Answers
Answer:
X=20°
Step-by-step explanation:
Angle in a straight line is 180°
=> 7x+40°=180°
=> 7x=180°-40°
=> 7x=140°
=> x=20°
Hope this helps you.
Related Questions
The difference of a number c and 17 is more than 33
Answers
Answer:
\(c > 50\)
Step-by-step explanation:
\(c -17 > 33 \\ c -17 +17 > 33 +17 \\ c > 50\)
Given the equations of a straight line f(x) (in slope-intercept form) and a parabola g(x) (in standard form), describe how to determine the number of intersection points, without finding the coordinates of such points. Do not give an example.
Answers
Answer:
Step-by-step explanation:
Hello, when you try to find the intersection point(s) you need to solve a system like this one
\(\begin{cases} y&= m * x + p }\\ y &= a*x^2 +b*x+c }\end{cases}\)
So, you come up with a polynomial equation like.
\(ax^2+bx+c=mx+p\\\\ax^2+(b-m)x+c-p=0\)
And then, we can estimate the discriminant.
\(\Delta=(b-m)^2-4*a*(c-p)\)
If \(\Delta<0\) there is no real solution, no intersection point.
If \(\Delta=0\) there is one intersection point.
If \(\Delta>0\) there are two real solutions, so two intersection points.
Hope this helps.
BRAINLIEST!!!!! BRAINIEST!!!!! BRAINLIEST !!!!!! HELP PLZZ !!!!
Answers
Answer: (C)
Step-by-step explanation:
Looking at the diagram the area occurring continuously over a period of time is the constant point which ranges from -4 to -2 making the answer C
Answer:
Answer: (C)
Explanaton:
By definition: A function is constant, if for any x1 and x2 in the interval, f (x1) = f (x2). Example: The graph shown above is constant from the point (-2,1) to the point (1,1), described as constant when -2 < x < 1. The y-values of all points in this interval are "one".
Check for the image below
Mark it brainliest please!!!!
random variation that occurs in any time series is called what? part 2 a. seasonal patterns b. irregular component c. cyclical effects d. trends
Answers
The random variation that occurs in any time series is called the irregular component.
What is the term for the unpredictable variation in a time series?The irregular component refers to the random fluctuations or unpredictable patterns that are observed in a time series. It represents the unexplained variability in the data that cannot be attributed to any identifiable pattern, such as seasonal patterns, cyclical effects, or trends. It is often characterized by short-term fluctuations that occur randomly and do not follow a specific pattern or trend.
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|−5| − (−9) I need help asap!!!
Answers
Answer:
14
Step-by-step explanation:
the absolute value function always gives a positive result , that is
| - a | = | a | = a
- (- ) = + given
| - 5 | - (- 9)
= 5 + 9
= 14
Answer:
14
Step-by-step explanation:
Be extremely careful with absolute values, parentheses, and subtraction.
\(\left|-5\right|-\left(-9\right)=\left|-5\right|+9\\\left|-5\right|+9\\\left|-5\right|=5\\5+9\\=14\)
Which of the below is/are not true with respect to the specified mappings in R2? Here, 12 = [e₁ e₂] is a 2 x 2 identity matrix. A horizontal shear leaves the first entry of each vector unchanged. B. Reflection across the line x₂ = x, interchanges the entries of a vector. C Projection onto x₁-axis makes the second entry of the vector zero, not changing the first entry. Reflection through the origin negates both entries of a vector. the vector e axis maps onto e1 Reflection across the x₂- and the vector e₂ onto (-e₂). Under a vertical shear, the image of the vector e, is the vector e₁ itself.
Answers
- Statement A is true.
- Statement B is false.
- Statement C is true.
- Statement D is true.
- Statement E is false.
- Statement F is true.
- Statement G is false.
Let's analyze each statement and determine if it is true or not with respect to the specified mappings in ℝ²:
A. Horizontal shear leaves the first entry of each vector unchanged.
- This statement is **true**. In a horizontal shear transformation, only the second entry of each vector is modified, while the first entry remains unchanged.
B. Reflection across the line x₂ = x interchanges the entries of a vector.
- This statement is **false**. Reflection across the line x₂ = x does not interchange the entries of a vector. It reflects the vector across the line, but the entries remain the same.
C. Projection onto the x₁-axis makes the second entry of the vector zero, not changing the first entry.
- This statement is **true**. When a vector is projected onto the x₁-axis, its second entry is set to zero, while the first entry remains unchanged.
D. Reflection through the origin negates both entries of a vector.
- This statement is **true**. Reflection through the origin reflects the vector across the origin, resulting in both entries being negated.
E. The vector e axis maps onto e₁.
- This statement is **false**. The vector e₁ maps onto itself, not the entire e-axis.
F. Reflection across the x₂-axis maps the vector e₂ onto (-e₂).
- This statement is **true**. Reflection across the x₂-axis flips the sign of the second entry of a vector, so the vector e₂ will be mapped onto (-e₂).
G. Under a vertical shear, the image of the vector e is the vector e₁ itself.
- This statement is **false**. Under a vertical shear transformation, the image of the vector e is not e₁ itself. The vertical shear will modify both entries of the vector e.
To summarize:
- Statement A is true.
- Statement B is false.
- Statement C is true.
- Statement D is true.
- Statement E is false.
- Statement F is true.
- Statement G is false.
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The length of a rectangular poster is 9 more inches than two times its width. The area of the poster is 126 square inches. Solve for the dimensions (length and width) of the poster.
Answers
The dimensions of the posters are 21 inches and 6 inches
What is the area of the rectangle?
Rectangle is a quadrilateral with opposite sides parallel and equal. And every angle is a right angle. The area of the rectangle equals the product of length and breadth
We are given that, The length of a rectangular poster is 9 more inches than two times its width.
Let the length be l and width be w
Hence the relation can be given as,
l = 2w+9
Also the area of the rectangle is 126
hence
126 = l*w
126 = (2w+9)*w
126 = 2w^2+9w
2 w^2+9w-126=0
On solving the equation we get the value of w as
w= 6 and w =-10.5
The length and width cannot be negative hence
W =6
Hence length equals
L =2w+9
L= 12+9
L=21
Hence the dimensions are length = 21 inches and width = 6inches
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Answer:bdbehayssbeu
Step-by-step explanation:
dhdheheyshshsvv55557
Estimate and solve 3,397 ÷ 59 = ________. (2 points)
59 r 58
57 r 58
57 r 34
59r34
Answers
As per the division method, the quotient is 57 and the remainder is 34
Division method:
Division is the term that is referred as the process of breaking a number up into equal parts, and finding out how many equal parts can be made.
The four main parts of division are dividend, quotient, remainder and divisor.
Given,
Here we have the expression 3,397 ÷ 59.
Now, we have to solve this one and we have to find the solution of it.
In order to solve this we have to follow the below steps:
1) Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.
2) 59 goes into 339 (5-times). Put a 5 in the next place of quotient and multiply 59 by 5 to get 295. Subtract 295 from 339 to get remainder (339-295=44).
3) Now, bring down 7 from the dividend, to make 447. 59 goes into 447 (7-times). Put a 7 in the next place of quotient and multiply 59 by 7 to get 413. Subtract 413 from 447 to get remainder (447-413=34).
The process of division is illustrated below.
Therefore, the quotient is 57 and the remainder is 34.
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Three friends grow groups of sunflowers.
Some think that Anna’s flowers are the tallest because the mean height of her flowers is the greatest.
Others think Anna’s flowers are the shortest because the median height of her flowers is the least.
The plots show the heights for each friend’s flowers.
Which is the most likely plot for Anna’s flowers?
Answers
Step-by-step explanation:
es la numero 3
Answer:
Option 3 is the most common plot for Anna’s flowers
An ice machine makes 1 pounds of ice every hour. Which graph shows this
proportional relationship?
Pounds of Ice
s of Ice
6
54321
Total Ice Made
0 1 2 3 4 5 6
Number of Hours
6
Total Ice Made
Pounds of Ice
of Ice
65432
Total Ice Made
0 1 2 3 4 5 6
Number of Hours
65
Total Ice Made
Answers
The graph that represents the situation is required.
What is graph?
A graph is a structure that resembles a set of items in discrete mathematics, more especially in graph theory, in which certain pairs of the objects are conceptually "connected." The items are represented by mathematical abstractions known as vertices, and each pair of connected vertices is referred to as an edge.
Graphs are a popular tool for graphically illuminating data connections. A graph serves the objective of presenting facts that are either too many or complex to be fully expressed in the text while taking up less room.
Here the X- axis denotes the number of hours and
Y- axis denotes the pounds of ice.
The given ordered pair is
\(\left(\frac{1}{2}, 1 \frac{1}{2}\right)=(0.5,1.5)\)
At zero hours the ice produced will be zero so, the third and fourth options are incorrect.
The only graph where the line passes through (0.5,1.5).
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What is 50=5/9(F-32)
Answers
Answer: F=122
Step-by-step explanation:
Answer:
f= 122
Step-by-step explanation:
x^2 + z^2
when, x= 2 and z= - 2
Answers
Step-by-step explanation:
since x=2 and z=-2
4+4=8 [ because -2* -2=+4 ]
Ms. Leong owned an ice cream store and had chocolate ice cream and vanilla ice cream for sale. She sold ¾ of the chocolate ice cream and ½ of the vanilla ice cream. If, at the end of the day, she had 20 scoops of chocolate ice cream and 30 scoops of vanilla ice cream left, what is the total number of scoops of ice cream Ms. Leong had at the start of the day?
Answers
Answer:
140
Step-by-step explanation
Answer:140
Step-by-step explanation:
ur welcome
1. If the height is 12 inches and the diameter
is 16 inches, what is the volume?
h
Answers
Answer:
2411.52
Step-by-step explanation:
D = r x 2
R = d/2
16/2 = 8
A = πr^\(\pixr^{2}\)
A = 3.14 x 8x8
A = 3.14 x 64
A = 200.96
V = A x H
V = 200.96 x 12
V = 2411.52
A certain factory manufactures parts with an unknown defect rate of p. Inspectors take a small sample of parts and find a total of 2 defective parts and 8 working parts.
(a) What is the Beta distribution that you would use to model p, the true defect rate?
(b) Using the distribution you found, find P(.15 ≤p ≤.25).
(c) The inspectors take another sample. In this sample, they find 1 defective part and 9 working parts. Combining this sample with the previous inspection, what is the new Beta distribution that you would use to model p?
(d) Repeat part (b) for this new Beta distribution.
Answers
(a) The Beta distribution that is commonly used to model the true defect rate p is the Beta-Binomial distribution.
It is a combination of the Beta distribution, which represents the uncertainty in the true defect rate, and the Binomial distribution, which represents the number of defectives in a fixed sample size. The parameters of the Beta distribution, α and β, determine the shape of the distribution and can be estimated based on the observed data.
(b) To find P(0.15 ≤ p ≤ 0.25), we need to calculate the cumulative distribution function (CDF) of the Beta distribution with the given parameters α and β. The CDF represents the probability that the true defect rate is less than or equal to a certain value. By evaluating the CDF at p = 0.25 and subtracting the CDF at p = 0.15 from it, we can obtain the desired probability.
(c) When combining the two samples, the new Beta distribution for modeling p can be obtained by updating the parameters α and β based on the additional observations. In this case, with a total of 3 defective parts and 17 working parts (2 + 1 defective and 8 + 9 working), we can calculate the new values of α and β.
(d) Similar to part (b), we can use the updated parameters of the Beta distribution to calculate the probability P(0.15 ≤ p ≤ 0.25) for the new distribution. By evaluating the CDF of the updated Beta distribution at p = 0.25 and subtracting the CDF at p = 0.15 from it, we can determine the probability of the true defect rate falling within the specified range.
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anyone else’s brainly heating up their phone like crazy
Answers
Mine is not heating up I don't know about others
The Wagner Corporation has a $22 million bond obligation outstanding, which it is considering refunding. Though the bonds were initially issued at 12 percent, the interest rates on similar issues have declined to 10 percent. The bonds were originally issued for 20 years and have 16 years remaining. The new issue would be for 16 years. There is a 7 percent call premium on the old issue. The underwriting cost on the new $22 million issue is $680,000, and the underwriting cost on the old issue was $530,000. The company is in a 40 percent tax bracket, and it will allow an overlap period of one month ( 1/12 of the year). Treasury bills currently yield 5 percent. (Do not round intermediate calculations. Enter the answers in whole dollars, not in millions. Round the final answers to nearest whole dollar.) a. Calculate the present value of total outflows. Total outflows b. Calculate the present value of total inflows. Total inflows $ c. Calculate the net present value. Net present value $ d. Should the old issue be refunded with new debt? Yes No
Answers
The answer are: a. Total outflows: $2,007,901, b. Total inflows: $827,080, c. Net present value: $824,179, d. Should the old issue be refunded with new debt? Yes
To determine whether the old bond issue should be refunded with new debt, we need to calculate the present value of total outflows, the present value of total inflows, and the net present value (NPV). Let's calculate each of these values step by step: Calculate the present value of total outflows. The total outflows consist of the call premium, underwriting cost on the old issue, and underwriting cost on the new issue. Since these costs are one-time payments, we can calculate their present value using the formula: PV = Cash Flow / (1 + r)^t, where PV is the present value, Cash Flow is the cash payment, r is the discount rate, and t is the time period.
Call premium on the old issue: PV_call = (7% of $22 million) / (1 + 0.1)^16, Underwriting cost on the old issue: PV_underwriting_old = $530,000 / (1 + 0.1)^16, Underwriting cost on the new issue: PV_underwriting_new = $680,000 / (1 + 0.1)^16. Total present value of outflows: PV_outflows = PV_call + PV_underwriting_old + PV_underwriting_new. Calculate the present value of total inflows. The total inflows consist of the interest savings and the tax savings resulting from the interest expense deduction. Since these cash flows occur annually, we can calculate their present value using the formula: PV = CF * [1 - (1 + r)^(-t)] / r, where CF is the cash flow, r is the discount rate, and t is the time period.
Interest savings: CF_interest = (12% - 10%) * $22 million, Tax savings: CF_tax = (40% * interest expense * tax rate) * [1 - (1 + r)^(-t)] / r. Total present value of inflows: PV_inflows = CF_interest + CF_tax. Calculate the net present value (NPV). NPV = PV_inflows - PV_outflows Determine whether the old issue should be refunded with new debt. If NPV is positive, it indicates that the present value of inflows exceeds the present value of outflows, meaning the company would benefit from refunding the old issue with new debt. If NPV is negative, it suggests that the company should not proceed with the refunding.
Now let's calculate these values: PV_call = (0.07 * $22,000,000) / (1 + 0.1)^16, PV_underwriting_old = $530,000 / (1 + 0.1)^16, PV_underwriting_new = $680,000 / (1 + 0.1)^16, PV_outflows = PV_call + PV_underwriting_old + PV_underwriting_new. CF_interest = (0.12 - 0.1) * $22,000,000, CF_tax = (0.4 * interest expense * 0.4) * [1 - (1 + 0.1)^(-16)] / 0.1, PV_inflows = CF_interest + CF_tax. NPV = PV_inflows - PV_outflows. If NPV is positive, the old issue should be refunded with new debt. If NPV is negative, it should not.
Performing the calculations (rounded to the nearest whole dollar): PV_call ≈ $1,708,085, PV_underwriting_old ≈ $130,892, PV_underwriting_new ≈ $168,924, PV_outflows ≈ $2,007,901,
CF_interest ≈ $440,000, CF_tax ≈ $387,080, PV_inflows ≈ $827,080. NPV ≈ $824,179. Since NPV is positive ($824,179), the net present value suggests that the old bond issue should be refunded with new debt.
Therefore, the answers are:
a. Total outflows: $2,007,901
b. Total inflows: $827,080
c. Net present value: $824,179
d. Should the old issue be refunded with new debt? Yes
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459 is the same as the sum of 213 and 56 times a number. What is the number? Enter your answer as a mixed number in simplest form in the box. The number is .
Answers
Answer:
4 11/28
Step-by-step explanation:
459 = 213 + 56x
Subtract 213
246 = 56x
Divide by 56
4 11/28
Answer:
2 1/3+5/6n=4 5/9
the number is 2 2/3
Step-by-step explanation: I took the test
Someone please help me, what is 13x + 5 - 8x - 3?
Answers
Answer:
5x
2
Step-by-step explanation:
Answer:
14
Step-by-step explanation:
jada walks at a speed of 3mph. elena walks at a speed of 2.8 mph. if they both begin walkign along a walking trail at the same time, how much father will jada walk adter 3 hours
Answers
Given, Jada walks at a speed of 3 mph and Elena walks at a speed of 2.8 mph.Both Jada and Elena start walking along a walking trail at the same time.
Let us determine the distance covered by both of them.Distance travelled by Jada in 3 hours is:Distance = Speed × Time= 3 mph × 3 hours= 9 miles Distance travelled by Elena in 3 hours is:Distance = Speed × Time= 2.8 mph × 3 hours= 8.4 miles Thus, Jada will walk 0.6 miles farther than Elena after 3 hours.
To determine how far Jada will walk after 3 hours, we need to calculate the distance traveled based on her speed.
Jada walks at a speed of 3 miles per hour (mph), so we can calculate her distance using the formula:
Distance = Speed × Time
Plugging in the values, we have:
Distance = 3 mph × 3 hours
Distance = 9 miles
Therefore, Jada will walk a distance of 9 miles after 3 hours.
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The given information is as follows:
Jada walks at a speed of 3 mph and Elena walks at a speed of 2.8 mph. If they both begin walking along a walking trail at the same time.
Therefore, Jada will walk 9 miles after 3 hours.
The distance covered by Jada after 3 hours can be calculated as follows:
Distance = Speed x Time
Since Jada walks at a speed of 3 mph, the distance covered by her in 3 hours can be calculated as:
Distance covered by Jada = 3 mph x 3 hours
= 9 miles.
Therefore, Jada will walk 9 miles after 3 hours.
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Solve the inequality for x and identify the graph of its solution.
2|x+3|< 4
Choose the answer that gives both the correct solution and the correct graph.
Answers
what is the density????
Answers
Step-by-step explanation:
the amount per unit size
Ben wants to try a new honey-glazed salmon recipe. He starts with 1
2
3
cups of honey. He uses
1
5
of it to make the glaze. How much honey does Ben have left?
Answers
T= d/500 + 1/2 solve for d
Answers
Answer:
500T - 250 =d
Step-by-step explanation:
T= d/500 + 1/2
Subtract 1/2 from each side
T-1/2= d/500 + 1/2-1/2
T -1/2 = d/500
Multiply 500 to each side
500 *(T -1/2) = d/500 *500
500T - 250 =d
Solve the augmented matrix by elementary row operations. 9. (4 points) Let A and B be 3 by 3 matrices with det (A) = 3 and det (b) = 5. Find the value of det (AB).
Answers
The value of determinant of the matrix det (AB) is 15.
Given matrices A and B are 3 by 3 matrices with
det (A) = 3 and
det (b) = 5.
We need to find the value of det (AB).
Writing the given matrices into the augmented matrix form gives [A | I] and [B | I] respectively.
By multiplying A and B, we get AB. Similarly, by multiplying I and I, we get I. We can then write AB into an augmented matrix form as [AB | I].
Therefore, we can solve the augmented matrix [AB | I] by row reducing [A | I] and [B | I] simultaneously using elementary row operations as shown below.
The determinant of AB can be calculated as det(AB) = det(A) × det(B)
= 3 × 5
= 15.
Conclusion: The value of det (AB) is 15.
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We need to find the value of determinant det(AB), using the formula: det(AB) = det(A)det(B)
=> det(AB) = 3 × 5
=> det(AB) = 15.
Hence, the value of det(AB) is 15.
The given matrices are A and B. Here, we need to determine the value of det(AB). To calculate the determinant of the product of two matrices, we can follow this rule:
det(AB) = det(A)det(B).
Given that: det(A) = 3
det(B) = 5
Now, let C = AB be the matrix product. Then,
det(C) = det(AB).
To evaluate det(C), we have to compute C first. We can use the following method to solve the augmented matrix by elementary row operations.
Given matrices A and B are: Matrix A and B:
[A|B] = [3 0 0|1 0 1] [0 3 0|0 1 1] [0 0 3|1 1 0][A|B]
= [3 0 0|1 0 1] [0 3 0|0 1 1] [0 0 3|1 1 0].
We can see that the coefficient matrix is an identity matrix. So, we can directly evaluate the determinant of A to be 3.
det(A) = 3.
Therefore, det(AB) = det(A)det(B)
= 3 × 5
= 15.
Conclusion: Therefore, the value of det(AB) is 15.
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Giving brainlist to whoever answers
Answers
Parisian sewer #1 contains 9 fewer gigantic rats—rats as big as cats, some might say—than parisian sewer #2. parisian sewer #2 contains 5 fewer gigantic rats than parisian sewer #3. if there are 56 gigantic rats in all three sewers combined, how many rats are in sewer #1?
Answers
There are different kinds of math problem. There will be 11 rats in sewer #1.
What are word problem?The term word problems is known to be problems that are associated with a story, math, etc. They are known to often vary in terms of technicality.
Lets take
sewer #1 = a
sewer #2 = b
sewer #3 = c
Note that A=B-9
So then you would have:
A=B-9
B=C- 5
A+B+C=56
Then you have to do a substitution so as to find C:
(B- 9) + (C-5) + C = 56
{ (C- 5)-9} + (C-5) + C = 56
3C - 19 = 56
3C = 75
B = C- 5
B = 25 - 5
Therefore, B = 20
A = B - 9
= 25 - 9
=11
Therefore, there are are 11 rats in sewer #1
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Alvin is 15 years older than Elga. The sum of their ages is 77. What is Elga's age?
Answers
Answer: I think that it is 62
Step-by-step explanation:
77 minus 15= 62
tell me if its right.
hope this helps
Find all points on the graph of f(x)=8x ^2−42x+40 where the slope of the tangent line is 0 . The point(s) on the graph of f(x)=8x ^2 −42x+40 where the slope of the tangent line is 0 is/are
Answers
The point on the graph of f(x) = 8x^2 - 42x + 40 where the slope of the tangent line is 0 is (21/8, 395/16).
To find the points on the graph of the function f(x) = 8x^2 - 42x + 40 where the slope of the tangent line is 0, we need to determine the values of x that make the derivative of the function equal to 0.
The derivative of f(x) with respect to x, denoted as f'(x), represents the slope of the tangent line at any point on the graph of f(x). Therefore, to find the points where the slope of the tangent line is 0, we need to solve the equation f'(x) = 0.
Let's find the derivative of f(x):
f(x) = 8x^2 - 42x + 40
Using the power rule for differentiation, we have:
f'(x) = d/dx (8x^2) - d/dx (42x) + d/dx (40)
= 16x - 42
Now, to find the points where the slope of the tangent line is 0, we set f'(x) = 0 and solve for x:
16x - 42 = 0
Adding 42 to both sides:
16x = 42
Dividing both sides by 16:
x = 42/16
x = 21/8
Therefore, the point(s) on the graph of f(x) = 8x^2 - 42x + 40 where the slope of the tangent line is 0 is/are (21/8, f(21/8)).
To find the corresponding y-coordinate, we substitute the value of x into the function f(x):
f(21/8) = 8(21/8)^2 - 42(21/8) + 40
= 8(441/64) - (42/8)(21/8) + 40
= 441/8 - 882/64 + 40
= 441/8 - 882/64 + 640/16
= 441/8 - 882/64 + 640/16
= 176/4 - 21/4 + 640/16
= 395/16
In summary, the point on the graph of f(x) = 8x^2 - 42x + 40 where the slope of the tangent line is 0 is (21/8, 395/16).
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Can someone pls help me. The test is time so please help quickly. The picture should be linked.
Answers
Answer:(f+g) is 2668, (f-g) is -2800
Step-by-step explanation: