Calculate the moles of calcium oxalate formed from 5 grams of potassium oxalate (molar mass 184.24 g/mol) the mole mole ratio from the balanced equation is 2.1 potassium oxalate to calcium oxalate

Answers

Answer 1

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).

We can calculate the moles of CaC₂O₄ obtained considering the following relationships.

The molar mass of K₂C₂O₄ is 184.24 g/mol.The mole ratio of K₂C₂O₄ to CaC₂O₄ is 2:1.

\(5 g K_2C_2O_4 \times \frac{1molK_2C_2O_4}{184.24gK_2C_2O_4} \times \frac{1molCaC_2O_4}{2molK_2C_2O_4} = 0.03molCaC_2O_4\)

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

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Related Questions

Calculate the volume in liters of 50.0 grams of NO2 at STP.

Answers

First, calculate how many moles of O2 you have:

O is 16g/mole, so O2 is 32g/mole. 50/32 = 1.5625 moles

1 mole of any gas at stp is 22.4 liters

1.5625 × 22.4 = 35 liters.

According to the mole concept, the number of moles in 50 g of NO₂ is 1.086 as molar mass of NO₂ is 46 g and as per STP conditions volume is 24.32 L.

What is a mole?

Mole is defined as the unit of amount of substance . It is the quantity measure of amount of substance of how many elementary particles are present in a given substance.

It is defined as exactly 6.022×10²³ elementary entities. The elementary entity can be a molecule, atom ion depending on the type of substance. Amount of elementary entities in a mole is called as Avogadro's number.

It is widely used in chemistry as a suitable way for expressing amounts of reactants and products.For the practical purposes, mass of one mole of compound in grams is approximately equal to mass of one molecule of compound measured in Daltons. Molar mass has units of gram per mole . In case of molecules, where molar mass  in grams present in one mole  of atoms is its atomic mass.

Initially the number of moles is calculated as, 50/46=1.086 moles . As 1 mole occupies 22.4 L at STP conditions,1.086 moles occupy 1.086×22.4=24.32 L.

Hence, the volume in liters of 50 g of NO₂ at STP is 24.32 L.

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Calculate the wavelength of light (in nm) of the spectral line of Hydrogen where an electron falls from the 6th Bohr orbit to the 3rd Bohr orbit.

a) 540 nm
b) 2000 nm
c) 1090 nm
d) 1050 nm

Answers

Answer:

The wavelength of light (in nm) of the spectral line of Hydrogen where an electron falls from the 6th Bohr orbit to the 3rd Bohr orbit is 1090nm

Explanation:

We know that , the wavelength of the light is calculated by Rydberg's formula-

\(\frac{1}{\pi} =R^2(\frac{1}{n^2_1} -\frac{1}{n^2_2})\)  \([n_2>n_1]\)

Here , R = Rydberg's constant \((1.097\times 10^7 m^-^1)\)

          Z = atomic number (for hydrogen , Z= 1)

     \(n_2 =6 , n_1=3\)

\(\pi =\) wavelength of light

Now , putting the values in the Rydberg's formula ,

  \(\frac{1}{\pi} =1.097\times10^7m^-^1(\frac{1}{3^2} -\frac{1}{6^2} )\)

     =\(1.097\times 10^7m^-^1 (\frac{4-1}{36} )\)

    =\(1.097\times 10^7m^-^1(\frac{3}{36} )\)

      =\(1.097\times 10^7m^-^1(\frac{1}{12} )\)

  \(\frac{1}{\pi}\)   = \(0.0914167\times 10^7m^-^1\)

\(\pi=\frac{1}{0.0914167\times10^7m^-^1}\)

\(\pi=10.9389\times10^-^7\\\pi=1093.89\times10^-^9m\)

  =1090nm

Hence , the wavelength of the light is 1090nm,, that is option D is correct.

What is the formula for this
ionic crystal?

What is the formula for thisionic crystal?

Answers

69 nice hoemmdmdmdkdjd

The ionic formula for the ionic crystal is Fe₃O₂

Ionic crystals are solid, crystalline ionic substances that are made up of ions linked together in a regular lattice structure by electrostatic attraction.

From the given structure; the key element shows that:

Fe is denoted by the red electrons, andO is denoted by the blue electrons

Therefore, from the diagram, the correct formula of the ionic crystal by considering the lone pairs and valence electrons is Fe₃O₂

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which properties of a material are affected by a bonding type

Answers

\(\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} -»}\)

Hardness, melting and boiling points, solubility, and conductivity.

Explanation:

Hope it helps you~

I need help someone plsss answer!!

I need help someone plsss answer!!

Answers

Answer:

c

Explanation:

cccccccccccccccccccccc

What is the pH of a solution whose hydronium ion [H20+] (or proton [H+1)
concentration is 7.6' 10-5 M?

Answers

Answer:

\(pH = - log(7.6 \times {10}^{ - 5} ) \\ pH = 4.12\)

Question 21 of 30
What is the frequency of an electromagnetic wave that has a wavelength of
3.7 x 10-11 m in a vacuum? (The speed of light in a vacuum is 3.00 × 108
m/s.)
OA. 8.1 x 1018 Hz
B. 1.2 x 10-19 Hz
OC. 1.1 x 102 Hz
OD. 2.7 x 1010 Hz
SUBMIT

Answers

The frequency of the electromagnetic wave is 8.1 x 10 ¹⁸ Hz.

The speed of light in a vacuum is given as 3.00 x 10⁸ m/s. The speed of light is also related to the wavelength and frequency of the electromagnetic wave by the equation:

c = λν

where c is the speed of light, λ is the wavelength, and ν is the frequency.

Rearranging the equation to solve for frequency, we get:

ν = c/λ

Substituting the values given in the problem, we get:

ν = (3.00 x 10⁸ m/s) / (3.7 x 10⁻¹¹ m)

ν = 8.1 x 10 ¹⁸ Hz

Therefore, the frequency of the electromagnetic wave is 8.1 x 10 ¹⁸ Hz, and the correct answer is (A) 8.1 x 10 ¹⁸ Hz.

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if there are 25 red colored glass beads in a bag that contains 150 glass beads, what is the percent of red glass beads? show your calculations.

Answers

The percentage of red glass beads would be = 16.67%

What is percentage?

Percentage is defined as the part of a portion of a value per 100 and it is represented by the symbol %.

The number of red colored glass beads = 25

The total number of glass beads = 150

The percentage of glass beads that are red colored glass would be;

= 25/150×100

= 2500/150

= 16.67%

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Read the descriptions below of two substances and an experiment on each. Decide whether the result of the experiment tells you the substance is a pure substance or a mixture, if you can. • Sample A is a solid yellow cube with a total mass of 50.0 g. The cube is ground to a fine orange powder and added to a 500 ml beaker full of water. The beaker is stirred vigorously. Some of orange powder settles to the bottom of the beaker, and some rises to the top and floats on the water. When the powder at both the bottom and the top of the beaker is filtered out, dried, and weighed, the total mass is measured to be 50.1 g. • Sample B is 100 mL of a clear liquid. The density of the liquid is measured, and turns out to be 0.77 g/mL. The liquid is then heated in a flask until it boils. The vapor that rises off the bolling liquid is collected for 10 minutes and cooled until it condenses into a separate beaker. The density of the liquid that remains in the flask is then measured, and turns out to be 1.04 g/mL. Opure substance х Is sample A made from a pure substance or a mixture? If the description of the substance and the outcome of the experiment isn't enough to decide, choose "can't decide." mixture O can't decide) O pure substance Is sample B made from a pure substance or a mixture? If the description of the substance and the outcome of the experiment isn't enough to decide, choose "can't decide mixture (can't decide)

Answers

Answer:

Sample A is  a pure substance

Sample B is a mixture

Explanation:

We are told that the when the yellow solid, sample A is ground it turned to orange colour  and was then dissolved. Some part of the solid settled out at the bottom of the beaker while some part floated on top of the water. 50g of the solid was dissolved and 50.1g of the solid was recovered.

This implies that the substance is pure since the mass dissolved was almost the same mass recovered. The 0.1g addition in mass may result from incomplete drying of the solid.

For sample B, the distillation of the sample of density 0.77 g/ml left a fraction in the beaker with density 1.04 g/ml indicating that the substance is a mixture. Different components of a mixture possess different densities.

a solution containing 1.00 g of an unknown nonelectrolyte liquid and 9.00 g of water has a freezing point of -3.33 *C. Calculate the molar mass of the unknown liquid in g/mol.

Answers

The depression in freezing point of water here is 3.33 °C. Then the molality of the solution is 1.79. From number of moles of solute is calculated as 0.0161. Then , the molar mass of the solute is 62.11 g.

What is depression in freezing point ?

The addition of a non-volatile salt into a solvent will decrease the freezing point of the solution than the pure solvent. The change in freezing point is proportional to the molality of the solution.

ΔTf = Kf m

Kf is called molal depression constant.

Kf for water = 1.86 °C Kg/mol

given ΔTf = 3.33 (0 - (-3.33))

then m = ΔTf /Kf =  3.33/ 1.86 °C Kg/mol = 1.79

Now, mass of water= 9 g = 0.009 kg

then number of moles = molality × mass of solvent

n = 0.009 kg × 1.79 = 0.0161.

mass of solute taken = 1 g

then, molar mass = 1/0.0161 = 62.11 g.

Therefore, the molar mass of the solute is 62.11 g.

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What is the iupac name of ch3ch(oh)so3na

Answers

Answer:

propane-1-ol.

is the ans.

ok

is the name

ok

How do I know I'm a fish eh sorry

Use the image to complete the sentences.

At left a grid labeled A of regularly arranged orange balls with small movement lines near each. At right a grid labeled B of regularly arranged orange balls with large movement lines near each.

Two different substances, Substance A and Substance B, are in direct contact with each other and are at different temperatures.

The particles in Substance B are vibrating
the particles in Substance A. This means Substance B is
Substance A and conduction will
.

Use the image to complete the sentences. At left a grid labeled A of regularly arranged orange balls

Answers

Answer:

1. FASTER THAN- #2

2. WARMER THAN #1

3. OCCUR FROM SUBSTANCE B TO SUBSTANCE A- #3

Explanation:

I did the assignment On edg And got it right

Answer:

Use the image to complete the sentences.  

At left a grid labeled A of regularly arranged orange balls with small movement lines near each. At right a grid labeled B of regularly arranged orange balls with large movement lines near each.

Two different substances, Substance A and Substance B, are in direct contact with each other and are at different temperatures.

The particles in Substance B are vibrating

✔ faster than

the particles in Substance A. This means Substance B is

✔ warmer than

Substance A and conduction will

✔ occur from Substance B to Substance A

.

Explanation:

I know im late

How many grams are in 7.32 x 1023 molecules of potassium carbonate (K2CO3)?

Answers

(I leave off the x10^23 because they both will divide out)    Use your per

N⁻³ and Na⁺ have same
A Atomic no.
B Mass No.
C No. of electrons
D No. of neutrons​

Answers

Answer:

C.) No. of electrons

Explanation:

A.) is incorrect. The atomic number represents the number of protons in an element. Nitrogen (N) and sodium (Na) always have a differing amount of protons.

B.) is incorrect. The mass number represents the number of protons and neutrons in an element. The number of neutrons and protons are specific to each element (disregarding isotopes). When elements ionize, these amounts are not altered.

C.) is correct. When an element becomes an ion, the number of electrons change. When nitrogen gains 3 electrons and sodium loses 1 electron, they end up having the same number of electrons (10).

D.) is incorrect. When elements ionize, the number of neutrons does not change. The only way two different elements could have the same number of neutrons is if at least one of the elements is an isotope. Isotopes are two or more atoms of the same element that differ in their amounts of neutrons.

If you change your workout from a
HIIT workout to a cardiovascular
endurance workout, what would you
expect to see in the heart rate? Why?
Please help☹️

Answers

Answer:

HIIT workouts are anaerobic, and cardiovascular endurance workouts are usually aerobic, depending on how much you work out. If you changed speed and switched to a different workout immediately after what you did before, your heart rate would increase, and you would experience pain on the side of your abdominal. It can be because your body isn’t used to the change in speed and endurance.


Question 6
Match all that apply. Conductive flow depends upon

cross-sectional area
trapped air
dissipation
driving force
conductivity of the material

Answers

Conductive flow depends upon :

cross-sectional areatrapped airdissipationdriving forceconductivity of the material

What does Conductive flow rely on ?

Conductive flow depends on the cross-sectional area of the material or medium through which the flow is occurring. A larger area can allow for greater flow, while a smaller area can restrict flow. The presence of trapped air or other gases can affect conductive flow by creating obstructions or barriers to the flow of material or electricity.

Conductive flow depends on the presence of a driving force, such as a voltage or pressure difference, which pushes or pulls the material or electricity through the medium. Materials with higher conductivity allow for more efficient conductive flow, while materials with lower conductivity can restrict flow.

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It was calculated that 4.3mL of 0.417 M HCl is required to titrate 11.9 mL of 0.151 M Mg(OH)2. Show evidence 2 HCl(aq) + Mg(OH)2(aq) → + MgCl2(aq) + 2 H2O(l)

Answers

Answer:

See explanation.

Explanation:

Hello,

In this case, for the described chemical reaction:

2 HCl(aq) + Mg(OH)2(aq) → MgCl2(aq) + 2 H2O(l)

We can notice there is a 2:1 molar ratio between the moles of hydrochloric acid and magnesium hydroxide, therefore, at the equivalence point:

\(n_{HCl}=2*n_{Mg(OH)_2}\)

And in terms of volumes and concentrations we verify:

\(V_{HCl}M_{HCl}=2*V_{Mg(OH)_2}M_{Mg(OH)_2}\)

So we use the given data to proof it:

\(4.3mL*0.417M=2*11.9mL*0.151M\\1.793=3.594\)

Therefore, we can conclude the data is wrong by means of the 2:1 mole ratio that for sure was not taken into account. This is also supported by the fact that normalities are actually the same, but the nomality of magnesium hydroxide is the half of the hydrochloric acid normality since the acid is monoprotic and the base has two hydroxyl ions.

Best regards.

Why is it difficult to rub away any carbon atoms from diamonds?​

Answers

Answer:

because diamond is the allotrope of carbon and diamond is the hardest substance in the world and it's melting point is very very high so it's difficult

Diamond has a very high melting point because a large amount of energy is needed to overcome the many strong covalent bonds. There are no electrons or other charged particles that are free to move so diamond does not conduct electricity. Hope this helps:)

which on the following is not a acid? A. HCl B. H2SO4 C. NaOh D. HN03

Answers

Answer:

     HN03 is not an acid at all........!

                              .....................

The owner of Grizzly Tea Shack is thinking about adding iced tea to the menu. He
thinks he can do this with minimal effort by adding ice cubes to cups of hot tea.
He decides to measure how changing the number of ice cubes in a glass of
freshly brewed tea affects its cooling rate.
To begin, the owner varies the number of ice cubes, x, he puts in glasses of
freshly brewed tea. He then checks the temperature (in Celsius), y, of each glass
after 10 minutes.
Ice cubes Temperature after 10 minutes (in degrees Celsius)
2
17
3
5
6
6
20
10
11
15
Round your answers to the nearest thousandth.

The owner of Grizzly Tea Shack is thinking about adding iced tea to the menu. Hethinks he can do this

Answers

Answer: 5,266

Explanation:

5,266

3
Which chemical equation below is balanced to correctly represent the Law of
Conservation of Mass?
04 Al + 3O2 + 2 Al2O3
O2 AL + O2 + 2 Al2O3
O AL + O2 + Al2O3

Answers

Answer:

4Al + 3O₂ →   2Al₂O₃

Explanation:

    4Al + 3O₂ →   2Al₂O₃

Only this reaction above obeys the law of conservation of mass. The others flout the rule.

The law of conservation of mass states that "matter is neither created nor destroyed in a chemical reaction but are simply transformed from one form to another".

By this law, the number of atoms on both sides of expression must be the same;

                                                    Number of atoms

Elements              Left hand side                                 Right hand side

  Al                                    4                                                     4

  O                                    6                                                    6

Metamorphism can best be defined as

a. Compaction and cementation of rock fragments
O
b. Precipitation of minerals dissolved in water
c. Solidification of magma by cooling
d. Changing of a rock by heat and pressure
Need help ASAP

Answers

Answer:

The answer is D if it's wrong let me know pls

Magnesium hydroxide reacts with chlorine to form magnesium chloride,
magnesium chlorate and water. How many grams of magnesium hydroxide is
needed to yield 8.00 moles of magnesium chlorate?
77.8 g Mg(OH)2
9178.1 g Mg(OH)2
2799.6 g Mg(OH)2
.823 g Mg(OH)2
How many grams of sodium sulfato pro

Answers

The grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g. None of the options provided match the calculated value of 466.64 g.

To determine the grams of magnesium hydroxide (Mg(OH)2) needed to yield 8.00 moles of magnesium chlorate (Mg(ClO3)2), we need to consider the balanced chemical equation for the reaction between magnesium hydroxide and chlorine.

The balanced equation is as follows:

2 Mg(OH)2 + 6 Cl2 → 2 Mg(ClO3)2 + 2 H2O

From the balanced equation, we can see that 2 moles of Mg(OH)2 react with 6 moles of Cl2 to produce 2 moles of Mg(ClO3)2.

Therefore, the stoichiometric ratio is 2 moles of Mg(OH)2 : 2 moles of Mg(ClO3)2.

To calculate the grams of Mg(OH)2 needed, we can use the stoichiometric ratio and the given moles of Mg(ClO3)2.

Given:

Moles of Mg(ClO3)2 = 8.00 moles

Using the stoichiometric ratio, we have:

8.00 moles Mg(ClO3)2 × (2 moles Mg(OH)2 / 2 moles Mg(ClO3)2) = 8.00 moles Mg(OH)2

To convert moles to grams, we need to multiply by the molar mass of Mg(OH)2.

The molar mass of Mg(OH)2 = (24.31 g/mol) + (2 * 16.00 g/mol) = 58.33 g/mol

Grams of Mg(OH)2 = 8.00 moles Mg(OH)2 × 58.33 g/mol = 466.64 g

Therefore, the grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g.

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a large doublet and a small septet pattern in 1h nmr is usually indicative of a(n)

Answers

Isopropyl group is  a large doublet and a small septet pattern in 1h nmr is usually indicative of a(n)

In organic chemistry, an isopropyl group is a functional group composed of a propane molecule with the middle carbon atom replaced by a hydroxy group (-OH). The chemical formula "-C(CH3)3" or "-(CH3)2CH-" is commonly used to represent it. Isopropyl groups can be found in a wide range of compounds, such as alcohols, esters, and ethers. Isopropyl alcohol, also known as isopropanol, rubbing alcohol, or IPA, is a type of organic compound classified as a secondary alcohol. Secondary alcohols are compounds that contain a secondary alcohol functional group and have the general formula HOC(R)(R') (R, R'=alkyl, aryl).

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What is the oxidation number for Chlorine

Answers

Answer:Chlorine:

It is an element that belongs to the p-block and non-metal.

It shows a variable oxidation state.

The oxidation number of chlorine can be - 1, 0, + 1, + 3, + 4, + 5, or + 7 which depends on the substance containing the chlorine.

Explanation:

Cl has a -1 oxidation number, except when bonded to a F or an O.

The reaction of charcoal (carbon) and oxygen is sped up by grinding the charcoal into a fine powder. This is an example of:
Group of answer choices

A. All of the above

B. Increasing concentration to increase reaction rate

C. Increasing temperature to increase reaction rate

D. increasing surface area to increase reaction rate

Answers

Answer:

D

Explanation:

Grinding to a powder increases the surface area of the charcoal .

The reaction of charcoal (carbon) and oxygen is sped up by grinding the charcoal into a fine powder. This is an example of increasing surface area to increase reaction rate. Option D is the answer.

Reason for the grinding

Grinding charcoal into a fine powder enhances its reactivity by increasing surface area. This finer texture promotes more frequent collisions between charcoal particles and oxygen molecules, facilitating faster chemical reactions.

The heightened contact points enable efficient utilization of reactants, optimizing resource consumption. Shorter diffusion paths within smaller particles expedite reactant diffusion, aiding quicker reaction rates.

Additionally, the augmented surface area promotes efficient heat transfer, crucial in reactions involving temperature changes.

Grinding charcoal amplifies the reaction rate by maximizing interaction opportunities, accelerating the conversion of charcoal and oxygen into products.

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Please help me do this

Please help me do this

Answers

The total mass of the balloon and its content is 1521.17 g, the number of moles of CO₂ in the balloon is 34.15 mol, and the number of CO₂ molecules in the balloon is 2.06 x 10²⁵ molecules.

a) The molar mass of CO₂ is 44.01 g/mol. To find the total mass of the balloon and its content, we need to add the mass of the balloon (20g) to the mass of the CO₂ inside the balloon.

Mass of CO₂ = number of moles of CO₂ x molar mass of CO₂

Since the balloon is at STP (standard temperature and pressure), we can use the molar volume of a gas at STP (22.4 L/mol) to find the number of moles of CO₂ in the balloon:

Volume of CO₂ = Volume of balloon = 765 L (at STP)

Number of moles of CO₂ = volume of CO₂ / molar volume of a gas at STP

                                          = 765 L / 22.4 L/mol

                                          = 34.15 mol

Mass of CO₂ = 34.15 mol x 44.01 g/mol

                       = 1501.17 g

Total mass of balloon and its content = 20 g + 1501.17 g

                                                               = 1521.17 g

b) Number of moles of CO₂ in the balloon is 34.15 mol

c) To find the number of CO₂ molecules in the balloon, we need to use Avogadro's number (6.02 x 10²³ molecules/mol).

Number of CO₂ molecules = number of moles of CO₂ x Avogadro's number

                                           = 34.15 mol x 6.02 x 10²³ molecules/mol

                                           = 2.06 x 10²⁵ molecules

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In the barium chloride laboratory activity, what change occurred in the physical appearance of the barium chloride during the heating process?
A. Barium chloride changed from sparkly white to dull white.
B. Barium chloride changed from dull white to sparkly white.
C. Barium chloride changed from sparkly yellow to dull yellow.
D. Barium chloride changed from dull yellow to sparkly yellow.

Answers

Barium chloride turned from sparkly white into dull white during the heating process.

Barium chloride: What is it?

An inorganic substance with the formula BaCl2 is barium chloride. It is among the most popular barium salts that dissolve in water. Like the majority of some of the other water-soluble barium salts, is also white, extremely hazardous, and gives flames a yellow-green tint.

What results from consuming barium chloride?

Among the most common barium salts is barium chloride. Bacl2 is hygroscopic and soluble in water. Deep hypokalemia, generalized muscle weakness, and eventually paralysis of the limbs and breathing muscles can occur within 1 to 4 hours of consumption.

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A 488.3 gram sample of an unknown substance (MM = 92.41 g/mol) is heated from -23.1 °C to 51.8 °C. (heat capacity of solid = 2.96 J/g・°C; heat capacity of liquid = 1.75 J/g・°C; ∆Hfus = 8.04 kJ/mol; Tfinal = 17.6 °C)
a) How much energy (in kJ) is absorbed/released to heat the solid?
b)How much energy (in kJ) is absorbed/released to melt the solid?
c)How much energy (in kJ) is absorbed/released to heat the liquid?
d) What is the total amount of energy that must be absorbed/released for the entire process?

Answers

Answer:

a) Q₁ = 58.82 KJ

b) Q₂ = 42.48 KJ

c) Q₃ = 29.22 KJ

d) Q = 130.52 KJ  

Explanation:

a)

In order to find the energy absorbed to heat the solid, we will use:

\(Q_{1} = mC_{1}\Delta T_{1}\)

where,

Q₁ = Heat absorbed for heating solid = ?

m = mass of solid = 488.3 g = 0.4883 kg

C₁ = Specific Heat Capacity of Solid = 2.96 J/g °C

ΔT₁ =  Change in temperature of Solid = Melting Temperature - Initial Temp.

ΔT₁ = 17.6°C - (-23.1°C) = 40.7°C

Therefore,

\(Q_{1} = (488.3\ g)(2.96\ J/g\ ^{0}C)(40.7\ ^{0}C)\)

Q₁ = 58.82 KJ

b)

In order to find the absorbed to melt the solid at 17.6°C, we will use:

\(Q_{2} = nH_{fus}\)

where,

Q₂ = Heat absorbed for melting solid = ?

H_fus = Heat of Fusion = 8.04 KJ/mol

n = no. of moles = \(\frac{m}{MM} = \frac{488.3\ g}{92.41\ g/mol} = 5.28 mol\)

Therefore,

\(Q_{2} = (5.28\ mol)(8.04\ KJ/mol)\)

Q₂ = 42.48 KJ

c)

In order to find the energy absorbed to heat the liquid, we will use:

\(Q_{3} = m C_{3}\Delta T_{3}\)

where,

Q₃ = Heat absorbed for heating Liquid = ?

m = mass of solid = 488.3 g = 0.4883 kg

C₃ = Specific Heat Capacity of Liquid = 1.75 J/g °C

ΔT₃ =  Change in temperature of Liquid = Final Temp. - Melting Temp.

ΔT₃ = 51.8°C - 17.6°C = 34.2°C

Therefore,

\(Q_{3} = (488.3\ g)(1.75\ J/g\ ^{0}C)(34.2\ ^{0}C)\)

Q₃ = 29.22 KJ

d)

Total amount of energy absorbed during entire process is:

\(Q = Q_{1} + Q_{2} + Q_{3}\)

\(Q = 58.82\ KJ + 42.48\ KJ + 29.22\ KJ\)

Q = 130.52 KJ

In order to heat a 488.3 g solid, 58.8 kJ are required. To melt the solid, 42.5 kJ are required. To heat the liquid, 29.2 kJ are required. The total amount of energy absorbed is 130.5 kJ.

Initially, a 488.3 g solid at -23.1 °C is heated up to 17.6 °C (melting point). We can calculate the heat required (Q₁) using the following expression.

\(Q_1 = c \times m \times \Delta T = \frac{2.96J}{g.\° C } \times 488.3g \times (17.6\° C-(-23.1\° C)) \times \frac{1kJ}{1000J} = 58.8 kJ\)

where,

c: heat capacity of the solidm: massΔT: change in the temperature

At 17.6 °C, we can calculate the heat (Q₂) required to melt the solid using the following expression.

\(Q_2 = \Delta H_{fus} \times \frac{m}{MM} = 8.04 kJ/mol \times \frac{488.3 g}{92.41g/mol} = 42.5kJ\)

where,

∆Hfus: enthalpy of fusionm: massMM: molar mass

The liquid is heated from 17.6 °C to 51.8 °C. We can calculate the heat required (Q₃) using the following expression.

\(Q_3 = c \times m \times \Delta T = \frac{1.75J}{g.\° C } \times 488.3g \times (51.8\° C-17.6\° C)) \times \frac{1kJ}{1000J} = 29.2 kJ\)

c: heat capacity of the liquidm: massΔT: change in the temperature

The total amount of energy absorbed (Q) is the sum of the energy absorbed in each step.

\(Q = Q_1 + Q_2 + Q_3 = 58.8kJ+42.5kJ+29.2kJ= 130.5kJ\)

In order to heat a 488.3 g solid, 58.8 kJ are required. To melt the solid, 42.5 kJ are required. To heat the liquid, 29.2 kJ are required. The total amount of energy absorbed is 130.5 kJ.

Learn more: https://brainly.com/question/10481356

A 488.3 gram sample of an unknown substance (MM = 92.41 g/mol) is heated from -23.1 C to 51.8 C. (heat

As you move from earth's inner core through the mantle to the crust, how would
temperature, pressure and density of the surrounding rock change?
The temperature would decrease, but pressure and density would increase.
They would all decrease.
O They would stay the same.
O They would all increase.

Answers

It would decrease, because there is less pressure and rock pushing down

Answer:

all decrease

Explanation:

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