Can you think of a way you use the geometrical terms reflection and translation in real life?

I have aids ;-;

20 tens, or 2010, equals 200 as the answer.

A modest electrical current is used in transcutaneous electrical nerve stimulation (TENS), a technique for reducing pain. A TENS machine is a tiny, battery-powered gadget with electrode leads that are wired to sticky pads. The pads are immediately affixed to your skin.

According to studies, using TENS for at least 30 minutes while being active is the best strategy for treating chronic pain. When you're resting, lying down, or just sitting motionless, it works less well.

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False. Sodium chloride (NaCl) is the main compound that exists in the ocean and is responsible for its salinity. Seawater is a complex mixture of various salts, dissolved gases, and other substances, but sodium chloride is the most abundant component. In fact, it accounts for about 85% of the total dissolved salts in the ocean.

Sodium chloride and other salts in the ocean come from a variety of sources, including the weathering of rocks on land, volcanic activity, and the input of salts from rivers and streams that drain into the ocean. Over time, these salts become concentrated in the ocean through processes such as evaporation and mixing.

It is important to note, however, that the concentration of sodium chloride and other salts in seawater is not uniform throughout the ocean. Factors such as temperature, depth, and location can all affect the concentration of salts in different regions of the ocean.

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Answer:

C

Explanation:

Actually, arranged to the size of smallest to least atom radius size = C

Atomic sizes generally get smaller as you go from L to R across a row of the periodic table.

Answer:

0.845 g C

Explanation:

To find the mass of carbon (C) consumed, you need to (1) convert grams Na₂SO₄ to moles Na₂SO₄ (via molar mass from periodic table), then (2) convert moles Na₂SO₄ to moles C (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles C to grams C (via molar mass from periodic table).

It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. This can be done by making sure the desired unit is the numerator. The final answer should have 3 sig figs because the given value (5.00 grams) has 3 sig figs.

Molar Mass (Na₂SO₄): 2(22.99 g/mol) + 32.07 g/mol + 4(16.00 g/mol)

Molar Mass (Na₂SO₄): 142.05 g/mol

1 Na₂SO₄ + 2 C ---> Na₂S + 2 CO₂

Molar Mass (C): 12.01 g/mol

5.00 g Na₂SO₄           1 mole Na₂SO₄            2 moles C              12.01 g
-----------------------  x  --------------------------  x  -----------------------  x  --------------- =
                                       142.05 g                1 mole Na₂SO₄        1 mole C

= 0.845 g C
                                   

The substances generated by the reaction are called products, and their formulas are placed on the right side of the equation.

A chemical reaction is a process in which chemical bonds between atoms to break and recognize, to form other new substances.

The substance which is present at the left hand side or start of a chemical reaction is known as Reactant.

The substance which is present at the right hand side or end of a chemical reaction is known as Product.

Example: Na + Cl → NaCl

Here Na and Cl are on the left hand side of a reaction so Na and Cl are reactants. Here NaCl is on the right hand side of a reaction so NaCl is product.

Thus from the above conclusion we can say that The substances generated by the reaction are called products, and their formulas are placed on the right side of the equation.

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The calorimeter constant when 51.203g of water at 55.2c is added to a calorimeter containing 49.783g of water at 23.5c and for the system to equilibrate, the final temperature reached is 37.6c is  9.67J/gc.

Given mass of water (m1) = 51.203g

Temperature of water (T1) = 55.2c

mass of water (m2) = 49.783g

Temperature of water (T2) = 37.6c

the final temperature reached is = 37.6c

We know that specific heat (Q) = mCpΔT where m is mass Cp is latent heat and ΔT is change in temperature.

So Qwater = 51.203 x 4.184 x (23.5 - 55.2) = 6791.9J

Qcalo = 49.783 x Cp x (23.5 - 37.6) = 701.9 x Cp

Given that Qwater = Qcalo

6791.9J = 701.9 x Cp

Cp = 9.67J/gc

Hence the calorimeter constant is  9.67J/gc

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Answer:

B

Explanation:

The student is not able to move the box in D --> 55N, 0N. Since the net force is 0, it means that no force is being applied. So you will choose answer B from your options.

Hope this helps, thank you !!

Answer:

13g

Explanation:

34+10+26=70

70-57=13

13g would complete the equation

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They are classified on the basis of their physical features- Shape and Appearance.

The four basic shapes of bacteria are Coccus (spherical or ovoid), bacillus (rod-like), vibrio (comma-shaped ), and spirilla (spiral or helical shaped).

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♪ ♫ Hope this helps :D

1. D. Absorbing excess carbon dioxide in the atmosphere

2.C. Abnormal warming of the earth

3.D. Organisms in the converted forest areas will lose their natural habitats.

4.D. Tropical rainforests have important functions in the ecosystem

5.C. Loss of habitat of many marine creatures

6.B. Use of sodium cyanide in fishing

1. The important roles of tropical rainforests in the earth's environment: Rainforests are often called the lungs of the planet for their role in absorbing carbon dioxide, a greenhouse gas, and increasing local humidity.

2. If all trees were cut down and burned, the forest's carbon storage capacity would be lost to the atmosphere.

3. The most common pressures causing deforestation and severe forest degradation are agriculture, unsustainable forest management, mining, infrastructure projects and increased fire incidence and intensity.

4. Need to conserve and protect tropical rainforests: The most important function of forests is that it produces mass amounts of oxygen as a by-product of photosynthesis. ... Forests also prevent soil erosion and keep soil pollution in check.

5. If coral reefs are destroyed: Sea life has the most to lose. Coral reefs cover less than 1% of the ocean floor. But, they provide an essential ecosystem for a quarter of all marine life.

6. Pollution, overfishing, destructive fishing practices using dynamite or cyanide, collecting live corals for the aquarium market, mining coral for building materials, and a warming climate are some of the many ways that people damage reefs all around the world every day.

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1-methylcyclohexene is expected to be formed in greater amounts because of it's more thermodynamic stability than 3-methylcyclohexene.

Methylcyclohexane is a colorless liquid with a faint, benzene-like odor that is used as a solvent and to manufacture organic chemicals. Flash point of Methylcyclohexane is 25 °F  and density is 0.811 g/mL at 20 °C. 1-Methylcyclohexanol falls in a tertiary alcohol category.

Cyclohexene is a hydrocarbon with the formula of C₆H₁₀. This cycloalkene is a colorless liquid but with a sharp smell and is an intermediate in various industrial processes. Cyclohexene is not very stable for long term storage with exposure to light and air as it forms peroxides.

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1. Short time scale change on the ecosystem:

One example of a short time scale change on the ecosystem is the oil spill that occurred in the Gulf of Mexico in 2010. This disaster resulted in the contamination of the water, which ultimately led to the death of marine life and affected the food chain. The spill had a significant impact on the fishing industry in the region and took years to recover from.

2. The law of unintended consequences:

The law of unintended consequences states that actions always have consequences that are not anticipated. One example is the use of pesticides in farming. Although the use of pesticides reduces the risk of crop damage and increases yield, it also has unintended consequences. The pesticides can harm other organisms that come into contact with the crops, including bees and other beneficial insects that play a critical role in pollination.

3. Disposal sanitary method:

The disposal of waste is a significant problem in today's world, and sanitary landfill is a popular method of disposal. It involves the burial of waste in a landfill that is lined with materials that prevent leaching of harmful chemicals into the soil. This method of disposal is effective but has disadvantages. It produces greenhouse gases and requires large amounts of land.

4. Causes of Acid Rain:

The causes of acid rain include emissions from industrial activity, power generation, and transportation. These emissions release sulfur dioxide and nitrogen oxides, which react with the atmosphere to form acid rain. Acid rain has significant consequences for aquatic life and forests, as well as buildings and infrastructure.

5. Greenhouse gases:

Greenhouse gases are gases that trap heat in the atmosphere, causing the earth's temperature to rise. Examples include carbon dioxide, methane, and water vapor. Greenhouse gases are primarily produced by human activity, including transportation, industrial processes, and deforestation. The increase in greenhouse gas concentrations has resulted in climate change.

6. Effect of Ozone problem on Human:

The ozone layer is essential because it absorbs harmful UV rays from the sun. The depletion of the ozone layer due to human activity has resulted in an increase in skin cancer and other health problems. Exposure to UV radiation can also cause damage to the eyes and the immune system.

7. Genetic Mutation causes:

Genetic mutations can occur naturally or due to human activity, including exposure to radiation, chemicals, and toxins. Genetic mutations can cause health problems, including cancer and developmental disorders. Mutations can also have positive effects, such as improving immunity to certain diseases.

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Answer:

below

Explanation:

First it warms up until it reaches the boiling point temperature ....add more energy and it will begin to boil ...continue adding energy and it will begin to vaporize into steam

Answer:

It evaporates the liquid water.

Explanation:

This energy exists in the form of heat. Evaporation happens when a liquid is heated. For example, as the sun heats water in a puddle, the puddle slowly shrinks. The water seems to disappear, but it moves into the air as a gas called water vapor.

If the equilibrium constant (Kc) has a value of 3.1 × 10⁻⁴ (which is much less than one), we would expect the rate constant (k) to be larger than kr.

Matching the words to the appropriate blanks:

smaller Kc: much less than one

k: larger

kr: much more than zero

Assuming both the forward and reverse reactions are elementary reactions, we can make some general observations about the relationship between the rate constants (k and kr) and the equilibrium constant (Kc).

The equilibrium constant (Kc) is related to the rate constants of the forward (k) and reverse (kr) reactions through the equation:

Kc = k/kr

Comparing the values, we can draw the following conclusions:

If Kc is much less than one (<<1), then the value of k is larger than kr. This implies that the forward reaction is faster than the reverse reaction, leading to a higher rate constant (k) compared to kr.

If Kc is much larger than one (>>1), then the value of kr is larger than k. This implies that the reverse reaction is faster than the forward reaction, resulting in a higher rate constant (kr) compared to k.

If Kc is much closer to one, there is no definitive conclusion about the relationship between the rate constants. We would need specific numerical values of Kc, k, and kr to make further determinations.

Therefore, based on the given information, if the equilibrium constant (Kc) has a value of 3.1 × 10⁻⁴ (which is much less than one), we would expect the rate constant (k) to be larger than kr.

Matching the words to the appropriate blanks:

smaller Kc: much less than one

k: larger

kr: much more than zero

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The energy are there in one photon of orange light whose wavelength is 630nm is  \(3.15401\times10^{-19}\) Joules.

W=c/v, c=speed of light, v=frequency

\(6.3 \times 10^-7=3 \times 10^8/v\)

\(v=3 \times 10^8 / 6.3 \times 10^-7\)

\(v=4.76 X 10^14 Hz\)-frequency of the yellow light.

E=hv, h=Planck's constant,

\(E=(4.76 \times 10^14)Hz \times 6.62607×10^-34 J s\)

\(E=3.15401\times10^{-19}\) Joules- the energy of a single photon of yellow light.

Planck's constant or Planck's constant, is a fundamental physical constant of quantum mechanics. The constant gives the ratio of the energy of the photon to its frequency, and for mass-energy equivalent, the ratio of mass to frequency.

In quantum mechanics, energy is exchanged and absorbed in certain amounts called quanta. The Planck constant is a number that defines the amount of energy in these quantities and expresses how small things can be. Learn more about Planck's constant in this infographic.

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Answer:

Single displacement (Substitution)

Explanation:

The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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Answer:

A balanced ionic equation shows the reacting ions in a chemical reaction. These equations can be used to represent what happens in precipitation reactions or displacement reactions.

Precipitation reactions

In a typical precipitation reaction, two soluble reactants form an insoluble product and a soluble product.

For example, silver nitrate solution reacts with sodium chloride solution. Insoluble solid silver chloride and sodium nitrate solution form:

AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)

The Na+ ions and NO3- ions remain separate in the sodium nitrate solution and do not form a precipitate. Ions that remain essentially unchanged during a reaction are called spectator ions.This means these can be ignored when writing the ionic equation. Only how the solid silver chloride forms is needed to be shown:

Ag+(aq) + Cl-(aq) → AgCl(s)

In a balanced ionic equation:

the number of positive and negative charges is the same

the numbers of atoms of each element on the left and right are the same

Displacement reactions

Displacement reactions take place when a reactive element displaces a less reactive element from one of its compounds.

A common type of displacement reaction takes place when a reactive metal reacts with the salt of a less reactive metal. For example, copper reacts with silver nitrate solution to produce silver and copper(II) nitrate solution:

2AgNO3(aq) + Cu(s) → 2Ag(s) + Cu(NO3)2(aq)

In this reaction, the NO3- ions remain in the solution and do not react - they are the spectator ions in this reaction. So, they can be removed from the ionic equation:

2Ag+(aq) + Cu(s) → 2Ag(s) + Cu2+(aq)

Question

Explain why this ionic equation is balanced:

Ba2+(aq) + SO42-(aq) → BaSO4(s)

Hide answer

There are the same numbers of atoms of each element on both sides of the equation. The total charge on both sides is also the same (zero).

Question

Balance this ionic equation, which represents the formation of a silver carbonate precipitate:

Ag+(aq) + CO32-(aq) → Ag2CO3(s)

Hide answer

2Ag+(aq) + CO32-(aq) → Ag2CO3(s)

Question

Balance this ionic equation, which represents the displacement of iodine from iodide ions by chlorine:

Cl2(aq) + I-(aq) → I2(aq) + Cl-(aq)

Hide answer

Cl2(aq) + 2I-(aq) → I2(aq) + 2Cl-(aq

Explanation:

this will help, I used this for my work x

AgNO₃ (aq) + NaCl (aq) → AgCl (s) + NaNO₃(aq) is the complete chemical equation taking place between the 2 reactants.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

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The steps that can be used as a rationale for the absence of Ag in an unknown solution (but with Pb²⁺ present) in a chemical analysis experiment are: a, b, d, e, and h.

Steps (a), (b), (d), (e), (f), and (g) can be used as a rationale for the absence of Ag in an unknown solution with Pb²⁺ present in a chemical analysis experiment. The lack of yellow precipitate with KyCrO, no blackening of the white solid with NaOH and SnCl₂, and the absence of a white precipitate with 6M HCl suggest the absence of Ag.

The presence of a light blue decantate in step 1-A and the lack of dark blue solution after the addition of 15M NH₃ further support this conclusion. Additionally, the absence of a white precipitate in step 2-B and the lack of reddish-brown precipitate after adding KFe(CN)₆⁻ also indicate the absence of Ag in the unknown solution.

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--The complete question is, Which step(s) can be used as a rationale for the absence of Ag in an unknown solution (but with Pb²⁺ present) in a chemical analysis experiment? Select all that apply:

a. A yellow precipitate did not form when KyCrO was added in step 1-C.

b. The white solid did not turn black upon addition of NaOH and SnCl2.

c. The presence of a light blue decantate in step 1-A.

d. All of the white precipitate from step 1-A dissolved in hot water.

e. A lack of dark blue colored solution after addition of 15 M NH3.

f. A white precipitate did not form in step 2-B.

g. A reddish brown precipitate did not form after adding K Fe(CN)6-

h. The white precipitate from step 1-B dissolved in 6 M NH3 and then reformed when 6 M HNO3 was added.

Note: The question is referring to a specific chemical analysis experiment, where the absence of Ag needs to be justified in an unknown solution with the presence of Pb²⁺.--

The formula for the strongest conjugate base is HCO₃⁻ (hydrogen carbonate).

The chemical formula for the most efficient conjugate base is HCO₃⁻, which refers to the compound hydrogen carbonate. When we analyze the relative acidic strength of Hf, H₂CO₃, and hydrogen sulfide (H₂S), we find that F⁻ has the lowest relative acidic strength. Since we already know that strong acids have the weakest conjugate bases, this leads us to the conclusion that F⁻ is the weakest conjugation base.

As a result, HCO₃⁻ possesses an effective conjugate base. Hydrogen carbonate is an intermediate form that results from the deprotonation of H₂CO₃. It is also known as bicarbonate, and it is amphoteric in its natural state. Bicarbonate plays an essential metabolic role in the system that maintains the physiological pH buffering balance.

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Answer: 828.57mL

Explanation:

First and foremost, we need to convert the degree in Celcius to Kelvin, this will be C + 273 = K

Temperature 1 = 0 + 273 = 273K.

Temperature 2 = 75 + 273 = 348K.

We then plug the values gotten into.the formula which will give:

650/273 = x/348

X = (650 × 348) / 273

X = 828.57mL

The volume that the sample will occupy at 75C would be 828.57mL.

Eutrophication of a lake is the process of D. rapid increase in the amount of dead and decaying plant matter in the lake as a result of excessive plant growth.

Eutrophication occurs when a lake becomes overly enriched with nutrients, such as nitrogen and phosphorus, typically from human activities like agricultural runoff or sewage discharge. These excess nutrients lead to an overgrowth of algae and aquatic plants in the lake, which is known as excessive plant growth.

As these plants die and decay, the process consumes oxygen, resulting in a rapid increase in the amount of dead and decaying plant matter. This leads to a decrease in dissolved oxygen levels in the lake, which can have detrimental effects on the ecosystem, including fish kills and the loss of biodiversity.

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Answer:1.96 grams per liter

Explanation:To find density you have to divide mass by the volume d=m/v

Now you need to find the mass of the carbon dioxide by 153.77- 144.85= 8.92 grams

Finally all you do is 8.92/4.55= 1.96 grams per liter

A balloon weighing 144.85 g is filled with carbon dioxide and reweighed. The weight of the balloon plus gas is 153.77 g. The volume of the full balloon is 4.55 L the density of carbon dioxide will be 1.96 cm³.

The density of any substance is the amount of the susbtance present at per unit cubic volume of the liquid and it is the ratio of the mass and the volume of the substance and unit will be centimeter cube.

The mass of carbon dioxide = 153.77 g - 144.85 g = 8.92

volume = 4.55 liters.

              density = mass / volume

Substituting the value,

              Density = 8.92 / 4.55 liters.

               Density = 1.96 cm³.

Therefore,  the density of carbon dioxide will be 1.96 cm³ if  A balloon weighing 144.85 g is filled with carbon dioxide and reweighed. The weight of the balloon plus gas is 153.77 g. The volume of the full balloon is 4.55 L

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The half-life of the reaction at 36°C is 19.2 seconds.

We can use the following equation to determine the  half-life of the reaction at 36°C;

\(t_{1/2}\) = ln(2) / k

where \(t_{1/2}\) is the half-life of the reaction and k is the reaction rate constant at the given temperature.

First, we need to find the reaction rate constant at 36°C. We can use the two rate constants given for 30°C and 42°C and the Arrhenius equation;

ln(k₂/k₁) = (-Ea/R) × (1/T₂ - 1/T₁)

where k₁ and k₂ are the rate constants at temperatures T₁ and T₂, Ea will be the activation energy, R is gas constant, and T is temperature in Kelvin.

We can choose 30°C (303 K) as T₁ and 42°C (315 K) as T₂, and solve for ln(k₂/k₁) to get;

ln(k₂/k₁) = (-Ea/R) × (1/T₂ - 1/T₁)

ln(0.0608/0.0202) = (-Ea/8.314 J/(mol×K)) × (1/315 K - 1/303 K)

Ea ≈ 52.7 kJ/mol

Next, we can use the Arrhenius equation to find the rate constant at 36°C (309 K);

k = A × exp(-Ea/RT)

k = 0.0202 s⁻¹ × exp(-52.7 kJ/mol / (8.314 J/(mol×K) × 309 K))

k ≈ 0.036 s⁻¹

Finally, we can use the half-life equation with this rate constant to find the half-life at 36°C;

\(t_{1/2}\)= ln(2) / k

\(t_{1/2}\) = ln(2) / 0.036 s⁻¹

\(t_{1/2}\) ≈ 19.2 s

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Hg⁺ with I⁻ forms HgI

Hg⁺ with S²⁻ forms Hg₂S

Hg⁺ with CO₃²⁻ forms Hg₂CO₃

K⁺ with I⁻ forms KI

K⁺ with S²⁻ forms K₂S

K⁺ with CO₃²⁻ forms K₂CO₃

Answer:

1.875 dm^3

Explanation:

M = moles of solute ÷ volume of solution

M =11.25 x 6

  = 1.875 dm^3

2L is the correct answer .

HOW TO CALCULATE ??

                      Molarity (M)            = 6

     On puting values and solving we get , V = 1.875 L ≈ 2L

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