By what percentage does the lift increase in a steady level turn at 45° angle of bank, compared tostraight and level flight?A) 52%B) 41%C) 31%D) 19%

This question is incomplete, the complete question is;

A pool of contaminated water is lined with a 40 cm thick containment barrier. The contaminant in the pit has a concentration of 1.5 mol/L, while the groundwater circulating around the pit flows fast enough that the contaminate concentration remains 0. There is initially no contaminant in the barrier material at the time of installation. The governing second order, partial differential equation for diffusion of the contaminant through the barrier is:

dC/dt = D( d²C / dz²)

where c(z,t) represent the concentration of containment of any depth into the barrier at anytime and D is the diffusion coefficient (a constant) for the containment in the barrier material.

a) write all boundary and initial conditions needed to solve this equation for C(z, t)

b) Find the steady  state solution (infinite time) for C(z)

Answer:

a) At t = 0, z= 0, c = 1.5 mol/L

at t =0, z = 0.4m, c = 0 mol/L

b) C(z) = z² - 4.15z + 1.5

Explanation:

a)

The boundary and initial conditions are as follows

At t = 0, z= 0, c = 1.5 mol/L

at t =0, z = 0.4m, c = 0 mol/L

b)

The governing second order, partial differential equation for diffusion of the contaminant through the barrier is :

(dC/dt) = D*(d²C/dz²) ..............equ(1)

For steady state, above equation becomes,

(d²C/dz²) =0

Integrating above equation,

(dC/dz) = Z + C1  { where C1 is integration constant) }

again integrating above equation,

C = z² + C1*z + C2    ...................equ(2)

applying boundary condition : at t =0, z= 0, c = 1.5 mol/L, to above equation

 C = z² + C1*z + C2

1.5 = 0 + 0*0 + c2

C2 = 1.5

applying boundary condition : at t =0, z= 0.4m, c = 0 mol/L, to equation (2) ,

0 = 0.4² + C1*0.4 +  1.5

0 = 0.16 + 0.4C1 + 1.5

0.4C1 = - 1.66

C1 = -1.66/0.4

C1 = -4.15

So, the steady state solution for C(z) is:

C(z) = z² - 4.15z + 1.5

The maximum positive moment at c is 135k/ft

the maximum positive vertical reaction at b is 27k

Part a

Maximum positive moment at c

For maximum positive moment at C and as per Muller's principle, ILD influence line will be on moment at с, this is calculated using the equation below:

Maximum positive moment at c = \((\frac{1}{2} *20*5*(0.4+0.5) )+(5*8)\)

                                                    = 135k.ft

Part b

Maximum positive vertical reaction at b

To find this using Muller's principle, we keep dead load throughout the span and consequently keep point load at B

Maximum positive vertical reaction at b = \((\frac{1}{2} *20*1*(0.4+1.5))+(1*8)\)

                                                                 = 27k

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Allowing contaminants to be drawn into a refrigerant identifier or air-conditioning machine can ruin it.

When contaminants, such as dirt, debris, or foreign substances, are allowed to enter a refrigerant identifier or air-conditioning machine, they can cause damage to the sensitive components and impair the proper functioning of the system. These contaminants can clog filters, block passages, interfere with sensors, or cause mechanical wear and tear, leading to decreased performance, reduced efficiency, and potential breakdown of the equipment.

To prevent such damage, it is crucial to ensure that the system remains free from contaminants by using appropriate filters and regularly maintaining and cleaning the equipment.

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Answer:

apple

Explanation:

is the answer toWhat is your favorite Electronic company? (E.g. Windows, Apple, Samsung...)

The angular velocity of gear B and C is 100 rpm and the accelerations of the points on gears B and C which are in contact is 1974 in / s² and 658 in / s².

Angular velocity is defined as the speed at which two bodies move apart angularly or at which an item spins or rotates about an axis. The rotational axis is parallel to the direction of the angular velocity.

Let E is the contact point between gear B and C

vD = f EB ωB = 2 x 10λ = 20λ in / s²

ωC = vE = f EC = 20λ / 6

= 3.333 λ rad / s 60 / 2λ = 100 rpm

Acceleration at point E

On gear B

aB = v²E / r EB

= (20λ)² / 2 = 1973 in / s²

On gear C

aC = v²E / r EC

=  (20λ)² / 6 = 658 in / s²

Thus, the angular velocity of gear B and C is 100 rpm and the accelerations of the points on gears B and C which are in contact is 1974 in / s² and 658 in / s².

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Answer:

The answer is below

Explanation:

\(\theta_1=cos^{-1}0.28=73.74^o\ lagging\\\\S_1=125\angle 73.74^o=35\ kW+j120\ kVAR\\\\S_2=10\ kW-j40\ kVAR\\\\S_3=15\ kW\)

Total power = P = 35 kW + 10 kW + 15 kW = 60 kW

Total kVAR = 120 kVAR - 40 kVAR = 80 kVAR

\(Total\ apparent \ power =S= S_1+S_2+S_3=(35+j120)+(10-j40)+(15)\\\\S=60\ kW+j80\ kVAR=100\angle 53.13^o\\\\Current(I)=\frac{S^*}{V^*} \frac{100000\angle -53.13^o}{1400\angle0}=71.43\angle-53.13^o\\ \\Power\ factor (PF)=cos(53.13)=0.6\ lagging\\\\The \ new\ power\ factor\ is\ to \ be\ 0.8[cos^{-1}0.8=36.87^o], hence\ since\ the\ total\ \\real\ power(P)= 60\ kW, the\ capacitor\ kVAR(Q_c)\ is:\\\\Q_c=60tan(53.13)-60tan(36.87)=80-45=35\ kVAR\\\\\)

\(C=\frac{Q_c}{wV^2} =\frac{35000\ VAR}{2\pi*60\ Hz*1400\ V}=47.38\ \mu f\)

New current (I') = \(\frac{S'^*}{V^*}=\frac{60000-j45000}{1400}=53.57\angle-36.87^o\)

Current reduce from 71.43 A to 53.57 A

The dynamic viscosity of the oil in poise is 13.625 pois

The kinematic viscosity of the oil in strokes is 14.34

F viscous is given as n*  ΔFr / Δy

where n = F * Δy / A * ΔVn

We have to define the terms of the formula

Δy = 12.5 x 10⁻³

ΔVr = 2.5m /s

A = 60 x 60 cm² = 0.36m

F = 98.1 n

We have to put the values in the formula

98.1 n *  12.5 x 10⁻³ /  0.36m * 2.5m /s

n = 1.3625  ns / m²

The kinematic viscosity of the oil in strokes if the specific gravity of the oil is 0.95

y = n / e

n =  1.3625  

e = 0.95 x 10³

y = 1.3625  / 0.95 x 10³

= 1.434 x 10⁻³

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The oven produces 800 J of thermal energy, which is valuable energy that may be used for cooking.

One of the most transportable large-capacity air fryers we recommend, the Gourmia GAF686 Digital, excelled in CR's air fryer tests. Despite having a 4.3-quart measured capacity, its overall dimensions are comparable to those of variations with smaller capacities. For instance, depending on what your air frying is, a 2-4.5l capacity air fryer is appropriate for 1-2 people and a 4.5-10l capacity is ideal for 2-4 people. To determine how much space you'll need, consider the number of people you'll be feeding. A larger capacity allows you to prepare several meals at once. A proportion that equals one-tenth of a quantity. One tenth of something is equivalent to one percent, represented by the symbol 1%; hence, 100 percent signifies the complete thing, and 200 percent designates twice the amount given.

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Answer:

1.) 103.23 degree centigrade

2.) 126.96 degree centigrade

Explanation:

Given that a transparent film is to be bonded onto the top surface of a solid plate inside a heated chamber. For the bond to cure properly, a temperature of 70°C is to be maintained at the bond, between the film and the solid plate. The transparent film has a thickness of 1 mm and thermal conductivity of 0.05 W/m·K, while the solid plate is 13 mm thick and has a thermal conductivity of 1.2 W/m·K. Inside the heated chamber, the convection heat transfer coefficient is 70 W/m2·K. If the bottom surface of the solid plate is maintained at 52°C.

To determine the temperature inside the heated Chamber, let us first calculate the heat transfer rate per unit area through the plate by using the formula

Heat transfer rate R = k( Tb - T2)/L

Where

k = 1.2 W/mA.K

Tb = 70 degree

T2 = 52 degree

L = 13mm = 13/1000 = 0.013m

substitute all the parameters into the formula above.

R = 1.2 x ( 70 - 52 )/ 0.013

R = 1.2 x (18/0.013)

R = 1661. 5 W/m^2

the surface temperature of the transparent film will be

Ts = Tb + (RLf/Kf)

Ts = 70 + (1661.5 x 0.001)/0.05

Ts = 70 + (1.6615)/0.05

Ts = 70 + 33.23

Ts = 103.23 degree centigrade

the temperature inside the heated Chamber will be calculated by using the formula

Ti = Ts + (R/h)

Ti = 103.23 + (1661.5/70)

Ti = 103.23 + 23.74

Ti = 126.97 degree centigrade

Electrotechnology is important to aerospace engineering for what key reason is option B. Spacecrafts need advanced electrical systems.

Electrotechnology plays a critical role in aerospace engineering because spacecrafts need advanced electrical systems to function.

These systems are responsible for powering and controlling various subsystems on the spacecraft, such as the propulsion system, the communication system, and the environmental control system.

Therefore, Electrotechnology is used to design and build these systems, as well as to troubleshoot and maintain them. It involves the use of electricity, electronics, and electromechanical systems to control and manipulate the flow of electrical energy.

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The time to achieve a grain diameter of 5.5 × 10⁻² mm is 477 minutes

A straight line passes through the middle of a rounded object or shape and emerges at the opposing edge.

We have to calculate the K

Given that the grain diameter exponent (n) = 2.2

Grain diameter (d) = 5.6 × 10⁻² mm = 5.6 × 10⁻⁵ m

d₀ =  2.4 × 10⁻² mm =  5.6 × 10⁻⁵ m

t = 500 min

\(K = \dfrac{d^n - d^n\circ}{t} \\\\K = \dfrac{(5.6 \times 10^-^5)^{2.2} - (2.4 \times 10^-^5)^2}{500} \\\\K = 7.48\times 10^{-13} m/min\)

From K we can determine the time required based on the desired diameter grain diameter (d) = 5.5 × 10⁻² mm = 5.5 × 10⁻⁵ m

\(K = \dfrac{(5.6 \times 10^-^5)^{2.2} - (2.4 \times 10^-^5)^2}{7.8 \times 10^{-13}} \\\\K = 477 min.\)

Therefore, the time is 477 minutes.

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Anemometer

Explanation:

An anemometer is a device used for measuring wind speed and direction. It is also a common weather station instrument. The term is derived from the Greek word anemos, which means wind, and is used to describe any wind speed instrument used in meteorology.

Answer:fall arrest harness

Explanation:cuz it’s just right

Answer:

Explanation:

7. False

8. True

9. True

10.True

11. True

Answer:

\(0.015\ \text{W}\)

Explanation:

\(T_{set}\) = Set temperature = \(70^{\circ}\text{C}\)

\(T_\infty\) = Air temperature = \(50^{\circ}\text{C}\)

A = Surface area = \(30\ \text{mm}^2=30\times 10^{-6}\ \text{m}^2\)

h = Convection heat transfer coefficient = \(25\ \text{W/m}^2\text{K}\)

Heater power is given by

\(P_e=hA(T_{set}-T_\infty)\\\Rightarrow P_e=25\times 30\times 10^{-6}(70-50)\\\Rightarrow P_e=0.015\ \text{W}\)

The required heater power is \(0.015\ \text{W}\)

The flow divider in a turbine engine duplex fuel nozzle serves the purpose of ensuring that the flow of fuel is evenly distributed between the two fuel nozzles in the duplex configuration.

The flow divider is essentially a small valve that regulates the fuel flow, so that an equal amount of fuel is delivered to each nozzle. This helps to maintain a consistent and balanced combustion process in the turbine engine. In a long answer, the flow divider also plays a critical role in preventing engine flameouts, which can occur if one fuel nozzle receives too much fuel while the other receives too little.

The purpose of a flow divider in a turbine engine duplex fuel nozzle is to regulate and distribute the fuel flow between primary and secondary circuits. This ensures proper atomization and mixing of fuel with air, leading to efficient combustion and overall engine performance.

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The use of salt on snowy and icy roads could have a negative effect on Montgomery County's Water Supply. The salt used on the roads for melting ice can cause a number of issues for water supplies and ecosystems, and Montgomery County is no exception.

When salt is used to melt snow and ice on the road, it can dissolve into the water and run off into streams, rivers, and lakes. The salt lowers the freezing point of water and melts ice, but it also alters the chemical makeup of the water, making it more saline. It can also damage aquatic plants, animals, and fish that rely on freshwater systems.

Therefore, it is important to take steps to minimize the use of salt or to use alternatives, such as sand or beet juice, which are less harmful to the environment and water supplies.

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Answer:

1. observational

2. clinical trial

*3. meta analysis*

Explanation:

Hopefully this is correct but if its not I apoligize

This scenario can be described as an experimental study. An experiment involves manipulating variables to observe the effects on an outcome.

In this case, the highway department manipulates the type of concrete used (Type A and Type B) and observes the time taken for cracks to appear in each section. The explanation for this conclusion is that by actively controlling the type of concrete used, the department can compare the performance and durability of both types, allowing them to make informed decisions about which concrete is more suitable for future use. In an observational study, no variables would be intentionally manipulated; rather, the researcher would simply observe and gather data without any intervention.

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Answer:

OBJECTLINE

HIDDEN LINE

SECTION LINE

CENTER LINE

Explanation:

Platinum filament.

Thomas Edison went through a series of different experiments while developing bulb until and unless the electricity passed through the Platinum filament, and it finally worked.

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Answer:

Connect your computer to the OBD(On-Board Diagnostics) port and see whats wrong

Explanation:

im a mekanic

mechanik

mecanic

meckanic

nvm, I fix cars

To ensure that the circuit's current is as minimal as feasible, set the rheostat to its maximum setting.

Both the voltmeter and ammeter readings should be noted (V).Rheostat settings can be changed to increase the circuit's current flow. Take note of I and V's values.

Take five sets of I and V readings by repeating the procedure.

V and I should be plotted on a graph. Make a line of best fit.

The resistor's resistance is indicated by the graph's gradient.

Describe Ohm's law in detail.

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The maximum possible coefficient of performance of this air conditioner is 2.5.

The maximum possible coefficient of performance of an air conditioner is determined by the following equation:

\(COP = (h_e - h_f) / w\)

where:

COP = coefficient of performance

h_e = enthalpy of the refrigerant at the evaporator

h_f = enthalpy of the refrigerant at the condenser

w = work done by the compressor

The enthalpy of the refrigerant at the evaporator and the condenser can be determined from the refrigerant tables. The work done by the compressor can be determined from the compressor efficiency.

The maximum possible coefficient of performance of an air conditioner is therefore determined by the refrigerant properties and the compressor efficiency.

In this case, the refrigerant is R-134a and the compressor efficiency is 80%. The refrigerant tables show that the enthalpy of R-134a at 0.700 MPa and 273 K is 247.1 kJ/kg and the enthalpy of R-134a at 1.60 MPa and 313 K is 415.7 kJ/kg.

Substituting these values into the equation for COP:

COP = (247.1 kJ/kg - 415.7 kJ/kg) / (0.8 × 100 kW) = 2.5

Therefore, the maximum possible coefficient of performance of this air conditioner is 2.5.

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Answer:

Most cylinder wear occurs at the top of ring travel.