Bromophenyl blue is an indicator which is yellow in acid solution and blue in alkali solution.Which will turn the indicator blue?ammonia solutioncopper oxide in waterchlorine watercarbon dioxide and water

Step 1 - Understanding the law of mass conservation

In physics, chemistry and biology the law of mass conservation states that no atom is created or destroyed, they are only rearranged in any given physical/chemical/biological process.

Therefore, if all atoms are preserved, the total mass of reactants and products is the same.

Step 2 - Answering the exercise

The melting of an ice cube is a physical process and, as such, is also subjected to the law of mass conservation. Therefore, if 10g of ice melt, 10g of water are produced.

Answer: 10.0g

Answer:

A hydrogen bond is the electromagnetic attraction created between a partially positively charged hydrogen atom attached to a highly electronegative atom and another nearby electronegative atom. A hydrogen bond is a type of dipole-dipole interaction; it is not a true chemical bond.

Explanation:

Answer:

Proton I believe

Explanation:

The product of molar concentration of ion present in chemical reactants raised to the power of number of ions produced per chemical compound in a saturated solution is called: solubility product.

Solubility product can be defined as a product of the molar concentration of ion present in two or more chemical reactants raised to the power of number of ions produced per chemical compound in a saturated solution.

Mathematically, the solubility product is given by this formula:

\(K_{sp} = [A^+]^x[B^{-}]^y\)

Where:

In Chemistry, the solubility product is typically used as an equilibrium constant for the dissolution of a chemical compound in a saturated solution.

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After an experiment, leftover reagents and products should be handled and disposed of properly to ensure safety and environmental responsibility.

Here are guidelines on what to do with leftover reagents and products:

It is important to prioritize safety and environmental considerations when handling and disposing of leftover reagents and products. Follow the guidelines provided by your institution, regulatory agencies, and local waste management authorities to ensure proper handling and disposal practices.

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After an experiment, leftover reagents and products should be handled and disposed of properly to ensure safety and environmental responsibility.

Here are guidelines on what to do with leftover reagents and products:

Leftover Reagents

If the reagent is still usable and stable, you may consider storing it appropriately for future use. Make sure to label the container clearly with the reagent's identity, concentration, and date.

If the reagent is no longer needed or has expired, check if it can be safely disposed of down the sink or in regular waste according to local regulations and guidelines. Some reagents may require special disposal procedures due to their hazardous nature.

If the reagent is hazardous or poses a risk to human health or the environment, it should be handled as hazardous waste. Contact your institution or a local waste management facility for guidance on proper disposal methods for hazardous waste.

Products of an Experiment:

If the products are desired and have value, they can be collected, purified, and stored for further use or analysis.

If the products are not needed or have no further use, check if they can be safely disposed of down the sink or in regular waste following local regulations.

If the products are hazardous, toxic, or potentially harmful, they should be treated as hazardous waste. Contact your institution or a local waste management facility for guidance on proper disposal methods for hazardous waste.

It is important to prioritize safety and environmental considerations when handling and disposing of leftover reagents and products. Follow the guidelines provided by your institution, regulatory agencies, and local waste management authorities to ensure proper handling and disposal practices.

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Answer: I am thankful for daytime since it can help us see, go outside for a walk, meet people clearly, do outdoor activities, and all the other things we do during day time.

NIGHT: I am thankful that there is night because we can have a proper sleep, and a slight cooling breeze. It can help us sleep more which is important because sleep can help us learn and focus. It gives us energy to start the day for tomorrow.

Explanation:

Answer:

See below

Explanation:

ΔQ = m c T        ΔQ = heat required(J)    m = mass (g)    T = C° temp change

                             c = heat capacity in J/g-C

A chemical reaction's theoretical yield is the amount of product obtained from the direct conversion of limiting reactant. The amount of HCl produced has a theoretical yield of 56.06 grammes of HCl.

Determine what portion of the product should be created using stoichiometry before you can compute the percent yield. The product quantity that may be produced at optimum efficiency with the specified reactant amounts is known as the theoretical yield.

By placing income in the numerator or cost (or market value) in the denominator of the percent yield equation, one can determine the yearly income return on an investment. Equation for percentage yield: Dividend payout Ratio / Share Price multiplied by 100. Coupon / Bond Price multiplied by 100.

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The Ksp for the equilibrium reaction HgBr₂(s) ⇄ Hg²⁺(aq) + 2Br⁻(aq) if HgBr₂ has a molar solubility of 2.50x10⁻⁷ M is 6.25x10⁻²⁰.

The given reaction is:

HgBr₂(s) ⇄ Hg²⁺(aq) + 2Br⁻(aq)   (1)

The equilibrium constant (Ksp) for the above reaction is given by:

\(Ksp = [Hg^{2+}][Br^{-}]^{2}\)   (2)  

At the equilibrium, we have (eq 1):

HgBr₂(s) ⇄ Hg²⁺(aq) + 2Br⁻(aq)  

                    s                2s  

Where:

s: is the molar solubility = 2.50x10⁻⁷ M  

By entering the values of molar solubility into equation (2) we can find the value of Ksp

\(Ksp = [Hg^{2+}][Br^{-}]^{2} = s(2s)^{2} = 4s^{3} = 4(2.50\cdot 10^{-7})^{3} = 6.25\cdot 10^{-20}\)

Therefore, the Ksp is 6.25x10⁻²⁰.

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I hope it helps you!  

The number of moles of oxygen consumed in the combustion of 20g of isoctane is 4.375 moles.

a) The equation for the complete combustion of isoctane is:
\(C_8H_{18} + 25O_2 --> 8CO_2 + 9H_2O\)
b) To calculate the number of moles of oxygen consumed, we first need to find the number of moles of isoctane used.
The molar mass of isoctane (\(C_8H_{18}\)) can be calculated as:
(8 x 12.01 g/mol) + (18 x 1.01 g/mol) = 114.16 g/mol
So, 20g of isoctane is equal to:
20 g ÷ 114.16 g/mol = 0.175 moles
According to the balanced chemical equation, 25 moles of oxygen are required to completely combust 1 mole of isoctane. Therefore, for 0.175 moles of isoctane, the amount of oxygen consumed can be calculated as:
0.175 moles x 25 moles of \(O_2\)/1 mole of isoctane = 4.375 moles of \(O_2\)

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To calculate the number of moles of oxygen consumed, we need to use the balanced equation to determine the mole ratio between isoctane and oxygen.

a) The equation for the complete combustion of isoctane is:

C8H18 + 12.5O2 → 8CO2 + 9H2O

b)  From the equation above, we can see that 1 mole of isooctane reacts with 12.5 moles of oxygen.
First, we need to calculate the number of moles of isoctane in 20g:
Number of moles of isoctane = mass / molar mass
Number of moles of isoctane = 20g / 114.23 g/mol
Number of moles of isoctane = 0.175 moles
Using the mole ratio, we can then calculate the number of moles of oxygen consumed:
Number of moles of oxygen consumed = number of moles of isoctane × mole ratio of oxygen to isoctane
Number of moles of oxygen consumed = 0.175 moles × 12.5
Number of moles of oxygen consumed = 2.1875 moles
Therefore, 2.1875 moles of oxygen are consumed during the combustion of 20g of isoctane.

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The best reagents to convert 1-hexyne into (e)-1,2-dibromo-1-hexene are 1 equiv. Br2 in CCl4, followed by NaOH to convert the mixture of (Z)- and (E)-isomers to the desired (E)-isomer.

This reaction is called the Vicinal Dibromination reaction. Option A: xs Br2 in CCl4 is a good choice of reagents, but it will give a mixture of (Z)- and (E)-isomers. Option B: 1 equiv. HBr will result in the formation of (Z)-1-bromo-1-hexene. Option C: ROOR is a radical initiator and will not result in the desired product.

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Activation polarization is occuring due to the evolution or deposition of some gases taking place in a redox reaction. Concentration polarization occurs between two electrodes when uneven distribution of ions occurs in the boundary.

Polarization is the process of charge separation between two species or the potential difference occurred due to the concentration gradient.

The two types of polarization occuring are activation polarization and concentration polarization. In activation polarization there occurs difference by the accumulation of gases.

For example the evolution of gases from the hydrogen electrode immersed in an electrolyte causes a polarization between the two electrodes.

In concentration polarization, there will be a concentration gradient of ions in the boundary of two electrodes occured due the electroanalytical reaction.

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Answer:

That is def true

Explanation:

Answer:

please mark brainliest!

Explanation:

The element Nickel (Ni) is one of the few ferromagnetic metals. Ferromagnetic means they are attracted to magnets and can be magnetized themselves. Most metals aren't magnetic with the exception of iron, nickel, cobalt, gadolinium, neodymium and samarium.

Answer: ummmmmm

Explanation:

Answer: EXAMPLEEE

Explanation: Brookite

Mohs scale hardness 51⁄2 to 6

Luster Submetallic

Streak White, greyish or yellowish

Diaphaneity Opaque to translucent

Answer:

NUCLEAR ENERGY -----> MECHANICAL ENERGY -------> THERMAL ENERGY --------> ELECTRICAL ENERGY

Explanation:

In nuclear reactor, various energy transformations occur in order to generate electricity. Nuclear reactor converts the energy released from nuclear fission and the heat generated is removed from the reactor by a cooling system where steam is generated. The steam then drives a turbine which powers a generator to produce electricity.

A nuclear reactor is hence an equipment where nuclear chain reactions occur and control can be obtained. The nuclear reactor uses mostly uranium-235 and Plutonium-239. When these radioactive substances absorbs neutrons, they undergo nuclear fission causing the nucleus to split into two or more smaller compounds with  the release of kinetic energy a form of mechanical energy, gamma radiations and others.The kinetic energy is then harnessed in the equipment as heat (thermal energy) which is received by a cooling system and steam is generated. The steam can then power the generator from which electricity is obtained (electrical energy).

So therefore, in a nuclear reactor, the nuclear energy is transformed to mechanical energy and then thermal energy which powers the generation of the electrical energy.

Answer:

nuclear energy Right arrow. mechanical energy Right arrow. thermal energy Right arrow. electrical energy or (A)

Explanation:

Alkenes are a group of unsaturated hydrocarbons (i.e., molecules with solely carbon and hydrogen) that include at least one double bond from carbon to carbon. Olefins is a different name for alkenes. Due to the double bond, alkenes are more reactive than alkanes.

What is Hydrocarbon?

A hydrocarbon is an organic compound made entirely of the two atom kinds of carbon and hydrogen. Hydrocarbons are typically colourless gases with barely perceptible odours. The four subcategories that are generally used to classify hydrocarbons are alkanes, alkenes, alkynes, and aromatic hydrocarbons. These chemicals' structures could be quite simple or extremely intricate. The study of hydrocarbons can provide insight into the chemistry and behavior of other functional groups. For commercial purposes, liquefied petroleum gas, which is produced from hydrocarbons like propane and butane, is also used as a fuel source (LPG). Benzene, one of the most fundamental aromatic hydrocarbons, serves as the building block for many synthetic drugs.

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Complete question

Name The Alkenes Below. Name The Alkenes Below. A) Ball& Sticklabels B) Ball & Stick ▼

Answer:

nitrogen and oxygen.   air we breathe is made up mostly of nitrogen molecules. Nitrogen atoms really like to stick to each other, which is why it’s hard to get nitrogen to react with

Explanation:

please tell me if I'm right ;)

Answer: chill google dat junk sis lol but i thought i could help i just dont wanna get u da wrong answer su

Explanation:

Answer:

The interaction of H+ ions and OH- ions produces water in a neutralization reaction, which occurs when an acid and a base combine to make water and a salt.

Explanation:

An acid and a base combine to produce an ionic molecule and potentially water in a neutralization reaction.

The statement that Carboniferous swamps produced so much oxygen that the atmospheric concentration of oxygen increased to 35% is not accurate.

The Carboniferous period, which occurred approximately 359 to 299 million years ago, was known for the formation of vast swamp forests and the subsequent development of coal deposits. However, it is unlikely that these swamps alone caused such a significant increase in atmospheric oxygen levels.

During the Carboniferous period, the oxygen levels in the atmosphere were indeed higher than they are today, but estimates suggest that they ranged between 26% and 31%, not as high as 35%. The increase in oxygen during this period was likely influenced by multiple factors, including the widespread growth of land plants and the lack of efficient decomposition and decay processes.

It's important to note that determining the exact oxygen levels in Earth's ancient atmosphere is challenging, and scientists rely on various geological and paleontological evidence to make estimations. While the Carboniferous swamps played a role in the overall oxygen cycle, attributing a specific increase to 35% solely to these swamps would be an oversimplification.

In summary, the Carboniferous swamps contributed to the oxygen levels in the atmosphere during that time, but the claim that they caused the atmospheric concentration of oxygen to increase to 35% is not supported by scientific evidence.

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Answer:

No, because oxygen wants two electrons to become stable and lithium will only give up 1 electron.

Answer:

A - The gas will become liquid.

Answer:

5 moles of Fe(II) are required to react completely with the 5 moles of Sulphur

Explanation:

The balanced equation in this question is

Iron + Sulfur = Iron(II) Sulfide

Fe (II) + S --> Fe(II)S

Thus one mole of sulfur reacts with one mole of Fe(II)

Hence, 5 moles of Fe(II) are required to react completely with the 5 moles of Sulphur

1.565 moles of K₂O will be formed when 3.13 moles of K reacts with O₂.

A mole is a unit of measurement used in chemistry to express the amount of a substance. It is defined as the amount of a substance that contains the same number of particles (atoms, molecules, or ions) as there are in 12 grams of carbon-12. One mole of a substance contains Avogadro's number of particles, which is approximately 6.022 x 10^23.

Stoichiometric coefficient is the number that appears in front of a chemical formula in a balanced chemical equation. It represents the relative number of moles of that substance that participate in the chemical reaction.

The balanced chemical equation for the reaction is:

4K + O₂ → 2K₂O

This equation shows that 4 moles of K reacts with 1 mole of O₂ to produce 2 moles of K₂O.

To determine how many moles of K₂O will be formed when 3.13 moles of K reacts with O₂, we need to use stoichiometry.

Assuming there is enough O₂ available for the reaction, we can use the mole ratio from the balanced equation to calculate the amount of K₂O produced.

From the balanced equation, the mole ratio of K to K₂O is 4:2 or 2:1. This means that for every 2 moles of K₂O produced, 4 moles of K are consumed.

Therefore, if 3.13 moles of K are reacted, the amount of K₂O produced will be:

(3.13 mol K) x (2 mol K₂O / 4 mol K) = 1.565 mol K₂O

Therefore, 1.565 moles of K₂O will be formed when 3.13 moles of K reacts with O₂.

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Answer:

it is a chemical process

Explanation:

rusting is the formation of reddish-brown ferric oxides on iron by low-temperature oxidation in the presence of water.

The chemical formula for rust is Fe2O3 and is commonly known as ferric oxide or iron oxide. The final product is a series of chemical reactions simplified below as- The rusting of the iron formula is simply 4Fe + 3O2 + 6H2O → 4Fe(OH)3. The rusting process requires both the elements of oxygen and water.

The yield of Cu(OH)2 is equal to the amount of CuCl2 used.

Yield is a quantitative measure of the amount of product obtained from a reaction. It is usually expressed as a percentage of the theoretical yield, which is the maximum amount of product that could be obtained from the given amounts of reaction components. Yield is an important concept in chemistry because it provides a means for evaluating the efficiency of the reaction, the quality of the conditions and the effectiveness of the purification process. Yield can be determined by measuring the amount of product obtained following a reaction, then dividing that amount by the theoretical yield. This calculation provides an estimate of how much of the desired product was obtained from the reaction.

The yield of Cu(OH)2 using CuCl2 is determined by the mole ratio of the two reactants. The balanced equation for the reaction is:
CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl
The mole ratio of CuCl2 to Cu(OH)2 is 1:1, so for every mole of CuCl2 used, one mole of Cu(OH)2 is produced. Therefore, the yield of Cu(OH)2 is equal to the amount of CuCl2 used.

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Answer:

ffff

Explanation:

If 263802 if 263 kJ are produced. Methane was burned in an amount of 3 kJkJ mol. Thus, approximately 5–6 g, or more than 1/4 mole, of methane was burned.

The pace at which mass is lost as a result of fuel combustion is known as the mass-burning rate. The rate of change in temperature from the fuel surface toward the flame can also be used to describe the temperature gradient at the fuel surface.

The product of the density of the unburned gas, the flame speed of the unburned gas, and the surface area of the flame front determines the mass burning rate of the unburned air-fuel-burned gas mixture inside the combustion chamber of an engine.

The product of the density of the unburned gas, the flame speed of the unburned gas, and the surface area of the flame front determines the mass burning rate of the unburned air-fuel-burned gas mixture inside the combustion chamber of an engine.

Combustion of methane, which you have kindly provided

CH4(g)+2O2(g)→CO2(g)+2H2O(g) ;ΔH=−802.3kJmol−1

As written, the enthalpy change is given per mole of reaction. That is, the exact amount of energy produced by burning 1 mol of methane to produce stoichiometric amounts of carbon dioxide and water vapour is 802.3 k J. In order to treat the energy as a product, I may write the reaction in this manner.:

CH4(g)+2O2(g)→CO2(g)+2H2O(g)+802.3 kJ.

o if 263 kJ are generated then

263kJ/ 802.3 kJ * 1⋅mol

methane were combusted. So this is something more than 1/4 a mole of methane combusted, approx. 5-6 g.

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