Calculate the 95% confidence interval for the slope. o (-0.327, 0.00) o (-0.305,-0.022) o (-0.308,-0.019) o (-0.322,0.021)

Answer:

B.) 20 degrees

Step-by-step explanation:

We know that the sum of angles in a triangle is equal to 180, so we can say that 80 + 4x + x is equal to 180. This means that 5x is 100 degrees, meaning that x = 20 degrees. The option with this answer is B.).

Answer:

The answer is B.

Step-by-step explanation:

4 × 20 = 80

80 + 80 = 160

A triangle is 180°

Find the missing x.

180 - 160 = 20

Plug 20 in for both x's to check your work.

Hope this helps :)

-ilovejiminssi♡

1. A secant is: segment HF

2. The radius = 8 units; 3. Perimeter of the triangle = 37.6.

In geometry, a secant is a line that intersects a curve or a circle at two distinct points, and it can be extended infinitely in both directions.

In geometry, the Tangent Theorem states that a line tangent to a circle is perpendicular to the radius that intersects the point of tangency.

1. The name of a secant in the circle shown can be segment HF.

2. DE is tangent to the circle, and DC is the radius, therefore triangle CDE is a right tringle. Applying the Pythagorean theorem, we have the equation:

CD² = 17² - 15²

CD² = 64

CD = 8

Therefore, radius = CD = 8

3. Applying the two-tangent theorem, we have:

Perimeter = 8 + 6.2 + 12.6 + (12.6 - 8) + 6.2

Perimeter = 37.6

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Answer:

.549 (all under bar/repeted)

Step-by-step explanation:

These two lines intercept on a graph on the coordinate X(0, 1) Y(9, 7).

The term "intercept" refers to the location where a line or curve intersects an axis on a graph. An object's x-intercept is defined as where a point crosses the x-axis. The term "y-intercept" refers to a point that crosses the y-axis. The intersection of the x-axis and the y-axis is what is meant by a line's intercept.

step1

y=-2x+9

graph the line using the slope and y intercept or two points

y=-2x+9

X(0,1) Y(9,7)

step2

y=3x-6

slope 3 y intercept (0,-6)

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Answer:

150 meters

Step-by-step explanation:

5x3=15

5x4=20

20x15=300

300/2=150

Answer:

150  meters <3

Step-by-step explanation:

A unit circle has a radius of 1, so r = 1. The point P(9/10, y) in the IV quadrant will have a positive x-value and a negative y-value.

Using the Pythagorean theorem we know that, x² + y² = r², in a Cartesian coordinate system. We can solve for y by rearranging the formula, r² - x2 = y², or y = ±√(r² - x²).

y = ±√(r² - x²)

y = ±√([1]² - [9/10]²)

Simplify the expression we have

y = ±√(1 - 81/100)

y = ±√(1-0.81)

y = ±√0.19, we choose the negative for quadrant IV.

y = -√0.19

y = -0.4359

Sin -0.4359 = 26 degrees in the IV quadrant, = 360-26 =334 degrees

CosA = 0.4359 in the Iv quadrant is positive we chose the positive figure 64 degrees

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The reason why the following hypotheses are not constructed correctly is because of option B. The hypothesized value is not the same under the null and alternative hypotheses.

In hypothesis testing, the null hypothesis (H0) and the alternative hypothesis (HA) should have the same hypothesized value, but with opposite signs. In this case, the hypothesized value is 10, but the signs are not opposite. The null hypothesis has a less than or equal to sign (≤) and the alternative hypothesis has a greater than or equal to sign (≥). This means that there is overlap between the two hypotheses, which is not correct.

The correct way to construct the hypotheses would be:
H0: μ ≤ 10; HA: μ > 10
or
H0: μ ≥ 10; HA: μ < 10

Option A is incorrect because the alternative hypothesis can have the equality sign if the null hypothesis does not have it. Option C is also incorrect because hypothesis testing is about a population parameter, not a sample statistic.

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Answer:

Step-by-step explanation:

\(8a - 5b - (6a - 9b)\)

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression.

\(8a - 5b - 6a + 9b\)

Collect like terms

\(2a + 4b\)

Factor out 2 from the expression

\(2(a + 2b)\)

Hope this helps...

Good luck on your assignment..

Answer:

2(a + 2b)

Step-by-step explanation:

If the radius of circle is represented by the expression "z + 3.6" , then the value of z is 568.9 ft.

The length of the radius of the circle is measured in feet ;

the expression that represents the radius of circle is = z + 3.6 ;

also given that the diameter of the circle is = 1145 ft ;

So ,the radius will be = 1145/2 ft ;

On equating both the radius ,

we get ;

z + 3.6 = 1145/2 ;

z + 3.6 = 572.5 ;

z = 572.5 - 3.6 ;

z = 568.9 .

Therefore , the value of z is = 568.9 ft .

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Answer: The correct answer is 2.3

Step-by-step explanation: Answer confirmed correct on test so no worries

Answer:

go to khan academy

Step-by-step explanation:

Answer:

no solution

Step-by-step explanation:

y=3x+1; 6x-2y=5

6x-2(3x+1)=5    replacing y with 3x+1 because y is equal that equation

6x -6x-2=5

0=7-->no solution

We can write this equation as (x-3)² + (y-2)² =25 in graphing form.

The vertex form of a quadratic equation is y = a (x h) 2 + k as opposed to the regular quadratic form, which is an x 2 + b x + c = y. Graphs

f(x) = ax² + bx + c, where a, b, and c are numbers and an is not equal to zero, is a quadratic function. A parabola is the shape of a quadratic function's graph.

Given Data

Equation:

x² +y² -6x +9y - 12 = 0

Writing in graphing form,

(x² - 6x) + (y² + 4y) = 12

(x² - 6x +9-9) + (y² +4y+4-4) = 12

(x² -6x +9) + (y² +4y+4) = 25

(x-3)² + (y-2)² =25

Center (x, y) = (3,-2)

radius r = 5

We can write this equation as (x-3)² + (y-2)² =25 in graphing form.

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We can use a normal probability model to represent the distribution of sample means when the sample size is large enough to ensure that sample means will be normally distributed, option (C) is correct.

The central limit theorem (CLT) states that when sample sizes are sufficiently large (typically, n > 30), the distribution of sample means will be approximately normal, regardless of the distribution of the variable in the population.

This is because as the probability of sample size increases, the sample mean becomes a more reliable estimate of the population mean, and the variability in the sample means decreases. This results in a distribution that is bell-shaped and symmetric, similar to a normal distribution, option (C) is correct.

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– The question is inappropriate, The correct question is:

We can use a normal probability model to represent the distribution of sample means for which of the following reasons? check all that apply.

A) the sample is randomly selected

B) the distribution of the variable in the population is normally distributed

C) the sample size is large enough to ensure that sample means will be normally distributed flag –

Answer:

4/7

Step-by-step explanation:

Since there are 7 possible outcomes because there are 7 triangles the denominator will be 7. Since there are 4 white squares the chances of landing on one is 4/7

The function f, in the slope-intercept form is f= -3x+6.

The slope or gradient of the line is a numerical value used to describe a line's steepness and direction in mathematics. It was first used to describe slope in O'Brien's (1844) and Todhunter's (1888) versions of the equation for a straight line, which are both written as "y = mx + b" and "y = mx + c," respectively. The choice of the letter m for slope has no apparent justification.

Calculating slope involves comparing the "vertical change" to the "horizontal change" between any two points on a line, or any two points. The ratio, which provides the same number for each, is occasionally given as a quotient ("rise over run").

Here given,

For a linear function f,

f(2)=0 and f(4)=-6

So, from the given hint the points are (2, 0) and (4, -6)

Here slope m=(-6-0)/(4-2)

m=-6/2

m= -3

We know that the equation of the function in slope-intercept form is:

f=mx +c

By substituting the point (2, 0) and m= -3 in the function we get,

0= -3(2)+c

c=6

Now, by substituting m= -3 and c=6 in the function, we get

f= -3x+6

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(i) The 90% confidence interval for the population parameter is (27.37, 45.79).

(ii) The interval (boundary values) of the 90% confidence interval is shown on the distribution graph.

After calculating the lower and upper limits using the formula above, the interval is found to be (27.37, 45.79) and  we can be 90% confident that the population parameter lies within this range.

Given the following information:

Random sample of 18 students

Sample standard deviation = 10.49

90% confidence interval

To find:

(i) Form a 90% confidence interval for the population parameter.

(ii) Show the interval (boundary values) on the distribution graph.

The population variance can be estimated using the sample variance. Since the sample size is small (n < 30) and the population variance is unknown, we will use the t-distribution instead of the standard normal distribution (z-distribution). The t-distribution has fatter tails and is flatter than the normal distribution.

The lower limit of the 90% confidence interval is calculated as follows:

Lower Limit = sample mean - (t-value * standard deviation / sqrt(sample size))

The upper limit of the 90% confidence interval is calculated as follows:

Upper Limit = sample mean + (t-value * standard deviation / sqrt(sample size))

The t-value is determined based on the desired confidence level and the degrees of freedom (n - 1). For a 90% confidence level with 17 degrees of freedom (18 - 1), the t-value can be obtained from a t-table or using statistical software.

After calculating the lower and upper limits using the formula above, the interval is found to be (27.37, 45.79).

(ii) Showing the interval (boundary values) on the distribution graph:

The distribution graph of the 90% confidence interval of the variance of the students' final grade is plotted. The range between 27.37 and 45.79 represents the interval. The area under the curve between these boundary values corresponds to the 90% confidence level. Therefore, we can be 90% confident that the population parameter lies within this range.

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The numbers : 4,-10 and -4 are integers.

A number without a decimal or fractional element is known as an integer, which can be both positive and negative, including zero.

The Latin word "integer" signifies "whole" or "intact." Thus, fractions and decimals are not included in integers.

All whole numbers and negative numbers are considered integers. This means that if we combine negative numbers with whole numbers, a collection of integers results.

"Negative 1 and one-third" includes a fractional part, so it is not an integer.

"2.5" and "0.ModifyingAbove 13 with Bar" contain a decimal, so it is also not an integer.

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Even if R is anti-reflexive, R2 may not necessarily be anti-reflexive. It depends on the specific properties and composition of the relation R.

Let R be a relation that is reflexive and transitive. We want to prove that R2 = R for any relation R with these two properties.

To prove this, we need to show that for any ordered pair (a, b), (a, b) ∈ R2 if and only if (a, b) ∈ R.

First, let's consider (a, b) ∈ R2. By definition, (a, b) ∈ R2 means that there exists an element c such that (a, c) ∈ R and (c, b) ∈ R.

Since R is reflexive, we know that (a, a) ∈ R and (b, b) ∈ R.

By the transitivity of R, if (a, c) ∈ R and (c, b) ∈ R, then (a, b) ∈ R.

Therefore, (a, b) ∈ R2 implies (a, b) ∈ R.

Now, let's consider (a, b) ∈ R. Since R is reflexive, we have (a, a) ∈ R and (b, b) ∈ R.

By the definition of R2, (a, a) ∈ R2 and (b, b) ∈ R2.

Since R is transitive, if (a, a) ∈ R2 and (a, b) ∈ R2, then (a, b) ∈ R2.

Therefore, (a, b) ∈ R implies (a, b) ∈ R2.

We have shown that for any ordered pair (a, b), (a, b) ∈ R2 if and only if (a, b) ∈ R. Hence, R2 = R.

If the relation R is anti-reflexive, it is not necessarily true that R2 is anti-reflexive.

To understand why, let's consider an example. Let R be a relation defined on the set of integers such that R contains the ordered pairs (a, b) where a < b.

In this case, R is anti-reflexive because for any integer a, (a, a) is not in R.

Now, let's consider R2. R2 is the composition of R with itself. If (a, b) ∈ R and (b, c) ∈ R, then (a, c) ∈ R2.

In our example, if we take a = 1, b = 2, and c = 3, we have (1, 2) ∈ R and (2, 3) ∈ R. Therefore, (1, 3) ∈ R2.

However, (1, 1) is not in R2 because (1, 1) is not in R. Therefore, R2 is not anti-reflexive in this case.

This example demonstrates that even if R is anti-reflexive, R2 may not necessarily be anti-reflexive. It depends on the specific properties and composition of the relation R.

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Number of observations would be necessary to determine the true cycle time with a 95% confidence level and an accuracy are 16.

Sample timings as observed are 3.5, 3.1, 4.0, 3.5, and 3.9.

Sample-time average (X) = (3.5+3.1+4+3.5+3.9)/5

The average sample time (X) is 3.6.

Observed time (T) Mean (X) (X - T) (X - T)^2

3.5 3.6 0.1 0.01

3.1 3.6 0.5 0.25

4.0 3.6 -0.4 0.16

3.5 3.6 0.1 0.01

3.9 3.6 -0.3 0.09

Allow Standard deviation to be S.

2 in (X-T) - 1 n

\(S=\sqrt{\frac{0.52}{4}}\)

S = 0.3605

Considering that (h) = 0.05,

Given that 95% of the time,

Z value at 95% confidence interval = 1.96

Let N be the number of observations.

2 N= Z.S hX

\(N=(\frac{1.96X0.3605}{0.05X3.6})\)

N = 15.4

N = 16 (rounded off to next whole number) (rounded off to next whole number)

Consequently, 16 observations are required.

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Answer:

Step-by-step explanation:

Number of observations would be necessary to determine the true cycle time with a 95% confidence level and an accuracy of 16.

Sample-time average (X) = (3.5+3.1+4+3.5+3.9)/5

The average sample time (X) is 3.6. Observed time (T) Mean (X) (XT) (X-T)^2

3.5 3.6 0.1 0.01

3.1 3.6 0.5 0.25

4.0 3.6 -0.4 0.16

3.5 3.6 0.1 0.01

3.9 3.6-0.3 0.09

Allow Standard deviation to be S.

2 in (X-T) - 1n

S=√0.52/4

S=0.3605

Considering that (h) = 0.05,

Given that 95% of the time,

Z value at 95% confidence interval = 1.96 Let N be the number of observations.

2 N=Z.S hx

N=(1.96X0.3605)÷(0.05×3.6)

N = 15.4

N = 16 (rounded off to next whole number) (rounded off to next whole number) Consequently, 16 observations are required.

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Answer:

Two examples of heterocrine glands are the pancreas and the salivary glands.

Step-by-step explanation:

Two examples of heterocrine glands are the pancreas and the salivary glands.

The pancreas is a heterocrine gland because it contains both exocrine cells that secrete digestive enzymes into the small intestine via ducts, as well as endocrine cells that secrete hormones directly into the bloodstream. The exocrine function of the pancreas helps in the digestion of carbohydrates, proteins, and fats.

The salivary glands are also heterocrine glands because they produce both exocrine and endocrine secretions. The exocrine function of the salivary glands involves the production and release of saliva into the oral cavity via ducts, which helps in the digestion of carbohydrates and lubrication of the mouth. The endocrine function of the salivary glands involves the secretion of hormones that regulate various physiological processes, including blood pressure and metabolism

Answer:

Disagree

Step-by-step explanation:

Answer:

x < 7

Step-by-step explanation:

-6x > -42

Divide each side by -6, remembering to flip the inequality

-6x/-6 < -42/-6

x < 7

Answer:

\(\boxed{x<7}\)

Step-by-step explanation:

\(-6x > -42\)

Divide both sides by -6 (flip sign).

\(\displaystyle \frac{-6x}{-6} < \frac{-42}{-6}\)

\(x<7\)

Answer:

3

384

5

2.8

10

Step-by-step explanation:

--------------------------------------

10 + 14 = 24  |  13 - 5 = 8

24 divided by 8 = 3

--------------------------------------

8 x 3 = 24  |  10 + 6 = 16

24 x 16 = 384

--------------------------------------

9 + 36 = 45  |  45 - 5 = 40

40 divided by 8 = 5

--------------------------------------

8 - 4 = 4  |  4 + 10 = 14

14 divided by 5 = 2.8

--------------------------------------

8 + 27 = 35  |  35 - 5 = 30

30 divided by 3 = 10

--------------------------------------

Answer:

1. y= 3x-6

2. y= 1/2x-2

Step-by-step explanation:

Rise over run

Answer:  the solution for y in terms of x is y = (-1/4)x - 8.

Step-by-step explanation: In order to obtain a solution for y in the given equation of 4y = -x - 32, it is imperative to achieve the isolation of y on a singular side of the equation. To accomplish this task, it is possible to perform division on both sides of the equation by a factor of 4:

The given equation 4y/4 = (-x - 32)/4 can be expressed in an academic manner as follows: The given equation reveals that the quotient of 4y divided by 4 is equivalent to the quotient of the opposite of x added to negative 32, also divided by 4.

Upon performing simplification, the expression on the right-hand side yields:

The equation y = (-1/4)x - 8 can be expressed in an academic manner as follows: The dependent variable y is equivalent to the product of the constant (-1/4) and the independent variable x, with an additional decrement of eight.

Answer:

divide numerator by the denominator of the fraction.Mean you can divide it

Step-by-step explanation:

I am not sure my answer correct or not,hope you know it.

Answer:

Step-by-step explanation:

oh and...you mean one of these.....sorry i just had to... XD  XD

Answer:

-1.5

Step-by-step explanation:

"h is the amount of right-shift in the translation of the function. Here, the shift is 1.5 units to the left (and 3.5 units down). This make h = -1.5 (and k = -3.5)."