Can I have some help please

The equation of the line is y=1/3x.

The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is

m=y₂-y₁/x₂-x₁

From the given graph let us take two points through which the line passes.

(-6, -2) and (6, 2)

m=2-(-2)/6-(-6)

m=4/12=1/3

The slope of the line is 1/3.

Now we have to find the y intercept

2=1/3(6)+b

2=2+b

b=0

The equation of line is y=1/3x

Hence, the equation of the line is y=1/3x.

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Answer:

16

Step-by-step explanation:

Answer:

420 = 4.2 x 100 = 4.2 × 102

Step-by-step explanation:

The situation Veronica receives $21 for babysitting, and then spends the same amount, $21, on a new shirt quantities combine to make 0.The correct answer is option C.

When we add +21 (the money she receives) and subtract -21 (the money she spends), the result is 0. This means that the net change in Veronica's money is zero, indicating that the quantities combine to make 0.

In situations A, B, and D, the quantities do not combine to make 0. In situation A, the player earns 4 points for getting an answer right and then earns an additional 4 points for making it around the board.

The total points earned in this situation would be 8, which is not equal to 0.

In situation B, the car is initially filled with 10 gallons of gas, but then half of that, which is 5 gallons, is used on a day's drive. The remaining fuel in the car would be 5 gallons, which is also not equal to 0.

In situation D, the bird flies 25 feet up in the air and then 25 feet across to its nest. The total distance traveled by the bird would be 50 feet, which is not equal to 0.

Therefore, only in situation C, where Veronica receives and spends the same amount of money, do the quantities combine to make 0.

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The probable question may be:

In which of these situations do the quantities combine to make 0?

A. A player a game earns 4 points for getting an answer right. She then earns 4 points for making it around the board.

B. A car is filled with 10 gallons of gas. Half of the 10 gallons are then used on a day's drive.

C. Veronica receives $21 for babysitting. She then spends $21 on a new shirt.

D. A bird flies 25 feet up in the air. It then flies 25 feet across to its nest.

Answer:

y= 3 y =0

Step-by-step explanation:

find the derivative

Answer:

Step-by-step explanation:

first step: 0.5 * x

second step: 3* (0.5x) = 1.5x

third step: (1.5x)^2

fourth step: (1.5x)^2 + 1 = 50

(1.5x)^2 + 1 = 50                    Subtract 1 from both sides

(1.5x)^2 = 49                          Take the square root of both sides

1.5x = sqrt(49)

1.5x = +/- 7

1.5x = +7

x = 7/1.5

x = 4.67

1.5x = - 7

x = - 7 / 1.5

x = - 4.67

Answer:

25.35 grams of C  is formed in 14 minutes

after a long time , the limiting amount of C = 60g ,

A = 0 gram

and  B = 30 grams;           will remain.

Step-by-step explanation:

From the information given;

Let consider x(t) to represent the number of grams of compound C present at time (t)

It is  obvious that x(0) = 0 and x(5) = 10 g;

And for x gram of C;

\(\dfrac{2}{3}x\)   grams of A is used ;

also \(\dfrac{1}{3} x\)   grams of B is used

Similarly; The amounts of A and B remaining at time (t) are;

\(40 - \dfrac{2}{3}x\)   and \(50 - \dfrac{1}{3}x\)

Therefore ; rate of formation of compound C can be said to be illustrated as ;

\(\dfrac{dx}{dt }\propto (40 - \dfrac{2}{3}x)(50-\dfrac{1}{3}x)\)

=\(k \dfrac{2}{3}( 60-x) \dfrac{1}{3}(150-x)\)

where;

k = proportionality constant.

= \(\dfrac{2}{9}k (60-x)(150-x)\)

By applying the  separation of variable;

\(\dfrac{1}{(60-x)(150-x)}dx= \dfrac{2}{9}k dt \\ \\ \\\)

Solving by applying partial fraction method; we have:

\(\{ \dfrac{1}{90(60-x)} - \dfrac{1}{90(150-x)} \}dx = \dfrac{2}{9}kdt\)

\(\dfrac{1}{90}(\dfrac{1}{x-150}-\dfrac{1}{x-60})dx =\dfrac{2}{9}kdt\)

Taking the integral of both sides ; we have:

\(\dfrac{1}{90}\int\limits(\dfrac{1}{x-150}- \dfrac{1}{x-60})dx= \dfrac{2}{9}\int\limits kdx\)

\(\dfrac{1}{90}(In(x-150)-In(x-60)) = \dfrac{2}{9}kt+C\)

\(\dfrac{1}{90}(In(\dfrac{x-150}{x-60})) = \dfrac{2}{9}kt+C\)

\(In( \dfrac{x-150}{x-60})= 20 kt + C_1 \ \ \ \ \ where \ \ C_1 = 90 C\)

\(\dfrac{x-150}{x-60}= Pe ^{20 kt} \ \ \ \ \ where \ \ P= e^{C_1}\)

Applying the initial condition x(0) =0  to determine the value of P

Replace x= 0 and t =0 in the above equation.

\(\dfrac{0-150}{0-60}= Pe ^{0}\)

\(\dfrac{5}{2}=P\)

Thus;

\(\dfrac{x-150}{x-60}=Pe^{20kt} \\ \\ \\ \dfrac{x-150}{x-60}=\dfrac{5}{2}e^{20kt} \\ \\ \\ 2x -300 =5e^{20kt}(x-60)\)

\(2x - 300 = 5xe^{20kt} - 300 e^{20kt} \\ \\ 5xe^{20kt} -2x = 300 e^{20kt} -300 \\ \\ x(5e^{20kt} -2) = 300 e^{20kt} -300 \\ \\ x= \dfrac{300 e^{20kt}-300}{5e^{20kt}-2}\)

Thus;

\(x(t)= \dfrac{300 e^{20kt}-300}{5e^{20kt}-2}\)

Applying the initial condition for x(7) = 15 , to find the value of k

Replace t = 7 into \(x(t)= \dfrac{300 e^{20kt}-300}{5e^{20kt}-2}\)

\(x(7)= \dfrac{300 e^{20k(7)}-300}{5e^{20k(7)}-2}\)

\(15= \dfrac{300 e^{140k}-300}{5e^{140k}-2}\)

\(75e^{140k}-30 ={300 e^{140k}-300}\)

\(225e^{140k}=270\)

\(e^{140k}=\dfrac{270}{225}\)

\(e^{140k}=\dfrac{6}{5}\)

\(140 k = In (\dfrac{6}{5})\)

\(k = \dfrac{1}{140}In (\dfrac{6}{5})\)

k = 0.0013

Thus;

\(x(t)= \dfrac{300 e^{20kt}-300}{5e^{20kt}-2}\)

\(x(t)= \dfrac{300 e^{20(0.0013)t}-300}{5e^{20(0.0013)t}-2}\)

\(x(t)= \dfrac{300 e^{(0.026)t}-300}{5e^{(0.026)t}-2}\)

The amount of C formed in 14 minutes is ;

\(x(14)= \dfrac{300 e^{(0.026)14}-300}{5e^{(0.026)14}-2}\)

x(14) = 25.35 grams

Thus 25.35 grams of C  is formed in 14 minutes

NOW; The limiting amount of C after a long time is:

\(\lim_{t \to \infty} = \lim_{t \to \infty} (\dfrac{300 e^{(0.026)t}-300}{5e^{(0.026)t}-2})\)

\(\lim_{t \to \infty} (\dfrac{300- 300 e^{(0.026)t}}{2-5e^{(0.026)t}})\)

As; \(\lim_{t \to \infty} e^{-20kt} = 0\)

⇒ \(\dfrac{300}{5}\)

= 60 grams

Therefore  as t → \(\infty\);   x = 60

and the amount of A that remain = \(40 - \dfrac{2}{3}x\)

=\(40 - \dfrac{2}{3}(60)\)

= 40 -40

=0 grams

The amount of B that remains = \(50 - \dfrac{1}{3}x\)

= \(50 - \dfrac{1}{3}(60)\)

= 50 - 20

= 30 grams

Hence; after a long time ; the limiting amount of C = 60g , and 0 g of A , and 30 grams of B will remain.

I Hope That Helps You Alot!.

Answer:

Step-by-step explanation:

We can use the method of undetermined coefficients to solve this differential equation. First, we will need to find the solution to the homogeneous equation and the particular solution to the non-homogeneous equation.

For the homogeneous equation, we will use the form y"+ky=0, where k is a constant. We can find the solutions to this equation by letting y=e^mx,

y"=m^2e^mx -> (m^2)e^mx+k*e^mx=0, therefore (m^2+k)e^mx=0

(m^2+k) should equal 0 for the equation to have a non-trivial solution. Therefore, m=±i√(k), and the general solution to the homogenous equation is y=A*e^i√(k)x+Be^-i√(k)*x.

Now, we need to find the particular solution to the non-homogeneous equation. We can use the method of undetermined coefficients to find the particular solution. We will let yp=a0+a1x+a2x^2+.... As the derivative of a sum of functions is the sum of the derivatives, we get

yp″=a1+2a2x....yp‴=2a2+3a3x+....

Substituting the general solution into the non-homogeneous equation, we get

a0+a1x+a2x^2+...+2a2x+3a3x^2+...=Y(4)

So, the coefficient of each term in the expansion of the left hand side should equal the coefficient of each term in the expansion of the right hand side. Since there is only one term on the right hand side, we get the recurrence relation:

a(n+1)=Y(n-2)/n^2

From this relation, we can find all the coefficients in the expansion for the particular solution. Using this particular solution, we can find the total solution to the differential equation as the sum of the homogeneous solution and the particular solution.

\(\sqrt{25*7x^{4}*x^{1} } \\=\sqrt{25*x^{4}*7 *x^{1} } \\=\sqrt{25x^{4} } *\sqrt{7x}\\=5x^{2} \sqrt{7x}\)

Option B is the answer.

Answer: C

i hope you can see my handwriting

Answer: B) 2&3

Step-by-step explanation:

7/3 is 2.33333 repeating which in a complete fraction is 2 1/3.

On a number line, your answer would between 2 and 3.

Answer:

117

Step-by-step explanation:

10*9=90

3*9=27

90+27=117

This is a easy method to do multipication in mind

Answer:

Step-by-step explanation:

inorder to solve the area of the shaded area;°/360ñRsquared

arc length you use ;°/360ñD

Answer:0.367

Step-by-step explanation:

Given

There are 6 cans of regular and 7 cans of diet cola

number of ways of selecting 2 regular colas and 1 can of diet cola is

\(\Rightarrow ^6C_2\times ^7C_1\)

The total no of ways of selecting 3 items out of 13 items is

\(\Rightarrow ^{13}C_3\)

Probability is

\(\Rightarrow P=\dfrac{^6C_2\times ^7C_1}{^{13}C_3}=\dfrac{105}{286}\\\Rightarrow P=0.367\)

Answer:

the cost per or per liter,one kilogram,one pound e.t c is called pricing in mathematics

Answer:

Definition: Price is the value that is put to a product or service and is the result of a complex set of calculations, research and understanding and risk taking ability. A pricing strategy takes into account segments, ability to pay, market conditions, competitor actions, trade margins and input costs, amongst others.

Answer:

c=pie r squared is the equations and the answer is 50.27

Step-by-step explanation:

Answer: x=35

Triangle angle sum property

(x+2)+3x+(x-7)=180

=>5x-5=180

=>5x=175

=>x=35

Yo help me out and mark my answer brainliest along with the previous q u asked. Helps out a lot!

Answer:

the linear equation is y=2 so anything that lands on that line after it is graphed, so the option (3,2)

Step-by-step explanation:

Answer:

2520

Step-by-step explanation:

There are 7 letters in MCHNLRN and they can be arranged into 7 ways:

7! = 5040 ways in total

However, the letter 'N' is repeated so we have to divide it by 2.

5040 ÷ 2 = 2520 ways

Answer:

2,520 ways

Step-by-step explanation:

MCHNLRN has 7 letters with one repetition.

therefore, =7!/2!

=2,520 ways

Answer:

40

Step-by-step explanation:

Girls=(25+b)

boys=b

girls + boys=105

(25+b)+b=105

2b=80

b=40

Check answer

girls=b+25

girls=40+25

girls=65

boys+girls=105

40+65=105

105=105

There are 40 boys in the school.

"It is a mathematical statement which consists of equal symbol between two algebraic expressions."

For given question,

Let 'x' be the number of girls and 'y' be the number of boys in the school.

There are 105 pupils in a school.

So, we get an equation,

⇒ x + y = 105               ..................(1)

the girls are 25 more than the boys.

So, we get an equation,

⇒ x = y + 25               .........................(2)

Substitute above value of x in equation (1)

⇒ (y + 25) + y = 105

⇒ 2y + 25 = 105

⇒ 2y = 80

⇒ y = 40

Substitute above value of y in equation (2),

⇒ x = 40 + 25

⇒ x = 65

Therefore, there are 40 boys in the school.

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Answer:

Step-by-step explanation:

F(x) = 2 - x²

\(\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{8.4\% of 16.83}}{\left( \cfrac{8.4}{100} \right)16.83} ~~ \approx ~~ 1.41~\hfill \underset{ Total~for~lunch }{\stackrel{ 16.83~~ + ~~1.41 }{\approx\text{\LARGE 18.24}}}\)

Answer:

its 2x^4+9x^3+3x^2+12x_2.

The loaded die appears to behave differently from a fair die.Based on the chi-square test, the loaded die does not exhibit equal probabilities for each outcome.

To test the claim that the outcomes of the loaded die are not equally likely, we can use the chi-square goodness-of-fit test. The null hypothesis (H₀) assumes that the outcomes are equally likely, while the alternative hypothesis (H₁) assumes that they are not equally likely.

Step 1: Set up hypotheses

H₀: The outcomes of the die are equally likely.

H₁: The outcomes of the die are not equally likely.

Step 2: Select the significance level

The significance level is given as 0.025, which means we have a two-tailed test and an alpha level of 0.025 for each tail.

Step 3: Compute the test statistic

We calculate the chi-square test statistic using the observed frequencies and the expected frequencies assuming equal probabilities for each outcome.

Expected frequencies (fair die):

1: 200/6 = 33.33

2: 200/6 = 33.33

3: 200/6 = 33.33

4: 200/6 = 33.33

5: 200/6 = 33.33

6: 200/6 = 33.33

Applying the chi-square formula, we get the test statistic:

χ² = ∑((observed - expected)² / expected)

Calculating this value, we get χ² ≈ 13.97.

Step 4: Determine the critical value

Since the significance level is 0.025 and the test is two-tailed, we divide the significance level by 2 to find the critical value associated with each tail. With 5 degrees of freedom (6 categories - 1), the critical value is approximately 11.07.

Step 5: Make a decision

The test statistic (13.97) is greater than the critical value (11.07), which leads us to reject the null hypothesis. Thus, we have evidence to suggest that the outcomes of the loaded die are not equally likely.

The loaded die appears to behave differently from a fair die.

In conclusion, based on the chi-square test, the loaded die does not exhibit equal probabilities for each outcome.

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Answer:

15,000 from her savings

Step-by-step explanation:2,500*12=30,000  45000-30,000=15,000

Answer:

Option B

Step-by-step explanation:

704 cubic centimeters

Answer:

4/15

Step-by-step explanation:

2/5 drive

1/3 bus

and rest walk

fraction of those who walk is 1-(2/5+1/3)

2/5+1/3=(6+5)/15=11/15

15/15-11/15=4/15

The graph of the solution to the given inequality on the number line plotted is attached.

Inequalities are the mathematical expressions in which both sides are not equal.

In inequality, unlike in equations, we compare two values.

The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

The given inequality is q < 69.5​.

The result can be shown in multiple forms.

Inequality Form:q<69.5

Interval Notation:(−∞,69.5)

Therefore, the graph the solution to the given inequality on the number line plotted below.

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The impact on Carns Company's income from eliminating the Small Tools Division would be a decrease of $1,209,000.

To determine the impact on Carns Company's income from eliminating the Small Tools Division, we need to consider the avoidable costs associated with the division.

The avoidable costs include all of the variable costs of the division and a portion of the fixed costs that are specifically related to the Small Tools Division. In this case, the variable costs of the division are $1,295,000, and $119,000 of the fixed costs are avoidable.

To calculate the impact on income, we subtract the avoidable costs from the loss reported by the division:

Impact on income = Loss - Avoidable costs

Impact on income = $205,000 - ($1,295,000 + $119,000)

Impact on income = $205,000 - $1,414,000

Impact on income = -$1,209,000

The negative sign indicates a decrease in income.

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