Choose the best real world exzample of convection:
A. clouds forming in the atmosphere
B. touching a warm cooking pot handle
C. sitting in front of a warm fireplace

WHICH ONE IS THE ANSWER HELP PLESEEE

Answers

Answer 1
The correct answer is A
Answer 2
I think that it is B. I’m not completely sure. I hope that I helped

Related Questions

Calculate the electric field when the forces is 2N and the medium is mica

Answers

Answer:

E₀ = 5.97 10⁸ N / C

Explanation:

Coulomb's law in a material medium is written

       \(F = \frac{1}{4\pi \epsilon } \frac{q_{1} q_{2} }{r^{2} }\)

ε is the electrical permittivity of the material

Electric field and force are related        

          F = q E

in dielectric materials such as mica there is an electric field inside the material that decreases the external field

           E = E₀ /ε

where ε is the electrical permittivity of the material; in general it is tabulated in the form

           \(\epsilon _{r} =\frac{\epsilon}{\epsilon_{o}}\)

          \(\epsilon = \epsilon_{r} \ \epsilon_{o}\)

we substitute

          F = q E₀ /  \epsilon_{r}  \epsilon_{o}

         \(E_{o} = \frac{F \ \epsilon_{r} \ \epsilon_{o} }{q}\)

for the case of mica it is equal to er = 5.4 and suppose a test charge equal to the charge of the electron

we calculate

          E₀ = 2  5.4  8.85 10⁻¹² / 1.6 10⁻¹⁹

          E₀ = 59.74 10⁷

          E₀ = 5.97 10⁸ N / C

_____ is a device
which increases or decreases voltage.
Iron
core
Electricity Primary
Coil
(input)
Secondary Electricity
Coil
in
out
(output)
100 V
10 A
1000 W
static charge
charges
transformer
force field
Primary
55 turns
Secondary
20 turns
Core
400 V
2.5 A
1000 W

_____ is a devicewhich increases or decreases voltage.IroncoreElectricity PrimaryCoil(input)Secondary

Answers

Answer:

transformers

Explanation:

A transformer is a device that increases or decreases voltage.

Select the correct answer. A truck moves 60 kilometers east from point A to point B. At point B, it turns back west and stops 15 kilometers away from point A. What are the total distance and total displacement of the truck? A. The total distance is 105 kilometers, and the total displacement is 15 kilometers east. B. The total distance is 105 kilometers, and the total displacement is 45 kilometers east. C. The total distance is 60 kilometers, and the total displacement is 60 kilometers east. D. The total distance is 60 kilometers, and the total displacement is 45 kilometers east. E. The total distance is 105 kilometers, and the total displacement is 75 kilometers east.

Answers

Answer:

Option a

Explanation:

a high energy pulsed laser emits a 2.9 ns long pulse with average power of 2.38 tw.. the beam is 0.41 cm in radius. what is the energy delivered in each pulse. what is the average value of the magnitude of the electric field

Answers

The energy delivered in each pulse is 690 Joules. The average value of the magnitude of the electric field is  1.303 × 10¹¹ V/m.

What is an electric field?

A region of space surrounding an electrically charged particle or object known as an electric field is one in which an electric charge would experience force. A vector quantity called an electric field can be represented by arrows pointing in the direction of or away from charges.

Pulse emitted = 2.9 × 10(-9) s

Radius = 4.1 × 10⁻³ m

Power= 2.38 × 10¹¹ W

Energy = U=P × t

=2.9 × 10⁻⁹ ×2.38 × 10''

= 690 Joule

The electric field RMS value is given by

S= P/A = cε₀ E²(rms)

\(E_{rms}= \sqrt{\frac{P}{Ac\epsilon_{0}} } \\=\sqrt{\frac{2.38\times 10^{11}}{\pi((4.1\times10^{-3})^{2})(3\times10^{8})(8.85\times10^{-12})}\)

= 1.303 × 10¹¹ V/m

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A body is positively charged, it implies that:
a. there is only a positive charge in the body
b. there is positive as well as negative charge in the body but the positive charge is more than negative charge
c. there is equally positive and negative charge in the body but the positive charge lies in the outer regions
d. the negative charge is displaced from its position​

Answers

When a body is positively charged, it implies that there is positive as well as negative charge in the body but the positive charge is more than negative charge.

Most of the materials that make up our world are composed of atoms, which are made up of a nucleus containing protons and neutrons surrounded by electrons. When an atom loses or gains electrons, it becomes positively or negatively charged, respectively. This is because the number of protons in an atom, which determines its atomic number and chemical properties, does not change.

When there are more protons than electrons, the atom becomes positively charged, and when there are more electrons than protons, it becomes negatively charged.Positive charge is the property of a material that has lost one or more electrons and therefore has more protons than electrons. Positive charges repel other positive charges, while negative charges attract positive charges.

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how long did it take a plane to fly south for 1000 meters at a rate of 5m/s

Answers

Answer:

200 seconds

Explanation:

Time = 1000/5

= 200s

A circular loop of wire with a radius of 13.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magnetic field. A field of 1.7 T is directed along the positive z-direction, which is upward. PART A: If the loop is removed from the field region in a time interval of 2.9 ms, find the average emf that will be induced in the wire loop during the extraction process.

Answers

The average emf that will be induced in the wire loop during the extraction process is 31.12 V.

A round circle of wire with a sweep of 13.0 cm and situated in the level xy-plane is situated in a district of uniform attractive field. Along the positive z-direction, which is up, a field of 1.7 T is directed.  In the event that the loop is removed from the field region within 2.9 milliseconds,

The typical emf that will be actuated in the wire circle during the extraction process= e =(π) r² B/t

                e = π × 169× 10⁻⁴ × 1.7/(2.9× 10⁻³)

                        = 31.12 V

What is the induced emf?

The occurrence of a potential difference in a coil as a result of changes in the magnetic flux that passes through it is what we mean by this term. In simpler terms, when the flux linking with a conductor or coil changes, electromotive force, or EMF, is said to be induced.

An induced emf is caused by what?

Changes in magnetic flux are the most fundamental cause of an induced EMF. Putting a current conveying loop that is moving continually in a steady and static attractive field. EMF will be produced as a result of a change in the area vector brought about by this.

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Two people carry identical 40.0N boxes up the ramp. The ramp is 2.00m long and 1.00m high. Person A walks up the ramp in 2.00s. Person B walks up the ramp in 4.00s. What is the difference in power the two people use to carry the boxes up the ramp

Answers

The difference in power for two people carrying the boxes up the ramp is 30 W.

Given the following data:

W = 40.0 N is the weight of a box.

The ramp's length is L = 2.00 m.

The platform height is h = 1.0 m.

t = 2.0 s is the time interval for the first person.

t' = 4.0 s is the time interval for the other person.

Power is the rate at which energy is used. The expression for the Power is given in the given question as,

P = W×(L+h)/t

Assume that you are solving for the first person.

P₁ = W(L+h)/t₁.................................................................. (1)

Substitute the following values into equation (1):

P₁ = 40(2+1)/2

P₁ = 20(3) (3)

P₁ = 60 W.

Regarding the second person,

P₂ = W(L+h)/t₂..................................................................... (2)

Fill in the blanks in equation (2) as follows:

P₂ = 40(2+1)/4

P₂ = 10*(3) *3)

P₂ = 30 W

Obtaining the difference in power as

P = P₁ - P₂

P = 60-30

P = 30 W

As a result, we can conclude that the difference in power for two people carrying the boxes up the ramp is 30 W.

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Approximately how long does it take the uterus lining to build up again after menstruation

Answers

The uterus lining is rebuilt by the end of the menstrual period. The rebuilding of the uterus lining starts after menstruation and the lining is typically completely rebuilt by day 14 of the menstrual cycle, which is when ovulation occurs and the uterus is preparing to potentially receive a fertilized egg.

The endometrium is the inner lining of the uterus, and it thickens every month to prepare for pregnancy. After menstruation, the endometrium grows and thickens to prepare for the implantation of a fertilized egg. The cells in the lining multiply and enlarge, and the glands in the lining begin to secrete mucus and other substances that help support the fertilized egg and promote its growth.

The rebuilding of the endometrium usually takes about two weeks after menstruation. This process is closely regulated by hormones such as estrogen and progesterone, which are produced by the ovaries and other parts of the body. These hormones help control the growth and development of the endometrium and other reproductive tissues.

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What's Alpha beta gamma emission??

Answers

Alpha radiation is the name for the emission of an alpha particle in fact an helium nuclei, beta radiation is the emission of electrons or positrons , and gamma radiation is the term used for the emission of energetic photons.

A car can go from 0 m/s to 38 m/s in 4.5 seconds. If a net force of 6570 N acted on
the car, what is its mass

Answers

The Mass of the car = 782.1 Kg

What is the mass of the car?

The mass of the car is calculated as follows:

Mass = Force/ acceleration

The force on the car = 6570 N

The acceleration of the car, a = 38 - 0/4.5

acceleration = 8.44 m/s²

Mass of the car = 6570/8.44

Mass of the car = 782.1 Kg

In conclusion, the mass of the car is obtained from the acceleration and force on the car.

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What is the primary purpose of wires in a circuit

Answers

Answer:

Electrical wire is used for power distribution to transmit electricity from a transformer or other source to an outlet, appliance, device, cable, switch, distribution board, socket, and light fitting. They conduct electricity and provide a low-resistance path for electricity to flow through.

Explanation:

( hope this is correct )

Calculate the kinetic energy of a car which has a mass of 1000 kg and is moving at the rate of 20 m/s.

Answers

Given,

The mass of the car, m=1000 kg

The velocity of the car, v=20 m/s

The kinetic energy of an object is the energy of the body possessed due to its motion. The kinetic energy of a body is directly proportional to the square of the velocity of the object.

The kinetic energy of the car is given by,

\(E=\frac{1}{2}mv^2\)

On substituting the known values,

\(\begin{gathered} E=\frac{1}{2}\times1000\times20^2 \\ =200000\text{ J} \\ =200\text{ kJ} \end{gathered}\)

Thus the kinetic energy of the given car is 200 kJ.

If a car lighter has a resistance of 3Ω how much power does it use running off a 12 Volt battery? a. 12 milliWatts b. 12 Watts c. 48 kW d. 120 Watts e. 144 Watts

Answers

The power used by car lighter when running off a 12 Volt battery is 48 Watts, the correct answer is (c) 48 kW (kiloWatts) can be expressed as 0.048 kW.

To calculate the power used by the car lighter running off a 12 Volt battery, we can use the formula:

Power (P) = (Voltage (V))^2 / Resistance (R, )Given that the resistance of the car lighter is 3 Ω and the battery voltage is 12 Volts, we can

substitute these values into the formula:

P = (12 V)^2 / 3 Ω

P = 144 V^2 / 3 Ω

Simplifying the equation, we find:

P = 48 Watts.

When one watt of power is used to travel between two points on a wire carrying one ampere of current, there is a difference in potential between those points of one volt.

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The application of 16 Newtons of force to an egg results in the egg accelerating at 68.6 m/s^2 what is the mass of the egg? Round to the nearest hundredths

Answers

Answer:

The mass of the egg = 0.23 kg

Explanation:

The force, F = 16 N

The acceleration, a = 68.6 m/s²

The relationship between the force (F), acceleration (a), and mass (m) is:

F = ma

Substitute F = 16, a = 68.6, and solve for m

16 = 68.6m

m = 16/68.6

m = 0.23 kg

ANSWER PLEASE!!! I NEED THE HORIZONTAL DISPLACEMENT!!!! A small plane is flying at 85 m/s as it passes directly over your brand-new car when a passenger drops his backpack. It takes 9 seconds for the backpack to fall to the ground. You are very worried that the backpack will land on your new car and you wonder if you should move it. What will be the horizontal displacement of the backpack as it fall? Should you move your car?

Answers

Answer: Δx = vxt = (85 m/s)(9s) = ? m

Explanation:

If the plane is in level flight,

 

Δx = vxt = (85 m/s)(9s) = ? m

 

Note that if Δx ≠ 0, it will not land on the car.

The values for the horizontal displacement and repositioning of the car are;

As it falls, the backpack will have a maximum horizontal displacement (away from the car) of 795 meters

The car should remain in its current position; Do not move the car

The reason the above values are correct is as follows;

The known information about the airplane, the backpack and the car are;

The speed of the airplane = 85 m/s

The time it takes the backpack to fall to the ground, t = 9 seconds

The position of the airplane when the backpack is dropped = Directly over the brand new car

Required:

The horizontal displacement of the backpack as it fallsShould the car be moved

Solution to the first question:

The horizontal displacement of the backpack = Horizontal velocity × Time, t

According to Newton's First Law of motion, the velocity of the backpack at the point it was dropped is the same as the velocity of the airplane

Given that the velocity of the airplane given is the horizontal velocity, we have;

The horizontal velocity of the backpack = 85 m/s

The displacement of the backpack = 85 m/s × 9 s = 795 m

The horizontal displacement of the backpack as it falls = 795 meters in front of the car

Solution to the second question:

Given that the backpack will land 795 meters in front, away from the car, the car is safe if it remains in its current position

The car should not be moved

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Consider the flask diagramed below with the following pressures 492 torr H2 and 0.376 atm for N2. What are the final partial pressures of H2 and N2 after the stopcock between the 2 flask is opened? (Assume the final volume is 3.00L). What is the total pressure in torr?

Answers

After the stopcock is opened the final pressure in the flask is 172.92 torr, the final partial pressure of H2 is 492 torr, and the final partial pressure of N2 is 0.376 atm.

The final partial pressures of H2 and N2 after the stopcock between the two flasks is opened are given by the Ideal Gas Law (PV=nRT).

The Ideal Gas Law states that the product of the pressure, volume, and molar amount of a gas is equal to the product of the universal gas constant, R, and the temperature.

At constant temperature, the product of pressure and volume is directly proportional to the number of moles of gas, n. Therefore, when the stopcock is opened, the number of moles of H2 and N2 in the final flask is the sum of the number of moles in the original flasks.

The number of moles of H2 in the first flask is given by n1 = (P1V1) / (RT) = (492 torr x 2.00 L) / (0.0821 atm x L / mol x 273K) = 0.0428 mol

The number of moles of N2 in the second flask is given by n2 = (P2V2) / (RT) = (0.376 atm x 1.00 L) / (0.0821 atm x L / mol x 273K) = 0.0141 mol

The final number of moles of H2 and N2 is n = n1 + n2 = 0.0428 mol + 0.0141 mol = 0.0569 mol

After the stopcock is opened, the final pressure is equal to the product of the number of moles, n, and the ideal gas constant, R, and the temperature divided by the final volume Vf,

Pfinal = nRT / Vf = 0.0569 mol * 0.0821 atm x L / mol x 273K / 3.00 L = 0.0227 atm

In torr, the final pressure is Pfinal760 = 0.0227760 =172.92 torr.

The final partial pressure of H2 is 492 torr and the final partial pressure of N2 is 0.376 atm.

In conclusion, after the stopcock is opened the final pressure in the flask is 172.92 torr, the final partial pressure of H2 is 492 torr, and the final partial pressure of N2 is 0.376 atm.

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how many molecules are in 3 moles of CO2

Answers

Answer:

1.806 x 10^24  molecules

Explanation:

1 mole of CO2 has 6.02 x 10^23 molecules

3 mole of CO2 has 3x6.02x10^23 molecuels = 1.806 x 10^24 molecules

The 3 mole of \(CO_{2}\) contains \(1.8066*10^{24}\) molecules.

One mole of \(CO_{2}\) contains \(6.022*10^{23}\) molecules.

In 3 moles of \(CO_{2}\) ,

                              \(=3*6.022*10^{23}=1.8066*10^{24}\) molecules.

Hence, the 3 mole of \(CO_{2}\) contains \(1.8066*10^{24}\) molecules.

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Which friction requires the least amount of force to overcome fluid friction or sliding friction?

Answers

Fluid friction requires less force to overcome than sliding friction. Fluid friction is the resistance to an object's motion through a fluid, such as air or water.

This type of friction depends on the shape and size of the object, as well as the properties of the fluid, such as viscosity. In general,

with streamlined shapes experience less fluid friction than those with irregular shapes.



Sliding friction, on the other hand, is the force that opposes the motion of two surfaces sliding against each other. This type of friction is caused by the irregularities on the surfaces that come into contact,

which resist the motion of one surface over the other. Sliding friction is affected by the materials of the surfaces and the force pushing the surfaces together.



In terms of the force required to overcome these types of friction, fluid friction requires less force than sliding friction. This is because fluid friction depends on the object's shape and size,

and the properties of the fluid, while sliding friction is determined by the force pushing the surfaces together and the materials of the surfaces.

Therefore, if you were trying to move an object, it would require less force to overcome fluid friction than sliding friction.

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A cart with a mass of 5.0 kg accelerates from rest due to a force of 10.0 N being applied to it at an angle of 30 degrees above the horizontal. Assuming no friction, what is the velocity of the cart after 5 seconds

Answers

The velocity of the cart after 5 seconds, assuming no friction, is 10.0 m/s.

Given: Mass of the cart, m = 5.0 kg Force acting on the cart, F = 10.0 N Angle of force with horizontal, θ = 30°Time taken by the cart, t = 5.0 s To find: Velocity of the cart after 5.0 s (v)We know that the acceleration (a) produced in the cart is given as

a = F/m,

which is equal to (10/5) = 2.0 m/s²Also, the horizontal component of force, Fcosθ = (10cos30°) = (10 × √3/2) = 5√3 N. The velocity of the cart after 5 seconds can be determined using the following kinematic equation: v = u + at Where ,u is the initial velocity of the cart (0, as it was at rest)Substituting the given values, we get :v = u + at v = 0 + (2.0 m/s² × 5.0 s) So ,v = 10.0 m/s

Hence, the velocity of the cart after 5 seconds, assuming no friction, is 10.0 m/s.

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write down the atomic numbers of nitrogen and sodium ?​

Answers

Answer:

Nitrogen is 7, sodium is 11

Answer:

\(nitrogen = 7 \\ atomic \: number \: of \: sodium = 11 \\ thank \: you\)

a 50 gram bullet is fired at a 2 kg block of lead resting on a frictionless surface. the bullet has an initial speed of 500 m/s, while the block is initially at rest. after hitting the block, the bullet rebounds with a speed of 300 m/s. how fast is the lead block moving after the bullet rebounds off of it? a. 10 m/s b. 20 m/s c. -5 m/s d. 5 m/s

Answers

The lead block is moving at a speed of 1 m/s after the bullet rebounds off of it. The correct answer is (c) -5 m/s.  

First, we need to find the momentum of the bullet before it hits the block:

p_bullet = m_bullet * v_bullet = 50 * 500 = 25,000 g

We also need to find the momentum of the block before the bullet hits it:

p_block = m_block * v_block = 2 * 2000 = 4000 g

After the bullet hits the block, it rebounds with a speed of 300 m/s. The momentum of the bullet after the collision is:

p_bullet_after = m_bullet * v_bullet_after = 25,000 * 300 = 750,000 g

The momentum of the block after the collision is:

p_block_after = m_block * v_block_after = 4000 * 300 = 120,000 g

The momentum of the system (bullet + block) before the collision is:

p_system_before = p_bullet + p_block = 750,000 + 120,000 = 870,000 g

The momentum of the system after the collision is:

p_system_after = p_bullet_after + p_block_after = 750,000 + 120,000 = 870,000 g

We want to find the speed of the block after the collision, so we can set the total momentum of the system before and after the collision equal to each other:

p_system_before = p_system_after

870,000 g = 750,000 g + 120,000 g

870,000 g = 870,000 g

Dividing both sides by 870,000 g gives us:

v_after = 1

Therefore, the lead block is moving at a speed of 1 m/s after the bullet rebounds off of it. The correct answer is (c) -5 m/s.  

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Combustion reactions take place between a fuel and oxygen and produce carbon dioxide and water. Balance the following combustion reaction.

Answers

The balanced reaction of combustion of a fuel is 6H2O + 4CO2 = 2C2H6 + 7O2 which produces oxygen.

Combustion is a chemical reaction during which a fuel is oxidized and a large quantity of energy is released. The oxidizer is often air. Fuel: any material that can be burned to release thermal energy. Most familiar fuels are hydrocarbons and are denoted by the general formula of CnHm. For example octane is C8H18.

A combustion process is complete if all the carbon in the fuel burns to CO2, all the hydrogen burns to H2O, and all the sulfur (if any) burns to SO2. That is, all the combustible components of a fuel are burned to completion during a complete combustion process.

In actual combustion processes, it is common practice to use more air than the stoichiometric amount to increase the chances of complete combustion or to control the temperature of the combustion chamber. The amount of air in excess of the stoichiometric amount is called excess air.

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Balanced reaction of combustion of a energy is 6H2O 4CO2 = 2C2H6 7O2 which produces oxygen.

Combustion can be defined as a chemical response in which which a energy is oxidized and a large volume of energy is released. The oxidizer is frequently air. Energy any material that can be burned to release thermal energy. utmost familiar energies are hydrocarbons and are denoted by the general formula of CnHm. For illustration octane is C8H18.

A combustion process is complete if all the carbon in the energy burns to CO2, all the hydrogen burns to H2O, and all the sulfur( if any) burns to SO2. That is, all the combustive factors of a energy are burned to completion during a complete combustion process.

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Question 1 (5 points) What is the frictional force acting on a 100 kg box as it moves across the floor with an acceleration of 1.5 m/s2, if the applied force is 300N? -150 N Ob 150 m/s2 C 150 N od -300 N Review Answers​

Answers

Answer:HJKGFHJYKIUGFJDTGYKUGFJDSX

Explanation:65TTY6Y Y YY. ;D DDS

HVC BJCHGNMGHJFYIKUHYGFTR6457TY8IUOHJKGYTDYR567YUOI8HJKBGJMVHDTR5E46T7Y TFGDGHYUFVYH T7UYGHUGFTY Y6TURF67URY

two carts collide and bounce apart. cart 1 had a momentum of –6 kg • m/s before the collision. cart 2 had a momentum of 10 kg • m/s before the collision. what is the total momentum of the carts after the collision? –16 kg • m/s –10 kg • m/s 4 kg • m/s 10 kg • m/s

Answers

The total momentum of the carts after the collision is –16 kg · m/s. The momentum of an object is given by the product of its mass and velocity.

The momentum of an object is given by the product of its mass and velocity. In this case, we know the momentum of each cart before the collision, but we need to use the law of conservation of momentum to find the total momentum of the carts after the collision. The law of conservation of momentum states that the total momentum of a system remains constant if there is no external force acting on the system. In this case, there is no external force acting on the carts, so the total momentum of the carts before the collision is equal to the total momentum of the carts after the collision. We can use the law of conservation of momentum to set up an equation:

Total momentum before collision = Total momentum after collision

(–6 kg · m/s) + (10 kg · m/s) = Total momentum after collision

Total momentum after collision = (–6 kg · m/s) + (10 kg · m/s)

Total momentum after collision = 4 kg · m/s

Therefore, the total momentum of the carts after the collision is 4 kg · m/s,

However, we need to note that the question is asking for the total momentum of the carts after the collision in terms of the momentum of cart 1 and cart 2, so we need to subtract the momentum of cart 2 from the momentum of cart 1 to get the total momentum of the carts after the collision:

Total momentum after collision = Momentum of cart 1 after collision

Momentum of cart 2 after collision

Total momentum after collision = (–6 kg · m/s) – (10 kg · m/s)

Total momentum after collision = –16 kg · m/s

Therefore, the answer is –16 kg · m/s,

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The total momentum of the carts after the collision is -16 kg · m/s. The carts collide and bounce apart, with Cart 1 having a momentum of -6 kg · m/s and Cart 2 having a momentum of 10 kg · m/s before the collision. After the collision, the momentum of the two carts is combined to give a total momentum of -16 kg · m/s.

In more detail, momentum is a vector quantity that represents the motion of an object and is calculated by multiplying its mass and velocity. When two objects collide, the total momentum before the collision is equal to the total momentum after the collision, assuming no external forces are involved. In this case, Cart 1 has a momentum of -6 kg · m/s, indicating it is moving in the opposite direction with respect to a chosen positive direction. Cart 2 has a momentum of 10 kg · m/s, indicating it is moving in the positive direction. After the collision, the carts bounce apart, resulting in a total momentum of -16 kg · m/s, with the negative sign indicating the direction opposite to the chosen positive direction.

Mathematically, we can express the total momentum of the carts after the collision as follows:

\(\[ \text{Total momentum} = \text{Momentum of Cart 1} + \text{Momentum of Cart 2} = -6 \, \text{kg} \cdot \text{m/s} + 10 \, \text{kg} \cdot \text{m/s} = -16 \, \text{kg} \cdot \text{m/s} \]\)

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A ball is thrown with an initial velocity of 20 m/s at an angle of 60° above the horizontal. If we can neglect air resistance, what is the horizontal component of its instantaneous velocity at the exact top of its trajectory?.

Answers

Answer:

\(10\; {\rm m\cdot s^{-1}}\).

Explanation:

Under the assumption that air resistance on the ball is negligible, gravitational pull from the Earth would be the only force acting on the ball during the flight.

The resultant force on the ball would be equal to the gravitational pull, which is entirely in the vertical direction. Thus, the net force in the horizontal direction would be \(0\) while the ball is in the air.

By Newton's Laws of Motion, since horizontal acceleration is \(0\) during the flight, velocity of the ball in the horizontal direction would stay unchanged in a translational equilibrium.

It is given that the ball was launched at an angle of elevation of \(\theta = 60^{\circ}\) above the horizon. The initial velocity \(u\) of the ball can be decomposed into two components:

Initial vertical velocity: \(u\, \sin(\theta)\) (opposite to the angle of elevation,) andInitial horizontal velocity \(u\, \cos(\theta)\) (adjacent to the angle of elevation.)

With \(u = 20\; {\rm m\cdot s^{-1}}\), the horizontal velocity of the ball at launch would be \((20\; {\rm m\cdot s^{-1}})\, \cos(60^{\circ}) = 10\; {\rm m\cdot s^{-1}}\).

Since the horizontal velocity of the ball stays unchanged during the flight, the horizontal velocity of the ball at the vertex of the trajectory would be equal to the value at launch: \(10\; {\rm m\cdot s^{-1}}\).

What do you think about replacing people with robots in some spheres of life? minimum 30 words


good luck ;)

Answers

Answer: good depending on what the robot is doing

Explanation:

Robots replacing people in some spheres of life would ensure that many dangerous jobs are taken over so that human casualties would significantly decrease such as mining.However, in a death to death situation leaving it up to a robot can be very one sided to some people and can cause two sides of an argument to arise. Some saying that the robot should have 'killed' one choice and some would say the other choice or the original choice the robot chose.

For example a self driving car, comes in path to either choose to drive into a innocent person on the side walk killing them, a brick wall killing the passengers in the car, the car in front killing the people in the front car or a harmless stray dog.

Humans have that choice as a quick decision to make at the spur of the moment as they deem fit. However if the robot decides to crash into the dog some may say that they would have crashed into the car in front. ect.

Overall, yes there are some places where robots can replace people and it will be a positive result, while there are other places where a robot taking over a persons 'job' could be a negative result.

Immediately after the switch is closed, what is the current in the circuit?.

Answers

Immediately after the switch is closed, the current in the circuit will be maximum.

Immediately after the switch is closed, the capacitor behaves like a short circuit and the current flows as if there is no resistance in the circuit.

This makes the current maximum when the switch is closed.

However, the current will gradually decrease as the capacitor starts to charge up and the voltage across it increases. After the capacitor is fully charged, the current will become zero as the capacitor will not allow any further flow of current.

Summary:After the switch is closed, the current in the circuit is maximum due to the capacitor behaving like a short circuit at that moment. However, the current will decrease as the capacitor charges up, and will become zero when the capacitor is fully charged.

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Question 4 Multiple Choice Worth 4 points)
(02.02 MC)
How do weathering and deposition differ?

Answers

Answer:

its A Weathering breaks down rocks; deposition leaves them in new places

Explanation:

Calculate Ax if v = 30 m-s¹ and At = 15 s.​

Answers

The acceleration at x is 2 m/s²

What is the acceleration at x?

Acceleration (a) is the rate of change of velocity (v) with respect to time (t).

The formula to calculate acceleration is:

a = (v - u) / t

Where u is the initial velocity (assuming u = 0 m/s in this case, since it's not given).

Substituting the given values, we get:

a = (v - u) / t

a = (30 m/s - 0 m/s) / 15 s

a = 2 m/s²

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