16) 100- 273= -173°celsius
17) -73°Celsius
18) °Celsius
19) 77°Celsius
distanced travelled by the solvent front = 8cm
and
distance travelled by BLUE is 6cm
distance travelled by PINK is 5cm
distance travelled by orange is 4cm
The chromatography experiment, the solvent front traveled a distance of 8cm, while the blue, pink, and orange substances traveled distances of 6cm, 5cm, and 4cm.
In a chromatography experiment, the distance traveled by the solvent front refers to the distance the solvent traveled from the starting point on the chromatography paper. In this particular case, the solvent front traveled a distance of 8cm.
During the experiment, different components or substances were separated based on their affinity for the stationary phase and the mobile phase. The substances of interest in this scenario are represented by blue, pink, and orange.
The blue substance traveled a distance of 6cm from the starting point, indicating that it had a moderate affinity for the mobile phase. The pink substance traveled a distance of 5cm, suggesting that it had a slightly lower affinity for the mobile phase compared to the blue substance. Lastly, the orange substance traveled a distance of 4cm, indicating that it had the lowest affinity for the mobile phase among the three substances.
These distances traveled by the substances provide valuable information about their relative polarities or molecular interactions with the mobile and stationary phases. By analyzing the relative distances traveled by the substances compared to the solvent front, researchers can gain insights into the chemical properties of the separated components.
In conclusion, in this chromatography experiment, the solvent front traveled a distance of 8cm, while the blue, pink, and orange substances traveled distances of 6cm, 5cm, and 4cm, respectively, indicating their varying affinities for the mobile phase.
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Which type of weathering occurred to form the Malham Pavement
Answer:
carbonation
Explanation:Please dont delete my answer again cause its correct, I had the same question on my test so I know its righ!!!!
What are some true statements about light
Answer:It allows us to see things so we know where we are going that’s why at night we had lamp posts
Explanation:
calculate the vapor pressure (in torr) at 333 k in a solution prepared by dissolving 39.5 g of the non-volatile non-electrolye sucrose in 104 g of water. the vapor pressure of water at 333 k is 149.44 torr.
The vapor pressure (in torr) at 333 k in a solution prepared by dissolving 39.5 g of the non-volatile non-electrolyte sucrose in 104 g of water is 134.047 torr.
Moles of urea taken = Mass/MW = 39.5/60 = 0.658
Moles of water = 104/18 = 5.77
Mole fraction of water, x = 5.77/(5.77+0.658) = 0.897
According to Raoult's law, a solvent's partial vapour pressure in a solution (or mixture) is equal to or the same as the pure solvent's vapour pressure times the mole fraction present in the solution. Raoult's law of partial pressures for a non-volatile solute, we have:
Psolution = Χsolvent x P0solvent
Where,
Psolution = vapour pressure of the solution
Χsolvent = mole fraction of the solvent
P0solvent = vapour pressure of the pure solvent
So, P = P^0 * x = 149.44*0.897 = 134.047 torr
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Tritium (hydrogen-3) has a half-life of 12.3 years. How old is a bottle of wine if the tritium content is determined to be 25% in new bottle of wine
Answer:
24.6 years
Explanation:
Applying,
A = (A')\(2^{a/n}\)..................... Equation 1
Where A = Original Tritium content in the wine, A' = Tritium content in the wine after decay, a = age of the old bottle, n = half life of Tritium
From the question,
Let A = X, therefore, A' = 0.25X
Given: n = 12.3 years
Substitute these values into equation 1
X = 0.25X(\(2^{a/n}\))
1 = 0.25×(\(2^{a/12.3}\))
1/0.25 =
4 = \(2^{a/12.3}\)
\(2^{a/12.3}\) = 2²
Equation the base,
a/12.3 = 2
a = 12.3×2
a = 24.6 years
Suppose that 75mL of 4. 25 M iron (III) chloride is combined with 81mL of 3. 50 M calcium chloride. What is the concentration of Cl- ion in the resulting solution?
The concentration of Cl- ion in the resulting solution is 6.12 M.
This can be calculated by finding the moles of Cl- ion in each solution, adding them together, and dividing by the total volume of the combined solutions. To find the moles of Cl- ion in the iron (III) chloride solution, we can use the formula: moles = concentration x volume. Thus, moles of Cl- ion = 4.25 M x 0.075 L = 0.31875 moles. Similarly, for the calcium chloride solution, we have moles of Cl- ion = 3.50 M x 0.081 L = 0.2835 moles.
Adding these two moles together gives a total of 0.60225 moles of Cl- ion in the combined solution. Dividing this by the total volume of the combined solutions (75 mL + 81 mL = 156 mL = 0.156 L) gives a concentration of 6.12 M. Therefore, the resulting solution has a Cl- ion concentration of 6.12 M, which is higher than the individual concentrations of the original solutions. This is because the two solutions have been mixed together, leading to an increase in the total number of Cl- ions in the resulting solution.
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what is the temperature of gas and volume of gas
Explanation:
500 degree Celsius because we can see it in the tube
Please help How many moles of a gas sample are in 5.0 L container at 215 K and 342 kPa(The gas constant is 8.31 L kPa/mol K) Round your answer to one decimal place and enter the number only with no units.
Answer
1.0 mol
Explanation
Given:
Volume, V = 5.0 L
Temperature, T = 215 K
Pressure, P = 342 kPa
The gas constant, R = 8.31 L kPa/mol K
What to find:
The number of moles of the gas sample.
Step-step-solution:
The number of moles of the gas can be determine using the ideal gas equation formula:
\(PV=nRT\)Put the given values into the formula and calculate for n:
\(\begin{gathered} 342\times5.0=n\times8.31\times215 \\ 1710=1786.65n \\ \text{Divide both sides by 1786.65} \\ \frac{1710}{1786.65}=\frac{1786.65n}{1786.65} \\ n=0.9571\text{ mol} \\ To\text{ one decimal place,} \\ n=1.0\text{ mol} \end{gathered}\)The number of moles of the gas sample is 1.0 mol.
Which represents the correct order of cell organization after cellular differentiation (simple to complex)?
A) organ system→organ→tissue→cell
B) cell→organ→organ system→tissue
C) tissue→cell→organ→organ system
D) cell→tissue→organ→organ system
What type of organism would recycle a dead tree in the forest?
A) decomposer
B) omnivore
C) producer
D) scavenger
Order these compounds in order of decreasing carbon–carbon bond length: HCCH, H2CCH2, H3CCH3.
The compounds ordered in decreasing carbon-carbon bond length are: H3CCH3 > H2CCH2 > HCCH.
The carbon-carbon bond length is influenced by the hybridization of the carbon atoms and the presence of multiple bonds.
In H3CCH3 (ethane), all carbon atoms are sp3 hybridized, and there are only single bonds between them. The carbon-carbon bond length in ethane is relatively long due to the larger size of sp3 hybrid orbitals. Therefore, H3CCH3 has the longest carbon-carbon bond length among the given compounds.
In H2CCH2 (ethylene), the central carbon atom is sp2 hybridized, and there is a double bond between the carbon atoms. The presence of the double bond results in a shorter carbon-carbon bond length compared to ethane.
In HCCH (acetylene), both carbon atoms are sp hybridized, and there is a triple bond between them. The triple bond contains two pi bonds, which are stronger and shorter than a single or double bond. Therefore, HCCH has the shortest carbon-carbon bond length among the given compounds.
In decreasing order of carbon-carbon bond length, the compounds are arranged as follows: H3CCH3 > H2CCH2 > HCCH.
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a 185.0 ml 185.0 ml solution of 2.320 m 2.320 m strontium nitrate is mixed with 210.0 ml 210.0 ml of a 2.742 m 2.742 m sodium fluoride solution. calculate the mass of the resulting strontium fluoride precipitate. mass: g g assuming complete precipitation, calculate the final concentration of each ion. if the ion is no longer in solution, enter a 0 for the concentration.
The final concentrations of strontium ion, sodium ion, and fluoride ion (which has precipitated as strontium fluoride) are 1.087 M, 2.914 M, and 0 M, respectively.
The balanced chemical equation for the precipitation reaction is:
Sr(NO3)2 + 2 NaF → SrF2 + 2 NaNO3
moles of strontium nitrate = concentration x volume = 2.320 mol/L x 0.1850 L = 0.4292 mol
moles of sodium fluoride = concentration x volume = 2.742 mol/L x 0.2100 L = 0.5752 mol
moles of strontium fluoride = 0.4292 mol x (1 mol SrF2 / 1 mol Sr(NO3)2) = 0.4292 mol
mass of strontium fluoride = moles of strontium fluoride x molar mass = 0.4292 mol x 125.62 g/mol = 53.68 g
total volume = 185.0 mL + 210.0 mL = 395.0 mL = 0.3950 L
concentration of strontium ion = moles of strontium ion / total volume = 0.4292 mol / 0.3950 L = 1.087 M
Moles of sodium ion = 2 x moles of sodium fluoride = 2 x 0.5752 mol = 1.1504 mol
concentration of sodium ion = moles of sodium ion / total volume = 1.1504 mol / 0.3950 L = 2.914 M
Concentration refers to the amount of a solute dissolved in a given amount of solvent or solution. It is usually expressed in units of molarity (moles per liter) or weight per volume (grams per liter). There are various methods for measuring concentration, including titration, spectrophotometry, and gravimetry. These methods allow chemists to accurately determine the amount of solute in a solution and adjust the concentration as needed.
Concentration plays a crucial role in many chemical reactions and processes. It can affect the rate of a reaction, the yield of a product, and the properties of a solution. For example, a higher concentration of reactants can increase the rate of a reaction, while a higher concentration of a solute can increase the boiling or melting point of a solution.
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you prepare a solution by dissolving cacl2 in water to make a 3.0m solution. what is the osmolarity of the solution
The osmolarity of a 3M solution of CaCl2 is: 3x3 = 9 osmol/L.
The osmolarity of solutions containing a single type of solute (for example: just glucose or just sodium chloride) can be calculated from the following equation:
osmolarity = molarity x n x f
n: number of particles that dissociated from the solute molecule.
f: osmotic coefficient of the solute
The osmolarity of solutions containing many different type of solutes (for example: glucose and sodium chloride) can be calculated from the following equation:
osmolarity = SUM OF ALL (molarity x n x f) OF EACH SOLUTE
n: number of particles that dissociated from the solute molecule.
f: osmotic coefficient of the solute
Value of the osmotic coefficient depend on the concentration of the solute and its chemical properties. The osmotic coefficient may be smaller or greater than one. It is smaller than one for electrolytes and for all solutes it approaches one as the solution becomes more and more dilute .
The osmolarity of a 2M solution of NaCl is: 2x2 = 4 osmol/L;
the osmolarity of a 3M solution of CaCl2 is: 3x3 = 9 osmol/L.
This equation can be also used to calculate the osmolarity of solutions whose solutes that do not dissociate such as glucose, urea, glycerol Their osmolarity equals their molarity because n=1.
The osmolarity of a 4M solution of glucose is 4x1 = 4 osmol/L.
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Cream of tartar creates a white-purple flame when burned. What can you hypothesize is a component of the cream
Potassium can be a component of the cream.
Why does potassium show white-purple flame when burned?An element's presence can be determined using a flame test. The potassium in cream of tartar is what gives it its white-purple color.
Low ionization enthalpy elements allow the flame to display color. Due to low ionization enthalpy, when an element is heated, its valence electrons are quickly excited to higher orbits and emit light as they return to their original orbit. Salts of potassium emit a white-purple color when ignited. The cream of tartar's chemical formula is KC₄H₅O₆.
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one third of the united states carbon consumption is used to operate what
Answer:
The carbon returns to the atmosphere as carbon dioxide. Cars, factories, and power plants rely on these fossil fuels to operate. In the year 2000, vehicles were the source of one-third of all carbon dioxide emitted in the United States.
Explanation:
Help please! I will mark as Brainliest!
Which Element is a member of the Alkali Metal Family?
O Helium (He)
O Oxygen (0)
O Sodium (Na)
O Chlorine (CI)
Answer:
the answer is Sodium (Na)
Which of the following equations represents the law of conservation of mass?
A-2H + 2O -->2H2O
B-2H2O -->2H2 + O2
C-H2O -->H2 + O2
D-H2 + O2 -->H2O + H2O2
Equations represents the law of conservation of mass is 2H₂O → 2H₂ + O₂
Law of conservation of mass stated that energy neither be created nor destroyed called as law of conservation of mass and as the same no of each atom present in the both side of the reaction this reaction represents the law of conservation of mass so in the equation 2H₂O → 2H₂ + O₂ the energy cannot be created nor destroyed water can form 2 mole of hydrogen and 1 mole of oxygen which form water
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If the theoretical yield of a reaction was calculated to be 42.6 grams and when the
experiment was conducted the amount produced was 20.7 grams, the what is the percent
yield of the experiment?
Answer:
48.59%
Explanation:
theoretical yield = 42.6g
actual yield = 20.7g
% yield = 20.7/42.6 x 100 = 48.59% (2 d.p.)
if the equilibrium constant is 4.9 × 10−6 at 298 k, what is the value at 373 k?
Equilibrium constant is a measure of the extent of a chemical reaction.
It is a ratio of the concentrations of products to reactants at a particular temperature and pressure, with each concentration raised to the power of its stoichiometric coefficient. The value of the equilibrium constant is dependent on temperature. As the temperature changes, the equilibrium shifts, and so does the value of the equilibrium constant.
In this case, the given equilibrium constant at 298 K is 4.9 × 10−6. To determine the value of the equilibrium constant at 373 K, we need to use the Van't Hoff equation, which relates the equilibrium constant at different temperatures:
ln(K2/K1) = ΔH/R [(1/T1) - (1/T2)]
where K1 is the equilibrium constant at the initial temperature (298 K), K2 is the equilibrium constant at the final temperature (373 K), ΔH is the enthalpy change of the reaction, R is the gas constant, T1 is the initial temperature, and T2 is the final temperature.
Assuming that the enthalpy change of the reaction is constant over the temperature range, we can solve for K2:
ln(K2/4.9 × 10−6) = ΔH/R [(1/298 K) - (1/373 K)]
K2 = 2.14 × 10−5
Therefore, the value of the equilibrium constant at 373 K is 2.14 × 10−5. As the temperature increased, the equilibrium shifted towards the products, resulting in a higher value of the equilibrium constant.
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For each hydrogen ion concentration listed, calculate the solution as the concentration of hydroxide ion in the solution. Indicate whether each solution is acidic or basic.
(a) [H+] = 4.79*10^-8 M
? M
acidic
basic
neutral
(b) [H+] = 8.90*10^-3 M
?M
acidic
basic
neutral
(c) [H+] = 6.97*10^-5 M
?M
acidic
basic
neutral
(d) [H+] = 1.28*10^-12 M
? M
acidic
basic
neutral
Answer:
basic neural acid neural acid basic
What is the change from a gas to a liquid called? What kind of change is this?
A sample of iron has the dimensions of 2 cm x 3 cm x 2 cm. If the mass of this
rectangular-shaped object is 94 g, what is the density of iron?
Answer: Volume iron = 2 x 3 x 2 => 12 cm³
Mass = 94 g
D = m / V
D = 94 / 12
D = 7.833 g/cm³
Explanation:
what are the 9 properties of minerals and explain each property?
Answer:
hardness-Hardness is the ability of a material to resist deformation
luster-the way light interacts with the surface of a crystal
color-the quality of an object or substance with respect to light reflected by the object
streak- the color of the powder produced when it is dragged across an un-weathered surface.
specif gravity-the density of that object divided by the density of water cleavage -the tendency of a mineral to break along smooth planes
fracture-any separation in a geologic formation
tenacity-refers to a mineral's toughness or resistance to breaking or being deformed.
lol sorry that took awhile
Bonds are securities that can be readily bought and sold. A bond issue consists of a number of bonds, usually in denominations of:_______
A bond issue consists of a number of bonds, usually in denominations of $1,000 and $5,000.
What are bonds and securities?The term bond refers to a sort of investment in which an individual loans money to the government or sometimes to the government in return for an interest on the investment. This interest is paid to the individual regularly as a return on his/ her investment.
Hence a bond issue consists of a number of bonds, usually in denominations of $1,000 and $5,000.
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Missing parts;
Bonds are securities that can be readily bought and sold. A bond issue consists of a number of bonds, usually in denominations of ______ or _____ and is sold to many different lenders.
Multiple choice question.
$100; $1,000
$1,000; $10,000
$500; $5,000
$1,000; $5,000
What is the wavelength of a 2.99 Hz wave?
Explanation:
wavelength=speed of light/frequency
=(3×10^8)/2.99
=1.0033 × 10^8
The wavelength of the wave is equal to 1 × 10⁸ m.
What are frequency and wavelength?The frequency of the wave can be described as the number of oscillations of a wave in one second. The frequency has S.I. units which can be represented as per second or hertz.
The wavelength of the wave can be defined as the distance between the two adjacent points in phase w.r.t. each other. Two crests or troughs on a wave are separated by a distance known as wavelength.
The relationship between wavelength (λ) , frequency (ν), and speed of light (c) is:
c = νλ
Given, the frequency of the wave, ν = 2.99 s⁻¹
The speed of the wave is equal to the speed of light, c = 3 × 10⁸ m/s
The wavelength of the waves can determine from the above-mentioned relationship:
The wavelength of the given wave will be equal to:
λ = c/ν = 3×10⁸/2.99 = 1 × 10⁸ m.
Therefore, the wavelength of the wave is equal to 1 × 10⁸ m.
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What is the molar concentration a a 12 % sodium chloride solution (MW 58.5)
The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.
To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.
First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.
In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.
To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.
We can start by calculating the number of moles of sodium chloride in 12 grams:
Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride
Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles
Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:
Volume of solution = mass of solution / density
Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L
Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:
Molar concentration = moles of solute / volume of solution
Molar concentration = 0.205 moles / 0.1 L = 2.05 M
Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.
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4. How many moles of KBr are found in 3 Liters of 0.4 M solution?
A.7.1moles
B. 43.9moles
C. 2.6moles
D 1.2 moles
There are 1.2 moles of KBr found in 3 Liters of 0.4 M solution.
HOW TO CALCULATE NUMBER OF MOLES?The number of moles of a substance can be calculated by multiplying the molarity by the volume.
No. of moles = Molarity × volume
According to this question, 3L of a KBr solution are contained in a 0.4M.
no. of moles = 3L × 0.4M = 1.2moles
Therefore, there are 1.2 moles of KBr found in 3 Liters of 0.4 M solution.
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Prototypes are used to
a. communicate a solution.
b. test the operation of a product.
c. identify a need.
d research a problem.
Answer:
Test the operation of the product
Explanation:
6. What is the optimum pH range for blood? What happens if the blood pH is outside this range? (C 3 marks) 7. What are the 3 mechanism that control body pH? (K/U 3 marks) 8. How does blood control pH?
The optimum pH range for blood is approximately 7.35 to 7.45. Deviations from this range can have serious consequences on physiological processes. The body employs three mechanisms to control pH: buffers, respiratory regulation, and renal regulation. Blood plays a crucial role in maintaining pH homeostasis by utilizing these mechanisms.
The optimum pH range for blood is tightly regulated between 7.35 and 7.45. If the blood pH deviates from this range, it can disrupt normal physiological processes. For example, if the blood becomes too acidic (pH below 7.35), a condition called acidosis occurs.
Acidosis can lead to impaired enzyme function, decreased oxygen delivery to tissues, and disruption of the central nervous system. On the other hand, if the blood becomes too alkaline (pH above 7.45), a condition called alkalosis occurs. Alkalosis can result in muscle twitching, confusion, and even seizures.
To maintain the pH within the optimal range, the body employs three primary mechanisms: buffers, respiratory regulation, and renal regulation. Buffers are chemical substances that can accept or donate hydrogen ions to resist changes in pH. They can bind excess hydrogen ions when blood becomes acidic or release hydrogen ions when blood becomes alkaline.
The respiratory system regulates pH by adjusting the levels of carbon dioxide (\(CO_{2}\)) in the blood through changes in breathing rate and depth. By altering the amount of \(CO_{2}\), the body can regulate the concentration of carbonic acid (\(H_{2}\)\(CO_{3}\)) and thus control pH. The kidneys play a crucial role in long-term pH regulation by selectively reabsorbing or excreting bicarbonate ions (\(HCO_{3}\)-) and hydrogen ions (H+) in the urine.
Hence, the optimum pH range for blood is approximately 7.35 to 7.45. Deviations from this range can lead to acidosis or alkalosis, disrupting physiological processes. The body controls pH through buffers, respiratory regulation, and renal regulation. Buffers resist pH changes, the respiratory system regulates \(CO_{2}\) levels to control carbonic acid concentration, and the kidneys selectively reabsorb or excrete bicarbonate and hydrogen ions to maintain pH homeostasis.
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A sample of 250 g of water are heated from 40°C to 121°C, calculate the amount of heat energy absorbed.
552,000 Joules
100,416 Joules
638, 555 Joules
73,885 Joules
Answer:
the anwser isn't in the choices
Explanation:
H=MC(change of temp.)
M=mass of water=250g
C=specific heat of water = 4.186 j/g
change in temperature is 121-40= 81
H= 250x4.186x81=84766.5J