Can you help with these two plz? Number a and b if you can do c and d for me that would be great as well!

Answer:

42.9 megabytes

Step-by-step explanation:

251 megabytes × 17.1% = 42.921  ≅ 42.9 megabytes (Rounded to the nearest tenth)

The following equation can be used to describe isotope decay: \(N(t) = N₀e^(kt) (kt)\)where: The quantity of thulium-167 extant at time t is denoted by N(t) (in days).

N0 is the starting concentration of thulium-167 (in grams). decay constant is denoted by k. The natural logarithmic base is e. (approximately 2.71828). We may utilise the stated decay rate of -0.75 to obtain the constant k. k = ln(1 - 0.75) / (-1) (-1) k = 0.2877 As a result, the equation for thulium-167 decay is: N(t) =\(N₀e^(0.2877t)\) (0.2877t) We'd want to know how long it takes for 500 g of the isotope to decay toequation can be used to describe 250 g. We'll refer to this as t1. We may The following equation can be used to describe isotope decay.

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Answer:

25%

Step-by-step explanation:

Answer:

20 rolls: 10.5

40 rolls: 20.5

Step-by-step explanation:

next one is C

The average would approach a set value.

это вопрос 10 класса? Вопрос старшеклассника??

Answer: I think its reflected

Step-by-step explanation:

Given the expression:

You need to expand it in order to find an equivalent expression.

It is important to remember the Sign Rules for Multiplication:

Now you have to apply the Distributive Property in order to expand the expression. You get:

Hence, the answer is: Last option.

Answer:

There are 245 expected defective chips in the batch

Step-by-step explanation:

From the question, we have that in a batch of computer chips, it is expected that a third is defective

Now, in this present batch, there are 735 chips

The number of defective chips is a third of this

Thus, we have the number of defective chips as;

1/3 * 735 = 245 chips

Answer: B, C, D are your answers!

Step-by-step explanation:

The statements about the local maximums and minimums for the given function that are true would be; B, C, and D.

To find the minimum of a continuous and twice differentiable function f(x), we can first differentiate it concerning x, and equating it to 0 will give us critical points.

Putting those values of x in the second rate of function, if results in negative output, then at that point, there are maxima. If the output is positive then it's minima and if it's 0, then we will have to find the third derivative (if it exists), and so on.

The maximum of a continuous and twice differentiable function f(x), we can firstly differentiate it concerning x, and equating 0 will give us critical points.

The statements about the local maximums and minimums for the given function are true;

B Over the interval [2, 4], the local minimum is -8.

C Over the interval [3, 5], the local minimum is -8.

D.Over the interval [1,4], the local maximum is 0.

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The maximum amount you can earn is $540

a. y = 13.50x , 10 <= x <= 40
b. x = 10, y = 135; x = 20, y= 270; x = 30, y = 405; x = 40, y = 540
c. Domain: 10 <= x <= 40; Range: 0 <= y <= 540
d. The minimum amount you can earn in a week with this job is $135. The maximum amount you can earn is $540.

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The distance between the first and second dark lines in the interference pattern of a double-slit experiment can be calculated using the formula for fringe separation or fringe width:

y = (λ * L) / d

where:

y = fringe separation (distance between consecutive dark lines)

λ = wavelength of light used

L = distance between the double slits and the screen (also known as the distance of the screen from the slits)

d = distance between the two slits (also known as the slit spacing)

Given:

λ = 550 nm (or 550 x\(10^-9\) m) (converted from 550 nm to meters)

L = 35.0 cm (or 35.0 x \(10^-2\)m) (converted from 35.0 cm to meters)

d = 1.80 μm (or 1.80 x \(10^-6\) m) (converted from 1.80 μm to meters)

Plugging these values into the formula, we get:

y = (550 x \(10^-9\) m * 35.0 x \(10^-2\) m) / (1.80 x \(10^-6\) m)

y = 0.0107 m

So, the distance between the first and second dark lines in the interference pattern is approximately 0.0107 meters.

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Given:

\(OA=3\) units

\(OA'=9\) units

To find:

The scale factor of the dilation.

Solution:

From the given figure it is clear that the center of dilation is point O. Point A' is the image of point A. So,

\(\text{Scale factor}=\dfrac{OA'}{OA}\)

Putting the given values, we get

\(\text{Scale factor}=\dfrac{9}{3}\)

\(\text{Scale factor}=3\)

Therefore, the scale factor of the dilation is 3.

The probability of having, at most, 9 girls, is 0.9515

The probability that a random baby is a girl is:

p = 0.5

And the probability that a random baby is a boy is:

q = 0.5

Then the probability that, at most, 9 out of 11 babys are girls, is given by:

1 - p(10) - p(11)

Where P(10) is the probability that 10 of the babies are girls and p(11) is the probability that the 11 babies are girls.

p(10) = C(11, 10)*(0.5)^10*(0.5)^1 = C(11, 9)*(0.5)^11

Where C(11, 10) is the combinations of 10 elements that we can make with a set of 11 elements, such that:

C(11, 10)=  11!/(11 - 10)!*10! = 11

Replacing that, we get:

P = 11*(0.5)^11 = 0.0054

p(11) = C(11, 11)*0.5^11 = 1*0.5^11 = 0.0005

Then the probability is:

P = 1 - 0.0054 - 0.0005 = 0.9515

The probability of having, at most, 9 girls, is 0.9515

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Answer:

Your answer is D.

Step-by-step explanation:

Using a Desmos Graphing calculator to graph that two equations.

Looking at the equation we look at the less/greater than or equal to shade the area.

I graph it seperately then added it together.

Answer:

Kami sold 28 large figurines

Step-by-step explanation:

L = number of large figurines

S = number of small figurines

L+S = 70   since he sold 70 figurines

12L  = 8S  since the amount  of money  collected for the large figurines is equal to the amount of money for the small figurines

L+S = 70  

12L  = 8S

Divide by 8

12/8 L = S    

3/2 L = S

Substitute this into the first equation

L+S = 70

L + 3/2 L = 70

Get a common denominator

2/2 L + 3/2L = 70

5/2 L = 70

Multiply each side by 2/5

2/5 * 5/2 L = 70 * 2/5

L = 28

Kami sold 28 large figurines

Answer:

x-intercept: -(\(\frac{35}{9}\),0)

y-intercept: (0,-3)

Step-by-step explanation:

Answer:

One

Step-by-step explanation:

Took the test!

Answer:

ONE TRIANGLE

Step-by-step explanation:

TOOK TEST

The 80% confidence interval estimate for the average browsing time is approximately 12.648572 minutes to 14.548572 minutes.

To construct an 80% confidence interval estimate of the average browsing time for the population of crownfashion.com visitors this week, we can use the following formula:

Confidence Interval = \(\bar{X}\) ± Z \(\times\)  (σ/√n)

Where:

\(\bar{X}\) is the sample mean (average browsing time) = 13.6 minutes,

Z is the Z-score corresponding to the desired confidence level (80% confidence level corresponds to a Z-score of 1.28),

σ is the population standard deviation = 5.2 minutes,

n is the sample size = 49.

Plugging in these values, we can calculate the confidence interval as follows:

Confidence Interval = 13.6 ± 1.28 \(\times\) (5.2/√49)

Simplifying the expression:

Confidence Interval = 13.6 ± 1.28 \(\times\) (5.2/7)

Confidence Interval = 13.6 ± 1.28 \(\times\) 0.742857

Confidence Interval = 13.6 ± 0.951428

The lower bound of the confidence interval is 13.6 - 0.951428 = 12.648572, and the upper bound is 13.6 + 0.951428 = 14.548572.

Therefore, the 80% confidence interval estimate for the average browsing time is approximately 12.648572 minutes to 14.548572 minutes.

The margin of error indicated by the interval is half of the width of the confidence interval, which is (14.548572 - 12.648572) / 2 = 0.95 minutes.

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As per the median, the set of data that fulfilling Marjane's requirement is 24, 25, 25, 25, 26, 26 (option c).

In statistics, data is a collection of numbers or values that represent a particular phenomenon. One way to measure central tendency, or the typical or representative value of the data, is through the median and the mode.

The median is the middle value when the data is arranged in numerical order, and the mode is the value that appears most frequently.

The third set of data is 24, 25, 25, 25, 26, 26.

The median is the middle value, which is also (25+25)/2 = 25.

The mode is the value that appears most frequently, which is 25.

Therefore, the mode and median are the same, fulfilling Marjane's requirement.

Therefore, the correct option is (c).

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The domain of the function is x < 2 and it is discontinuous at x = 2

The domain of a function is the range of input values to the function.

Given that the above function f(x) = √[(x² + 1)/(2 - x)]

The domain of the function is the range of values of x that make the denominator greater than zero

So, the domain is √(2 - x) ≥ 0

2 - x ≥ 0

2 ≥ x

x ≤ 2

So, the function is valid for x < 2 and discontinuous at x = 2 since at x = 2, √(2 - x) = √(2 - 2) = 0

So, we see that the function is valid for x < 2 and discontinuous at x = 2

So, the domain of the function is x < 2 and it is discontinuous at x = 2

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Answer:

A

Step-by-step explanation:

the function for M is y=5x+1 and its rate of change is 2 off of P

Answer:

-3x-18

Step-by-step explanation:

The expression -3(x+6) means that -3 is multiplied with x and 6 in the brackets so the answer would be

\(-3x-18\)

Answer:

Given

height of photo = h

Width = 6+3h

Perimeter = 284

Find

Height of the photo

Explanation

As we see the photo is in the shape of rectangle ,

and we know that perimeter of rectangle = 2( L + B)

so , according to the question

width = 3h + 6 = 3*34 + 6 = 108

Final Answer

Therefore , the height of the photo is 34 in. and width is 108 in.

Answer:

60%

Step-by-step explanation:

If the standard deviation is 1.538, then the difference between the mean price of used cars sold at each dealership is approximately 5.07 (1.538 x 3.3) times the variability.

The variability at each dealership, measured by standard deviation, is 1.538.

To determine how many times the difference between the mean price of used cars sold at each dealership is, we need to use a statistical measure called the coefficient of variation (CV).

The CV is calculated by dividing the standard deviation by the mean, and multiplying by 100 to get a percentage. In this case, the CV is approximately 3.3%.

This means that the difference between the mean price of used cars sold at each dealership is about 3.3 times the standard deviation or variability.

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The inequality that represents the cost, c, that Mr. Daniels can spend on the class trip is; c < 300

We are told that;

Mr. Daniels is organizing a class trip.

Mr. Daniels wants to spend less than $300

Thus, if the cost that Mr. Daniels can spend on the class trip is given as c, then it means that c has to be less than the amount which he wants to spend which is $300.

Thus, since c has to be less than $300, then it means that the inequality to be used would be a less than sign which can be expressed as;

c < 300

Thus, we conclude that it is the required inequality.

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Based on the information provided, it can be concluded it will take the painter 877.5 minutes to paint 75% of the pyramid.

Let's calculate the surface:

Surface area: Base + 1/2 perimeter of the base x slant height

Surface area: (50x50) + 1/2 (50x4) (40)

Surface area:  2500 + 0.5 x 200 x 40

Surface area: 2500 + 4000

Surface area: 6500

Calculate the 75%

6500 / 100 x 75 = 4875

And now let's divide this surface by the painting rate

4875 / 100 = 48-75 x 18 = 877.5 minutes

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360º for any convex polygon

We need to compare the cash flows of machines A and B using the concept of Capital Cost (CC) analysis and a minimum acceptable rate of return (MARR) of 10%.

For machine A, the CC is not provided in the question. To determine the CC for machine A, we need additional information such as the initial investment cost and the expected cash inflows and outflows over the machine's useful life. Similarly, for machine B, the CC is not provided in the question.

We need additional information about the initial investment cost and the expected cash inflows and outflows over the machine's useful life to calculate the CC for machine B. Without the CC values, we cannot determine which machine to select based on CC analysis. To make a decision, we need more information.

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If after the plumber has worked alone for 3 hours, his apprentice joins him and working together they complete the job 4 hours later, it would take the plumber 9 hours to do the entire job by himself.

Let's start by assigning some b to represent the rate at which each person works. Let's say that the plumber's rate is P (in units of job per hour) and the apprentice's rate is A (also in units of job per hour). Since the plumber works twice as fast as the apprentice, we can write:

P = 2A

Next, let's think about how much work can be done in a certain amount of time. If the plumber works alone for 3 hours, he completes 3P units of work. When the apprentice joins him, they work together for another 4 hours to complete the entire job, which is a total of 7 hours of work. So, the amount of work done in those 4 hours is:

4(P + A)

We also know that the total amount of work is 1 (since it's one complete job). Putting this all together, we can write an equation:

3P + 4(P + A) = 1

We can simplify this to:

7P + 4A = 1

But we also know that P = 2A, so we can substitute that in:

7(2A) + 4A = 1

Simplifying this, we get:

18A = 1

So, A = 1/18. This means that the apprentice can complete 1/18 of the job in one hour. Since the plumber works twice as fast, he can complete 2/18 of the job (or 1/9) in one hour.

To find out how long it would take the plumber to do the entire job by himself, we can use the formula:

Time = Work / Rate

The entire job is 1, and the plumber's rate is 1/9. So:

Time = 1 / (1/9) = 9 hours

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Using strong induction, we can prove that the square root of -2 is irrational by showing that it cannot be expressed as a fraction of coprime odd integers.

To prove that √-2 is irrational using strong induction, we need to show that for any natural number n, if the square root of -2 can be expressed as a fraction a/b, where a and b are coprime integers, then a and b must be odd.

We can start by using the base case, n = 1. Assume that √-2 can be expressed as a fraction a/b where a and b are coprime integers. Then, we have

√-2 = a/b

Squaring both sides gives

-2 = a^2/b^2

Multiplying both sides by b^2 gives

-2b^2 = a^2

This implies that a^2 is even, and therefore a is also even. We can express a as 2k for some integer k, which means

-2b^2 = (2k)^2

Simplifying, we get

-2b^2 = 4k^2

Dividing both sides by -2 gives

b^2 = -2k^2

This implies that b^2 is even, which means that b is also even. However, this contradicts our assumption that a and b are coprime integers. Therefore, √-2 cannot be expressed as a fraction a/b where a and b are coprime integers.

Now, let's assume that for all n ≤ k, the square root of -2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd. We want to prove that this also holds for n = k+1.

Assume that √-2 can be expressed as a fraction a/b where a and b are coprime integers with a and b odd. Then, we have

√-2 = a/b

Squaring both sides gives

-2 = a^2/b^2

Multiplying both sides by b^2 gives

-2b^2 = a^2

This implies that a^2 is even, and therefore a is also even. We can express a as 2k for some integer k, which means

-2b^2 = (2k)^2

Simplifying, we get

-2b^2 = 4k^2

Dividing both sides by -2 gives

b^2 = -2k^2

This implies that b^2 is even, which means that b is also even. However, this contradicts our assumption that a and b are coprime integers with a and b odd. Therefore, √-2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd.

By strong induction, we have proven that for any natural number n, the square root of -2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd. Therefore, √-2 is irrational.

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Answer:

23.4units

Step-by-step explanation:

√(22)²+(8)²

√484+64

√548

23.4