can someone help me with this pls

A demand that is completely inelastic is one in which a change in price has no impact on the quantity demanded. The demand curve in this situation is vertical, and there is no demand elasticity.

A demand curve in economics is a graph showing the relationship between the price of a specific good (the y-axis) and the amount of that good that is desired at that price (the x-axis). Demand curves can be applied to both the price-quantity relationship for a single consumer (an individual demand curve) and for all consumers in a specific market.

Demand curves are typically thought to slope downward, as the adjacent image illustrates. This is due to the law of demand, which states that for the majority of goods, the quantity demanded decreases as the price increases. This law does not apply in some peculiar circumstances. These include Veblen goods, Giffen goods, and speculative bubbles, in which consumers are drawn to a commodity if its price increases.

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The measurement which is closest to the  height of this cylinder is: C. 48 in.

Given the following data:

To determine the measurement which is closest to the  height of this cylinder in inches:

Mathematically, the volume of a cylinder is given by the formula:

\(Volume = \pi r^2h\)

Where:

Substituting the given parameters into the formula, we have;

\(8478 = 15^2h\\\\8478 = 225h\\\\h=\frac{8478}{225}\)

Height, h = 37.38 inches.

Closest height = 48 inches.

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The answer to the inequality is expressed as x< 1 and x< -4

Inequalities are mathematical expressions having both sides unequal or rather not equivalent to each other.

Given the inequality;

4x (x+3) < -24

First, expand the bracket

4x² + 12x < -  24

Let's turn to quadratic inequality

4x² + 12x - 24 < 0

Factorize further

4 ( x² + 3x - 4) < 0

4 ( x² + 4x - x - 4) < 0

4 ( x(x + 4) - 1 (x + 4) ) < 0

4(x - 1) ( x + 4) < 0

expand the bracket

4x - 4 < 0

x < 1

And

4x + 16 < 0

x < -4

Thus, the answer to the inequality is expressed as x< 1 and x< -4

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Answer:

Step-by-step explanation:

That's the graph. The slope is -2 and 5 means where the y intersects.

Answer:

Step-by-step explanation:

2(l + w) = P

2l + 2w = P

   2l     = P - 2w

       l = (P - 2w)/2

The ordered pair (-2, 2) satisfies both inequalities y < -x + 1 and y > x.

The correct option is A: (-2, 2).

To determine which ordered pairs satisfy both inequalities y < -x + 1 and y > x, we need to check each pair's coordinates in both inequalities.

Let's test each ordered pair:

A: (-2, 2)

For y < -x + 1: 2 < -(-2) + 1 → 2 < 3 (True)

For y > x: 2 > -2 → 2 > -2 (True)

B: (1, 1)

For y < -x + 1: 1 < -(1) + 1 → 1 < 0 (False)

For y > x: 1 > 1 → 1 > 1 (False)

C: (0, 0)

For y < -x + 1: 0 < -(0) + 1 → 0 < 1 (True)

For y > x: 0 > 0 → 0 > 0 (False)

D: (-1, -1)

For y < -x + 1: -1 < -(-1) + 1 → -1 < 2 (True)

For y > x: -1 > -1 → -1 > -1 (False)

From the above calculations, we can see that only the ordered pair (-2, 2) satisfies both inequalities y < -x + 1 and y > x. Therefore, the correct answer is option A: (-2, 2).

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The complete question:

Which ordered pairs make both inequalities y < -x + 1 and y > x true?

A: (2, 2)

B: (1, 1)

C: (0,0)

D: (-1, -1)

1. The probability of selecting exactly one tank with high-viscosity material is 0.

2. The probability of selecting at least one tank with high-viscosity material is 1.

3. The probability of selecting exactly one tank with high-viscosity material and exactly one tank with high impurities is 0.25.

1. The probability of selecting exactly one tank with high-viscosity material is calculated by the binomial distribution formula, P(X = n) = (nCx)p^x(1-p)^n-x, where n is the number of trials, x is the number of successes, and p is the probability of success. In this case, n = 4, x = 1, and p = 24/24 = 1. Therefore, P(X = 1) = (4C1)1^1(1-1)^4-1 = 0.

2. The probability of selecting at least one tank with high-viscosity material is calculated by the complement rule, P(X > 0) = 1 - P(X = 0). In this case, P(X > 0) = 1 - (4C0)1^0(1-1)^4-0 = 1.

3. The probability of selecting exactly one tank with high-viscosity material and exactly one tank with high impurities is calculated by the binomial distribution formula, P(X = n) = (nCx)p^x(1-p)^n-x, where n is the number of trials, x is the number of successes, and p is the probability of success. In this case, n = 8, x = 2, and p = 24/24 = 1. Therefore, P(X = 2) = (8C2)1^2(1-1)^8-2 = 0.25.

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Mean is average. Multiply total books by the mean to find the total cost:

5x 10 = $50 total.

Subtract the highest and lowest prices to find the total of the remaining 3 books.

50 - 15-6 = 29

The median price was 8, this is the middle number, subtract 8 from 29 to get the cost of the last 2 books:

29-8 =21

Now you need a price lower than the median but higher than the lowest cost so that has to be 7

Subtract 7 from 21 to get the cost of the last book 21-7 = 14

The price of the remaining books is $7 and $14

Answer:

Levi saved 3/5 of the amount he needs to buy a 75 dollar video game. he earns 7.50 per hour working at the pizza shopping town how many hours will he need to work to pay for the rest of the game show all of your work to solve this problem explain the Steps you used! thank you 6th grade form please

Step-by-step explanation:

Answer:

Hello, Jaesuk Sakai Here!! (^^

Step-by-step explanation:

Words in 2 minutes = 90

Words in a minute = 90 / 2

                             = 45

So rate is 45 words/minutes

Happy to Help~ jaesuk sakai!

\(\textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{current amount}\dotfill &\\ P=\textit{initial amount}\dotfill &50\\ t=years\dotfill &15000\\ h=\textit{half-life}\dotfill &5730 \end{cases} \\\\\\ A = 50\left( \frac{1}{2} \right)^{\frac{15000}{5730}}\implies A=50\left( \frac{1}{2} \right)^{\frac{500}{191}} \implies A \approx 8.15\)

After 15,000 years, there wοuld be apprοximately 3.125 grams οf the carbοn-14 sample remaining.

Expοnential decay is a mathematical prοcess that describes the decrease οf a quantity οver time, where the rate οf decrease is prοpοrtiοnal tο the quantity itself. It is characterized by an expοnential functiοn, which decreases at a cοnstant percentage rate οver equal intervals οf time.

Tο sοlve this prοblem, we can use the fοrmula fοr expοnential decay:

A =

where:

Aₒ = initial amοunt

A = amοunt remaining after time t

T = half-life

We are given:

Aₒ = 50 grams (initial amοunt)

T = 5730 years (half-life)

t = 15000 years (time elapsed)

Substituting these values intο the fοrmula, we get:

\(A = 50 * (1/2)^{(15000/5730)\)

A = 50 * 0.0625

A = 3.125 grams

Therefοre, after 15,000 years, there wοuld be apprοximately 3.125 grams οf the carbοn-14 sample remaining.

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Answer:

no

Step-by-step explanation:

because even going back to back it would take you about one or two days

The student with the worst result was student 7, as their mean was the furthest from the expected value and they had the highest standard deviation.

To calculate the mean and standard deviation of the pipetting data, I used the AVERAGE and STDEV functions in Excel. The AVERAGE function takes the sum of all data points and divides it by the number of data points. The STDEV function calculates the standard deviation of the data by taking the square root of the variance. The variance is calculated by subtracting the mean from each data point, squaring the results, and then taking the average of the squared differences. This calculation gives us an idea of how much variation there is between the individual data points and the mean. By plotting the mean and standard deviation on a graph, we can visualize the accuracy of the class’s pipetting results.

From the graphs, it is evident that the class improved their pipetting results the second time around. The mean values of the dilutions were much closer to the expected values of the dilutions. Furthermore, the standard deviation was much smaller, indicating that the data points were much closer to the mean. The student with the worst result was student 7, as their mean was the furthest from the expected value and they had the highest standard deviation.

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To calculate the 90% confidence interval for the average EPS of all industrials listed on the DJIA, we will use the formula:

Confidence interval = sample mean ± (critical value * standard deviation / √sample size)

Step 1: Find the critical value.
Since we want a 90% confidence interval, the corresponding critical value can be obtained from the z-table. The critical value for a 90% confidence level is 1.645.

Step 2: Calculate the margin of error.
The margin of error is given by (critical value * standard deviation / √sample size).
Substituting the values, we get: 1.645 * 0.395 / √9 = 0.29175.

Step 3: Calculate the confidence interval.
The confidence interval is given by the sample mean ± margin of error.
Substituting the values, we get: 1.85 ± 0.29175.

The 90% confidence interval for the average EPS of all industrials listed on the DJIA is (1.55825, 2.14175).

We can be 90% confident that the true average EPS of all industrials listed on the DJIA falls within the range of 1.55825 to 2.14175.

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Answer:

Step-by-step explanation:

Circumference of circle = 7π cm

θ = 2π × 5.5/(7π) = 11/7 radians

The limit of the expression \(f(x) = \frac{x^2 - 12}{x^2 - 3}\)a s x approaches 3 is -1/2

The expression is given as:

\(f(x) = \frac{x^2 - 12}{x^2 - 3}\)

As the variable x approaches 3, the limit is represented as:

\(\lim_{x \to 3} f(x)\)

So, we have:

\(\lim_{x \to 3} = \frac{3^2 - 12}{3^2 - 3}\)

Evaluate the exponents

\(\lim_{x \to 3} = \frac{-3}{6}\)

Evaluate the quotient

\(\lim_{x \to 3} = -\frac{1}{2}\)

Hence, the limit of the expression as x approaches 3 is -1/2

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Answer:

B. 7/3

Step-by-step explanation:

Took the final test and this was the correct answer

a) A function that expresses f(x) is f(x) = 1.5x.

b) A graph of the function is shown in the image below.

c) The domain and range of the function are all real numbers or [-∞, ∞].

Assuming the variable x represent the amount of a transaction and the variable f(x) represent the amount Isabel is charged for the transaction, a linear function charges on each sale by the credit card company can be written as follows;

f(x) = 1.5x

Part b.

In this exercise, we would use an online graphing tool to plot the function f(x) = 1.5x as shown in the graph attached below.

Part c.

By critically observing the graph shown below, we can logically deduce the following domain and range:

Domain = [-∞, ∞] or all real numbers.

Range = [-∞, ∞] or all real numbers.

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Complete Question:

A transaction is positive if there is a sale and negative when there is a return. Each time a customer uses a credit card for a transaction, the credit company charges Isabel. The credit company charges 1.5% of each sale and a fee of 0.5% for returns.

a) Let x represent the amount of a transaction and let f(x) represent the amount Isabel is charged for the transaction. Write a function that expresses f(x).

b) Graph the function.

c) What are the domain and range of the function?

(i) The sequence converges to 0, with a rate of convergence of 2 and a rate constant of 1.

(ii) The sequence converges to 1, with a rate of convergence of 10^-2 and a rate constant of 1.

(i) The given sequence xk = 2^(-k) represents a geometric sequence with a common ratio of 1/2. As k approaches infinity, the terms of the sequence get arbitrarily close to 0. Therefore, the sequence converges to 0. The rate of convergence is 2, indicating that each term is half the value of the previous term, and the rate constant is 1, as the limit of the sequence is 0.

(ii) The sequence xk = 1 + 5×10^(-2k) is also a geometric sequence with a common ratio of 10^(-2). As k approaches infinity, the terms of the sequence approach 1. Therefore, the sequence converges to 1. The rate of convergence is 10^(-2), meaning that each term is a hundredth of the previous term, and the rate constant is 1, as the limit of the sequence is 1.

The convergence of the sequences (iii), (iv), and (v) cannot be determined without further information or calculations.

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To determine a formula for the n-th term of an arithmetic sequence, we need to find the common difference (d) first.

The common difference is the constant value that is added or subtracted to each term to get to the next term.

In this case, we can find the common difference by subtracting the fourth term from the seventh term:

d = a₇ - a₄

d = 31 - 19

d = 12

Now that we have the common difference, we can use it to find the formula for the n-th term of the arithmetic sequence. The formula is given by:

aₙ = a₁ + (n - 1)d

In this formula, aₙ represents the n-th term, a₁ represents the first term, n represents the position of the term, and d represents the common difference.

Since we don't have the first term (a₁) given in the problem, we can find it by substituting the known values for a₄ and d:

a₄ = a₁ + (4 - 1)d

19 = a₁ + 3(12)

19 = a₁ + 36

a₁ = 19 - 36

a₁ = -17

Now we can substitute the values of a₁ and d into the formula to get the final formula for the n-th term:

aₙ = -17 + (n - 1)(12)

Therefore, the formula for the n-th term (aₙ) of the given arithmetic sequence is aₙ = -17 + 12(n - 1).

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The statement "The arithmetic mean is the sum of the quantitative observations divided by the total number of observations" is true.

Arithmetic mean is the average value of a set of numerical values, calculated as the sum of the values divided by the number of values. It is a crucial concept in mathematics and a fundamental aspect of statistical analysis.

Average = (sum of values) / (total number of values)

Formula for Arithmetic Mean: The formula for calculating the arithmetic mean of a set of values can be represented as;

X = (x1 + x2 + x3 +…+ xn) / n

Where; X = Arithmetic mean, x1, x2, x3,…xn = numerical values, n = number of values

Example

Let's say you have the following set of values; {10, 20, 30, 40, 50}

To calculate the arithmetic mean, apply the formula:

X = (10 + 20 + 30 + 40 + 50) / 5= 150/5= 30

Therefore, the arithmetic mean of the set of values {10, 20, 30, 40, 50} is 30.

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The maximum height of the projectile is 66 feet.

The given quadratic equation represents the height of a projectile, y, in feet, at a particular time, t, in seconds.

We can find the maximum height of a projectile using a quadratic equation by applying the formula -b / 2a.Let us consider the given quadratic equation:

y = -16t² + 64t + 2

The maximum height will occur at the vertex of the parabola. The x-coordinate of the vertex is given by:-b / 2a

The coefficient of t² is -16, and the coefficient of t is 64. Therefore, we have:

a = -16

b = 64

The x-coordinate of the vertex is given by:

-b / 2a = -64 / 2(-16) = -64 / (-32) = 2

Therefore, the maximum height occurs when t = 2.To find the maximum height, we need to substitute t = 2 into the quadratic equation:

y = -16t² + 64t + 2

y = -16(2)² + 64(2) + 2

y = -16(4) + 128 + 2

y = -64 + 130

y = 66

The maximum height of the projectile is 66 feet.

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The area of quadrilateral EDFG is approximately 107.38 cm².

As 3DE = 3FC = AB, we can divide square ABCD into nine congruent smaller squares, each with an area of 20 cm² (since the total area of the square is 180 cm²). We can see that quadrilateral EDFG consists of two of these smaller squares and two right triangles.

The area of each of the smaller squares is 20 cm², so the area of both of them together is 40 cm². To find the area of the two right triangles, we need to first find the length of the diagonal of each of these squares. Using the Pythagorean theorem, we can see that the diagonal of each square is:

√(AB² + AB²) = √(2AB²) = AB√2 = 3DE√2

So the diagonal of each square is 3 times the length of DE (or FC), multiplied by the square root of 2. Since DE = FC = AB/3 = 6 cm, the diagonal of each square is:

3DE√2 = 3(6)√2 = 18√2 cm

The height of each right triangle is DE, which is 6 cm, and the base is half of the diagonal of each square, or (18√2)/2 = 9√2 cm. So the area of each right triangle is:

(1/2) × base × height = (1/2) × (9√2) × 6 = 27√2 cm²

Therefore, the area of quadrilateral EDFG is:

2 × area of small squares + 2 × area of right triangles

= 2(20 cm²) + 2(27√2 cm²)

= 40 cm² + 54√2 cm²

≈ 107.38 cm² (rounded to two decimal places)

Therefore, the area of quadrilateral EDFG is approximately 107.38 cm².

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Answer:

x=9/2 or 4.5

Step-by-step explanation:

Answer:

The coordinate pair is (5,4)

Step-by-step explanation:

2x - y = 6 and y = 4.

Find where the two lines intersect

We know the y coordinate is 4.  We need to find the x coordinate

Using the first equation, let y =4 and solve for x

2x-y =6

2x-4 = 6

Add 4 to each side

2x-4+4 = 6+4

2x = 10

Divide by 2

2x/2 = 10/2

x =5

The coordinate pair is (5,4)

Answer:

29 oranges

Step-by-step explanation:

10 divided by 0.34 = 29.41,

but you can't buy have an orange, so 29 oranges. (Atleast not in the USA)

Brainliest??? Please!!!

Answer:

29 oranges

Step-by-step explanation:

u can buy 29 oranges

Answer:

the first one

Step-by-step explanation:

Answer:

(x + 5)² + (y – 2)² = 3

Step-by-step explanation:

In total, there are 5 non-congruent triangles with integer sides that have a perimeter of 12.

The number of such non-congruent triangles can be found by considering all possible combinations of sides that add up to 12.

We can start by finding all possible combinations of two sides, and then adding the third side to make the perimeter equal to 12.

For example, for the two sides with lengths 1 and 11, the third side must be equal to 0, which is not allowed in a triangle.

The combinations of two sides are:

(1, 11), (2, 10), (3, 9), (4, 8), (5, 7), (6, 6).

For the combination (1, 11), the third side cannot be greater than 10, so it is not a valid triangle.

For the combination (2, 10), the third side can have lengths 0, 1, or 2, but none of these values result in a valid triangle.

For the combination (3, 9), the third side can have length 0, 1, 2, or 3. The only value that results in a valid triangle is 3, so there is 1 such triangle.

For the combination (4, 8), the third side can have length 0, 1, 2, or 4. The only value that results in a valid triangle is 4, so there is 1 such triangle.

For the combination (5, 7), the third side can have length 0, 1, 2, 3, or 5. The only value that results in a valid triangle is 5, so there is 1 such triangle.

For the combination (6, 6), the third side can have length 0 or 6. The only value that results in a valid triangle is 6, so there is 1 such triangle.

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