Calculate the pH of 0.046 M HClO4.a. 0.046b. 7.00c. 1.34d. 12.66e. none of these

Answer:

375.3KJ

Explanation:

The following data were obtained from the question:

Mass of water = 166g

Heat of Vaporisation (ΔHv) = 40.7kJ/mol

Heat (Q) =..?

Next, we shall determine the number of mole in 166g of water. This is illustrated below:

Mass of H2O = 166g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Number of mole = Mass/Molar Mass

Number of mole of H2O = 166/18

Number of mole of H2O = 9.22 moles.

Now, we can obtain the heat required to vaporise the water as shown below:

Q = n·ΔHv

Q = 9.22 mol x 40.7kJ/mol

Q = 375.3KJ

Therefore, the heat required to vaporise the water is 375.3KJ.

Answer:

24

Explanation:

52-28=24

Answer:

??

Explanation:

Answer:

The organisms that eat the producers are the primary consumers. They tend to be small in size and there are many of them. ... Because of this inefficiency, there is only enough food for a few top level consumers, but there is lots of food for herbivores lower down on the food chain.

Explanation:

The sentence that describe the merits of a career in transportation distribution, and logistics is that TDL expert work in the collaborative environment that values the team work. Thus, option (B) is correct.

The planning, management, and movement of people, materials,  as wel as goods by road, pipeline,  can be seen as th functions of the transportation, distribution, and logistics career cluster.

They are in charge of overseeing all organizational transportation-related matters in terms of execution, direction, and coordination which could invlves the act of planning routes and schedules,  as well as making cars  safe and compliant with the law.

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The elements arranged in increasing order of the most positive electron affinity for each group are:

(a) Li, Na, K

(b) I, Br, Cl, F

(c) Ba, Ca, Si, P, O

(a) Li, Na, K: In this group, the electron affinity increases as we move from left to right in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are Li, Na, and K.

(b) F, Cl, Br, I: In this group, the electron affinity generally increases as we move from left to right and from bottom to top in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are I, Br, Cl, and F.

(c) O, Si, P, Ca, Ba: In this group, the electron affinity generally increases as we move from left to right and from top to bottom in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are Ba, Ca, Si, P, and O.

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It is because the high temperature superconductor was more affordable، easy to use and more efficient than before.

Hope it helps you...

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Answered by Benjemin

1. Fluid compressibility (C): Fluid compressibility refers to the measure of how much a fluid's volume changes in response to a change in pressure.

2. Solution-gas/liquid ratio (SGLR): The solution-gas/liquid ratio represents the volume of gas dissolved in a given volume of liquid at a specific pressure and temperature.

3. Fluid formation volume factor (FVF): The fluid formation volume factor represents the ratio of the volume of a fluid at reservoir conditions (pressure and temperature) to its volume at surface conditions.

4. Fluid densities (ρ): Fluid densities refer to the mass per unit volume of a fluid.

5. Fluid viscosities (μ): Fluid viscosities represent the measure of a fluid's resistance to flow.

1.  Equation: C = -1/V * dV/dP

  Symbol: C

  Unit: 1/Pascal (Pa^-1)

  Correlation: The compressibility of fluids can vary depending on the fluid type. For ideal gases, the compressibility is inversely proportional to pressure.

2.Equation: SGLR = V_gas / V_liquid

  Symbol: SGLR

  Unit: Volumetric ratio (e.g., scf/bbl)

  Correlation: The solution-gas/liquid ratio is influenced by the pressure and temperature conditions, as well as the composition of the fluid.

3. Equation: FVF = V_reservoir / V_surface

  Symbol: FVF

  Unit: Volumetric ratio (e.g., bbl/STB)

  Correlation: The fluid formation volume factor depends on the composition and properties of the fluid, as well as the reservoir conditions.

4. Equation: ρ = m / V

  Symbol: ρ

  Unit: Mass per unit volume (e.g., kg/m^3)

  Correlation: Fluid densities can vary depending on the type and composition of the fluid. For example, water has a density of approximately 1000 kg/m^3.

5. Equation: No single equation; viscosity is measured experimentally using viscometers.

  Symbol: μ

  Unit: Pascal-second (Pa·s) or centipoise (cP)

  Correlation: The viscosity of a fluid is influenced by temperature and pressure. Different fluids exhibit different viscosities, ranging from low-viscosity fluids like water to high-viscosity fluids like heavy oil.

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Answer:

dhuqhruhqhuehauhrergre

Explanation:

Answer:

See the answer below

Explanation:

In chemistry, indicators are substances that are capable of changing colors with respect to the pH. Each indicator has its characteristic color in acidic pH and another characteristic color in alkaline pH.

Methyl orange indicator appears red in acidic solution and yellow in basic solutions. Phenolphthalein is usually colorless in acidic solutions and appears pink in basic solutions. A red litmus paper will turn blue in alkaline solutions while a blue litmus paper will turn red in acidic solutions.

Answer:

The first question is option 2

and the second question in option 1

Explanation:

Answer:

He numbered these orbits due to their location.

Explanation:

Scientist Neil Bohr in his atomic model describes that electrons are moving with high velocity in circular paths around the nucleus is called shells or orbits. As long as electrons are in their particular orbit their energy is constant. He named those orbits as K- shell, L- shell and M- shell etc. When the electron absorb energy, it is able to jump to the next shell and comes back to its original shell when it loses energy. He also give numbers i.e. 1,2,3,4 to the shells due to their nearness to the nucleus. Shell 1 is near to the nucleus whereas shell 4 is farther from the nucleus.

Answer: 10^-11

Explanation:

to find the concentration of H+ ions given the ph, we use the formula 10^(-pH).

so 10^-11

Answer:

Carbon dioxide

Explanation:

Carbon dioxide gas is used by plants for the preparation of food materials. During this food preparation process, plants take up carbon dioxide from the air and give up oxygen.

Answer:

The optimum ratio found through the loudness test represents the ratio of oxygen to hydrogen where the most efficient combustion occurs. When hydrogen and oxygen combine in the correct ratio, a chemical reaction occurs that produces a loud "pop" sound and releases energy in the form of heat and light.

The balanced chemical equation for the reaction between hydrogen and oxygen is:

2H2 + O2 -> 2H2O

This equation shows that two molecules of hydrogen react with one molecule of oxygen to produce two molecules of water. If there is not enough oxygen present, the reaction will be incomplete and unreacted hydrogen will remain. If there is too much oxygen present, the excess oxygen will not react and will simply be wasted.

Therefore, the optimum ratio of oxygen to hydrogen is the ratio where all of the hydrogen is completely reacted with the oxygen, and no excess oxygen is present. This ensures the most efficient combustion and the maximum release of energy in the form of heat and light.

Answer:

(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl

Explanation:

This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.

An iceberg has a volume of 7670 cubic feet. The mass of the ice (in kg) composing the iceberg is 0.0002483 kg

The volume of iceberg = 7670 cubic feet.

Density of ice = 0.917 g/cm\(^{3}\)

so, Density is given by,

Density = mass / volume

density of ice =  (0.917 /1000) kg/cm\(^{3}\)

1 cm\(^{3}\) = 0.00003531 ft\(^{3}\)

therefore,

0.000917 kg/cm\(^{3}\) = (0.000917 × 0.00003531 ) kg/ft\(^{3}\)

                            = 0.0000000324 kg/ft\(^{3}\)

now,putting the values in formula , we get,

Density = mass / volume

mass = density × volume

         = (0.0000000324 × 7670 ) kg

         = 0.0002483 kg

Hence,An iceberg has a volume of 7670 cubic feet. The mass of the ice (in kg) composing the iceberg is 0.0002483 kg.

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1. The initial pH of the solution is 1.89.

2. At half the equivalence point (20 mL of NaOH added), the pH of the solution is 3.26.

3. At the equivalence point (30 mL of NaOH added), the pH of the solution is 10.72.

4. At some volume past the equivalence point the pH of the solution is 12.30

In the sketch (in figure), the x-axis represents the volume of NaOH added and the y-axis represents the pH of the solution. The initial pH before any NaOH has been added is 1.89, which is the pH of the 0.15 M formic acid solution.

As NaOH is added, the pH increases slowly at first, but then increases more rapidly as the solution enters the buffer region. At the half-equivalence point (20 mL of NaOH added), the pH is 3.26. At the equivalence point (30 mL of NaOH added), the pH jumps up to 10.72 due to the complete reaction of the formic acid with NaOH.

After the equivalence point, the pH continues to increase as more NaOH is added. At 50 mL past the equivalence point, the pH is 12.30, which is close to the pH of a strong base.

The titration of 0.15 M formic acid (HCOOH) with 0.25 M NaOH can be represented by the following equation:

\(HCOOH + NaOH\) → \(NaCOOH + H_2O\)

Before any NaOH is added, the solution consists of 0.15 M formic acid, which is a weak acid. The initial pH of the solution can be calculated using the dissociation constant (Ka) of formic acid:

\(HCOOH + H_2O < = > H_3O^+ + HCOO^-\)

\(Ka = [H_3O^{+}][HCOO^{-}]/[HCOOH]\)

Since formic acid is a weak acid, we can assume that \([H_3O^+]\) is equal to \([HCOO^-]\). Let x be the concentration of \([H_3O^+]\) and [\([HCOO^-]\)] at equilibrium, then:

\(Ka = x^2 / (0.15 - x)\)

At equilibrium, the concentration of HCOOH will be (0.15 - x) M.

Let's solve for x:

\(Ka = x^2 / (0.15 - x)\)

\(1.77 * 10^{-4} = x^2 / (0.15 - x)\)

x = 0.0129 M

1. Therefore, the initial pH of the solution is:

\(pH = -log[H_3O^+]\)

pH = -log(0.0129)

pH = 1.89

Now let's consider the pH at different points during the titration:

Before any NaOH has been added:

The initial pH of the solution is 1.89.

2. At some fraction of the equivalence point:

At the equivalence point, all of the formic acid will have reacted with an equal amount of NaOH. Since NaOH is a strong base, the solution will be basic after the equivalence point.

At some fraction of the equivalence point, we can assume that the solution is a buffer consisting of formic acid and its conjugate base, sodium formate (NaCOOH). We can use the Henderson-Hasselbalch equation to calculate the pH:

pH = pKa + log([NaCOOH] / [HCOOH])

At the fraction of the equivalence point, we can assume that the concentration of HCOOH and NaCOOH are equal, and the concentration of NaOH is equal to the fraction of the equivalence point times the initial concentration of formic acid. Thus:

[HCOOH] = 0.15 M - (fraction of equivalence point) × (volume of NaOH added)

[NaCOOH] = (fraction of equivalence point) × (volume of NaOH added)

\([H_3O^+] = Ka * [HCOOH] / [NaCOOH]\)

Let's assume that the fraction of the equivalence point is 0.5, which means that half of the initial concentration of formic acid has reacted with NaOH. Let's also assume that we have added 20 mL of NaOH so far:

\([HCOOH] = 0.15 M - 0.5 * 0.02 L * 0.25 M\\[HCOOH] = 0.14 M\\[NaCOOH] = 0.5 * 0.02 L * 0.25 M\\[NaCOOH] = 0.0025 M\)

\([H_3O^+] = 1.77 * 10^{-4} * (0.14 / 0.0025)\)

\([H_3O^+] = 9.88 * 10^{-3} M\)

\(pH = pKa + log([NaCOOH] / [HCOOH])\\\\pH = 3.75 + log([0.0025 / 0.14])\\\\pH = 3.26\)

Therefore, at half the equivalence point (20 mL of NaOH added), the pH of the solution is 3.26.

3. At the equivalence point:

The pH can be calculated using the hydrolysis constant (Kb) of sodium formate:

\(NaCOOH +\) \(H_2O\) ⇌ \(NaOH + HCOOH\)

\(Kb = [NaOH][HCOOH]/[NaCOOH]\)

Let's assume that we have added 30 mL of NaOH, which is the equivalent amount to the initial concentration of formic acid:

\([NaOH] = [HCOOH] = 0.15 M\\[NaCOOH] = 0.5 * 0.03 L * 0.25 M\\[NaCOOH] = 0.00375 M\\\\Kb = [NaOH]^2 / [NaCOOH]\\\\Kb = (0.15)^2 / 0.00375\\\\Kb = 6\\\\pOH = -log[OH-]\\pOH = -log\sqrt{(Kb * [NaCOOH])} \\pOH = -log\sqrt{6 * 0.00375} \\pOH = 3.28\\pH = 14 - pOH\\pH = 10.72\)

Therefore, at the equivalence point (30 mL of NaOH added), the pH of the solution is 10.72.

4. At some volume past the equivalence point:

After the equivalence point, the solution will be basic due to the excess of NaOH. The pH can be calculated using the concentration of NaOH and the volume of NaOH added:

pOH = -log[OH-]

pOH = -log(0.25 × (volume of NaOH added - volume of NaOH at equivalence point))

pH = 14 - pOH

Let's assume that we have added 50 mL of NaOH past the equivalence point:

pOH = -log(0.25 × (0.05 L - 0.03 L))

pOH = 1.70

pH = 14 - pOH

pH = 12.30

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Carbon dioxide molecules can absorb and emit infrared radiation, and they are one of the most abundant constituents of Earth's atmosphere.

Thus, the correct options are:d) Are one of the most abundant constituents of Earth's atmospheree) Can move in many ways, thus absorbing and emitting infrared radiation

Carbon dioxide is a trace gas present in the Earth's atmosphere. It's a vital component of Earth's carbon cycle, which helps to regulate Earth's temperature and support life as we know it. Carbon dioxide molecules are one of the most common gases in the atmosphere, accounting for around 0.04% of the Earth's atmosphere.

The greenhouse effect is caused by carbon dioxide, methane, and other greenhouse gases. When the Sun's energy reaches the Earth's surface, it is absorbed and then radiated back into space as infrared radiation. Greenhouse gases absorb this radiation and trap it in the atmosphere, which causes the Earth's temperature to rise and the climate to change.

Carbon dioxide molecules are capable of absorbing and emitting infrared radiation due to their molecular structure, which consists of one carbon atom and two oxygen atoms. This property of carbon dioxide is the main reason it's classified as a greenhouse gas.

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We can calculate the molarity by dividing the quantity of barium hydroxide in moles by the volume of the initial solution.

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Answer:

0.016 moles

Explanation: Because you are doing P4, you take the molar mass/atomic mass of phosphorous which is 30,97(rounded up) and multiply it by 4 since that's the subscript. Then you take 2.0 grams and divide it by the molar mass, which is 123.88, and that gives you 0.016 moles (rounded up)

The weak acid will exhibit the highest percentage ionization in the solution with the highest Ka value.

To determine the highest percentage ionization, we need to compare the acid dissociation constant (Ka) values of the given weak acids. A higher Ka value indicates a higher degree of ionization in the solution. Here are the Ka values for each option:

A. HSO3⁻ (Ka = 6.3 × 10^(-8))
B. HF (Ka = 6.3 × 10^(-4))
C. H3BO3 (Ka = 5.4 × 10^(-10))
D. HC2H3O2 (Ka = 1.8 × 10^(-5))
E. H2C2O4 (Ka = 5.8 × 10^(-2))

From the given Ka values, we can see that HF (B) has the highest Ka value, which means it has the highest percentage ionization among the given aqueous solutions of weak acids.

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Equilibrium constant K= 44.8 for H₂ + I₂ → 2HI Equimolar reactants, HI = 0.50M, H₂ = 5.6×10⁻³ M. The correct option is e.

given equilibrium constant (K) and the equilibrium concentration of the product HI = 0.50M

balanced equation for the reaction

H₂ + I₂ → 2HI

K =\(\frac{HI^{2} }{[H_{2][I_{2}] } }\)

K=44.8 and [HI]=0.50M

[H₂] = \(\frac{[HI]^{2} }{K}\)

[H₂] =\(\frac{(0.50M)^{2} }{44.8}\)

[H₂] ≈0.0056M

equilibrium concentration of hydrogen is 0.0056M sa per the given reaction.

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Answer:

noc

Explanation:

xd

Answer:

It is possible to fill a balloon with a mixture of hydrogen and oxygen and find that ... the following equation is balanced because the total mass of the reactants is ... of hydrogen and one mole of oxygen is equal to the mass of two moles of water.

Explanation:

ig this can be Explanation:

and the answer:)

Answer: Hot Rocks

Explanation:

Answer:

d is your answer please follow me

Explanation:

Adding sodium hydroxide (NaOH) will also affect the

position of the equilibrium. While neither sodium ions (Na

+ ) or hydroxide ions (OH - ) are present on either side, the

hydroxide ions will remove H + ions and the equilibrium

will shift to the right hand side to replace the hydrogen

ions that were removed .

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Answer:

The SAE curriculum includes practical farming tasks conducted outside the scheduled classroom and laboratory period by students. SAEs offer a method for students in agricultural education to gain real-world work opportunities that they are most interested in in the field of agriculture. Supervised agricultural experience is an essential component of agricultural education, and all Agriculture, Food and Natural Resources (AFNR) courses are a necessary component.

Explanation: Hope it helps

The wavelength of the light is approximately 500 nm. The energy of the photon of light is approximately 6.56 x 10-20 J.

Answer: Question 1:The formula relating wavelength, frequency, and the speed of light is given by:c = fλHere,λ = wavelength, f = frequency, c = speed of lightI. n the problem, frequency is given as 5.98 x 1014 s-1. Therefore, using the formula, the wavelength of light can be calculated as follows:λ = c/f= (3 x 108 m/s)/(5.98 x 1014 s-1)≈ 500 nm

Therefore, the wavelength of the light is approximately 500 nm.

Question 2:The formula relating energy and frequency of light is given by:E = hfwhereE = energy of photonh = Planck's constant = 6.626 x 10-34 J s (Joule seconds)f = frequency of lightIn the problem, the frequency of light is given as 9.89 x 1013 Hz. Therefore, using the formula, the energy of the photon of light can be calculated as follows:E = hf= (6.626 x 10-34 J s) x (9.89 x 1013 Hz)≈ 6.56 x 10-20 J

Therefore, the energy of the photon of light is approximately 6.56 x 10-20 J.

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