check the file.........................................................................................................
Answers
What is meant by the number of complete oscillation made by an oscillating body in 10 seconds is 500 complete oscillations is that the frequency of the oscillating body is 50Hz
What is frequency?
Frequency of an oscillating body can be defined as the number of complete oscillations per unit time
Frequency is measured in hertz (Hz).
Also, the frequency of 1Hz is one oscillation per second.
frequency = number of oscillations/ time taken
frequency = 500/10 = 50 Hz
Thus, what is meant by the number of complete oscillation made by an oscillating body in 10 seconds is 500 complete oscillations is that the frequency of the oscillating body is 50Hz
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Related Questions
The argument against your claim (what the other side would say if they disagreed with your claim.) is:
Group of answer choices
counterclaim
author's purpose
opinion
argument
Answers
Answer:
a counterclaim
Explanation:
authors purpose is what an author wrote somthing for
opinion is someones thoughts or "side" on a argument
an arguement is a battle of opinions if that makes sense
An incandescent bulb is supplied with
100 J of energy every second and
transfers 5 J of energy by light
Calculate the efficiency of the bulb.
I need some help can you explain this to me please and thank you
Answers
Answer:
Efficiency = 5%
Explanation:
Given that,
Supplies energy to the bulb = 100 J
Transferred energy by the bulb = 5 J
We need to find the efficiency of the bulb. It can be given by "
\(\eta=\dfrac{\text{useful energy out}}{\text{useful energy in}}\times 100\\\\=\dfrac{5}{100}\times 100\\\\=5\%\)
So, the efficiency of the bulb is 5%.
Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.
Answers
No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.
This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.
i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.
ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.
The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.
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How are period and frequency related to each other?
A. Period is half the frequency
B. Period is twice the frequency
C. Period is equal to frequency
D. Period is the reciprocal of frequency
E. Period is the day root of frequency
Answers
Answer:
D
Explanation:
this is because the formula for frequency is
f = 1/T
and it is a reciprocal
the solution to the assessment problem is found by representing each of the coupled inductors as __________.
Answers
The solution to the assessment problem can be found by representing each of the coupled inductors as a set of ideal transformers.
This allows us to apply the concepts of mutual inductance and coupling coefficient to determine the overall behavior of the circuit. By breaking down the coupled inductors into their individual components, we can then apply standard circuit analysis techniques to solve for the voltage, current, and power in the system. It is important to note that the accuracy of this approach may be limited by the assumptions made about the behavior of the transformers and the accuracy of the models used to represent them.
In many practical applications, this method can provide a useful approximation for understanding and designing complex systems.
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Whenever energy is changed from one form to another is some energy lost as heat
Answers
Answer:
That is very true, there can never be 100% energy conversion.
4.) An 800-kg elevator is lifted vertically by a strong rope. Find the acceleration of the elevator if the rope tension is (a) 9000 N, (b) 7840 N, and (c) 2000 N.
Answers
Answer:
A) 11.25 m/s2
B) 9.8m/s2
C) 2.5 m/s2
Explanation:
Based on Newton's laws of motion, we know that the acceleration experienced by an object is directly proportional to the force acting on it, with its mass being the constant of proportionality.
Simply, we can represent this using the formula: F = Ma
Where F = force (N)
M = mass of the object (800kg)
a = acceleration of the object.
Making acceleration the subject of the formula, we have
acceleration = Force / mass
We can now use this to solve for the various forces.
A) Force = 9000 N
a = 9000/ 800 = 11.25 m/s2
B) Force = 7840 N
a = 7840/800 = 9.8m/s2
C) Force = 2000N
a = 2000/800 = 2.5 m/s2
For general projectile motion with no air resistance, the vertical component of a projectile's acceleration For general projectile motion with no air resistance, the vertical component of a projectile's acceleration remains a non-zero constant. continuously decreases. first decreases and then increases. is always zero. continuously increases.
Answers
Answer:
Rmains constant
Explanation:
The equation of the trajectory of a projectile motion is presented as follows;
\(Y = x \cdot tan \theta -\dfrac{g \cdot x^2}{2 \cdot u^2 \cdot cos^2 \theta}\)
The vertical componet of the prjectile motion is
y = (u·sinθ)·t - g·t²/2
Where;
θ = The angle with which the projectile is launched
x = The horizontal distance
u = The initial velocity of the projectile
g = The acceleration due to gravity = Constant
t = The time of motion
The acceleration acting on the projectile is the 'g' which is the constant acceleration due to gravity
Therefore, for general projectile motion with no air resistance, the vertical component of the projectile acceleration remains constant
In terms of diameter, the planet saturn is larger than _______ , but smaller than _______.
Answers
Answer:
Larger than mercury, venus, earth, mars, uranus, neptune
smaller than jupiter
The work function for metallic cesium is 2.14eV. Calculate the kinetic energy and the speed of the electrons ejected by light of wavelength: a) 740 nm b) 350 nm
Answers
Answer: (a) The speed is zero.
(b) The speed of the electrons ejected by light of wavelength 350 nm is 6.0 × 10⁵ m/s.
a) Let's find out the energy of the incident light by using E = hc/λ
where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength of the light. Here we have λ = 740 nm = 7.4 × 10⁻⁷m
So, E = hc/λ
= (6.63 × 10⁻³⁴ J.s × 3 × 10⁸ m/s)/(7.4 × 10⁻⁷m)
= 2.69 × 10⁻¹⁹ J.
Since the work function is given in electron volts, we need to convert the energy into eV.1 eV = 1.6 × 10⁻¹⁹ J2.69 × 10⁻¹⁹ J = (2.69 × 10⁻¹⁹ J / 1.6 × 10⁻¹⁹ J/eV) = 1.68 eVThe kinetic energy of the ejected electron can be calculated as the difference between the energy of the incident light and the work function.KE = E - Φ = 1.68 eV - 2.14 eV = -0.46 eV. Since the electron has a negative kinetic energy, it is not ejected. Therefore, the speed is zero.
b) To find the speed, we can use the formula: KE = 1/2 mv²
v = √(2KE/m)
The mass of the electron is 9.11 × 10⁻³¹ kg. So,
v = √(2 × 1.41 eV × 1.6 × 10⁻¹⁹ J/eV / 9.11 × 10⁻³¹ kg)= 6.0 × 10⁵ m/s.
Therefore, the speed of the electrons ejected by light of wavelength 350 nm is 6.0 × 10⁵ m/s.
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Question:
Define work.
Answers
Answer:
Work, in physics, refers to the measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.
Hey there!
Work is defined as the the force which gets applied to an object in order to displace (move) it. For example, you work in order to walk up & down the stairs. For this, you need to apply force as well. So, work done = force × distance.
Hope it helps!
A T-shirt cannon needs to launch shirts as far as possible. What angle should the cannon be fired at?
Parallel to the ground 30 degrees
over the ground 45 degrees
over the ground 60 degrees
over the ground
Answers
Answer:
over the ground 45 degrees
Explanation:
the distance from the point of no return to the intersection is the same no matter what speed you are going. true or false
Answers
It is FALSE to state that the distance from the point of no return to the intersection is the same no matter what speed you are going.
What is the Point of No Return in Traffic?If you are 100 feet or fewer from the junction, you have passed "the point of no return" and cannot safely halt before the intersection. As a result, it is preferable to proceed through the junction at your present, legal speed, but with extreme caution.
The point of no return is the moment at which you can no longer halt without entering that space, which is two seconds away. Time yourself in this scenario. Red, green, and flashing lights Yellow arrows: Each traffic signal turn is a dangerous 4-second danger zone. The riskiest is a left turn that requires you to stop and surrender.
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A car starts from rest and constantly accelerates at a rate of 10 [m/s2 ] during a 402 [m] race. how fast is the car going at the finish line?
Answers
A car starts from rest and constantly accelerates at a rate of 10 [m/s2 ] during a 402 [m] race. At the finish line, the speed of the car is \(\mathbf{89}.\mathbf{6660}\ \mathbit{m}/\mathbit{s}\).
The initial velocity of the car \(u = 0\)
Constant acceleration \(a = 10~ m/s^2\)
Distance of the Race \(d = 402~ m\)
The car is accelerating with a constant acceleration \(a\) , so the car's velocity will change with time as it approaches the finish point which is at a distance \(d\) from the initial point.
Newton's equation is the backbone of Classical Mechanics. Let's say the velocity of the car at the finish line is \(v\). We know that displacement is the product of average velocity and time.
Or \(s=\frac{u+v}{2}\times t\)
Using Newton’s first equation \(v\ =\ u\ +\ at\)
Newton's equation of motion turns out to be,
\(v^2 = u^2+2ad\)
\(v^2 = 2\times 10 \times 402\)
so, \(v = \sqrt{8040} = 89.6667 ~m/s\)
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In the figure, the north pole of the magnet is first moved down toward the loop of wire, then withdrawn upward. As viewed from above, the induced current in the loop is A) always clockwise with increasing magnitude B) always clockwise with decreasing magnitude C) always counterclockwise with increasing magnitude D) always counterclockwise with decreasing magnitude E) first counterclockwise, then clockwise-
Answers
In the attached figure, north pole of magnet first moved down toward the loop of wire and withdrawn upward then the induced current in the loop is equals to the first clockwise, then counter-clockwise. So, option(d) is right one.
A magnet is a bar magnetic which produces the magnetic field and attract or reple other objects.
North pole of the magnet faces the loop. First it is move up away from the loop. According to Lenz's law, the induced current in the loop is such that it opposes the cause producing it. So, the current will try to pull back the magnet towards it. We knoe opposite pole attract each other, so the pole induced in the loop should be south. We also know that clockwise current produces a south pole and counterclockwise current produces a north pole. Hence the direction of current is clockwise. Then, the magnet is moved down towards the loop. For similar reasons, the loop will try to push it back up. Hence the current is counterclockwise so as to generate north pole.
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Complete question:
The attached figure complete the question.
Drift velocity (v) of the charge carriers is given by the equation...
Answers
The drift velocity (v) of charge carriers in a conductor is given by the following equation: v = I / (n \(\times\) A \(\times\) q).
v = I / (n \(\times\) A \(\times\) q)
where:
v is the drift velocity, measured in meters per second (m/s)
I is the current flowing through the conductor, measured in amperes (A)
n is the number of charge carriers per unit volume of the conductor, measured in per cubic meter (\(m^(-3)\))
A is the cross-sectional area of the conductor, measured in square meters (m^2)
q is the charge of a single carrier, such as an electron, measured in coulombs (C)
This equation relates the drift velocity of the charge carriers to the current flowing through the conductor, the number of charge carriers per unit volume, the cross-sectional area of the conductor, and the charge of a single carrier. The drift velocity represents the average velocity of the charge carriers as they move through the conductor in response to an applied electric field.
The number of charge carriers per unit volume (n) depends on the material of the conductor and the temperature. In metals, the charge carriers are typically electrons, and the number density is on the order of 10^28 to 10^29 electrons per cubic meter.
The cross-sectional area (A) of the conductor is the area of the cross-section of the conductor perpendicular to the direction of the current flow, and is a measure of the amount of material available for the charge carriers to move through.
The charge of a single carrier (q) is typically the charge of an electron, which is approximately 1.6 x \(10^{-19\) coulombs.
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Which of the following statements correctly summarizes the events in the early universe according to the Big Bang theory?A. The Big Bang began with the initiation of what we call inflation, which gradually slowed to the current expansion rate of the universe. Forces came to exist for a different reason, having to do with quantum fluctuations in the space-time continuum. Particles came to exist as a result of cracks made when forces froze. Once there were particles, gravity brought them together to make stars, and the stars then turned the particles into hydrogen, helium, and other elements.B. An episode of what we call inflation initiated the event of the Big Bang. Once the Big Bang got underway, particles and forces began to appear one by one. The forces produced protons, which fused to make hydrogen and helium until the universe was about 380,000 years old. Then gravity began to act, turning the hydrogen and helium into galaxies.C. Forces and various subatomic particles began to appear during the first second after the Big Bang. For reasons not understood, the particles were all made of ordinary matter and none were made of antimatter, thus explaining why we live in a universe made of matter. The particles underwent some fusion for the first 380,000 years after the Big Bang, at which time the first stars were born.D. The universe began with the forces unified. During the first fraction of a second, the forces separated and there was a brief but important episode of inflation. Subatomic particles of both matter and antimatter then began to appear from the energy present in the universe. Most of the particles annihilated to make photons, but some became protons, neutrons, electrons, and neutrinos. The protons and neutrons underwent some fusion during the first three minutes, thereby determining the basic chemical composition of the universe.
Answers
The correct statement summarizing the events in the early universe according to the Big Bang theory is option D.
After the forces of the cosmos came together, there was a time of inflation. Then subatomic matter and antimatter particles appeared, the majority of which annihilated to produce photons. Protons, neutrons, electrons, and neutrinos were among the particles that did not decay, though. During the first three minutes, protons and neutrons fused, revealing the universe's basic chemical make-up.
All of the fundamental forces of nature were combined in the early moments of the Big Bang. But the forces split into various interactions as the cosmos grew and contracted. This trend was accompanied by inflation, a rapid expansion. After inflation, a hot, thick soup of energy flooded the entire cosmos.
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PLEASEHELP THANK YOU SM
Answers
Answer:
I belive it would be the first answer choice.
Explanation:
When the Mass is lower, the ball moves faster so it would have more kintetic energy
If a 5 kg cart is pulled with a net force of 20 Newtons. What is the magnitude, in m/s2, of the acceleration?
Answers
Answer:
F=ma
a=F/m=20/5=4 m/s^2
If the mass of block B is 2kg, the gravitational force exerted on block B is most nearly which of the following?
0.2N
2N
20N
P.S The acceleration is 10m/s^2 but I have no idea how to get that, so could someone explain that to me.
Answers
Answer:
20 N.
Explanation:
The following data were obtained from the question:
Mass of block B (m) = 2 Kg
Acceleration due to gravity (g) = 10 m/s²
Gravitational force (F) =..?
Force is simply defined as the product of mass and acceleration i.e
Force = mass (m) × acceleration (a)
F = ma
Thus, we can say that the gravitational force on block B will be the product of the mass of block B and acceleration due to gravity i.e
Gravitational force (F) = mass of block B (m) × acceleration due to gravity (g)
F = mg
Mass of block B (m) = 2 Kg
Acceleration due to gravity (g) = 10 m/s²
Gravitational force (F) =..?
F = mg
F = 2 × 10
F = 20 N
The, the gravitational force exerted on block B is 20 N
Gravitational force exerted on block B is 20 N
Given that;
Mass of block = 2 kg
Acceleration = 10 m/s²
Find:
Gravitational force exerted on block B
Computation:
Gravitational force = ma
Gravitational force exerted on block B = Mass of block × Acceleration
Gravitational force exerted on block B = 2 × 10
Gravitational force exerted on block B = 20 N
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Which of these is a covalent compound?
Responses
CO
upper case C O,
LiCl
upper case L lower case i upper case C lower case l,
AlCl3
upper case A lower case l upper case C lower case l subscript 3 end subscript,
MgO
Answers
Answer: CO
I hope this helps
Answer:
co
Explanation:
A 2 kg book is sitting on a table. A 10 n force is pulling to the right. A 3 n force is pulling to the left. What is the net force acting on the book?.
Answers
The net force acting on the book is 7N right.
The net force is defined as the total of all forces exerted on an object. Net force is essential since it aids in describing the motion of an item and can be used to calculate acceleration. The first law of motion of Isaac Newton states that an object in motion will remain in motion and an object at rest will remain at rest unless acted upon by a net force that is imbalanced. This indicates that knowing the net force acting on an object will aid in predicting its velocity.
In this case, we are given that:
Force F1 = 10 N pulling to the right
Force F2 = 3 N pulling to the left
Let's assume the right is positive and the left is negative.
To calculate the net force, we can use this following formula:
Fnet = F1 + F2
Fnet = 10 + (-3)
Fnet = 7
As the result, the net force would be 7 N.
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Which of the following statements about Australian football is TRUE?
A.
The players tend to wear a large amount of padding.
B.
Goals are scored by kicking the ball through goalposts.
C.
Each team has a number of set plays for both offense and defense.
D.
The constant movement of the ball is similar to baseball.
Answers
Answer:
B.
Goals are scored by kicking the ball through goalposts.
Explanation:
According to the superposition principle of waves, A. when two wave pass through the same material they always double in amplitude. B. many different waves can pass through the same point at once. C. when two waves pass through the same material they always cancel each other out. D. only one wave is able to pass through a single point at a single time.
Answers
Answer:
a
Explanation:
A doll sets on the a table 3 meters high weighing 1.5kg. What is the gravitational potential energy?
A-4.5 joules
B-19.6 joules
C-14.7 joules
D-44.1 joules
Answers
Answer:
Explanation:
A - 4.5
an oil film ( ) floating on water ( ) is illuminated by white light at normal incidence. the film is thick. the reflected light will be predominately a single color. find the wavelength of the dominant visible light among the reflected light. take the range of visible light to be - .
Answers
The visible range is 6.02×10^-7 m.
The refractive index of the oil film is n=1.58
The thickness of the film is , t=286 nm= 286×10^-9 m
2nt=( m+ ½) λ
m=0, 1, 2,.....
Substituting m=0, t and n
2× 1.58 ×(286×10^-9) =(0+½) λ=1.81×10^-6m (This is of infrared range)
Substituting m=1, t and n
2× 1.58 ×(286×10^-9) =(1+½) λ=1.81×10^-6=6.02×10^-7 m, this is visible range
About wavelengthWaves are vibrations that propagate. There are many types of waves such as sound waves, mechanical waves, to electromagnetic waves. All waves have different characteristics.
The physical characteristics of the wave are represented by the wavelength, frequency, amplitude, direction of vibration, and also the direction of propagation. Wavelength is the distance of one wave and is represented by the Greek letter Lambda (λ).
On transverse waves, length can be calculated as the distance from the peak of the wave to the crest of the next wave, or the trough of the wave to the trough of the next. Whereas in longitudinal waves, the wavelength can be calculated from one stretch to the next stretch, or the distance from one density to the next.
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please help and thanks
Answers
Answer:
the first on the left goes with the 3rd on the right
second left last right
3rd goes with 1st
4th goes with 5th
5th goes with 4th
and last but not least 6th goes with the second
Explanation:
if im correct mark brainliest if im wrong leave a comment.Consider the vibrations of a 2-dimensional square lattice with lattice constant a. There is only one atom in each primitive cell. Atoms have a mass M, and they can only oscillate out of the plane (transverse motion). We assume only nearest neighbour interactions (spring between nearest neighbour atoms) with a force constant a. Let Um denote the transverse displacement from equilibrium of the atom in the / row and the m column of the 2D lattice. (a) Show that the equation of motion for the displacements in is: M am = a[(u1+1,m + U1–1,m - 2uim) + (U1,m+1 + U1m-1 - 2uim)] (b) Show that the dispersion relation is given by the expression Mw2 = 2a[2 - cos(qxa) - cos(qya)]
Answers
In this scenario, we are considering the vibrations of a 2-dimensional square lattice with a lattice constant of a. Each primitive cell contains only one atom with a mass of M that can only oscillate out of the plane (transverse motion).
We are assuming that the interactions between nearest-neighbor atoms are only through springs, with a force constant of a.
To show the equation of motion for the displacements, let Um denote the transverse displacement from the equilibrium of the atom in the / row and the m column of the 2D lattice. The equation of motion is given by:
M am = a[(u1+1,m + U1–1,m - 2uim) + (U1,m+1 + U1m-1 - 2uim)]
This equation relates the acceleration of the atom in the / row and the m column to the displacements of its nearest neighbors.
To show the dispersion relation, we need to find the relationship between the frequency of vibration and the wave vector of the lattice. The dispersion relation is given by:
Mw2 = 2a[2 - cos(qxa) - cos(qya)]
Here, qxa and qya are the components of the wave vector in the x and y directions, respectively. This equation shows that the frequency of vibration is proportional to the wave vector and the mass of the atoms.
Overall, these equations describe the behavior of vibrations in a 2-dimensional square lattice with nearest neighbor interactions and transverse motion.
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A 1.00-kg glider attached to a spring with a force constant 25.0 N/m oscillates on a frictionless, horizontal air track. At t = 0, the glider is released from rest at x = -2.80 cm (that is, the spring is compressed by 2.80 cm). (a) Find the period of the glider's motion. How does the period depend on the mass and the spring constant? Does it depend on the amplitude of oscillation? s (b) Find the maximum values of its speed and acceleration. speed m/s acceleration m/s2 (c) Find the position, velocity, and acceleration as functions of time. (Where position is in m, velocity is in m/s, acceleration is in m/s2, and t is in s. Use the following as necessary: t.) x(t) = v(t) = a(t) =
Answers
Answer:
a) T = 1.26 s , b) v_max = 0.14 m / s , a_max = 0.7 m / s²
c) x = 0.028 cos (5 t) , v = - 0.14 sin 5t, a = - 0.7 cos 5t
Explanation:
This is a simple harmonic motion exercise that is described by the equation
x = A cos (wt +Ф)
with
w = √ (k / m)
let's apply this expression to our case
a) Angular velocity is related to frequency
w = 2π f
frequency and period are related
f = 1 / T
we substitute
2π / T = √ (k / m)
T = 2π √(m / k)
let's calculate
T = 2π √(1/25)
T = 1.26 s
In the expression for the period, the amplitude does not appear, therefore there is no dependence, as long as Hooke's law is fulfilled, which is correct for small amplitudes.
b) in the initial equation we have the position as a function of time, let's use the definition of speed and acceleration
v = dx / dt
v = - A w sin (wt + Ф)
the speed is maximum when the sine is -1
v_max = A w
w = √ (k / m)
w = √ 25/1
w = 5 rad / s
the amplitude of the movement is equal to the maximum compression of the spring
A = 2.8 cm = 0.028 m
we substitute
v_max = 0.028 5
v_max = 0.14 m / s
acceleration
a = dv / dt
a = - A w² cos (wt + Ф)
the acceleration is maximum when the cosine is -1
a_max = A w²
let's calculate
a_max = 0.028 5²
a_max = 0.7 m / s²
c) let's start by finding the phase constant
v = -A w cos (wt + Ф)
at t = 0 they indicate that the system has v = 0
0 = -A w sin (0 + Ф)
Ф = sin⁻¹ 0
Ф = 0
we write the equation
x = 0.028 cos (5 t)
v = - A w sin (wt + Ф)
v = - 0.028 5 sin (5t + 0)
v = - 0.14 sin 5t
acceleration
a = - A w² cos (wt + Ф)
a = - 0.028 5 2 cos (5 t + 0)
a = - 0.7 cos 5t
relative to sphere at the speed of sphere Z is _ m/s
Answers
We are given that a sphere Z moves with a relative speed of 1 m/s with respect to sphere X which moves at 5 m/s. Let's draw the velocity vectors of the spheres:
Where:
\(\begin{gathered} v_x=\text{ velocity of sphere x} \\ v_z=\text{ velocity of sphere z} \end{gathered}\)From the relative velocity equation we have:
\(v_z=v_r+v_x\)Where:
\(v_r=\text{ velocity of z relative to x}\)Since we are given the relative velocity we can plug in the values to get the velocity of "z":
\(\begin{gathered} v_z=1\frac{m}{s}+5\frac{m}{s} \\ \\ v_z=6\frac{m}{s}_{} \end{gathered}\)Now, we do the same but now using the sphere Y:
Now, we use the relative velocity equation for these velocities:
\(v_z=v_r+v_y\)In this case, we have that:
\(v_r=\text{ velocity of z with respect to y}\)Now, we subtract the velocity of "y" from both sides:
\(v_z-v_y=v_r\)Substituting the values:
\(6\frac{m}{s}-2\frac{m}{s}=v_r\)Solving the operations:
\(4\frac{m}{s}=v_r\)Therefore, the velocity of "Z" relative to "Y" is 4 m/s.
