
magnetic force.
Explanation:bc it makes sense, and can i please get brainliest answer i never asked. its ok if you say no. have a great day <3.
Which correctly describes latent heat?
A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid
Answers
Option C. The heat absorbed or lost by a substance while it's changing state correctly describes latent heat
Latent heat is the heat absorbed or lost by a substance while it is changing state.
The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.
For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.
Latent heat is not associated with a temperature change; rather, it's associated with a change of state.
For instance, the temperature of water remains at 100°C while boiling.
When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.
When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.
Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.
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Before a collision, a 25 kg object is moving at 12 m/s to the right. After a collision with stationary box, the 25 kg object moves at 8 m/s to the right. What is the resulting momentum of the box?
Answers
The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.
kinetic energy during an object falling
Answers
Answer:
\(kinetic \: energy = \frac{1}{2} m {v}^{2} \\ m = mass \: of \: the \: object \\ v = velocity \: \)
5. Apply Concepts A heat engine has an energy input of 300 J. Its output of use-
ful energy is 150 J. What is the total output of non-useful energy from the heat
engine? Explain how you know.
Answers
Given the data from the question, the total output of non-useful energy from the heat engine is 150 J
What is a heat engine?A heat engine is a device / equipment that can convert or transfer thermal energy into useful-work. Some examples of heat engines include
refrigeratorsInternal combustion Thermal power stationfirearms heat pumpsHow to determine output non-useful energyFrom the question given above, the following data were obtained:
Input energy = 300 JOutput (useful) = 150 JOutput (non-useful) =?Output (non-useful) = Input – Output (useful)
Output (non-useful) = 300 – 150
Output (non-useful) = 150 J
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A soccer ball is kicked with an initial horizontal velocity of 11 m/s and an initial vertical velocity of 17 m/s.
1)what is the initial speed of the ball?20.25 m/s
2)what is the initial angle 0 of the ball with respect to the ground? 57.09 degrees
3)what is the maximum height the ball goes above the ground? 14.74m
I need help with 4,5 and 6
4)How far from where it was kicked will the ball land?
5) what is the speed of the ball 2.5 second after it was kicked?
6)how high above the ground is the ball 2.5 seconds after it is kicked?
Answers
The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and 6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.
4) To calculate the distance from where the ball was kicked, we need to find the time it takes to reach the ground. We can use the fact that the vertical displacement of the ball is zero at the highest point. Using the formula vf = vi + at, the time it takes to reach maximum height is t = vf / g where g is the acceleration due to gravity which is -9.8 m/s² since it is downward and vf is the final velocity which is 0 because the ball comes to rest at the highest point. t = 17 / 9.8 = 1.73 s. This means the total time for the ball to hit the ground is 2 x 1.73 = 3.46 s. Using the formula for horizontal distance traveled d = vt, we get d = 11 x 3.46 = 38.06 m. So, the distance from where the ball was kicked will be 38.06 meters.5) To calculate the speed of the ball 2.5 seconds after it was kicked, we need to find the horizontal and vertical components of the velocity of the ball at 2.5 seconds. The horizontal component is constant, so it will still be 11 m/s. To find the vertical component, we use the formula vf = vi + at where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. vf = 17 + (-9.8 x 2.5) = -7.5 m/s. Since the ball is moving downward, the velocity is negative. Therefore, the speed of the ball 2.5 seconds after it was kicked is sqrt(11² + (-7.5)²) = 13.82 m/s.6) To calculate how high above the ground is the ball 2.5 seconds after it is kicked, we use the formula for the displacement of an object in the vertical direction y = vi*t + (1/2)*a*t² where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. y = 17*2.5 + (1/2)*(-9.8)*(2.5)² = 21.88 m. So, the ball is 21.88 m above the ground 2.5 seconds after it is kicked.For more questions on speed
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Why is it called a building if it’s already built
Answers
Answer:
Because the 'ing' in the English language is added to certain verbs to make them nouns.
Explanation:
Hope this helps :D
Explanation:
It is called a building because the ‘ing’ in the English language is added to certain verbs to make them nouns. The verb ‘built’ is suffixed with ‘ing’ to make the thing a noun- Building.
Reason: The act is of building it when the actual work is in progress. Building is a gerund- a noun made from a verb. Any action verb can be made a gerund
A student must use an object attached to a string to graphically determine the gravitational field strength near Earth's surface. The student attaches the free end of the string to the ceiling and pulls the object-string system so that the string makes an angle of 5 degrees from the object's vertical hanging position. The student then releases the object from rest and uses a stopwatch to measure the time it takes for the object to make one complete oscillation. Which of the following is the next step that will allow the student to determine the gravitational field strength?
А) Repeat the experiment by adding additional mass to the object for multiple trials
B) Repeat the experiment by changing the length of the string for multiple trials
C) Repeat the experiment by changing the angle that the string makes with the object's vertical hanging position
D) Repeat the experiment by measuring the time it takes to make two oscillations, three oscillations, and additional oscillations for multiple trials
Answers
Answer:
B) True. By changing the length get a different period and with a graph you can find the best value of the gravity pull
Explanation:
The student is reacting a simple pendulum experiment where he can determine the value of the relationship of gravity with the expression
T = 2π \(\sqrt{\frac{L}{g} }\)
let's analyze each statement
A) False. The mass is not a paramer of the period expression
B) True. By changing the length get a different period and with a graph you can find the best value of the gravity pull
C) False. The angle while it is small does not influence the period
D) True. By changing the number of oscillations the period does not change, so you can get the value of the pull of gravity.
We can see that the expressions B and d are true, the most exact value is obtained using procedure B since the graphs allow to reduce the errors
A man pushing a crate of mass
m = 92.0 kg
at a speed of
v = 0.855 m/s
encounters a rough horizontal surface of length
ℓ = 0.65 m
as in the figure below. If the coefficient of kinetic friction between the crate and rough surface is 0.359 and he exerts a constant horizontal force of 289 N on the crate.
A man pushes a crate labeled m, which moves with a velocity vector v to the right, on a horizontal surface. The horizontal surface is textured from the right edge of the crate to a horizontal distance ℓ from the right edge of the crate.
(a) Find the magnitude and direction of the net force on the crate while it is on the rough surface.
magnitude
N
direction
Opposite Direction or Same Direction
(b) Find the net work done on the crate while it is on the rough surface.
J
(c) Find the speed of the crate when it reaches the end of the rough surface.
m/s
Answers
(a) The magnitude and direction of the net force on the crate while it is on the rough surface is 34.7 N in opposite direction.
(b) The net work done on the crate while it is on the rough surface is -22.6 J.
(c) The speed of the crate when it reaches the end is 0.5 m/s.
What is the net force on the crate while it is on the rough surface?
The magnitude and direction of the net force on the crate while it is on the rough surface is calculated as follows;
F (net) = F - Ff
where;
F is the applied forceFf is the frictional force on the crateF (net) = F - μmg
where;
μ is the coefficient of frictionm is massg is gravityF (net) = 289 N - (0.359 x 92 X 9.8)
F (net) = -34.7 N
The negative sign indicates opposite direction to the applied force.
The net work done on the crate while it is on the rough surface is calculated as follows;
W = F(net) x L
where;
L is the distance travelled by the crateW = -34.7 x 0.65
W = -22.6 J
The speed of the crate when it reaches the end is calculated as follows;
acceleration of the crate = F(net) / m
a = -34.7 N / 92 kg
a = -0.377 m/s²
v² = u² + 2aL
v² = ( 0.855)² + ( 2 x -0.377 x 0.65)
v² = ( 0.855)² - ( 2 x 0.377 x 0.65)
v² = 0.24
v = √ 0.24
v = 0.5 m/s
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A steel column is 3 m long and 0.4 m diameter. It carries a load of 50 MN. Given that the
modulus of elasticity is 200 GPa. Calculate the compressive stress.
Answers
The compressive stress in the steel column is found to be approximately 397.6 MPa.
The formula for calculating the area of a circle can be used to determine the steel column's cross-sectional area (A),
A = π*(d/2)², diameter of the column is d,
A = π*(0.4/2)²
A = 0.1257m²
The compressive stress (σ) in the column can be calculated using the formula, σ = F/A, F is the load carried by the column is F.
σ = 50 MN/0.1257m²
σ = 397.6 MPa
Therefore, the compressive stress in the steel column is approximately 397.6 MPa.
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A ball is tossed up into the air with an initial speed of 5.0. How long does it take to return to the person's hand
Answers
Answer:
Explanation:
\(y(t) = 5t-5t^2\)
When y(t) = 0, the ball is on the hand.
\(0=5t-5t^2\\0=5t(1-t)\\t=0,1\)
It takes 1 second.
There are several different possibilities.
==> If the 5.0 means 5 miles per hour, that's 2.24 meters per second, up.
The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (2.24/9.8) = 0.229 second. Then, after is starts to fall, it takes the same amount of time to the person's hand.
Total time = 0.457 second.
==> If the 5.0 means 5 meters per second, up . . .
The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (5.0/9.8) = 0.51 second. Then, after is starts to fall, it takes the same amount of time to the person's hand.
Total time = 1.02 second.
==> If the 5.0 means 5 km/minute, that's about 83.33 meters per second, up.
The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (83.33/9.8) = 8.503 seconds. Then, after is starts to fall, it takes the same amount of time to the person's hand.
Total time = 17.01 seconds.
==> If the 5.0 means 5 furlongs per fortnight, that's about 0.00083 meters per second, up.
The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (0.00083/9.8) = 0.000085 second. Then, after is starts to fall, it takes the same amount of time to the person's hand.
Total time = 0.00017 second.
This is why all of your numbers always need their units.
Find the acceleration due to gravity on planet Fergie which has a mass of 6.23 * 10^23 kg and a radius of 5.79* 10^7 m
Answers
Answer:
The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
Explanation:
We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.
Now, the acceleration due to gravity is defined through the following equation:
\(mg = GMm/R^2\)
where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.
Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get
g = 0.0123 m/s^2.
Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
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There are four springs stretched by the same mass. Spring A stretches 25 cm. Spring B stretches 10 cm. Spring C stretches 100 cm.
Spring D stretches 1 cm.
Which spring is the weakest?
O B
D C
Answers
Answer:
spring D stretches the weakest
How do you find the period of a sound wave?
Answers
Answer:
Period refers to the time for something to happen and is measured in seconds/cycle. In this case, there are 11 seconds per 33 vibrational cycles. Thus the period is (11 s) / (33 cycles) = 0.33 seconds. We now know that the period is 3.2 seconds and that the frequency is 0.31 Hz.
The power of the heater is 50 W. The mass of the sand in the cup is 550 g. The initial temperature of the sand is 20 °C. The heater is switched on for 2.0 minutes. The temperature is recorded until the temperature stops increasing. The highest temperature recorded by the thermometer is 33 °C. (a) Calculate the energy supplied by the heater.
Answers
Answer:
6000J
Step-by-step:
To calculate the energy supplied by the heater, we can use the formula:
Energy = Power x Time
where power is measured in watts (W) and time is measured in seconds (s). However, in this problem, we are given the power in watts and the time in minutes, so we need to convert the time to seconds before we can use the formula.
1 minute = 60 seconds
Therefore, 2.0 minutes = 2.0 x 60 seconds = 120 seconds
Now we can use the formula to calculate the energy supplied by the heater:
Energy = Power x Time
Energy = 50 W x 120 s
Energy = 6000 J
Therefore, the energy supplied by the heater is 6000 joules (J).
Hope this helps!
A 66 kg driver gets into an empty taptap to start the day's work. The springs compress 2.3×10−2 m
. What is the effective spring constant of the spring system in the taptap?
Enter the spring constant numerically in newtons per meter using two significant figures
Answers
Explanation:
You want N/m
N = 66 * 9.81
m = 2.3 x 10^-2 m
66* 9.81 / 2.3 x 10^-2 = 28150 = 28 000 N/m to two S D
The components of lifetime fitness include all of the following components except
Answers
Answer:it’s A
Explanation:
because i took the quiz
Answer:
D is the correct answer, not A
Explanation: