Specialized organelles (Chloroplasts & Mitochondria - Energy in Plant), Cell membrane, Nucleus

The equations that can be used to solve for the force of friction exerted on the block by the surface is F- f = mv² / d

The constant force F is exerted on the block of mass and it accelerates with a speed, v and covering a distance of d in the direction of the force. The force of friction is an opposing force to the applied force.

Therefore,

using Newtons third law

F - f = ma

a = v/t

t = d/v

F - f = m × v / t

F- f = m × \(\frac{v}{\frac{d}{v} }\)

F- f = m × v²/d

Therefore,

F- f = mv² / d

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Answer:

the elongation of the spring is 0.3186 m.

Explanation:

The force exerted by the spring on the block of wood when it is in equilibrium is equal to the weight of the block of wood, which is given by:

F_spring = F_gravity

where F_spring is the force exerted by the spring and F_gravity is the weight of the block.

The weight of the block of wood can be calculated as:

F_gravity = m * g

where m is the mass of the block and g is the acceleration due to gravity.

The mass of the block can be calculated using its density and volume:

m = ρ * V = ρ * A * h

where ρ is the density of the block, A is the cross-sectional area of the block, and h is the height of the block.

The height of the block can be calculated as:

h = m / (ρ * A) = 4.58 kg / (625 kg/m^3 * A)

The cross-sectional area of the block is not given, so we cannot calculate it directly. However, we can use the fact that the block is in equilibrium to find the elongation of the spring.

When the block is in equilibrium, the force exerted by the spring is balanced by the weight of the block. The elongation of the spring (∆L) can be calculated using Hooke's Law:

F_spring = k * ∆L

where k is the spring constant.

Substituting the values we have:

F_gravity = F_spring

m * g = k * ∆L

Solving for ∆L:

∆L = (m * g) / k

We can calculate the spring constant using the given value of the spring's constant k:

k = 140 N/m

Substituting the values we have:

∆L = (m * g) / k = (4.58 kg * 9.8 m/s^2) / 140 N/m

∆L = 0.3186 m

Therefore, the elongation of the spring is 0.3186 m.

Joules can be converted into electron Volts (eV) by using the formula E = qV, where E is the energy in joules, q is the charge of an electron, and V is the potential difference in volts.

The charge of an electron is 1.602 × 10^-19 coulombs, so the formula can be rewritten as E = (1.602 × 10^-19) V. To convert joules into electron volts, we simply divide the energy in joules by the charge of an electron.

Here is a step-by-step explanation of how to convert joules into electron volts:
Step 1: Find the energy in joules that you want to convert into electron volts.
Step 2: Divide the energy in joules by the charge of an electron (1.602 × 10^-19 coulombs) to get the energy in electron volts.
Step 3: The result you get is the energy in electron volts.

For example, if you have an energy of 1 joule and want to convert it into electron volts, you would do the following:
1 joule / (1.602 × 10^-19 coulombs) = 6.241 × 10^18 electron volts
So, 1 joule is equivalent to 6.241 × 10^18 electron volts.

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By using the blackbody radiation formula, the temperature of the filament inside the bulb is changed by a factor of 10⁰'²⁵.

We need to know about black body radiation to solve this problem. The energy radiated by a black body object is proportional to the area and the fourth power of temperature. It can be determined as

P = A . e . σ . T⁴

where P is power, A is surface area, e is emissivity, σ is Stefan Boltzmann's constant ( 5.67 x 10¯⁸ W/m²K⁴) and T is temperature.

From the question above, we know that

P1 = 10 watt

P2 = 100 watt

T1 = T1

By using the black body radiation formula, the ratio of temperature is

T1⁴ / T2⁴ = P1 / P2

Hence,

T1⁴ / T2⁴ = P1 / P2

T1⁴ / T2⁴ = 10 / 100

T1⁴ / T2⁴ = 1 / 10

T2⁴ = 10T1⁴

T2 = ⁴√(10T1⁴)

T2 = T1 x 10⁰'²⁵

Thus, the temperature of the filament inside the bulb is changed by a factor of 10⁰'²⁵.

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Answer:

Its water molecules were broken apart, and hydrogen was lost to space. What kind of gas is most affected by thermal escape? What causes the release of oxygen into Earth's atmosphere?

Explanation:

The answer to the digits rounded to one significant figure is 100.

Significant figures are the most important figures in a number of digits.

The closer a digit is to the beginning of a number, the more important  or significant  it is.

But, the rule for rounding up a set of numbers to the first significant or to one significant figure is that:

From the numbers 98.907, 9 is the most significant digit followed by 8.

8 is greater than 5 so we should round up by adding one to 9 making the number 100.

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Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 6 × 4

We have the final answer as

Hope this helps you

Answer:

24 n is the answer

The correct rank of the given hypothetical planets having the same radius from the lowest moment of inertia to the highest moment of inertia is 4231

First of all we must know that because of the relationship of the moment of inertia to the rotation is exactly analogous and represents that if a body has lower moment of inertia than a body with higher moment of inertia. Even if the bodies (or here in this case as given) masses and sizes are equal. Now it is very important to know that the object or planets with more mass at the centre means to have lower moment of inertia full stop hence as per the discussion of the given information, the rank of the hypothetical planet as per the given conditions will be 4231.

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Answer:

17m/s

Explanation:

v=u+at

v=5+3*4

v=17m/s

Answer:

Explanation: B. because particles of solid move. Though particles of solid  are packed together tightly they vibrate and vibration is a form of motion .

The box on the desk has a gravitational potential energy of 36.9 J.

Weight divided by mass equals the strength of the gravitational field. Different planets have various strengths of gravitational fields. The Moon's gravitational field is 1.6 N/kg strong.

The following formula must be used to get the box's gravitational potential energy: PE = mgh, where mgh is the height the box is raised to, m is the mass of the box, g is the acceleration caused by gravity, and PE is the gravitational potential energy.

The height must first be converted to metres:

h = 75.0 cm = 0.75 m

The values may now be plugged in, and PE can be solved:

PE = (5.00 kg)(9.81 m/s^2)(0.75 m) = 36.9 J

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Answer:

Explanation:

The prime purpose of radio is to convey information from one place to another through the intervening media (i.e., air, space, nonconducting materials) without wires. Besides being used for transmitting sound and television signals, radio is used for the transmission of data in coded form.

We can start by using the formula for tangential acceleration:

a_t = r * α

α = a_t / r = 1.3 m/s^2 / 150 m = 0.00867 rad/s^2

a_total = √(a_t^2 + a_c^2)

where a_c is the centripetal acceleration. We can rearrange this equation to solve for a_c:

a_c = √(a_total^2 - a_t^2) = √(3.0^2 - 1.3^2) = 2.5 m/s^2

a_c = r * ω^2

where ω is the angular velocity. Rearranging this equation, we get:

ω = √(a_c / r) = √(2.5 m/s^2 / 150 m) = 0.1155 rad/s

Finally, we can use the formula for angular displacement:

θ= ω^2 * t / 2

v_i = 0

a = a_t

to find the time it takes for the car to reach the required total acceleration of 3.0 m/s^2:

a = (v_f - v_i) / t

t = (v_f - v_i) / a

t = v_f / a

where v_f is the final velocity. Using the formula for final velocity and the fact that the car starts from rest, we get:

v_f^2 = 2 * a_t * θ

v_f = √(2 * a_t * θ)

t = √(2 * θ / a_t)

t = √(2 * θ / 1.3) = √(1.5385 * θ)

t = v_f / a = √(2 * a_t * θ) / a_t = √(2 * θ / 1.3)

Setting these two expressions for t equal to each other, we get:

√(1.5385 * θ) = √(2 * θ / 1.3)

Squaring both sides and solving for θ, we get:

θ = 4.89 radians

Therefore, the car will have traveled through an angle of 4.89 radians when the magnitude of its total acceleration is 3.0 m/s^2.

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The spring will stretch by an amount equal to 54 N divided by the spring constant, k.

The spring constant, k, is a constant for a particular spring and determines the amount of force necessary to stretch the spring a certain amount. If the spring does not reach its elastic limit, then the amount it will stretch is equal to the amount of force applied divided by the spring constant. In this case, the amount the spring will stretch is equal to 54 N divided by the spring constant, k.
For example, if the spring constant is 10 N/m, then the spring will stretch by an amount of 5.4 m. This means that when 54 N of force is applied, the spring will stretch by 5.4 m.
It is important to note that if the spring is stretched past its elastic limit, it will not return to its original length when the force is removed. Therefore, it is important to ensure that the spring is not stretched past its elastic limit when determining how much it will stretch.
In summary, the spring will stretch by an amount equal to 54 N divided by the spring constant, k. If the spring does not reach its elastic limit, then it will stretch an amount equal to the amount of force applied divided by the spring constant. It is important to make sure the spring does not exceed its elastic limit when determining how much it will stretch.

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Answer:Control S, Command S on MAC=Save

In Chapter 2 section 2.21, it is stated that in a cathode ray tube, electrons pass from the cathode to the anode. This is because the cathode is negatively charged, while the anode is positively charged.

The flow of electrons is controlled by an electric field between the cathode and anode, which causes the electrons to move towards the anode. Therefore, the correct answer to the question is option B) electrons pass from the cathode to the anode.

In Chapter 2, Section 2.21, regarding a cathode ray tube, the correct answer is B) electrons pass from the cathode to the anode. The cathode emits electrons, which are attracted to the positively charged anode, resulting in the flow of electrons in the tube.

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Granulation is the visible surface pattern of the sun, consisting of many small cells caused by convective motions. This is evidenced by the fact that the cells are roughly hexagonal, which is the shape expected from convective fluid motions.

Additionally, the cells are seen to rise and fall, consistent with convection currents, and the temperature variations across the cells are also consistent with convective heating and cooling. Finally, models of the sun's interior suggest that granulation is indeed caused by convection driven by heat flow from the core to the surface.

Granulation is a process in which small particles are agglomerated or fused together to form larger particles. The resulting particles, or granules, are more uniform in size and shape than the original particles and have improved flow, packing, and handling properties. Granulation is a common process in many industries, including pharmaceuticals, chemicals, food, and mining.

The process of granulation typically involves three stages: wetting, nucleation, and growth. In the wetting stage, the smaller particles are moistened or coated with a liquid binder, such as water or a solvent. In the nucleation stage, the wetted particles begin to form small aggregates, or nuclei, as the binder dries and the particles come into contact with each other. In the growth stage, the nuclei grow by further aggregation and consolidation, resulting in larger granules.

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Answer:

1) 2,641,895.5 m

2) 1.85903476 × 10⁻⁹ kg

3) 9.32 C

4) 38.7 kg

Explanation:

1) The gravitational force of attraction between the object and the mass of the Earth is given by the following formula;

\(F} =G\dfrac{M_{1} \cdot m_{2}}{R^{2}} = m_2 \times g\)

Where;

M₁ = The mass of the Earth = 5.97 × 10²⁴

m₂ = The mass of the object

G = The universal gravitational constant

R = The radius of the Earth = 6,378,100 m

g = The acceleration due to gravity = 9.8 m/s²

By comparison, we have;

\(\dfrac{G \cdot M_{1}}{R^{2}} = g\)

When the object is r meters away, g is halved, therefore, we have;

\(\dfrac{G \cdot M_{1}}{r^{2}} = \dfrac{g}{2} =\dfrac{G \cdot M_{1}}{\left (2\times R^{2}\right )}\)

Therefore, r² = 2·R² = 2 × (6,378,100 m)² = 8.13603192 × 10¹³ m²

r = √(8.13603192 × 10¹³ m²) = 9019995.52217 m

The distance of the object from the surface of the Earth = 9,019,995.52217 - 6,378,100 = 2,641,895.52217 m ≈ 2,641,895.5 m

The object needs to be approximately 2,641,895.5 m from the Earth's surface to experience half of the acceleration due to gravity experienced on the Earth's surface

2) The electrostatic force between the charges = k×q²/r²

Where;

q = 1.602 × 10⁻¹⁹ C

r = Distance between the charges

k = Coulomb constant = 8.9875517923 × 10⁹ kg·m³·s⁻²·C⁻²

We have;

The electrostatic force between the charges = 8.9875517923 × 10⁹ × (1.602 × 10⁻¹⁹)²/r²

The gravitational force between the charges = 6.67408 × 10⁻¹¹ × m²/r²

Given that the ratio between the two forces = 1, we have;

(8.9875517923 × 10⁹ × (1.602 × 10⁻¹⁹)²/r²)/(6.67408 × 10⁻¹¹ × m²/r²) = 1

∴ m² = (8.9875517923 × 10⁹ × (1.602 × 10⁻¹⁹)²)/(6.67408 × 10⁻¹¹) = 3.4560102×10⁻¹⁸ kg²

The mass m = √(3.4560102×10⁻¹⁸ kg²) = 1.85903476 × 10⁻⁹ kg

The mass of each particle will be 1.85903476 × 10⁻⁹ kg

3)  F = k×q²/r²

q² = F × r²/k

Which gives;

q² = 50 × 125000²/(8.9875517923 × 10⁹) ≈ 86.93 C²

q = √86.93 ≈ 9.32 C

The charges of each object = 9.32 C

4) \(F} =G\dfrac{m^2 }{r^{2}}\)

r = 0.25 cm = 0.0025 m

F = 0.016 N

G = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²

Therefore;

m² = F·r²/G = 0.016 × (0.0025)²/(6.67408 × 10⁻¹¹) ≈ 1498.334 kg²

m = √(1498.334 kg²) ≈ 38.7 kg

The mass of each object = 38.7 kg.

The Coulomb and gravitational laws together with Newton's second law allow to find the results for the questions are:

    1) The distance where the acceleration of gravity measures half its value on earth is;  r’= 2.64 106 m

    2) The mass of the particle is:   m = 1.86 10-9 kg

    3) The charge of the particles is:   q = 9.32 C

    4) The mass is:   m = 38.7 kg

Part 1

The Universal Gravitational Law says that the force between two objects is proportional to their masses and inversely proportional to the square of their distance

     F =\(-G \frac{Mm}{r^2}\)  

Where F is the gravitational force, G the gravitational constant, M and m the mass of the two bodies and r the distance between them.

They ask to calculate the distance to the point where the acceleration is half that of the gravitation acceleration at the earth's surface.

            a = g / 2

If we use Newton's second law that gives the relationship between the net force, the mass and the acceleration of the body.

          F = m a

Let's substitute

        \(-G \frac{Mm}{r^2} = m \frac{g}{2}\)  

         r² = \(\frac{2GM}{g}\)  

Let's calculate

        r² = \(\frac{2 \ 6.67 \ 10^{-11} \ 5.97 \ 10^{24} }{9.8}\)  

        r = \(\sqrt{81.360 \ 10^{12}}\)  

        r = 9.02 10⁶ m

This is the distance from the center of the earth, the distance measured from the surface of the planet is

       r = R + r '

       r ’= r- R

       r ’= 9.02 10⁶ - 6.378 10⁶

       r’= 2.64 10⁶ m

Part 2

Coulomb's law states that the electric force between two charged bodies is:  

      F = \(k \frac{q_1q_2}{r^2}\)

Where q₁ and q₂ are the charges of the leather and k is the Coulomb constant

They ask what mass the particles must have so that the electrostatic force (Fe) and the gravitational force (Fg) have been equal

Indicate the charges of the particles q₁ = q₂ = 1.602 10⁻¹⁹ C

Let's equalize the two forces

     \(F_e = F_g \\k \frac{q_1q_2}{r^2} = G \frac{m_1m_2}{ r^2 } \\k q^2 = G m^2\)

     \(m = \sqrt{\frac{k}{G} } \ q\)  

     m = \(\sqrt{\frac{8.99 \ 10^9 }{ 36.67 \ 10^{-11}} } \ 1.602 \ 10^{-19}\)

     m =  \(\sqrt{1.3478 \ 10^{20} } \ 1.602 \ 10^{-19}\)  

    m = 1.86 10⁻⁹ kg

Part 3

They indicate that the electrostatic force between two objects is F = 50 N and the distance between them is r = 125 km = 125 103 m, they ask what is the charge of the objects.

Let's use Coulomb's law

        F = \(k \frac{q_1q_2}{r^2}\)  

        q² = \(\frac{F}{k} \ r^2\)  

        q² = \(\frac{50 \ (125 \ 10^3)^2 }{8.99 \ 10^9 }\)  

        q = \(\sqrt{86.93}\)  

        q = 9.32 C

Part 4

Indicate the gravitational force between two objects is F_g = -0.016 N when they are separateda distance  r = 0.25 cm = 0.25 10⁺² m, ask the mass of the bodies.

Let's use the law of universal gravitation.

      \(-G \frac{Mm}{r^2} \\m^2 = - \frac{F}{G} \ r^2\)

Let's calculate

      m² = \(- \frac{(-0.016) }{6.67 \ 10^{-11}} \ (0.25 \ 10^{-2})^2\)

     m = \(\sqrt{1498.33}\)  

     m = 38.7 kg

In conclusion using the Coulomb and gravitational laws together with Newton's second law we can find the results for the questions are:

   1) The distance where the acceleration of gravity measures half its value on earth is;  r’= 2.64 106 m

    2) The mass of the particle is:   m = 1.86 10-9 kg

    3) The charge of the particles is:   q = 9.32 C

    4) The mass is:   m = 38.7 kg

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A fish appears closer to the surface of the water than it really is when observed from a riverbank. Refraction is the bending of light as it passes from one medium to another with a different optical density. In the case of the fish appearing closer to the surface of the water, this is an example of refraction because the light rays coming from the fish underwater undergo bending at the air-water interface.

When light passes from water (a denser medium) to air (a less dense medium), it changes its direction due to the difference in optical density. This bending of light causes the fish to appear higher or closer to the surface of the water than its actual position.

The other options mentioned in the question are not examples of refraction:

A parabolic mirror in a headlight focusing light into a beam is an example of reflection and focusing of light using a curved surface.

Light bending slightly around corners is an example of diffraction, not refraction.

In a mirror, when you lift your right arm, the left arm of your image is raised. This is an example of lateral inversion due to reflection, not refraction.

Therefore, the correct example of refraction from the given options is when a fish appears closer to the surface of the water than it really is when observed from a riverbank.

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The current in a 20.0-mH inductor changes with time as

i = 4.00t² − 7.00t,

where i is in amperes and t is in seconds. If the current is 100 mA at t = 0,

Therefore, the current at t = 5.00 ms is 50.0 mA.

Solution:The given formula for the current in the inductor is

i = 4.00t² − 7.00t

The given current i = 100 mA at t = 0

Secondly, we need to find the current at t = 5.00 msi.e.

t = 5.00 × 10⁻³ s

Put this value of t in the equation of current

i = 4.00 × (5.00 × 10⁻³)² − 7.00 × (5.00 × 10⁻³)

i = 100 × [4(5 × 10⁻³)² − 7(5 × 10⁻³)]

i = 100 × [4(25 × 10⁻⁶) − 7(5 × 10⁻³)]

i = 100 × [100 × 5 × 10⁻⁶]

i = 500 × 10⁻⁴

i = 50.0 mA

The current at t = 5.00 ms is 50.0 mA.

Given the formula for the current in the inductor as

i = 4.00t² − 7.00t,

we need to determine the current at t = 5.00 ms, given that the current is 100 mA at t = 0.

To do this, we first need to put the value of t = 5.00 × 10⁻³ s in the equation for the current, which gives

i = 4.00 × (5.00 × 10⁻³)² − 7.00 × (5.00 × 10⁻³).

Simplifying this equation, we get i = 50.0 mA.

Therefore, the current at t = 5.00 ms is 50.0 mA.

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Answer:

116 degrees, 64 degrees

Explanation:

We have two congruent, isosceles forming a parallelogram (imagine flipping one over and joining it to the other)

Opposite angles should then be equal, so if the largest is 116 degrees, then the angle opposite to it is also 116 degrees, and the angle adjacent to it is supplementary, which would be 64 degrees

The tip of the turbine fan blade is moving at approximately 540 meters per second.

The tip of the turbine fan blade in a turbojet engine is moving at a considerable speed. To determine its velocity, we need to consider both the linear and rotational aspects of its motion.

First, let's calculate the linear velocity. The diameter of the turbine fan blade is given as 1.8 meters, which means the radius is half of that, or 0.9 meters. The linear velocity can be determined by multiplying the radius by the rotational velocity.

In this case, the blade rotates at 300 revolutions per second, so the linear velocity is 0.9 meters (radius) multiplied by 300 revolutions per second, resulting in 270 meters per second.

Next, to find the velocity of the blade tip, we need to consider the circumference of the circle traced by the blade tip during each revolution.

The circumference is given by 2π times the radius, which in this case is 2π multiplied by 0.9 meters, equal to approximately 5.65 meters. Multiplying this value by the rotational velocity of 300 revolutions per second gives us a tip velocity of approximately 1695 meters per second.

Therefore, the tip of the turbine fan blade in a turbojet engine is moving at approximately 540 meters per second, considering both its linear and rotational velocities.

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The normal force between the steel spatula and the dry steel frying pan is 0.5 N.

The frictional force between two surfaces can be calculated using the formula Ff = μk × FN, where Ff is the frictional force, μk is the coefficient of kinetic friction, and FN is the normal force. Rearranging the formula to solve for the normal force gives us FN = Ff / μk.

Plugging in the given values for the frictional force and coefficient of kinetic friction, we get:

FN = 0.150 N / 0.3

FN = 0.5 N

Therefore, the normal force between the steel spatula and the dry steel frying pan is 0.5 N.

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The magnetic field at the center of a current-carrying loop is given by the formula: B = (μ₀/4π) * (2I/ r)

where B is the magnetic field at the center of the loop, I is the current in the loop, r is the radius of the loop, and μ₀ is the permeability of free space. In this case, we are given the magnetic field B = 3.00 mT = 3.00 × 10^(-3)  T and the radius r = 0.700 cm = 0.00700 m.Substituting these values into the above formula, we can solve for the current I: I = (B * r * 4π)/ (2 * μ₀)

I = (3.00 × 10^(-3) T * 0.00700 m * 4π)/ (2 * 4π × 10^(-7) T·m/A)

I = 0.0133 A

Therefore, the current in the loop is 0.0133 A (amperes).

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Answer:

-1

Explanation:

count 3 spaces in T and go to the object and it should be at -1. I hope this is correct and helps you!

Answer:

Explanation:

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Rewrite using the commutative property of multiplication.

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Rewrite using the commutative property of multiplication.

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Rewrite using the commutative property of multiplication.

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Answer:

B. protons and neutrons exist inside the atomic nuclei electrons orbit atomic nuclei.

Explanation:

protons are positively charged while neutrons are negatively charged, and electrons orbit the outside like a loner while protons and neutrons get ki-ssy faced inside the nuclei and electrons do have a charge.

Bernoulli's principle states that the pressure of a moving fluid is primarily determined by its velocity.

According to Bernoulli's principle, there is a relationship among pressure, velocity, and elevation within a flowing fluid. When the velocity of a fluid increases, the pressure exerted by the fluid decreases, and vice versa. Essentially, as the speed of the fluid increases, its pressure decreases, and as the speed of the fluid decreases, its pressure increases.

This principle is rooted in the conservation of energy in fluid flow. It suggests that an increase in fluid velocity corresponds to a decrease in pressure energy, whereas a decrease in fluid velocity corresponds to an increase in pressure energy.

In summary, according to Bernoulli's principle, the velocity of a moving fluid is the characteristic that primarily influences its pressure.

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False.

a quantity  having direction as well as magnitude, especially as determining the position of one point in space relative to another.Vectors are quantities that are fully described by magnitude and direction. Not Length!

Answer:

B.) False

Explanation:

Please put my answer as brainlist answer

I hope it helps you

Note that the sentences with the blank spaces are completed as follows;

The periodic table, commonly known as the periodic table of elements, is an arrangement of chemical elements in rows and columns. It is frequently utilized in chemistry, physics, and other disciplines, and is widely regarded as a chemical icon. Because of the arrangement of the elements, it is known as the periodic table.

The periodic table is important because it is arranged to give a wealth of information on elements and their relationships to one another in a single reference.

The table may be used to forecast the characteristics of all elements, even those yet to be found.

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