Can you please help me

Answer:

(-1)(11)(3)(5)

Step-by-step explanation:

First off:  -165 separates into the factors (-1) and (165).  Next, we divide 165 by 15, obtaining 15(11).

So far, we have (-1)(11)(15).

15 is still factorable.  We get:

(-1)(11)(3)(5), which is the desired prime factorization of -165.

To find the average rate of change of the function f(x) = 1.85x^2 over the interval 10 ≤ x ≤ 20, we need to find the difference in the function values at the endpoints of the interval and divide by the length of the interval.

The function value at x = 10 is:

f(10) = 1.85(10)^2 = 185

The function value at x = 20 is:

f(20) = 1.85(20)^2 = 740

The length of the interval is:

20 - 10 = 10

So the average rate of change of the function over the interval 10 ≤ x ≤ 20 is:

(f(20) - f(10)) / (20 - 10) = (740 - 185) / 10 = 55.5

Rounding to the nearest tenth, the average rate of change of the function over the interval 10 ≤ x ≤ 20 is approximately 55.5.

Answer: C

Step-by-step explanation:

The rest of the quadrilaterals provided have 2 pairs of parallel lines.

The choice is:

Explanation:

The quadrilateral that has exactly one pair of parallel lines is called a trapezoid.

Here's what a trapezoid looks like :

\(\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\linethickness{0.3mm}\qbezier(0,0)(0,0)(1,3)\qbezier(5,0)(5,0)(4,3)\qbezier(1,3)(1,3)(4,3)\qbezier(3,0)(8.2,0)(0,0)\put(-0.5,-0.3){$\sf A$}\put(5.3,-0.3){$\sf B$}\put(4.2,3.1){$\sf C$}\put(0.6,3.1){$\sf D$}\end{picture}\)

Answer:

Step-by-step explanation:

2g=7h-3f

g=\(\frac{7h-3f}{2}\)

Answer:

g= \(g=\frac{7}{2}h- \frac{3}{2}f\), f∈R, h∈R

Step-by-step explanation:

3f+2g=7h

2g=7h-3f

g=\(\frac{7}{2}h - \frac{3}{2} f\)

Answer:

k = 6 and k = -4

Step-by-step explanation:

To determine two integral values of k (integer values of k) for which the roots of the quadratic equation kx² - 5x - 1 = 0 will be rational, we can use the Rational Root Theorem.

The Rational Root Theorem states that if a rational number p/q is a root of a polynomial equation with integer coefficients, then p must be a factor of the constant term (in this case, -1) and q must be a factor of the leading coefficient (in this case, k).

Possible p-values:

Possible q-values:

Therefore, all the possible values of p/q are:

\(\sf \dfrac{p}{q}=\dfrac{\pm 1}{\pm 1}, \dfrac{\pm 1}{\pm k}=\pm 1, \pm \dfrac{1}{k}\)

To find the integral values of k, we need to check the possible combinations of factors. Substitute each possible rational root into the function:

\(\begin{aligned} x=1 \implies k(1)^2-5(1)-1 &= 0 \\k-6 &= 0 \\k&=6\end{aligned}\)

\(\begin{aligned} x=-1 \implies k(-1)^2-5(-1)-1 &= 0 \\k+4 &= 0 \\k&=-4\end{aligned}\)

\(\begin{aligned} x=\dfrac{1}{k} \implies k\left(\dfrac{1}{k} \right)^2-5\left(\dfrac{1}{k} \right)-1 &= 0 \\\dfrac{1}{k}-\dfrac{5}{k}-1 &= 0 \\-\dfrac{4}{k}&=1\\k&=-4\end{aligned}\)

\(\begin{aligned} x=-\dfrac{1}{k} \implies k\left(-\dfrac{1}{k} \right)^2-5\left(-\dfrac{1}{k} \right)-1 &= 0 \\\dfrac{1}{k}+\dfrac{5}{k}-1 &= 0 \\\dfrac{6}{k}&=1\\k&=6\end{aligned}\)

Therefore, the two integral values of k for which the roots of the equation kx² - 5x - 1 = 0 will be rational are k = 6 and k = -4.

Note:

If k = 6, the roots are 1 and -1/6.

If k = -4, the roots are -1 and -1/4.

If the first quartile is 39 years old, it means that approximately one-fourth of the employees at CCNHS – Main Campus are 39 years old or younger.

The first quartile (Q1) of the ages of the 256 employees of CCNHS – Main Campus being 39 years old implies that 25% of the employees have an age equal to or less than 39 years old.

In statistical terms, the first quartile represents the point below which 25% of the data falls. It divides the data set into four equal parts, with each part containing 25% of the data. Therefore, if the first quartile is 39 years old, it means that approximately one-fourth of the employees at CCNHS – Main Campus are 39 years old or younger.

This information provides insight into the age distribution of the employees at the institution. It indicates that a significant portion of the employees are relatively young, with a quarter of them falling below the age of 39. Understanding the age demographics of the workforce can be useful for various purposes, such as planning professional development programs or implementing age-specific policies.

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Answer:

His final velocity is 48.03 m/s

Step-by-step explanation:

Using SI units  (m, kg, s)

a = 3.7

x0 = 25

x1 = 300

v0 = 16.5

Apply kinematics formula

v1^2 - v0^2 = 2a(x1-x0)

solve for v1

Final velocity

v1 = sqrt(2a(x1-x0)+v0^2)

= sqrt( 2(3.7)(300-25)+16.5^2) )

= 48.03 m/s

Answer:

24 1 2 3 4 5 6 7 8 9 0 10 11 12 13 14 1 5 q5

Answer:

d. y = x + 6

Step-by-step explanation:

Equation of AD can be written in the slope-intercept form, y = mx + b

First, find the slope (m) and y-intercept (b) of line AD.

✔️Slope (m) = change in y/change in x

Using two points on line AD, (-5, 1) and (0, 6):

Slope (m) = (6 - 1)/(0 - (-5))

Slope (m) = 5/5

m = 1

✔️y-intercept (b) is the point where the line cuts across the y-axis = 6

b = 6

✔️To write the equation, substitute m = 1 and b = 6 into y = mx + b

y = 1(x) + 6

y = x + 6

From the graph attached below, the solution to the system of linear inequalities are (1, 4)

A system of linear inequalities is a collection of linear inequalities in the same variables. The solution is any ordered pair that satisfies each of the inequalities.

In the problem given;

y < - x + 5 ...eq(i)

y ≥ 3x + 1 ...eq(ii)

To determine the solution to the system of linear inequalities, it is easier for us to use graphical method. This is simply done by plotting the points and determine the coordinate at which both inequalities intersect.

From the graph of the system of linear inequalities, the solution to this is (1, 4) which is option E

Kindly find attached graph below

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Answer:

Where is the question? First tell the question then I think I can help you

When it comes to interest, most Certificates of Deposit (CDs) will allow periodic interest payouts. So, correct option is B.

A CD is a type of savings account that allows you to earn a fixed interest rate on your deposit for a specific period of time, called the term. Typically, the longer the term of the CD, the higher the interest rate offered.

However, during the term of the CD, the funds are locked in, meaning that you cannot withdraw the principal without incurring a penalty.

While some CDs may allow for unlimited withdrawals of interest, this is not common, and may still come with restrictions or penalties. Loans against principal are also not typically allowed with CDs, as the funds are meant to be held for a set term.

Therefore, the most common option available for CD holders is to receive periodic interest payouts, which can be monthly, quarterly, or annually, depending on the terms of the CD. This allows the CD holder to earn interest on their deposit while still receiving some income during the term of the CD.

So, correct option is B.

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The mistake katie has made is included an extra length, the correct option is C.

We are given that;

The table of lengths of caterpillars

Now,

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

Katie has made the mistake of including an extra length in her diagram. She has included the length 81 twice in the stem-and-leaf diagram, once in the row for 5 and once in the row for 8. However, there is only one caterpillar with a length of 81 mm in the data. Therefore, she should remove one of the 81s from her diagram.

Therefore, by algebra the answer will be included extra length.

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Answer:

si

Step-by-step explanation:

You want math problems???

Answer:

Hᴇʏᴀᴀᴀ!! ᴍʏ ɴᴀᴍᴇ ɪꜱ ᴘɪɴᴋʏ ᴀɴᴅ ɪ ᴀᴍ ʜᴇʀᴇ ᴛᴏ ᴀɴꜱᴡᴇʀ ʏᴏᴜʀ Qᴜᴇꜱᴛɪᴏɴ!!ʕ ꈍᴥꈍʔ☆

Step-by-step explanation:

ɪ ᴅᴏɴ'ᴛ ʀᴇᴀʟʟʏ ʟɪᴋᴇ ᴍᴀᴛʜ ʙᴜᴛ ɪꜰ ɪ ʜᴀᴅ ᴛᴏ ᴄʜᴏᴏꜱᴇ ᴀ ꜰᴀᴠᴏʀɪᴛᴇ ɪᴛ ᴡᴏᴜʟᴅ ʙᴇ ᴀʟɢᴇʙʀᴀ!!  (◕ᴗ◕✿)

  ʜᴀᴠᴇ ᴀɴ ᴀᴍᴀᴢɪɴɢ ɴɪɢʜᴛ ᴏʀ ᴅᴀʏ!

      *:･ﾟ✧*:･ﾟꜰʀᴏᴍ ʏᴏᴜʀ ᴏɴᴇ ᴀɴᴅ ᴏɴʟʏ ᴘɪɴᴋʏ  ʕ ﾟ ● ﾟʔ✧✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ

Answer:

A) \(\frac{7}{tan55^\circ}\)

Step-by-step explanation:

\(tan\theta=\frac{opposite}{adjacent}\\ \\tan55^\circ=\frac{7}{BC}\\ \\BC*tan55^\circ=7\\\\BC=\frac{7}{tan55^\circ}\)

Answer:

18

Step-by-step explanation:

Answer:

It is odd

Step-by-step explanation:

For example let's substitute 1 for x

f(x) = 4(1)+3

         4+3

f(x) = 7 this is odd

Let's substitute 2

f(x) = 4(2)+3

         8+3

f(x) = 11 this is odd

This means no matter what you substitute for x, it will be odd

Hope this helps!

Answer:

1)

A) \(\frac{}{X}\) ~ N(8.5;0.108)

B) P(\(\frac{}{X}\) > 9)= 0.0552

C) P(X> 9)= 0.36317

D) IQR= 0.4422

2)

A) \(\frac{}{X}\) ~ N(30;2.5)

B) P( \(\frac{}{X}\)<30)= 0.50

C) P₉₅= 32.60

D) P( \(\frac{}{X}\)>36)= 0

E) Q₃: 31.0586

Step-by-step explanation:

Hello!

1)

The variable of interest is

X: pollutants found in waterways near a large city. (ppm)

This variable has a normal distribution:

X~N(μ;σ²)

μ= 8.5 ppm

σ= 1.4 ppm

A sample of 18 large cities were studied.

A) The sample mean is also a random variable and it has the same distribution as the population of origin with exception that it's variance is affected by the sample size:

\(\frac{}{X}\) ~ N(μ;σ²/n)

The population mean is the same as the mean of the variable

μ= 8.5 ppm

The standard deviation is

σ/√n= 1.4/√18= 0.329= 0.33 ⇒σ²/n= 0.33²= 0.108

So: \(\frac{}{X}\) ~ N(8.5;0.108)

B)

P(\(\frac{}{X}\) > 9)= 1 - P(\(\frac{}{X}\) ≤ 9)

To calculate this probability you have to standardize the value of the sample mean and then use the Z-tables to reach the corresponding value of probability.

Z= \(\frac{\frac{}{X} - Mu}{\frac{Sigma}{\sqrt{n} } } = \frac{9-8.5}{0.33}= 1.51\)

Then using the Z table you'll find the probability of

P(Z≤1.51)= 0.93448

Then

1 - P(\(\frac{}{X}\) ≤ 9)= 1 - P(Z≤1.51)= 1 - 0.93448= 0.0552

C)

In this item, since only one city is chosen at random, instead of working with the distribution of the sample mean, you have to work with the distribution of the variable X:

P(X> 9)= 1 - P(X ≤ 9)

Z= (X-μ)/δ= (9-8.5)/1.44

Z= 0.347= 0.35

P(Z≤0.35)= 0.63683

Then

P(X> 9)= 1 - P(X ≤ 9)= 1 - P(Z≤0.35)= 1 - 0.63683= 0.36317

D)

The first quartile is the value of the distribution that separates the bottom 2% of the distribution from the top 75%, in this case it will be the value of the sample average that marks the bottom 25% symbolically:

Q₁: P(\(\frac{}{X}\)≤\(\frac{}{X}\)₁)= 0.25

Which is equivalent to the first quartile of the standard normal distribution. So first you have to identify the first quartile for the Z dist:

P(Z≤z₁)= 0.25

Using the table you have to identify the value of Z that accumulates 0.25 of probability:

z₁= -0.67

Now you have to translate the value of Z to a value of \(\frac{}{X}\):

z₁= (\(\frac{}{X}\)₁-μ)/(σ/√n)

z₁*(σ/√n)= (\(\frac{}{X}\)₁-μ)

\(\frac{}{X}\)₁= z₁*(σ/√n)+μ

\(\frac{}{X}\)₁= (-0.67*0.33)+8.5=  8.2789 ppm

The third quartile is the value that separates the bottom 75% of the distribution from the top 25%. For this distribution, it will be that value of the sample mean that accumulates 75%:

Q₃: P(\(\frac{}{X}\)≤\(\frac{}{X}\)₃)= 0.75

⇒ P(Z≤z₃)= 0.75

Using the table you have to identify the value of Z that accumulates 0.75 of probability:

z₃= 0.67

Now you have to translate the value of Z to a value of \(\frac{}{X}\):

z₃= (\(\frac{}{X}\)₃-μ)/(σ/√n)

z₃*(σ/√n)= (\(\frac{}{X}\)₃-μ)

\(\frac{}{X}\)₃= z₃*(σ/√n)+μ

\(\frac{}{X}\)₃= (0.67*0.33)+8.5=  8.7211 ppm

IQR= Q₃-Q₁= 8.7211-8.2789= 0.4422

2)

A)

X ~ N(30,10)

For n=4

\(\frac{}{X}\) ~ N(μ;σ²/n)

Population mean μ= 30

Population variance σ²/n= 10/4= 2.5

Population standard deviation σ/√n= √2.5= 1.58

\(\frac{}{X}\) ~ N(30;2.5)

B)

P( \(\frac{}{X}\)<30)

First you have to standardize the value and then look for the probability:

Z=  (\(\frac{}{X}\)-μ)/(σ/√n)= (30-30)/1.58= 0

P(Z<0)= 0.50

Then

P( \(\frac{}{X}\)<30)= 0.50

Which is no surprise since 30 y the value of the mean of the distribution.

C)

P( \(\frac{}{X}\)≤ \(\frac{}{X}\)₀)= 0.95

P( Z≤ z₀)= 0.95

z₀= 1.645

Now you have to reverse the standardization:

z₀= (\(\frac{}{X}\)₀-μ)/(σ/√n)

z₀*(σ/√n)= (\(\frac{}{X}\)₀-μ)

\(\frac{}{X}\)₀= z₀*(σ/√n)+μ

\(\frac{}{X}\)₀= (1.645*1.58)+30= 32.60

P₉₅= 32.60

D)

P( \(\frac{}{X}\)>36)= 1 - P( \(\frac{}{X}\)≤36)= 1 - P(Z≤(36-30)/1.58)= 1 - P(Z≤3.79)= 1 - 1 = 0

E)

Q₃: P(\(\frac{}{X}\)≤\(\frac{}{X}\)₃)= 0.75

⇒ P(Z≤z₃)= 0.75

z₃= 0.67

z₃= (\(\frac{}{X}\)₃-μ)/(σ/√n)

z₃*(σ/√n)= (\(\frac{}{X}\)₃-μ)

\(\frac{}{X}\)₃= z₃*(σ/√n)+μ

\(\frac{}{X}\)₃= (0.67*1.58)+30= 31.0586

Q₃: 31.0586

Answer:

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Step-by-step explanation:

uyfiuyf

floor plan => It is the scale drawing that show the relationship between rooms, spaces, and physical features viewed from the above

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Answer:

Rounding it to the nearest foot, the length of the main span of the Akashi Kaikyo Bridge is 5,020 feet.

Step-by-step explanation:

Given that the Verrazano Narrows Bridge has a main span of 3,260 feet, while the Akashi Kaikyo Bridge has a main span that is about 54% longer, to determine the length of the main span of this last bridge, the following calculation must be performed:

3,260 x 1.54 = X

5,020.4 = X

Thus, rounding it to the nearest foot, the length of the main span of the Akashi Kaikyo Bridge is 5,020 feet.

The surface areas of the figures are 336, 82 and 836

From the question, we have the following parameters that can be used in our computation:

The figures

For the triangular prism, we have

Surface area = 2 * 1/2 * 6 * 8 + 12 * 10 + 8 * 12 + 6 * 12

Surface area = 336

For the rectangular prism, we have

Surface area = 2 * (7 * 3 + 3 * 2 + 2 * 7)

Surface area = 82

For the cylinder, we have

Surface area = 2π * 7 * (7 + 12)

Surface area = 836

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The surface area of the prisms are

1. 336 cm²

2. 82 m²

3. 836 cm²

The area occupied by a three-dimensional object by its outer surface is called the surface area.

A prism is a solid shape that is bound on all its sides by plane faces.

The surface area of prism is expressed as;

SA = 2B +pH

where B is the base area , p is the perimeter and h is the height.

1. SA = 2B +ph

B = 1/2 × 6 × 8

= 24 m²

p = 6+8+10 = 24m

h = 12m

SA = 2 × 24 + 24 × 12

= 48 + 288

= 336 cm²

2. SA = 2( 3× 2) + 3× 7)+ 2 × 7)

= 2( 6+21+14)

= 2( 41)

= 82 m²

3. SA = 2πr( r +h)

= 2 × 3.14 × 7( 7 + 12)

= 44( 19)

= 836 cm²

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Answer: 1:2

Step-by-step explanation:

24 ÷ 12 = 2

12 ÷ 12 = 1

Answer to the question is 1:2

Answer:

I;m wondering the same thing

Step-by-step explanation:

Answer: don’t know maybe a glitch or had something to do with the honor code

Step-by-step explanation:

Answer:

y intercept when x is 0, so the answer is 3

Answer:

6.8 gallons per day vhuwhbehkq i had to put those random letter because it had to be 20 letters or more

Answer:

19/24 = 0.791666667

Step-by-step explanation:

7/8 - 1/12

Least common multiple of 8 and 12 is 24. Convert 7/8 and 1/12 to fractions with denominator 24.

21/24 - 2/24

Since 21/24 and 2/24 have the same denominator, subtract them by subtracting their numerators.

21 - 2 / 24

Subtract 2 from 21 to get 19.

19/24