Can anyone solve this for me ​
I give you brainliest thing

An integer z ∈ [0,11) such that z ≡ 2^100 (mod 11), we can simply take the remainder of 9 when divided by 11, which is 9 itself. Therefore, we can say that: z ≡ 2^100 ≡ 9 (mod 11)

From exercise 11.7, we know that 2^5 ≡ 1 (mod 11). Therefore, we can write 2^100 as:

2^100 = (2^5)^20

Using the above congruence, we can reduce this to:

2^100 ≡ 1^20 ≡ 1 (mod 11)

Now, we can use the observation that 100 = 64 + 32 + 4 to write:

2^100 = 2^64 * 2^32 * 2^4

Using the fact that 2^5 ≡ 1 (mod 11), we can reduce each of these terms modulo 11 as follows:

2^64 ≡ (2^5)^12 * 2^4 ≡ 1^12 * 16 ≡ 5 (mod 11)

2^32 ≡ (2^5)^6 * 2^2 ≡ 1^6 * 4 ≡ 4 (mod 11)

2^4 ≡ 16 ≡ 5 (mod 11)

Therefore, we can substitute these congruences into the expression for 2^100 and simplify as follows:

2^100 ≡ 5 * 4 * 5 ≡ 100 ≡ 9 (mod 11)

Hence, we have found that 2^100 is congruent to 9 modulo 11. To find an integer z ∈ [0,11) such that z ≡ 2^100 (mod 11), we can simply take the remainder of 9 when divided by 11, which is 9 itself. Therefore, we can say that: z ≡ 2^100 ≡ 9 (mod 11)

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Answer:

2a(3a + 8)

Step-by-step explanation:

Combine like terms

6a2 + 15 + a

6a2 + 16a

Answer:

5 feet 4.4 inches tall

Step-by-step explanation:

There are 40 ways to place three rooks on a 4x5 board so that no rook is threatening another.

To determine this, we can first place the rooks in three distinct rows, which can be done in 4 * 3 * 2 = 24 ways. Then, we can place one rook in each of the five columns in the first row, which leaves only three columns for the second row and two columns for the third row.

Since no two rooks can be in the same column, we have 5 * 3 * 2 = 30 ways to place the remaining two rooks.

Therefore, the total number of arrangements is 24 * 30 = 720, but since each arrangement can be rotated by 90, 180, or 270 degrees, we need to divide by 4 to obtain the final answer of 720/4 = 180, and since there are two ways to arrange the rooks in each row, the final answer is 180/2 = 90.

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Answer:

The domain (x) is the height of the ball

the answer is 0 is less then or equal to d is less then or equal to 412

Answer:

Step-by-step explanation:0.18

To multiply 121 and 121x²-1, we used the distributive property of multiplication and simplified the expression to get the final answer of 1331x² - 121.

To multiply 121 and 121x²-1, we need to use the distributive property of multiplication. We can break up 121 as 11 * 11 and write as

121 * (121x²-1) = (11 * 11) * (121x²-1)

Using the distributive property here, we can then write

= 11 * 11 * 121x² - 11 * 11 * 1

Simplifying the expression, we get

= 1331x² - 121

So the multiplication of 121 and 121x²-1 is 1331x² - 121.

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--The given question is incomplete, the complete question is given

" Multiply 121 * 121x²-1 "--

Answer:

...

Step-by-step explanation:

Significant zeros are zeros that contribute to the precision of a number, while nonsignificant zeros are placeholders or indicate the magnitude of a number.

Significant zeros are zeros that are considered significant and contribute to the precision of a number. They are located between nonzero digits or at the end of a number with a decimal point.

For example:

In the number 4,503, the zeros between 4 and 3 are significant.

In the number 0.00856, the zeros after the decimal point and before the 8 are significant.

Nonsignificant zeros, on the other hand, are zeros that do not contribute to the precision of a number and are used for placeholders or to indicate the magnitude of a number. They are typically located at the beginning or end of a number without a decimal point. Examples include:

In the number 0420, the zero at the beginning is nonsignificant.

In the number 0.003, the zeros before the decimal point is nonsignificant and serve as placeholders.

It's important to note that the significance of zeros can vary depending on the context and the rules of significant figures or decimal places being used in a specific calculation or measurement.

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As per the concept of average, the price relatives for the four stocks making up the Boran index are as follows:

Stock A: January Year 3 - 73.88, March Year 3 - 67.16

Stock B: January Year 3 - 75.38, March Year 3 - 73.08

Stock C: January Year 3 - 82.50, March Year 3 - 73.75

Stock D: January Year 3 - 32.50, March Year 3 - 18.75

To calculate the price relatives for each stock, we need to compare the prices of each stock in different periods to the base-year price. The base-year price is the price per share in the year 1 base period. The formula for calculating the price relative is:

Price Relative = (Price in Current Period / Price in Base Year) * 100

Now let's calculate the price relatives for each stock based on the given data:

Stock A:

Price Relative for January Year 3 = (24.75 / 33.50) * 100 ≈ 73.88

Price Relative for March Year 3 = (22.50 / 33.50) * 100 ≈ 67.16

Stock B:

Price Relative for January Year 3 = (49.00 / 65.00) * 100 ≈ 75.38

Price Relative for March Year 3 = (47.50 / 65.00) * 100 ≈ 73.08

Stock C:

Price Relative for January Year 3 = (33.00 / 40.00) * 100 ≈ 82.50

Price Relative for March Year 3 = (29.50 / 40.00) * 100 ≈ 73.75

Stock D:

Price Relative for January Year 3 = (6.50 / 20.00) * 100 ≈ 32.50

Price Relative for March Year 3 = (3.75 / 20.00) * 100 ≈ 18.75

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The value of the test statistic t for the given data is approximately -3.91.

To calculate the test statistic t for comparing the means of two samples, we can use the formula:

t = (ẋ₁ - ẋ₂) / √[(s₁² / N₁) + (s₂² / N₂)]

Given the following statistics:

Product 1:

N₁ = 17 (sample size)

ẋ₁ = 11 (sample mean)

s₁ = 1.0 (sample standard deviation)

Product 2:

N₂ = 12 (sample size)

ẋ₂ = 13 (sample mean)

s₂ = 1.1 (sample standard deviation)

Substituting these values into the formula, we get:

t = (11 - 13) / √[(1.0² / 17) + (1.1² / 12)]

Calculating the expression:

t = -2 / √[(0.05882352941) + (0.10083333333)]

 = -2 / √(0.15965686274 + 0.10083333333)

 = -2 / √(0.26049019607)

 = -2 / 0.51038048215

 ≈ -3.91

Therefore, the value of the test statistic t for the given data is approximately -3.91.

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The present value of the working capital cash flow expected to be received in year 10 is approximately $101,548.6.

The present value of the working capital cash flow expected to be received in year 10,  to discount it back to its present value using the after-tax cost of capital.

The present value (PV) :

PV = CF / (1 + r)²n

Where:

CF = Cash Flow in year 10

r = After-tax cost of capital

n = Number of years

The cash flow in year 10 is the liquidation of the working capital investment, which is $200,000. The after-tax cost of capital is 10%, which means the discount rate (r) is 0.10. The number of years (n) is 10.

After-tax cost of capital = Cost of capital × (1 - Tax rate)

= 10% × (1 - 30%)

= 0.10 × (1 - 0.30)

= 0.10 × 0.70

= 0.07

The present value of the cash flow:

PV = $200,000 / (1 + 0.07)²10

= $200,000 / (1.07)²10

= $200,000 / 1.967151

= $101,548.68

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Answer:

-16 - 5x = -16

-5X=-16+16

-5X=0

X=5

Step-by-step explanation:

Answer:

Step-by-step explanation:

a) 2x - y = 0

The probability of there being any boys is 0.75 or 75% and the probability of having only girls in the case of triples is 0.125 or 12.5%.

To determine the probability of there being any boys when pregnant with twins, we can make use of binomial distribution. The binomial distribution is used to calculate the probability of a specific number of successes in a fixed number of independent trials. For twins, there are three outcomes possible (1). Both girls, (2) Both boys, (3) One boy and One girl.

So, the probability of having any boys can be calculated by adding the probabilities of the (2) and (3) outcome.

The probability of having a baby boy is given as 0.5. So, the probability of having a girl will be 1 - 0.5 = 0.5.

Using the binomial distribution formula, the probability of getting k boys out of 2 babies can be calculated as follows:

\(P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)\)

Where:

P(X = k) is the probability of getting k boys,

n is the number of trials (2 babies),

k is the number of successful outcomes (boys),

p is the probability of success (probability of having a boy),

C(n, k) is the number of combinations of n items taken k at a time.

Now, let's calculate the probability of having any boys, atleast one boy for twins:

\(P(X > = 1) = P(X = 1) + P(X = 2)\\P(X = 1) = C(2, 1) * 0.5^1 * (1 - 0.5)^(2 - 1)\)

= 2 * 0.5 * 0.5

= 0.5

\(P(X = 2) = C(2, 2) * 0.5^2 * (1 - 0.5)^(2 - 2)\)

= 1 * 0.5^2 * 1^0

= 0.25

P(X >= 1) = 0.5 + 0.25

P(X >= 1) = 0.75

Now, let's see the case to find probability of having only have girls when pregnant with triplets.

Using the same binomial distribution formula, the probability of getting k girls out of 3 babies can be calculated as follows:

\(P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)\)

In this case, we have to calculate the probability of having only girls, so k= 0.

\(P(X = 0) = C(3, 0) * 0.5^0 * (1 - 0.5)^(3 - 0)\)

= 1 * 1 * 0.5^3

= 0.125

Therefore, the probability of there being any boys is 0.75 or 75% and the probability of having only girls in the case of triples is 0.125 or 12.5%.

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Answer: this is the answer--->\(4x^2+3x+10\)

Answer:

There are 15 Black tokens.

Step-by-step explanation:

If the ratio is 8:5 we divide 24 by 8 to get 3. We then do 5 x 3 for the black tokens and get 15.

The number of black tokens in the bag are 15.

What is mean by Ratio?

A ratio indicates how many times one number contain in another number. The ratio of two number is written as x : y, which is equivalent to x/y.

Where, x and y are individual amount of two quantities.

And, Total quantity gives after combine as x + y.

Given that;

In the bag, there are 24 green tokens in the bag.

And, The ratio of green tokens to black tokens is 8 to 5.

Now,

There are 24 green tokens in the bag.

And, The ratio of green tokens to black tokens is 8 to 5.

So, Number of green tokens = 8x

And,  Number of black tokens = 5x

Hence, We can formulate;

⇒ 8x = 24

⇒ x = 3

Thus, Number of black tokens = 5x

                                               = 5 × 3

                                               = 15

Therefore, The number of black tokens in the bag are 15.

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Step-by-step explanation:

t(150) = 400/570-150

=400/420

=20/21

=.95238

Answer:

D -6x + 2 = -15

Step-by-step explanation:

-4(3/2 x - 1/2) = -15

-4 × 3/2 x + (-4) × (-1/2) = -15

-6x + 2 = -15

Answer: D -6x + 2 = -15

Answer:

D

Step-by-step explanation:

Somehting bknbye3uehnfhnjun Español uno, como sulfhídrica

Answer: Mary will be 11, and yes you can

Step-by-step explanation: hector will be 16 in 8 years so you just add the 8 on to the 3

The new treatment for depression is effective in decreasing depression scores, and the researcher may proceed with caution.

The psychologist used a test statistic to compare the sample mean from her study to the mean of a national norm group to determine whether a new treatment for depression improves (decreases) depression scores. She obtains a t test statistic of -2.64 and a one-tailed probability of .02. The correct conclusion about results of the study is that the new treatment for depression is effective in decreasing depression scores.What is the correct conclusion about results of the study?The given study is a two-tailed hypothesis because it examines a difference in both directions. However, if the hypothesis states that one group would do better than the other, it becomes a one-tailed test.A probability value of 0.02 in a one-tailed test means that the null hypothesis is rejected if the sample data falls beyond the 2.5th percentile or 97.5th percentile of the standard normal distribution. The sample value is -2.64; this is beyond the 2.5th percentile of the standard normal distribution. As a result, the null hypothesis can be rejected.The mean score is lower (better) in the treatment group than in the population, according to the test. The new treatment for depression is effective in decreasing depression scores, and the researcher may proceed with caution.

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Step-by-step explanation:

Statements

1.RA equal RB

2.RP equal RP

3.RA is perpendicular to AP, RB is perpendicular to PB

4.right triangle RAP is congruent to Right triangle RBP

5.PA equal PB

Reasons

1.radii of same circle are equal

2.Reflexitive

3.Radius is perpendicular to tangent

4.HL

5 CPCTC

Answer:

RA = RB ----- radii of the same circles are =

RP = RP ----- reflexive

RA ⊥ AP, RB ⊥ PB ----- Radius congruent to tangent

rtΔ RAP ≅ rtΔ RBP ----- HL

PA = PB ----- CPCTE

The rectangular coordinates of the points of intersection of the polar curves r = 2sin(2θ) and r = 2sin(θ), the equations can be converted to rectangular form. However, solving the resulting system of equations algebraically may be challenging. Alternatively, graphing the polar curves and visually identifying the points of intersection can provide an effective method.

To find the rectangular coordinates of the points of intersection of the polar curves r = 2sin(2θ) and r = 2sin(θ), the equations can be converted to rectangular form, the rectangular coordinates of the above points are given below:

For the equation r = 2sin(2θ):

x = 2sin(2θ)cos(θ)

y = 2sin(2θ)sin(θ)

For the equation r = 2sin(θ):

x = 2sin(θ)cos(θ)

y = 2sin^2(θ)

The rectangular coordinates of the point(s) of intersection of the polar curves r = 2sin(2θ) and r = 2sin(θ) can be found by converting the polar equations to rectangular form and solving for the x and y coordinates.

To convert the polar equations to rectangular form, we can use the relationships x = rcos(θ) and y = rsin(θ). Substituting these expressions into the given polar equations, we get:

For the equation r = 2sin(2θ):

x = 2sin(2θ)cos(θ)

y = 2sin(2θ)sin(θ)

For the equation r = 2sin(θ):

x = 2sin(θ)cos(θ)

y = 2sin^2(θ)

To find the points of intersection, we need to set the x and y coordinates of both equations equal to each other and solve for θ. However, solving this system of equations algebraically can be complex due to the trigonometric functions involved.

Graphing the polar curves and visually inspecting the points of intersection may provide a more intuitive approach to finding the rectangular coordinates. By plotting both polar curves on a graph, the points where the curves intersect can be determined by their shared coordinates.

In summary, to find the rectangular coordinates of the points of intersection of the polar curves r = 2sin(2θ) and r = 2sin(θ), the equations can be converted to rectangular form. However, solving the resulting system of equations algebraically may be challenging. Alternatively, graphing the polar curves and visually identifying the points of intersection can provide an effective method.

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Answer:

HJ = 8  JE = 4

Step-by-step explanation:

it is given that H is the midpoint of GE and J is the midpoint of FE. According to the midpoint theorem the line segment connecting the midpoint of two sides is parallel to the three side and its length is half of the third side. since JH is connecting the midpoints.

HJ= 1/2 (GF)

x + 3 = 1/2 (4x - 4)

x + 3 = 2x - 2

x = 5

^ Thus meaning the value of x is 5.

Now you just fill into your equations:

HJ = x + 3 = (5)  + 3 = 8

JE = x - 1 = (5) - 1 = 4

Therefore, HJ = 8; JE = 4.

Answer:

HJ = 8

JE = 4

Step-by-step explanation:

Your welcome.

Answer:

C) 240ma

Step-by-step explanation:

Answer:

77 goles

Step-by-step explanation:

Un futbolista ha marcado 2/9 del número de goles marcados por su equipo.

Otro anotó una cuarta parte del resto.

El resto = 1 - 2/9

= 7/9

De ahí que otro futbolista anotó

= 1/4 de 7/9

= 7/36

Si los otros jugadores han marcado 45 goles

Tenemos que averiguar la fracción de goles que marcó el otro jugador

Deje que el número total de goles marcados por el equipo durante la temporada = 1

Por lo tanto:

1 - (2/9 + 7/36)

1 - (8 + 7/36)

1 - 15/36

1 - 5/12

= 7/12

¿Cuántos goles marcó el equipo a lo largo de la temporada?

El número total de goles que marcó ese equipo se calcula como:

7/12 × x = 45

Donde x = número total de goles

7x / 12 = 45

Cruz multiplicar

7x = 45 × 12

x = 45 × 12/7

x = 77,142857143

Aproximadamente = 77 goles

Answer:

Answer:

Step-by-step explanation:

Answer:

56/5

Step-by-step explanation:

\( \frac{0 \frac{4 \frac{y1 \frac{ { {. \frac{ {x}^{?} }{?} }^{2} }^{2} \times \frac{?}{?} \times \frac{?}{?} }{?} \times \frac{?}{?} \times \frac{?}{?} }{?} }{?} }{?} \)

\( {4445xx \frac{51}{?} \times \frac{?}{?} }^{?} \)

Answer: The answer is D

5n^7 - 11n^4 - 9n - 3

Step-by-step explanation: