Answers
The carbon dioxide readily absorbs radiation with an energy of 4.67×10⁻²⁰J and wavelength is 7.04 x 10¹³, then the frequency is 4.26 x 10⁻¹¹ m.
What is frequency?Frequency can be defined as the number of occurrences of a repeating event per unit of time. It is also known as temporal frequency to emphasizes the contract to spatial frequency and can be called as ordinary frequency to emphasize the contract to angular frequency. It is denoted by f.
f = hc / ∧
f = 6.626 x 10⁻³⁴ x 3.0 x 10³ / 4.67 x 10⁻²⁰
f = 4.26 x 10⁻¹¹ m
Thus, carbon dioxide readily absorbs radiation with an energy of 4.67×10⁻²⁰J and wavelength is 7.04 x 10¹³, then the frequency is 4.26 x 10⁻¹¹ m.
To learn more about frequency, refer to the link below:
https://brainly.com/question/14316711
#SPJ1
Related Questions
Brittleness
Hardness
Elasticity
Conductivity
Biodegradability
1. Ability to break easily.
2. Ability to decomposed by microorganism.
3. Ability to let the heat and electricity to pass through.
4. Ability to be stretched and return to its original shape.
5. Ability to resist pressure that may cause deformation.
Answers
Answer:
BrittlenessBiodegradableConductivityElasticityHardnessCan I get BRAINLIEST.... Please
lndicate the ionisation of the following acids,tetraoxosulphate (vi)acid,trioxonitrat
e(v)acid,ethanoic acid.
Answers
The ionization of the following acids can be represented as:
Tetraoxosulphate (VI) Acid (\(H_{2}SO_{4}\)) ionizes as H+ and SO4^2- ions.
Trioxonitrate (V) Acid (\(HNO_{3}\)) ionizes as H+ and \(NO_{3-}\) ions.
Ethanoic Acid (\(CH_{3}COOH\)) ionizes as H+ and \(CH_{3}COO^{-}\) ions.
Tetraoxosulphate (VI) Acid, also known as sulfuric acid (\(H_{2}SO_{4}\)), ionizes as follows:
\(H_{2}SO_{4}\) → \(H+\) + \(SO_{4}^{2-}\)
In this reaction, sulfuric acid donates two hydrogen ions (H+) to the solution, forming sulfate ions (\(SO_{4}^{2-}\)).
Trioxonitrate (V) Acid, commonly known as nitric acid (\(HNO_{3}\)), ionizes as follows:
\(HNO_{3}\) → \(H+_{}\) + \(NO_{3-}\)
Nitric acid dissociates to release one hydrogen ion (\(H+\)) and a nitrate ion (\(NO_{3-}\)).
Ethanoic Acid, also known as acetic acid (\(CH_{3}COOH\)), ionizes as follows:
\(CH_{3}COOH\) → H+ + \(CH_{3}COO^{-}\)
Acetic acid donates a hydrogen ion (H+) to the solution, forming an acetate ion (\(CH_{3}COO^{-}\)).
In all cases, the acids dissociate in water, producing hydrogen ions (H+) as positively charged ions and their corresponding anions. The hydrogen ions are responsible for the acidic properties of these substances, while the anions contribute to the overall charge balance in the solution. The ionization of acids allows them to conduct electricity in aqueous solutions and react with other substances.
The question was incomplete. find the full content below:
Indicate the ionization of the following acids,
Tetraoxosulphate (VI) Acid
Trioxonitrate (V) Acid
Ethanoic Acid.
Know more about ionization here:
https://brainly.com/question/30831422
#SPJ8
PLZZZZZZZZZZZZ HELPPPPPPPPP BRAINLIEST FOR WHO GETS IT RIGHTTTTTTWhat is the mass of reactants in the following equation?
N2 + 3H2 ----> 2NH3
Question 3 options:
34.05 amu
31.03 amu
30.02 amu
15.01 amu
Answers
Answer: 34.05
Explanation:
2N and 6H = abt 34
Describe what is meant by synthesis. How do the functions of analysis, synthesis, and evaluation relate to each other
Answers
Answer:
New element formed by combination of reactants.
Explanation:
Synthesis refers to the production of a new product from the combination of two or more reactants. Analysis, synthesis, and evaluation are related to each other because in synthesis a new product is formed while in analysis, we examine the structure of the new product in detailed and in evaluation, we assess the quantity of a new product. So analysis and evaluation gives a lot of information about the product which is formed in synthesis.
What is the molarity? (Question in the photo lol sorry)
Answers
The question requires us to calculate the molarity of a Ba(OH)2 solution which pH is 10.20.
To solve this problem, we'll need to go through the following steps:
1) calculate the concentration of H+ ions ([H+]), using the pH of solution provided;
2) calculate the concentration of OH- ions ([OH-]), considering [H+] and the definition of Kw;
3) consider the dissociation of Ba(OH)2 and use [OH-] to calculate the concentration of the solution.
Next, we'll go through these steps:
1) The definition o pH is given as:
\(pH=-\log _{10}\lbrack H^+\rbrack\)where [H+] corresponds to the concentration of H+ ions, in mol/L.
We can use this definition to calculate [H+] from pH, as it follows:
\(\lbrack H^+\rbrack=10^{-pH}\)Applying the value of pH provided to the equation above, we'll have:
\(\lbrack H^+\rbrack=10^{-10.20}\to\lbrack H^+\rbrack=6.309\times10^{-11}mol/L\)Thus, the concentration of H+ ions in the solution is 6.309 x 10^-11 M.
2) Now, we can use the following definition of the ion-product constant of liquid water:
\(K_w=\lbrack H^+\rbrack\times\lbrack OH^-\rbrack\)We can rearrange the equation and calculate the concentration of OH- ions, and knowing that Kw value corresponds to 1.01 x 10^-14, we can calculate [OH-]:
\(\begin{gathered} \lbrack OH^-\rbrack=\frac{K_w}{\lbrack H^+\rbrack} \\ \lbrack OH^-\rbrack=\frac{1.01\times10^{-14}}{(6.31\times10^{-11})} \\ \lbrack OH^-\rbrack=1.601\times10^{-4}\text{mol}/L \end{gathered}\)Thus, the concentration of OH- in the solution is 1.601 x 10^-4 mol/L.
3) Next, we need to consider the dissocation of Ba(OH)2 to obtain the concentration of the solution.
Considering that Ba(OH)2 completely dissociates in water:
\(Ba(OH)_{2(aq)}\to Ba^{2+}_{(aq)}+2OH^-_{(aq)}\)Note that each molecule of Ba(OH)2 would produce 2 ions OH-. In terms of concentration, we can say that the concentration of OH- in solution would be twice the concentration of Ba(OH)2.
Since we calculated the concentration of OH- ions, we can use the relation above to calculate the concentration of Ba(OH)2 by simply dividing [OH-] by 2:
\(\text{molarity of Ba(OH)}_2=\frac{\lbrack OH^-\rbrack}{2}=8.001\text{ }\times10^{-5}mol/L\)Therefore, the concentration of Ba(OH)2 in solution is 8.001 x 10^-5 mol/L. Note that, since the question required the concentration of solution and not the number of moles, we don't need to consider the volume given for this calculation.
The best option to answer the question would be number 4 (7.92 x 10^-5 M)
Concerning Boyle's Law, if you had a gas at a pressure of 101 kPa and decreased the volume of the container holding the gas to one quarter from where it started, what would be the new pressure of the gas
Answers
Answer:
\(P_2=404 kPa\)
Explanation:
Hello,
In this case, the Boyle's is mathematically defined via:
\(P_1V_1=P_2V_2\)
Which stands for an inversely proportional relationship between volume and pressure, it means the higher the volume the lower the pressure and vice versa. In such a way, since the volume is decreased to one quarter, we can write:
\(V_2=\frac{1}{4} V_1\)
We can compute the new pressure:
\(P_2=\frac{P_1V_1}{V_2} =\frac{P_1V_1}{\frac{1}{4} V_1} =\frac{101kPa*V_1}{\frac{1}{4} V_1} \\\\P_2=4*101kPa\\\\\\P_2=404 kPa\)
Which means the pressure is increased by a factor of four.
Regards.
Which of the following continents houses more than half of the chronically hungry population?
Answers
A 25 ml solution of 0.5 M NaOH is titrated until neutralized into a 50 ml sample of HCl?
Answers
The concentration of the acid is \(0.25 M\).
Titration is a laboratory technique used to determine the concentration of a substance in a solution by reacting it with a standardized solution of known concentration.
The titration formula can be given by,
(Volume of the Base) \(\times\) (Normality of the Base) = (Volume of the Acid) \(\times\) (Normality of the Acid)
\(\Rightarrow V_1N_1=V_2N_2\)
Given, the volume of the base (\(NaOH\)), \(V_1 =25 ml\).
The concentration of the base (\(NaOH\)), \(M_1=0.5 M\).
The equivalence of the base (\(NaOH\)) is \(1\).
Hence, the normality of the base (\(NaOH\)), \(N_1=\frac{0.5}{1}N=0.5N\).
Given, the volume of the acid (\(HCl\)), \(V_2 =50 ml\).
Let us assume that the normality of the acid (\(HCl\)) \(N_2\).
Substitute the values in the given formula of titration.
\((25\times0.5)=(50 \times N_2)\\\Rightarrow 12.5=50N_2\\\Rightarrow N_2=\frac{12.5}{50} N\\\Rightarrow N_2=0.25 N\)
Hence, the normality of the acid (\(HCl\)), \(N_2=0.25 N\).
The equivalence of the acid (\(HCl\)) is \(1\).
Therefore, the concentration of the acid, \(M_1=\frac{0.25}{1}=0.25 M\).
Learn more about titration here: brainly.com/question/186765
What is the chemical formula for copper(II) sulfate?
O CuSO4
O Cu₂SO4
O CuS
O Cu₂S
Answers
The chemical formula for copper(II) sulfate is CuSO4.
What is copper(II) sulfate?Copper(II) sulfate is a chemical compound that is made up of copper, sulfur, and oxygen. It has the chemical formula CuSO4 and is commonly referred to as "blue vitriol" or "bluestone." Copper(II) sulfate can be prepared by reacting copper oxide or copper metal with sulfuric acid. It is a blue-colored crystalline solid that dissolves easily in water.
Copper(II) sulfate has many uses in industry and can be used as a fungicide, herbicide, pesticide, and in the manufacture of other chemicals. It is also commonly used in schools and laboratories as a reagent in chemical reactions and experiments.
Learn about copper(II) sulfate here https://brainly.com/question/30459517
#SPJ1
Translate this word equation into a formula equation:
Barium + Gold (II) Phosphate -> Gold +
Barium Phosphate
Answers
5. When magnesium hydroxide and HCl are mixed together, magnesium
chloride and water are formed. In a particular reaction, 25.0 g of HCI is used with
enough magnesium hydroxide to completely react the HCl.
Mg(OH)₂ +HCI—-> MgCl2 + H20
(a) Balance this equation.
(b) Calculate the number of moles of hydrochloric acid available (25.0 g).
(c) How many moles and grams of magnesium hydroxide were needed for
complete reaction of the 25.0 g of HCI ?
moles=
grams
=
Answers
The moles and mass of the magnesium hydroxide are 0.356 mol and 20.77 g.
What is the balanced chemical equation?A balanced equation in which the number of atoms of each element is equal on both sides of the chemical equation. The law of conservation of matter must follow a balancing of equations.
By obeying the law of conservation of matter, the total mass of the chemical elements on the reactant side must be equal to the total mass of chemical elements on product side in a balanced chemical equation.
The balanced chemical equation magnesium hydroxide and HCl:
\(Mg(OH)_2 +2HCI \longrightarrow MgCl_2 + 2H_2O\)
The mass of the HCl = 25 g
The number of moles of HCl = 25/36.5 = 0.712 mol
2 mol of HCl reacts with magnesium hydroxide = 1 mol
0.712 mol of HCl reacts with magnesium hydroxide = 0.712/2 = 0.356 mol
The mass of magnesium hydroxide = 0.356 × 58.32 = 20.77 g
Learn more about the balanced chemical equation, here:
brainly.com/question/28294176
#SPJ1
Reaction 1: Solid sodium hydroxide dissolves in water to form an aqueous solution of ions. ????????????H(????) → ????????+(????????) + ????H −(????????) + x1????????
Reaction 2: Solid sodium hydroxide reacts with an aqueous solution of hydrogen chloride to form water and an aqueous solution of sodium chloride. ????????????H(????) + H +(????????) + ????????−(????????) → H2????(????) + ????????+(????????) + ????????−(????????) + x2????????
Reaction 3: An aqueous solution of sodium hydroxide reacts with an aqueous solution of hydrogen chloride to form water and an aqueous solution of sodium chloride. ????????+(????????) + ????H −(????????) + H +(????????) + ????????−(????????) → H2????(????) + ????????+(????????) + ????????−(????????) + x3????J
Procedure Reaction
1 a. In the glassware menu, take out a 50 mL graduated cylinder and a foam cup. From the tools menu, take out the scale. From the solutions stockroom, move the distilled water and solid NaOH onto the workbench.
b. Transfer 50.0 mL of water to the foam cup. To do this, drag the carboy of water onto the graduated cylinder. (Before you release the mouse button, the cursor will show a "plus sign" to indicate that it is the recipient). A transfer textbar will appear, enter "50.0" mL and click on pour. (You will notice that the graduated cylinder now reads 50.0 mL).
c. Weigh about 1 gram of solid sodium hydroxide pellets, NaOH(s), directly into the foam cup and record its mass to the nearest 0.01 gram. To do this, place the foam cup on the balance so it registers a mass, then click the "Tare" button. Drag the NaOH bottle onto the foam cup. (When you release the mouse, the bottle will be tipped to show that it is in the pour mode). Next, type "1.00" grams into the transfer bar and then click pour. Note that the balance now reads the mass of the transferred NaOH. You may now take the cup off of the scale.
d. Click on the graduated cylinder, record its temperature and then drag it onto the foam cup. (When you release the mouse, the graduated cylinder will be tipped to show that it is in pour mode.) Enter "50.0" mL in the transfer bar and then click pour. Record the highest temperature. e. Remove the foam cup and graduated cylinder from the workbench. (Right click on the item and select "remove.")
Reaction 2
a. Take the 0.5 M HCl from the strong acids cabinet and a fresh foam cup and a fresh 50 mL graduated cylinder from the glassware menu and place them on the workbench. The procedure for Reaction 2 is the same as for Reaction 1 except that 50.0 mL of 0.50 M hydrochloric acid solution is used in place of the water. After measuring 50.0 mL of the HCl solution into the graduated cylinder, proceed as before with steps b-e of the procedure for Reaction 1.
Reaction 3
a. Take out a 25 mL graduated cylinder, a fresh foam cup, the 1.0 M HCl and the 1.0 M NaOH. (If you are running out of room on the workbench, you may remove the previously used chemicals.) Use the graduated cylinder to measure and transfer 25.0 mL of 1.0 M HCl into the foam cup. Pour an equal volume of 1.0 M sodium hydroxide solution into a clean graduated cylinder.
b. Record the temperature of each solution to the nearest 0.1 oC. Pour the sodium hydroxide solution into the foam cup and record the highest temperature obtained during the reaction.
Data and Analysis
Reaction 1Reaction 2Reaction 3
Mass of solution* (g) 1.03g 1.03g
Initial temperature(°C) 25oC 25OC 25OC
Maximum temperature (°C) 30.3oC 37oC 31.7oC
Temperature change (∆T)
Heat energy q (kJ)
Moles of NaOH
Molar heat of reaction (-q/mol) also known as Enthalpy change,
DH (kJ/mol)
Answers
Source https://www.physicsforums.com/threads/calorimetry-help-chemistry.399653/
The conversion of more than one substance reactant into one or more distinct substances, products, and subsequent discussion can be characterized as follows:
Reaction Calculation:Calculating the Reaction 1:
\(NaOH\ (s) \rightarrow Na^+ \ (aq) + OH^- \ (aq) + X_1\ \ KJ ......................... (1)\)
\(NaOH\) mass = \(1\ g\)
\(H_2O\) mass = \(50 \ mL = 50\ g\)
water heat of \(s_p\) = \(4.186\ \frac{ J}{ g\ ^{\circ}C}\)
\(\Delta T\) = final temp - initial temp \(= 30.3 - 25 = 5.3^{\circ} \ C\\\)
Therefore
Calculating the releasing heat
= mass × sp heat × \(\Delta T\)
= 50 × 4.186 × 5.3 J
= 1109.3 J
Calculating the \(NaOH\) mass \(= 1\ g = \frac{1}{ 40}\ mole= 0.025 \ mole\)
Calculating the releasing heat per mole:
\(\to NaOH = \frac{1109.3}{ 0.025} = 44372\ J = 44.4\ KJ\)
Thus
\(\to X_1 = 44.4\ KJ\)
Calculating the Reaction 2:
\(NaOH \ (s) + H^+\ (aq) + Cl^- \ (aq) \rightarrow Na^+ \ (aq) + Cl^- \ (aq) + H_2O + X_2 \ KJ\\\)
Calculating the net ionic from the equation:
\(NaOH\ (s) + H^+\ (aq) \rightarrow Na^+ \ (aq) + H_2O \ (l) + X_2 \ KJ ................................... (2)\)
Calculating the \(NaOH\) mass:
\(= 1\ g = \frac{1 }{ 40} = 0.025\ mole\)
Calculating the \(HCl\) mass:
\(= 50\ mL = 50\ g\) [ density = 1 approx]
sp heat of the solution \(= 4.186 \frac{J}{g\ ^{\circ}C}\) [ assume the sp heat same as water]
\(\Delta T\) = final temp - initial temp \(= 36.97 - 25 = 11.97^{\circ} \ C\)
Calculating the releasing heat:
= mass × sp heat × \(\Delta T\)
= 50 × 4.186 × 11.97 J
= 2505.3 J
Calculating the releasing heat per mole in \(NaOH\):
\(= \frac{ 2505.3 }{ 0.025} = 100212\ J = 100.2 KJ\)
Thus
\(X_2 = 100.2 \ KJ\)
Calculating the Reaction 3:
\(Na^+ \ (aq) + OH^-\ (aq) + H^+ \ (aq) + Cl^- \ (aq) \rightarrow Na^+\ (aq) + Cl^-\ (aq) + H_2O + X_3\ KJ\)
Calculating the net ionic in the given equation
\(H^+ + OH\rightarrow H_2O\ (l) + X_3\ KJ .............................................................. (3)\)
Calculating the volume of \(NaOH\):
\(= 25 \ mL\ of\ 1.0\ M = 25 \times \frac{1 }{ 1000} \ mole = 0.025 \ mole\)
Calculating the volume of HCl:
\(= 25 \ mL\ of\ 1.0\ M = 25 \times \frac{1 }{ 1000} \ mole = 0.025 \ mole\)
Calculating the total volume
\(= 50 \ mL = 50\ g\) { density = 1]
Calculating the sp heat in the solution
\(= 4.186 \frac{J}{ g \ ^{\circ} C}\) [ assumed the sp heat is the same as water]
\(\Delta T\) = final temp - initial temp \(= 31.7- 25 = 6.7^{\circ}\ C\)
Calculating the releasing heat
= mass × sp heat × \(\Delta T\)
= 50 × 4.186 × 6.7 J
= 1402.3 J
Calculating the releasing heat per mole in \(NaOH\):
\(=\frac{1402.3 }{ 0.025} \ J\\\\= 56092\ J\\\\= 56,09\ KJ\)
Therefore
\(X_3 = 56.09 \ KJ\\\\X_1 = 44.4\ KJ\\\\X_2 = 100.2\ KJ\\\\X_3 = 56.09\ KJ\\\\X_2 - [ X_1+ X_3 ] = 100.2 - [44.4 + 56.09]\ = 100.2 - 100.49= -0.29\)
So, the difference is equal to zero.
\(\to X_2 = X_1 + X_3\)
This is due to the fact that if we add the reaction (1) and (3) we get the reaction (2)
Calculating the difference percentage:
\(= [\frac{0.29 }{100.2} ] \times 100 = 0.29\%\)
The number of joules released in reaction 1 would be 4 times what is released in the calculation if we used 4 g of \(NaOH\).
\(\to 4 \times 1109.3\ J = 4437.2 \ J\\\\\)
Calculating the \(NaOH\) moles \(= \frac{4}{40} = 0.1\)
\(\to X_1 = \frac{4437.2}{ 0.1} = 44372 \ J = 44.4\ KJ\)
As a result, it has no bearing on the solution's molar heat.
Find out more about the reaction here:
brainly.com/question/17434463
How many grams of Aspirin (acetylsalicylic acid) should we form in this reaction if we started with 2.08g of Salicyclic Acid?
Answers
Taking into account the reaction stoichiometry, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.
Reaction stoichiometryIn first place, the balanced reaction is:
C₄H₆O₃ + C₇H₆O₃ (Salicyclic Acid) →C₉H₈O₄ (aspirin) + C₂H₄O₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
C₄H₆O₃: 1 moleC₇H₆O₃: 1 moleC₉H₈O₄: 1 moleC₂H₄O₂: 1 moleThe molar mass of the compounds is:
C₄H₆O₃: 102 g/moleC₇H₆O₃: 138 g/moleC₉H₈O₄: 180 g/moleC₂H₄O₂: 60 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
C₄H₆O₃: 1 mole ×102 g/mole= 102 gramsC₇H₆O₃: 1 mole ×138 g/mole= 138 gramsC₉H₈O₄: 1 mole ×180 g/mole= 180 gramsC₂H₄O₂: 1 mole ×60 g/mole= 60 gramsMass of aspirin formedThe following rule of three can be applied: if by reaction stoichiometry 138 grams of salicyclic acid form 180 grams of aspirin, 2.08 grams of salicyclic acid form how much mass of aspirin?
\(mass of aspirin=\frac{2.08 grams of salicyclic acidx 180 grams of aspirin}{138 grams of salicyclic acid}\)
mass of aspirin= 2.713 grams
Then, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.
Learn more about the reaction stoichiometry:
brainly.com/question/24741074
brainly.com/question/24653699
#SPJ1
Which best describes a neutralization reaction?
➪A reaction between an acid and a base
➪A reaction between two acids
➪A reaction between a base and a salt
➪A reaction between two salts
Answers
Answer:
D got it right
Explanation:
Answer:
The answer is d
Explanation:
God bless you have a great day
20 POINTS!!!! HELP PLS IN A HURRY!!!!!!!!
Ionic compounds that dissolve in water conduct electricity because they break into ____ that move freely.
Answers
Also what happens if you decrease NOCL
Answers
Answer:
el que paso del one jhaulio
Explanation:
When a hydrogen atom is added to a polyatomic ion, the amount of negative charge . Following this pattern, we can see that hydrogen carbonate has a charge of and hydrogen sulfate has a charge of .
Answers
If we add one or two hydrogen ions to a polyatomic ion that has a 3-charge, as the phosphate ion (PO₄3-), it will still be a polyatomic ion. (Three H+ would entirely cancel out the 3-charge, turning it into a neutral molecule and removing it from the category of polyatomic ions.
Why does carbonate have a negative 2 charge?As a result, the carbonate ion has 2 more electrons than protons due to its negative charge. The doubly bonded oxygen in the carbonate ion is neutral, whereas each single bonded oxygen has a negative charge. This is the cause of the total charge of "-2," then.
An essential component of the atmosphere of stars like the Sun is the hydrogen anion.
learn more about carbonate ion
https://brainly.com/question/28770987
#SPJ1
4.The voltaic cell has with Pt/H+/H2 and Ag/AgC/Cl- half cells is a possible design for an electronic pH meter, in that the actual cell E depends on [H3O+].
(a) Write out (under each half cell) the electrode reactions, and give below the overall cell equation.
(b) Indicate with arrows the direction of motion of the ions and electrons as the cell reacts spontaneously.
(c) Mark the electrodes as + or – and cathode or anode.
(d) What is the standard cell potential, Eo?
Eo = _______________________
(e) Calculate the actual cell potential, E, if the unknown [H3O+] is 1.0 x 10-4 M.
E = _________________________
(f) If [H+] remains variable, then for this cell E = A + B.pH. What are the values of the Constants A and B?
A = ____________ , B = ______________
Answers
Answer:
(a) Electrode reactions:
Pt/H+/H2: 2H+(aq) + 2e- -> H2(g) (reduction)
Ag/AgCl/Cl-: AgCl(s) + e- -> Ag(s) + Cl-(aq) (reduction)
Overall cell equation: 2AgCl(s) + H2(g) -> 2Ag(s) + 2HCl(aq)
(b) Direction of motion of ions and electrons:
In the Pt/H+/H2 half-cell, hydrogen ions (H+) move towards the platinum electrode and accept electrons to form hydrogen gas (H2). In the Ag/AgCl/Cl- half-cell, silver ions (Ag+) move towards the silver chloride (AgCl) electrode and accept electrons to form silver (Ag) metal while chloride ions (Cl-) move away from the electrode. Electrons move from the hydrogen electrode to the silver electrode through the external circuit.
(c) Electrode labeling:
The Pt/H+/H2 electrode is the cathode (-) and the Ag/AgCl/Cl- electrode is the anode (+).
(d) Standard cell potential (Eo):
The standard cell potential can be calculated using the standard reduction potentials for each half-cell:
Eo(cell) = Eo(reduction, Ag/AgCl/Cl-) - Eo(reduction, Pt/H+/H2)
Eo(reduction, Ag/AgCl/Cl-) = +0.222 V (from standard reduction potential tables)
Eo(reduction, Pt/H+/H2) = 0 V (by definition)
Eo(cell) = +0.222 V - 0 V = +0.222 V
(e) Actual cell potential (E):
E(cell) = Eo(cell) - (0.0592 V / n) * log[H3O+]
where n is the number of electrons transferred in the balanced equation (2 in this case)
E(cell) = +0.222 V - (0.0592 V / 2) * log(1.0 x 10^-4 M)
E(cell) = +0.222 V - (0.0296 V) = +0.1924 V
(f) Values of constants A and B:
E(cell) = A + B.pH
At pH 7 (neutral), E(cell) = Eo(cell) = +0.222 V
Therefore, A = +0.222 V and B = -0.0592 V/pH
A graduated cylinder contains 4.50 mL of water. After a piece of zinc is dropped into the cylinder, the water level rises to 9.24 mL. What is the volume of the piece of zinc?
Answers
Answer: Well, the volume of the copper is (63.4 - 40.0) * mL = 23.4 * mL
Explanation:
Do you agree? The copper displaces the given volume of water.
Now ρ Cu = 8.90 ⋅ g ⋅ c m 3 OR ρ Cu = 8.90 ⋅ g ⋅ m L − 1, i.e. 1 ⋅ m L ≡ 1 ⋅ c m 3
But by definition, ρ density = mass volume
And thus mass = ρ × volume = 8.90 ⋅ g ⋅ m L − 1 × 23.4 ⋅ m L
= 208.3 * G
Determine the mass in grams of 5.83 × 10²¹ atoms of arsenic. (The mass of one mole of arsenic is 74.92 g.)
Answers
Answer: 0.725g
Explanation: mass = (5.83*10^21/6.02214076*10^23)*74.92 g = 0.725 g
Explain the scientific meaning and use of the word "transformation".
Answers
Transformation in chemistry is scientifically used to explain the process of changing one compound to another in a chemical reaction.
What is transformation?The word "transformation" has a very special significance in chemistry. We know that in English, to transform would simply imply to change from one form to another. This is not quite far from its meaning in the parlance of chemistry.
The word transformation is normally applied in the area of chemical reactions especially as it has to do with reaction with in organic chemistry. It has to do with the change from one molecule to another and this is of great importance in the discussion of synthetic chemistry.
As such, the word transformation in chemistry is scientifically used to explain the process of changing one compound to another in a chemical reaction.
Learn more about chemical transformation:https://brainly.com/question/8210521
#SPJ1
pls help me in solve this question in chemistry
Answers
The chemical equation for the decomposition of water is:
\(2 H_2O -- > 2 H_2 + O_2\)
To balance this equation, we need to count the number of atoms of each element on both sides of the equation.
On the left side of the equation, we have:
2 hydrogen atoms (2 H₂O)
2 oxygen atoms (2 H₂O)
On the right side of the equation, we have:
2 hydrogen atoms (2 H₂)
2 oxygen atoms (1 O₂)
We can see that the number of hydrogen atoms is already balanced, but the number of oxygen atoms is not. To balance the equation, we need to add a coefficient in front of O2 so that we have the same number of oxygen atoms on both sides.
The balanced equation is:
\(2 H_2O -- > 2 H_2 + 1 O_2\)
A compound is broken down into simpler compounds during a decomposition reaction. Different techniques, such as heating, exposure to light, or the inclusion of a catalyst, can be used to produce this reaction.
The reactant component splits into two or more products, which may be elements or compounds, during decomposition. A synthesis reaction, in which less complex substances join to create a more complex compound, is the antithesis of this reaction.
learn more about decomposition here
https://brainly.com/question/27746877
#SPJ1
1) G to H.
2) I to J.
3) J to I.
4) I to H.
Answers
3 ..............................
How many moles of NaCl are there in 200.0 mL of 1.00 M NaCl solution? How many grams? (Hint: The molar mass of NaCl is 58.44 g/mol)
Answers
1) Moles of NaCl in 200.0 mL of solution.
\(\text{Molarity (M)=}\frac{\text{moles of solute}}{\text{liters of solution}}\)Solve for moles
\(\text{moles of solute=Molarity}\cdot\text{liters of solution}\)Convert mL into L.
\(L=200.0mL\cdot\frac{1L}{1000mL}=0.200L\)Plug in know values
\(\text{moles of NaCl=1.00 M}\cdot0.200L=0.20molNaCl_{}\)There are 0.20 moles of NaCl in 200.0 mL of solution.
2) grams of NaCl in 200.0 mL of solution.
\(undefined\).
Consider the following reaction at 298K.
I2 (s) + H2 (g) 2 I- (aq) + 2 H+ (aq)
Which of the following statements are correct?
Answers
From the forgoing, we can conclude that the the correct statements are;
n = 2 mol of electronsK < 1What are the redox reaction?The redox reaction is one in which one specie is oxidized and the other is reduced. We can obtain the equilibrium constant from the relation;
E°cell = 0.0592/n log K
E°cell = cell potential
n = number of electrons
K = equilibrium constant
E°cell = -0.403 - 0.535 = -0.938 V
n = 2 electrons
Thus;
-0.938 = 0.0592/2 logK
-0.938 * 2/ 0.0592 = log K
K = 2 * 10^-31
Also;
ΔG = - nFE°cell
ΔG = - (2 * 96500 * -0.938)
ΔG = 181kJ/mol
Learn more about equilibrium constant: brainly.com/question/10038290
#SPJ1
What is the change in enthalpy when 90.6 g
of steam at 100◦C is converted to liquid water
at the same temperature and pressure? The
heat of vaporization of water is 40.7 kJ/mole.
Answers
The change in enthalpy when 90.6 g of steam at 100◦C is converted to liquid water at the same temperature and pressure is 204.7 KJ
How do i determine the change in enthalpy?First, we shall obtain the number of mole water converted to steam. details below:
Mass of water = 90.6 grams Molar mass of water = 18 g/mol Mole of water =?Mole = mass / molar mass
Mole of water = 90.6 / 18
Mole of water = 5.03 moles
Finally, we shall determine the change in enthalpy. Details below:
Mole of water (n) = 5.03 molesHeat of vaporization (ΔHv) = 40.7 KJ/molChange in enthalpy (ΔH) =?ΔH = n × ΔHv
ΔH = 5.03 × 40.7
ΔH = 204.7 KJ
Thus, we can conclude that the change in enthalpy is 204.7 KJ
Learn more about enthalpy change:
https://brainly.com/question/24170335
#SPJ1
Plants use sunlight to produce some ATP during photosynthesis. How do plants produce ATP when the Sun is not out?
Plants are secondary consumers.
Plants also use cellular respiration.
Plants extract ATP from the stars.
Plants are weak in the dark.
Answers
Answer:
The answer is
Plant also use cellular respiration
Answer:
B - Plants also use cellular respiration.
Explanation:
Did the test.
You are inside a room with a temperature of 11°C. You step outside and the temperature is 100°C. What is the AT?
A) 0.76°C
B) 157°C
C) 89°C
D) 6052°C
E) 1.31°C
F) 21°C
Answers
Answer:
89°c
Explanation:
i think this is the answer cause the temperature changed from 11 to 100 and so the atmospheric temperature would be the change in temperature
100-11=89°c
I hope this helps and sorry if it's wrong
8. A moving truck is loading heavy furniture using a long ramp. Why does this simple machine make the work easier?
The ramp makes the furniture weigh less.
It takes less force to move the furniture up the long ramp.
The ramp acts like a lever to make the work easier.
The furniture fits on the ramp.
Answers
Environmental scientists collect air samples so they can test the quality of the air. They start with rigid metal containers that are completely empty—the air has been pumped out of them.
What happens to the pressure inside the container and the volume of the container as air enters it?
Answers
Explanation:
filling air inside an empty o2 medal containers, if air is added, the air inside, creates volume inside.
due to heat, weather,... depending on what indoor or outdoor storage said containers r placed in,;
So, I can't give you an answer, due to lack of details..sorry...