Chauncy is driving down the hill that descends at an angle a 4.5° below horizontal. After driving 4.60 kilometers along the road, how much elevation has chauncy lost?

To solve this, we must know each and every concept behind velocity and its calculation. Therefore,  the car's velocity after it has traveled 35.0 m is 157.5m/s.

Velocity is the vector measurement of an object's rate of motion and direction of motion. As a result, in order to calculate velocity using this definition, we must be familiar with both magnitude and direction.

For example, if an item travels west with 5 meters a second (m/s), its velocity to the west will be 5 m/s. The most frequent and simplest approach to determine velocity is using the formula shown below.

Mathematically,

Vf= Vi +2as

Vf= final velocity=?

Vi= initial velocity=0

s= displacement =35.0 m

substituting all the given values in the above equation, we get

Vf=0+2× 4.50 ×35

Vf=157.5m/s

Therefore,  the car's velocity after it has traveled 35.0 m is 157.5m/s.

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Answer:

density = mass/volume

density=0.8

volume=36

mass=?

0.8=mass/36

mass = 36x0.8=28.8g

Explanation:

As the source of sound waves approaches you the sound waves get closer together, increasing their frequency and the pitch of the sound. The opposite happens when the source of sound waves moves away from you

Answer:

obviously sasuke

Explanation:

everyone is always over estimating borutos powers like lets be real here sasuke is almost as strong as naruto and when they were younger he had better hand to hand combat and in jutsu's he was a prodigy and he is able to calculate precise movements to try and defeat his oponent lets not forget that he has the sharingon over whatever jutsus boruto has (i dont know because ive never seen the anime and i dont plan on doing so) (i hate boruto its trash) which means he could read borutos chakra and he would be more powerful because his sharingan awoken when he was a mear child he would be much more powerful beause hes mastered his sharingan. oh yeah and his fire ball and chidori (which could k!11 boruto if sasuke inflicts enough chakra into his jutsu) (if u want to say otherwise my pronouns are she/her so use them if u want to say something involving pronouns thanks)

We have the following regarding the motion;

1) The height from which the glasses fell is  278 m

2) The velocity at the time of the fall is 74 m/s

3) The acceleration of the hot balloon is 9.8 m/s^2

We know that we can obtain the height that the glasses started falling from by the use of the equation;

h = ut + 1/2 gt^2

h = height

u = initial velocity

g = acceleration due to gravity

t = time taken

Then;

h = (5.4 * 7) + (0.5 * 9.8 * (7)^2)

h = 37.8 + 240.1

h = 278 m

The velocity when it fell to the ground is obtained from;

v = u + gt

v = 5.4 + (9.8 * 7)

v = 74 m/s

c) Given the fact that the motion was under gravity, the hot balloon was having an acceleration of 9.8 m/s^2

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Answer:

\(5,480\:\text{N}\)

Explanation:

The formula for work is given by \(W=F\Delta x\), where \(F\) is the force applied over a distance of \(\Delta x\).

Plugging in given values, we get:

\(16,700=F\cdot 3.05,\\F=\frac{16,700}{3.05},\\F\approx \boxed{5,480\:\text{N}}\)(three significant figures).

Answer ; 5

Explanation: hope it helps ur welcome

Nuisance static charges are more likely to occur when the air is dry.

When the air is dry, it is not able to hold a sufficient amount of moisture or humidity. When the moisture content of the air is low, the air has a low electrical conductivity, which increases the likelihood of static charges.Static electricity can be created by the rubbing of two objects. When these objects are separated after rubbing, they are left with a static electric charge. The strength of the electric charge is determined by the materials used to create the two objects. Some materials are better at holding static charges than others.

Dry air only exacerbates the situation. Static charges can be a nuisance for a variety of reasons. They can cause shocks, interfere with electronic devices, and can even cause damage to sensitive equipment. In order to reduce the occurrence of static charges, it is important to ensure that the air in your environment is sufficiently humid. This can be achieved by using a humidifier or by simply placing bowls of water around the room. Additionally, anti-static products, such as sprays and mats, can be used to reduce the occurrence of static charges.

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Answer:

Josie's ball faster than T

Answer:

20 N exerts no torque about the pivot.

14 N exerts a counterclockwise torque of 14 * .3 = .42 N-m

6  exerts a clockwise torque of 6 * .7 = .42 N-m

The meter stick will not turn because there is no net torque on the meter stick.

The answer is C. I searched it up and people keep on saying that it's B, which is incorrect. I found another question on Brainly where someone said that C was the answer and the person who asked the question said "Correct, thanks."

Answer:B

Explanation:

Answer:

The answer is B.

Explanation:

edge2020

Answer:

This is known as a Waxing Crescent Moon. This Moon can be seen after the New Moon, but before the First Quarter Moon. The crescent will grow larger and larger every day, until the Moon looks like the First Quarter Moon.

Answer:

Explanation:

The centripetal acceleration:

aₙ = F /m = 125 /19 ≈ 6.6 m/s²

The seagull will fly 134 meters in 10.0 seconds if its velocity remains constant at 13.4 meters per second.

The pace at which an object's position changes about a frame of reference is known as its velocity, and it depends on time. A specification of a thing's speed and direction of motion is what velocity is.

The various forms of velocities include uniform, variable, average, and instantaneous velocities.

The body is said to be moving at a uniform speed if it travels the same distance in the same amount of time. If the body goes in a straight line without changing its direction, the velocity is said to be constant. In all scenarios, there is no acceleration.

Given:

Velocity = 13.4 m/s

Time = 10.0 s

The distance the seagull will fly can be calculated by multiplying its velocity by the time it travels:

distance = velocity x time

distance = 13.4 m/s x 10.0 s

distance = 134 meters

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Answer:

8173.8 km

Explanation:

Fg=G(M*m/r^2)

r=sqrt(G*M*m/Fg)

G=6.6743*10^-11

M(earth)=5.972*10^24kg

M(object)=352kg

Fg=-2100N

r=sqrt((6.6743*10^-11)*(5.972*10^24kg)*(352)/-2100)

r=8173808m

r=8173.8km

According to Newton's calculations, gravity reduces to a fourth of what it was at the surface of the Earth if the distance from the planet's centre is doubled. At the Earth's surface, a satellite with a mass of 1,000 kg exerts a weight force of 9,800 N.

Satellites are pulled toward Earth by its gravity, even when they are hundreds of kilometres distant. The satellite doesn't fall back to Earth; instead, it travels into orbit above it due to gravity and the velocity it acquired during launch into space.

A satellite that is in a steady circular orbit around the Earth is always falling. It encounters a gravitational pull toward the centre of Earth as it orbits, which forces it to shift course and “fall” towards Earth.

Therefore, Since gravity is the only force acting on a satellite in circular orbit, the centripetal force and gravity must be equal: Fc = Fg.

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The magnitude of the weight of the disk is greater than the magnitude of the tension force of the string. ((c) \(F_{T} < F_{g}\))

A rigid body is a system whose geometry cannot be neglected and in which deformations due to external forces applied on the system are negligible.

In this question we need to establish a free body diagram with all critical forces and motion conditions. There are two external forces: (i) tension (\(F_{T}\)), (ii) weight (\(F_{g}\)), both in newtons.

The disk falls due to gravity and rotates around the string in a case of rolling, which combines rotation and translation. By Newton's laws of motion we have the following expression:

\(\sum F = -F_{g}+F_{T} = -m\cdot R\cdot \alpha\)   (1)

Where:

By algebra we derive the following relationship between the two forces:

\(-F_{g} = -F_{T}-m\cdot R\cdot \alpha\)

\(F_{g} > F_{T}\)

Therefore, the magnitude of the weight of the disk is greater than the magnitude of the tension force of the string. ((c) \(F_{T} < F_{g}\)) \(\blacksquare\)

The statement is incomplete and poorly formatted. Correct and complete form is shown below:

A thin uniform disk of mass m and radius r has a string wrapped around its edge and attached to the ceiling. The bottom of the disk is at height 3R above the floor, as shown above. The disk is released from rest. The rotational inertia of a disk around its center is \(I = \frac{1}{2}\cdot M\cdot R^{2}\).

When released from rest, the disk falls and the string unwinds. The force that the string exerts on the disk is \(F_{T}\), and the gravitational force exerted on the disk is \(F_{g}\). Which of the following expression correctly relates \(F_{T}\) and \(F_{g}\) as the disk falls?

(a) \(F_{T} > F_{g}\), (b) \(F_{T} = F_{g}\), (c) \(F_{T} < F_{g}\)

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Answer:

speed

Explanation:

After the collision, the momentum of the two-mass system must be conserved. The momentum of the system before the collision is equal to the momentum of the system after the collision. Therefore, the momentum of the two-mass system before the collision is equal to the momentum of the two-mass system after the collision.

Before the collision, the momentum of mass A is 8 kg m/s (10 kg times 8 m/s). The momentum of mass B before the collision is -12 kg m/s (30 kg times -4 m/s). Therefore, the total momentum of the two-mass system before the collision is equal to 8 - 12 = -4 kg m/s.

After the collision, the momentum of the two-mass system must also equal -4 kg m/s. Since mass A has a mass of 10 kg and mass B has a mass of 30 kg, we can set up the following equation:

10vA + 30vB = -4 kg m/s

Solving this equation for vB gives us the following expression:

vB = (-4 kg m/s - 10vA) / 30

We can substitute the initial velocity of mass A, 8 m/s, into this equation to get the final velocity of mass B:

vB = (-4 kg m/s - 10(8 m/s)) / 30

vB = -6 m/s

Since momentum must be conserved, the final velocity of mass A must be equal to the total momentum of the system (minus the momentum of mass B) divided by the mass of mass A. This gives us the following expression:

vA = (-4 kg m/s + 30(-6 m/s)) / 10

vA = 2 m/s

Therefore, the final velocity of mass A is 2 m/s and the final velocity of mass B is -6 m/s.

The change in momentum of mass A is equal to the initial momentum of mass A minus the final momentum of mass A.

The initial momentum of mass A before the collision is 8 kg m/s (10 kg times 8 m/s). The final momentum of mass A after the collision is 2 kg m/s (10 kg times 2 m/s). Therefore, the change in momentum of mass A is equal to 8 - 2 = 6 kg m/s.

The change in momentum of mass B is equal to the initial momentum of mass B minus the final momentum of mass B.

The initial momentum of mass B before the collision is -12 kg m/s (30 kg times -4 m/s). The final momentum of mass B after the collision is 6 kg m/s (30 kg times -6 m/s). Therefore, the change in momentum of mass B is equal to -12 - 6 = -18 kg m/s.

The impulse experienced by mass A is equal to the change in momentum of mass A divided by the time during which that change occurs. Since the change in momentum of mass A is 6 kg m/s and the time of the collision is likely instantaneous, the impulse experienced by mass A is 6 kg m/s.

The net force on mass A is equal to the impulse experienced by mass A divided by the time of the collision. Since the impulse experienced by mass A is 6 kg m/s and the time of the collision is 0.06 seconds, the net force on mass A is equal to 6 kg m/s / 0.06 s = 100 N.

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An elliptical orbit is an oval-shaped path that a satellite takes around its primary body, such as the Earth. The speed of a satellite in its orbit varies depending on its distance from the primary body, which changes throughout the elliptical orbit.

According to Kepler's laws of planetary motion, a satellite moves fastest when it is closest to the primary body, and slowest when it is farthest away. Therefore, an Earth satellite has the greatest speed at the point in its orbit called perigee, which is the point where it is closest to the Earth. At perigee, the satellite experiences the strongest gravitational pull from the Earth, which accelerates it and increases its speed.

Conversely, the satellite has the least speed at the point called apogee, which is the farthest point in its orbit from the Earth. At apogee, the satellite experiences the weakest gravitational pull from the Earth, which decelerates it and decreases its speed.

It's important to note that the speed of a satellite in orbit is also affected by other factors, such as the presence of other gravitational bodies and atmospheric drag. However, the varying distance from the primary body is the primary factor affecting the speed of a satellite in an elliptical orbit around the Earth.

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Answer:

Kelvin

Explanation:

Kelvin is the universal and scientific unit for temperature as Celsius and Fahrenheit temperatures we use in everyday situations

Answer:

Just multiply the speed by time to get your distance of 60.06, and then divide it by two and you will get your final answer of 30.03

Explanation:

Hope this helps.

Answer:

The time taken by the car to come at rest is 2.5 seconds

Explanation:

The parameters given are;

Speed of bus = 72 km/hr

Distance at which bus stopped = 25 m

Given that the speed and the distance covered before stopping are j=known, we have;

v² = u² - 2·a·s

Where:

v = Final velocity = 0

a = Deceleration of the bus

s = Distance covered while decelerating = 23 m

u = Initial  velocity = 72 km/hr = 20 m/s

Which gives;

0² = (20 m/s)² - 2×a×25 m

20² = 2×a×25 m

a = 20²/(2×25) = 8 m/s²

The time, t, it takes for the car to come at rest is given by the relation;

v = u - at

0 = 20 - 8×t

t = 20/8 = 2.5 s.

One statement that is not true is that UV radiation is a type of electromagnetic radiation. It is also a type of ionizing radiation. UV radiation is actually a form of non-ionizing radiation.

UV radiation, or ultraviolet radiation, is a type of electromagnetic radiation that falls between visible light and X-rays on the electromagnetic spectrum. It is often categorized into three types: UVA, UVB, and UVC. Unlike ionizing radiation, such as X-rays and gamma rays, which have enough energy to remove tightly bound electrons from atoms or molecules, UV radiation lacks the necessary energy to ionize atoms or molecules. Instead, it primarily interacts with the outermost electrons of atoms or molecules, leading to chemical reactions and causing biological effects.

UV radiation is commonly associated with sunlight and has various effects on living organisms and materials. It can cause sunburn, premature aging of the skin, and an increased risk of skin cancer. Exposure to excessive UV radiation can also damage the eyes and impair the immune system. It is important to protect oneself from excessive UV exposure by wearing sunscreen, protective clothing, and sunglasses.

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Answer: 114.543 i think

Answer:

A mass driver or electro magnetic catapult is a proposed method of non-rocket space launch which would use a linear motor to accelerate and catapult payloads up to high speeds. All existing and contemplated mass drivers use coils of wire energized by electricity to make electromagnets.

Explanation:

may i be marked brainliest?

The resulting equation of motion for the system is given by m × x''(t) + k × x(t) = f(t), which is 2 × x''(t) + 18 * x(t) = 2 * sin(2t).

What is  equation of motion?

The equations of motion are a set of mathematical relationships that describe the motion of objects under the influence of forces. There are different sets of equations of motion, depending on the specific scenario and the type of motion being considered (linear motion, projectile motion, circular motion, etc.). The equations of motion for linear motion, also known as the equations of uniformly accelerated motion.

To find the equation of motion for the system, we start with Newton's second law of motion, which states that the sum of forces acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the object is the 2-kg mass attached to the spring.

The force exerted by the spring is proportional to the displacement of the mass from its equilibrium position, and it can be expressed as F_spring = -k× x(t), where k is the spring constant and x(t) is the displacement of the mass at time t.

In addition to the force exerted by the spring, there is an external force f(t) = 2 ×sin(2t) acting on the mass.

Applying Newton's second law, we have the equation of motion: m ×x''(t) + k ×x(t) = f(t).

Substituting the given values, m = 2 kg and k = 18 N/m, we obtain 2 ×x''(t) + 18 × x(t) = 2 ×sin(2t).

Therefore, the resulting equation of motion for the system is 2 × x''(t) + 18 × x(t) = 2 × sin(2t).

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