Based on the chemical equation provided, use the drop-down menu to choose the coefficients that will balance the chemical equation.
()H2 + ()O2 → ()H2O

Answer:

B. Frequency

Explanation:

Answer:

the speed after 3 seconds is 10 m/s

Explanation:

The computation of the speed is shown below:

As we know that

V = U  + at

Here,

U = 34 m/s

a =  - 8 m/s²

t = 3 Sec

V = velocity after 3 sec

V  = 34 + (-8)3

 = 34 - 24

 V = 10 m/s

Hence, the speed after 3 seconds is 10 m/s

(a) If the orbital period of Eris is 559 years then the semi major axis of Eris is 67.864 AU (10.152 Tm)

(b) Aphelion distance is 97.5 AU, while its perihelion distance is 38.3 AU then it's orbit is very eccentric .

It's eccentricity would be 0.43607.

One of our solar system's biggest dwarf planets is Eris. Despite being three times further from the Sun, it is roughly the same size as Pluto.

Eris at first glance seemed bigger than Pluto. This sparked a discussion among scientists, and the International Astronomical Union ultimately decided to define the definition of a planet in 2006. The objects Pluto, Eris, and several like them are currently categorized as dwarf planets.

Eris was found on January 5, 2005, using information gathered on October 21, 2003 by Mike Brown, a professor of planetary astronomy at the California Institute of Technology, Chad Trujillo, of the Gemini Observatory, and David Rabinowitz, of Yale University, during a Palomar Observatory survey of the outer solar system.

Possibility of Life

It appears implausible that life could live on Eris' surface given how frigid it is there.

Dimension and Distance

Eris is approximately 1/5 the radius of Earth, with a radius of around 722 miles (1,163 kilometers). Like Pluto, Eris is a bit smaller than the Moon. Eris would be around the size of a popcorn kernel if the Earth were the size of a nickel.

Eris is 68 astronomical units from the Sun at an average distance of 6,289,000,000 miles (10,125,000,000 kilometers). The distance between the Sun and Earth is one astronomical unit, or AU. From here, sunlight travels from the Sun to Eris' surface over the course of more than nine hours.

Rotation and Orbit

One orbit of the Sun by Eris takes 557 years on Earth. The Kuiper Belt, a region of frozen debris beyond Neptune's orbit, lies well beyond Eris' plane of orbit, which is far outside the plane of the solar system's planets.

Eris has days that are comparable to ours in length since it rotates around the Sun every 25.9 hours.

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Answer:

50 m/s^2

Explanation:

F=ma

25 N= 0.5 kg • a

divide both sides by 0.5 kg

a=50 m/s^2

Answer:

Explanation:

jhgfhmhvmghmm

Answer:

Explanation:

70.0(5.00)(9.81) = 3,433.5 = 3430 N

To solve this we must be knowing each and every concept related to  centripetal force and its calculations. Therefore, the centripetal force acting on her is 3430 N.

The term centripetal relates to a propensity to gravitate toward the center. Centripetal refers to moving in the direction of the center. The force that maintains an item moving in a circular direction and helps it stay on the path is referred to as centripetal force.

Furthermore, centrifugal force is indeed the tendency of things to deviate from a circular route and fly in a straight line. People frequently confuse centripetal force with centrifugal force.

Mathematically,

F = m a

  = 70 acceleration

  = 70 × 5 × 9.81

 = 3430 N

Therefore, the centripetal force acting on her is 3430 N.

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The tax rate you will pay is displayed in tax brackets for each category of taxable income.

Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.

Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.

As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.

Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.

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Answer:

   \(c_{e1} = \frac{(m_2 c_{e2} \ + m_3 c_{e3} ) \ (T_{Teq} - T_2) }{m_1 (T_1 - T_{eq}) }\)

Explanation:

This is a calorimeter problem where the heat released by the console is equal to the heat absorbed by the cupcake and the plate.

           Q_c = Q_{abs}

where the heat is given by the expression

           Q = m c_e ΔT

            m₁ c_{e1) (T₁-T_{eq}) = m₂ c_{e2} (T_{eq} -T₂) + m₃ c_{e3} (T_{eq}- T₁)

note that the temperature variations have been placed so that they have been positive

They ask us for the specific heat of the console

           \(c_{e1} = \frac{(m_2 c_{e2} \ + m_3 c_{e3} ) \ (T_{Teq} - T_2) }{m_1 (T_1 - T_{eq}) }\)

The mass of the Ball B is 1.35 x 10⁻⁶ kg.

Gravitational Force is described by Newton's law of universal gravitation, which states that the force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

The law of universal gravitation is important in many fields, including astronomy, physics, and engineering.

The gravitational force F between two objects of masses m1 and m2 separated by a distance r is given by:

F = G(m₁m₂)/r²

where G is the gravitational constant.

We can rearrange the equation to solve for the mass of Ball B:

m₂ = Fr²/Gm₁

Substituting the given values, we get:

m₂ = (8.7 x 10⁻¹⁰ N)(3.0 m)²/(6.6743 x 10¹¹ N(m^2/kg²))(30 N)

m₂ = 1.35 x 10⁻⁶ kg

Therefore, the mass of Ball B is approximately 1.35 x 10⁻⁶kg.

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Answer:

A) 3.0 ohms

Explanation:

R=V/I=12V/4.0A=3.0 ohms

Answer: the radius of the circular path is approximately 1637.58 meters.

Explanation:

The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:

F_c = m * g * tan(banking angle)

Where:

F_c is the centripetal force

m is the mass of the airplane

g is the acceleration due to gravity

tan(banking angle) is the tangent of the banking angle

Now, the centripetal force is also given by the formula:

F_c = (m * v^2) / r

Where:

v is the speed of the airplane

r is the radius of the circular path

Equating the two expressions for F_c, we get:

(m * g * tan(banking angle)) = (m * v^2) / r

Canceling out the mass (m) on both sides of the equation, we have:

g * tan(banking angle) = v^2 / r

Solving for r, we get:

r = (v^2) / (g * tan(banking angle))

Substituting the given values:

v = 400 km/h = 400,000 m/h

g = 9.8 m/s^2

banking angle = 20°

Converting the speed to m/s:

v = 400,000 m/h * (1/3600) h/s = 111.11 m/s

Converting the banking angle to radians:

banking angle = 20° * (π/180) rad/° = 0.3491 rad

Now, substituting the values into the formula:

r = (111.11^2) / (9.8 * tan(0.3491))

r ≈ 1637.58 meters

Therefore, the radius of the circular path is approximately 1637.58 meters.

Determine the planet's radius and mass. Use the formula g=GMR2 to get the acceleration 93.63×10¹⁶m/s brought on by gravity on that planet's surface.

The most practical formula for estimating the acceleration caused by gravity is given by these two laws: g = G*M/R2, where g is the acceleration caused by gravity, G is M represents mass, R is distance, and G is the gravitational constant of the universe.

g = G*M/R2,

g = 5.972×10²⁴/ 6.378×10⁶

g = 5.972×10¹⁸/6.378

g = 93.63×10¹⁶m/s

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Answer:

CuCl₂   +    H₂S    →    CuS   +    2HCl  

Explanation:

The unbalanced reaction expression is given as;

        CuCl₂   +    H₂S    →    CuS   +    HCl

The problem here involves balancing of chemical equations.

 We use a mathematical approach to solve this problem. Here assign coefficients a, b, c and d as values that will effect the balance;

          aCuCl₂   +    bH₂S    →    cCuS   +    dHCl

Conserving Cu:  a  = c

                     Cl:   2a  = d

                     H: 2b  = d

                     S: b  = c

let a  = 1; c  = 1, b  = 1 and d  = 2

         CuCl₂   +    H₂S    →    CuS   +    2HCl  

Answer:

The crowning of Charlemagne by Pope Leo III was significant in a number of ways. For Charlemagne, it was necessary because it encouraged to give him higher reliability. It gave him the rank of a dictator, giving him the only ruler in Europe west of the Byzantine emperor in Constantinople.

The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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According to the information, the ball will just pass over the net (question A); and the ball hits the ground approximately at 7.04 meters from the player and after a time of flight of approximately 1.31 seconds (question B).

To determine if the ball will clear the net, we compare the vertical displacement of the ball with the net height. The ball's initial height is 1.1 meters, and it reaches its highest point during flight. By calculating the trajectory, we can confirm that the ball's vertical displacement at its highest point will be higher than the net height of 1.81 meters, ensuring it clears the net.

To find when and where the ball hits the ground, we need to calculate the time of flight and horizontal displacement. Using the given initial velocity and angle, we can determine the time it takes for the ball to reach the ground. By calculating the horizontal displacement based on the initial horizontal velocity and total time of flight, we find that the ball hits the ground approximately 7.04 meters from the player. The time of flight is approximately 1.31 seconds. The specific values may vary depending on the given initial conditions.

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Answer:

(a) a = 2.44 m/s²

(b) s = 63.24 m

Explanation:

(a)

We will use the second equation of motion here:

\(s = v_it+\frac{1}{2}at^2\)

where,

s = distance covered = 47 m

vi = initial speed = 0 m/s

t = time taken = 6.2 s

a = acceleration = ?

Therefore,

\(47\ m = (0\ m/s)(6.2\ s)+\frac{1}{2}a(6.2\ s)^2\\\\a = \frac{2(47\ m)}{(6.2\ s)^2}\)

a = 2.44 m/s²

(b)

Now, we will again use the second equation of motion for the complete length of the inclined plane:

\(s = v_it+\frac{1}{2}at^2\)

where,

s = distance covered = ?

vi = initial speed = 0 m/s

t = time taken = 7.2 s

a = acceleration = 2.44 m/s²

Therefore,

\(s = (0\ m/s)(6.2\ s)+\frac{1}{2}(2.44\ m/s^2)(7.2\ s)^2\\\\\)

s = 63.24 m

Answer:C or B

Explanation:

Gases easily compress when pressure is applied, but liquids don't. So, option A.

The attracting and repellent forces that develop between the molecules of a substance are known as intermolecular forces.

Here,

The interactions between the individual molecules of a substance are mediated by the intermolecular forces. The majority of the physical and chemical features of matter are caused by intermolecular forces.

Compared to gases, which have relatively far-apart particles, liquids exhibit higher intermolecular forces due of the near proximity of their particles. The greater the intermolecular forces get as they get closer to one another since they are electrostatic in nature.

There is no force between particles in a gas. Particles have no restrictions on their movement. The container's walls colliding with one another provide the only forces that exist. which rely on the quantity of gas (number of collisions) and the momentum of each collision respectively. The pressure is nearly consistent throughout the entire mass of the gas because the molecules are free to move.

There is no compression of liquids. Since their volume is constant, changing pressure has no effect on it.

Hence,

Gases easily compress when pressure is applied, but liquids don't. So, option A.

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Expansion of universe is not a hypothetical one but the universe is expanding in the sense increase distance over the space and dark matter.

The increase in distance over time between any two particular gravitationally unbound regions of the observable universe is known as the universe's expansion. 

As a result, the size of space itself expands intrinsically. It is not necessary for space to exist outside of the cosmos or for it to extend into anything.

The metric changes in scale rather than space or the things in space moving in the conventional sense. Objects move farther apart from one another at ever-increasing speeds as the spatial component of the universe's spacetime metric scales up.

Any viewer in the cosmos would see that all of space appears to be expanding, except for the galaxies receding with a speed proportional to the distance from the observer.

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Answer:

it might be damaged

Explanation:

depending on how harsh the weather is it might be more or less damaged

ANSWER:

66.8 m

STEP-BY-STEP EXPLANATION:

Given:

Area of mirror = 28.02 cm²

We make a sketch of the situation in order to solve the problem:

We calculate the height as follows:

Now, we determine for AEF that it has the same angle as ABC, like this:

It is located 66.8 meters from the pole

Traditional Banking Benefits

Online Banking Benefits

Banks provide a secure place to keep money. By depositing money in a bank account, individuals and businesses can keep their money safe from theft, fire, or other unforeseen events.

Check writing, electronic financial transfers, and credit or debit card transactions are all services provided by banks. Individuals and organizations may use these services to pay bills, acquire goods and services, and receive payments more easily.

Individuals and corporations can get loans and lines of credit from banks. These loans can be used to pay for college, buy a house or car, establish a company, or cover unforeseen needs.

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Answer:

3 N.

Explanation:

If you want to know how much two charges push or pull each other, you can use Coulomb's law. It says that the force F depends on how big the charges are (Q and q) and how far apart they are (r). The bigger the charges and the closer they are, the stronger the force. The smaller the charges and the farther they are, the weaker the force. The exact formula is:

F = k | Q q | / r 2

where k is a number that makes everything work out right. It's about 8.99 × 10 9 N ⋅ m 2 / C 2 .

Now let's say you have two charges that are a certain distance r 0 apart and they have a force F 0 between them. What happens if you move them twice as far apart? The new distance is 2 r 0 and the new force is F 1 . How do F 1 and F 0 compare? Well, you can use Coulomb's law again and divide them:

F 1 / F 0 = (k | Q q | / (2 r 0 ) 2 ) / (k | Q q | / r 0 2 )

If you simplify this, you get:

F 1 / F 0 = (1/2) 2

F 1 / F 0 = 1/4

This means that the new force is only one-fourth of the old force. So if the old force was 12 N, then the new force is:

F 1 = F 0 /4

F 1 = (12 N) /4

F 1 = 3 N

So moving the charges twice as far apart makes the force four times weaker. It goes from 12 N to 3 N.

(a) The amount of friction force acting on the ice is 9.8 N.

(b) The acceleration of the ice is 0.98 m/s².

The amount of friction force acting on the ice is calculated by applying the following equation based on Newton's second law of motion.

F = μmg

where;

F = 0.1 x 10 kg x 9.8 m/s²

F = 9.8 N

The acceleration of the ice is calculated as follows;

a = μg

a = 0.1 x 9.8 m/s²

a = 0.98 m/s²

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Answer:

A, B, and C all apply.

Explanation:

The strength of the electric field between two charged objects is directly proportional to the magnitude of the charges (A and B) and inversely proportional to the distance between them (C). The type of material the cups are made of (insulators or conductors) does not affect the strength of the electric field.

500 miles/hr West

Because it has magnitude and direction