.
How is 700,000,000 expressed in standard scientific notation?
7.0 × 10^-8

7.0 × 10^+8
IS IT POSITIVE 8 OR NEGATIVE 8?

Answer:

132 degrees.

Step-by-step explanation:

Let the supplement be x and the angle be y.

x + y = 180 degrees.

y = (3x - 12) degrees.

x + 3x - 12 = 180

4x = 192

x = 48 degrees

y = 132 degrees

Hope this helped!

The correct values of a and b to rewrite the expression as (x + a)(x + b) are:

a = 9

b = -8

So, (x + 9)(x - 8) is the correct form of the given expression.

Here, we have to rewrite the expression x² + x - 72 in the form (x + a)(x + b), we need to find two numbers a and b such that when multiplied,

it give us the constant term -72 and when added, it give us the coefficient of the x term, which is 1.

The expression x² + x - 72 can be factored as follows:

x² + x - 72

= x² + 9x - 8x - 72

=x(x+9) -8(x+9)

= (x + 9)(x - 8)

Therefore, the correct values of a and b to rewrite the expression as (x + a)(x + b) are:

a = 9

b = -8

So, (x + 9)(x - 8) is the correct form of the given expression.

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The value of sin X is 5/13.

The value of cos X is 12/13.

The value of cos X is 5/12.

The value of sin M is 12/13.

The value of cos X is 5/13.

The value of cos X is 12/5.

The value of the trig ratios is calculated as follows;

sin X = opposite side / hypothenuse side

sin X = 5/13

cos X = adjacent side / hypothenuse

cos X = 12/13

tan X = opposite side / adjacent side

tan X = 5/12

sin M = 12/13

cos M = 5 / 13

tan M = 12/5

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Answer:

see explanation

Step-by-step explanation:

(a)

the sum to infinity of a geometric progression is

S∞ = \(\frac{a_{1} }{1-r}\) : | r | < 1

where a₁  is the first term and r the common ratio

here a₁ = 20 and r = \(\frac{a_{2} }{a_{1} }\) = \(\frac{16}{20}\) = \(\frac{4}{5}\) = 0.8

S∞ = \(\frac{20}{1-0.8}\) = \(\frac{20}{0.2}\) = 100

(b)

the sum to n terms of an arithmetic progression is

\(S_{n}\) = \(\frac{n}{2}\) [ 2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

here a₁ = 20 , d = a₂ - a₁ = 16 - 20 = - 4 and \(S_{n}\) = - 160

substitute values into formula and solve for n

\(\frac{n}{2}\) [ (2 × 20) - 4(n - 1) ] = - 160 ( multiply both sides by 2 to clear the fraction )

n(40 - 4n + 4) = - 320

n(- 4n + 44) = - 320

- 4n² + 44n = - 320 ( add 320 to both sides )

- 4n² + 44n + 320 = 0 ( divide through by - 4 )

n² - 11n - 80 = 0 ← in standard form

(n - 16)(n + 5) = 0 ← in factored form

equate each factor to zero and solve for n

n - 16 = 0 ⇒ n = 16

n + 5 = 0 ⇒ n = - 5

now n > 0 , then n = 16

there are 16 terms in the arithmetic progression

8 ounces for $1.47. It comes out to $0.07 per ounce compared to $0.12 per ounce.

Answer:Rite aid

Step-by-step explanation:

8 ounces for $1.47. It comes out to $0.07 per ounce compared to $0.12 per ounce.

The capacity of the cylinder with a radius of 2 cm and height of 7 cm is approximately 26.208 cubic centimeters.

The formula for the capacity of a cylinder is:

C = πr^2h

where C is the capacity, r is the radius, and h is the height.

We are told that the capacity varies jointly with the height and the square of the radius, which means that we can write:

C = k r^2 h

where k is the constant of proportionality.

To find k, we can use the given information about the cylinder with a radius of 3.3 cm and height of 6.6 cm:

\(169.56 = k (3.3)^2 (6.6)\)

Simplifying, we get:

k ≈ 0.936

Now we can use this value of k to find the capacity of the cylinder with a radius of 2 cm and height of 7 cm:

\(C = k (2)^2 (7)\)

C ≈ 26.208 cubic centimeters

Therefore, the capacity of the cylinder with a radius of 2 cm and height of 7 cm is approximately 26.208 cubic centimeters.

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Step-by-step explanation:

so, working together, in 1 day 1/10 + 1/15 of the work is done.

how many days (x) until we get 1/1 of the work done ?

x × (1/10 + 1/15) = 1

x × (3/30 + 2/30) = 1

x × 5/30 = 1

x×5 = 30

x = 30/5 = 6

so, together, they will finish the work in 6 days.

Answer:

-1 3/5

Step-by-step explanation:

-4/5 - 4/5= -8/5

-8/5= -1 3/5

you can figure it out by using Google btw

To determine whether the series is convergent or divergent, we can use the comparison test. First, we notice that the denominator of each term in the series is a positive power of n,

which suggests using a comparison with the p-series: \[\sum_{n = 1}^{\infty}{\dfrac{1}{n^p}}\] , where p is a positive constant. This series is convergent if p>1 and divergent if p<=1.

In our given series, the exponent of e is always positive, so each term is greater than or equal to e^0=1. Thus, we can compare our series to the p-series with p=9:

\[\sum_{n = 1}^{\infty}{\dfrac{e^{1/n^{{\color{black}8}}}}{n^{{\color{black}9}}}} \geq \sum_{n = 1}^{\infty}{\dfrac{1}{n^9}}\] , Since the p-series with p=9 is convergent, we can conclude that our given series is also convergent by the comparison test.

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Answer:

(the volume of the hemisphere has no units, so i will suppose that it is 6m^3)

For a sphere of radius R, the volume is:

V = (4/3)*pi*R^3

Where pi = 3.14

And a hemisphere is half of a sphere, then the volume of a hemisphere of radius R is:

V = (1/2)*(4/3)*pi*R^3

We know that the volume of the hemisphere is 6 m^3, then we have the equation:

6 m^3 = (1/2)*(4/3)*3.14*R^3

Now we can solve this for R.

6 m^3 = 2.1*R^3

∛(6 m^3/2.1) = R = 1.41 m

The radius of the hemisphere is 1.41m

Now we want to find the surface of a sphere with this radius (if the radius is the same, then the diameter is the same)

For a sphere of radius R, the surface is:

S = 4*pi*R^2

Then the surface of this sphere is:

S = 4*3.14*(1.41 m)^2 = 24.971 m^2

The sum of the expression 70a and 21b is equivalent to 7(10a + 3b).

Step-by-step explanation:

EquationAn equation is an expression that is used to show the relationship between two or more variables and numbers.Given the expression:7(10a + 3b)Opening the bracket:= 70a + 21bThe sum of the expression 70a and 21b is equivalent to 7(10a + 3b).

The value of y in the triangle is 12

From the question, we have the following parameters that can be used in our computation:

The triangle

On the triangle, we have the following equivalent ratio

y : 18 = 10 : 15

Using the above as a guide, we have the following:

Express ratio as fraction

This gives

y/18 = 10/15

So, we have

y = 18 * 10/15

Evaluate

y = 12

Hence, the value of y is 12

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Answer:

its 26. Just take my word for it

Step-by-step explanation:

14-12=2

26-14=12

40-26=14

You see the pattern. Alexi will score 26 pts. btw, this goes against the laws of probability, but whatever.

Answer:

No

Step-by-step explanation:

No, because one of the x-value is used more than once, this graph is not a function.

If this has helped please mark as brainliest

Answer:

218.57

Step-by-step explanation:

Since it is an isoceles triangle, the sides are 32, 32, and 14.

Using Heron's Formula, which is Area = sqrt(s(s-a)(s-b)(s-c)) when s = a+b+c/2,  we can calculate the area.

(A+B+C)/2  = (32+32+14)/2=39.

A = sqrt(39(39-32)(39-32)(39-14) = sqrt(39(7)(7)(25)) =sqrt(47775)= 218.57.

Hope this helps have a great day :)

Check the picture below.

so let's find the height "h" of the triangle with base of 14.

\(\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=\sqrt{c^2 - a^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{32}\\ a=\stackrel{adjacent}{7}\\ o=\stackrel{opposite}{h} \end{cases} \\\\\\ h=\sqrt{ 32^2 - 7^2}\implies h=\sqrt{ 1024 - 49 } \implies h=\sqrt{ 975 }\implies h=5\sqrt{39} \\\\[-0.35em] ~\dotfill\)

\(\stackrel{\textit{area of the triangle}}{\cfrac{1}{2}(\underset{b}{14})(\underset{h}{5\sqrt{39}})}\implies 35\sqrt{39} ~~ \approx ~~ \text{\LARGE 218.57}\)

Type of Attention Impact on Encoding Process

1. Sustained attention Facilitates thorough encoding of information.

2. Selective attention Enhances encoding of attended stimuli while filtering out irrelevant information.

3. Divided attention Impairs encoding by dividing attentional resources among multiple tasks.

4. Exogenous attention Captures attention involuntarily, potentially interrupting the encoding process.

5. Endogenous attention Voluntarily directed attention that can prioritize specific information for encoding.

1. Sustained attention: Sustained attention refers to the ability to maintain focus over an extended period. It has a positive impact on the encoding process as it allows for thorough and comprehensive encoding of information.

2. Selective attention: Selective attention involves focusing on specific stimuli while filtering out irrelevant information. It enhances the encoding process by directing attention to the relevant stimuli, promoting their effective encoding.

3. Divided attention: Divided attention refers to the attempt to allocate attention to multiple tasks simultaneously. Dividing attention among multiple tasks impairs the encoding process as attentional resources become fragmented, leading to less effective encoding of information.

4. Exogenous attention: Exogenous attention is captured involuntarily by external stimuli, potentially interrupting the encoding process. It can divert attention away from the intended encoding task, resulting in a negative impact on encoding.

5. Endogenous attention: Endogenous attention is voluntarily directed attention that allows individuals to prioritize specific information for encoding. It enhances the encoding process by selectively focusing on relevant stimuli and allocating cognitive resources accordingly.

Different types of attention have varying impacts on the encoding process. Sustained attention and selective attention positively influence encoding, while divided attention and exogenous attention have negative effects. Endogenous attention, on the other hand, can enhance encoding by prioritizing specific information.

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Answer:

Pyramid?

Step-by-step explanation:

Answer:

Pyramid

Step-by-step explanation:

It looks like a triangle that is in 3D so the only thing that looks like a triangle in 3D is a pyramid. It is just tilted.

The earthquake in the ocean was about 15.85 times more intense than the one in the city.

The Richter scale is a logarithmic scale used to measure the intensity of earthquakes. Each increase of one on the Richter scale represents a tenfold increase in the amplitude of the seismic waves. Therefore, to find out how many times more intense the earthquake in the ocean was compared to the one in the city, we need to calculate the difference in their Richter scale readings:

8.1 - 6.9 = 1.2

Since each increase of one on the Richter scale represents a tenfold increase in the amplitude of the seismic waves, a difference of 1.2 on the Richter scale means that the earthquake in the ocean was:

\(10^{(1.2)} = 15.85\)

times more intense than the one in the city.

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If G is not a PRG, then Construction 3.17 cannot be EAV-secure. This shows the contrapositive of Theorem 3.18.

To prove the opposite, we need to show that if G is not a pseudorandom generator (PRG), then Construction 3.17 cannot be EAV-secure (indistinguishable encryptions in the presence of an eavesdropper).

Let's assume that G is not a PRG. This means that there exists some efficient algorithm D that can distinguish the output of G from random strings with non-negligible advantage. We will use this assumption to construct an adversary A that can break the EAV-security of Construction 3.17.

The adversary A works as follows:

1. A receives a security parameter n.

2. A runs the key generation algorithm Gen and obtains the key k.

3. A chooses two distinct messages m0 and m1 of length ℓ(n).

4. A computes the ciphertexts c0 = G(k) ⊕ m0 and c1 = G(k) ⊕ m1.

5. A chooses a random bit b and sends cb to the challenger.

6. The challenger encrypts cb using the encryption algorithm Enc with key k and obtains the ciphertext c*.

7. A receives c* and outputs b' = D(G(k) ⊕ c*).

8. If b = b', A outputs 1; otherwise, it outputs 0.

We analyze the probability that A can distinguish between encryptions of messages m0 and m1. Since G is not a PRG, D has a non-negligible advantage in distinguishing G's output from random strings. Therefore, there exists a non-negligible function negl such that:

|Pr[D(G(k)) = 1] - Pr[D(U) = 1]| ≥ negl(n),

where U denotes a truly random string of length ℓ(n).

Now, consider the probability of A winning the PrivK game:

Pr[PrivK_A,Π

eav

(n) = 1] = Pr[b = b']

           = Pr[D(G(k) ⊕ c*) = D(G(k))]

           = Pr[D(G(k)) = 1]

           ≥ Pr[D(U) = 1] - negl(n).

Since negl(n) is non-negligible, we have:

Pr[PrivK_A,Π

eav

(n) = 1] ≥ 2^(-1) + negl(n).

Thus, if G is not a PRG, then Construction 3.17 cannot be EAV-secure. This shows the contrapositive of Theorem 3.18.

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The length of one edge of the tabletop is 4.89 feet.

We know that square is a shape that has all the side equal. Based on this using the formula to find the length of edge of the tabletop.

The area of square table is given by the formula -

Area of square table = side²

We will keep the value of area of square table to find the value of side which will be length of edge

24 = side²

Side = ✓24

Taking square root for the value on right side of the equation

Side = 4.89

Hence, the length of one edge of the tabletop is 4.89 feet.

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Answer:

35

Step-by-step explanation:

Answer:the answer is 35

Step-by-step explanation:

Answer:

Answer A is correct

Step-by-step explanation:

Mr. Richardson has spend 1/3 of the total investment on stock.

Now let's find how much money he has spend on stock

\(=4500000 * \frac{1}{3}\\=\frac{4500000}{3}\\ =$ 1500000\)

Now let's write this in scientific notation

\(1500000\\=$ 1.5 *10^{6}\)

Hope this helps you

Let me know if you have any other questions :-)

Answer:

12 X=2.2

13. y = 6.4

14. m= 8.5

15. z=9.9

16. n= 18.4

17. X= 5.8

Answer:

n = 3/25

Step-by-step explanation:

5(n-1/10)=1/2

5n = 6/10

n = 3/25

Answer:

Step-by-step explanation:

lets remove the parenthesis

5n- 5/10=1/2

5n=1/2+1/2

5n=1

n=1/5

The value assigned to variable y in the given expression "x = 0; y = (x > 0) ? 10 : -10;" is -10.

In the given expression "x = 0; y = (x > 0) ? 10 : -10;", the variables x and y are being assigned values based on a conditional statement.

First, the value of x is assigned as 0.

The conditional statement (x > 0) checks whether the value of x is greater than 0. In this case, since x is equal to 0, the condition evaluates to false.

The ternary operator ? : is used to specify different values for y based on the outcome of the conditional statement. If the condition is true, the value assigned to y would be 10. On the other hand, if the condition is false, the value assigned to y would be -10.

In this case, since the condition (x > 0) is false, the value assigned to y is -10, as indicated after the colon :.

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There is a circular cross-section with a center at (1, 1) and radius of 1 is rotated about the line y = 1 so it should be a sphere.

If a cylinder is cut along to its circular base, its cross-sectional area is the same as the area of a circle. The area of a two-dimensional shape created when a three-dimensional object, like a cylinder, is cut perpendicular to a predetermined axis at a point is known as the cross-sectional area.

A sphere is a geometrical object that resembles a two-dimensional circle in three dimensions. In three-dimensional space, a sphere is a collection of points that are all located at the same r-distance from a single point. The radius of the sphere is denoted by the letter r, and the specified point represents its center.

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Answer:

sphere

Step-by-step explanation:

i took the quiz

Answer:

The answer is A

Step-by-step explanation:

Fist multiply 3 and .15 to get .45 for 3 pencils. Then subtract .45 from 6.45 and get 6. Then divided 6 by 5 to get 1.2 for each book

i think the answer is a: $1.20

my work:

3 x 0.15 = 0.45.

6.45 - 0.45 = 6.00

6.00 / 5 = 1.20

and i checked my work by doing 1.20 x 5 + 0.40 = $6.45.

Answer: answer below!

Step-by-step explanation:

looo down

Josiah's mistake is (b) He did not multiply the numerator and denominator by the correct number to equal 1,500

The proportion is given as:

Multiply both sides by 1500

Evaluate the expression on the right-hand side

Multiply 10 by 1500 on the left-hand side

Divide 15000 by 20 on the left-hand side

Rewrite the equation as:

From the question, we can see that the products are not well carried out.

Hence, Josiah's mistake is (b)