Can someone help me please

Answer:

\(t= 7.67\)

\(t= 10.13s\)

Step-by-step explanation:

Solving (a):

\(H=-16t^2+122t+5\)

Required: Time to hit the ground

This means that H = 0

So, we have:

\(0=-16t^2+122t+5\)

Rewrite as:

\(16t^2-122t-5=0\)

Solve for t using:

\(t= \frac{-b \± \sqrt{b^2 - 4ac}}{2a}\)

\(t= \frac{122 \± \sqrt{(-122)^2 - 4*16*-5}}{2*16}\)

\(t= \frac{122 \± \sqrt{15204}}{2*16}\)

\(t= \frac{122 \± 123.3}{32}\)

Split:

\(t= \frac{122 + 123.3}{32}\) or \(t= \frac{122 - 123.3}{32}\)

\(t= \frac{245.3}{32}\) or \(t= \frac{-1.3}{32}\)

\(t= 7.67\) or \(t= -0.0406\)

Time can not be negative. so: \(t= 7.67\)

Solving (b):

\(h=-16t^2+162t+0.2\)

Required: Time to hit the ground

This means that h = 0

\(0=-16t^2+162t+0.2\)

Rewrite as:

\(16t^2-162t-0.2= 0\)

Solve for t using:

\(t= \frac{-b \± \sqrt{b^2 - 4ac}}{2a}\)

\(t= \frac{162 \± \sqrt{(-162)^2 - 4*16*-0.2}}{2*16}\)

\(t= \frac{162 \± \sqrt{26256.8}}{32}\)

\(t= \frac{162 \± 162.04}{32}\)

\(t= \frac{162 + 162.04}{32}\) or \(t= \frac{162 - 162.04}{32}\)

\(t= \frac{324.04}{32}\) or \(t= \frac{-0.04}{32}\)

Time can not be negative. So:

\(t= \frac{324.04}{32}\)

\(t= 10.13s\)

The largest value that f(4) can possibly be is 29.

The mean value theorem states that for a function f(x) that is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), there exists a number c in the open interval (a, b) such that:

f(b) - f(a) = f'(c)(b - a)

In this case, we are given that f(0) = -3 and that f'(x) ≤ 8 for all values of x. To determine how large f(4) can possibly be, we can use the mean value theorem with a = 0 and b = 4:

f(4) - f(0) = f'(c)(4 - 0)

Substituting the given values:

f(4) - (-3) = f'(c)(4)

f(4) + 3 = 4f'(c)

Since f'(x) ≤ 8 for all values of x, we can say that f'(c) ≤ 8. Therefore:

f(4) + 3 ≤ 4f'(c) ≤ 4(8) = 32

Therefore, we have:

f(4) ≤ 32 - 3 = 29

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The length of the hypotenuse of the triangle is 5 mm.

Given is a right triangle with length of the two legs 4 mm and 3 mm we need to find the measure of the hypotenuse of the right triangle,

Using the Pythagorean theorem, which says that the measure of the hypotenuse of a right triangle is equal to the sum of the square of the two legs,

So,

h = √4²+3²

h = √16+9

h = √25

h = 5

Hence the length of the hypotenuse of the triangle is 5 mm.

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21 is the value of function f(3) .

What is function?

f(x) = 5x + 6

f(3) = 5(3) + 6 = 15 + 6 = 21

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Answer:

$15.60

Step-by-step explanation:

We can solve this problem easily by adding up Miguel's expenses, and then subtracting them from the amount he started with. Be careful, as he pays $4, not $2, in total for bus fare, because he is paying $2 to and from:

\(6.75+3.65+4.00\)

\(=14.40\)

Let's subtract our sum, \(14.40\), from our total, \(30\):

\(30-14.40\)

\(=15.60\)

Miguel has $15.60 left.

Solution:

Given;

Answer:

infinite number of solutions

Answer:

I only see one raffle, but the expected value of one ticket is $2. (I think)

Step-by-step explanation:

Have a nice day!

The expected value E(x) of 1 ticket is $0.40.

To calculate the total amount by the formula;

Amount = Ticket x Value

Raffle 1

Given;

Tickets  = 800

Value = $2 per ticket

Grand ticket = $450 ...for 1

consolation =$100.. for 2

We need to find the expected value of each ticket;

First, we have to calculate the total amount of the 800 tickets

Amount = Ticket x Value

Amount = 800 x 2

Amount = 1600

Next, we have to calculate the total amount of the prizes

Amount = Ticket x Value

Amount = 450 x 200

Amount = 650

The expected value E(x) of 1 ticket is calculated:

E(x) = 650 / 1600

E(x) = $0.40

Thus, the expected value E(x) of 1 ticket is $0.40.

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The study is a randomized controlled trial (RCT) study.

In an RCT study, participants are randomly assigned to either the treatment group or the control group. The treatment group receives the intervention (in this case, one of the two surgery procedures) being studied, while the control group does not receive the intervention.

The participants are then followed to observe the outcome of interest (in this case, the hours to recovery after surgery).

The goal of an RCT study is to determine if the intervention has an effect on the outcome. By randomly assigning participants to the treatment and control groups, any observed differences in the outcome between the two groups can be attributed to the intervention.

This helps to control for other factors that may influence the outcome and reduces the risk of bias in the results.

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Answer:

The answer is D on edg 2020

Step-by-step explanation:

brainliest plz

Answer:

Its D

Step-by-step explanation:

∠2 ≅ ∠4

Answer:

x = - 7

Step-by-step explanation:

The vertex form of a parabola is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

y = - (x + 7)² - 10 ← is in vertex form

with h = - 7 since - (- 7) = + 7

vertex = (- 7, - 10 ) with x- value - 7

The ocean freight charges for the given shipment in Canadian dollars would be approximately 603.25 CAD.

To calculate the ocean freight charges in Canadian dollars for the given shipment, we need to follow these steps:

Step 1: Calculate the volume and weight of each cargo item:

For the skids of Apple:

Volume = 100 cm x 100 cm x 150 cm

= 1,500,000 cm³

= 1.5 m³

Weight = 400 kg each x 2

= 800 kg

For the boxes of Orange:

Volume = 35" x 25" x 30"

= 26,250 cubic inches

= 0.4292 m³

Weight = 100 kg each x 3

= 300 kg

Step 2: Calculate the total volume and weight of the shipment:

Total Volume = Volume of Apples + Volume of Oranges

= 1.5 m³ + 0.4292 m³

= 1.9292 m³

Total Weight = Weight of Apples + Weight of Oranges

= 800 kg + 300 kg

= 1,100 kg

Step 3: Convert the ocean freight rate to Canadian dollars:

Ocean freight rate to Mumbai = $250 USD / m³

Conversion rate: 1 USD = 1.25 CAD (Canadian dollars)

Freight rate in CAD = $250 USD/m³ x 1.25 CAD/USD

= 312.5 CAD/m³

Step 4: Calculate the freight charges for the shipment:

Freight charges = Total Volume x Freight rate in CAD

Freight charges = 1.9292 m³ x 312.5 CAD/m³

= 603.25 CAD

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Answer: 7

Step-by-step explanation:

Answer:

hike 2 = -62

hike 3= -38

hike 4 = -225

Answer:

c

Step-by-step explanation:

This question is based on the trigonometry. Therefore, the correct option is C,  i,e.  \([\dfrac{-\pi}{2} ,\dfrac{\pi}{2}]\) is the range of \(Sin^{-1} x\).

Given:

Function is y = \(Sin^{-1} x\).

We need to determined the range of the function  y = \(Sin^{-1} x\).

As we know that,

Domain of \(Sin^{-1} x\) is −1 ≤ \(Sin^{-1} x\) ≤ 1.

By using the graph of y = \(Sin^{-1} x\) . we would be find the range.

We observe in graph that,

The upper limit of graph of given function is \(+\dfrac{\pi}{2}\).

And, the lower limit of graph of given function is \(-\dfrac{\pi}{2}\).

Thus, the range of  y = \(Sin^{-1} x\) function is \([\dfrac{-\pi}{2} ,\dfrac{\pi}{2}]\).

Therefore, the correct option is C,  i,e.  \([\dfrac{-\pi}{2} ,\dfrac{\pi}{2}]\) is the range of \(Sin^{-1} x\).

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So our final solutions on the given interval are theta = 153.4 degrees and theta = 333.4 degrees.

An equation is a mathematical statement that uses an equal sign (=) to show that two expressions are equal. It typically contains variables, constants, and mathematical operations. The goal of solving an equation is to find the value(s) of the variable(s) that make the equation true. Equations are commonly used in various fields of mathematics, as well as in physics, chemistry, engineering, and many other scientific disciplines.

Here,

To solve the equation tan(theta) = -1/2, we first need to find the angle whose tangent is -1/2. We can do this by using the inverse tangent function (also known as arctan or tan^-1) on a calculator or by using the reference angles for tangent.

Using a calculator, we get theta = -26.6 degrees or theta = 153.4 degrees.

To find all solutions on the given interval 0(degrees) < theta < 360 degrees, we need to add 360 degrees to each solution that is less than 0 degrees and subtract 360 degrees from each solution that is greater than 360 degrees.

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Answer:

11, 6

just do 8 - (-3) and 9 - 3

If lea wants to divide the canvas into sections that contain an area of 3 then Lea can create 81 sections on the canvas.

To find the number of sections Lea can create on the painting canvas, given the length is 3^5 mm, the width is 3^7 mm, and each section has an area of 3^8 mm^2 we should follow the steps given below:

Step 1: Calculate the total area of the canvas by multiplying the length and the width.
\(Total area = (3^5 mm) * (3^7 mm)\)

Step 2: Use the property of exponents that states a^m * a^n = a^(m+n) to simplify the total area.
Total area = 3^(5+7) mm^2
Total area = 3^12 mm^2

Step 3: Divide the total area of the canvas by the area of each section to find the number of sections.
Number of sections = (3^12 mm^2) / (3^8 mm^2)

Step 4: Use the property of exponents that states a^m / a^n = a^(m-n) to simplify the number of sections.
Number of sections = 3^(12-8)
Number of sections = 3^4

Step 5: Calculate the numerical value of 3^4.
Number of sections = 81

Lea can create 81 sections on the canvas.

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Answer:  C $462.50

Step-by-step explanation:

It's $462.50 because since $6 has a higher profit you would want to try and sell more of that product (The football). So $6 times 45 is 270. And the max number of balls the store can have is 80, 80 minus 45 is 35 so there can only 35 baseballs left. 35 times $5.50 is 192.50. Lastly, you add the two products, and you get 462.50.

The maximum profit the store can make from selling footballs and baseballs in a typical month is $462.50.

An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

Example: so

1 + 3x + 4y = 7 is an expression.com

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

33 + 77 – 88 is an expression.

We have,

Let's say the store sells x footballs and y baseballs.

The total number of balls sold can be expressed as x + y ≤ 80.

Also, we know that 35 ≤ x ≤ 45 and 40 ≤ y ≤ 55.

To maximize the profit, the store should sell the maximum number of footballs and baseballs that it can stock.

From the constraints, we see that the maximum number of footballs the store can sell is 45 and the maximum number of baseballs it can sell is 55, which together make a total of 100 balls.

However, this exceeds the 80-ball limit, so we need to adjust the numbers.

Let's say the store sells 45 footballs and y baseballs.

Then, y ≤ 35 since 45 + 35 = 80, which is the maximum number of balls the store can stock.

Similarly, let's say the store sells x footballs and 55 baseballs.

Then, x ≤ 25 since 25 + 55 = 80.

To find the maximum profit, we need to calculate the profit from selling 45 footballs and 35 baseballs, which will give the highest profit among the feasible combinations.

The profit from selling 45 footballs is 45 × $6 = $270.

The profit from selling 35 baseballs is 35 × $5.50 = $192.50.

The total profit is $270 + $192.50 = $462.50.

Therefore,

The maximum profit the store can make from selling footballs and baseballs in a typical month is $462.50.

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Each transformation affects the shape and position of the graph. It is important to carefully consider the order of the transformations and their impact on the equation.

1. Horizontal Shift (c):
If there is a horizontal shift, the equation becomes y = (x - c)^3.
For example, if there is a shift of 2 units to the right, the equation would be y = (x - 2)^3.

2. Vertical Shift (d):
If there is a vertical shift, the equation becomes y = x^3 + d.
For example, if there is a shift of 3 units upwards, the equation would be y = x^3 + 3.

3. Vertical Stretch (a):
If there is a vertical stretch or compression, the equation becomes y = a * x^3.
For example, if there is a vertical stretch by a factor of 2, the equation would be y = 2 * x^3.

4. Reflection (along the x-axis):
If there is a reflection along the x-axis, the equation becomes y = -x^3.
This flips the graph of the original function upside down.

5. Reflection (along the y-axis):
If there is a reflection along the y-axis, the equation becomes y = (-x)^3.
This mirrors the graph of the original function.

6. Combined Transformations:
If there are multiple transformations, we can apply them in the order they are given. For example, if there is a vertical stretch by a factor of 2 and a horizontal shift of 3 units to the right, the equation would be y = 2 * (x - 3)^3.

Remember, each transformation affects the shape and position of the graph. It is important to carefully consider the order of the transformations and their impact on the equation.

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The solution of the quadratic equation is x=5±√35 .

A quadratic equation is given by the equation which can be written in the form ax²+bx +c.

the given quadratic equation is :

x²-10x+25=35

Simplifying the equation we get:

or, x²-10x+25-35=0

or, x²-10x-10=0

Now we will solve the equation by completion squares method:

x²-10x-10=0

or, x²-2×x×5+5²-5²-10=0

or, (x-5)²=35

or, x-5=±√35

or, x= 5±√35

Therefore the solution of the quadratic equation is 5+√35 and 5-√35 .

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Answer:

25k-6

Step-by-step explanation:

I used the info from the question

Various approaches to fractional derivatives and fractional integrals share the goal of generalizing differentiation and integration, but differ in formulation and properties.

Fractional derivatives and fractional integrals are mathematical operations that extend the concepts of differentiation and integration to non-integer orders. These operations have applications in various fields such as physics, engineering, and signal processing.

Different approaches have been proposed to define fractional derivatives and fractional integrals, such as the Riemann-Liouville approach, the Caputo approach, and the Grünwald-Letnikov approach, among others.

These approaches share the common goal of generalizing the notions of differentiation and integration to non-integer orders, allowing for a more flexible and nuanced understanding of rates of change and accumulated effects.

However, the approaches differ in their mathematical formulations, resulting in different properties and interpretations of fractional derivatives and fractional integrals. For example, the Riemann-Liouville approach defines the fractional derivative as a convolution integral, while the Caputo approach combines a fractional derivative with an initial condition.

The choice of approach depends on the specific problem at hand and the desired properties of the fractional derivative or integral. Each approach has its advantages and limitations, and researchers continue to explore and develop new approaches to refine and expand our understanding of these fractional calculus operations.

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Answer:

g(12) = 5

C

Step-by-step explanation:

Since the question asks what would be the answer to the equation if x=12, you just subsitute x for 12 which would be 1/2(12) - 1 which equals 6-1 which would equal 5.

The length of a side of the equilateral triangle is 22 inches.

Let's denote the side length of the equilateral triangle as x inches.

According to the given information, the side length of the square is 2 inches longer than the side length of the triangle, so the side length of the square is (x + 2) inches.

The perimeter of the equilateral triangle is given by P_triangle = 3x inches.

The perimeter of the square is given by P_square = 4(x + 2) inches.

It is also given that the perimeter of the square is 30 inches more than the perimeter of the triangle, so we can set up the following equation:

P_square = P_triangle + 30

Substituting the values of the perimeters, we get:

4(x + 2) = 3x + 30

Simplifying the equation:

4x + 8 = 3x + 30

x = 22

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Answer:

15

Step-by-step explanation:

The correct answer is D. f(x) = 11x - 4 and g(x) = (x + 4)/11

To determine which pair of functions are inverses of each other, we need to check if the composition of the functions results in the identity function, which is f(g(x)) = x and g(f(x)) = x.

Let's test each option:

Option A:

f(x) = x/2 + 15

g(x) = 12x - 15

f(g(x)) = (12x - 15)/2 + 15 = 6x - 7.5 + 15 = 6x + 7.5 ≠ x

g(f(x)) = 12(x/2 + 15) - 15 = 6x + 180 - 15 = 6x + 165 ≠ x

Option B:

f(x) = ∛3x

g(x) = (x/3)^3 = x^3/27

f(g(x)) = ∛3(x^3/27) = ∛(x^3/9) = x/∛9 ≠ x

g(f(x)) = (∛3x/3)^3 = (x/3)^3 = x^3/27 = x/27 ≠ x

Option C:

f(x) = 3/x - 10

g(x) = (x + 10)/3

f(g(x)) = 3/((x + 10)/3) - 10 = 9/(x + 10) - 10 = 9/(x + 10) - 10(x + 10)/(x + 10) = (9 - 10(x + 10))/(x + 10) ≠ x

g(f(x)) = (3/x - 10 + 10)/3 = 3/x ≠ x

Option D:

f(x) = 11x - 4

g(x) = (x + 4)/11

f(g(x)) = 11((x + 4)/11) - 4 = x + 4 - 4 = x ≠ x

g(f(x)) = ((11x - 4) + 4)/11 = 11x/11 = x

Based on the calculations, only Option D, where f(x) = 11x - 4 and g(x) = (x + 4)/11, satisfies the condition for being inverses of each other. Therefore, the correct answer is:

D. f(x) = 11x - 4 and g(x) = (x + 4)/11

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