Charisse was riding north then she turned 90° to the left after turning in what direction was charisse riding Explain your answer

The value of equivalent expression is,

3 = 87 ÷ h

We have to given that;

Equation is,

⇒ 3/5 = 17 2/5 ÷ h

Now, We can simplify as;

⇒ 3/5 = 17 2/5 ÷ h

⇒ 3/5 = 87/5 ÷ h

⇒ h = 87/5 × 5/3

⇒ h = 29

For Option A;

3 = 87 ÷ h

h = 87 / 3

h = 29

For B;

3 × 9 = (87 ÷ h) ÷ 9

27 × 9 = 87 ÷ h

h = 87 / 27 x 9

h = 0.35

C) 3 - 9 = 87 ÷ h

h = 87 / - 3

h = - 29

Thus, The value of equivalent expression is,

3 = 87 ÷ h

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Answer:

I don't see any answer options, but the total cost should be:

c = $5.00 + $1.25g

Step-by-step explanation:

Assuming that the cost is for one person playing g games, and that person needs to rent 1 pair of shoes, the cost should be:

c = $5.00 + $1.25g

Answer:

18

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

Answer: I'd say reflection

Answer:

It is a reflection

Step-by-step explanation:

In Geometry, a reflection is known as a flip. A reflection is a mirror image of the shape. An image will reflect through a line, known as the line of reflection. A figure is said to reflect the other figure, and then every point in a figure is equidistant from each corresponding point in another figure.

\(_5C_3\cdot _4C_2=\dfrac{5!}{3!2!}\cdot\dfrac{4!}{2!2!}=\dfrac{4\cdot5}{2}\cdot\dfrac{3\cdot4}{2}=2\cdot5\cdot3\cdot2=60\)

Answer:

\(\large \boxed{\mathrm{A. \ 60}}\)

Step-by-step explanation:

\(\displaystyle nC_r=\frac{n!}{r!(n-r)!}\)

\(5C_3 \times 4C_2\)

\(\displaystyle \frac{5!}{3!(5-3)!} \times \frac{4!}{2!(4-2)!}=10 \times 6 = 60\)

Okay so to get this answer u have too Take 17 and subtract 2 This equals 15, So the answer would be 15, This is how I get my answers at least

Step-by-step explanation:

The above pictures shows working.

9 hours long after the second runner started will the second runner overtake the first runner.

What does it mean to do speed?

Runner I = 6 mph

Runner II = 7 mph

Difference in time= 90 minutes

Train A will have covered 9 miles before Runner II starts

catch up distance= 9 miles

catch up speed = 7-6 mph

catch up speed = 1 mph

Catchup time = catchup distance/catch up speed

catch up time= 9/1

catch up time= 9 hours

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To verify if each given function is a solution of the differential equation, we need to substitute the function into the differential equation and check if the equation holds true.

For the differential equation y" - 4y = 0:

a) Substitute y(t) = e^(2t):

y" = (e^(2t))'' = 4e^(2t)

4y = 4e^(2t)

The equation y" - 4y = 0 holds true.

b) Substitute y(t) = cosh(t):

y" = (cosh(t))'' = cosh(t)

4y = 4cosh(t)

The equation y" - 4y = 0 holds true.

For the differential equation y" + 2y - 3y = 0:

a) Substitute y(t) = e^(-3t):

y" = (-3e^(-3t))

2y = 2e^(-3t)

The equation y" + 2y - 3y = 0 holds true.

b) Substitute y(t) = e^(t):

y" = e^(t)

2y = 2e^(t)

The equation y" + 2y - 3y = 0 holds true.

For the differential equation 12y" + 5ty' + 4y = 0, t > 0:

a) Substitute y(t) = t^2:

y" = 2

y' = 0

5ty' = 0

12y" + 5ty' + 4y = 12(2) + 0 + 4(t^2) = 24 + 4t^2

The equation 12y" + 5ty' + 4y = 0 holds true.

b) Substitute y(t) = t^2:

y" = 2

y' = 0

5ty' = 0

12y" + 5ty' + 4y = 12(2) + 0 + 4(t^2) = 24 + 4t^2

The equation 12y" + 5ty' + 4y = 0 holds true.

For the differential equation y" + y = sec(t):

a) Substitute y(t) = sec(t):

y" = sec(t)tan(t)

y = sec(t)

The equation y" + y = sec(t) holds true.

b) Substitute y(t) = sec(t):

y" = sec(t)tan(t)

y = sec(t)

The equation y" + y = sec(t) holds true.

Therefore, each given function is a solution to its respective differential equation.

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Answer:

x = 5

Step-by-step explanation:

Add the equations

x + y = 3

x - y = 7

––––––––

2x = 10

Divide both sides by2

x = 5

Note: for the equations in the question,

none of the given answers are correct.

Answer:

Step-by-step explanation:

Assuming the question is x^2 + 6x = 27x, subtract 6x from both sides.       x^2 = 21x. Then, divide both sides by x and you get x= 0, 21

(a), The equation of the line that is perpendicular to this line and passes through the point (7, 6) is y = 7/8x - 1/8.

(b), The equation of the line that is parallel to this line and passes through the point (7, 6) is y = -8/7x - 1/8

An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.

The general form of the equation of the line:-

y = mx + c

m = slope

c = y-intercept

Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given that the equation is -8x - 7y = 1.

a) For perpendicular lines the slope will be inverse and opposite of the given equation.

y = mx + c

-8x - 7y = 1.

y = -8/7x - 1/7

The equation can be written as,

y = -8/7x - 1/7

6 = ( 7/8 ) x ( 7 ) + c

c = ( -1 / 8 )

The equation can be written as,

y = 7/8x  - 1/8.

b) For the parallel lines the slope will remain the same,

y = -8/7x - 1/7

y = -8/7x + c

6 = (-8/7 x 7 ) + c

c = 6 + 8

c = 14

The equation can be written as,

y = (-8/7)x + 14

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Answer:

mode: none

median: 4

mean: 4.2

Step-by-step explanation:

when dealing with mean, median, mode the first thing you should do is arrange the numbers in order from least to greatest. Once you have done so the easiest thing to do first is see which number is in the very middle, this is your median. Mode is the number that appears the most. Mean is another word for average. To find the mean, add up all the numbers then divide the sum of all the numbers by how many numbers are listed. In this case, 2+3+4+5+7=21.

21 divided by 5 (how many numbers there are) = 4.2

Based on the graph of the function (F(x) = log6x), the following facts are true:

A graph is a type of chart that is used to graphically represent data on both the horizontal and vertical lines of a Cartesian coordinate i.e x-axis and y-axis.

By critically observing the graph of the function (F(x) = log6x) attached in the image below, we can infer and logically deduce that its domain and range include all real numbers that are greater than 0 (x > 0).

This ultimately implies that, the following facts are true:

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Complete Question:

Which facts are true for the graph of the function below? Check all that apply. F(x) = log6 x

A. It is increasing.

B. The range is y > 0.

C. The x-intercept is (1, 0).

D. It is decreasing.

E. The y-intercept is (0, 6).

F. The domain is x > 6.

Answer:

- 10√2 - 5√5

Step-by-step explanation:

- 2√50

√50 = √( 2 x 5 x 5 ) = 5√2

- 2√50

= - 2 x 5√2

= - 10√2

- √125

= - √( 5 x 5 x 5 )

= - 5√5

- 2√50 - √125

= - 10√2 - 5√5

Answer:

Step-by-step explanation:

50: 2 * 5 * 5

125:5 * 5 * 5

sqrt(50) = 5*sqrt(2)  For every pair of primes, 1 of them is put outside the sqrt sign and one is discarded.

sqrt(125) = 5*sqrt(5) Same rule.

-2 sqrt(50) - sqrt(125)

-2*5*sqrt(2) - 5sqrt(5)

Answer: -10*sqrt(2) - 5sqrt(5)

You could write the answer as

Answer: -5(2sqrt(2) + sqrt(5) )

Comment: I don't know which answer you should use. I think the second one is more complete, but your marker may not agree.

Answer:

unbihbhi

Step-by-step explanation:

kbhgyiu

SOLUTION

We want to find which of the following values make the inequality

x ≤ 16.3 to be true.

This inequality means that x is equal to 16.3 or less than 16.3. So the numbers that fall under this are numbers smaller than 16.3 and also 16.3.

The numbers that fall under here are 8, 1/4, -3 and 16.3

Hence the answer b, c, e and f

Answer:

a

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

Step-by-step explanation:

45 Grey Marbles and 180 White Marbles

Question 1: The item not included in the cost of merchandise inventory is "Purchase discounts."

2: The total cost of the merchandise is $3,332.00.

5: The company's gross margin and operating expenses, are $211,000 and $191,720.

Merchandise inventory expenses normally consist of the price paid for the inventory, deductions from the purchase price resulting from purchase returns and allowances, and freight expenses paid by the purchaser.

Although purchase discounts reduce the cost of merchandise inventory, they are not considered part of it. Instead, they are treated as a distinct discount in the accounting records.

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Answer:

Sam has is 7/5 times the reciprocal of the total number of stamps in the new set.

Step-by-step explanation:

Let's start by finding out what fraction of the new set of stamps Sam has after adding 4/5 of the set to his collection.

Let the total number of stamps in the new set be x.

If Sam's collection initially had 3/5 of the new set, then the number of stamps in his collection before adding the new set would be:

3/5 * x = the number of stamps in Sam's collection before adding the new set

After adding 4/5 of the new set to his collection, Sam has:

3/5 * x + 4/5 * x = 7/5 * x

So Sam has 7/5 of the new set of stamps.

However, the problem asks for the fraction of the new set that Sam has, not the fraction of the total number of stamps in the new set.

To find the fraction of the new set that Sam has, we need to divide the number of stamps he has by the total number of stamps in the new set:

(7/5 * x) / x

Simplifying the expression:

(7/5) / 1

We can express this fraction in terms of x by multiplying both the numerator and denominator by 1/x:

(7/5) * (1/x)

Therefore, the fraction of the new set of stamps that Sam has is 7/5 times the reciprocal of the total number of stamps in the new set.

Answer:

4/4

Step-by-step explanation:

y=4 x+1

   4        hope that helps!!

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The equation of the line with the given slope and the y-intercept.

slope = 1/5; y-intercept = -5 is y = 1 / 5 x - 5

The equation of a line can be described as follows:

y = mx + b

where

Therefore,

slope of the line = 1 / 5

y-intercept = - 5

Hence, the equation of the line can be represented as follows:

y = 1 / 5 x - 5

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The circumference is 160 feet for a length of 40 feet. The perimeter is 200 feet for a length of 50 feet. The circumference is 240 feet for a length of 60 feet.

A rectangular region with a 1200 square foot area will have a different perimeter depending on how long it is. The perimeter will be 160 feet if the area is 40 feet long. The length of 40 feet is multiplied by four to get a final measurement of 160 feet. In a similar manner, if the area is 50 feet long, the perimeter will be 200 feet.

The length of 50 feet is multiplied by four to get a final result of 200 feet. Finally, the perimeter will be 240 feet if the area is 60 feet long. The length of 60 feet is multiplied by four to get a final measurement of 240 feet. A rectangular region with an area of 1200 square feet will therefore have a different perimeter depending on its length, with a length of 40 feet resulting in a perimeter of 160 feet, a length of 50 feet resulting in a perimeter of 200 feet, and a length of 60 feet resulting in a perimeter of 240 feet.

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Answer: About 99.74% of births would be expected to occur within 24 days of the mean pregnancy length.

Step-by-step explanation:

Complete question is attached below.

Given: The lengths of pregnancy terms for a particular species of mammal are nearly normally distributed about a mean pregnancy length with a standard deviation of 8 days.

i.e. \(\sigma= 8\)

let X denotes the random variable that represents the lengths of pregnancy.

The probability of births would be expected to occur within 24 days of the mean pregnancy​ length:

\(P(\mu-24<X<\mu+24)=P(\dfrac{\mu-24-\mu}{8}<\dfrac{X-\mu}{\sigma}<\dfrac{\mu+24-\mu}{8})\\\\=P(\dfrac{-24}{8}<Z<\dfrac{24}{8})\ \ \ [\because Z=\dfrac{X-\mu}{\sigma}]\\\\=P(-3<Z<3)\\\\=P(Z<3)-P(Z<-3)\\\\=P(Z<3)-(1-P(Z<3))\\\\=2P(Z<3)-1\)

\(= 2(0.9987)-1\ \ \ [\text{ By z-table}]\\\\=0.9974\)

=99.74%

Hence, about 99.74% of births would be expected to occur within 24 days of the mean pregnancy length.

To determine whether there is enough evidence to reject the null hypothesis, we need to compare the computed test statistic to the critical value.

In this case, the computed test statistic is 2.50 and the critical value is 2.33. If the computed test statistic falls in the rejection region beyond the critical value, we can reject the null hypothesis. Conversely, if the computed test statistic falls within the non-rejection region, we fail to reject the null hypothesis.In this scenario, since the computed test statistic (2.50) is greater than the critical value (2.33), it falls in the rejection region. This means that the observed data is unlikely to occur if the null hypothesis were true.

Therefore, based on the given information, there is enough evidence for the emergency room nurse to reject the null hypothesis. This suggests that there is sufficient evidence to support the claim that the average number of cases of upper respiratory infections per day at the hospital is over 21 cases.

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There is enough evidence to reject the null hypothesis in this case because the computed test statistic (2.50) is higher than the critical value (2.33). This suggests the average number of daily respiratory infections exceeds 21, providing substantial evidence against the null hypothesis.

Yes, there is enough evidence for the emergency room nurse to reject the null hypothesis. The null hypothesis is typically a claim of no difference or no effect. In this case, the null hypothesis would be an average of 21 upper respiratory infections per day. The test statistic computed (2.50) exceeds the critical value (2.33). This suggests that the average daily cases indeed exceed 21, hence providing enough evidence to reject the null hypothesis.

It's crucial to understand that when the test statistic is larger than the critical value, we reject the null hypothesis because the observed sample is inconsistent with the null hypothesis. The statistical test indicated a significant difference, upheld by the test statistic value of 2.50. The significance level (alpha) of 0.05 is a commonly used threshold for significance in scientific studies. In this context, the finding suggests that the increase in respiratory infection cases is statistically significant, and the null hypothesis can be rejected.

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