Calculate the force of attraction between two bodies with their mass 100 kg each which are 1m apart on the surface of the earth. Will the force of attraction be different if the same bodies are taken on the moon, their separation remaining constant? [Ans: 6.67×10-7 N]​

The physical factors of the room that determine how much light reaches the working plane include the size and placement of windows, the presence of obstructions, and the reflectance of the surfaces.

The amount of light that reaches the working plane in a room is influenced by several physical factors. Firstly, the size and placement of windows play a crucial role. Larger windows allow more natural light to enter the room, while the location of the windows determines the direction and angle of the incoming light. For example, windows facing the south tend to receive more sunlight throughout the day compared to those facing other directions.

Secondly, obstructions in the room can block or diffuse the light. Objects such as furniture, partitions, or screens can cast shadows and obstruct the direct path of light, reducing the amount that reaches the working plane. Additionally, the presence of curtains or blinds can further control the amount of light entering the room.

Lastly, the reflectance of the room's surfaces affects the distribution of light. Light-colored walls, ceilings, and floors reflect more light, helping to distribute it evenly across the space. On the other hand, dark or highly absorbent surfaces can absorb light, resulting in reduced overall brightness.

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1: Average tangential acceleration = (12 m/s - 0 m/s) / 3.3 s ≈ 3.64 m/s²

2: radius = 3.64 m/s² / 11 rad/s² ≈ 0.331 m

3: θ = 0.5 * 11 rad/s² * (3.3 s)² ≈ 59.67 radians

4: The ant has traveled approximately 19.78 meters along the arc of the tire during the given time interval.

1: The average tangential acceleration of the tire can be determined using the formula:

Average tangential acceleration = (final tangential velocity - initial tangential velocity) / time

Given that the ant's speed increases from zero to 12 m/s in 3.3 seconds, the initial tangential velocity is 0 m/s and the final tangential velocity is 12 m/s. Plugging these values into the formula, we get:

Average tangential acceleration = (12 m/s - 0 m/s) / 3.3 s ≈ 3.64 m/s²

2: The radius of the tire can be determined using the formula:

Average tangential acceleration = rotational acceleration * radius

Given that the rotational acceleration of the wheel is 11 rad/s² and the average tangential acceleration is 3.64 m/s², we can rearrange the formula to solve for the radius:

radius = average tangential acceleration / rotational acceleration

Plugging in the values, we get:

radius = 3.64 m/s² / 11 rad/s² ≈ 0.331 m

3: The angle the ant has turned during this time interval can be calculated using the formula:

θ = 0.5 * rotational acceleration * (time)²

Plugging in the given values, we get:

θ = 0.5 * 11 rad/s² * (3.3 s)² ≈ 59.67 radians

4: The distance the ant has traveled along the arc during this time interval can be calculated using the formula:

Distance = radius * θ

Plugging in the values, we get:

Distance = 0.331 m * 59.67 radians ≈ 19.78 meters

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The water level rise dH= 0.7 x 10⁻⁶cm.

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(a) The spring constant of the bungee cord is 62.5 N/m

(b) The extension of the bungee cord past its natural length is 16 m.

(c) The maximum extension of the bungee cord to get it to break is 320 m.

The spring constant of the bungee cord is calculated by applying the following equation as shown below.

F = kx

where;

k = F / x

k = ( 500 N ) / ( 8 m )

k = 62.5 N/m

The extension of the bungee cord is calculated as follows;

x = W / k

x = ( mg ) / k

x = ( 102 kg  x 9.8 m/s² ) / ( 62.5 N/m )

x = 16 m

The maximum extension of the bungee cord is calculated as follows;

x = F / k

x = ( 20,000 N ) / ( 62.5 N/m )

x = 320 m

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The wavelength of the wave will increase to 10 meters. Option B.

The speed of a wave (v) is equal to the product of its wavelength (λ) and frequency (f):

v = λ × f

Rearranging this equation to solve for frequency:

f = v/λ

In the first scenario, where the wave has a speed of 20 m/s and a wavelength of 5 meters, we can calculate the frequency as:

f1 = v/λ1 = 20/5 = 4 Hz

In the second scenario, the frequency is reduced by half, so the new frequency is:

f2 = f1/2 = 4/2 = 2 Hz

To find the new wavelength (λ2), we can rearrange the original equation to solve for wavelength:

λ = v/f

Substituting the values for the second scenario, we get:

λ2 = v/f2 = 20/2 = 10 meters

Therefore, if the same wave was created in the same medium with half of the original frequency, the wavelength would double and become 10 meters.

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Answer:

if they both face each other they cancel out

Explanation:if there is one on 1 side and on the other as well they cancel out and it is 0

Answer:

If the forces are equal and the forces act in oppposite direction then the net force is equal to zero

Answer:

Total displacement = 0

Explanation:

He lives his front porch and still returns to his front porch.

Now, displacement is a vector quantity and as such, it is the distance between the initial point of movement and the final point of movement.

In this case the initial point is the same as the final point and thus the displacement is zero.

Blunt force injuries are caused by non-sharpened objects such as bats or pipes. These types of injuries occur when a blunt object strikes the body, resulting in damage to the underlying tissues and organs.

Unlike sharp force injuries that penetrate or cut the skin, blunt force injuries typically cause a wider area of impact and can result in contusions, bruising, fractures, and internal organ damage.

The force applied by the object can cause compression, shearing, or crushing of tissues, leading to various degrees of injury. Blunt force injuries can range from minor bruises to severe trauma, depending on the intensity and location of the impact.

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There are numerous connections among illnesses of the circulatory system. For instance, excessive blood pressure harms the blood vessels and may cause additional circulation issues.

Prevention of circulatory diseases

High cholesterol causes the blood arteries to narrow, which raises a person's risk of developing a blood clot.

Obesity and being overweight raise the risk of getting cardiovascular disorders. A healthy diet and exercise, though, can lower the risk.

By lowering the risk of high blood pressure, high cholesterol, and being overweight — all of which are risk factors for circulatory disorders — regular exercise helps to keep the heart healthy.

It is more common for someone to get a circulatory disease if they have family members who have the condition. A healthy lifestyle, however, can lower this risk.

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Total distance travelled by the athlete is 37.03km as it is calculated by the expression of distance in terms of speed and time.

Velocity is the distance travelled by a moving body per unit time . Distance travelled is the speed unit time.here an athlete runs with velocity 12 km/hr in 55 min, 14 km/hr in next 22 min and 19 km/hr for the next 66 min.

              55min= 55/60hr  ,

              22min=22/60hr ,

              66 min= 66/60 hr.

        Distance= speed . time

       Putting these in the expression

    Total speed= 55/60 hr..12 km +22/60 hr. .14 km/hr  + 66/60hr . 19       km/hr.

            = 37.03 km

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Generally, the coefficient of static friction should be at least 0.7 for a car traveling at this speed, but this value could be higher depending on the specific conditions.

The coefficient of static friction, or μs, is the ratio of the maximum static force that can be applied without causing slipping to the normal force between two surfaces. The coefficient is affected by the surfaces in contact and the material they are made of.

The tires of a car also have an effect on the coefficient of static friction. Tires with a greater tread depth can provide better grip on the road and therefore have a higher coefficient of static friction than tires with a shallow tread. Tire pressure also plays a role, as low pressure can reduce the coefficient of static friction.

The weight of the vehicle is also an important factor. Heavier vehicles tend to have a higher coefficient of static friction, as the greater mass increases the normal force between the car and the surface.

In conclusion, the coefficient of static friction for a car traveling at 115 km/h around a turn depends on several factors, including the road surface, the vehicle's tires, and the vehicle's weight.

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Answer:

105N

Explanation:

force = mass x acceleration

force without the 25N = 40 x 2

= 80N

On top of this, he has to counteract the 25N so the actual force is 80N + 25N which is 105N

Answer:

The molecules in hot air are moving faster than the molecules in cold air.

Answer:

C.

Explanation:

This is to support from being eroded a foundation to that will separate the water from the soil and to avoid it from being eroded.

Answer:

When a simple pendulum makes 10 oscillation in 20 seconds, the time taken for each osillation

=20/10

= 2seconds

hence, as the time period is calculated to be 10secondd, the frequency of oscillation

=1/T

=1/2

= 0.5 here's

Modern seatbelts have locking mechanisms that are triggered by sudden or rapid movement or deceleration.

Seatbelt locking mechanisms are designed to secure the occupant in the event of a sudden stop, impact, or collision. They utilize various mechanisms to detect abrupt changes in movement or deceleration and lock the seatbelt to prevent excessive forward movement of the occupant.

One common type of locking mechanism is the emergency locking retractor (ELR), which is found in most modern seatbelts. The ELR allows the seatbelt to freely extend and retract during normal driving conditions but locks the belt during sudden movements or rapid deceleration. This is achieved through a pendulum or inertia sensor within the seatbelt retractor mechanism.

When the vehicle experiences a rapid forward movement or deceleration, the pendulum or inertia sensor detects the change and engages the locking mechanism. The locking mechanism prevents the seatbelt from extending further, holding the occupant in place and preventing excessive forward motion during a crash or sudden stop. This helps to distribute the forces of the impact more evenly across the body, reducing the risk of injury.

In addition to the sudden or rapid movement, some seatbelts may also have a feature called a pretensioner. Pretensioners are designed to activate during a collision and instantly retract the seatbelt, removing any slack and tightening it against the occupant's body. This further enhances the effectiveness of the seatbelt by reducing the occupant's forward movement and ensuring a snug fit.

Overall, the locking mechanisms in modern seatbelts are triggered by sudden or rapid movement or deceleration, enabling them to provide effective restraint and protection in the event of a crash or sudden stop.

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The new velocity of the object after the event is 7.99m/s.

We are given that,

Mass = m = 50kg

Initial velocity = v = 11.2m/s

Energy = E = 1539j

The kinetic energy of object can be calculated as,

K= (1/2)mv²

K = (50×125.44)/2

K = 3136J

Consequently, since both the initial kinetic energy and the total amount of energy transferred are known. The article's resulting energy is easily discernible.

Final energy = initial kinetic energy - the ending energy

Final energy  = 3136-1539= 1597 joules

Therefore, using the equation for kinetic energy derivation, the speed of the object can now be determined.

K.E = 1/2MV²

1597 = 50/2V²

3194 = 50V²

V = 7.99m/s

Therefore , the new velocity of the object after the event would be 7.99m/s.

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Charge q1=1.00 nC is at x1 = 0 and charge q2 = 3.00 nC is at x2 = 2.00 m. At a point 1.00 m away from charge q1, the electric field will be equal to zero.

This can be determined by calculating the electric field at this point, which is given by:E = (1/4πεo) x (q1/x2 - q2/x2), where εo is the electric permittivity of free space and x is the distance from charge q1.
At x = 1.00 m, E = 0.

An electric field is defined as the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, which is either attracting or repelling them. It is also refers as the physical field for a system of charged particles.

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The required acceleration would that same net force give to an 18-kg tool is 10m/s^2.

Acceleration  is the pace of progress of speed. Generally, speed increase implies the speed is changing, however not dependably. At the point when an item moves in a round way at a steady speed, it is as yet speeding up, in light of the fact that the course of its speed is evolving.

We have,

Mass(m1) = 4.5 kg, a = 40 m/s^2,Mass(m2) = 18

To find: New acceleration for 18 kg tool

F = ma = 4.5(40) = 180 N

New acceleration = F/m2 = 180/18 = 10 m/s^2

Thus, required acceleration is 10 m/s^2.

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The statement is correct. The placement of the distribution box is not critical as long as it is watertight. The distribution box is responsible for evenly distributing effluent wastewater from the septic tank to the drain field.

As long as the box is watertight, it can be placed in various locations depending on the specific site conditions and design.


The placement of the distribution box is critical for proper functioning in addition to it being watertight. Proper placement ensures the even distribution of wastewater and prevents system failure. thus, based on the explanation the above statement is True.

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If I hold a positive charge in my hand and there are positive charges of equal magnitude 1 mm to your north and 1 mm to your east then the direction of the force on the charge I am holding is towards the north-east direction.

Reasoning:

It is given that there is a positive charge in my hand. There are two more positive charges with the same magnitude. One is 1 mm far towards the east, and the other one is 1 mm far towards the north. It is required to find the direction of the force acting on the charge in my hand.

Let the magnitude of the charge in my hand is Q, and the magnitude of the other charges is q.

Thus the electric force applied on the charge in my hand due to each other is,

\(F=\frac{kQq}{r^2}\)

Here k is the Coulomb constant, and r is the distance between the charges.

It is also known that the force on a positive charge due to another positive charge is acted outwards.

Thus, the force on the charge due to the charge on the east is,

\(\vec{F_1}=\frac{kQq}{( 10^{-3}\text{ m})^2}\hat{i}\)

And the force on the charge due to the charge on the north is,

\(\vec{F_2}=\frac{kQq}{( 10^{-3}\text{ m})^2}\hat{j}\)

As the forces are equal in magnitude and one is perpendicular to the other, thus the net force will be acted at an angle of \(45^\circ\) from the north or from the north direction.

Thus the net force is acting in the north-east direction.

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Answer:c 40kg

Explanation:

Answer:

B. 30 kg * m/s

Explanation:

college board answer

Answer:

The horizontal component of the velocity is approximately 13.22 m/s

Explanation:

The velocity of the kick which the football player gives the ball = 21 m/s

The angle of the path taken by the ball = 51°

The velocity can be represented vectorially, showing the vertical and horizontal components as follows;

v = 21 × cos(51°)·\(\hat i\) + 21 × sin(51°)·\(\hat j\)

Where we have;

The horizontal component of the velocity = 21 × cos(51°)

The vertical component of the velocity = 21 × sin(51°)

Therefore;

The horizontal component of the velocity = 21 × cos(51°) ≈ 13.22 m/s

The horizontal component of the velocity ≈ 13.22 m/s.

The ball rolling down the longest ramp (ramp 3) will have the greatest speed at the bottom, followed by the ball rolling down the intermediate ramp (ramp 2), and finally the ball rolling down the shortest ramp (ramp 1). So the correct answer is option 3: ramp 3.

The ball rolling down the steeper ramp will experience a greater net force, and thus will accelerate more than the ball rolling down the shallower ramp. However, the ball rolling down the steeper ramp also has to travel a longer distance to reach the bottom, so the relationship between the ramp length and the ball's final speed at the bottom is not immediately clear.

To solve this problem, we can use the conservation of energy principle. At the top of each ramp, the ball has only potential energy, which is converted into kinetic energy as the ball rolls down the ramp. If we assume that there is no friction, the total mechanical energy of the ball is conserved.

Let M be the mass of the ball, h be the height of the ramp, and L1, L2, and L3 be the lengths of the ramps for cases 1, 2, and 3, respectively. The potential energy of the ball at the top of the ramp is Mgh, where g is the acceleration due to gravity. At the bottom of the ramp, the ball has both potential and kinetic energy, given by:

1/2 M v² + Mgh

where v is the final speed of the ball at the bottom of the ramp.

Since the total mechanical energy is conserved, we can equate the initial potential energy to the final total energy:

Mgh = 1/2 M v² + Mgh

Simplifying, we get:

v = √(2gh)

Since the height of the ramp is the same for all cases, the final speed of the ball at the bottom of the ramp depends only on the length of the ramp. The longer the ramp, the greater the final speed.

The ball will therefore be moving with the greatest speed at the bottom of the longest ramp (ramp 3), followed by the intermediate ramp (ramp 2), and lastly the shortest ramp (ramp 1). (ramp 1). Therefore, choice 3: ramp 3 is the right response.

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The total work done on the block by the force of friction as it moves a distance L up the incline depends on the coefficient of friction (μ), the magnitude of the normal force (N), and the distance traveled (L). The work done by friction can be calculated as:

Wfric = μN cosθ × L

where θ is the angle of the incline.

The cosine of the angle accounts for the fact that friction acts parallel to the incline, so only the component of the force in the direction of motion contributes to the work done. Friction always opposes motion, so the work done by friction is always negative. This means that the force of friction removes energy from the system, which results in a decrease in the speed of the block. If the work done by friction is greater than the work done by other forces, such as the force of gravity, the block will eventually come to a stop.

Therefore, to calculate the total work done by friction, we need to know the angle of the incline, the coefficient of friction, and the normal force acting on the block.

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Answer:

2 or more atoms

Explanation:

yes yes yes yes yes yes yes yes

Answer:

Two or more

Explanation:

It's mostly two but unique structures might compose of more than 2

Answer:

F= ke

Here, F means Force, k is the spring constant and e is the exrension in metres.

(Hooke's Law)

1. The phone is moving with a velocity of 20.77 m/s before racking into pieces

2. The time taken for the ball to come back to their hand is 0.82 s

3. The maximum height reached by the batarang is 49.03 m

4. The cliff is 1016.06 m high

5. The object is moving with a velocity of –8.6 m/s after 2 s

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 22)

v² = 431.2

Take the square root of both side

v = √431.2

v = 20.77 m/s

We'll begin obtaining the time taken to reach the maximum height. This is illustrated below:

v = u – gt (since the ball is going against gravity)

0 = 4 – (9.8 × t)

0 = 4 – 9.8t

Collect like terms

0 – 4 = –9.8t

–4 = –9.8t

Divide both side by –9.8

t = –4 / –9.8

t = 0.41 s

Finally, we shall determine the time for the entire trip

T = 2t

T = 2 × 0.41

T = 0.82 s

v² = u² – 2gh (since the ball is going against gravity)

0² = 31² – (2 × 9.8 × h)

0 = 961 – 19.6h

Collect like terms

0 – 961 = –19.6h

–961 = –19.6h

Divide both side by –19.6

h = –961 / –19.6

h = 49.03 m

h = ½gt²

h = ½ × 9.8 × 14.4²

h = 4.9 × 207.36

h = 1016.06 m

v = u – gt (since the ball is going against gravity)

v = 11 – (9.8 × 2)

v = 11 – 19.6

v = –8.6 m/s

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