What evidence contradicts the theory that moving two-
ton stones was physically impossible for the Egyptians,
and must have been done using alien technology?

Answer:

\(\boxed {\boxed {\sf 2.36 \ mol \ SO_2}}\)

Explanation:

We are asked to convert grams to moles. We will use the molar mass and dimensional analysis to perform this conversion.

The molar mass is the mass of 1 mole of a substance. These values are found on the Periodic Table because they are equivalent to the atomic masses, but the units are grams per mole instead.

We are given a mass of sulfur dioxide (SO₂). Look up the molar masses of the individual elements.

Notice that the formula of the compound contains a subscript. The subscript after O means there are 2 moles of oxygen in 1 mole of sulfur dioxide. We must multiply oxygen's molar mass before adding sulfur's.

Now we will use dimensional analysis to convert grams to moles. From the molar mass, we know there are 64.068 grams of sulfur dioxide per mole, so we can set up a ratio.

\(\frac {64.068 \ g \ SO_2} {1 \ mol \ SO_2}\)

We are converting 151 grams to moles, so we multiply by this value.

\(151 \ g \ SO_2 *\frac {64.068 \ g \ SO_2} {1 \ mol \ SO_2}\)

Flip the ratio so the units of grams of sulfur dioxide cancel.

\(151 \ g \ SO_2 *\frac {1 \ mol \ SO_2}{64.068 \ g \ SO_2}\)

\(151 *\frac {1 \ mol \ SO_2}{64.068 }\)

\(\frac {151}{64.068 } \ mol \ SO_2\)

\(2.356870825 \ mol \ SO_2\)

The original measurement of grams (151) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 6 in the thousandth place tells us to round the 5 in the hundredth up to a 6.

\(2.36 \ mol \ SO_2\)

151 grams of sulfur dioxide is approximately 2.36 moles of sulfur dioxide.

The value that is equivalent to 4 cups is d. 240 milliliters.

One cup is equal to 240 milliliters. Therefore, 4 cups can be calculated as follows:

4 cups x 240 milliliters/cup = 960 milliliters or 0.96 liters (rounded to two decimal places)

Option d, 240 milliliters, is equivalent to 4 cups and is the correct answer. Options a and c are close to the correct answer, but not equivalent to 4 cups. Option b, 20 milliliters, is much smaller than 4 cups and is not a reasonable conversion factor. Therefore, d. 240 milliliters, is the correct choice.

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Answer:

Knowing your lab equipment and their names will aid in having a successful experiment and may help in correcting errors.

If you do not know your lab equipment, that will only result in having a lack of knowledge of the equipment or not knowing how to correct a mistake in an experiment.

Explanation:

Hope I helped.

Answer:

D

Explanation:

bothe cylinders are at room temperature so no cylinder has more themal energy. That crosses off the answers A B and C.

The difference between a solution and a suspension is in the particle sizes involved. A solution is a mixture of ions or molecules (very, very small). Solutions are transparent, meaning that you can see through them. A suspension has bigger particle sizes and so it may look cloudy or murky

Answer:a. steep cement-covered slope

Answer:A.) Mechanical and nuclear

Explanation:

iv,e got nuthing sorry im only a kid i have to leared that yet

answer:

B) Radiant and Thermal

explanation:

  "In a flashlight, chemical energy in the batteries is converted to electrical energy when the circuit including the batteries, switch and light bulb is completed. The electrical energy is converted to light (electromagnetic / radiant energy) and some heat (thermal energy) by the light bulb." -https://www.crosbyisd.org/cms/lib6/TX02216626/Centricity/Domain/392/6_9C-EnergyFormsConversions.pdf

Answer:

A) NaOH

got it right on the test.

Explanation:

Answer:

NaOH  

Explanation:

The moles can be defined as the mass of the substance with respect to molar mass. The moles of potassium nitrate is 1 mol.

The moles of a compound can be calculated from:

\(\rm Moles=\dfrac{Mass}{Molar\;mass}\)

The molarity can be defined as the moles of solute in a liter of solution.

The molarity can be expressed as:

\(\rm Molarity=\dfrac{Moles\;\times\;1000}{Volume\;(mL)}\)

The molarity of potassium nitrate solution is 2 M, and the volume is 500 mL.

The moles of potassium nitrate is given as:

\(\rm 2\;M=\dfrac{Moles\;\times\;1000}{500\;mL}\\ Moles=\dfrac{2\;\times\;500}{1000}\;mol\\ Moles=1\;mol\)

The moles of potassium nitrate in 2 M, 500 mL solution are 1 mol.

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Answer:

This question is incomplete

Explanation:

This question is incomplete but one can assume the answer from the definition of quantum mechanics. Quantum mechanics is the science that describes particles in nature at the atomic and subatomic particle (electron, proton and neutron) level. Thus it can be assumed that atoms and subatomic particles are used to broadly describe particles.

Increasing atomic radius can have a significant impact on the crystal structure of a material, affecting parameters such as interatomic distances, coordination numbers, lattice parameters, symmetry, and mechanical properties.

As the atomic radius increases, there are several effects on the crystal structure of a material:

1. Interatomic Distance: With increasing atomic radius, the average distance between neighboring atoms in a crystal lattice also increases. This leads to a larger unit cell and a decrease in atomic packing density.

2. Coordination Number: The coordination number refers to the number of atoms surrounding an atom in a crystal lattice. As the atomic radius increases, the coordination number may change. For example, a smaller atom might have a higher coordination number, while a larger atom might have a lower coordination number. This can influence the overall structure and stability of the crystal.

3. Lattice Parameters: The lattice parameters, such as the lattice constant or unit cell dimensions, may be affected by changes in atomic radius. An increase in atomic radius can result in an expansion of the crystal lattice, leading to changes in the lattice parameters.

4. Symmetry: Changes in atomic radius can affect the symmetry of the crystal structure. Larger atoms may disrupt the symmetry and introduce distortions or vacancies in the crystal lattice.

5. Mechanical Properties: The mechanical properties of a material, such as its strength, hardness, and flexibility, can be influenced by changes in atomic radius. Alterations in atomic size can affect the bonding forces between atoms and, consequently, the material's mechanical behavior.

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Answer:

? which gas, explain further

Explanation:

Organic molecules are more diverse compared to inorganic molecules due to the unique properties of carbon, its ability to form covalent bonds with other elements, and the presence of functional groups, allowing for a wide range of molecular structures and chemical reactions.

Organic molecules are primarily composed of carbon atoms, which possess a unique ability to form strong covalent bonds with other atoms, including carbon itself. Carbon atoms can bond with up to four other atoms, enabling the formation of complex and varied molecular structures. This property, known as catenation, allows carbon to form long chains, branched structures, and ring systems, resulting in an immense diversity of organic compounds.

Furthermore, carbon atoms can also bond with other elements such as hydrogen, oxygen, nitrogen, sulfur, and phosphorus, forming functional groups. These functional groups significantly influence the chemical behavior and reactivity of organic molecules. They introduce specific characteristics and properties, such as acidity, basicity, polarity, and the ability to undergo various types of reactions. The presence of functional groups further expands the possibilities for molecular diversity in organic compounds.

In contrast, inorganic molecules typically lack the same level of structural complexity and diversity found in organic molecules. While inorganic compounds can exhibit a range of chemical properties and reactions, they are often limited by the nature of their bonding and the types of elements involved. Inorganic molecules predominantly involve ionic bonding, where electrons are transferred between atoms, resulting in simpler and more repetitive structures

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D. High pressure most likely describes the environment in which this rock formed.

The rock shown in the photograph is a type of sedimentary rock called "conglomerate." Conglomerate rocks are formed by the deposition and cementation of large, rounded fragments of pre-existing rocks. The rounded nature of the rock fragments suggests that they have undergone transport and erosion before being deposited and lithified into conglomerate.

The most likely environment for the formation of conglomerate rocks is a high-energy setting, such as river channels, where the rock fragments are subjected to high pressures during transport. The high pressure is a result of the weight and force of the moving water, which helps to compact and cement the rock fragments together.

The other options, such as low mineral content, low temperature, and high humidity, are not necessarily indicative of the environment in which conglomerate rocks are formed. Conglomerate formation is primarily associated with the physical processes of transportation and deposition, rather than the chemical composition, temperature, or humidity of the environment.

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Answer:

Wavelength (λ) = 1.875 × 10⁻⁶ m

Explanation:

Given:

Energy (e) =  1.06 × 10⁻¹⁹ J

Find:

Wavelength (λ) = ?

Computation:

e = hc / λ

λ = hc / e

where c = 3 × 10⁸

Planck's constant (h) = 6.625 × 10⁻³⁴

So,

Wavelength (λ) = (6.625 × 10⁻³⁴)(3 × 10⁸) / (1.06 × 10⁻¹⁹)

1. Wavelength (λ) = 1.875 × 10⁻⁶ m

2. Given n = 4 to n = 3 both are integer not fraction so, electron is quantize

Answer:

Power Plant = Mitochondria (Mitochondria is the powerhouse of the cell)

City Limits = Cell Membrane (Outer layer of a cell)

City Hall = Nucleus (The nucleus is the control center in a cell)

City Food Processing Plant (Chloroplast process the cells food)

City Plans = Chromosomes (They contain the genetic information about the cell)

Community = Cytoplasm (Mainly process of elimination)

Explanation:

Explanations are in parenthesis

Answer:

it's A

Explanation:

100 on test5tttttttttttttttt

Answer:

Group 15

Explanation:

Answer:

1.5x1020 molecules = 2.5x10-4 moles.

: PM2.5 is defined as the mass concentration of particles in the air less than or equal to 2.5 micrometers in diameter.Question 15: False, carbon dioxide (CO2) is not considered a criteria air pollutant.

Question 16: The closest answer is 50%, but the exact percentage is not provided in the question.Question 17: The term "photochemical smog" is most synonymous with ozone (O3), which is a criteria air pollutant.Question 18: True, attainment of ambient air quality standards requires that measured concentrations at all monitoring stations within an air district are below ambient air standards.

Question 14 asks about the definition of PM2.5. PM2.5 refers to particulate matter with a diameter less than or equal to 2.5 micrometers. It represents the mass concentration of particles suspended in the air, which are small enough to be inhaled into the respiratory system and can have adverse health effects.

Question 15 states whether carbon dioxide (CO2) is a criteria air pollutant. Criteria air pollutants are a set of pollutants regulated by environmental agencies due to their detrimental impact on air quality and human health. However, carbon dioxide is not considered a criteria air pollutant because it does not directly cause harm to human health or the environment in the same way as pollutants like ozone or particulate matter.

Question 16 asks about the percentage of carbon monoxide (CO) emissions from mobile sources in Santa Clara County. While the exact percentage is not provided in the question, the closest answer option is 50%. However, it is important to note that the precise percentage may vary depending on specific local conditions and emissions sources.

Question 17 inquires about the criteria air pollutant most synonymous with the term "photochemical smog." Photochemical smog is primarily associated with high levels of ground-level ozone (O3). Ozone is formed when nitrogen oxides (NOx) and volatile organic compounds (VOCs) react in the presence of sunlight, creating a hazy and polluted atmospheric condition.

Question 18 addresses the concept of "attainment" of ambient air quality standards. To achieve attainment, measured concentrations of pollutants at all monitoring stations within an air district must be below the established ambient air quality standards. This ensures that the air quality in the given area meets the required standards for protecting human health and the environment.

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Answer:

Nucleus is known as the brain of the cell.

correct option is B letter

The volume of the diluted HBr stock solution is 546mL.

CALCULATE VOLUME:

The volume of a diluted solution can be calculated by using the following expression:

C1V1 = C2V2

Where;

According to this question, 45.5mL of a 18.0M HBr stock solution is diluted to 1.5 M, the volume of the diluted solution is calculated as follows:

18.0 × 45.5 = 1.5 × V2

819 = 1.5V2

V2 = 819 ÷ 1.5

V2 = 546mL

Therefore, the volume of the diluted HBr stock solution is 546mL.

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The statement that best describes the cell condition supporting Na+ sequestration in the vacuole is option B: Na+ sequestration can occur if the concentration of protons (H+) in the cytoplasm is less than the concentration of protons (H+) in the vacuole.

Option B accurately describes the condition that enables Na+ sequestration in the vacuole. In plant cells, the vacuole plays a crucial role in ion homeostasis by actively transporting ions such as Na+ into its lumen, maintaining a lower concentration of Na+ in the cytoplasm compared to the vacuole.

This sequestration process relies on proton pumps present in the vacuolar membrane, which actively transport protons (H+) from the cytoplasm into the vacuole, creating an electrochemical gradient. The higher concentration of protons (H+) in the vacuole creates an electrochemical potential that facilitates the uptake of Na+ ions.

By maintaining a lower concentration of protons (H+) in the cytoplasm relative to the vacuole, the cell can drive Na+ ions into the vacuole against their concentration gradient, effectively sequestering them and preventing their accumulation in the cytoplasm.

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The normality of Ba(OH)2 solution is 0.0544 N.

The normality of Ba(OH)2 solution can be calculated by using the concept of acid-base titration.

In the given question, a 25.0 mL sample of Ba(OH)2 solution is neutralized by 45.3 mL of 0.150 N HCl.

Here, we need to determine the normality of the Ba(OH)2 solution.

Steps involved in the calculation of normality of Ba(OH)2 solution are as follows:

Step 1: Write the balanced chemical equation of the reaction taking place.

Ba(OH)2 + 2HCl → BaCl2 + 2H2O

Step 2: Determine the number of equivalents of HCl that reacted. It can be calculated by using the formula;

N1V1 = N2V2

N1 = N2V2 / V1

N1 = (0.150 N) × (45.3 mL) / (1000 mL/L)

N1 = 0.0068 equivalents of HCl

Step 3: Determine the number of equivalents of Ba(OH)2 that reacted.

It can be determined from the balanced chemical equation that 2 moles of HCl react with 1 mole of Ba(OH)2.

So, the number of equivalents of Ba(OH)2 that reacted can be calculated by using the formula;

N1V1 = N2V2

N2 = 2N1

N2 = 2 × 0.0068

N2 = 0.0136 equivalents of Ba(OH)2

Step 4: Determine the normality of Ba(OH)2 solution.

The normality can be calculated by using the formula;

N = Number of equivalents of solute / Volume of solution in L.

N = 0.0136 eq / (25.0 mL × 1 L / 1000 mL)

N = 0.0544 N

Therefore, the normality of Ba(OH)2 solution is 0.0544 N.

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The new volume of the gas at 20 °C is 205 mL

The correct answer to the question is Option C. 205 mL

From the question given, the following data were obtained:

Initial volume (V₁) = 250 mL

Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K

Initial pressure (P₁) = 10 atm

Final temperature (T₂) = 20 °C = 20 + 273 = 293 K

Final pressure (P₂) = 12 atm

The new volume of the gas can be obtained by using the combine gas equation as follow:

\( \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \\ \\ \frac{10 \times 250}{298} = \frac{12 \times V_2}{293} \\ \\ cross \: multiply \\ \\ 298 \times 12 \times V_2 = 10 \times 250 \times 293 \\ \\ divide \: both \: side \: by \: 298 \times 12 \\ \\ V_2 = \frac{10 \times 250 \times 293}{298 \times 12} \\ \\ V_2 = 205 \: mL \\ \)

Therefore, the new volume of gas is 205 mL

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The value of the equilibrium constant at 25°C for the given reaction is 1365.

The equilibrium constant (K) can be calculated using the standard free energy change (∆G°) through the following equation;

∆G° = -RT ln K

where R is gas constant (8.314 J/K·mol), T is temperature in Kelvin (25°C = 298 K), and ln is natural logarithm.

First, we need to convert the ∆G° value given in kilojoules to joules;

∆G° = -18.1 kJ/mol x 1000 J/kJ

= -18,100 J/mol

Then, we can plug in the values into the equation and solve for K;

-18,100 J/mol = -8.314 J/K·mol x 298 K x ln K

ln K = (-18,100 J/mol) / (-8.314 J/K·mol x 298 K)

= 7.19

K = \(e^{(7.19)}\) = 1365

Therefore, the value of the equilibrium constant is 1365.

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Answer:

The process of making S'more by adding chocolate bar, gram-crackers, and marshmallows in layers is not a chemical reaction

Explanation:

In a chemical reaction, the substances involved in the reaction are known as the reactants and the substances produced have different physical and chemical properties than those of the reactants and they are known as the products.

The bonds that hold the atoms of the reactants are broken down and rearranged, creating entirely new substances as products. Therefore, energy must be added and/or evolved in any chemical reaction and all reactant atoms should be involved in the reaction.

The change in energy can be sensed as heat change such as increase or decrease in the temperature of the products

Since S'more does not involve any of the above changes that occur in a chemical reaction when the chocolate bar, gram-crackers, and marshmallows are put together, it is not a chemical change or a chemical reaction.

20ul of a 1M stock of ascorbic acid and 100mls of water is needed to make 2mm of ascorbic acid in a final volume of 100mls

To make a 2mm solution of ascorbic acid in a final volume of 100mls, we first need to calculate how many moles of ascorbic acid are required. We can use the formula:

molarity = moles of solute / liters of solution

Given that we need 2mm of ascorbic acid, we can calculate the number of moles of ascorbic acid required: 2mm = 2 x 10^-3 molar

We are told that the final volume is 100mls = 0.1Lmoles of ascorbic acid = molarity x liters of solution = 2 x 10^-3 x 0.1 = 2 x 10^-4 moles

To make a 1M stock solution, we know that 1 mole of solute is dissolved in 1 liter of solvent.

volume of 1M stock solution = moles of solute / 1 = 2 x 10^-4 moles / 1 = 2 x 10^-4 L = 20 ul.

The total volume of the final solution is 100mls = 0.1L. The volume of the 1M stock solution is 20ul = 2 x 10^-5L. So the volume of water needed for the final solution is:0.1L - 2 x 10^-5L = 0.09998 L ≈ 100mls So, you need 20ul of a 1M stock of ascorbic acid and 100mls of water to make 2mm of ascorbic acid in a final volume of 100mls.

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Answer:

group, 6 or 16

Explanation:

as the group's progress going from the left of the table to the right of the the table, the valance electrons increase. although group 14 is split up by a ladder stair steppy thingy. the ones on the top take electrons, and the ones below give electrons.

The concentration of the vial is 0.5 %. We will suppose that it is % w/v. The concentrarion % w/v is defined as:

% w/v = mass of solute in g/volume of solution in mL * 100

We have to find the mL that we have to administer to deliver 20 mg. Let's convert those mg into g. We know that there are 1000 mg in 1 g.

1000 mg = 1 g

mass of solute in g = 20 mg * 1 g/(1000 mg)

mass of solute in g = 0.020 g

Now that we know the concentration of the solution and the mass in grams of the medication, we can find the volume in mL.

% w/v = mass of solute in g/volume of solution in mL * 100

0.5 = 0.020 / volume of solution in mL * 100

volume of solution in mL = 0.5/(100 * 0.020)

volume of solution in mL = 0.25 mL

Answer: we need to administer 0.25 ml