Calculate the pH of 15 mL of water after 0.15 mL of 1 M HCl is added.

Mass of water vapor = 193 g

Given

435 kJ of heat are released

Required

mass of water vapor

Solution

The heat to change the phase can be formulated :

Q = mLf (melting/freezing)

Q = mLv (vaporization/condensation)

Lv for water = 2256 kJ/kg or 2256 J/g or 40.7 kJ/mol

So the mass of water vapor :

\(\tt m=\dfrac{Q}{Lv}\\\\m=\dfrac{435000~J}{2256~J/g}\\\\m=192.8\approx 193~g\)

When a and b are mixed on the surface of an object, a chemical reaction takes place called a Combination reaction.

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Answer:

It's a metaphor. It's comparing Jordan and their emotions to a tornado

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The mass of a sample of copper (II) sulfate containing 2.56 x \(10^{23\) atoms of copper would be 27.52 grams.

According to Avogadro, 1 mole of every substance contains 6.022 x \(10^{23\) molecules or atoms of the substance.

Following this principle, the amount, in moles. of copper (II) sulfate present in 2.56 x \(10^{23\) atoms of the substance would be:

6.022 x \(10^{23\)  atoms = 1 mole

2.56 x \(10^{23\) atoms = 2.56 x \(10^{23\) /6.022 x \(10^{23\)

                             = 0.43 mol

Recall that: mass = mole x molar mass

Mass of 0.43 mol copper = 0.43 x 64

                                          = 27.52 grams.

In other words, a sample of copper (II) sulfate containing 2.56 x \(10^{23\) atoms of copper will contain 27.52 grams of copper.

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Answer:

-1 that's it I think so..........

For the first tetrahedral center, the configuration is R. For the second tetrahedral center, the configuration is S.

The central carbon has an in-plane bond to methyl pointing to the lower left, an in-plane bond to hydrogen pointing up, a wedged bond to NH2 pointing to the lower right, and a dashed bond to ethyl pointing to the lower right.

The central carbon has an in-plane bond to an alkene or vinyl group pointing to the lower left, an in-plane bond to hydrogen pointing to the lower right, a wedged bond to bromine pointing up, and a dashed bond to methyl pointing up.

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Answer:

A) Paired

Explanation:

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Answer:

it should be chemical

Explanation:

Answer:

b. .28 M KCI

Explanation:

Use the dilution formula.

C₁V₁ = C₂V₂

C₂ = C₁V₁/V₂

C₂ = 1.6*0.175 / 1.0

C₂ = 0.28

The new concentration of the solution of KCl which is diluted to a new volume of 1.0 L is  0.28 M KCI.

Concentration is the abundance of substance or constituent divided by the volume of the mixture.

By the dilution formula

C₁V₁ = C₂V₂

C₂ = C₁V₁/V₂

The concentration is 1.6 M

The volume of KCl is 0.175

The new volume v2 is 1.0 l

Putting the values in the equation

C₂ = 1.6 × 0.175 / 1.0

C₂ = 0.28

Thus, the correct option is b. 0.28 M KCI.

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Answer:

To make sure all the sulphuric acid has been used up

Two common methods used to specify experimental uncertainty are: Standard deviation and Confidence intervals.

Standard deviation: This is a measure of the spread of a set of data points around the mean. It is calculated as the square root of the variance and gives an indication of the precision of the measurement.

Confidence intervals: This is a range of values that is likely to contain the true value of a population parameter with a specified degree of confidence. Confidence intervals are often used to indicate the precision of an estimate and to quantify the uncertainty associated with a measurement.

Both of these methods provide valuable information about the uncertainty associated with a measurement and can be used to make informed decisions based on the results of an experiment.

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Due to its tiny size and high charge, lithium ion is most likely to combine with OH- to produce a soluble ionic molecule. Although they have a lower solubility, Ag+, Pb2+, Ni2+, and Zn2+ can also form ionic compounds.

With potassium cation  and hydroxide anion , the +1 charge already counterbalances the -1 charge, without the need for additional cations or anions. This indicates that to create a neutral chemical with the formula , one unit of each ion must be added.

When naming binary ionic compounds, the nonmetal anion (element stem + -ide) comes after the cation (specifying the charge, if necessary). Without employing prefixes, it is possible to tell from the compound name how many of each element are present.

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Answer:

A FUSE is a type of conductor which protects the circuit by shorting it down when there is excess flow of current passing through it.

Explanation:

A fuse wire is made up of conducting materials such as alloy of tin and lead that has high resistivity. It has a low melting point of 200°C. It works based on the principle of heating effect of electric current. The functions of fuses include the following:

--> Fuses are made up of thin wire CONDUCTORS which interrupts or breaks the current flow of a circuit when in excess, thereby protecting the circuit from damage.

--> it prevents overload of current. In the event where too many appliances are connected to a single circuit, this can lead to overload which triggers a fuse to terminate the circuit connection.

--> It prevents total black-out: SWITCH-LIKE devices known as CIRCUIT BREAKERS share this function with the fuses. The nearest circuit breaks if any dysfunction occurs in the components of the circuit thereby preventing blackout.

Answer:

On the reactant side, there are two H atoms and two O atoms

There are a total of 4 hydrogen atoms on the reactant side of the balanced equation.

On the reactant side of the balanced equation, there are no hydrogen atoms present.

The balanced equation for the reaction between calcium carbide (CaC2) and water is:

CaC2 + 2H2O → C2H2 + Ca(OH)2

In this equation, the reactant side consists of CaC2 and 2H2O. CaC2 does not contain any hydrogen atoms, while 2H2O represents two molecules of water, each containing two hydrogen atoms. Therefore, the total number of hydrogen atoms on the reactant side is 2 (hydrogen atoms in one molecule of water) multiplied by 2 (two molecules of water), which equals 4 hydrogen atoms.

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Answer:

Explanation:

The energy of combustion per gram of hydrogen using a bomb calorimeter with heat capacity of 11.3 kj/c is 180.83 kj/g.

To calculate the energy of combustion per gram of hydrogen using a bomb calorimeter, we need to use the formula:

Energy of combustion = heat capacity x mass of substance x temperature increase

First, we need to convert the mass of hydrogen from grams to moles. The atomic weight of hydrogen is 1.008 g/mol, so:

1.15 g / 1.008 g/mol = 1.14 mol of hydrogen

Now, we can calculate the energy of combustion:

Energy of combustion = 11.3 kj/c x 1.14 mol x 14.3 c
Energy of combustion = 182.09 kj/mol

To get the energy of combustion per gram of hydrogen, we need to divide by the number of grams in one mole of hydrogen:

182.09 kj/mol / 1.008 g/mol = 180.83 kj/g

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The balanced equation for the reaction of iron with water that results in the production of iron oxide and hydrogen gas is

3 Fe (s) + 4H₂O (g) → Fe₃O₄ (s) + 4H₂ (g)

Iron does not react directly with liquid water but react with water vapour. When the reaction happens, it results in the formation of a solid and a gas. The products of the reaction are Iron oxide and hydrogen. The equation of the reaction would be

Fe (s) + H₂O (g) → Fe₃O₄ (s) + H₂ (g)

Now, we need to balance the equation. On the right-hand side, we have 3 Fe, 4 O and 2 H. Similarly on the left-hand side there are 1 Fe, 1 O and 2 H.

To balance the equation, we add 3 to Fe, 4 to H₂0 and 4 to H₂.

As a result, the balanced chemical equation for the reaction would be

3 Fe (s) + 4H₂O (g) → Fe₃O₄ (s) + 4H₂ (g)

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(a) To determine if this can be done, we need to calculate the maximum amount of polysilicon that can be etched while keeping the SiO2 removal below 50 Å.

Let's assume the initial thickness of SiO2 is 1000 Å. Since the selectivity is 30, the maximum amount of polysilicon that can be etched is:

50 Å * (1/30) = 1.67 Å

Now, taking into account the overetch of 10%, the total amount of polysilicon that can be etched is:

1.67 Å / (1-0.1) = 1.85 Å

So, we need to etch a maximum of 1.85 Å of polysilicon.

The total thickness of the polysilicon and SiO2 layers is:

0.35 um + 1000 Å = 1350 Å

To find the required polysilicon uniformity, we can use the following equation:

(1 - uniformity) * 0.35 um = 1.85 Å

Solving for uniformity, we get:

uniformity = 1 - (1.85 Å / 0.35 um) = 0.9947 or 99.47%

So, the required polysilicon uniformity is 99.47%.

(b) To find the maximum polysilicon film thickness, we can use the same approach as above.

Let's assume the initial thickness of SiO2 is 1000 Å. The maximum amount of polysilicon that can be etched is:

50 Å * (1/30) = 1.67 Å

The total thickness of the polysilicon and SiO2 layers cannot be less than:

1000 Å + 50 Å + 1.67 Å = 1051.67 Å

So, the maximum polysilicon film thickness is:

1051.67 Å - 1000 Å = 51.67 Å

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Answer:

B: electronegativity

Explanation:

Electronegativity is the measure of how strongly atoms attract bonding electrons to themselves.

A is incorrect because Atomic radius though decreases as you go from lithium to fluorine of the periodic table. Atomic radius increases when you go from either top to bottom of the periodic table, or if you go from right to left. So answer A is inaccurate.

C is incorrect because in period 2, all the elements have two electron subshells. For example, Al has 13 electrons. So it has two electron subshells. This is since the first subshell has only two valence electrons and while the second subshell in Al has 11 valence electrons. Therefore, it is inaccurate to say this answer.

D is incorrect because in the first shell, you can only have a max of two electrons. The first shell neither decreases or increases. Therefore, D is inaccurate too.

B is correct because as you go from the periodic table from left to right, the electronegativity and ionization energy increases. This is since the more valence electrons an element has, the more electronegative is.  Fluorine for example is desperately trying to get one more electron to have a total of 8 electrons. It wants to have a full shell. Therefore, B is the most relevant answer.

As the chemical elements in Period 2 are considered in order from lithium to fluorine, there is an  increase in: B)  electronegativity.

On a periodic table, the horizontal columns represents the periods of chemical elements in ascending order such as from lithium (Li) to fluorine (F).

Electronegativity can be defined as a measure of the ability (tendency) of an atom of a chemical element to attract any shared pair of electrons.

Generally, the electronegativity of a chemical element typically increases across the period from left to right.

For example,  electronegativity increases from lithium (Li) to fluorine (F) in Period 2 on a periodic table.

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Answer:

4

Explanation:

oxidation number resolved 4

The oxidation state of an element is calculated by subtracting and the total sum of oxidation states of all the individual atom (excluding the one that has to be calculated) from total charge on the molecule. Therefore, the oxidation state of phosphorous in H\(_2\)PO\(_2\)⁻ is  +1.

Oxidation state of an element is a number that is assigned to an element in a molecule that represents the number of electron gained or lost during the formation of that molecule or compound.

P\(_4\)  \(\rightarrow\) H\(_2\)PO\(_2\)⁻

Oxidation number of P=0

Oxidation number of P in H\(_2\)PO\(_2\)⁻

(+1)×2+ Oxidation number of P + (-2)2 = -1

2 + Oxidation number of P -4 = -1

Oxidation number of P= +1

Therefore, the oxidation state of phosphorous in H\(_2\)PO\(_2\)⁻ is  +1. The oxidation state of phosphorous in P\(_4\) is 0.

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Answer:

C₄H₁₂ + 7O₂ --> 4CO₂ + 6H₂O

Explanation:

Organic molecules react with O2 to create water and CO2 in combustion processes. C4H12 is an organic molecule that combines with O2 to create water and CO2 as shown in the reactions.

As a result, this is the sole reaction that obeys the general combustion equation.

The additional calcium hydroxide will react with some of the hydrochloric acid, leading to a higher consumption of the acid for the analysis.

If solid calcium hydroxide is inadvertently transferred along with the saturated liquid for analysis, the following effects can be expected:
a) More hydrochloric acid will be used for the analysis in part a. This is because calcium hydroxide reacts with hydrochloric acid to form calcium chloride and water according to the following equation:
Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O
b) The molar solubility of calcium chloride will decrease due to the additional calcium hydroxide. This is because calcium hydroxide reacts with calcium chloride in the solution to form calcium carbonate, which is insoluble in water:
CaCl₂ + Ca(OH)₂ → CaCO₃ + 2H₂O
As a result, more calcium carbonate will precipitate out of the solution, leading to a decrease in the molar solubility of calcium chloride.
c) The solubility product constant (Ksp) of calcium hydroxide will increase due to the additional solid. This is because the presence of more calcium hydroxide will increase the concentration of calcium and hydroxide ions in the solution, shifting the equilibrium towards the formation of more solid calcium hydroxide. This will increase the value of Ksp, indicating a higher degree of saturation of the solution with respect to calcium hydroxide.

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We are given:

Volume of gas = 3.8 L

Pressure = 460 mmHg

Temperature = 77°c = (77+273)K = 350K

Converting the pressure to atm:

Pressure(in atm)  = Pressure(in mmHg) / 760

Pressure = 460/760 = 0.6 atm

Finding the number of moles:

using the ideal gas equation:

PV = nRT                                         [where R is the universal gas constant]

replacing the given values in this equation

(0.6)(3.8) = n(0.082)(350)

n = (0.6*3.8)/(0.082*350)

n = 0.08 moles

Explanation:

To find the isotope that is expected to be radioactive we have to compare the given isotopes with the ones that we find the in the periodic table.

(A) Ti:

Isotope ----> atomic mass = 48 atomic number = 22

Periodic table ---> average atomic mass = 47.9 atomic number = 22

(B) Sr:

Isotope ----> atomic mass = 88 atomic number = 38

Periodic table ---> average atomic mass = 87.6 atomic number = 38

(C) Os:

Isotope ----> atomic mass = 192 atomic number = 76

Periodic table ---> average atomic mass = 190.2 atomic number = 76

(D) Pu:

Isotope ----> atomic mass = 244 atomic number = 94

Periodic table ---> average atomic mass = 244 atomic number = 94

If we take a look at them we will see that the only one that is different is osmium. The atomic mass of the isotope is 192 amu, that means that this isotope has 2 more neutrons than the average atom of the element. So we can expect that it could be radioactive.

Answer: C. Os

The mass of Potassium in 34.8 g of Potassium Iodide is 8.20g.

To determine the mass of potassium (K) in 34.8 g of potassium iodide (KI), we can use the concept of molar mass and stoichiometry.

First, calculate the molar mass of KI, which is the sum of the molar masses of potassium (K) and iodine (I). Potassium has a molar mass of 39.10 g/mol, and iodine has a molar mass of 126.90 g/mol. The molar mass of KI is 39.10 g/mol + 126.90 g/mol = 166.00 g/mol.

Next, we can find the moles of KI in the given mass. Moles of KI = (34.8 g) / (166.00 g/mol) = 0.2096 moles.

Since the ratio of potassium to iodide in KI is 1:1, there are also 0.2096 moles of potassium present. Now, we can find the mass of potassium by multiplying the moles of potassium by its molar mass:

Mass of potassium (K) = (0.2096 moles) x (39.10 g/mol) = 8.1976 g

So, there are approximately 8.20 g of potassium in 34.8 g of potassium iodide (KI).

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