Calculate conditional probabilities of having a particular type of insurance, given Sex, and determine if the two variables are independent.
Row Labels F M Grand Total
BCBS 9 4 13
Medicaid 10 4 14
Private 9 4 13
Self Pay 5 5 10
Grand Total 33 17 50

Answer:

c) terms

Step-by-step explanation:

The rate of change is 3.0, or three assignments are completed every hour when timed in hours.

m =  (6 - 3) miles / (2 - 1) hour = 3 miles / 1h

The rate of change is 3.0, or three assignments are completed every hour when timed in hours.

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Answer:

8 gallons

Step-by-step explanation:

To answer this question :

1 PINT = 0.125 Gallons

1 x 0.125 = 0.125

total gallons of water = 64 x 0.125 = 8 gallons

Answer:

What was the question that you have to show your work for?

Step-by-step explanation:

Answer:

What is the question

Step-by-step explanation:

In this problem, we are given the integral ∫i sin(sin(18x)) dx, and we need to evaluate it using an appropriate substitution.To evaluate the integral, we can make the substitution u = sin(18x).

This choice of substitution is appropriate because it involves the inner function of the sine function.Taking the derivative of u with respect to x, we get du/dx = 18 cos(18x). Solving for dx, we have dx = du / (18 cos(18x)).

Now, substituting u and dx in terms of u into the original integral, we have:

∫i sin(u) (du / (18 cos(18x)))

Simplifying, the integral becomes:

(1/18) ∫i sin(u) du

The integral of sin(u) with respect to u is -cos(u). Therefore, the integral becomes:

(1/18) (-cos(u)) + C

Finally, substituting back u = sin(18x), we have:

(1/18) (-cos(sin(18x))) + C

So, the exact answer to the integral ∫i sin(sin(18x)) dx is (-1/18) cos(sin(18x)) + C.

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Given initial value problem is, y″ − 36y = 9, y(0) = 1, y′(0) = 0

We have to solve this initial value problem by undetermined coefficients.

The general solution of the given differential equation is of the form:

y = C1e^(6t) + C2e^(-6t) + 1/4where C1 and C2 are constants and 1/4 is the particular solution found by the method of undetermined coefficients.

Now we have to determine the values of C1 and C2 using the initial conditions.

The first initial condition:y(0) = 1

Putting t = 0 in the general solution of y, we get:

y(0) = C1e^(6×0) + C2e^(-6×0) + 1/4= C1 + C2 + 1/4= 1

Solving for C1 and C2, we get:C1 + C2 = 3/4 .... (1)

The second initial condition:y′(0) = 0.

Differentiating the general solution of y with respect to t, we get:

y′ = 6C1e^(6t) - 6C2e^(-6t)

Then, putting t = 0 in the above expression, we get:

y′(0) = 6C1 - 6C2= 0

Solving for C1 and C2, we get:C1 = C2 .... (2)

From equations (1) and (2), we get:C1 = C2 = 3/8.

Therefore, the solution of the initial value problem is: y = 3/8(e^(6t) + e^(-6t)) + 1/4.

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Answer: 7 students

Step-by-step explanation:

From the question, we are informed that there a camp is divided into2 groups and that there are 14 kids in Camp A and 21 kids in Camp B.

If the camps are divided into groups of equal size, there will be 7 students in a group. This will be gotten from :

Camp A = 14/2 = 7 students

Camp B = 21/3 = 7 students

Answer:

198 in²

Step-by-step explanation:

triangle (A=1/2)bh [A=1/2(22×8)] b=22 H=8

rectangle (A=bh) [A= 22×5] B=22 H=5

triangle = 88

rectangle = 110

So, 88+110 = 198

(a) The magnitude of B is approximately 3.39 km.

(b) The magnitude of A = magnitude of B = 4.40 km.

(c)  The direction of A - B relative to due south is south of east.

(a) To find the magnitude of B, we can use the Pythagorean theorem because the displacement A and displacement B form a right triangle.

Given:

Displacement A = 2.80 km (due south)

Resultant displacement A + B = 4.40 km

Let's assume the magnitude of displacement B is 'x' km.

According to the Pythagorean theorem:

(A + B)² = A² + B²

(4.40 km)² = (2.80 km)² + x²

19.36 km² = 7.84 km²+ x²

11.52 km² = x²

Taking the square root of both sides:

x = √11.52 km

x ≈ 3.39 km

Therefore, the magnitude of B is approximately 3.39 km.

(b) To find the direction of A + B as a positive angle relative to due south, we can use trigonometric functions. Since displacement A is due south, and displacement B is due east, we have a right triangle where the angle between A and A + B is the angle we're looking for.

Let θ be the angle between A and A + B.

Using trigonometric functions:

tan(θ) = opposite/adjacent = A/B

tan(θ) = 2.80 km / 3.39 km

θ = arctan(2.80/3.39)

θ ≈ 41.5 degrees

Therefore, the direction of A + B as a positive angle relative to due south is approximately 41.5 degrees east of south.

(c) If A - B had a magnitude of 4.40 km, it means the magnitudes of A and B are equal.

Let's assume the magnitude of displacement B is 'y' km.

Given:

Magnitude of A - B = 4.40 km

Therefore, the magnitude of A = magnitude of B = 4.40 km.

(c) The magnitude of B would be 4.40 km.

(d) Since A - B points in the opposite direction of B, the direction of A - B relative to due south would be the same as the direction of B relative to due south, but in the opposite direction.

Therefore, the direction of A - B relative to due south is south of east.

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The area left for children for playing 114464 sq. m

As per the given data inside a park:

The length of the park is 400 m

The breadth of the park is 300 m

The formula for the area of the park = Length × Breadth

= (400 × 300) sq. m

= 120000 sq. m

The width of the walking track inside the park is 4 m

The length of the park without the walking track

= 400 − (4 + 4) m

= 400 − 8 m

= 392 m

The breadth of the park without the walking track

= 300 − (4 + 2) m

= 300 − 8 m

=292 m

Area of the park without the walking track:

= 392 × 292

= 114464 sq. m

Therefore the area left for children for playing other than the walking track is 114464 sq. m.

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The equation that also models this situation is D) t=35sin(pi/6(m+3))+55.

The given temperature function for a city, t = 35 cos(π/6(m+3)) + 55, is a periodic function with a period of 12. To obtain the sine equivalent of the given cosine function, we need to use the identity sin(x) = cos(π/2 - x)In this case,x = π/2 - π/6(m+3) = π/3 - π/6m, so that sin(x) = cos(π/2 - x) = cos(π/6m - π/6)                                                                                                                                   Hence, we get a new equation as;  t = 35 cos(π/6(m+3)) + 55= 35 sin(π/6m - π/6) + 55= 35 sin(π/6(m+2)) + 55= 35 sin(π/6(m+3-1)) + 55So, we can conclude that option D) t=35sin(pi/6(m+3))+55 also models the situation.

To obtain the sine equivalent of the given cosine function, we need to use the identity sin(x) = cos(π/2 - x). The sine equivalent of the temperature function t = 35 cos(π/6(m+3)) + 55 is t = 35 sin(π/6(m+3)) + 55. Therefore, option D) t=35sin(pi/6(m+3))+55 also models the situation.

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Answer:

Yes. When computing the sample standard deviation, divide by n −1. When computing the population  standard deviation, divide by N

Step-by-step explanation:

The algebraic expression for "2 diminished by 7" is represented as "2 - 7."

To translate "2 diminished by 7" into an algebraic expression, we can use the subtraction operation. The expression "2 - 7" represents the subtraction of 7 from 2. In algebraic notation, the "-" symbol indicates subtraction, and the expression can be read as "2 subtract 7" or "2 minus 7."

In more detail, when we subtract 7 from 2, we are essentially taking away 7 units from a starting value of 2. The result of this subtraction is negative because we are subtracting a larger number from a smaller one. Thus, the expression "2 - 7" evaluates to -5.

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Answer:

Graph.

y=−1/3x+3

y

=

−

1

3

x

−

1

Step-by-step explanation:

Answer:

\(\displaystyle \frac{x^2}{5}+\frac{y^2}{9}=1\)

Step-by-step explanation:

We want to find the locus of a point such that the sum of the distance from any point P on the locus to (0, 2) and (0, -2) is 6.

First, we will need the distance formula, given by:

\(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Let the point on the locus be P(x, y).

So, the distance from P to (0, 2) will be:

\(\begin{aligned} d_1&=\sqrt{(x-0)^2+(y-2)^2}\\\\ &=\sqrt{x^2+(y-2)^2}\end{aligned}\)

And, the distance from P to (0, -2) will be:

\(\displaystyle \begin{aligned} d_2&=\sqrt{(x-0)^2+(y-(-2))^2}\\\\ &=\sqrt{x^2+(y+2)^2}\end{aligned}\)

So sum of the two distances must be 6. Therefore:

\(d_1+d_2=6\)

Now, by substitution:

\((\sqrt{x^2+(y-2)^2})+(\sqrt{x^2+(y+2)^2})=6\)

Simplify. We can subtract the second term from the left:

\(\sqrt{x^2+(y-2)^2}=6-\sqrt{x^2+(y+2)^2}\)

Square both sides:

\((x^2+(y-2)^2)=36-12\sqrt{x^2+(y+2)^2}+(x^2+(y+2)^2)\)

We can cancel the x² terms and continue squaring:

\(y^2-4y+4=36-12\sqrt{x^2+(y+2)^2}+y^2+4y+4\)

We can cancel the y² and 4 from both sides. We can also subtract 4y from both sides. This leaves us with:

\(-8y=36-12\sqrt{x^2+(y+2)^2}\)

We can divide both sides by -4:

\(2y=-9+3\sqrt{x^2+(y+2)^2}\)

Adding 9 to both sides yields:

\(2y+9=3\sqrt{x^2+(y+2)^2}\)

And, we will square both sides one final time.

\(4y^2+36y+81=9(x^2+(y^2+4y+4))\)

Distribute:

\(4y^2+36y+81=9x^2+9y^2+36y+36\)

The 36y will cancel. So:

\(4y^2+81=9x^2+9y^2+36\)

Subtracting 4y² and 36 from both sides yields:

\(9x^2+5y^2=45\)

And dividing both sides by 45 produces:

\(\displaystyle \frac{x^2}{5}+\frac{y^2}{9}=1\)

Therefore, the equation for the locus of a point such that the sum of its distance to (0, 2) and (0, -2) is 6 is given by a vertical ellipse with a major axis length of 3 and a minor axis length of √5, centered on the origin.

The possible weights that correctly round to 41.34 kilograms will be:

C. 41.32 kilograms

D. 41.35 kilograms

E 41.263 kilograms

Expression simply refers to the mathematical statements which have at least two terms which are related by an operator and contain either numbers, variables, or both. Addition, subtraction, multiplication, and division are all possible mathematical operations.

Based on the options given, the closest numbers are 41.32 kilogram, 41.35 kilograms and 41.263 kilograms

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Answer:

1) scalene 2) Isosceles 3) Equilateral 4) Scalene

Step-by-step explanation:

1. no sides are the same length

2. two sides are the same length

3. all sides are the same length

4. no sides are the same length

Answer: Hello Luv........

1) scalene 2) Isosceles 3) Equilateral 4) Scalene

Step-by-step explanation: Sorry i copied other.

1. no sides are the same length.

2. two sides are the same length.

3. all sides are the same length.

4. no sides are the same length.

Mark me brainest please. Hope this helps. Anna ♥

Answer:

50

Step-by-step explanation:

180-80-50=50

Answer:

50°

Step-by-step explanation:

All triangles have interior angles that add up to 180°

50° + 80° + x = 180°

        130° + x = 180°

       -130°       - 130°

                   x = 50°

When a point is rotated 90 degrees clockwise, its coordinates change as follows:

New X-coordinate = Old Y-coordinate

New Y-coordinate = -Old X-coordinate

In this case, the original point is (-3,3). When we rotate it 90 degrees clockwise, the new coordinates become (3,-3).

The new point (3,-3) is located in Quadrant III, where the x-coordinate is positive and the y-coordinate is negative. Therefore, the correct answer is C. quadrant III.

The percentage of B5 produced from coconut oil is 0.045 X% of the imported diesel fuel. The percentage of E10 produced from molasses and cassava is 0.1143 Y% of the imported petrol.

To calculate the volume of B5 (a biodiesel blend of 5% biodiesel and 95% petroleum diesel) that can be produced from the coconut oil produced in Fiji, we need to know the total volume of coconut oil produced and the conversion efficiency of the trans-esterification process.

Let's assume that the volume of coconut oil produced in Fiji is X million litres, and the conversion efficiency is 90%. Therefore, the volume of biodiesel (CME) that can be produced from coconut oil is 0.9X million liters. Since B5 is a blend of 5% biodiesel, the volume of B5 that can be produced is 0.05 × 0.9X = 0.045X million liters.

To calculate the total volume of E10 (a gasoline blend of 10% ethanol and 90% petrol) that can be produced from the molasses and cassava, we need to know the total volume of molasses and cassava produced and the conversion efficiency of ethanol production.

Let's assume that the total volume of molasses and cassava produced is Y million liters, and the conversion efficiency is 80%. Therefore, the volume of ethanol that can be produced is 0.8Y million liters. Since E10 is a blend of 10% ethanol, the total volume of E10 that can be produced is 0.1 × 0.8Y = 0.08Y million liters.

The percentage of B5 produced from coconut oil is (0.045X / 100) × 100% = 0.045 X% of the imported diesel fuel.

The percentage of E10 produced from molasses and cassava is (0.08Y / 70) × 100% = 0.1143 Y% of the imported petrol.

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The complete question is:

A country imports in the vicinity of 100 million litres of diesel fuel (ADO) for use in diesel vehicles and 70 million litres of petrol fir petrol vehicles. It also produces molasses and cassava, which are feedstock for the production of ethanol, and coconut oil (CNO) that can be converted to biodiesel (CME) via trans-esterification.

a) Calculate the volume of B5 that can be produced from the coconut oil produced in Fiji, and the total volume of E10 that can be produced from all the molasses and cassava that the country produces annually. Express your results as the percentages of the respective imported fuel.

\(u_{2} = u_{1} + 8 \\ u_{3} = u_{2} + 4 \\ u_{4} = u_{3} + 2 \\ u_{5} = u_{4} + 1 \\ u_{6} = u_{5} + 0.5 \\ ....\)

\(u_{2} = u_{1} + 2 {}^{3} \\ u_{3} = u_{2} + 2 {}^{2} \\ u_{4} = u_{3} + 2 {}^{1} \\ u_{5} = u_{4} + 2 {}^{0} \\ u_{6} = u_{5} + 2 {}^{ - 1} \\ ....\)

\(u_{n + 1} = u_{n} + 2 {}^{4 - n} \)

\(\\ \tt\hookrightarrow \dfrac{44.8}{x+4}=\dfrac{56}{35}\)

\(\\ \tt\hookrightarrow \dfrac{44.8}{x+4}=1.6\)

\(\\ \tt\hookrightarrow x+4=\dfrac{44.8}{1.6}\)

\(\\ \tt\hookrightarrow x+4=28\)

\(\\ \tt\hookrightarrow x=24\)

The statement "Using the three standard deviation criterion, the last observation (x=43) would be considered an outlier" is true.

Given data:

7, 11, 12, 18, 20, 22, 43.

To find out whether the last observation is an outlier or not, let's use the three standard deviation criterion.

That is, if a data value is more than three standard deviations from the mean, then it is considered an outlier.

The formula to find standard deviation is:

S.D = \sqrt{\frac{\sum_{i=1}^{N}(x_i-\bar{x})^2}{N-1}}

Where, N = sample size,

             x = each value of the data set,

    \bar{x} = mean of the data set

To find the mean of the given data set, add all the numbers and divide the sum by the number of terms:

Mean = $\frac{7+11+12+18+20+22+43}{7}$

          = $\frac{133}{7}$

          = 19

Now, calculate the standard deviation:

$(7-19)^2 + (11-19)^2 + (12-19)^2 + (18-19)^2 + (20-19)^2 + (22-19)^2 + (43-19)^2$= 1442S.D

                                                                                                                               = $\sqrt{\frac{1442}{7-1}}$

                                                                                                                                ≈ 10.31

To determine whether the value of x = 43 is an outlier, we need to compare it with the mean and the standard deviation.

Therefore, compute the z-score for the last observation (x=43).Z-score = $\frac{x-\bar{x}}{S.D}$

                                                                                                                      = $\frac{43-19}{10.31}$

                                                                                                                      = 2.32

Since the absolute value of z-score > 3, the value of x = 43 is considered an outlier.

Therefore, the statement "Using the three standard deviation criterion, the last observation (x=43) would be considered an outlier" is true.

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The required quadratic function having a leading coefficient of 3 and a constant term of –12 is f(x) = 3x^2 + bx - 12.

The equation is the relationship between variables and represented as y = ax + b is an example of a polynomial equation.

Here,
A quadratic function can be written in the general form:

f(x) = ax² + bx + c

where a, b, and c are constants.

Given a leading coefficient of 3 and a constant term of -12, we can write the quadratic function as,

f(x) = 3x² + bx - 12

Therefore, a quadratic function having a leading coefficient of 3 and a constant term of –12 is f(x) = 3x^2 + bx - 12.

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Answer: ty

Step-by-step explanation:

Brainliest pls:)

Answer:

Not enough information

Step-by-step explanation:

You gave the height, but there is no length. You need both the height and length because the area of a triangle is 1/2bh

Answer:

b ≈ 29.7 units

Step-by-step explanation:

Because we don't know whether this is a right triangle, but have an angle sandwiched between two sides, we can use the law of cosines to find b.

The law of cosines is given by the following formula:

(1.) a^2 = b^2 + c^2 - 2bc * cos(A)

(2.) b^2 = a^2 + c^2 -2ac * cos(B)

(3.) c^2 = a^2 + b^2 - 2ab * cos(C)

Because angle B is sandwiched between a and c, we can use formula 2 by plugging in 45 for a, 23 for c, and 36 for B.

Step 1: Plug everything in and simplify:

b^2 = a^2 + c^2 -2ac * cos(B)

b^2 = 45^2 + 23^2 - 2(45)(23) * cos(36)

b^2 = 2025 + 529 - 2070 * cos(36)

b^2 = 2554 - 2070 * cos(36)

b^2 = 879.3348216

Step 2:  Take the square root of both sides to find b and then round to the nearest tenth:

√b^2 = ± √879.3348216

b = 29.65358025

b = 29.7

Although taking the square root of number gives you a positive and negative number since squaring both a positive and negative number give you a positive answer (e.g., 2 * 2 = 4 and -2 * -2 = 4), we can only use the positive answer since you can't have a negative measure.  Thus, b is approximately 29.7 units.

To determine the square footage of wallpaper required to cover the wall surrounding a Norman window, we need to calculate the areas of both the rectangular and semicircular sections of the wall.

1. Rectangular Section: Measure the length and height of the rectangular portion of the wall. Multiply these two measurements to calculate the area of the rectangle.

2. Semicircular Section: Measure the diameter of the semicircular portion of the wall. Divide the diameter by 2 to find the radius. Use the formula (π * r^2) / 2 to calculate the area of the semicircle.

3. Total Square Footage: Add the area of the rectangular section and the area of the semicircular section to obtain the total square footage of wallpaper required to cover the wall surrounding the Norman window.

Since the specific measurements of the window and wall are not provided, please measure the length, height, and diameter of the window to accurately determine the square footage of wallpaper required.

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