endothermic equations​

Answer:

maybe 2455.2, good luck

Answer:

Below

Explanation:

a)  From the equation every 2 moles of (CuNo3)2 results in ONE mole of O2

   starting with 5 moles you would get  2 1/2 moles of O2

       each mole of O2 weighs ( 2 * 15.99) = 31.98 g ( from periodic table)

              2 1/2 of these would weigh   79.95 g

b)   each mole of Cu(NO3)2 produces the same number of moles of Cu O

       how many moles of Cu (NO3)2  are in 87.49 g

     again from periodic table   Cu = 63.546 gm N = 14.007  O=15.999

         total mole weight of Cu(No3)2 would then be 187.554 g

                  87.49 g / 187.554 g / mole = .466 moles  the same amount of Cu O

c)    Want to try this one yourself?

Answer:

Bones, teeth, shells, and other hard body parts can be fairly easily preserved as fossils. However, they might become broken, worn, or even dissolved before they are buried by sediment. The soft bodies of organisms, on the other hand, are relatively hard to preserve.

As per the given details, Metal D is extracted from its oxide by reduction with hydrogen, and Metal E is removed from the earth as the metal itself.

Based on the provided information, we can match the metals to the methods used to extract them as follows:

Sodium - Extracted by electrolysis of a molten ionic compound.

Magnesium - Extracted from its oxide by reduction with carbon.

Carbon - Not a metal, so it doesn't apply in this context.

Metal E - Extracted from its oxide by reduction with hydrogen.

Iron - Removed from earth as metal itself.

Hydrogen - Not a metal, so it doesn't apply in this context.

Copper - Not a metal D or E, so it doesn't apply in this context.

Matching the metals to the extraction methods:

Sodium - extracted by electrolysis of a molten ionic compound.

Magnesium - extracted from its oxide by reduction with carbon.

Metal D - extracted from its oxide by reduction with hydrogen.

Metal E - removed from earth as metal itself.

Iron - removed from earth as metal itself.

Therefore, Metal D is extracted from its oxide by reduction with hydrogen, and Metal E is removed from the earth as the metal itself.

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Answer:

623 kgm^-3

Explanation:

Density = Mass/Volume

Mass = 1209 kg

Volume = 1.94 m^3

Density = 1209 / 1.94 kgm^-3

             = 623.1958763 kgm^-3

             = 623 kgm^-3 (3sf)

Considering the Hess's Law, the enthalpy change for the reaction is 221.8 kJ/mol.

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

In this case you want to calculate the enthalpy change of:

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g)

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: H₂ (g) + F₂ (g) → 2 HF (g)     ∆H° = -79.2 kJ/mol

Equation 2: C (s) + 2 F₂ (g) → CF₄ (g)     ∆H° = 141.3 kJ/mol

Equation 3: 2 C(s) + 2 H₂ (g) → C₂H₄ (g)     ∆H° = -97.6 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

First, to obtain the enthalpy of the desired chemical reaction you need one mole of C₂H₄ (g) on reactant side and it is present in first equation. Since this equation has one mole of C₂H₄ (g) on the product side, it is necessary to locate it on the reactant side (invert it).

When an equation is inverted, the sign of ΔH° also changes.

Now, you need 2 moles of CF₄ (g) on the product side. The second equation has 1 mole of CF₄ (g) on the product side, so it is necessary to multiply it by 2 to obtain 2 moles of CF₄ (g).

Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 2, the variation of enthalpy also.

Finally, you need 4 moles of  HF (g) on the product side. The first equation has 2 moles of  HF (g) on the product side, so it is necessary to multiply it by 2 to obtain 4 moles of the compound.

Since the equation is multiply by 2, the variation of enthalpy also is multiplied by 2.

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1: 2 H₂ (g) + 2 F₂ (g) → 4 HF (g)     ∆H° = -158.4 kJ/mol

Equation 2: 2 C (s) + 4 F₂ (g) → 2 CF₄ (g)     ∆H° = 282.6 kJ/mol

Equation 3: C₂H₄ (g) → 2 C(s) + 2 H₂ (g)     ∆H° = 97.6 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g)     ΔH°= 221.8 kJ/mol

Finally, the enthalpy change for the reaction is 221.8 kJ/mol.

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We would expect to measure a pressure of approximately 75.25 kPa for the gas in the container at the higher temperature of 267 oC.

To determine the expected pressure of the gas in the container at the higher temperature, we can use the combined gas law, which relates the initial and final conditions of temperature and pressure in a fixed volume system. The combined gas law equation is given as:

(P1 * V1) / T1 = (P2 * V2) / T2

Where:

P1 = Initial pressure

V1 = Initial volume (which is fixed in this case)

T1 = Initial temperature

P2 = Final pressure (to be determined)

V2 = Final volume (which is fixed in this case)

T2 = Final temperature

In this scenario, the initial conditions are given as 3 oC (which is equivalent to 276 K) and 38.5 kPa. The final temperature is 267 oC (which is equivalent to 540 K). Since the volume is fixed, we can substitute the given values into the equation:

(38.5 kPa * V1) / 276 K = (P2 * V1) / 540 K

Simplifying the equation, we can cancel out V1:

38.5 / 276 = P2 / 540

Solving for P2:

P2 = (38.5 / 276) * 540 ≈ 75.25 kPa

Therefore, we would expect to measure a pressure of approximately 75.25 kPa for the gas in the container at the higher temperature of 267 oC.

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Answer: The molar mass is the mass of a given chemical element or chemical compound (g) divided by the amount of substance (mol).

Explanation: The molar mass of a compound can be calculated by adding the standard atomic masses (in g/mol) of the constituent atoms.

The boiling point of water is 100.0 °C, the boiling point of the solution will be : 101.49 °C.The correct answer is option (a) 100.00049 °C.

Ideal Solution : An ideal solution is a homogeneous mixture of two or more components that obeys Raoult's law, which states that each component's vapor pressure is proportional to its mole fraction.The boiling point of a solution depends on the solvent's properties and the solute's concentration. It's dependent on the mole fraction of the solvent and solute, as well as the total concentration of the solution. The change in boiling point of a solution is given byΔTb = Kb × m × i, whereKb = ebullioscopic constant, m molarity of the solution, and i = van't Hoff factor.Assuming that the solution's behavior is ideal, we may use the molality of the solution to compute the boiling point elevation of the solution.The molality of the solution is given by the following formula:m = (n₂ / m₂) ÷ (n₁ / m₁), where n is the number of moles, m is the mass, and the subscripts 1 and 2 refer to water and non-volatile solute sucrose, respectively.The molar mass of sucrose (C₁₂H₂₂O₁₁) is342.3 g/mol; therefore, the number of moles of sucrose is115.0 g ÷ 342.3 g/mol = 0.335 mol.m₁ = mass of water = 350.0 g, and m₂ = mass of sucrose = 115.0 g, as given in the problem.Therefore, the molality of the solution is given by:m = (0.335 mol / 0.115 kg) ÷ (1 mol / 1 kg) = 2.91 mol/kg.Substituting these values in the formula for ΔTb, we get:ΔTb = Kb × m = 0.512 °C m⁻¹ × 2.91 mol/kg = 1.49 °C.100.0 °C + 1.49 °C = 101.49 °C.

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Answer: During diffusion, molecules flow down their concentration gradient.

Explanation:

They're flowing from an area of high concentration to an area of low concentration. Molecules flowing down a concentration gradient is a natural process and does not require energy.

Answer:

Glass blower

Explanation:

it's the best instrument

Answer:

28 g/mol, N2

Explanation:

Given data:

Volume of gas = 5.0 L

Mass of gas = 6.3 g

Pressure = 1 atm

Temperature = 273 K

Molar mass of gas = ?

Solution:

We will calculate the density first.

d = mass/ volume

d = 6.3 g/ 5.0 L

d = 1.26 g/L

Molar mass:

d = PM/RT

M = dRT/P

M =  1.26 g/L× 0.0821 atm.L/mol.K × 273 K/ 1 atm

M = 28 g/mol

Molar mass of N₂ is 28 g/mol thus given gas is N₂.

Answer:

The molar mass of a gas can be calculated by dividing the density of the gas by its molar density at STP, which is 0.08206 g/L. Therefore, the molar mass of the gas is 3.786 g/L / 0.08206 g/L = 46.3 g/mol.

The most likely noble gas with a molar mass of 46.3 g/mol is Xenon (Xe), which has a molar mass of 131 g/mol.

Explanation:

The observation of a smaller outside hole than inside leads Becca to infer that an impact from the outside caused the hole, with a larger object striking and passing through the window from the inside.

From the observation that the hole in the window is smaller on the outside than on the inside, Becca, as a forensic technician, might deduce the following:

The hole was caused by an impact from the outside: The smaller outside hole suggests that the force that created the hole originated from the outside and exerted more pressure on the window surface facing inward.

The object causing the hole was larger on the inside: The discrepancy in hole sizes implies that the object that struck the window had a larger size or diameter on the inside, and as it penetrated the glass, it compressed or fragmented the glass, resulting in a larger hole on the inside.

The object may have passed through the window: The difference in hole sizes indicates that the object may have penetrated the window, potentially passing through to the inside. This could suggest a break-in or an incident involving the window being struck from the outside.

Overall, the observation of a smaller outside hole than inside leads Becca to infer that an impact from the outside caused the hole, with a larger object striking and passing through the window from the inside.

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Answer:

they are all Radioactive

The given reaction has ΔG value  -12207KJ. Therefore, the given reaction is a spontaneous reaction as value of ΔG is negative.

A spontaneous process refers to anything that happens by itself, without external energy input. A ball is going to roll down an incline, water will flow downhill, ice will melt into water, radioactive elements will decay, and iron will rust, for instance. It is impossible for a reaction to not be spontaneous if it is exothermic (H negative) and increases the entropy for the system (S positive). The system's overall heat capacity is measured in enthalpy. The system's unpredictability is gauged by entropy.

ΔG=ΔH-T×ΔS

ΔG=11-298×41

     = -12207KJ

Since ΔG is negative, reaction is spontaneous

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NaClO₃ ⇒ NaCl + O₂ ⇒ unbalanced

1. O : left 3, right 2

give coefficient left 2, right 3

2NaClO₃ ⇒ NaCl + 3O₂

2. Na and Cl : left 2, right 1

give coefficient right 2

2NaClO₃ ⇒ 2NaCl + 3O₂ ⇒ balanced

Answer:

B. because if it was to change so would the amount of wieght that gravity puts on us.

Explanation:

A. might seem right but it's not 35,000 under seal level is the OPPOSITE of 35,000 above sea level.

C. water pressure can change where you are at because of the speed or the type of body of water.

D. it does not make any sense.

hope this helps!!!

Answer:

62 picometer/millisecond

Explanation:

You multiply the speed value by 1

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The molality of the magnesium chloride solution dissolved in 500g of water is 1m.

Molality is the concentration of a substance in solution, expressed as the number of moles of solute per kilogram of solvent.

The molality of a solution can be calculated by dividing the number of moles of solute by the mass (in kilograms) of solvent as follows:

molality = no. of moles/mass

According to this question, 48 grams of MgCl2 dissolved in 500g of water. 48 grams of magnesium chloride is equivalent to 0.5041 moles. 500 g of water is equal to 0.5kg.

molality = 0.5041 mol / 0.5kg

molality = 1m

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Answer:

B. Conjugated diene

Explanation:

Answer:

it is 1e-0

Explanation:

The alkyl halide that would give the highest yield of the elimination product when treated with sodium ethoxide in ethanol is (B)tertiary butyl bromide.

This is because tertiary alkyl halides are more reactive than primary or secondary alkyl halides in elimination reactions.

In an elimination reaction, the alkyl halide is treated with a strong base, such as sodium ethoxide, to remove a proton and a halogen atom, forming an alkene. The reactivity of the alkyl halide is determined by the stability of the intermediate carbocation that is formed during the reaction.

Tertiary carbocations are more stable than primary or secondary carbocations, so tertiary alkyl halides are more reactive in elimination reactions.

Therefore, the tertiary butyl bromide would give the highest yield of the elimination product when treated with sodium ethoxide in ethanol.

Answer: (B)tertiary butyl bromide.

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Answer:

B

Explanation:

The percentage left is 57%.

We know that a fraction is a part of a whole. Let us in this case take the whole as one and then the fraction that we remove out of it is 3/7. We now have to find the percentage that remains.

Thus'

Fraction that remains = 1 - 3/7 = 4/7

Hence;

Percentage that is left = 4/7 * 100

= 57%

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The given reaction releases 906 kJ of heat energy when 4 moles of ammonia react.

So, the amount of heat energy released when 1 mole of ammonia reacts is:

906 kJ ÷ 4 mol = 226.5 kJ/mol

To produce 453 kJ of heat energy, we can use the following proportion:

226.5 kJ/mol = 453 kJ/x

where x is the number of moles of ammonia required.

Solving for x, we get:

x = (453 kJ × 4 mol) ÷ 906 kJ

x ≈ 2 mol

Therefore, 2 moles of ammonia must react to produce 453 kJ of heat energy.

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The given reaction releases 906 kJ of heat energy when 4 moles of ammonia react.

So, the amount of heat energy released when 1 mole of ammonia reacts is:

906 kJ ÷ 4 mol = 226.5 kJ/mol

To produce 453 kJ of heat energy, we can use the following proportion:

226.5 kJ/mol = 453 kJ/x

where x is the number of moles of ammonia required.

Solving for x, we get:

x = (453 kJ × 4 mol) ÷ 906 kJ

x ≈ 2 mol

Therefore, 2 moles of ammonia must react to produce 453 kJ of heat energy.

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Answer:

rigidity ,if the substance easily not changing it's state by giving heat then it shows strong force of attraction