Answers
Explanation:
Reduce the amount of CO2 in the air.
Increase the planetary temperature.
Make the planet breathable.
Construct plants for generating super-greenhouse gases made of complex combinations of carbon,chlorine and flourine.
Related Questions
Suppose an object’s initial velocity is 10 m/s and its final velocity is 4 m/s. Mass is constant. What can best be concluded about the object based on the work-energy theorem? A. Work is positive, the environment did work on the object, and the energy of the system increases. B. Work is positive, the object did work on the environment, and the energy of the system increases. C. Work is negative, the object did work on the environment, and the energy of the system decreases. D. Work is negative, the environment did work on the object, and the energy of the system decreases.
Answers
Explanation:
"Work is negative," the correct answer is, "the object did work on the environment, and the system's energy declines."
In fact, the work-energy theorem states that work done is equal to kinetic energy variation:
where W represents labor, Kf represents final kinetic energy, and Ki represents starting kinetic energy. Because the kinetic energy is proportional to the velocity v,
Since the final velocity is less than the initial velocity, the work is negative (the system's kinetic energy is reduced).
This also implies that the thing worked on the environment: in reality, by working, the object gave some of its kinetic energy to the environment, resulting in a decrease in kinetic energy.
Answer:
Work is negative, the object did work on the environment, and the energy of the system decreases.
Explanation:
Calculate the ratio of H+ ions to OH– ions at a pH = 8. Find the concentration of H+ ions to OH– ions listed in Table B of your Student Guide. Then divide the H+ concentration by the OH– concentration. Record this calculated ratio in Table A of your Student Guide. Compare your approximated and calculated ratios of H+ ions to OH– ions at a pH = 8. Are they the same? Why or why not? Record your explanation in Table A. What is the concentration of H+ ions at a pH = 8? mol/L What is the concentration of OH– ions at a pH = 8? mol/L What is the ratio of H+ ions to OH– ions at a pH = 8? :1 OR 1:
Answers
At pH = 8, the ratio of H+ ions to OH- ions is 1:1, indicating a neutral solution. The concentration of H+ ions and OH- ions is approximately 1 x 10^(-8) mol/L. The calculated and approximated ratios should match.
To calculate the ratio of H+ ions to OH- ions at pH = 8, we need to use the relationship between pH and the concentration of H+ ions. The pH scale is a logarithmic scale that measures the acidity or alkalinity of a solution based on the concentration of H+ ions.
The formula to calculate the concentration of H+ ions (\(C_H\)+) from pH is:
\(C_H\)+ = \(10^(^-^p^H^)\)
Substituting pH = 8 into the formula:
\(C_H\)+ = \(10^(^-^8^))\)
Using the properties of logarithms, we can calculate the concentration of H+ ions:
\(C_H\)+ ≈ 1 x \(10^(^-^8^))\) mol/L
According to the concept of neutrality in water, the concentration of H+ ions is equal to the concentration of OH- ions. Therefore, the concentration of OH- ions (\(C_O_H\)-) is also approximately 1 x \(10^(^-^8^))\)mol/L.
To calculate the ratio of H+ ions to OH- ions, we divide the concentration of H+ ions by the concentration of OH- ions:
Ratio = \(C_H\)+ / \(C_O_H\)-
Ratio = (1 x \(10^(^-^8^))\) / (1 x \(10^(^-^8^))\))
Ratio = 1:1
The ratio of H+ ions to OH- ions at pH = 8 is 1:1, indicating a neutral solution. This means that the concentration of H+ ions is equal to the concentration of OH- ions, resulting in a balanced ratio.
When comparing the calculated ratio of 1:1 to the approximated ratio at pH = 8, they should be the same because the ratio of H+ ions to OH- ions is determined solely by the pH value, which is consistent and mathematically derived. Therefore, the approximated and calculated ratios should match.
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a student stands several meters in front of a smooth reflecting wall, holding a board on which a wire is fixed at each end. the wire, vibrating in its third harmonic, is 75.0cm long, has a mass of 2.25g, and is under a tension of 400 N. a second student, moving towards the wall, hears 8.30 beats per second. what is the speed of the student approaching the wall? (solve without calculus)
Answers
Answer:
Explanation:
From the question we are told that
The length of the wire is \(L = 75.0cm = \frac{75}{100} = 0.75 \ m\)
The mass of the wire is \(m = 2.25 \ g = \frac{2.25}{1000} = 0.00225 \ kg\)
The tension is \(T = 400 \ N\)
The frequency of the beat heard by the second student is
\(f_b = 8.30\ beat/second\)
The speed of the wave generated by the vibration of the wire is mathematically represented as
\(v = \sqrt{\frac{TL}{m}}\)
substituting values
\(v = \sqrt{\frac{400 *0.75}{0.00225}}\)
\(v = 365.15 m/s\)
The wire is vibrating in its third harmonics so the wavelength is
\(\lambda = \frac{2L}{3}\)
substituting values
\(\lambda = \frac{2*0.75}{3}\)
\(\lambda = 0.5 \ m\)
The frequency of this vibration is mathematically represented as
\(f = \frac{v}{\lambda }\)
substituting values
\(f = \frac{365.15}{0.5 }\)
\(f = 730.3 Hz\)
The speed of the second student (Observer) is mathematically represented as
\(v_o = [\frac{f_b}{2f} ] * v\)
substituting values
\(v_o = [\frac{8.30}{2* 730.3} ] * 365.15\)
\(v_o = 2.08 \ m/s\)
what current flows through the 75 ohm resistor in the circuit below?
Answers
The current that flows through the 75 ohm resistor in the circuit shown below is 0.12A.
How to calculate current?The current flowing through a circuit can be calculated using the Ohm's law equation as follows;
V = IR
Where;
V = voltage (V)I = current (A)R = resistance (ohm)According to this question, a circuit is shown in the above image. A 75 ohm resistor is given alongside a voltage of 9V. The current can be calculated as follows;
9 = I × 75
I = 0.12A
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1. Imagine that you take a 200.0 km trip. You travel the first half of the trip at 100.0 km/hr. Your speed for the second half is 50.0 km/hr. How much time does the entire trip take?
2. In the above problem, what is your average speed in km/hr and m/s
Answers
Answer:
Explanation:
Speed = Distance/Time
Given
Distance = 200km
Total speed = 100+50 = 150km/hr
Time = Distance/Speed
Time = 200/150
Time = 1.33hr
b) Average speed in km/hr is 150km/hr
Convert to m/s
150km/hr = 150 * 1000 m/1 * 3600s
150km/hr = 150,000/360
150km/hr = 416.67m/s
Which statement describes the law of conservation of energy?
A. Energy cannot change forms.
B. Energy cannot be created or destroyed.
C. Air resistance has no effect on the energy of a system.
D. The total energy in a system can only increase.
Answers
Answer:
The correct answer is B. Energy cannot be created or destroyed.
The law of conservation of energy states that energy cannot be created or destroyed, but it can be transformed from one form to another. This means that in any physical process, the total amount of energy in a system remains constant. Energy can be converted from one form to another, such as from kinetic energy to potential energy or from electrical energy to light energy, but the total amount of energy in the system remains the same.
Option A is incorrect because energy can change forms, as mentioned above.Option C is incorrect because air resistance is a type of force that opposes the motion of an object, and therefore, it can cause a decrease in the kinetic energy of a system.Option D is incorrect because the law of conservation of energy states that the total energy in a system remains constant, it cannot increase or decrease without an external force acting on it. A student pushes a 6.0-kg box to the right with a
constant force FSB. The box moves at a constant velocity. The box experiences a
friction force f from the floor.
a. What type of friction does the box experience? Explain your reasoning.
b. Identify the four forces acting on the box.
Answers
b. The four forces acting on the box are:
1. Force of gravity (weight), which acts downwards towards the center of the earth, and has a magnitude of mg, where m is the mass of the box and g is the acceleration due to gravity.
2. Normal force, which is the force exerted by the floor on the box, perpendicular to the surface of contact, and has a magnitude of mg when the box is at rest or moving at a constant velocity.
3. Force applied by the student, denoted as FSB, which is directed to the right and has a magnitude that is equal to or greater than the force of friction.
4. Force of friction, denoted as f, which opposes the motion of the box and is directed to the left, opposite to the direction of the applied force. The magnitude of the frictional force is equal to the magnitude of the force applied by the student, as long as the box is moving at a constant velocity.
An aluminium bar 600mm long, with diameter 40mm, has a hole drilled in the center of the bar. The hole is 30mm in diameter and is 100mm long. If the modulus of elasticity for the aluminium is 85GN/m2, calculate the total contraction on the bar due to a compressive load of 180kN.
Answers
Answer:
\(\delta = 0.385\,m\) (Compression)
Explanation:
The aluminium bar is experimenting a compression due to an axial force, that is, a force exerted on the bar in its axial direction. (See attachment for further details) Under the assumption of small strain, the deformation experimented by the bar is equal to:
\(\delta = \frac{P\cdot L}{A \cdot E}\)
Where:
\(P\) - Load experimented by the bar, measured in newtons.
\(L\) - Length of the bar, measured in meters.
\(A\) - Cross section area of the bar, measured in square meters.
\(E\) - Elasticity module, also known as Young's Module, measured in pascals, that is, newtons per square meter.
The cross section area of the bar is now computed: (\(D_{o} = 0.04\,m\), \(D_{i} = 0.03\,m\))
\(A = \frac{\pi}{4}\cdot (D_{o}^{2}-D_{i}^{2})\)
Where:
\(D_{o}\) - Outer diameter, measured in meters.
\(D_{i}\) - Inner diameter, measured in meters.
\(A = \frac{\pi}{4}\cdot [(0.04\,m)^{2}-(0.03\,m)^{2}]\)
\(A = 5.498 \times 10^{-4}\,m^{2}\)
The total contraction of the bar due to compresive load is: (\(P = -180\times 10^{3}\,N\), \(L = 0.1\,m\), \(E = 85\times 10^{9}\,Pa\), \(A = 5.498 \times 10^{-4}\,m^{2}\)) (Note: The negative sign in the load input means the existence of compressive load)
\(\delta = \frac{(-180\times 10^{3}\,N)\cdot (0.1\,m)}{(5.498\times 10^{-4}\,m^{2})\cdot (85\times 10^{9}\,Pa)}\)
\(\delta = -3.852\times 10^{-4}\,m\)
\(\delta = -0.385\,mm\)
\(\delta = 0.385\,m\) (Compression)
Identify the type of particle that would be given off by each of the following nuclear reactions:
What isotope is produced when plutonium-239 (Pu-239) undergoes alpha decay?
A. Lead-210
B. Thorium-234
C. Uranium-235
Answers
Answer:
C po ang sa got pa braenlest
Answer:
C. Uranium-235
Explanation:
I just took the test.
The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the
Answers
Answer:
equator
Explanation:
in south & north pole you could have 20+ hours daylight or night, everyday!
Hi! I need help quick!
Explain the difference between the first day of fall and the first day of winter
Answers
Answer:
We usually travel in January or Feb for our tropical get-a-way. For those of you that have traveled in the fall and winter...
What is the real difference...Like in the floral and fauna, weather, and the capacity of the resorts between these 2 times of the year.
Let e_1 = [1 0], e_2 = [0 1], y_1 = [2 5], and y_2 = [-1 6] and let T: R2 rightarrow R2 be a linear transformation that maps e1 into y1 and maps e2 into y2. Find the images of [5 -3] and [x_1 x_2].
Answers
1.The image of [5 -3] under T is T([5 -3]) = [2x5 - 3x-1, 5x6 - 3x1] = [10 -3, 30 -3]
2.The image of [x1 x2] under T is T([x1 x2]) = [2x1 + 5x2, -1x1 + 6x2] = [2x1 + 5x2, -x1 + 6x2]
An image is a visual representation of something, such as a physical object, a person, a place, or an idea. Images can be two-dimensional, such as a photograph or screen display, or three-dimensional, such as a statue or hologram. Images can be digital or analog, static or dynamic, and can be captured using photography, scanning, or computer graphics.
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Ellie has a more complicated relationship with her body. She often experiences a gender identity that doesn’t align with her body. What might this way of feeling be linked to?
A. Misinformation
B. Gender Dysmorphia
C. Construed body image
D. Positive body image
Answers
Ellie's experience of a gender identity that doesn't align with her body is likely linked to gender dysphoria, a condition characterized by distress caused by the incongruence between one's internal sense of gender and assigned sex at birth.
The correct answer is option B.
Gender dysphoria refers to the distress or discomfort individuals may experience when their gender identity does not match the sex they were assigned at birth. It involves a deep-rooted sense of incongruence between one's internal sense of gender and the external physical characteristics.
It is important to note that gender dysphoria is not a result of misinformation or a lack of understanding. It is a genuine psychological condition recognized by medical and mental health professionals. Individuals with gender dysphoria often experience significant distress and may seek gender-affirming interventions, such as hormone therapy or gender-affirming surgeries, to align their physical appearance with their gender identity.
Misinformation, on the other hand, refers to inaccurate or misleading information, which may not directly relate to Ellie's experience. Construed body image and positive body image are also not directly linked to Ellie's situation. Construed body image refers to the way individuals perceive their own bodies, which may be influenced by various factors, while positive body image refers to a healthy and accepting attitude toward one's own body.
In summary, Ellie's experience of a gender identity that doesn't align with her body is likely linked to gender dysphoria. Gender dysphoria involves distress or discomfort resulting from a mismatch between an individual's internal sense of gender and their assigned sex at birth.
Therefore, among the options provided the correct answer is option B.
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A certain unbalanced force gives a 5kg object an acceleration of 15 m/s2. What would be the acceleration if the same force was applied to 30 kg object ?
Answers
Answer:
a2 = 2.5 m/s2
Explanation:
F1 = m1 a1 We use the same force so F1 = F2
= 5kg × 15m/s2 F2 = m2 a2
= 75N a2 is required
a2 = F2 / m2
= 75N / 30 kg
= 2.5 m/s2
What's centrifugal force
Answers
GOOGLE: Centripetal force is defined as, "the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation," while centrifugal force is defined as "the apparent force that is felt by an object moving in a curved path that acts outwardly away from the center of
I don't actually know what that is but I hope this helps! Good luck!
A car accelerates uniformly from rest to a speed of 55.0 mi/h in 10.0 s.
Answers
The distance the car travels during the 10.0 s acceleration is 403.5 feet.
What is difference between velocity and speed?Speed refers to how fast an object is moving without any consideration of its direction. It is a scalar quantity, which means it only has a magnitude and no direction. Speed is calculated by dividing the distance traveled by the time it takes to travel that distance.
Velocity, on the other hand, refers to how fast an object is moving in a specific direction. It is a vector quantity, which means it has both a magnitude (the speed) and a direction. Velocity is calculated by dividing the displacement (change in position) by the time it takes to cover that displacement.
We use:
distance = (1/2) x acceleration x time²
Since the car starts from rest, its initial velocity (u) is 0. The final velocity (v) is 55.0 mi/h, and the time (t) is 10.0 s. We need to convert the final velocity from miles per hour to feet per second to match the units of acceleration in feet per second squared.
Final velocity (v) = 55.0 mi/h = 80.7 ft/s (1 mile = 5280 feet)
Time (t) = 10.0 s
To find the acceleration (a), we can use the following equation, which relates acceleration, velocity, and time:
acceleration = (v - u) / t
Since the initial velocity is 0, we can simplify this to:
acceleration = v / t
acceleration = 80.7 ft/s / 10.0 s = 8.07 ft/s^2
Therefore, the constant acceleration of the car is 8.07 ft/s^2.
To find the distance the car travels, we can substitute the values we have into the equation for distance:
distance = (1/2) x acceleration x time²
distance = (1/2) x 8.07 ft/s² x (10.0 s)²
distance = 403.5 feet
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Which statement places events during the Space Race in the correct order from the earliest to the most recent?
1.NASA was established, US satellite Explorer launched, first man walked on the moon, first man orbited the Earth
2.first man walked on the moon, first man orbited the Earth, NASA was established, US satellite Explorer launched
3.US satellite Explorer launched, NASA was established, first man orbited the Earth, first man walked on the moon
4. first man orbited the Earth, first man walked on the moon, US satellite Explorer launched, NASA was established
Answers
Answer:
3,1,4,2
Explanation:
Answer:C
Explanation:
What is the sum of the following vectors?
Answers
Answer:h
Explanation:
4. S. crossirostris's wings were made of a delicate flap of skin. If this flap of skin
tore, the animal could not fly. Use this information to explain how
S. crassirostris might have had trouble competing with bird species living during
the Mesozoic era.
Answers
Birds underwent significant diversification and adaptation during the Mesozoic epoch, allowing them to develop into effective and adaptable flyers.
What are the birds?The wings of S. crossirostris, also referred to as the "delicate-winged pterosaur," were constructed of a delicate flap of skin called the patagium. This delicate membrane was prone to breaking, unlike the stiff feathers of birds.
In terms of flight prowess and ecological success, S. crossirostris would not have been able to compete with birds due to the restrictions imposed by its delicate wing structure.
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How can we protect ourselves from ultraviolet radiation
Answers
Answer:
Use sunscreen, avoid spending a lot of time in sunny areas, being indoors from 12:00 p.m. to 2:00 p.m.
Explanation:
crown please
when the same amount of heat is added to equal masses of water and copper at the same temperature the copper is heated to a higher final temperature than water. on a molecular level what explains this difference
a. the average kinetic energy of water molecules is greater than the average kinetic energy of the copper
b.more of the heat is transferred to the potential energy of the water molecules than the potential energy of the copper atoms
c.the intermolecular forces between copper atoms are stronger than those between water molecules
d.more of the heat is transferred to the kinetic energy of the water molecules than to the kinetic energy of the copper atoms
Answers
Answer:
C
Explanation:
The intermolecular forces between the water molecule is less binding than that of the copper molecule. Hence the water would take a shorter time to be converted to vapour where the temperature of boiling is constant however the temperature of that of the copper molecule keeps increasing.
A runner sprints for 20 minutes at an average pace at 7mph.what is the distance traveled?
Answers
Answer:
A runner sprints for 20 minutes at an average pace at 7mph.what is the distance traveled?
Explanation:
140
1. What happens to the man in a lift if he's moving under constant velocity
2. If he's in upward motion
3. If he's in downward motion
Answers
a) If he's in upward motion or If he's in downward motion N = mg
net force = mass * acceleration
a) If he's in upward motion
N - mg = ma
Since , lift is moving under constant velocity
a = 0
N - mg = m * 0
N = mg
b) If he's in downward motion
mg - N = ma
Since , lift is moving under constant velocity
a = 0
mg = N
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Why is the pressure so high deep inside the outer planets?
Answers
Answer:
Due to its larger size
Explanation:
This is due to those planets being much larger than Earth. The larger a planet is, the more gravity that planet has, since gravity is mainly calculated based on the mass and radius of the planet. Also since the pressure deep inside of the planet depends mainly on the gravity of that planet on the surface, this is calculated as the square of the planet's surface gravity. Ultimately, the bigger the planet is the higher the pressure deep inside the planet will be.
What combination do I need to use for this egg to survive a 5 meter drop?
Answers
Answer:
lunch box, cotton, toilet paper, and the foam peanuts
Explanation:
bc I did this experiment in 3rd grade =w="
Hope this helped! Have a nice day!
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A hiker walks from
(x1, y1) = (−3.60 km, 3.25 km) to (x2, y2) = (3.05 km, 5.90 km). (Take east to lie along the positive x-axis and north to lie along the positive y-axis.)
(a) What distance has he traveled? (Assume the hiker walked in a straight line.)
(b) The hiker desires to return to his starting point. In what direction should he go? (Give the angle with respect to due east. Enter an angle between 0° and 360°.)
Answers
(a) The distance travelled by the hiker is 7.16 km
(b) If the hiker desires to return to his starting point, he should move at 201.71° with respect to east.
Form a right angled triangle with the distance between initial and final points as hypotenuse. The adjacent side will be the total distance travelled on x-direction and the opposite side will be the total distance travelled in y-direction.
Adjacent side = \(x_{2}\) - \(x_{1}\) = 3.05 - ( - 3.6 )
Adjacent side = 6.65 km
Opposite side = \(y_{2}\) - \(y_{1}\) = 5.9 - 3.25
Opposite side = 2.65 km
According to Pythagoras theorem,
\(Hypotenuse^{2}\) = \(Opposite side^{2}\) + \(Adjacent side^{2}\)
\(Hypotenuse^{2}\) = \(2.65^{2}\) + \(6.65^{2}\)
Hypotenuse = √ ( 7.02 + 44.22 )
Hypotenuse = 7.16 km
sin θ = Opposite side / Hypotenuse
sin θ = 2.65 / 7.16
θ = \(sin^{-1}\) ( 0.37 )
θ = 21.71°
This is the angle in which the hiker travelled from initial to final direction. The angle in which the hiker should travel to return to initial point with respect to east is
θ = 21.71° + 180°
θ = 201.71°
Therefore,
(a) The distance travelled by the hiker is 7.16 km
(b) If the hiker desires to return to his starting point, he should move at 201.71° with respect to east.
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calculate the upthrust aciting on a body if its
true weight is 550 N and apparent weight
lis 490 N
Answers
Answer:
As a body moving upward
T=real weight + apparent weight
T=550+490
T=1040
hope u will get the answer:)
Explanation:
ONE sound wave travels through two containers of different gasses. Wave through container 1 has a wavelength of 1.2 m. Wave through container 2 has a wavelength of 3.6 m. The frequency of wave through container 2 must be __________ the frequency of wave through container 1.
a. one-ninth
b. one-third
c. the same as
d. three times larger than
Answers
Which point on the standing wave is a node?
A.A
B.B
C.C
D.D
Answers
Point B on the standing wave is referred to as a node. The correct option is B.
In a standing wave, a node refers to a point or region of minimal or zero amplitude. It is a point where the displacement of the wave is always zero, and it remains stationary as the wave oscillates. At a node, the particles or elements that make up the medium through which the wave is propagating do not experience any displacement from their equilibrium positions.
Nodes occur due to destructive interference between two waves of equal frequency and amplitude traveling in opposite directions. The superposition of these waves results in the formation of a standing wave pattern, characterized by nodes and antinodes.
Nodes are important features of standing waves and have several properties:
Fixed position: Nodes maintain a fixed location within the standing wave pattern and do not move as the wave oscillates.
Zero displacements: At nodes, the amplitude of the wave is zero, and there is no displacement of the medium particles or elements.
Energy concentration: Nodes are regions of low energy in a standing wave. The energy of the wave is primarily concentrated in the regions between the nodes, known as antinodes.
Separation distance: The distance between adjacent nodes in a standing wave is equal to half the wavelength of the wave.
Therefore, The correct answer is option B.
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A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C
Answers
The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).
The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.
In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²
(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:
Electric flux = Electric field strength × Area
Electric flux = 18 N C⁻¹ × 0.450 m²
Electric flux = 8.1 N m² C⁻¹
In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.
The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).
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