Calcium chloride forms an ionic solid. How are the particles held together
and arranged in the solid?

A. Calcium chloride molecules are held together by covalent bonds in
a regular pattern.

B. Calcium and chloride atoms are held together by metallic bonds in
an irregular way.

C. Calcium chloride molecules are held together by intermolecular
attractions in an irregular way.

D. Calcium and chloride atoms are held together by electrostatic
forces in a regular pattern.

Octane, C8H18, a component of gasoline, burns completely in the following manner: 16 CO2 (g) + 18 H2O → 2C8H18 (l) + 25 O2 (g).

A fuel and an oxidant, often atmospheric oxygen, engage in a high-temperature exothermic (heat-releasing) redox (oxygen-adding) chemical reaction during combustion that results in oxidized, frequently gaseous products in a mixture known as smoke.

Combustion reaction examples include: Consider a fireplace with wood burning within. The oxygen in the air and the fuel, which is wood, continuously react in a combustion reaction. While the smoke you see is carbon dioxide, the fire that is produced is energy being released in a protracted exothermic reaction.

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CCC Pattern compare the ions of elements listed in the table with the atoms of the element. Based on the patterns in their particle compositions and charges, the definition of ion would be that CCC pattern compare ions of elements.

An ion is a structure in crystal system having regular repeating arrangement, which can be called as an ionic lattice.

Lattice is formed because ions attract each other and form a regular pattern with oppositely charged ion next to each other.

An atom is the smallest unit of an element that retains the chemical properties of element. Every atom includes a nucleus, generally containing both positively charged particles called ions and uncharged particles called ion.

In the space surrounding, the nucleus are negatively charged particles called electron.

Therefore, ions are oppositely charged particles in lattice.

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Answer:

O sólido tem densidade mais alta em comparação ao líquido.

Explicação:

A densidade da amostra sólida é maior do que a densidade do líquido porque há pouco espaço entre as partículas do sólido. A densidade tem relação inversa com o volume de uma substância, se uma substância ocupa mais espaço então sua densidade é menor, enquanto se a substância ocupa menos espaço então tem maior densidade. As substâncias sólidas ocupam menos espaço em comparação com as substâncias líquidas, então podemos dizer que a densidade do sólido é maior do que as substâncias líquidas.

The acetic acid in the 21.88 g mass of vinegar that reacts with 40.1 mL of

sodium hydroxide, has a percentage (w/w) of approximately 35%.

Known and derived parameters;

Mass of vinegar added to the flask = 119.22 g - 97.34 g = 21.88 g

Mass of the of the tartaric acid in 250.0 mL of water = 5.023 grams

The reaction between tartaric acid and sodium hydroxide is presented as follows;

C₄H₆O₄ (aq) + 2NaOH(aq) \(\longrightarrow\) C₄H₄O₄Na₂ + 2H₂O

Therefore;

1 mole of tartaric acid reacts with 2 moles of sodium hydroxide.

Molar mass of tartaric acid = 150.087 g/mol

\(Number \ of \ moles \ of \ tartaric \ acid = \dfrac{5.023}{150.087} \times \dfrac{34.2}{250.0} \approx \mathbf{4.578 \times 10^{-3}}\)

Which gives;

Number of moles in 40.1 ml of the sodium hydroxide solution is therefore;

\(Moles \ of \ NaOH \approx \dfrac{40.1}{28.3} \times 2 \times 4.578 \times 10^{-3 } \approx \mathbf{0.13}\)

The reaction between acetic acid and NaOH is presented as follows;

CH₃COOH + NaOH \(\longrightarrow\) CH₃COONa + H₂O

Number of moles of acetic acid = Number of moles of NaOH

Which gives;

Number of moles of acetic acid in the vinegar = 0.13 moles

Molar mass of acetic acid = 60.052 g/mol

Mass of acetic acid = 60.052 g/mol × 0.13 moles = 7.80676 g

\(Percentage \ by \ weight = \dfrac{7.80676}{21.88} \times 100 \approx \mathbf{35.68\%}\)

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\(\\ \sf\longmapsto 5L\)

\(\\ \sf\longmapsto 5(1000)\)

\(\\ \sf\longmapsto 5000mL\)

Answer:

............................................................................................................................

Explanation:

because ........................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................

Option C, The electron transition from n = 5 to n = 1 in hydrogen atom requires the largest amount of energy as it is moving from a higher energy state to a lower energy state, thus overcoming the highest amount of electrostatic force of attraction to the nucleus.

In the hydrogen atom, the energy of an electron is related to its distance from the nucleus, which is characterized by the principal quantum number (n). As the distance of an electron from the nucleus increases, its energy decreases. Therefore, the electron transition that requires the largest amount of energy is when an electron jumps from the state with the lowest principal quantum number to the state with the highest principal quantum number.

From the options given, the transition that requires the largest amount of energy is c. From n = 5 to n = 1 because, in this case, the electron is transitioning from the state with the highest principal quantum number (n = 5) to the state with the lowest principal quantum number (n = 1). This transition requires the largest amount of energy because the electron must overcome the highest amount of electrostatic force of attraction to the nucleus.

It's important to notice that all the other options (a. from n=1 to n=2, b. from n=2 to n=3, d. from n=3 to n=5) are transitions that go to a lower n, meaning that the electron is getting closer to the nucleus and therefore lower energy state.

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The solubility of carbon dioxide in water at the given pressure would be 8.45 g CO2 in 100 mL of water.  

According to Henry's law:

C = kH x P

where:

To solve this problem, we need to use the Henry's law constant for carbon dioxide in water at 20 \(^oC\), which is 0.0349 mol/L/atm. Let's convert the given solubility from mass/volume units to molar concentration units as follows:

Now we can use Henry's law to calculate the solubility of carbon dioxide in water at 5.50 atm:

Concentration from mol/L to mass/volume units:

0.192 mol/L x 44.01 g/mol = 8.45 g CO2 / 100 mL

Therefore, the solubility of carbon dioxide in water at 5.50 atm pressure is approximately 8.45 g CO2 in 100 mL of water at 20 \(^oC\).

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Answer:

See explanation

Explanation:

A saturated solution is a solution that contains just as much solute as it can normally hold at that temperature.

If the temperature is cooled and  crystals of copper sulphate are formed in the solution, then the solution is no longer saturated because some solute are now leaving the solution.

b) percent by mass = mass of solute/mass of solution * 100

percent by mass = 20%

mass of solute = x g

mass of solution =  80 g​

20 = x/80 * 100

1600 = 100x

x = 1600/100

x = 16 g

Answer: 0.00098

Explanation:

1. Zeroes that appear before a nonzero significant figure are not significant.

  Ex: 0.002 (1 significant figures), 0.13 (2 significant figures)

2. Zeroes that appear between nonzero digits are significant

  Ex: 0.705 (3 significant figures), 2006 (4 significant figures)

3. Zeroes that appear after a nonzero digit are significant only if it is

A. Followed by a decimal point

  Ex: 40 (1 significant figure), 20. (2 significant figures)

or B. They appear to the right of a decimal point

  Ex: 37.0 (3 significant figures), 4.100 (4 significant figures)

It will take 21.57min for the concentration of A to reach

0.080 M if The kinetics of a gas phase reaction of the form A → Products results

The kinetic concept of gases is an easy, historically tremendous classical version of the thermodynamic conduct of gases, with which many major principles of thermodynamics had been installed. gasoline kinetics is technological know-how in the department of fluid dynamics, worried with the take a look at of motion of gases and their outcomes on physical systems. based on the principles of fluid mechanics and thermodynamics, gasoline dynamics arises from the studies of fuel flows in transonic and supersonic flights.

Unit of rate constants for

0 order reaction = M/s

1st order reaction = sec-1

2nd order reaction = M-1s-1

So, this reaction is a 0-order reaction because it's rate constant has a unit M/min

Now half-life of 0 order reaction = Ao/2K

Where Ao = initial concentration

              K = rate constant

using kinetics of a gas

Given,

Ao = 0.337M and K = 0.00781M/min

Putting all the values we get

t1/2 = 0.337/2×0.00781 min

On calculating

t1/2 =  21.57min

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Answer:

the atoms are rearranged

Explanation:

they are just in a diff order

The particle diagram represents a chemical change because the breaking of old chemical bonds and the formation of new chemical bonds occurs and a completely new substance is formed.

A chemical change is when a chemical substance is completely transformed into one or more different types of substances. Chemical changes occur through chemical reactions and result in substances with different and new chemical and physical properties.

Chemical changes are irreversible in nature and are also known as permanent changes. When chemical responses occur, the molecules are modified and joined by an energy change as new molecules are produced.

Examples of chemical changes: burning of coal, rusting of iron, digestion of food, adding vinegar to baking soda,  germination of seeds, ripening of fruits, cooking an egg, etc.

The given diagram is quite similar to the water formation reaction:

2H₂   + O₂  \(\longrightarrow\) 2H₂ O

In which the bond between the hydrogen atoms and oxygen atoms is broken and the formation of the O-H bond, therefore, is a chemical change.

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How many mL of a 0.10 M NaOH solution are needed to neutralize 15 mL of 0.20 M H3PO4?

  5.0 (328)

Ph. D. in organic chemistry with 6+ years of teaching experi..

Write down the balanced reaction first

3NaOH + H3PO4   makes    Na3PO4 + 3H2O

Given 0.10M NaOH (0.10mol/lit NaOH)

0.2M H3PO4 ( 0.2 mol/lit H3PO4)

15 ml of H3PO4 or 0.015 lit of H3PO4

Find volume of NaOH needed to neutralize the solution

Relate moles of H3PO4 with the moles of NaOH with the helps of coefficients in front of NaOH and H3PO4 seen in balanced equations.

               moles ↔ Litre use definition of molarity (moles/litrs)

Start with what is given for H3PO4

0.015 lit of H3PO4 x 0.2 moles of H3PO4 / lit of H3PO4 x 3 moles of NaOH/1 mole of H3PO4 x lit of NaOH/0.1 mol of NaOH = 0.09 lit or 90 ml.

The same colors in above equations cancel our leaving lit of NaOH as final answer.

By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers.

By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers. Energy storage's inherent ability to offer backup power in the event of grid failure is a feature that both residential consumers and commercial owners find highly desirable.

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Answer:

In an acid-base reaction, the base always receives the H+.

Explanation:

The current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.

To calculate the current in amperes, we need to use Faraday's laws of electrolysis and the stoichiometry of the reaction.

Faraday's laws state that the amount of substance produced or consumed during electrolysis is directly proportional to the quantity of electricity passed through the cell. The relationship is given by:

Q = nF

Where Q is the electric charge in coulombs (C), n is the number of moles of substance involved in the reaction, and F is Faraday's constant, which is equal to 96,485 C/mol.

In this case, the substance being produced is Cl2, and we know the mass of Cl2 produced, which is 4.8 x 10^5 g.

First, we need to calculate the number of moles of Cl2 produced:

Molar mass of Cl2 = 35.45 g/mol

Moles of Cl2 = mass / molar mass = (4.8 x 10^5 g) / (35.45 g/mol) ≈ 1.354 x 10^4 mol

Now we can calculate the quantity of electricity passed through the cell using Faraday's laws:

Q = nF

Q = (\(1.354 x 10^4\)mol) * (96,485 C/mol)

Q ≈ 1.308 x 10^9 C

The quantity of electricity is given in coulombs. To find the current, we need to divide this value by the time in seconds.

Given that the time is 18 hours, we convert it to seconds:

Time = 18 hours * 60 minutes/hour * 60 seconds/minute

Time = 6.48 x 10^4 seconds

Finally, we can calculate the current:

Current (I) = Q / Time

I = (1.308 x 10^9 C) / (6.48 x 10^4 s)

I ≈ 2.02 x 10^4 Amperes

Therefore, the current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.

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Answer:

I think this means that they always compatible so th er e basically friends and they stick together. c: hope I helped

Answer:

chemical bonds

Explanation:

The atoms in chemical compounds are held together by attractive electrostatic interactions known as chemical bonds. Ionic compounds contain positively and negatively charged ions in a ratio that results in an overall charge of zero. The ions are held together in a regular spatial arrangement by electrostatic forces.

The mass (in grams) of chlorine gas is needed to react with 251 grams of iron is 479 grams. Option C.

To determine the mass of chlorine gas needed to react with 251 grams of iron, we need to use the stoichiometry of the balanced chemical equation:

2Fe + 3Cl2 → 2FeCl3

From the balanced equation, we can see that 2 moles of iron (Fe) react with 3 moles of chlorine gas (Cl2) to produce 2 moles of iron(III) chloride (FeCl3).

To calculate the mass of chlorine gas, we can follow these steps:

Step 1: Convert the given mass of iron (Fe) to moles.

Using the molar mass of iron (Fe), which is approximately 55.85 g/mol, we can calculate the number of moles of iron:

moles of Fe = mass of Fe / molar mass of Fe

moles of Fe = 251 g / 55.85 g/mol

moles of Fe ≈ 4.5 mol (rounded to one decimal place)

Step 2: Use the mole ratio from the balanced equation to find the moles of chlorine gas (Cl2) needed.

From the balanced equation, we know that 2 moles of Fe react with 3 moles of Cl2. Therefore, the moles of Cl2 can be calculated as:

moles of Cl2 = (moles of Fe / 2) * 3

moles of Cl2 = (4.5 mol / 2) * 3

moles of Cl2 ≈ 6.75 mol (rounded to two decimal places)

Step 3: Convert the moles of chlorine gas to grams.

Using the molar mass of chlorine gas (Cl2), which is approximately 70.90 g/mol, we can calculate the mass of chlorine gas:

mass of Cl2 = moles of Cl2 * molar mass of Cl2

mass of Cl2 = 6.75 mol * 70.90 g/mol

mass of Cl2 ≈ 479 grams (rounded to the nearest whole number) Option C is correct.

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The reaction is endothermic since the energy level of the products have are higher than that of the reactants.

The activation energy (AE) is the energy difference between the reactants and the transition state.

The change in energy E and the energy difference between the reactants and the products

The data given is as follows:

Reactants: 0 kJ/mol

AE forward 125 kJ/mol

AE reverse: 86 kJ/mol

Products: 39 kJ/mol

The values of ΔE forward and ΔE reverse are as follows:

ΔE forward = (39 - 0) kJ/mol

ΔE forward = +39 kJ/mol

ΔE reverse = (0 - 39) kJ/mol

ΔE reverse =  -39 kJ/mol

3. Given that Ea = 154 kJ/mol and ΔE = 136 kJ/mol

AE reverse = ΔE - AE forward

E = 136 kJ/mol - 154 kJ/mol

E = -18 kJ/mol

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The list which includes only bulk properties of matter is boiling point, surface tension and vapor pressure.

Definition of matter

Something that has mass and occupies space is defined as a matter.

Hence, all the physical objects or substances that are found on the planet Earth are typically composed of matter.

Matter are classified into three (3) states:

Gas

Solid

Liquid

The property of the matter that affects matter as a whole is known as bulk property of matter and they are listed as follows:

Hence, boiling point, vapor pressure and surface tension are considered as a bulk properties of matter.

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The correct option is B. dynamic logic , The following factors are crucial for assessing and contrasting logic families: The supplied power necessary to run the specified logic function is referred to as power dissipation.

The power delivered from another gate is not included in this parameter. Some of these logic families employ static methods to reduce the complexity of the design. Clocked dynamic approaches are used by other logic families, such domino logic, to reduce size, power usage, and delay. Various solid-state and vacuum tube logic systems were employed for logic circuitry activities prior to the widespread introduction of integrated circuits.

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Answer: Molecular mass of \(CH_3COONa\) is 82 g

Explanation:

Molecular mass (M) is defined as the mass in grams of 1 mole of a substance.

S.I Unit of Molar mass is gram per mole and it is represented as g/mol.

Atomic Mass of Carbon (C) = 12 g

Atomic Mass of hydrogen (H) = 1 g

Atomic Mass of oxygen (O) = 16 g

Atomic Mass of sodium (Na) = 23 g

Molecular mass of \(CH_3COONa\) = 12(1)+1(3)+12(1)+16(2)+23(1) = 82 g

The units which are used to represent the volume are mL, L, cm³, m³, etc. The volume of air in liters that you might inhale (and exhale) in 24.0 hours is 10,684.8 L.

The measure of the capacity that an object holds is generally defined as the volume. For example if a beaker can hold 100 mL of water, then its volume is said to be 100mL.

Here in minute, volume is:

15 × 0.495 = 7.42 L

In an hour, volume is:

7.42 × 60 = 445.2

In 24 hours, the volume will be:

Volume = 445.2 × 24 = 10,684.8 L

Thus the volume of air in 24 hours is 10,684.8 L.

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Answer:

The volume of Component 1 is 36 cubic inches.

Explanation:

To calculate the volume of a composite solid, we need to determine the individual volumes of the different components and then add them together.

In this case, the composite solid consists of multiple components with the following dimensions:

Component 1:

Length: 4 inches

Width: 3 inches

Height: 3 inches

To find the volume of Component 1, we multiply the length, width, and height together:

Volume of Component 1 = Length x Width x Height = 4 in x 3 in x 3 in = 36 cubic inches

Therefore, the volume of Component 1 is 36 cubic inches.

Please provide the dimensions of the remaining components of the composite solid, and I will calculate the total volume by summing up the individual volumes.

Answer:

The moon is not pulling the tide as hard

Explanation:

I suppose, I know it dills with the moon though

Explanation:

Normalmente, las olas se forman por el viento aunque su historia comienza muy lejos, en el Sol. ... Cuando el viento sopla sobre el mar, las partículas de aire rozan a las partículas de agua y se empiezan a formar pequeñas olas de pocos milímetros de longitud, llamadas ondas capilares.

Normally, waves are formed by the wind, although their history begins very far away, in the Sun. ... When the wind blows over the sea, the air particles brush against the water particles and small waves of few millimeters in length, called capillary waves.

Answer:

physical and chemical.

The normal boiling point of the unknown liquid is 57.4°C.

The normal boiling point occurs when the vapor pressure of the liquid is equal to the atmospheric pressure. At normal boiling point, the temperature of the liquid is called the boiling point.

Using the Clausius-Clapeyron equation:

ln(P₂/P₁) = -(ΔHvap/R) * (1/T₂ - 1/T₁)

where P₁ is the vapor pressure at the given temperature T₁, P₂ is the vapor pressure at the boiling point temperature T₂, ΔHvap is the heat of vaporization, R is the gas constant.

At -170°C, the vapor pressure of the liquid is given as P₁ = 117 torr. At normal boiling point, the vapor pressure of the liquid is P₂ = 760 torr.

Converting all units to SI units, we have:

P₁ = 15.47 Pa

P₂ = 101325 Pa

ΔHvap = 5480 J/mol

R = 8.314 J/(mol*K)

Plugging in the values, we get:

㏑(101325/15.47) = -(5480/8.314) * (1/T₂ - 1/103.15)

Solving for T₂, the boiling point is found to be:

T₂ = 57.4°C

As a result, the unknown liquid's usual boiling point is 57.4°C.

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The amount of volume of KOH solution that should be added to make 500mL of a 0.300M solution is 200mL.

The volume of a solution given the concentration can be calculated using the following expression;

CaVa = CbVb

Where;

According to this question, we are to calculate how many mL of a 0.75 M OH solution that should be added to a 500 mL flask to make 500 mL of a 0.300 M KOH solution.

0.75 × Va = 500 × 0.3

0.75Va = 150

Va = 150/0.75

Va = 200mL

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