Calculate the density of the four solutions. All of the solutions has the volume equal to 25 ml. Red solution has 25.0 g of mass. Green has 26.5 g of mass. Yellow has 28.2 g of mass and Blue one has 30.0 g of mass.

Four physical properties of matter are density, colour, hardness, melting and boiling points and many more.

The matter is usually composed of tiny particles known as atoms and can be represented as something that occupies space. It must represent both the mass and volume properties.

Properties are defined as the features that capable us to differentiate one material from another. A physical property is usually a characteristic of matter that does not depend on its chemical composition.

Generally a physical property is defined as an attribute of matter that is independent of its chemical composition. Some of the main examples of physical properties density, color, hardness, melting and boiling points, and electrical conductivity.

Learn more about physical properties from the link given below.

https://brainly.com/question/18327661

#SPJ4

In order to determine the specific heat capacity of a substance, the following formula can be used:Q = m c ΔTwhere Q is the heat energy transferred to the substance, m is the mass of the substance, c is its specific heat capacity, and ΔT is the change in temperature of the substance.

In the given problem, 14000 J of energy is transferred to 1.5 kg of liquid A. The temperature of liquid A rises from 12°C to 19°C. Therefore, we can plug in these values into the formula:14000 = 1.5 x c x (19-12)14000 = 1.5 x c x 7Simplifying this equation, we can cancel out 1.5 and multiply 7 by c:14000 / (1.5 x 7) = c

Therefore, the specific heat capacity of liquid A is approximately 1333 J/kg °C.

To know more about mass visit:-

https://brainly.com/question/11954533

#SPJ11

Answer: There are \(27.701 \times 10^{23}\) molecules in 4.6 moles of ammonium nitrate \((NH_{4}NO_{3})\).

Explanation:

According to the mole concept, there are \(6.022 \times 10^{23}\) molecules present in 1 mole of every substance.

Hence, the number of molecules present in 4.6 moles of ammonium nitrate are calculated as follows.

\(4.6 \times 6.022 \times 10^{23}\\= 27.701 \times 10^{23} molecules\)

Thus, we can conclude that there are \(27.701 \times 10^{23}\) molecules in 4.6 moles of ammonium nitrate \((NH_{4}NO_{3})\).

Answer:

Answer:

Don't plagiarize here.

Explanation:

Your online teacher knows that you are looking here for the answer!!!!

When placed at the same temperature, the entropy of 10 mole of Ar(g) at 10.0 atm and the 10 mole of Ar(g) at 0.5 atm. The system has a higher entropy is 10 mole of Ar(g) at 0.5 atm.

The entropy is the measure the randomness of the of the system.  the measure of the system's thermal energy per unit the temperature that is not available for doing the useful work.

The Entropy will increases with temperature at the constant pressure. The  pressure increases leads to the higher degree of the order in the molecular arrangement. so, the entropy decreases with the increasing pressure.

To learn more about entropy here

https://brainly.com/question/13999732

#SPJ4

The new pressure of the gas : 0.75 atm

Boyle's Law  

At a constant temperature, the gas volume is inversely proportional to the pressure applied  

\(\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}\)

P₁=1 atm ⇒ standart temperature and pressure (STP)

V₁=3 L

V₂=4 L

\(\tt P_2=\dfrac{P_1.V_1}{V_2}\\\\P_2=\dfrac{1\times 3}{4}\\\\P_2=0.75~atm\)

Both students have correctly prepared a 1.0 M aqueous solution of potassium phosphate.

To determine which student has correctly prepared a 1.0 M aqueous solution of potassium phosphate (K₃PO₄), we need to compare their procedures.

Jennifer filled a 1.0 liter volumetric flask to calibration line having with water and then weighs out 212.3 g of potassium phosphate to add to the flask.

Joe, on the other hand, weighs out 212.3 g of the potassium phosphate as well as adds it to a 1.0 liter volumetric flask. He then fills the flask to the calibration line with water.

To determine the correct preparation method, we need to consider the molar mass of potassium phosphate (K₃PO₄), which we calculated previously as 212.27 g/mol.

Comparing the two methods;

Jennifer uses the correct amount of potassium phosphate (212.3 g), which corresponds to approximately 1 mole of K₃PO₄.

Joe also uses the correct amount of potassium phosphate (212.3 g), which corresponds to approximately 1 mole of K₃PO₄.

Both students have used the correct amount of potassium phosphate, which matches the molar mass of K₃PO₄. Therefore, both students have correctly prepared a 1.0 M aqueous solution of potassium phosphate.

To know more about aqueous solution here

https://brainly.com/question/1382478

#SPJ4

--The given question is incomplete, the complete question is

"An experiment in chm 2045 requires students to prepare a 1.0 M aqueous solution of potassium phosphate. Jennifer fills a 1.0 liter volumetric flask to the calibration line with water. She then weighs out 212.3 g of potassium phosphate and adds it to the volumetric flask. Joe weighs out 212.3 g of potassium phosphate and adds it to a 1.0 liter volumetric flask. He then fills the volumetric flask to the calibration line with water. Which student has correctly prepared a 1.0 M aqueous solution of potassium phosphate?"--

Explanation:

Avogadro's number. What can be said about 1 mol Ag and 1 mol Au? ... They contain the same number of atoms.

1 mole of Ag and 1 mole of Au contain the same number of particle. Therefore, option B is correct.

The International System of Units uses the mole (symbol: mol) as the unit of material quantity. How many elementary entities of a particular substance are present in an object or sample is determined by the quantity of that material. It is specified that the mole contains exactly 6.022140761023 elementary entities.

A mole is defined as the mass of a substance that has the same number of elementary particles as there are atoms in precisely 12.000 g of 12C.

In the periodic chart, group 11 includes the chemical elements roentgenium (Rg), copper (Cu), silver (Ag), and gold (Au). However, no chemical tests have yet been done to demonstrate that roentgenium behaves similarly to the heavier homologue of gold.

Thus, option B is correct.

To learn more about mole, follow the link;

https://brainly.com/question/26416088

#SPJ2

Answer:0.2496m³/day

Explanation:

When naming an alkene, the parent chain is the longest carbon chain that contains both atoms of the double bond (option D).

This chain is numbered in such a way that the carbons of the double bond get the lowest possible numbers. If there are multiple double bonds, the numbering starts at the end closest to one of them. If there are substituents present, they are named and numbered using the lowest possible numbers.

However, if there is a choice, the substituent closer to the double bond gets the lower number. If there are multiple branches, the parent chain is still the longest one that contains both atoms of the double bond, but the branches are named and numbered as substituents.

It is important to note that the prefix "ene" is added to the end of the parent chain name to indicate that it is an alkene.

To know more about alkene. please visit.....

brainly.com/question/22850898

#SPJ11

Answer:

based on texture/ feel, oder/smell, melting/boiling point

Explanation:

Answer:

Smell it, drink it, throw it at someone.

Explanation:

If none of that hurts or kills anyone, you can mark everything that would off the list.

Answer:

ot

Explanation:

there is no choices

Answer:

Advertise

Explanation:

once a product is ready to be sold, engineers explain their ideas to marketing people, who will advertise the product.

Answer:

116 years

Explanation:

To solve this, we will use the half life equation;

A(t) = A_o(½)^(t/t_½)

Where;

A(t) is the amount of strontium left after t years;

A_o is the initial quantity of strontium that will undergo decay;

t_½ is the half-life of strontium

t is the time it will take to decay

We are given;

A(t) = 7.5 g

A_o = 120 g

From online values, half life of strontium-90 is 29 years. Thus, t_½ = 29

Thus;

7.5 = 120 × ½^(t/29)

Divide both sides by 120 to get;

7.5/120 = ½^(t/29)

0.0625 = ½^(t/29)

In 0.0625 = (t/29) In ½

-2.772589 = (t/29) × (-0.693147)

(t/29) = -2.772589/(-0.693147)

t/29 = 4

t = 29 × 4

t = 116 years

The amino acid sequence will be determined by the codons in the mRNA sequence that is being translated.

During translation, the mRNA sequence is read three nucleotides at a time, and each codon is translated into an amino acid based on the genetic code. This process is known as the "triplet code" because codons are made of three nucleotides.

The ribosome reads the mRNA sequence and translates it into a protein by recruiting amino acids in the correct order. The tRNA molecules carry the correct amino acids to the ribosome, where they are added to the growing polypeptide chain.

The ribosome continues to read the mRNA sequence until it reaches a stop codon, which signals the end of the translation and the completion of the amino acid sequence.

For more questions like Amino acid  click the link below:

https://brainly.com/question/11737661

#SPJ4

The most suitable solution of alcohol for the component dyes of wet-erase markers would be a 70% solution of isopropyl alcohol. Isopropyl alcohol or rubbing alcohol is an organic compound that has a wide range of applications.

It is a colorless liquid and is most commonly used as a solvent in medical settings and cleaning. It is composed of about 70% isopropyl alcohol and 30% distilled water.

The solvent properties of isopropyl alcohol make it ideal for use in many applications. It is capable of dissolving a wide range of organic and inorganic substances, including oils, dirt, and bacteria. As a result, it is often used as a cleaning agent, antiseptic, and disinfectant. It is also commonly used as a solvent in the production of various products, including wet-erase markers.

The component dyes of wet-erase markers are most soluble in a 70% solution of isopropyl alcohol. This solution provides the optimal conditions for dissolving the dyes and allowing them to mix with other components of the marker ink.

Overall, a 70% solution of isopropyl alcohol is the most effective solvent for the component dyes of wet-erase markers.

Learn more about alcohol

https://brainly.com/question/29268872

#SPJ11

70% Isopropyl alcohol (rubbing alcohol)

Wet-erase markers are water-soluble, and dry-erase markers are alcohol-soluble. To determine the solution of alcohol in which the component dyes of wet-erase markers are most soluble, the best answer is 70% Isopropyl alcohol (rubbing alcohol).

Explanation:

Wet-erase markers, also known as Vis-a-Vis markers, use a water-soluble ink that works effectively on wet or non-porous surfaces like plastic, acetate sheets, and laminated surfaces. However, simply wiping off the marks with water alone is insufficient. Instead, rubbing with a damp cloth or a tissue soaked in rubbing alcohol is required to remove the marks.

The component dyes of wet-erase markers are most soluble in 70% Isopropyl alcohol (rubbing alcohol). Isopropyl alcohol has a low molecular weight and serves as a versatile solvent, making it an excellent choice for dissolving the ink dyes of wet-erase markers. Additionally, it is less harsh compared to other types of alcohols, making it suitable for cleaning delicate surfaces.

To know more about topic Rubbing alcohol or Isopropyl alcohol here: https://brainly.com/question/32798438

#SPJ11

In an open container, an equilibrium vapor pressure can be reached as long as the liquid has molecules capable of evaporating and the surrounding space allows for the escape and mixing of vapor molecules with the air.

Vapor pressure is the pressure exerted by the vapor molecules when the liquid and vapor are in equilibrium. It is a measure of the tendency of a liquid to evaporate. At any given temperature, molecules within the liquid have a range of kinetic energies. Some molecules have sufficient energy to overcome intermolecular forces and escape into the gas phase, forming vapor. As more molecules escape, the vapor density increases, creating a pressure known as the vapor pressure.

In an open container, the vapor molecules can freely escape into the surrounding space and mix with the air. Initially, the evaporation rate is high as molecules escape from the liquid surface. As the concentration of vapor molecules increases, collisions between the vapor and liquid surface also result in some molecules returning to the liquid phase, which is called condensation. Eventually, a dynamic equilibrium is established where the rate of evaporation and condensation become equal.

At this equilibrium, the vapor pressure above the liquid remains constant as long as the temperature is constant. The concentration of vapor molecules in the air above the liquid reaches a steady state, and the system is said to be saturated. The equilibrium vapor pressure is determined by the temperature and the characteristics of the liquid, such as its volatility and intermolecular forces.

Therefore, In an open container, an equilibrium vapor pressure can be reached above a liquid.

To know more about vapor pressure, refer to the link below:

https://brainly.com/question/15629887#

#SPJ11

Answer:

The answer is Bicarbonate ions.

Answer:

C. Carbonic base

Explanation:

EDG2021

your anwser would be 342 gmol  Please mark branliest

Just get out that Periodic Table of the Elements, find the atomic masses for each atom, and add them up!

Carbon = 12

Hydrogen = 1

Oxygen = 16

C=12×12=144

H=1×22=22

O=16×11=176

Sucrose =144+22+176=342gmol

Answer:

Cohesion

Explanation:

D. you're welcome

One of water's most distinctive properties is cohesion—that is, the tendency of water molecules to "stick" to one another. In plants, this cohesion results in columns of water that stretch through the plant's xylem (the vascular tissue responsible for the transport of water), from the roots all the way to the leaves.

25.0 mL of HCl is required to react with the excess NaOH.

The number of mL of HCl required to react with the excess NaOH can be determined using the equation

M1V1 = M2V2,

where M1 is the molarity of NaOH, V1 is the volume of NaOH, M2 is the molarity of HCl, and V2 is the volume of HCl. First, we need to find the moles of NaOH using the given molarity and volume:

Moles of NaOH = M1V1 = (0.100 M)(50.0 mL) = 5.00 x 10^-3 moles NaOH

Next, we use the balanced chemical equation for the reaction between NaOH and HCl to determine the moles of HCl required to react with the excess NaOH:

NaOH + HCl → NaCl + H2O

According to the balanced equation, 1 mole of NaOH reacts with 1 mole of HCl. Therefore, the moles of HCl required to react with the excess NaOH is also 5.00 x 10^-3 moles HCl.

Finally, we use the equation M1V1 = M2V2 to find the volume of HCl required:

Moles of HCl = M2V2

5.00 x 10^-3 moles HCl = (M2)(V2)

V2 = (5.00 x 10^-3 moles HCl) / M2

If the molarity of HCl found in question 1 is 0.200 M, then:

V2 = (5.00 x 10^-3 moles HCl) / (0.200 M)

V2 = 25.0 mL HCl

To learn more about Molarity :

https://brainly.com/question/30404105

#SPJ11

Answer:

The closer a place is to the equator the warmer it is

Explanation:

The equator is the part of the earth that is in the sun the longest and the poles are in the sun for a very short period of time each year. Therefore the equator is the warmest compared to the two poles.

The atomic mass of rubidium listed in the periodic table to determine the mass of Rb−87 is 86.13 amu.

The atomic mass is the weight of the roton neutron and electron present inside the nucleus and shells of an atom and the elements are arranged on the basis of this only.

The mass of Rb−85 is 84.9118 amu for 1 amu it will be

amu =  84.9118 / 85 = 0.99

so, the amu for Rb−87 will be,

     AMU = 87 × 0.99 = 86.13 amu.

Therefore, the mass of Rb−87 is 86.13 amu for  atomic mass of rubidium listed in the periodic table.

Learn more about atomic mass, here:

https://brainly.com/question/18909702

#SPJ1

The mass of the N₂O in the given question is 92.4g.

STEP1- Apply the ideal gas equation

            PV=nRT

STEP2- Put the given values in the equation

            P=130kPa,     T=298K,     V=40L  R=8.31

STEP3- Solve the equation

           N=PV/RT,

           N=130×40/8.31×298

             N=2.1moles

             N=mass/molecular mass

             mass=2.1×44

            mass = 92.4g

Hence, the mass of N₂O is 92.4g.

learn more about ideal gas.

https://brainly.com/question/25290815

#SPJ1

Answer:I think it’s mechanical energy

Explanation:

The pressure of a gas is directly proportional to its volume, according to Boyle's Law. this pressure is less than the maximum pressure that the can can withstand (3,800 kPa), the can will not burst.

Therefore, we can use the following equation to find the pressure of the gas in the can after it is crushed: P1V1 = P2V2 where P1 and V1 are the initial pressure and volume of the gas, and P2 and V2 are the final pressure and volume of the gas, respectively. Given that the initial volume (V1) of the gas in the can is 235 mL and the initial pressure (P1) is 110 kPa, we can substitute these values into the equation P1V1 = P2V2 110 kPa × 235 mL = P2 × 8.5 mL Solving for P2, we get: P2 = (110 kPa × 235 mL) / 8.5 mL P2 = 3,027 kPa Therefore, the pressure of the gas in the can after it is crushed to a volume of 8.5 mL is 3,027 kPa. Since this pressure is less than the maximum pressure that the can can withstand (3,800 kPa), the can will not burst.

learn more about pressure at :

https://brainly.com/question/12971272

#SPJ4

The required volume for 50% conversion of compound A in the plug flow reactor is determined using the flow rate, reaction rate, conversion, and rate constant, and The length of the reactor required to achieve 65% conversion of compound A is calculated using the volume, flow area, conversion, and rate constant.

(a) The required volume for a conversion of 50% of A can be calculated using the following equation:

V = (F0 / (-rA)) * (1 / X) * (1 / kp)

where:

V is the required volume,

F0 is the molar flow rate of A,

-rA is the rate of reaction of A,

X is the desired conversion (in this case, 50%),

kp is the rate constant for the reaction.

Given that F0 = 10 mol/s, X = 0.50, and kp = 50 mol/s·m³·bar, we can substitute these values into the equation to find V.

(b) The length required for a conversion of 65% of A can be calculated using the equation:

L = (V / A) * (1 / X) * (1 / kp)

where:

L is the required length,

V is the volume,

A is the area of flow in the tube,

X is the desired conversion (in this case, 65%),

kp is the rate constant for the reaction.

Given that V is the volume calculated from part (a) and A = 0.02 m², we can substitute these values along with X = 0.65 and kp = 50 mol/s·m³·bar into the equation to find L.

To know more about rate constant please refer:

https://brainly.com/question/24749252

#SPJ11

No, only water. Everything has a different b.p & m.p so you can't rlly say all liquids will turn to gas in 100°C. But water does.

Hope it helps :))))

Answer:

Please did you ever get an answer??

Explanation:

Im doing usa test prep too and its really late