Calculate the ph at the equivalence point in titrating 0. 120 m solutions of each of the following acids with a solution 0. 090 m in naoh.

The charge on lysine at pH 14 is +2. (D)

Lysine has a side chain of an amine group, which can be deprotonated at a pH above the pKa value of the amino group.

This can be seen in the Henderson-Hasselbalch equation, which is used to calculate the pH at which a weak acid and its conjugate base are in equilibrium:pH = pKa + log([A-]/[HA])

In the case of lysine, the amine group is the weak base, and its conjugate acid is the ammonium ion. When the amine group loses its proton, it becomes the ammonium ion, and when it gains a proton, it becomes the neutral amine.

The pKa of lysine's amine group is approximately 10.5, so at a pH of 14, the ammonium ion is deprotonated to become the neutral amine, and the charge on lysine is +2. Therefore, the answer is (d) +2.

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Answer:

here you go

Explanation:

Atomic Number (Z) = Mass Number (A) - Number of Neutrons An atom has 5 protons, 5 electrons and 6 neutrons The atomic number = number of protons = number of electrons = 5 The mass number = 5 protons + 6 neutrons = 11

= 18.02 g/mol) im sure its that

Answer:

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Explanation:

SUMMURY

Radiation is energy. It travels in the form of energy waves or high-speed particles. Radiation can occur naturally or be man-made. ... Ionizing radiation, which includes ultraviolet radiation, radon, x-rays, and gamma rays.

Radiation is energy that comes from a source and travels through space at the speed of light. This energy has an electric field and a magnetic field associated with it, and has wave-like properties. You could also call radiation “electromagnetic waves”.

DIFFENITION :

radiation

1a: the action or process of radiating

b: the process of emitting radiant energy in the form of waves or particles

c(1): the combined processes of emission, transmission, and absorption of radiant energy

(2): the transfer of heat by radiation

— compare CONDUCTION, CONVECTION

2a: something that is radiated

b: energy radiated in the form of waves or particles

3: radial arrangement

4: ADAPTIVE RADIATION

There is a golden role of solubility, polar solute dissolve in polar solvent and non polar solute dissolve in non polar solvent. Therefore, it was unable to diffuse through the 20 MWCO membrane.

Solutions are a homogeneous mixture of two or more substances. A solution is a homogeneous mixture of solvent and solute molecules. Solvent is a substance that is in large amount in solution. solute is the substance which is in small amount in a solution. There are two types of mixture that is homogeneous and heterogeneous. Solution is a homogeneous solution.

Lee molecular weight of urea is 60.07 . It was unable to diffuse through the 20 MWCO membrane due to urea being unable to fit through the pores of the membrane.

Therefore, it was unable to diffuse through the 20 MWCO membrane.

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The delta S degree rxn for the given reaction is 126.8 J/mol . K, indicating an increase in entropy.

Delta S degree rxn can be calculated using the formula:

Delta S degree rxn = Sum of S degrees (products) - Sum of S degrees (reactants).

Using this formula, the delta S degree rxn for the given reaction can be calculated as follows:

Delta S degree rxn = (2 x 229.2 J/mol . K) + (1 x 130.7 J/mol . K) - (1 x 200.9 J/mol . K) - (2 x 130.7 J/mol . K)
= 458.4 J/mol . K + 130.7 J/mol . K - 200.9 J/mol . K - 261.4 J/mol . K
= 126.8 J/mol . K

The delta S degree rxn for the given reaction is 126.8 J/mol . K. This indicates that the reaction results in an increase in entropy as the products have a greater degree of disorder than the reactants.

In conclusion, the calculation of delta S degree rxn involves finding the difference between the sum of S degrees of the products and the sum of S degrees of the reactants. The delta S degree rxn for the given reaction is 126.8 J/mol . K, indicating an increase in entropy.

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The likely magnitude of the equilibrium constant K is greater than 10^3, and answer (b) is the most appropriate choice.The equilibrium constant K for the combustion reaction 2H2(g) + O2(g) = 2H2O(g) is likely to be very large, indicating a strong preference for the products at equilibrium.

This is because the reaction involves the formation of strong covalent bonds between the hydrogen and oxygen atoms, releasing a large amount of energy in the form of heat and light. The combustion reaction also involves the conversion of two moles of hydrogen gas and one mole of oxygen gas into two moles of water vapor, which means that the number of moles of gas decreases, leading to a decrease in entropy. Despite this decrease in entropy, the exothermic nature of the reaction is likely to drive the equilibrium towards the products. Therefore, the likely magnitude of the equilibrium constant K is greater than 10^3, and answer (b) is the most appropriate choice.

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A graph enables you to easily denote the relationship between variables as positive or negative.

This question is incomplete but I will try to help you as much as I can. A graph is one of the numerous was of data representation in science. A graph has two axes; the vertical ( Y - axis) and the horizontal (X - axis).

A graph enables you to easily denote the relationship between variables as positive or negative. A graph is sometimes called a scatter plot.

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the mass of a billiard ball that has a volume of 100 cm³ and a density of 2. 5 g/cm³ is 250 g

mass  can be determined by the density of an object and volume.

The mass of a substance can be calculate by using the formula

From the question

mass = density * volume

mass = 2. 5 g/cm³ * 100 cm³

mass = 250 g

therefore,the mass of a billiard ball that has a volume of 100 cm³ and a density of 2. 5 g/cm³ is 250 g

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Answer:

3, because H2 ×3 =6, and if you plug in a two in NH3 it would be equal

None of these answer choices are correct. The correct valuation for available-for-sale securities is at fair value, not amortized cost.

Available-for-sale securities are reported on the balance sheet at fair value, with unrealized gains or losses recognized in other comprehensive income. Trading securities are also valued at fair value, but the changes in fair value are recognized in the income statement as gains or losses. Held-to-maturity securities, on the other hand, are valued at amortized cost. They are reported on the balance sheet at their initial cost and subsequently adjusted for amortization of any premiums or discounts, as well as interest income or expense. Therefore, none of the given answer choices accurately represent the correct valuation method for available-for-sale, trading, or held-to-maturity securities.

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Answer:

0.10 moles H₂O

Explanation:

The unbalanced equation:

NH₃ (g) + O₂ (g) ----> NO (g) + H₂O (g)

Reactants: 1 nitrogen, 3 hydrogen, 2 oxygen

Products: 1 nitrogen, 2 hydrogen, 2 oxygen

The balanced equation:

4 NH₃ (g) + 5 O₂ (g) ----> 4 NO (g) + 6 H₂O (g)

Reactants: 4 nitrogen, 12 hydrogen, 10 oxygen

Products: 4 nitrogen, 12 hydrogen, 10 oxygen

Now that the reaction is balanced, you can use the coefficients of the desired molecules to construct the mole-to-mole ratio. This ratio should be multiplied by the given value (0.085 moles). It is important to arrange the ratio in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to match the given value.

0.085 moles O₂          6 moles H₂O
-------------------------  x  ------------------------  =  0.10 moles H₂O
                                      5 moles O₂

The solubility of the gas at a pressure of 85 kPa is 0.456 g/L.

The relationship between pressure and a gas's solubility is straightforward. That is, it gets bigger as the strain gets bigger.

The combined gas law can be used to resolve this issue and says that:

(P1V1)/T1 = (P2V2)/T2

To solve for V2, which stands for the new volume at the reduced pressure, we can rearrange this equation as follows:

V2 = (P1V1T2)/(P2T1)

Since the temperature is held constant, T1 = T2, and this simplifies to:

V2 = (P1V1)/P2

Solubility2 = (Solubility1 x P2) / P1

where the solubility at greater pressure is denoted by Solubility1.

With numbers from the problem substituted, we obtain:

Solubility2 = (0.584 g/L x 85 kPa) / 109 kPa

Simplifying this expression, we get:

Solubility2 = 0.456 g/L.

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The dependent was before she started changing them and the independent variable is the process of them changing.

The independent variable is the type of gel, the dependent variable is the growth rate of the bacteria.

Dependent variables and independent variables are terms used in mathematics, statistics, and other experimental sciences. Each of them is characterized by:

According to the above, in the situation presented, the independent variable is the type of gel because two types of gel are used, to obtain different results according to the characteristics of each gel.

Additionally, the dependent variable of this experiment is the growth rate of the bacteria under different conditions (gel A and gel B).

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Answer:

I think its Motion

Explanation:

15.6g of potassium would produce 1 mole of potassium oxide 15.6g K + 0.8 mol O2 → 1.2 mol K2O.

Potassium is an essential mineral that plays an important role in a number of bodily functions. It is a type of electrolyte that helps regulate the body's water balance, acid-base balance, and heart rate. It also helps to maintain healthy muscle and nerve function, as well as normal blood pressure. Potassium can be found in many foods, including fruits, dairy products, legumes, nuts, and leafy green vegetables.

Assuming you had unlimited oxygen, 15.6g of potassium would produce 1 mole of potassium oxide (K2O). This is because the molar mass of potassium oxide is 94.2 g/mol and there are 2 moles of oxygen for every 1 mole of potassium in the reaction equation: K + O2 → K2O.
Therefore, 15.6g of potassium would produce 1 mole of potassium oxide, which can be calculated as follows:
15.6g K / (39.1g K/mol) = 0.4 mol K
0.4 mol K x (2 mol O2/1 mol K) = 0.8 mol O2
0.4 mol K + 0.8 mol O2 = 1.2 mol K2O
Therefore, the answer is:
15.6g K + 0.8 mol O2 → 1.2 mol K2O

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In Experiment 2, the gas produced at the negative electrode is typically hydrogen (H2).

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Answer:

Explanation: the answer is YES

CO(NH2)2  and (NH2)2 CO is the urea

Answer:

2.78035217*10^6 m

Explanation:

C = v

3.0e8 = (107.9)

= 2.78035217*10^6 m

Answer:

1,354

Explanation:

Answer:

single reaction equation

Explanation:

Type of Chemical Reaction: For this reaction we have a single replacement reaction. Balancing Strategies: In this single replacement (also called displacement) reaction the Al and Fe are switching places.

Answer:

B. Pure substance

Explanation:

Iron (Fe) is an element making it a pure substance

The most appropriate reagent for the conversion of 2-hexanol to 2-hexanone is a oxidizing agent such as sodium dichromate (Na2Cr2O7) or potassium permanganate (KMnO4).

Oxidation of alcohols to carbonyl compounds (such as ketones) can be achieved using oxidizing agents like sodium dichromate or potassium permanganate. In this case, 2-hexanol can be oxidized to 2-hexanone using either of these reagents.

PCC is a mild oxidizing agent that selectively oxidizes primary alcohols to aldehydes and secondary alcohols to ketones without over-oxidizing them. In this case, 2-hexanol is a secondary alcohol, and using PCC will result in the formation of 2-hexanone.
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Answer:

C.

Explanation:

Answer:By their movement, by their wastes, and by their metabolic.

Explanation:The nutrient cycle is a system where energy and matter are transferred between living organisms and non-living parts of the environment. This occurs as animals and plants consume nutrients found in soil, and these nutrients are then released back into the environment via death and decomposition.