Change to a mixed number. 13/3

Answer:q=0,\:q=-16

Step-by-step explanation:

The output value of (f∘g)(x) is:  \((f \circ g)(x) = \frac{4x^2-29x+60}{x +3}\)

The domain of (f∘g)(x) is (-∞, -3) U (-3, ∞).

In this scenario, we would determine the corresponding composite function of f(x) and g(x) under the given mathematical operations (multiplication) in simplified form as follows;

\(f(x) = \frac{x-6}{x +3}\)

g(x) = 4x - 15

Next, we would write the numerators and denominators in factored form as follows;

(x - 6)(4x - 15)

4x² - 15x - 24x + 60

4x² - 29x + 60

Now, we can derive the corresponding composite function of f(x) and g(x);

\((f \circ g)(x) = \frac{4x^2-29x+60}{x +3}\)

For the restrictions on the domain, we would have to equate the denominator of the rational function to zero and then evaluate as follows;

x + 3 ≠ 0

x ≠ -3

Domain = (-∞, -3) U (-3, ∞).

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The required first five terms in the sequence are -13, -7, -1, 5, and 11.

An arithmetic sequence is defined as an arrangement of numbers that is in a particular order.

Given the sequence aₙ = a₍ₙ₋₁₎ + 6 where a₁ = -13,

To determine the next 4 terms of the sequence

The second term a₂ = a₍₂₋₁₎ + 6 = a₁ - 6 = -13 + 6 = -7

The third term a₃ = a₍₃₋₁₎ + 6 = a₂+ 6 = -7+ 6 = -1

The fourth term a₄ = a₍₄₋₁₎ + 6 = a₃+ 6 = -1 + 6 = 5

The fifth term a₅ = a₍₅₋₁₎ + 6 = a₄ + 6 = 5 + 6 = 11

Therefore, the required first five terms in the sequence are -13, -7, -1, 5, and 11.

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To find the probability that Naomi selects both white balls, we need to consider the total number of possible outcomes and the number of favorable outcomes.

Total number of outcomes:

Naomi selects 2 balls without replacement, so the total number of outcomes is the number of ways she can choose 2 balls out of the total number of balls in the bag. This can be calculated using combinations:

Total outcomes = C(20, 2) = (20!)/(2!(20-2)!) = (20 * 19)/(2 * 1) = 190

Number of favorable outcomes:

Naomi needs to select 2 white balls. There are 2 white balls in the bag, so the number of favorable outcomes is the number of ways she can choose 2 white balls out of the 2 white balls in the bag:

Favorable outcomes = C(2, 2) = 1

Probability = Favorable outcomes / Total outcomes = 1/190

Therefore, the correct answer is (G) 1/190.

Answer:

C

Step-by-step explanation:

Answer:

x = 4

Step-by-step explanation:

if a line is parallel to a side of a triangle and it intersects the other two sides then id divides those sides proportionally.

DE is such a line , then

\(\frac{BD}{AD}\) = \(\frac{BE}{EC}\)  ( substitute values )

\(\frac{x+2}{x}\) = \(\frac{3}{2}\) ( cross- multiply )

3x = 2(x + 2)

3x = 2x + 4 ( subtract 2x from both sides )

x = 4

Answer:

Step-by-step explanation:

xhxj

a. The answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. The answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

a. To represent 20 longs in base seven, we need to find the fewest number of multibase blocks required.

In base seven, we have the following conversions:

1 long = 1 unit

1 flat = 10 units

1 block = 10 flats

To represent 20 longs, we can use 2 flats (each flat representing 10 units) and 0 units since there are no remaining units.

So, the fewest number of multibase blocks required would be 2 flats.

Therefore, the answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. To represent 10 longs in base three, we need to find the fewest number of multibase blocks required.

In base three, we have the following conversions:

1 long = 1 unit

1 flat = 3 units

1 block = 3 flats

To represent 10 longs, we can use 3 flats (each flat representing 3 units) and 1 unit since there is one remaining unit.

So, the fewest number of multibase blocks required would be 3 flats and 1 unit.

Therefore, the answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

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The contrapositive of the statement is:

Jose isn't going for a bike ride if and only if he doesn't woke up early.

What is contrapositive?

A conditional statement's hypothesis and conclusion are switched, and both are then rejected, in a contrapositive. For instance, "if not B then not A" is the opposite of "if A then B." A conditional statement's contrapositive combines the inverse and converse.

The given statement is,

Jose wakes up early if and only if he is going for a bike ride.

We divide the statement into two parts.

1. Jose wakes up early.

2. He is going for a bike ride.

The negative of the statements are,

Jose doesn't wakes up early and he isn't going for a bike ride.

Therefore, the contrapositive of the statement is,

Jose isn't going for a bike ride if and only if he doesn't woke up early.

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Answer:

tiookvgvc. jbjvth kivtcth jjvf h. bkbgv

Answer:

The IQR of the given distribution is

Step-by-step explanation:

The given distribution has the five-number

28, 34, 43, 59, 62

Divide these numbers in two equal parts.

(28, 34), 43,( 59, 62)

Now divide each parenthesis in two equal parts.

(28), (34), 43,( 59), (62)

It means first quartile is the average of 28 and 34. Third quartile is the average of 59 and 62.

The interquartile range (IQR) of this distribution is

Therefore the IQR of the given distribution is 29.5.

The value of y when x = 15 is 9

If the  variable y varies directly as x, this is expressed as;

y = kx

where k is the constant of proportionality

If x = 20 when y = 12, then;

k = y/x

k = 12/20

If x = 15, then the value of y is;

y = 12/20*15

y = 9

Hence the value of y when x = 15 is 9

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Answer:

a) 12

b)5

Step-by-step explanation:

Answer:

(a) 12

(b) 5

Step-by-step explanation:

(a) 3/5 = (3×4)/(5×4) = 12/20

(b) (5×5)/(5×6) = 25/30

While an absolute value may be any number, the output from an absolute value expression is always greater than or equal to zero

The absolute value | x | of a real number x is defined as the non-negative value of x without regard to its sign. For example, the absolute value of 3 is 3, and the absolute value of −3 is also 3. The absolute value of a number may be thought of as its distance from zero along real number line.

The absolute value of any number is seen to be always greater than or equal to zero. Both a number and its opposite are the same distance from zero on the number line. Since they have the same distance from zero, they have the same absolute value.

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Answer:

75

Step-by-step explanation:

the line in the middle of the box tells you the median

Answer:

d) 1/12

Step-by-step explanation:

Answer:

f(-4) = -36

Step-by-step explanation:

Step-by-step explanation:

A function assigns the value of each element of one set to the other specific element of another set. The value of the function when the value of x is -4 is 92.

What is a Function?

A function assigns the value of each element of one set to the other specific element of another set.

Given that F(x)=3x²-10x+4, therefore, the value of the function can be calculated by substituting the value of x as -4.

Therefore, the value of the function when the value of x is -4  can be calculated as shown below,

F(x) = 3x² - 10x + 4

F(-4) = 3(-4)² - 10(-4) + 4

= 3(16)  + 40 + 4

= 48 + 40 + 4

= 92

Hence, the value of the function when the value of x is -4 is 92.

Answer:

d = 0

Step-by-step explanation:

To find the solution to the given equation, we must solve for d in the equation.

7.5d = 2.5d

Subtract 2.5d from both sides.

5d = 0

Divide both sides by 5.

d = 0

So the solution to the equation would be d = 0.

I hope this helps. Happy studying.

Answer:

  (-∞, -3] or [-3, ∞)

Step-by-step explanation:

You want the largest domain interval(s) on which the function shown in the graph could be one-to-one.

A one-to-one function must pass the horizontal line test. That is, no horizontal line can intersect its graph in more than one place.

For that to be true of the given function, the interval on which it is defined cannot include values on both sides of x=-3, where the graph has a minimum. That is, the domain must be either x ≤ -3, or x ≥ -3, (or some subset of either of these).

The largest intervals on which the function has an inverse are ...

  (-∞, -3]  or  [-3, ∞)

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To make the given function one-to-one and have an inverse, we can restrict its domain to (-∞, a) or (a, ∞), where 'a' is the x-coordinate of the highest or lowest point on the graph.

To make the given function one-to-one and have an inverse, we need to restrict its domain. The largest domains, in interval notation, that can be used are: (-∞, a) or (a, ∞) where 'a' is the x-coordinate of the highest or the lowest point on the graph, depending on the function type.

If the graph has a highest point, the domain is restricted to (a, ∞), where 'a' is the x-coordinate of the highest point. If the graph has a lowest point, the domain is restricted to (-∞, a), where 'a' is the x-coordinate of the lowest point.

For example, if the graph has a highest point at (3, 5), the domain would be restricted to (3, ∞) to make the function one-to-one and have an inverse.

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well which one is it there's 2 questions?

If triangle RST is an acute triangle, then m∠S must be less than 90°.

What is Acute Traingle?

A form of triangle called an acute triangle has acute angles at each of its three internal angles. Triangles with sharp angles are also known as acute triangles. Acute triangles have different side lengths, but their interior angles are always less than 90°.

In light of the foregoing, if triangle RST is an acute triangle,

then,

∠R , ∠S and ∠T, all are less than 90.

A triangle that is equilateral and has all three interior angles equal and less than 90 degrees, or angles that are all 60 degrees, is an example of an acute triangle.

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Answer:

Step-by-step explanation:

2y = -x +9

3x - 6y = -15

The solution is the value of x and y that will make the two equations true in the same time.

3x-6y = -15;  divide both sides by 3

x-2y = -5; substitute 2y for -x+9 because the first equation tell us they are equal

x-(-x+9) = -5; open parenthesis

x+x-9 = -5 ; add 9 to both sides  and combine like terms

2x = -5 +9; 2x = 4; divide both sides by 2

x= 2

Substitute x for 2

2y = -x+9 ; 2y = -2 +9 ; 2y = 7; y = 7/2 = 3.5

Solution is (2, 3.5)

Answer:

(2, 7/2)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define Systems

2y = -x + 9

3x - 6y = -15

Step 2: Rewrite Systems

2y = -x + 9

Step 3: Redefine Systems

y = -x/2 + 9/2

3x - 6y = -15

Step 4: Solve for x

Step 5: Solve for y

Step-by-step explanation:

If the x is squared, the parabola is vertical (opens up or down). If the y is squared, it is horizontal (opens left or right). If a is positive, the parabola opens up or to the right. If it is negative, it opens down or to the left

Answer:

If the x is squared, the parabola is vertical (opens up or down). If the y is squared, it is horizontal (opens left or right). If a is positive, the parabola opens up or to the right. If it is negative, it opens down or to the left.

Hope you got it

If you have questions just ask me

Answer:

3 large frames

Step-by-step explanation:

Let the large frames she bought be x in number and small frames be y in number.

ATQ, 17x+6y=141 and x+y=18. Solving it, we will get x=3 and y=15. So she bought 3 large frames

The value of the angle U from the calculation is 88 degrees.

The sine rule can be applied in a variety of situations, such as determining a triangle's unknown side lengths or angles. The sine rule can be used to locate the missing side or angle if you know the lengths of two sides and the measure of an angle (not necessarily the included angle).

By the use of the sine rule;

u/Sin U = w/Sin W

Thus;

76/Sin U = 71/Sin 69

Sin U = 76Sin 69/71

U = Sin-1 (76Sin 69/71)

U = 88 degrees

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The degree 3 polynomial is "x³-2x²-64x+128".

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The value of df, when x = π/4 and dx = 1/24, is (-5π - 5√2)/(96√2).

To find the derivative of the function f(x) = -5cos(x) + xtan(x), we'll use the sum and product rules of differentiation. Let's start by finding df/dx.

Apply the product rule:

Let u(x) = -5cos(x) and v(x) = xtan(x).

Then, the product rule states that (uv)' = u'v + uv'.

Derivative of u(x):

u'(x) = d/dx[-5cos(x)] = -5 * d/dx[cos(x)] = 5sin(x) [Using the chain rule]

Derivative of v(x):

v'(x) = d/dx[xtan(x)] = x * d/dx[tan(x)] + tan(x) * d/dx[x] [Using the product rule]

= x * sec^2(x) + tan(x) [Using the derivative of tan(x) = sec^2(x)]

Applying the product rule:

(uv)' = (5sin(x))(xtan(x)) + (-5cos(x))(x * sec^2(x) + tan(x))

= 5xsin(x)tan(x) - 5xcos(x)sec^2(x) - 5cos(x)tan(x)

Simplify the expression:

df/dx = 5xsin(x)tan(x) - 5xcos(x)sec^2(x) - 5cos(x)tan(x)

Now, we need to evaluate df/dx at x = π/4 and dx = 1/24.

Substitute x = π/4 into the derivative expression:

df/dx = 5(π/4)sin(π/4)tan(π/4) - 5(π/4)cos(π/4)sec^2(π/4) - 5cos(π/4)tan(π/4)

Simplify the trigonometric values:

sin(π/4) = cos(π/4) = 1/√2

tan(π/4) = 1

sec(π/4) = √2

Substituting these values:

df/dx = 5(π/4)(1/√2)(1)(1) - 5(π/4)(1/√2)(√2)^2 - 5(1/√2)(1)

Simplifying further:

df/dx = 5(π/4)(1/√2) - 5(π/4)(1/√2)(2) - 5(1/√2)

= (5π/4√2) - (10π/4√2) - (5/√2)

= (5π - 10π - 5√2)/(4√2)

= (-5π - 5√2)/(4√2)

= (-5π - 5√2)/(4√2)

Now, to evaluate df/dx when dx = 1/24, we'll multiply the derivative by the given value:

df = (-5π - 5√2)/(4√2) * (1/24)

= (-5π - 5√2)/(96√2)

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Step-by-step explanation:

We have the roots 1/2 and 4/3 and we need to write a quadratic equation of the form a x^{2} +bx+cax

2

+bx+c using those roots. Since we know that 1/2 and 4/3 are roots of our quadratic, we can equate each root to xx and factor backwards:

x= \frac{1}{2}x=

2

1

and x= \frac{4}{3}x=

3

4

2x=12x=1 and 3x=43x=4

2x-1=02x−1=0 and 3x-4=03x−4=0

Now we can multiply the left sides of our equations to get our quadratic:

(2x-1)(3x-4)=6 x^{2} -8x-3x+4=6 x^{2} -11x+4(2x−1)(3x−4)=6x

2

−8x−3x+4=6x

2

−11x+4

W can conclude that the quadratic equation with roots 1/2 and 4/3 is 6x^2-11x+46x

2

−11x+4

Answer:

n^2 +24n +144

Step-by-step explanation:

(-12-n)^2

(-12-n)(-12-n)

144+12n+12n+n^2

n^2 +24n +144

i think... :)

The essays that she can review in 1 hour would be; 2 2/3.

A fraction represents a part of a number or any number of equal parts.

We are given that English teacher reviewed 2 /3 of an essay in 1/ 4 of an hour.

Thus, Fraction of the essay reviewed = 2/3

Amount of time used = 1/4

Therefore, the fraction of essay for an hour can be calculated as;

= Fraction of the essay reviewed / Amount of time used

= 2/3 ÷ 1/4

= 2/3 × 4

= 8/3

= 2 2/3

Hence, She will review 2 2/3 essay.

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