Morgann and Leti are on a swing set at the park. Morgann makes 5 complete cycles in 30

seconds. What is the period of each cycle? What is the frequency between the 2 swings

Answers

Answer 1

The frequency between the two swings is the same, as both swings are experiencing the same cycle time. frequency between the 2 swings is approximately 0.167 cycles per second.



Morgann makes 5 complete cycles in 30 seconds. To find the period (time taken for one cycle), you can divide the total time (30 seconds) by the number of cycles (5).
Period = Total time / Number of cycles
Period = 30 seconds / 5 cycles
Period = 6 seconds
So, the period of each cycle is 6 seconds.
Frequency refers to the number of cycles completed in one second. To find the frequency, you can divide the number of cycles (5) by the total time (30 seconds).
Frequency = Number of cycles / Total time
Frequency = 5 cycles / 30 seconds
Frequency = 1/6 cycles per second (approximately 0.167 cycles per second).

Frequency is the number of times an observation is repeated while falling between a class' upper and lower bounds. Furthermore, Cumulative Frequency is the result of adding all frequencies up to that class. Additionally, since the cumulative frequency and frequency for the first class are the same. The Frequency is therefore lower than or equal to the Cumulative Frequency.

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Related Questions

If the forces on an object are not equal and _____ , then they are unbalanced.

Answers

Hello there! If the forces on an object are not equal and opposite, then they are unbalanced.

Isaac Newton’s third law of motion states that for every action, there is an equal and opposite reaction. This refers to most situations in which the two forces exerted on something apply the same amount of force, creating a state of balance without movement. For example, one could push a wall and it would not move. The wall exerts an equal and opposite force on the person that causes no movement. Hope this helps!

Complete this sentence: Only the most reactive metals in the chart
react with______.

Answers

Completing the sentence given ; Only the most reactive metals react with water

Reactivity of metals is a chemical property that measures the rate at which metals easily loses their electrons in substances to form a positive ion in a substance.

The most reactive metals react vigorously with water while the least reactive metals does not react with water and dilute acids vigorously but they slowly react with oxygen.

Examples of very reactive metals are :

Potassium sodium and Lithium

Hence we can conclude that Only the most reactive metals react with water.

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Complete this sentence: Only the most reactive metals in the chartreact with______.

a ball which is dropped from the top of a building strikes the ground with a speed of 30 m/s. assume air resistance can be ignored. the height of the building is approximately:

Answers

We can use the We can use the kinematic equation to solve this problem:

v_f^2 = v_i^2 + 2ad

where

v_f = final velocity = 30 m/s

v_i = initial velocity = 0 (since the ball is dropped)

a = acceleration due to gravity = -9.81 m/s^2 (negative because it is in the opposite direction of motion)

d = distance (height of the building)

Rearranging the equation:

d = (v_f^2 - v_i^2) / 2a

Substituting the given values:

d = (30^2 - 0^2) / (2*(-9.81))

d = 459.15 m

Therefore, the height of the building is approximately 459.15 meters. to solve this problem:

v_f^2 = v_i^2 + 2ad

where

v_f = final velocity = 30 m/s

v_i = initial velocity = 0 (since the ball is dropped)

a = acceleration due to gravity = -9.81 m/s^2 (negative because it is in the opposite direction of motion)

d = distance (height of the building)

Rearranging the equation:

d = (v_f^2 - v_i^2) / 2a

Substituting the given values:

d = (30^2 - 0^2) / (2*(-9.81))

d = 459.15 m

Therefore, the height of the building is approximately 459.15 meters.

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please help me out with this. ​

please help me out with this.

Answers

To find the current in the resistor, we can use Ohm's Law and the concept of equivalent resistance. Thus, option A is correct.

First, let's calculate the equivalent resistance of the three cells connected in parallel. When resistors are connected in parallel, the reciprocal of the equivalent resistance is equal to the sum of the reciprocals of the individual resistances:

1/Req = 1/R1 + 1/R2 + 1/R3

Given that R1 = R2 = R3 = 22 Ω (internal resistance of each cell), we can substitute the values:

1/Req = 1/22 + 1/22 + 1/22

1/Req = 3/22

Taking the reciprocal of both sides, we find:

Req = 22/3 Ω

Now we can use Ohm's Law to calculate the current (I) in the resistor. Ohm's Law states that the current flowing through a resistor is equal to the voltage across it divided by its resistance:

I = V/R

Given that V = 1.1 V (emf of each cell) and R = 32 Ω (resistance), we can substitute the values:

I = 1.1/32

Calculating this value, we find:

I ≈ 0.034375 A

Therefore, the current in the resistor is approximately 0.034375 A.

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Calculate the velocity of a non-relativistic electron whose de broglie wavelength is 3. 637 nm.

Answers

Answer: The velocity of the non-relativistic electron is approximately 1.497 × 10^6 m/s.

Explanation:

The de Broglie wavelength (λ) of a particle is given by the equation:

λ = h/p

where h is Planck's constant and p is the momentum of the particle.

In the case of an electron, the momentum (p) is related to its velocity (v) by:

p = mv

where m is the mass of the electron.

Combining these two equations, we get:

λ = h/mv

Solving for v, we get:

v = h/(mλ)

We can put in the given values and constants:

λ = 3.637 nm = 3.637 × 10^-9 m (convert nanometers to meters)

h = 6.626 × 10^-34 J·s (Planck's constant)

m = 9.109 × 10^-31 kg (mass of an electron)

v = h/(mλ) = (6.626 × 10^-34 J·s)/(9.109 × 10^-31 kg × 3.637 × 10^-9 m)

v = 1.497 × 10^6 m/s

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An induced charge is when charged particles can be attracted to neutral objects.
True or false?

Answers

Answer:

the answer is true Induction charging is a method used to charge an object without actually touching the object to any other charged object.

Explanation:

when you increase magnification is it necessary to increase the amount of light

Answers

According to my research on how microscopes work, I can say that based on the information provided within the question as you move to a higher level of magnification on a microscope the following terms have the following effects

Resolution increases

Working Distance decreases

Amount of Light needed increases

Depth of Field decreases

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Someone please help me to answer this questions...​

Someone please help me to answer this questions...

Answers

Answer:

a.25J

Explanation:

m=0.5kg

g=10

h=5

potential energy=m×g×h

=0.5×10×5

=25J

a 0.250-kg rubber ball is thrown down onto the floor at a speed of 5.30 m/s. it rebounds from the floor with a speed of 3.71 m/s. if the ball is in contact with the floor for 0.028 s, what is the average force exerted on the ball by the floor?

Answers

The average force exerted on the ball by the floor is 80.46 N

To find the average force exerted on the ball by the floor, we can use the impulse-momentum theorem, which states that the change in momentum of an object is equal to the impulse applied to it. In this case, the impulse is the force exerted by the floor over the time of contact.

First, let's calculate the initial momentum of the ball:

p = m * v
p = 0.250 kg * 5.30 m/s
p = 1.325 kg m/s

Next, let's calculate the final momentum of the ball:

p' = m * v'
p' = 0.250 kg * (-3.71 m/s)
p' = -0.928 kg m/s

The change in momentum is:

Δp = p' - p
Δp = -0.928 kg m/s - 1.325 kg m/s
Δp = -2.253 kg m/s

The impulse applied to the ball is equal to the change in momentum:

J = Δp
J = -2.253 kg m/s

Finally, we can calculate the average force exerted by the floor using the formula:

F = J / Δt
F = (-2.253 kg m/s) / (0.028 s)
F = -80.46 N

Note that the negative sign indicates that the force is acting in the opposite direction to the motion of the ball, i.e. upwards. Therefore, the average force exerted on the ball by the floor is 80.46 N upwards.

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Damron Inc. Wants to purchase a shear for their sheet metal shop and chooses dimensions of​ cost, reliability, and flexibility as critical to their long term success. They evaluate three different shears and rate their performance on each criterion on a scale from 1​ (poor) to 5​ (excellent). What is the value index for the shear made by Belsky​ Manufacturing? Dimension Importance Belsky Mfg. Reber Ind. Floyd Co. Cost 4 1 5 3 Reliability 2 5 2 1 Flexibility 3 3 3 4 A. 23 B. 81 C. 18 D. 9

Answers

Rate the effectiveness of four different shears on a scale of 1 to 10 for each category. Reber thinks that the shear should be bought.

Describe flexibility.

Flexibility is the term used to describe a joint's or a collection of joints and muscles' ability to move through a range of motion efficiently painlessly.

Flexibility is the capacity to swiftly and collectedly adapt to brief change, enabling you to successfully handle unforeseen issues or duties. Here are some instances of what you could do: Offer to help another team member if you see them to be overworked.

Flexibility in the workplace refers to the capacity to quickly adjust to novel situations as they emerge. A flexible worker can alter their plans to deal with or get around unexpected challenges.

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A horse accelerates from rest for 1 s and covers a distance D. If instead the accelerates from rest with the same accelerations for 2 s will the distance it covers be equal to 2D, 4D, or 9D

Answers

Answer:

4D

Explanation:

We will use 2nd equation of motion in this question:

s = Vi t + (0.5)gt²

where,

s = distance covered

t = time taken

g = acceleration due to gravity

For t = 1 s:

s = D

Therefore,

D = (0 m/s)(1 s) + (0.5)g(1 s)²

D = 0.5g   -------------- equation (1)

For t = 2 s:

s = D

Therefore,

s = (0 m/s)(1 s) + (0.5)g(2 s)²

s = 0.5g(4)

using equation (1):

s = 4D

therefore, correct answer is:

4D

According to Newton’s law of universal gravitation, which statements are true?

A: As we move to higher altitudes, the force of gravity on us decreases.
B: As we move to higher altitudes, the force of gravity on us increases.
C: As we gain mass, the force of gravity on us decreases.
D: As we gain mass, the force of gravity on us increases.
E: As we move faster, the force of gravity on us increases.

Answers

Before we solve this, we should know this fact:

According to Newton's Law of Gravitation, the force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. The force acts along the line joining the centres of the two objects. It can be shown by this:

\(F ∝ \frac{Mm}{ {d}^{2} } \)

Now, let us check all the options.

A. As we move to higher altitudes, the force of gravity on us decreases.

This statement is true.

The force of gravity is inversely proportional to the square of distance from the centre of the earth. If, we go up the surface of the earth, the distance from the centre of the earth increases and hence the value of force of gravity decrease. So, force of gravity decreases with altitude.

B. As we move to higher altitudes, the force of gravity on us increases.

This statement is false.

We have already got the result in option A. that the force of gravity decreases with altitude. It never increases with altitude.

C. As we gain mass, the force of gravity on us decreases.

This statement is false.

The force of gravity is directly proportional to the product of the masses. So, if increase our mass, then the force of gravity will also increase and if we decrease our mass, then the force of gravity decreases.

D. As we gain mass, the force of gravity on us increases.

This statement is true.

As mentioned earlier in option C., the force of gravity is directly proportional to the product of the masses of the earth and another object. So, as we gain mass, the force of gravity on us increases.

E. As we move faster, the force of gravity on us increases.

This statement is true.

Here, we have to consider a different formula. According to Newton's Second Law,

F = ma, where F is the force, m is the mass and a is the acceleration.

In other words,

F ∝ a, i.e., force is directly proportional to acceleration.

We know, acceleration is the rate of change of velocity of an body within a time period.

So, if speed is increased, then acceleration will also be greater, which results in the increase of force. So, as we move faster, the force of gravity on us increases.

Answers:

A: As we move to higher altitudes, the force of gravity on us decreases.

D: As we gain mass, the force of gravity on us increases.

E: As we move faster, the force of gravity on us increases.

Hope you could understand.

If you have any query, feel free to ask.

A block of wood is 10 cm long ,by 4cm broadby1.5 cm thik the block weighs 31g find the density of the wood in kg/m3

Answers

Answer:

/////////////////////////////////////////////////

Explanation:

in order to allow both telecommunications and power cables in a cable tray or cable runway, they must be ? , as required by the national electrical code (nec).

Answers

To accommodate both telecommunications and power cables in a cable tray or cable runway, they must be separated, as mandated by the National Electrical Code (NEC).

The National Electrical Code (NEC) sets standards for electrical installations to ensure safety and proper functioning. According to NEC guidelines, telecommunications and power cables should be physically separated when placed in a cable tray or cable runway. This separation is necessary to prevent interference and potential hazards. Telecommunications cables carry data signals, while power cables carry electrical currents. When these cables are in close proximity, there is a risk of electromagnetic interference (EMI) from the power cables affecting the data signals in the telecommunications cables. This interference can lead to signal degradation and communication errors. Additionally, power cables carry high voltage, which poses a safety hazard if there is a fault or short circuit. Therefore, by keeping telecommunications and power cables separated in cable trays or runways, the risk of interference and safety concerns is minimized, ensuring proper functionality and compliance with the NEC.

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A projectile falls beneath the straight-line path it would follow if there were no gravity. How many meters does it fall below this line if it has been traveling for 1 s? for 2 s?.

Answers

A projectile that has been traveling for 1 s falls 4.9 meters below the straight-line path it would follow if there were no gravity. It would fall 19.6 meters below for 2 seconds.

Gravity is the force that pulls objects towards each other, and its strength depends on mass and distance between the objects. When an object is thrown into the air, gravity pulls it downwards causing it to follow a curved path. The height of the object above the ground and the time it has traveled affects the distance it will fall below the straight-line path that it would have traveled if there were no gravity.

The vertical distance that a projectile falls below the line of its unimpeded flight is known as its displacement, or drop, below the straight-line path. For an object that has been traveling for 1 second, it falls 4.9 meters below the straight-line path it would have followed if there were no gravity, and it would fall 19.6 meters below for 2 seconds.

The formula used to calculate the displacement of a projectile is: d = 1/2gt^2, where d is the displacement, g is the acceleration due to gravity and t is the time traveled.

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a hanging spring is stretched by 0.2 m when a mass of 0.5 kg is attached to it. the mass is then pulled down a further 0.1 m and released from rest. what is the angular frequency of the resulting oscillations? show your work.

Answers

The angular frequency of the oscillations is 3.126 rad/s.

What is the angular frequency?

To find the angular frequency of the oscillations, we need to use the formula:

ω = √(k/m)

where ω is the angular frequency, k is the spring constant, and m is the mass attached to the spring.

First, let's find the spring constant k. According to Hooke's law, the force F applied to a spring is proportional to its displacement x from its equilibrium position, and the constant of proportionality is the spring constant k:

F = -kx

where the negative sign indicates that the force is in the opposite direction to the displacement. We can rearrange this equation to solve for k:

k = -F/x

where F is the weight of the mass attached to the spring, which is given by:

F = mg

where m is the mass of the object and g is the acceleration due to gravity. Therefore, we have:

k = -(mg)/x

Substituting the given values, we get:

\(k = -(0.5 kg)(9.81 m/s^2)/(0.2 m)\)

= -24.525 N/m

Next, we need to find the new equilibrium position of the mass after it is pulled down by an additional 0.1 m. Since the spring is initially stretched by 0.2 m, the total displacement from the rest position is 0.2 m + 0.1 m = 0.3 m. Therefore, the new equilibrium position is 0.3 m below the original rest position.

Now, we can find the angular frequency of the oscillations using the formula:

ω = √(k/m)

where m is the mass of the object. Since the mass is the same as before, we have:

ω = √(k/m)

= √(-24.525 N/m / 0.5 kg)

= 3.126 rad/s

Therefore, the angular frequency of the oscillations is 3.126 rad/s.

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is isopropyl alcohol a element compound or mixture

Answers

Answer:

Isopropyl is an element compound.

Explanation:

whats the order of solid liquid and gas from least particle motion to the most?

Answers

Answer:

Solid < Liquid < Gas

The diagram below represents two horizontal platforms that are different height levels above ground ball rolls off the taller platform with a horizontal speed of 15 m/s in travels through the air landing on top of the short a platform. What is the total time the ball is in the air.

Answers

The total time the balls are in the air is 2.77 s.

The correct answer is option E.

To calculate the total time the ball is in the air, we need to analyze the vertical motion of the ball. Let's consider the given values:

Height of the taller platform (H1) = 6.0 m

Height of the shorter platform (H2) = 3.6 m

Horizontal speed of the ball (ux) = 15 m/s

We can neglect friction for this calculation. Since the ball rolls off the taller platform horizontally, the initial vertical velocity (uy) is zero. We can use the following equation to calculate the time of flight:

H = ut + (1/2)\(gt^2\)

Phase 1: Upward motion

In this phase, the ball moves vertically against the force of gravity. The acceleration due to gravity (g) is approximately 9.8 m/s^2. The initial vertical velocity (uy) is zero.

Using the equation of motion:

H1 = (1/2)\(gt^2\)

6.0 = (1/2)(\(9.8)t^2\)

12.0 =\(4.9t^2\)

\(t^2\) = 12.0 / 4.9

\(t^2\) ≈ 2.449

t ≈ \(\sqrt{2.449}\)

t ≈ 1.564 s

Phase 2: Downward motion

In this phase, the ball moves vertically downward. The final velocity in the upward phase (when it reaches the top of the shorter platform) is zero. We can calculate the time it takes to fall from the shorter platform using the same equation:

H2 = (1/2)g\(t^2\)

3.6 = (1/2)(9.8)\(t^2\)

7.2 = 4.9\(t^2\)

\(t^2\) = 7.2 / 4.9

\(t^2\) ≈ 1.469

t ≈ \(\sqrt{1.469}\)

t ≈ 1.212 s

Total time:

The total time the ball is in the air is the sum of the times for phase 1 and phase 2:

Total time = t1 + t2

Total time ≈ 1.564 + 1.212

Total time ≈ 2.776 s

Therefore, among the given options the correct one is option E.

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The question probable may be:

The diagram represents two horizontal platforms that are different height levels above ground ball rolls off the taller platform with a horizontal speed of 15 m/s in travels through the air landing on top of the short a platform. What is the total time the ball is in the air where H1 =6.0 m H2= 3.6m (NEGLECT FRICTION)

A.0.16 s

B. 0.70 s

C.0.49s

D. 1.1 s

E. 2.77 s

4. Without the sun, there would be no way to replace energy released into the environment. True or False

Answers

Answer:

true

Explanation:

What electromotive force would cause 200 mA of current to flow through a 500ohm resistor? 250 V (B) 10kV 2. 5kV (D) 100 V

Answers

The electromotive force would cause 200 mA of current to flow through a 500ohm resistor is (D) 100 V.

The electromotive force that would cause 200 mA of current to flow through a 500 ohm resistor is 100 V. This can be determined using Ohm's law.Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. Mathematically, Ohm's law is represented by the equation V = IR, where V is voltage, I is current, and R is resistance.To find the electromotive force, we can rearrange Ohm's law to be E = IR, where E is electromotive force. Substituting the given values, we have:E = (0.2 A)(500 Ω)E = 100 V .

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what type of energy transfer is occurring?
a ceiling fan plugged into the wall socket

what type of energy transfer is occurring? a ceiling fan plugged into the wall socket

Answers

Answer:

electrical to mechanical

Explanation:

I would like to know how to find the distance my fake planet is to its sun and the orbital length in measurement using the information I have gathered so far about my made up DnD planet I have searched a million things up and have gotten myself in a loop hole because in order to get X I need to know B and in order to know B I need to either know X or A and if I use the one using A then A needs X in order to find B to find X.

Heres the information:
Day Duration: 36 hours
Orbit Duration: 1.6 Earth years
Year Duration: 389.3... days
Gravity: 9.608 m/s²
Axial Precession: 15,000 years
Axial Tilt: 21.7 to 23.5
Axial Oscillate: 8333.3... years per 0.1 oscillate of 1.8 oscillation
Number of moons: 3
CLimate regions: much similar to earth Temperate regions are
the magority of the planet with tropical at the equator and
subtropical at the poles with seasons changing at the prevernal,
vernal, estival, serotinal, autumnal, and hibernal periods
Radius: 4578.2 (m)
Planet Mass: 3017387649322753000
Circumference: 28765.6789733

Answers

It is to be noted that based on the information provided, it is not possible to calculate the distance of the planet from its sun as we need more information about orbit and its eccentricity.

What is Space Orbit distance?

The distance of your fictional planet from its sun, and its orbital period, can be calculated using the information you've provided about its day duration, orbit duration, year duration, and radius.

The distance between a planet and its sun is known as an astronomical unit (AU). To calculate the distance in AU, you can use the formula: d = (T² * G * M_sun) / (4 * pπ²)

where T is the planet's orbital period in Earth years, G is the gravitational constant (6.67 x 10^-⁻¹¹ m³ kg^⁻¹ s^⁻²), M_sun is the mass of the sun (2 x 10^30 kg), and pi is the mathematical constant (3.14).To find the orbital period you need to know year duration in seconds and divide it by 365.25 for Earth-based standard.

With that you can calculate the distance of the planet from its sun. The calculation of axial precession, tilt and oscillation etc don't provide information about the distance from its sun or the orbital period, It helps us to understand the planet's rotation around it's axial and the behaviors of the planet's climate because of axial tilt, precession and oscillation

Also, radius, planet mass and circumference also don't provide any information about distance of the planet from its sun or the orbital period as well.

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monochromatic light is incident on a metal surface, and electrons are ejected. if the intensity of the light increases, what will happen to the ejection rate of the electrons? monochromatic light is incident on a metal surface, and electrons are ejected. if the intensity of the light increases, what will happen to the ejection rate of the electrons?

Answers

increasing the intensity of monochromatic light incident on a metal surface will not affect the ejection rate of electrons, but it will increase the total number of electrons ejected per unit time.

What is Photoelectric effect.?

The photoelectric effect refers to the emission of electrons from a metal surface when light shines on it. When a photon of light with sufficient energy (i.e., frequency) strikes the metal surface, it can transfer its energy to an electron in the metal, causing the electron to be ejected from the metal. This phenomenon was first observed by Heinrich Hertz in 1887 and explained by Albert Einstein in 1905, who proposed that light consists of discrete packets

The ejection rate of electrons from a metal surface is determined by the energy of the photons of light that strike the surface. In the photoelectric effect, electrons are ejected from a metal surface when they absorb photons of sufficient energy. The energy of a photon is directly proportional to its frequency, as given by the equation:

E = hf

where E is the energy of the photon, h is Planck's constant, and f is the frequency of the photon.

Increasing the intensity of monochromatic light does not change the frequency or energy of the photons. Therefore, the ejection rate of electrons from the metal surface will not change with an increase in the intensity of the light. However, the total number of electrons ejected per unit time (i.e., the current) will increase with increasing intensity, since there are more photons striking the surface per unit time.

In summary, increasing the intensity of monochromatic light incident on a metal surface will not affect the ejection rate of electrons, but it will increase the total number of electrons ejected per unit time.

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True or False? Define east as the negative direction and west as the positive direction. (a) If a car is traveling east, its acceleration must be eastward. (b) If a car is slowing down, its acceleration may be positive. (c) An object with constant nonzero acceleration can never stop and stay stopped.

Answers

(a) False. If a car is traveling east, its acceleration must be eastward is the wrong statement.

(b) True. If a car is slowing down, its acceleration may be positive right statement.

(c) True.  An object with constant nonzero acceleration can never stop and stay stopped is right statement.

Acceleration is what?

The pace at which speed changes is known as acceleration. Acceleration typically, but not always, indicates a change in speed. Because the direction of an object's velocity is shifting even while it follows a circular course, it continues to accelerate.

In which scenario, if a car is moving east and we designate east as the positive direction, will the acceleration be negative?

The negative acceleration would suggest a slowing of the object if it is moving eastward (has positive velocity).

What are some instances of a positive and a negative acceleration?

As a result, accelerating a moving vehicle forward is a positive acceleration, while reversing it is a negative acceleration.

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A train car With a mass of 1650kg is moving east at 2m/s. It collides with an identical train car, Which is stationary. What will the result velocity of the combinad train cars be if the colisión is perfectly ineslastic

Answers

Answer:

the combined train cars will be moving east at a speed of 1 m/s after the perfectly inelastic collision.

Explanation:

First, we can calculate the initial momentum of the first train car before the collision:

p1 = m1v1 = 1650 kg * 2 m/s = 3300 kgm/s east

Since the second train car is stationary, its initial momentum is zero:

p2 = m2*v2 = 0

The total momentum before the collision is therefore:

p_total = p1 + p2 = 3300 kg*m/s east

After the collision, the two train cars stick together and move as one, so we can treat them as a single object with a combined mass of 2*m1 = 3300 kg. Let's call the final velocity of the combined train cars v_final.

The conservation of momentum tells us that the total momentum after the collision is also p_total, so we can write:

p_total = m_total * v_final

Substituting in the values we have:

3300 kg*m/s east = 3300 kg * v_final

Solving for v_final, we get:

v_final = 1 m/s east

So the combined train cars will be moving east at a speed of 1 m/s after the perfectly inelastic collision.

A standing wave has a frequency of 471 Hz and a wavelength of 1.9. What is the speed of the
wave? (Round to the 2nd number after the decimal)
1
I REALLY NEED HELP !

Answers

Answer:

c = 894.90 m/s

Explanation:

Given data:

Frequency of wave = 471 Hz

Wavelength of wave = 1.9 m

Speed of wave = ?

Solution:

Formula:

Speed of wave = frequency × wavelength

c = f×λ

c = 471 Hz × 1.9 m

  Hz = s⁻¹

c = 471s⁻¹ × 1.9 m

c = 894.90 m/s

The speed of wave is 894.90 m/s.

GIVING BRAINLIEST PLEASE HELP!!
-if you answer correctly ill give you brainliest which will give you 25pts-

GIVING BRAINLIEST PLEASE HELP!!-if you answer correctly ill give you brainliest which will give you 25pts-

Answers

Answer:

b and d :)

Explanation:

Answer:

A, B, And C,

Explanation:

The law of conservation of energy is a physical law that states energy cannot be created or destroyed but may be changed from one form to another. Another way of stating this law of chemistry is to say the total energy of an isolated system remains constant or is conserved within a given frame of reference.

What is the net force on an
object with a 15 N force to
the left and an 8 N force to
the right?

Answers

The net force on the body is 7N towards Left.

As we know, that the force is vector quantity so will have magnitude as well as direction.

While calculating the net force we have to keep in mind that the direction of the applied force is important to note.

In our case, 15N force is applied towards the left direction.

A force of 8N is applied toward the right direction.

These forces will collide with each other in order to cancel each other they both have opposite direction.

Let say the net force on the body is F, the net force on the body will be,

F = 15N - 8N

F = 7N.

We know the magnitude. Now, we have to find the direction, on collision the force with bigger magnitude will dominate over the force with smaller magnitude. hence the direction of the net force will be in the direction of the Bigger force, i.e. Left Direction.

To know more about Force, visit,

https://brainly.com/question/12785175

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What do you use to write on a blackboard? ​

Answers

Answer:

Chalk, expo markers. Why?

Answer:

Chalk

Explanation:

please mark as brainliest

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