Answer:
Looks like A but I'm not sure.
Explanation:
dont take my word for it I might be wrong
Answer:
deforestación en el mundo es incontrolable
A car of mass of 1200 kg is driven around a corner of a radius of 45m at 15 ms-1
.
(a) Calculate the acceleration of the car.
(b) Calculate the centripetal force acting on the car.
(c) Explain how the centripetal force is being produced.
Explanation:
w = v/r
= 15/ 45 = 1/3 rads-¹
a = w²r
= 1/9 • 45 = 5 ms-²
F = mv²/r
= 1200• 15• 15/45
= 6000N
The car, when rounding the curve, is pulled towards the center by the friction between it's wheels and the road.
Mr. Ben drove from Town A to Town B. For the first 3 hours, he traveled at an average speed of 60 km/h, and after that, he drove at another average speed of 70 km/h. If the distance between Town A and B is 460 km, what was the total time for the whole journey?
Answer:
First you calculate the distance covered in First 3hrs then calculate the time for the remaining distance then add the total time
Whats the hottest planet in our solar system and why?
Please make the answer simpler thanks!
The greenhouse effect makes Venus roughly 700°F (390°C) hotter than it would be without a greenhouse effect.
From the question The hottest planet in our solar system is : Venus
Characteristics of VenusThe Venus which is the second planet from the sun, it is the hottest planet in the solar system due to the greenhouse effect which makes the Venus to be hotter that Mercury which is closest to the sun. The temperature of venus is set at approximately 700°F
Hence we can conclude that The hottest planet in our solar system is Venus
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A glider on an airtrack is measured to have a momentum of -0.128 kgm/s in the x-direction (i.e., its momentum is directed to the left). If the glider is known to have a mass of 127.8 grams, what is the velocity of the glider?
What's the Solution?
The momentum is directed to the left, the velocity is negative. Therefore, the velocity of the glider is -1.002 m/s to the left.
The momentum of an object is defined as the product of its mass and velocity:
momentum = mass x velocity
In this case, we are given the momentum of the glider, its mass, and its direction of motion. We can use these values to solve for the velocity of the glider.
First, we convert the mass of the glider from grams to kilograms:
mass = 127.8 g = 0.1278 kg
Next, we use the formula for momentum to solve for the velocity of the glider:
momentum = mass x velocity
-0.128 kgm/s = 0.1278 kg x velocity
velocity = (-0.128 kgm/s) / (0.1278 kg)
velocity = -1.002 m/s.
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PLS ANSWER FAST WILL GIVE BRAINLY!!!! ANSWER ONLY IF YOU KNOW!!!!
What is the overall charge of an atom?
Answer:
The nucleus has an overall positive charge as it contains the protons. Every atom has no overall charge (neutral). This is because they contain equal numbers of positive protons and negative electrons. These opposite charges cancel each other out making the atom neutral.
1. Find the acceleration of an object when the force is 5.2 N and the mass is 2.6 x 10kg.
Answer:
F=ma
5.2N=26a
a=5.2÷26=0.2
Answer:
0.2 metre square
Explanation:
acceleration=force/mass
What is a population?
Answer:
:)
Explanation:
Population is how many people or citizens are in that country or continent.
how much work does the electric field do in moving a -7.7µc charge from ground to a point whose potential is 55v higher?
The electric field does -423.85 × 10^-6 J of work in moving the -7.7 µC charge from ground to a point whose potential is 55 V higher.
The work done by an electric field on a charge can be calculated using the equation:
W = qΔV
where W is the work done, q is the charge of the object, and ΔV is the change in potential energy.
For the given situation, q = -7.7 µC and ΔV = 55 V. Thus,
W = (-7.7 × 10^-6 C) × (55 V) = -423.85 × 10^-6 J
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An object’s momentum includes its __________.
Answer: Momentum can be defined as "mass in motion
Explanation:
Which best explains how the coating works?
Glare appears on a computer screen when light from
the surroundings reflects off of the screen's surface.
Some computer screens have a special coating to
reduce glare.
O The coating absorbs light that shines on it and
prevents the light from reflecting.
O The surface of the coating is rough, so light that
shines on it gets scattered in many directions.
O The coating bends light that passes through it and
prevents the light from reaching the user's eyes.
O The surface of the coating allows light from the room
to pass through but blocks the light from the screen.
My
Answer: Glare appears on a computer screen when light from the surroundings reflects off of the screen's surface. Some computer screens have a special coating to reduce glare. Which best explains how the coating works? The surface of the coating is rough, so light that shines on it gets scattered in many directions.
HOPE THIS HELPS IF NOT SORRY
The surface of the coating is rough, so light that shines on it gets scattered in many directions best explains how the coating works.
What is coating?A coating is a protective layer that is put to the surface of an item, The coating can be applied for ornament and jewelry.
Paints are a type of coating that protect the surface of the material and also used for its decoration as well as also used in corrosion prevention.
When any light is to fall on any rough surface in that condition, the light get scattered in many directions.
The surface of the coating is rough, so light that shines on it gets scattered in many directions best explains how the coating works.
Hence, option B is correct.
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Box is kicked (given an initial speed), causing it to slide along a level floor. There is friction acting between the box and floor surfaces. What is true about this motion
Answer:
I would assume that the box slows down due to the frictional force between the floor and the box. In addition, the frictional force points opposite of the boxes motion. As we know, the box was given an initial speed, therefore, having an applied force. Hence, we can conclude that the frictional force opposing the motion of the crate is equal to the applied force but acting in the opposite direction. This frictional force is called static friction. When we increase the applied force (push harder), the frictional force will also increase until it reaches a maximum value.
Hope that helps!
Calculate the total charge Q of a thin plate with the charge density distribution p(x,y) = x²y mC/m². The plate shape is restricted by the lines: y=2-x² and y=2x-1, where x and y are measured in metres. a) Sketch the plate shape. [10 marks] [4 marks] b) Present the total charge through the double integral. c) Reduce the double integral to the repeated integrals and show limits of integration. [6 marks] d) Calculate the integral and present your answer with five significant figures. [20 marks]
a) Sketch the plate shape: we get a shape that resembles a trapezoid.
The plate shape is determined by the lines y = 2 - x² and y = 2x - 1. To sketch the plate shape, we can plot these two lines and shade the region in between them. The intersection points of the lines are found by solving the equations simultaneously:
2 - x² = 2x - 1
Simplifying, we get:
x² + 2x - 3 = 0
Factoring, we have:
(x - 1)(x + 3) = 0
So, x = 1 and x = -3. Plugging these values into the equations of the lines, we find the corresponding y-values:
For x = 1:
y = 2 - (1)² = 1
For x = -3:
y = 2(-3) - 1 = -7
Plotting these points and connecting them with the lines, we get a shape that resembles a trapezoid.
b) Total charge through the double integral:
To find the total charge Q, we need to integrate the charge density p(x, y) over the entire plate. We can express this as a double integral:
Q = ∬ p(x, y) dA
c) Reducing the double integral to repeated integrals: The limits of integration for x are the values of x that define the boundaries of the plate shape, which are -3 to 1.
Since the plate shape is described by the lines y = 2 - x² and y = 2x - 1, we can rewrite the double integral as a repeated integral by integrating with respect to x and y separately:
Q = ∫∫ p(x, y) dy dx
The limits of integration for y are from the lower curve y = 2 - x² to the upper curve y = 2x - 1. The limits of integration for x are the values of x that define the boundaries of the plate shape, which are -3 to 1.
d) Calculating the integral: The total charge Q of the thin plate is approximately 12.4 mC.
Now, we can evaluate the double integral to find the total charge Q:
Q = ∫(-3 to 1) ∫(2 - x² to 2x - 1) x²y dy dx
Performing the inner integral with respect to y first, we get:
Q = ∫(-3 to 1) [x²(y²/2 - y)] from 2 - x² to 2x - 1 dx
Simplifying the inner integral, we have:
Q = ∫(-3 to 1) [(x²/2)(2 - x²) - x²(2x - 1)] dx
Expanding and simplifying further, we get:
Q = ∫(-3 to 1) (x² - x⁴/2 - 4x³ + 2x²) dx
Integrating term by term, we have:
Q = [x³/3 - x⁵/10 - x⁴ + 2x³/3] from -3 to 1
Evaluating the integral at the limits, we get:
Q ≈ 12.4 mC (rounded to five significant figures)
Therefore, the total charge Q of the thin plate is approximately 12.4 mC.
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1. The mass of the Earth is 81 times the mass of the Moon. Using Newton's Law of Gravity, what would the effect of gravitation be if the mass of the Moon were increased by four times and the distance between Earth and
the Moon were cut in half?
Answer:
8 × the gravitational attraction
Explanation:
Hope this helps. :)
4. a.) Which is closer to the Moon-the middle of Earth or the water on t
side of Earth facing the Moon?
or
Answer:
The water on the side of the Earth facing the Moon
Vikram and Shruti are sitting on the back seat of a car, Vikram says that both of us are at rest while Shruti says that both of us are in motion. Then they decide to place their problem before the science teacher. The teacher explained their problem with concerning facts.
Answer:pizza party
Explanation:
A 6. 58 x 103 N upward tension force is exerted on a 521-kg downward-moving freight elevator. Determine the acceleration of the elevator.
To determine the acceleration of the freight elevator, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
Given:
Tension force (F) = 6.58 x 10^3 N (upward)
Mass of the elevator (m) = 521 kg
We need to consider the net force acting on the elevator. Since the tension force is upward and the elevator is moving downward, the net force can be calculated as the difference between the tension force and the force due to the gravitational pull:
Net force (F_net) = Tension force - Force due to gravity
The force due to gravity can be calculated using the equation F_gravity = m * g, where g is the acceleration due to gravity (approximately 9.8 m/s^2).
Substituting the given values, we have:
F_gravity = 521 kg * 9.8 m/s^2
Now we can calculate the net force:
F_net = 6.58 x 10^3 N - (521 kg * 9.8 m/s^2)
Next, we can use Newton's second law to calculate the acceleration (a):
F_net = m * a
Substituting the values:
6.58 x 10^3 N - (521 kg * 9.8 m/s^2) = 521 kg * a
Now we can solve for acceleration:
a = (6.58 x 10^3 N - (521 kg * 9.8 m/s^2)) / 521 kg
Calculating this expression will give us the acceleration of the elevator.
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Can you please answer with clear working out .
During summer, surface temperatures over Arctic sea ice are often above 0
∘
C, with a temperature inversion extending from the surface to altitudes of a few hundred meters. For these conditions, describe the expected sign (positive, negative or zero) and relative magnitude (small or large) of the sensible heat flux H, the latent heat flux H
L
, and the Bowen ratio B.
When the Bowen ratio is low and negative, it means the surface is wet, and the latent heat flux is significant, while the sensible heat flux is minor. Because of Arctic sea ice's nature, the Bowen ratio is expected to be small and negative.
During summer, the Arctic sea ice's surface temperatures are often above 0° C, with a temperature inversion expanding from the surface to altitudes of some hundred meters.
For such conditions, the sensible heat flux H is expected to be positive, while the latent heat flux H L is expected to be small or zero. The Bowen ratio B is expected to be small and negative.
Let us discuss each term in more detail. Sensible heat flux (H):The rate of heat transfer from the Earth's surface to the atmosphere due to the temperature difference is referred to as the sensible heat flux. The earth surface warms up due to solar radiation, and then the warm surface transfers heat to the cooler air. The air then heats up and rises, creating convection currents that aid in the heat transfer process.
Sensible heat flux is positive when heat moves from the surface to the atmosphere.Latent heat flux (H L ):The heat required for a phase transition, such as a liquid converting to a gas, is referred to as latent heat. The energy required to convert a material from one phase to another is referred to as latent heat. Evaporation and transpiration are the two main processes that contribute to the latent heat flux.
Because Arctic sea ice's surface temperature is typically above the melting point of ice during summer, the latent heat flux is expected to be small or zero.
Bowen ratio (B):The Bowen ratio is a measure of the ratio of sensible heat flux to latent heat flux. It's a dimensionless quantity that helps to understand the surface's evapotranspiration efficiency.
When the Bowen ratio is low and negative, it means the surface is wet, and the latent heat flux is significant, while the sensible heat flux is minor. Because of Arctic sea ice's nature, the Bowen ratio is expected to be small and negative.
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1. Sensible heat flux (H) is negative, indicating heat transfer from the surface to the atmosphere.
2. Latent heat flux (H_L) is positive, indicating heat transfer from the atmosphere to the surface through evaporation.
3. Bowen ratio (B) is negative, indicating that the sensible heat flux is larger than the latent heat flux. The magnitude of the Bowen ratio can vary depending on the specific conditions.
In summer, surface temperatures over Arctic sea ice are often above 0°C, and there is a temperature inversion that extends from the surface to altitudes of a few hundred meters.
1. Sensible heat flux (H): The sensible heat flux is the transfer of heat between the surface and the atmosphere due to temperature differences. In this case, the sensible heat flux is expected to be negative. This means that heat is being transferred from the surface (warmer) to the atmosphere (cooler). The magnitude of the sensible heat flux can vary depending on the temperature difference between the surface and the atmosphere, but it is generally larger when the temperature difference is greater.
2. Latent heat flux (H_L): The latent heat flux is the transfer of heat between the surface and the atmosphere due to the evaporation and condensation of water. In this case, the latent heat flux is expected to be positive. This means that heat is being transferred from the atmosphere (warmer) to the surface (cooler) through the process of evaporation. The magnitude of the latent heat flux depends on factors such as the availability of moisture and the temperature difference between the surface and the atmosphere. It can be larger when there is more moisture available for evaporation and when the temperature difference is greater.
3. Bowen ratio (B): The Bowen ratio is the ratio of sensible heat flux to latent heat flux. It provides information about the relative importance of sensible and latent heat transfer processes. In this case, the Bowen ratio is expected to be negative. This indicates that the sensible heat flux is larger than the latent heat flux. The magnitude of the Bowen ratio can vary depending on the specific conditions, but it is generally larger when the sensible heat flux is dominant.
To summarize:
- Sensible heat flux (H) is negative, indicating heat transfer from the surface to the atmosphere.
- Latent heat flux (H_L) is positive, indicating heat transfer from the atmosphere to the surface through evaporation.
- Bowen ratio (B) is negative, indicating that the sensible heat flux is larger than the latent heat flux. The magnitude of the Bowen ratio can vary depending on the specific conditions.
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of the following, which is the most likely source for coarse particulate matter?
Among the options provided, the most likely source for coarse particulate matter is D) cars driving on unpaved roads.
When vehicles drive on unpaved or gravel roads, the movement of the tires can kick up dust and particles from the road surface, leading to the generation of coarse particulate matter. This can contribute to increased levels of dust and particles in the air.
While other options like residential fireplaces, power generation, and fossil fuel combustion in vehicles can also contribute to particulate matter emissions, cars driving on unpaved roads specifically generate coarse particles by disturbing the road surface.
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Complete question :
Of the following, which is the most likely source for coarse particulate matter?
A) residential fireplaces
B) power generation
C) fossil fuel combustion in vehicles
D) cars driving on unpaved roads
Which change to an object would double its kinetic energy?
A. Increasing its mass to twice its original value
B. Increasing its mass to four times its original value
C. Increasing its velocity to four times its original value
D. Increasing its velocity to twice its original value
Assume the supports of the uniform cantilever (m= 2900 kg) are made of wood. Calculate the minimum cross-sectional area required of each, assuming a safety factor of 9.0. Fa (20.0 m), Fb, center of gravity (distance from Fb to end is 30.0 m)
the minimum cross-sectional area required for each support, assuming a safety factor of 9.0 and a compressive strength of 40 MPa for the wood supports, is 99.58 mm^2 for support A and 14.88 mm^2 for support B.
To calculate the minimum cross-sectional area required for each support, we need to first determine the maximum force that each support will experience.
Assuming a uniform cantilever with a mass of 2900 kg and a length of 50.0 m (20.0 m to support A and 30.0 m to the center of gravity at point B), we can calculate the total weight of the cantilever as:
W = m*g = 2900 kg * 9.81 m/s^2 = 28,449 N
At support A, the maximum force will be equal to the weight of the cantilever plus any additional loads or forces applied to the cantilever at that point. Since no additional loads or forces were specified, we can assume that Fa = W = 28,449 N.
At point B, the maximum force will be equal to the weight of the portion of the cantilever from point B to the end, which is:
Wb = (m/2)*(Lb/L) * g = (2900/2)*(30.0/50.0)*9.81 = 4262 N
To determine the minimum cross-sectional area required for each support, we need to consider the maximum stress that the supports will experience. Assuming a safety factor of 9.0, the maximum stress can be calculated as:
σmax = Fmax/SF
Where Fmax is the maximum force on the support and SF is the safety factor.
Assuming a compressive strength of 40 MPa for the wood supports, the minimum cross-sectional area required for each support can be calculated as:
Amin = Fmax/(σmax)
For support A, the minimum cross-sectional area required is:
Amin,A = Fa/(σmax*SF) = 28,449 N/(40 MPa*9.0) = 99.58 mm^2
For support B, the minimum cross-sectional area required is:
Amin,B= Wb/(σmax*SF) = 4262 N/(40 MPa*9.0) = 14.88 mm^2
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(a) what impulse is applied to the driver by the seatbelt, assuming he follows the same motion as the car?
The impulse applied to the driver by the seatbelt, assuming he follows the same motion as the car is 1890 N sec.
In order to change the momentum of an object, you must exert a certain amount of force over a specific period of time. For example, when you hit a ball with a cricket bat, you apply a force for a time to cause a change of momentum in the ball.
A resultant force causes an acceleration and a change in the velocity of a body as long as the body is acting on it. Therefore, a net force applied over a long period of time produces a larger change in linear momentum than the same force applied for a short period of time.
Impulse is often stated to be the product of the mass and velocity of the object. The equation for impulse is given as,
J = m* v = 70* 27 = 1890 N sec
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Jordan wants to see if earthworms prefer rough or smooth terrain to crawl through. What will be his
independent variable? This is what he will change in his experiment.
change the type of worm
how much food they have
change the terrain
O where each worm starts from
Answer:
Change the terrain
Explanation:
independent variable is the cause and the change in terrain will change the outcome
A block of mass 20 kg is acted upon by a force F=30N at an angle 530 with the horizontal in downward direction as shown. The coefficient of friction between the block and the horizontal surface is 0.2. The friction force acting on the block by the ground is (g=10m/s2)
The friction force acting on the block by the ground is approximately 35.2 N.
The block of mass 20 kg is acted upon by a force F = 30 N at an angle of 53 degrees with the horizontal in a downward direction. The coefficient of friction between the block and the horizontal surface is 0.2, and the gravitational acceleration (g) is 10 m/s^2.
To determine the friction force acting on the block, we first need to find the normal force and the horizontal component of the applied force. We can do this using trigonometry and Newton's laws.
The vertical component of the applied force is Fv = F * sin(53°), which is approximately 24 N. The weight of the block is W = mg, or 20 kg * 10 m/s^2, which equals 200 N. The normal force (N) is the sum of the vertical component of the applied force and the weight of the block, so N = 200 N - 24 N, which equals 176 N.
The horizontal component of the applied force is Fh = F * cos(53°), which is approximately 18 N. The friction force (Ff) can be calculated using the equation Ff = μ * N, where μ is the coefficient of friction. Therefore, Ff = 0.2 * 176 N, which equals 35.2 N.
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A force of F= 45 N is used to drag a crate 3 m across a floor.
ANSWER:
(a) 108 J
(b) 0 J
(c) 108 J
STEP-BY-STEP EXPLANATION:
(a)
Express the relation between horizontal component of work done and force on the crate:
\(W_h=F_h\cdot d\)Here Wh is the horizontal component of the work done on the crate and Fh is the horizontal component of force and d is the distance of the crate across the floor.
Replacing:
\(\begin{gathered} W_h=36\cdot3 \\ W_h=108\text{ J} \end{gathered}\)(b)
Express the relation between vertical component of work done and force on the crate:
\(W_v=F_v\cdot d\)Here Wv is the vertical component of the work done on the crate and Fv is the vertical component of force and d is the distance of the crate across the floor.
Replacing:
\(\begin{gathered} W_h=27\cdot0 \\ W_h=0\text{ J} \end{gathered}\)(c)
Express the relation for total work done by the 45 N force:
\(\begin{gathered} W_{\text{total}}=W_h+W_v \\ \text{ replacing} \\ W_{\text{total}}=108+0 \\ W_{\text{total}}=108\text{ J} \end{gathered}\)Which force(s) drive(s) water circulation in the deep ocean?
Choose all that apply.
wind
differences in water pH
differences in water temperature
differences in water salinity
differences in water density
Mixed wave frequencies presented together produce:
Mixed wave frequencies presented together produce a phenomenon called interference, which can result in either constructive or destructive interference, depending on the alignment of the waves' phases.
Mixed wave frequencies presented together can produce interference patterns that can either amplify or cancel out certain frequencies. This is known as the principle of superposition. The resulting pattern is determined by the amplitude and phase of each wave. This phenomenon can be observed in a variety of natural phenomena, such as sound waves and light waves. In the case of sound waves, interference can lead to the creation of beats or harmonics, while in the case of light waves, interference can produce colorful patterns such as those seen in soap bubbles or oil slicks.
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The heat of fusion of a substance is 42. 5 J/g. How much energy is released when 40 g of this substance at its freezing point completely changes into a solid? Show your work.
A. ) 1. 700
B. ) 1. 06
C. ) 42. 5
D. ) 0 J
The heat energy of the substance option (A) -1700J is correct.
We are given that,
Heat of fusion of a substance = ΔHf = 42.5J/g
Mass of the substance = m= 40g
The latent heat of fusion is the quantity of heat required to transform one gramme of a substance from a solid to a liquid. But in this case, it's important to figure out how much heat is released as liquid copper solidifies. So, ΔHf = -42.5 J/g
Thus , we have to calculated here the heat energy of the substance by the formula,
q = m·ΔHf
Where, q is heat energy ,m is mass ΔHf is the heat of fusion of a substance,
q = m·ΔHf
q = -42.5 J/g× 40g
q = -1700J
Therefore , the heat energy of the substance would be option (A) -1700J
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the wave speed on a string under tension is 220 m/sm/s . part a part complete what is the speed if the tension is halved? express your answer with the appropriate units. vv = 156 msms
The speed, expressed with the appropriate units, is approximately `156 m/s`. Hence, the required answer is `v = 156 m/s.`
The wave speed on a string under tension is 220 m/s. The wave speed on a string under tension is given by the formula \(`v = sqrt(T/μ)`,\)
where `T` is the tension in newtons, `μ` is the linear density of the string in kilograms per meter, and `v` is the wave speed in meters per second.
Express your answer with the appropriate units.
To determine the wave speed on a string under tension of `T/2`, substitute `T/2` for `T` in the formula, then solve for `v`. \(v = sqrt((T/2)/μ).\)
We can simplify this expression by taking out a factor of 1/2 under the square root sign. \(v = sqrt(T/4μ)\)
Next, we can further simplify this expression by taking out the factor of 1/4 under the square root sign. \(v = (1/2)sqrt(T/μ)\)
Since the wave speed is proportional to the square root of the tension, halving the tension will reduce the wave speed by a factor of the square root of 2.
Therefore: \(`v = (1/2)sqrt(T/μ)`\)
`v = (1/2)sqrt(1/2 × 220/μ)
= (1/2) × 10sqrt(2/μ)``v ≈ 156 m/s`.
The speed, expressed with the appropriate units, is approximately `156 m/s`. Hence, the required answer is `v = 156 m/s.`
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Hey everyone,
right now
I want you to stop
stop whatever you are doing
walk to a mirror
look in it
look at your face
your gorgeous face
look at your eyes
how they shine
look at your hair
it's perfect
you are beautiful
I hope you realize
you are pretty freakin amazing <3
Answer:
oooh thanks
Explanation:
..................
Answer:
awwww thx you are to :)
Explanation: