Can't get it very well can you help withs steps

Main Answer: A range of values, that with a certain degree of probability contain the population parameter, is known as a "confidence interval estimate."

Supporting Question and Answer:

What is the purpose of a confidence interval estimate in statistics?

The purpose of a confidence interval estimate in statistics is to provide a range of values that, with a certain degree of probability, contains the population parameter of interest. This range allows for a measure of uncertainty and provides a level of confidence in the estimation process.

Body of the Solution: The correct answer is "confidence interval estimate."

A confidence interval estimate is a range of values that, with a certain degree of probability (often represented by a confidence level), is believed to contain the population parameter of interest. It is used in statistics to provide an estimate of an unknown population parameter based on sample data. The confidence interval provides a range rather than a single point estimate, allowing for a measure of uncertainty in the estimation process.

Final Answer: The correct answer is "confidence interval estimate."

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A range of values, that with a certain degree of probability contain the population parameter, is known as a "confidence interval estimate."

The purpose of a confidence interval estimate in statistics is to provide a range of values that, with a certain degree of probability, contains the population parameter of interest. This range allows for a measure of uncertainty and provides a level of confidence in the estimation process.

The correct answer is "confidence interval estimate."

A confidence interval estimate is a range of values that, with a certain degree of probability (often represented by a confidence level), is believed to contain the population parameter of interest. It is used in statistics to provide an estimate of an unknown population parameter based on sample data. The confidence interval provides a range rather than a single point estimate, allowing for a measure of uncertainty in the estimation process.

The correct answer is "confidence interval estimate."

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The average of the sample ranges for the weight of packages of Skittles is 0.11. So, the correct answer is (e) 0.11.

To find the average of the sample ranges for the weight of packages of Skittles, we first calculate the range for each sample. The range is the difference between the maximum and minimum values in each sample.

Sample 1: Range\(= 3.62 - 3.58 = 0.04\)

Sample 2: Range\(= 3.65 - 3.49 = 0.16\)

Sample 3: Range \(= 3.65 - 3.45 = 0.20\)

Sample 4: Range \(= 3.64 - 3.54 = 0.10\)

Sample 5: Range\(= 3.62 - 3.49 = 0.13\)

Next, we calculate the average of these sample ranges:

A\(verage = (0.04 + 0.16 + 0.20 + 0.10 + 0.13) / 5 = 0.11\)

Therefore, the average of the sample ranges for the weight of packages of Skittles is \(0.11\). So, the correct answer is (e) \(0.11.\)

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Answer:

1/3

Step-by-step explanation:

The test statistic for the student who scored 79.6 points on the exam is 1.38

The relationship between a value and the mean of a group of values is quantified by a Z-score. The Z-score is calculated using standard deviations from the mean. A Z-score of zero means the data point's score is equal to the mean score.

Formula for z-score = x - u / σ

According to the question,

Sample size = 20 grades

Mean of sample = 74.8

Sample Standard deviation = 15.5

We have to calculate z-score for the student who scored 79.6 points on the exam.

But here if we see , sample size is less than 30 and population standard deviation is unknown.

So, we can't use Z-score .

t-statistics = x - u / (s/√n)

=> 79.6 - 74.8 / ( 15.5 / √20)

=> 4.8√20 / 15.5

=> 1.38 is required answer

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Answer:

It is called an isosceles trapezoid/ trapezium

Step-by-step explanation:

The magnitude of vector u (||u||) is approximately 11.704, the magnitude of vector v (||v||) is 5, and the dot product of vectors u and v (u⋅v) is 54.

To compute the requested values, we'll use the definitions of vector norms and the dot product.

Magnitude of vector u (||u||):

||u|| = √\(((-6)^2 + (-10)^2 + 1^2)\)

= √(36 + 100 + 1)

= √(137)

≈ 11.704

Magnitude of vector v (||v||):

||v|| = √\(((-4)^2 + (-3)^2 + 0^2)\)

= √(16 + 9 + 0)

= √(25)

= 5

Dot product of vectors u and v (u⋅v):

u⋅v = (-6)(-4) + (-10)(-3) + (1)(0)

= 24 + 30 + 0

= 54

Therefore, the computed values are:

||u|| ≈ 11.704

||v|| = 5

u⋅v = 54

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Answer:

The perpendicular bisector theorem states that if XY bisects another line segment AB, creating perpendicular angles, then, the line segment XA & XB are congruent to each other.

The length of WY is 7.3. Since WZ is perpendicular to line XY, XZ= ZY and WX= WY. Since WX= 7.3, then WY also must equal 7.3

Answer:

X

Step-by-step explanation:

18/6=3

A green leaf can only reflect green wavelength. when it put on red light it appears dark because in red light leaf is not able to reflect any light so it looks dark.

In the day light the green leaf absorbs all constituents light colors of white except green. It means the leaf absorbs all wavelengths of colors that are  violet, indigo, blue, yellow, orange, red but not green. Since the green light alone is reflected thus leaf appears green. Under the red light all colors including the green are absorbed in the red color. Hence the leaf appears as dark. in the red light, the leaf will absorb the light and it appears dark. All the objects absorb all the colors present in the sunlight or from any source of white light and reflect the color ray of particular color of the object. It is the property of all the colored objects. So all the objects appear in some color. here green leaf absorbs the colors from sunlight.

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Answer:

$ 25.92

Step-by-step explanation:

Hi there !

100 % .............. $ 24

108 % ................$ x

x = 108×24/100

= 2592/100

= $ 25.92

Good luck !

Answer:

Step-by-step explanation:

given:

A shoe store marks up its merchandise by 8%.

find:

What was the selling price of a pair of shoes whose wholesale price is $24.00?

solution:

selling price = wholesale price x (1 + percentage)

                    = $24  x  ( 1 + 0.08)

                    = $25.92

The probability to get a sample average of 51 or more customers if the manager had not offered the discount is 1.36%

We can use the formula for the standard error of the mean to calculate the standard deviation of the sample means. The standard error of the mean is given by:

standard error of the mean = standard deviation / √(sample size)

In this case, the standard error of the mean is:

standard error of the mean = 10 / √(6) = 4.08

To find the probability of observing a sample mean of 51 or more customers, we need to standardize the sample mean using the standard error of the mean. This gives us the z-score, which we can use to look up the probability in a standard normal distribution table.

The z-score is given by:

z-score = (sample mean - population mean) / standard error of the mean

In this case, the population mean is 42, and the sample mean is 51. Therefore, the z-score is:

z-score = (51 - 42) / 4.08 = 2.21

Using Table 1 (or a calculator or statistical software), we can find that the probability of observing a z-score of 2.21 or higher is approximately 0.0136 or 1.36%.

This means that if the manager had not offered the discount, there would be a 1.36% chance of observing a sample mean of 51 or more customers.

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Complete Question:

A small hair salon in Denver, Colorado, averages about 42 customers on weekdays with a standard deviation of 10. It is safe to assume that the underlying distribution is normal. In an attempt to increase the number of weekday customers, the manager offers a $4 discount on 6 consecutive weekdays. She reports that her strategy has worked since the sample mean of customers during this 6-weekday period jumps to 51. Use Table 1.

What is the probability to get a sample average of 51 or more customers if the manager had not offered the discount?

Answer:

15x + 20y  =  150

Step-by-step explanation:

15x is how many soccer balls he can get and 20y is how many footballs he can get. (I don't know how to explain my thinking.)

The domain and range of a given relation, we need to understand the nature of the relation and the restrictions it imposes on the variables involved.

Since you haven't provided a specific relation, I'll explain the general concepts of domain and range.

The domain of a relation refers to the set of all possible input values, or the values for which the relation is defined.

It represents the x-values that can be plugged into the relation to obtain a meaningful output.

The domain can be restricted due to various reasons, such as the presence of square roots, division by zero, or logarithms.

The range of a relation, on the other hand, refers to the set of all possible output values.

It represents the y-values that the relation can produce when given valid input values from the domain.

To determine the domain and range of a specific relation, you need to analyze the given relation for any restrictions on the variables involved.

If the relation contains a square root, the expression within the square root must be non-negative to avoid complex or imaginary numbers.

If there is a denominator, it should not be zero.

Without the specific relation, it's not possible to provide a detailed analysis.

Explanation helps you understand the general concept of domain and range.

If you provide the specific relation, I'll be glad to help you determine its domain and range.

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The domain of a relation is the set of all possible input values, or the x-values, of the ordered pairs. The range of a relation is the set of all possible output values, or the y-values, of the ordered pairs.

To find the domain and range of a given relation, we need to examine the x-values and y-values of the ordered pairs in the relation.

Let's consider the given relation:

First, we look at the x-values of the ordered pairs. The set of all x-values is the domain of the relation.

Next, we look at the y-values of the ordered pairs. The set of all y-values is the range of the relation.

By analyzing the given relation, we can determine the domain and range.

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The probability of the team having at most 1 injury in the game can be calculated using a Poisson distribution.

To find the probability of the team having at most 1 injury in a typical football game, we can use a Poisson distribution. The Poisson distribution is commonly used to model the occurrence of rare events, such as injuries in this case.

The parameter for the Poisson distribution is the average number of injuries per game, which is given as 3.2.

Let's denote the random variable X as the number of injuries in a game. We need to calculate the probability P(X ≤ 1), which represents the probability of having at most 1 injury.

Using the Poisson distribution formula, we can compute this probability:

P(X ≤ 1) = P(X = 0) + P(X = 1)

Using the Poisson probability mass function, we substitute the values into the formula and calculate the probability.

The result will be the probability that the team will have at most 1 injury in the game.

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The probability that a continuous random variable takes a value less than zero is any number between zero and one.

The standard deviation of a normal distribution cannot be negative.

For any continuous random variable, the probability that it takes a value less than zero is given by the cumulative distribution function (CDF) at zero. Since the CDF is a monotonically increasing function that ranges from 0 to 1, the probability that the random variable takes a value less than zero is any number between 0 and 1, inclusive.

The standard deviation of a normal distribution is always a positive number since it is the square root of the variance, which is defined as the average of the squared deviations from the mean.

Since the deviations are squared, they are always non-negative, and their average (the variance) cannot be negative. Therefore, the standard deviation of a normal distribution cannot be negative.

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In the concept of inequality, the function that represents their saving based on the number of week is

w1 = $10 + x

w2 = $330 + x

And in the 170th week b0th of them have the same amount.

Inequality:

Inequality refer the non equal relation between two expressions.

Given,

Cole and Mikey both have summer jobs. Each of them is trying to save money in order to buy a car. Mikey already has $10 in his savings, while Cole has $330 in his saving account.

Here we need to find the function that represents their savings.

Let us represents the w1 as Cole savings and w2 as Mickey savings.

And x represents the amount of money saved per week.

So, the equation of their savings is written as,

w1 = $10 + x

w2 = $330 + x

So, to calculate Mikey and Cole have the same amount or money, then we have to equate the given expression, then we get,

$10 + x = $330 + x

2x = $340

x = 340/2

x = 170

At the 170th week both has the same amount.

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Between the scores of 55 and 100, approximately 82 percent of the general population would fail a standardized intelligence test with a mean of 100 and a standard deviation of 15.

To determine the range of scores at which 82 percent of the population would fail the intelligence test, we need to calculate the corresponding z-scores using the normal distribution. The z-score represents the number of standard deviations a particular score is away from the mean.

First, we find the z-score for the lower bound of the range (55). By subtracting the mean (100) from the score (55) and dividing by the standard deviation (15), we get a z-score of -3. The corresponding cumulative probability for this z-score is approximately 0.0013.

Next, we find the z-score for the upper bound of the range (100). Again, subtracting the mean (100) from the score (100) and dividing by the standard deviation (15), we get a z-score of 0. The corresponding cumulative probability for this z-score is 0.5.

To determine the range where 82 percent of the population would fail, we look for the z-score that corresponds to a cumulative probability of 0.82. By consulting a standard normal distribution table or using statistical software, we find that a z-score of approximately 0.98 corresponds to a cumulative probability of 0.82.

Finally, we convert this z-score back to the original scale by multiplying it by the standard deviation (15) and adding the mean (100). The resulting score is approximately 115. Therefore, approximately 82 percent of the general population would fail the test between the scores of 55 and 115.

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Answer:

30.99

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

MV is half of QM

Answer:

Step-by-step explanation:

Position at the second instant when the car has zero velocity is \(3.76m\). Acceleration at the second instant when the car has zero velocity is \(6.47 m/s^{2}\)

1.To determine the location of the front bumper at the second moment when the automobile has zero velocity, we must first determine the value of t at which the car's velocity is zero. The car's velocity is provided by the derivative of its location, x'(t), which is as follows:

\(x'(t) = (4.80m/s^2). t^2 - (0.100m/s^6)t^6\)

We can solve for \(t\) by setting \(x'(t) = 0\)

\((4.80m/s2)t2 - (0.100m/s^6)t^6 = 0\)

\(t = ((0.100m/s6)/(4.80m/s2))\)

\(t = 0.67 seconds\)

We use t = 0.672 seconds since t must be positive. We can get the location of the front bumper at t = 0.672s by plugging this value of t back into x(t):

\(2.17m + (4.80m/s^{2} )(0.672s)^{2} - (0.100m/s^{6} )(0.672s)^{6}\)

\(= 2.17m + 1.59 m = 3.76 m\)

2.To calculate the acceleration of the automobile at the second instant when the velocity is zero, take the second derivative of the location, x"(t), and multiply it by t = 0.672s:

\(x''(t) = (9.60 m/s^2)\)

\(t - (0.600 m/s^6)t^5\)

\(x''(0.672s) = (9.60 m/s^2)\)

\((0.672s) - (0.600 m/s^6)\)

\((0.672s)^5 = 6.47 m/s^2\)

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Answer:

1. none are odd

2. 21,35

3.none

4.none

5.27,81

Answers:

1. None (all even)

2. 21 & 35

3. None (all even)

4. None (all even)

5. 27 & 81

Answer:

ASA (Angle-Side-Angle)

Line AC bisects angle BAD so the two angles left are congruent, the same with BCD.

Line AC is in both triangles

The line AC is between the two angles, so ASA.

When there are precisely two outcomes of a trial that are mutually exclusive, the binomial distribution is used.

A discrete distribution is the binomial distribution. It is a probability distribution that is frequently utilised. It is then designed to represent a variety of distinct phenomena that appear in business, social sciences, natural sciences, and medical research.

The probability of achieving a specific number of successes, such as successful basketball shots, out of a fixed number of trials can be determined using the binomial distribution. To determine discrete probabilities, we use the binomial distribution.

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Answer:

as 92 is 2 std deviaiton above mean ; th

Step-by-step expla

The Element 22 from the scalar multiplication of the matrix is -30 and the right option is a. -30.

The term scalar multiplication refers to the product of a real number and a matrix.

To get the value of element 22 after scalar multiplication of matrix \(\left[\begin{array}{ccc}0&8\\6&-5\\\end{array}\right]\) by 6, we following the steps below.

Step 1:

Element 22 means element in the Second row and second column

performing the operetion, Multiplying 6 by the matrix

Hence, the right option is a. -30.

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Answer:

2400 foot pounds

Step-by-step explanation:

The amount of work done by the four men is  1200 ft-lbs. so option B is correct.

The muscular work done by each man is equal to the weight of the boxes carried multiplied by the vertical distance moved.

The weight of each box is 5 pounds, and each man carries 20 boxes, so the total weight carried by each man is:

20 boxes x 5 pounds/box = 100 pounds

The vertical distance moved is the height of the ramp, which is 30 feet.

Therefore, the muscular work done by each man is:

Muscular work = weight x vertical distance

Muscular work = 100 pounds * 30 feet

Muscular work = 3000 ft-lbs

Since there are four men carrying boxes, the total muscular work done is:

Total muscular work = 4 * 3000 ft-lbs = 12000 ft-lbs

Therefore, the answer is B. 1200 ft-lbs.

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Step-by-step explanation:

According to the Question , diameter of circle is 16 inches. We need to find the area in terms of pi (π) . We know the area of circle as product of pi and square of radius . Therefore ,

\(\to\tt \orange{ Area = \pi r^2 } \\\\\tt \to Area = \pi (8 \ in.)^2 \\\\\tt\to \boxed{\orange{\tt Area = 64\pi in^2 }}\)

Answer:

\(64\pi\)

Step-by-step explanation:

diameter => D = 2r

r = D/2 = 16/2 = 8

area =

\(\pi \times r {}^{2} \)

=

\(64\pi\)

Answer:

Step-by-step explanation:

6\(\sqrt{5\\\)

\(\sqrt{5*36}\)

\(\sqrt{180}\)

If you think about it logically, how can you take 6 out? So there was a number 36 under the root, and because of that there is a possibility to take it out, because 6 squared is 36

Answer:

Vertically opposite angles are equal

So

x = 75°

Vertically opposite angles are equal

So

5y = 135°

Divide both sides by 5

y = 27

Hope this helps you

The resulting graph should be a U-shaped curve that is shifted 4 units to the left and 1 unit down from the basic graph of y = \(x^{2}\).

The function g(x) = (x + 4)2 - 1 can be obtained from the basic graph of the quadratic function y =\(x^{2}\).

This basic graph is a U-shaped curve with its vertex at the origin (0, 0).

To obtain g(x) from this graph, we can perform two transformations as follows:Shift the graph 4 units to the left by replacing x with (x + 4).

This gives us the graph of y = \((x+4)^{2}\).

Shift the graph 1 unit down by subtracting 1 from the entire function.

This gives us the graph of y = \((x+4)^{2}\) - 1.

The vertex of the graph is located at the point (-4, -1), and it opens upwards because the coefficient of the \(x^{2}\) term is positive.

To graph this function using the graphing tool, we can follow these steps:Enter the equation y =\((x+4)^{2}\) - 1 into the graphing tool.

Adjust the x-axis and y-axis ranges if necessary, so that the graph is visible.

Click on the "Graph" button to plot the function on the graphing tool.

The resulting graph should be a U-shaped curve that is shifted 4 units to the left and 1 unit down from the basic graph of y = \(x^{2}\).

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