Answer:
119.87 cm³Explanation:
The volume of a substance when given the density and mass can be found by using the formula
\(volume = \frac{mass}{density} \\\)
From the question we have
\(volume = \frac{935}{7.8} \\ = 119.871794...\)
We have the final answer as
119.87 cm³ to two decimal placesHope this helps you
what volume of dry carbon dioxide, measured at 25 degrees celsius and 785 mm hg, will result from the combustion of 2.50 g of pentane? the vapor pressure of water at 25 degrees celsius is 23.7 torr.
The volume of dry carbon dioxide is 55mL measured at 25 degrees Celsius and 785 mm hg, will result from the combustion of 2.50 g of pentane.
Carbon dioxide may be found in solid form as dry ice. Since CO2 does not have a liquid state at normal atmospheric pressure and instead sublimates directly from the solid state to the gas state, it is frequently used for short-term refrigeration. In addition to being utilised in fog machines in theatres for dramatic effects, it is largely employed as a cooling agent.
Its benefits include being colder than water ice and leaving no traces behind (apart from accidental frost from atmospheric moisture). It is helpful for keeping frozen items (like ice cream) from spoiling in situations when mechanical chilling is not possible.
At Earth's atmospheric pressure, dry ice sublimates at 194.7 K (78.5 °C; 109.2 °F). The solid is hazardous to handle without protection against frostbite injuries because to the intense cold. While typically not very toxic, the buildup in confined spaces can make the outgassing from it hypercapnic (abnormally elevated blood carbon dioxide levels).
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What is the molarity of a solution prepared by dissolving 30.0 grams of NaOH in enough water to make a solution with a total volume of 2.40 liters
Answer:
\( \fbox{0.3125 M}\)
Given:
Given mass of NaOH = 30 gramMolar mass of NaOH = 40 gramVolume = 2.40 litresTo find:
Molarity = ?
Solution:
Molarity is nothing but the number of moles of solute dissolved in per litre of solution. given by formula,
\(Molarity = \frac{given \: mass}{molar \: mass \times Volume}\)
\( \sf Molarity \: = \frac{30}{40 \times 2.4} = 0.3125 \: M\)
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A beaker contains 300.0 ml of a 0.20 M Pb(NO,), solution. If 200.0 ml of a 0.20 M solution of MgCl, is added to the beaker, what will be the final
concentration of Pb?* ions in the resulting solution?
(A) 0.020 M
(B) 0.040 M
(C) 0.080 M
(D) 0.120 M
(E) 0.150 M
Answer:
A.0.020 M
because Pb lead is added on only 300 ml breaker but it was not added in 200 ml breaker.
If you burn 27.827.8 g of hydrogen and produce 249249 g of water, how much oxygen reacted?
Approximately 222.4 grams of oxygen reacted in the combustion process. To determine the amount of oxygen that reacted, we can use the balanced chemical equation for the combustion of hydrogen:
2H₂ + O₂ → 2H₂O
From the equation, we can see that 1 mole of oxygen reacts with 2 moles of hydrogen to produce 2 moles of water.
First, we need to convert the given masses of hydrogen and water into moles using their molar masses:
Molar mass of hydrogen (H₂) = 2 g/mol
Molar mass of water (H₂O) = 18 g/mol
Mass of hydrogen in moles = 27.8 g / 2 g/mol = 13.9 mol
Mass of water in moles = 249 g / 18 g/mol = 13.8 mol
Since the stoichiometry of the reaction tells us that 2 moles of hydrogen react with 1 mole of oxygen, we can calculate the moles of oxygen consumed as:
Moles of oxygen consumed = 13.9 mol / 2 = 6.95 mol
Finally, we can convert the moles of oxygen to grams using its molar mass:
Molar mass of oxygen (O₂) = 32 g/mol
Mass of oxygen consumed = 6.95 mol × 32 g/mol = 222.4 g
Therefore, approximately 222.4 grams of oxygen reacted in the combustion process.
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1. We learned in chapter 3 that gases are compressible. How does the kinetic molecular theory explain this? 2. Name two independent ways (in terms of V and T) to increase the pressure of a gas inside a container without adding more gas. 3. What two variables are held constant in Boyle's law? 4. What is the partial pressure of oxygen gas (in percent) in normal air?
The kinetic molecular theory explains the compressibility of gases as gas particles are in constant, random motion and have negligible volume. When pressure is applied, the particles can be compressed due to their free movement.
Two independent ways to increase gas pressure without adding more gas are by decreasing volume or increasing temperature, while keeping the number of particles constant. Decreasing volume increases collisions and pressure, while increasing temperature raises particle speed and pressure.
The variables held constant in Boyle's law are temperature and the number of gas particles. Boyle's law states that pressure and volume are inversely proportional, so decreasing volume leads to increased pressure while temperature and particle number remain unchanged.
The partial pressure of oxygen gas in normal air is around 20.9%. This means oxygen contributes approximately 20.9% to the total pressure of the air mixture.
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Perform the following
mathematical operation, and
report the answer to the correct number of significant figures.
7.68 x 4.564 = [?]
Given the empirical formula of your compound is CH₂, what is the gram formula mass of the empirical formula?
Answer:
14g
Explanation:
The empirical formula of the compound is CH₂ ;
When we are dealing with compounds the gram formula mass or gram - molecular weight is the molar mass of the compound.
It is determined by adding the atomic masses of the components together and then expressed in grams.
Atomic mass of C = 12
Atomic mass of H = 1
Gram formula mass = 12 + 2(1) = 14g
the electron configuration for al is [ne] 3s2 3p1. which electron is the hardest to remove?
The electron configuration for Al is [Ne] 3s² 3p¹. The electron that is the hardest to remove is the one that has the lowest energy level and is closest to the nucleus of the atom.
Al is the chemical symbol for aluminum. It has an atomic number of 13 and is located in group 13 of the periodic table. It has three valence electrons, making it a member of the boron family.What is electron configuration?The electron configuration is a description of how the electrons in an atom are arranged. It is represented by a string of numbers and letters that indicate the energy levels, sublevels, and orbitals that the electrons occupy.What does [Ne] 3s² 3p¹ represent?The [Ne] in the electron configuration represents the electron configuration of the noble gas neon, which has an atomic number of 10 and a full valence shell. The 3s² 3p¹ represents the three valence electrons of aluminum that occupy the 3s and 3p orbitals. The electron that is the hardest to remove is the one that has the lowest energy level and is closest to the nucleus of the atom.In this case, the electron that is the hardest to remove is one of the 3p¹ electrons, which is located in the highest energy level and farthest from the nucleus.
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How is melting order related to the melting point of a substance?
solids are similar to liquids in that both are condensed states, with particles that are far closer together than those of a gas. However, while liquids are fluid, solids are not. The particles of most solids are packed tightly together in an orderly arrangement. The motion of individual atoms, ions, or molecules in a solid is restricted to vibrational motion about a fixed point. Solids are almost completely incompressible and are the densest of the three states of matter.
The standard potential for the reduction of agscn(s) is 0. 09 v. Agscn(s) e− ---→ag(s) + SCN−(aq).
Using this value and the electrode potential for Ag+(aq),
calculate the Ksp for AgSCN
The Ksp for AgSCN is 1.1 × 10⁻¹².
The half-reaction for the formation of AgSCN is: Ag⁺(aq) + SCN⁻(aq) → AgSCN(s)
The standard potential for this half-reaction is given as 0.09 V.
The standard potential for the reduction of Ag⁺ to Ag(s) is 0.80 V. Using the Nernst equation:
Ecell = E°cell - (RT/nF)lnQWe can calculate the equilibrium constant, Kc, for the reaction from the cell potential as:
Ecell = E°cell - (0.0257/n)logKcSubstituting the values:
0.80 = 0.09 + (0.0257/2)log(Kc/[Ag⁺][SCN⁻])Simplifying and solving for Kc:
Kc = [Ag⁺][SCN⁻]/[AgSCN] = 1.1 × 10⁻¹²Since the reaction is a 1:1 stoichiometry, we can use the Kc as the Ksp value for AgSCN. Therefore, the Ksp for AgSCN is 1.1 × 10⁻¹².
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what are the major ionic species of iron chloride
The major ionic species of iron chloride are Fe3+ and Cl-.
Iron(III) chloride (FeCl3) is a compound that consists of two ions: Fe3+ and Cl-. When dissolved in water, it forms an aqueous solution that contains both Fe3+ and Cl- ions. These ions are responsible for the chemical properties of iron(III) chloride, such as its solubility, reactivity, and color.
Chloride ion (Cl-) is an anion, which means that it has a negative charge. It is a halogen that is part of Group 17 of the periodic table. Iron(III) ion (Fe3+) is a cation, which means that it has a positive charge. It is a transition metal that is part of Group 8 of the periodic table.
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I'll give brianliest if correct .
Does a chemical reaction in a closed or open best supports the law of conservation of matter
Answer:
Normally, it explains that matter cannot be created or destroyed. It demonstrates different chemical reactions that help show the different transformations of the matter but will never destroy it or create it.
Which of the following answers correctly describes protons?
O A) Protons have a positive charge and are located outside of the atom's nucleus.
O B) Protons have a negative charge and are located inside the atom's nucleus.
OC) Protons have a positive charge and are located inside the atom's nucleus.
OD) Protons have a neutral charge and are located outside of the atom's nucleus
Identify the preferred site(s) of electrophilic attack on the following compound. ortho/para positions on ring 1 meta position on ring 1 ortho/para positions on ring 2 meta position on ring 2
The preferred site(s) of electrophilic attack on the given compound are ortho/para positions on ring 1.
What is electrophilic substitution?Electrophilic substitution is a type of organic reaction in which an electrophile substitutes a functional group or an atom in an organic compound. This occurs when an electrophile, a positive or partial positive charge, reacts with an electron-rich compound.
How to identify the preferred site(s) of electrophilic attack?When determining the preferred site(s) of electrophilic attack on a compound, one can consider the presence of an electron-donating group or an electron-withdrawing group. An electron-donating group causes the ortho and para positions to be more reactive than the meta position, while an electron-withdrawing group causes the meta position to be more reactive than the ortho and para positions.
In the given compound, the preferred site(s) of electrophilic attack are the ortho and para positions on ring 1. This is due to the presence of a strong electron-donating group (-NH2) on the ring that makes the ortho and para positions more reactive than the meta position. Hence, the correct option is ortho/para positions on ring 1.
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how many grams would be contained in 3.49 x 10^80 molecules of H2S04? ( the 80 is an exponent )
ANSWER
\(\text{ The mass of H}_2SO_4\text{ is 5.6886 }\times\text{ 10}^{58}\text{ grams}\)EXPLANATION
Given that;
\(\text{ The number of molecules of 3.49 }\times\text{ 10}^{80}\text{ }\)Follow the steps below to find the grams of H2SO4
Step 1; Find the number of moles of H2SO4 using the below formula
\(\text{ mole }=\text{ }\frac{\text{ Number of molecules}}{\text{ Avgadro's number }}\)Recall, that Avogadro's number is 6.02 x 10^23
\(\begin{gathered} \text{ mole = }\frac{\text{ 3.49}\times\text{ 10}^{80}}{6.02\text{ }\times\text{ 10}^{23}} \\ \\ \text{ mole = }\frac{3.49}{6.02}\times\text{ 10}^{80\text{ - 23}} \\ \text{ mole = 0.58 }\times\text{ 10}^{57} \\ \text{ mole = 5.8 }\times\text{ 10}^{56}\text{ moles} \end{gathered}\)Step 2; Find the mass of H2SO4 using the formula below
\(\begin{gathered} \text{ mole = }\frac{\text{ mass}}{\text{ molar mass}} \\ \text{ cross multiply} \\ \text{ mass = mole }\times\text{ molar mass} \end{gathered}\)Recall, that the molar mass of 98.079 g/mol
\(\begin{gathered} \text{ mass = 5.8 }\times\text{ 10}^{56}\times\text{ 98.079} \\ \text{ Mass = 5.8 }\times\text{ 98.079 }\times\text{ 10}^{56} \\ \text{ Mass = 568.86 }\times\text{ 10}^{56} \\ \text{ Mass = 5.6886 }\times\text{ 10}^{58}\text{ grams} \end{gathered}\)Which two events will happen if more H2 and N2 are added to this reaction after it reaches equilibrium?
3H2 + N2 to 2NH3
If more \(H_{2}\) and \(N_{2}\) are added to the reaction 3\(H_{2}\) + N2 → 2\(NH_{3}\) after it reaches equilibrium, two events will occur Shift in Equilibrium and Increased Yield of \(NH_{3}\)
1. Shift in Equilibrium: According to Le Chatelier's principle, when additional reactants are added, the equilibrium will shift in the forward direction to consume the added reactants and establish a new equilibrium. In this case, more \(NH_{3}\) will be produced to counteract the increase in \(H_{2}\) and \(N_{2}\).
2. Increased Yield of \(NH_{3}\): The shift in equilibrium towards the forward reaction will result in an increased yield of \(NH_{3}\). As more \(H_{2}\) and \(N_{2}\) are added, the reaction will favor the production of \(NH_{3}\) to maintain equilibrium. This will lead to an increase in the concentration of \(NH_{3}\) compared to the initial equilibrium state.
It is important to note that the equilibrium position will ultimately depend on factors such as the concentrations of \(H_{2}\), \(N_{2}\), and \(NH_{3}\), as well as the temperature and pressure of the system. By adding more reactants, the equilibrium will adjust to achieve a new balance, favoring the formation of more \(NH_{3}\).
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into both ends of a meter-long glass tube samples of gases are introduced simultaneously. one end receives hydrogen chloride gas (hcl) while the other end receives ammonia gas (nh3). when the gases meet in the tube, they react to form solid ammonium chloride (nh4cl). where in the tube does the nh4cl form?
Option (B) closer to the end where HCl was introduced is correct because, according to Graham's Law of Diffusion, The Rate of diffusion is indirectly proportional to 1/√(Molar. mass).
The ammonium chloride (NH₄Cl) will form primarily in the middle of the glass tube, where the two gases (NH₃ and HCl) are first able to react with one another. This is because the gases travel through the tube at different velocities, so the reaction will occur where the gases first meet.
As the reaction progresses, the ammonium chloride will continue to form until the reaction is complete and the tube is filled with the solid product.
The reaction of the two gases is reversible, meaning that the NH₄Cl can also break down back into NH₃ and HCl. However, as the gases continue to travel through the tube, the reaction rate of the NH₄Cl breaking down is much slower than the rate at which it is formed.
Therefore, the majority of the ammonium chloride will form in the middle of the tube where HCl is introduced.
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How many neutrons are in the nucleus of a potassium atom with a mass number of 39?.
Answer:
20 neutrons
Explanation:
neutrons = mass number - atomic number
mass number = 39, atomic number = 19
neutrons = 39 - 19 = 20
Does chlorine have a smaller ionic radius than soium.
Answer:
sodium atoms are much larger than chlorine atoms but in case of sodium ions they are much smaller thqn chlorine ions
You heat two substances, A and B. Both substances change color. When cooled, both substances return to their original colors.
What most likely happened in this situation?
A chemical change occurred in both substances.
A physical change occurred in both substances.
A physical change occurred in substance A, and a chemical change occurred in substance B.
A chemical change occurred in substance A, and a physical change occurred in substance B.
Answer:
B: Physical change occurred in both substances.
Explanation:
Physical change vs chemical change.
Physical change, a substance's appearance changes, but its matter does not.
Chemical change, a type of matter that changes, and also new substance is formed with new properties.
Since one thing happened on both, the correct answer is B.
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Side groups of amino acids are typically classified under which of the following?
A) polar, nonpolar
B) linear, circular
C) alpha, omega
D) long, short
E) primary, secondary
Side groups of amino acids are typically classified as A) polar or nonpolar.
Amino acids are the building blocks of proteins and are composed of an amino group (-NH2), a carboxyl group (-COOH), and a side chain that is unique to each amino acid. The side chains can be classified as either polar or nonpolar based on their chemical properties.
Polar side chains contain functional groups such as -OH or -NH2 that can participate in hydrogen bonding with water or other polar molecules. Examples of polar amino acids include serine (Ser), threonine (Thr), and asparagine (Asn).
Nonpolar side chains, on the other hand, are hydrophobic and do not interact with water or other polar molecules. These side chains are typically composed of hydrocarbons and can be further divided into aliphatic or aromatic categories. Examples of nonpolar amino acids include glycine (Gly), alanine (Ala), and phenylalanine (Phe).
In summary, side groups of amino acids are classified as polar or nonpolar based on their chemical properties.
So A is correct option.
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Find the valance shell and valance electron nitrogen
Answer:
The number of valence electrons is the number of electrons in the outer shell, that the atom uses for bonding. Nitrogen has 5 electrons in its n=2 (outer) shell. There is a quick way of identifying the number of valence electrons - it is the same as the Group number.
Explanation:
14. The atoms of element X contains nineteen electrons. With which of the following elements will the chemistry of Z be similar? a Aluminum b) Bromine c) Lithium d) Magnesium
First of all, Z is unknown. I hope it is a mistake.
Now, it is given that the element X has nineteen electrons. This proves that X is actually Potassium.
As per the periodic table, both Potassium and Lithium belongs to group 1 as their valency is 1 because of the presence of only one electron in the outermost shell of electrons i.e., they lose an electron during a chemical reaction to form a stable compound. Furthermore, both are metallic.
Magnesium belongs to group 2 and hence its valency is two, which is different from potassium though it is metallic. Similiarly, bromine belongs to group 17 and gains one electron during a reaction in contrast to potassium.
( No internal links available for reference. For clarification, check the periodic table).
why do not all paramagnetic complexes obey the spin only formula
Paramagnetic complexes are those complexes that have unpaired electrons in their d-orbitals.
According to the spin-only formula, the magnetic moment of a paramagnetic complex is directly proportional to the number of unpaired electrons. However, not all paramagnetic complexes obey this formula. This is because the spin-only formula assumes that the only interaction between the electrons is due to their spin. However, in reality, the electrons also interact with each other through their orbital motion, and this interaction can affect the magnetic moment of the complex.
For example, consider the complex [Co(NH3)6]3+. According to the spin-only formula, it should have a magnetic moment of 3.87 BM (Bohr magnetons) due to its three unpaired electrons. However, the actual magnetic moment of the complex is only 3.3 BM. This is because the six ammonia ligands around the cobalt ion cause the d-orbitals to split into two sets with different energies, known as the crystal field splitting.
The three unpaired electrons occupy the lower energy set of d-orbitals, but they also experience repulsion from each other due to their negative charges. This causes them to occupy different orbitals and results in a weaker magnetic moment than predicted by the spin-only formula.
Thus not all paramagnetic complexes obey the spin-only formula because it does not take into account the interaction between electrons through their orbital motion. The crystal field splitting and electron-electron repulsion can affect the magnetic moment of the complex, resulting in a deviation from the spin-only formula.
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for the following reaction, 18.6 grams of chlorine gas are allowed to react with with 3.82 grams of water. chlorine (g) water (l) hydrochloric acid (aq) chloric acid (hclo3) (aq) what is the maximum amount of hydrochloric acid that can be formed? grams what is the formula for the limiting reagent? subscriptsuperscript help what amount of the excess reagent remains after the reaction is complete? grams
18.6 grams of chlorine gas are allowed to react with with 3.82 grams of hydrogen to form hydrochloric acid.
H2+Cl2 → 2HCl
At normal temperature and pressure, hydrogen chloride (HCl), a gas composed of the elements hydrogen and chlorine, is a gas. Hydrochloric acid is the name given to a gaseous solution in water. Chlorine (Cl2) gas and hydrogen (H2) gas can be combined directly to generate hydrogen chloride; the process is quick at temperatures above 250 °C (482 °F). Heat is released during the reaction, which is described by the equation H2 + Cl2 2HCl, and moisture seems to speed up the process. A chloride, often sodium (NaCl) chloride, is typically used to create hydrogen chloride both in laboratories and on an industrial scale by reacting with sulfuric acid (H2SO4). Additionally, it is created when certain chlorides (such as phosphorus trichloride, PCl3,
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Suppose a fox population exists in an ecosystem. Some of the foxes maintain a heavy coat year-round, while others shed their heavy coat in the summer. Summers in this ecosystem
are becoming steadily hotter because of global warming. Which members of the species will most likely be able to adapt to the changing temperatures?
subject science
Answer:
The fox who shed their heavy coat in the summer.
Explanation:
If a fox has the ability to shed its coat in the summer, it will have no difficulties adapting to new temperatures even during winter. However, the heavy-coated one will.
arrange 0.35 kilograms 9.4 grams and 5 grams to smallest to largest
Answer:
5 grams < 9.4 grams < 0.35 kilograms
Explanation:
Kilograms (Kg) and grams (g) are both units of measurement for MASS quantity. However, these units are not the same as they vary in magnitude. The kilograms is bigger unit of measurement than the grams. 1000grams makes 1kilograms.
According to this question, 0.35 kilograms 9.4 grams and 5 grams are to be arranged in ascending order i.e. from smallest to largest. First, we need to change all the units to the same.
We change 0.35kg to g
Since 1000g = 1kg
Then, 0.35kg = 0.35 × 1000
= 350g.
Rearranging the values, we have:
5 grams < 9.4 grams < 0.35 kilograms
Si un elemento químico tiene un numero atomico z=12, y es un atomo neutro (igual cantidad de electrones y protones), ¿Cual es la configuracion electronica esperada?
Answer:
1s² 2s² 2p⁶ 3s²
Explanation:
La configuración electrónica muestra la secuencia de llenado de electrones en los orbitales de los subniveles guiada por algunos principios.
El número máximo de electrones en los orbitales de los subniveles es dos para el subnivel s (un orbital); seis para el subnivel p (tres orbitales); diez para el subnivel d (cinco orbitales) y catorce para el subnivel f (siete orbitales). Esto indica que el número máximo de electrones en un orbital es dos.
Se sabe que un elemento químico que tiene un número atómico Z = 12 y es un átomo neutro es Magnesio (Mg). Sin embargo, dado que tiene el mismo número de protones y electrones; La configuración electrónica esperada se puede escribir como:
1s² 2s² 2p⁶ 3s²
A reaction is in equilibrium as shown: A + B C + D. Calculate the equilibrium constant in the final concentrations stabilized at: A= 9.6 M B= 10.0 M C= 4.0 M D= 4.0 M K =
Answer:
K = 0.167
Explanation:
The equilibrium constant, K of a reaction, is defined as the ratio of the concentrations of products and concentrations of reactants.
For the reactions:
A + B ⇄ C + D
For the definition, K is:
K = [C] [D] / [A] [B]
K = [4.0M] [4.0M] / [9.6M] [10.0M]
K = 0.167