Answer:
9/40= 0.225 (experimental probability for white)
(b) because the spinner has 10 sections but there has only been 3 outcomes. If the spinner has 3 sections the changes of white would be 0.333.
2. Is correct, the more times you spin the closer you’ll get to the theoretical probability.
Step-by-step explanation:
Find the volume common to two circular cylinders, each with radius r, if the axes of the cylinders intersect at right angles. Note the equations of the two cylinders could be the following x2+y2=r2,y2+z2=r2 which their axes are at right angles to each other. To solve the volume we will be using the triple integrals formula in rectangular coordinates which is V=∫∫∫dzdydx
The total volume of the two circular cylinders intersecting perpendicularly is\(V=πr2+πr3=πr2(1+r)\).
The volume of the two circular cylinders intersecting perpendicularly can be calculated using the triple integral formula in rectangular coordinates. The triple integral formula is V=∫∫∫dzdydx.
We can separate the integral into three components. The x-component is ∫dx from \(-√r2-y2 to √r2-y2\). The y-component is ∫dy from -r to r. The z-component is ∫dz from 0 to r.
Substituting the components into the equation for the triple integral, we get \(V=∫-rrdr∫-√r2-y2√r2-y2dx∫0rdz\).
We can solve the integral by splitting the y-component into two pieces:
\(V=∫-rrdr∫-r0dx∫0rdz+∫-rrdr∫0√r2-y2dx∫0rdz\)
The first integral can be solved easily and yields V=πr2. The second integral can be solved using the substitution u=r2-y2 and yields V=πr3.
Hence, the total volume of the two circular cylinders intersecting perpendicularly is V=πr2+πr3=πr2(1+r).
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select all the correct answers
what is 9,150,000,000,000,000,000 expressed in scientific notation
9.15 × \(10^{18}\)
9.15E18
9.15E-18
9.15E-19
9.15 × \(10^{19}\)
9.15E19
9.15 × \(10^{-19}\)
9.15 × \(10^{-18}\)
Answer:
8.) 9.15 x 10^18
Step-by-step explanation:
to get scientific notation, you move the decimal place until all numbers except one are past the decimal. If you move it to the left, the exponent is postitive. If you move it to the right, it's negative. So, 9,150,000,000,000,000,000 expressed in scientific notation is 9.15 x 10^18 because you moved the decimal 18 spaces to the left.
The number 9,150,000,000,000,000,000 expressed in scientific notation will be 9.15 × 10¹⁸ or 9.15E18. Then the correct options are A and B.
What is Algebra?Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.
The number is given below.
⇒ 9,150,000,000,000,000,000
The number represented in the scientific notation will be given as,
⇒ 9,150,000,000,000,000,000
⇒ 9.15 × 10¹⁸
⇒ 9.15E18
The number 9,150,000,000,000,000,000 expressed in scientific notation will be 9.15 × 10¹⁸ or 9.15E18. Then the correct options are A and B.
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Expression 9 x, if x=5
Answer:
45
Step-by-step explanation:
9x
Replace x with 5
9*5
45
Answer:
45
Step-by-step explanation:
9x5 equals 45
jarak kota a ke kota b adalah 130 km Amir berangkat dari a pukul 8.15 menuju b dengan kecepatan rata-rata 50 km per jam Amir tiba di kota b pada pukul
Answer:
10:51
Step-by-step explanation:
Given that :
Distance from A to B = 130km
Departure time = 8 : 15
Average speed = 50 km/hr
Recall :
Speed = distance / time
Time = distance / speed
Time = (130 km) ÷ (50km/hr)
Time = 130 / 50
Time = 2.6 hours = 2 hours + (0.6 * 60) = 2 hours 36 minutes
Arrival time = (8:15) + (2 hours 36 minutes) = 10:51
What is the quotient?
Answer:
A
Step-by-step explanation:
B isn't applicable, because it's below
C and D aren't because it's not negative
10 times much as 5000
Answer:
50,000
Step-by-step explanation:
10*5,000=50,000
Answer: 50,000
Step-by-step explanation:
10× 5,000= 50,000
Or
Just add one zero to 5,000 :)
Hope this helps :)
Consider the following initial value problem, in which an input of large amplitude and short duration has been idealized as a delta function.
y′+y=2+δ(t−4),y(0)=0.
a) Find the Laplace transform of the solution.
b) Obtain the solution y(t).
c) Express the solution as a piecewise-defined function and think about what happens to the graph of the solution at t=4
The Laplace transform of the solution is Y(s) = (2 + e^(-4s))/(s+1).
Solution y(t) = L^-1{(2/(s+1)) + (e^(-4s)/(s+1))}.
Solution as a piecewise-defined function
y(t) = { 2e^(-t) for t < 4{ 2e^(-t) + e^(-(t-4)) for t >= 4a) To find the Laplace transform of the solution, we apply the Laplace transform to both sides of the differential equation and use the fact that the Laplace transform of a delta function is 1:
sY(s) - y(0) + Y(s) = 2 + e^(-4s)
sY(s) + Y(s) = 2 + e^(-4s)
Y(s) = (2 + e^(-4s))/(s+1)
b) To obtain the solution y(t), we take the inverse Laplace transform of Y(s):
y(t) = L^-1{(2 + e^(-4s))/(s+1)}
y(t) = L^-1{(2/(s+1)) + (e^(-4s)/(s+1))}
Using the Laplace transform table, we know that the inverse Laplace transform of 2/(s+1) is 2e^(-t). We can also use the table to find that the inverse Laplace transform of e^(-4s)/(s+1) is e^(-t)u(t-4), where u(t) is the Heaviside step function. Substituting these into the equation above, we get:
y(t) = 2e^(-t) + e^(-(t-4))u(t-4)
c) The solution y(t) can be expressed as a piecewise-defined function as follows:
y(t) = { 2e^(-t) for t < 4
{ 2e^(-t) + e^(-(t-4)) for t >= 4
At t = 4, there is a discontinuity in the derivative of the solution due to the presence of the delta function in the initial value problem. The solution jumps from 2e^(-4) just before t = 4 to 2e^(-4) + 1 just after t = 4. This discontinuity is known as a "shock" and is a characteristic feature of systems with sudden changes or impulses in the input. The graph of the solution will have a vertical tangent at t = 4, indicating the discontinuity in the derivative.
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In AABC, the measure of ZC=90°, AC = 7, BA = 25, and CB= 24. What is the value of
the cosine of ZA to the nearest hundredth?
Answer:
Step-by-step explanation:
300
The time series regression model contains a variable W and a regression equation of y = 200 + W + 2W2 to forecast future values. If W represents a time period, what is the forecast for time period 2 and the forecast error if the actual value for time period 2 is 100? Select the best answer.
forecast value = 210; forecast error is 110
forecast value = 210; forecast error is -110
forecast value = 210; forecast error is 0
forecast value = 100; forecast error is 0
The forecast value for time period 2 is 210, and the forecast error is -110 when the actual value is 100. Option B
To calculate the forecast value for time period 2, we substitute W = 2 into the regression equation:
y = 200 + W + 2W^2
= 200 + 2 + 2(2^2)
= 200 + 2 + 2(4)
= 200 + 2 + 8
= 210
Therefore, the forecast value for time period 2 is 210.
To calculate the forecast error, we compare the forecasted value with the actual value for time period 2. Given that the actual value is 100, the forecast error can be calculated as the difference between the actual value and the forecast value:
Forecast error = Actual value - Forecast value
= 100 - 210
= -110
Hence, the forecast error is -110.
Therefore, the correct answer is:
Forecast value = 210; forecast error is -110. So Option B is correct.
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please help I will give you any award
Answer:
218.57
Step-by-step explanation:
Since it is an isoceles triangle, the sides are 32, 32, and 14.
Using Heron's Formula, which is Area = sqrt(s(s-a)(s-b)(s-c)) when s = a+b+c/2, we can calculate the area.
(A+B+C)/2 = (32+32+14)/2=39.
A = sqrt(39(39-32)(39-32)(39-14) = sqrt(39(7)(7)(25)) =sqrt(47775)= 218.57.
Hope this helps have a great day :)
Check the picture below.
so let's find the height "h" of the triangle with base of 14.
\(\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=\sqrt{c^2 - a^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{32}\\ a=\stackrel{adjacent}{7}\\ o=\stackrel{opposite}{h} \end{cases} \\\\\\ h=\sqrt{ 32^2 - 7^2}\implies h=\sqrt{ 1024 - 49 } \implies h=\sqrt{ 975 }\implies h=5\sqrt{39} \\\\[-0.35em] ~\dotfill\)
\(\stackrel{\textit{area of the triangle}}{\cfrac{1}{2}(\underset{b}{14})(\underset{h}{5\sqrt{39}})}\implies 35\sqrt{39} ~~ \approx ~~ \text{\LARGE 218.57}\)
If N and N′ are normed linear spaces, then the set B(N,N′) of all continuous linear transformations of N into N′ is itself a normed linear space with respect to the pointwise linear operations and the norm defined by (1). Further, if N′ is a Banach space, then B(N,N′) is also a Banach space. ∥T∥=sup{∥T(x)∥:∥x∥≤1}.
The set B(N,N') of all continuous linear transformations from a normed linear space N to another normed linear space N' forms a normed linear space itself. This is true for any normed linear spaces N and N', and the norm on B(N,N') is defined as the supremum of the norms of the transformed vectors.
To show that B(N,N') is a normed linear space, we need to verify that it satisfies the properties of a normed space. Firstly, we define the norm ∥T∥ of a linear transformation T in B(N,N') as the supremum of the norms of the transformed vectors, i.e., ∥T∥ = sup{∥T(x)∥ : ∥x∥ ≤ 1}. This definition ensures that the norm is non-negative, satisfies the triangle inequality, and is homogeneous.
The set B(N,N') forms a vector space under the pointwise linear operations, where addition and scalar multiplication are defined component-wise. This means that for any two linear transformations T1 and T2 in B(N,N') and any scalar α, the operations T1 + T2 and αT1 are well-defined and also belong to B(N,N').
Continuity of the linear transformations in B(N,N') ensures that the set is closed under these operations, as the sum or scalar multiple of continuous functions is also continuous. Therefore, B(N,N') is a vector space.
Now, if N' is a Banach space (a complete normed linear space), we need to show that B(N,N') is also complete. This can be proven by establishing that every Cauchy sequence of linear transformations in B(N,N') converges to a limit that is also a linear transformation in B(N,N').
The completeness of N' guarantees the convergence of the sequence, and continuity ensures that the limit is also a continuous linear transformation.Therefore, B(N,N') is a normed linear space, and if N' is a Banach space, then B(N,N') is also a Banach space.
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The stock of Company A lost $5. 31 throughout the day and ended at a value of $112. 69. By what percentage did the stock decline?
If the stock of Company A lost $5. 31 throughout the day and ended at a value of $112. 69. The stock of Company A declined by 4.5% throughout the day.
The percentage decline in stock price is calculated by dividing the loss in value by the original value of the stock. To find out the percentage loss of stock A, we can use the formula:
(Loss in value / Original value) x 100%
Let us substitute the values we know:
Loss in value = $5.31
Original value = $118.00
Percent change = (5.31 / 118.00) x 100%
Percent change = 0.045 or 4.5%
Therefore, the stock of Company A declined by 4.5% throughout the day.
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The graph of g is a horizontal shrink by a factor of 1/2 and a translation 1 unit down, followed by a reflection in the x-axis of the graph of f(x)=(x+6)^2+3. Write a rule for g. Then identify the vertex.
Answer:
steps below
Step-by-step explanation:
f(x)=(x+6)²+3 ... Gray graph
horizontal shrink by a factor of 1/2: f(2x) = (2x+6)²+3 ... green
translation 1 unit down: f(2x)-1 = (2x+6)²+2 ... purple
reflection in the x-axis: g(x) = - ((2x+6)²+2) = - (2x+6)²-2 = -4(x+3) - 2 .. Red
parabola equation: y = a(x-h)² + k (h,k): vertex
vertex (-3 , -2)
The rule of function g(x) is \(g(x) = -4(x + 3)^2 -2\), and the vertex of the function is (-3,-2)
The equation of the function is given as:
\(f(x) = (x + 6)^2 + 3\)
The rule of shrinking the function by a factor of 1/2 is:
\((x,y) \to (2x,y)\)
So, we have:
\(f'(x) = (2x + 6)^2 + 3\)
When the function is translated down by 1 unit, the rule of the transformation is:
\((x,y) \to (x,y-1)\)
So, we have:
\(f"(x) = (2x + 6)^2 + 3-1\)
\(f'"x) = (2x + 6)^2 + 2\)
Lastly, the function is reflected across the x-axis,
The rule of this transformation is:
\((x,y) \to (x-y)\)
So, we have:
\(g(x) = -(2x + 6)^2 -2\)
Factor out 2
\(g(x) = -(2(x + 3))^2 -2\)
Expand
\(g(x) = -4(x + 3)^2 -2\)
The above represents the rule of function g(x), and the vertex of the function is (-3,-2)
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Help please due today!!
lisa is on her way home in her car. she has driven 24 miles so far, which is three-fourths of the way home. what is the total length of her drive?
If lisa is on her way home in her car, she has driven 24 miles so far, which is three-fourths of the way home, Lisa's total drive is 32 miles.
Let's represent the total length of Lisa's drive as x. We know that she has driven 24 miles so far, which is three-fourths of the total length. We can write this information as:
24 = (3/4) x
To find x, we need to isolate it on one side of the equation. We can start by multiplying both sides by 4/3 to get rid of the fraction:
24 * (4/3) = x
Simplifying, we get:
32 = x
We can say that Lisa has already driven 24 miles, which is three-fourths of the total distance. To find the total distance, we use the equation 24 = (3/4) x, where x represents the total distance.
To solve for x, we multiply both sides of the equation by 4/3 to cancel out the fraction, giving us 32 = x. Therefore, Lisa's total drive is 32 miles.
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Given the function, f(x)= |x-1| -2, choose the correct transformation
Answer:
c
Step-by-step explanation:
I attached a desmos graph so you could get a better understanding but it's right 1, down 2
can someone please help my ASAP
Domain: (-∞, ∞)
Range: (-∞,1]
Answer:
Domain = All Real Numbers
Range = y≤1
Step-by-step explanation:
Since parabolas are continuous, the domain is all real numbers. The range, or y value, is all real numbers less than or equal to 1 (y≤1), since 1 is the vertex.
Hope this helps :)
Find the length of arc XPY. Leave your answer in terms of π. A.24π m B.12π m C.4π m D.720π m
The length of arc XPY in terms of π include the following: B.12π m
How to calculate the length of the arc?In Mathematics and Geometry, the arc length formed by a circle can be calculated by using the following equation (formula):
Arc length = 2πr × θ/360
Where:
r represents the radius of a circle.θ represents the central angle.By substituting the given parameters into the arc length formula, we have the following;
Arc length XPY = 2 × π × 8 × 3/4
Arc length XPY = 12π meters.
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Missing information:
The question is incomplete and the complete question is shown in the attached picture.
Please help me guys please
c. the number of persons allegric to penicillin
Guys I need help plz and can you show work also thx
Answer: first problem 3rd choice The graph shifts vertically up 5 units
11.) the y intercept is -5
19.) f(-8) = -18
last item third choice All real numbers such that are ≥ 0 and ≤ 40
Step-by-step explanation:
19.) f(x)=2(-8 -3) + 4
2 (-11) + 4
-22 + 4
f(-8) = -18
Translate the algebraic expression shown below into a verbal expression. X 4
Answer:
answer is D
Step-by-step explanation:
A) if sum of four and some number = x + 4
B) if product of some number and 4 = 4x
C) the different between 4 and some number = x - 4
D) if quotient of some number and 4 = x/4
∵therefore D is the answer
8. Find the greatest number which exactly divides 48 and 140.
Answer:
4
Step-by-step explanation:
Greatest Common Factor or Divisor is 4, because it is the greatest number that divides evenly into all of them.
Hope this helps! :)
Assume that there is a statistically significant bivariate relationship between the amount of texting during driving and the number of accidents. Scientists later investigate whether or not this bivariate relationship is moderated by age.
Age 16-20: r = 0.6 p = 0.01
Age 21+: r = 0.2 p = 0.05
T or F: Based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
It is False that based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
In the given scenario, it is not completely true that based only on the r and p values listed above, you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
Let's first understand what is meant by the term "moderator.
"Moderator: A moderator variable is a variable that changes the strength of a connection between two variables. If there is a statistically significant bivariate relationship between the amount of texting during driving and the number of accidents, scientists investigate whether this bivariate relationship is moderated by age.
Therefore, based on the values of r and p, it is difficult to determine if age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
As we have to analyze other factors also to determine whether the age is a moderator or not, such as the sample size, the effect size, and other aspects to draw a meaningful conclusion.
So, it is False that based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
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How many ways can you arrange 2 letters from the word S Q U A R E
Answer:
30
Step-by-step explanation:
WE use permutation for this question:
since the letters in SQUARE are all distinct, so:
\(^{6}P_{2} = 6*5=30\)
The number of ways of arranging 2 letters from the word S Q U A R E is given by A = 15 ways
What are Combinations?The number of ways of selecting r objects from n unlike objects is given by combinations
ⁿCₓ = n! / ( ( n - x )! x! )
where
n = total number of objects
x = number of choosing objects from the set
Given data ,
Let the number of ways of arranging 2 letters from the word S Q U A R E be represented as A
Now , to select 2 letters from the 6 letters in the word SQUARE, without regard to order.
This is a combination problem, since the order in which we select the letters does not matter. Therefore, we can use the formula:
6 C 2 = 6! / 2!(6 - 2)!
= 6 x 5 / (2 x 1) x (4 x 3 / (2 x 1))
= 15
Hence , there are 15 ways to arrange 2 letters from the word SQUARE
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Need help ASAP!!!!!!!!
Answer:
y=35
x=27.8
Step-by-step explanation:
4. Andrés desea embaldosar el piso de su casa que tiene 375 cm de ancho y 435 cm de largo. Calcula la longitud del lado que tendrían las baldosas. ¿Cuántas baldosas colocaría en total?
Answer:
Sabemos que el piso es un rectángulo de 435 cm de largo y 375 cm de ancho.
Recordar que para un rectángulo de largo L, y ancho W, el área es:
A = L*W
Entonces el área del piso, será:
A = 435cm*375cm = 163,125 cm^2
Primero, sabemos que se utilizaran baldosas (las cuales son cuadradas) y queremos saber la longitud de lado que tendrían las baldosas.
No tenemos ningún criterio para encontrar este lado, solo que (si queremos usar un número entero de baldosas) el largo L del lado de la baldosa deberá ser un divisor de tanto el ancho como el largo del suelo.
Dicho de otra forma
el largo, 435cm, tiene que ser múltiplo de L
el ancho, 375cm, tiene que ser múltiplo de L.
Por ejemplo, ambos números son múltiplos de 5, entonces podríamos tomar L = 5cm
En este caso, el área de cada baldosa es:
a = L^2 = 5cm*5cm = 25cm^2
Y el número total de baldosas que necesitaría usar esta dado por el cociente entre el área del suelo y el area de cada baldosa.
N = ( 163,125 cm^2)/(25cm^2) = 6,525 baldosas.
También sabemos que ambos números (435cm y 375cm) son múltiplos de 15cm
Entonces las baldosas podrían tener 15cm de lado.
En este caso, el área de cada baldosa es:
A = (15cm)^2 = 225cm
En este caso el número total de baldosas necesarias será:
N = ( 163,125 cm^2)/(225cm^2) = 725 baldosas.
Evaluate the factorial expression.15!12!(4−1)!
we have
15!12!(4−1)!
15!12!(3!)=3,758,268,687,305,932,800,000
therefore
the answer is
3,758,268,687,305,932,800,000ASAP please help right now
Answer:
1
Step-by-step explanation:
Because the shape divided has to create another shape and for 1 it's an oval at the beginning and then after the lines of symmetry go through its seen as 8 triangles.
7. which of the following would be an empty set ?
A. the set of prime numbers that are odd numbers.
B. the set of even numbers that are prime numbers.
C. the set of multiple of 3 that prime numbers.
D. the set of all numbers that are divisible by 2.
Answer:
the set of odd numbers that are divisible by 2
4 find the area bounded by the two functions f(x) = −x2 4x 2 and g(x) = −2x 10 .
The area bounded by the two functions f(x) = −x2 4x 2 and g(x) = −2x is =64 unit
To find the area bounded by the two functions f(x) = −x2 + 4x + 2 and g(x) = −2x + 10, we must first determine where the two functions intersect.
To do this, we set the two functions equal to each other and solve for x:
−x2 + 4x + 2 = −2x + 10
−x2 − 2x + 8 = 0
(x − 4)(x − 2) = 0
x = 4, x = 2
Now, we can calculate the area of the bounded region between f(x) and g(x):
Area = ∫24(g(x) − f(x)) dx
Area = ∫24(−2x + 10 − (−x2 + 4x + 2)) dx
Area = ∫24(x2 − 2x + 8) dx
Area = [x3/3 − x2/2 + 8x]24
Area = (64/3) − (32/2) + (64) = 64
Therefore, the area bounded by the two functions is 64.
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