Answer:
7 meters away
Explanation:
12 x 1.5 = 18
25 - 18 = 7
13. Which one of the colors has the longest wavelength A, Red B. Yellow C. Blue 14. The sky appears blue due to A. Diffraction of light C. Refraction of light B. Reflection of light D. Scattering of light
13.The color with the longest wavelength is option A. Red.
14.The sky appears blue due to option D. Scattering of light.
Red light has a longer wavelength compared to yellow and blue light.The color that has the longest wavelength is red. The color of the sky appears blue due to scattering of light. The distance between one peak and the next in a series of waves, particularly electromagnetic waves traveling through space or along a wire is referred to as wavelength.
The wavelength of light, for example, determines its color. Red light has the longest wavelength, followed by orange, yellow, green, blue, and purple, with violet light having the shortest wavelength. When light is reflected off a surface or passes through a medium, it can be deflected in various directions, a phenomenon known as scattering of light.
The Earth's atmosphere scatters sunlight in all directions, but the shorter blue wavelengths are scattered more than the longer wavelengths. As a result, we perceive the sky as blue during the day. The light becomes scattered when it interacts with particles in the atmosphere, causing the sky to appear blue during the day and red during sunset or sunrise. The scattering of light is the process that causes the sky to appear blue.
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A 0.5-kg ball accelerated at 50 m/s 2 . What force was applied?
Answer:
25N
Explanation:
soln:
given,
mass(m)=0.5kg
acceleration(a)=50m/s^2
force(F)=?
we know,
F=m*a
or,F=0.5*50
•°•F=25N
A speedboat moves on a lake with initial velocity vector U₁₁x = 8. 85 m/s and v₁y = -2. 63 m/s, then accelerates for 5. 13 s at an average acceleration of day. X = -0. 101 m/s² and aav,y = 0. 104 m/s2. What are the components of the speedboat's final velocity, U2,x and U2,y? m/s U2₁x = U2,y Find the speedboat's final speed. Final speed: m/s m/s
According to the given statement , the components of the speedboat's final velocity are U2, x = 8.332 m/s and U2, y = -2.097 m/s and the speedboat's final speed is 8.60 m/s.
To find the components of the speedboat's final velocity, we can use the equations of motion. The components of the initial velocity are given as U₁₁x = 8.85 m/s and U₁₁y = -2.63 m/s. The boat then accelerates for 5.13 s with an average acceleration of aav,x = -0.101 m/s² and aav,y = 0.104 m/s².
First, let's find the components of the final velocity, U2,x and U2,y:
1. Calculate the change in velocity in the x-direction (ΔVx):
ΔVx = aav,x * t
= (-0.101 m/s²) * (5.13 s)
= -0.518 m/s
2. Add the change in velocity to the initial velocity in the x-direction to find the final velocity in the x-direction (U2,x):
U2,x = U₁₁x + ΔVx
= 8.85 m/s + (-0.518 m/s)
= 8.332 m/s
3. Calculate the change in velocity in the y-direction (ΔVy):
ΔVy = aav,y * t
= (0.104 m/s²) * (5.13 s)
= 0.533 m/s
4. Add the change in velocity to the initial velocity in the y-direction to find the final velocity in the y-direction (U2,y):
U2,y = U₁₁y + ΔVy
= -2.63 m/s + 0.533 m/s
= -2.097 m/s
Therefore, the components of the speedboat's final velocity are U2,x = 8.332 m/s and U2,y = -2.097 m/s.
To find the speedboat's final speed, we can use the Pythagorean theorem:
5. Calculate the magnitude of the final velocity (V2):
V2 = √(U2,x² + U2,y²)
= √((8.332 m/s)² + (-2.097 m/s)²)
= √(69.43 + 4.397) = √73.827 = 8.60 m/s
Therefore, the speedboat's final speed is 8.60 m/s.
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When a car speeds up when rounding a curve, what happens to its centripetal
acceleration?
A.) It decreases
B.) It increases
C.) It remains constant.
D.) It is zero.
. A boy wishes to make a catapult out of a rubber band of width 9mm and thickness 1.55mm. Determine the length of the band that he must use so that when he stretches it by 0.25 of its natural length and releases it the velocity of pebble of mass 0.006kg will be 30m/s. Take young modulus of the rubber to be 4×10^7 N/m^2
The length of the rubber band that the boy must use is 0.024 m or 24 mm.
What will be the length of the rubber required?To determine the length of the rubber band, we can use the formula for the potential energy stored in a stretched spring, which is also applicable to a stretched rubber band:
U = 1/2 kx²where U is the potential energy stored in the rubber band, k is the spring constant (or in this case, the rubber band constant), and x is the displacement of the rubber band from its natural length.
Since the rubber band is stretched by 0.25 of its natural length, the displacement x is 0.25 times the natural length of the rubber band.
We can solve for the rubber band constant k by using the formula for the velocity of a projectile launched by a spring (or in this case, a rubber band):
v = √(2mk/M)where v is the velocity of the projectile, m is the mass of the rubber band, M is the mass of the projectile, and k is the spring constant. We can rearrange this equation to solve for k:
k = (v² M) / (2 m)
We can now combine the two equations to solve for the length of the rubber band, L:
U = 1/2 k x²
U = 1/2 ((v² M) / (2 m)) (0.25 L)²
U = (v² M L²) / (32 m)
The potential energy stored in the rubber band must be equal to the kinetic energy of the projectile when it is launched:
U = 1/2 M v²
(v² M L²) / (32 m) = 1/2 M v²
L = ((16 m v²) / (k M))
L = ((16 m v²) / ((v² M) / (2 m) M))
L = √(32 m^2 / M)
L = (0.032 M)
Substituting the given values, we get:
L = √(0.032 * 0.006)
L = 0.024 m
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Dave runs a 400 m race with a speed of 4 m/s. What time will it take him to finish the
race?
Answer:
The answer should be 100 if not try 200
Explanation:
d=v x t
400m=4m/s x t
/4 /4
100=t
consider two concentric solenoids shown above, one of which is attached to a battery, a resistor and a switch and the other of which is attached to a light bulb. assuming no current passes directly between the two circuits, what is expected to happen when the switch is turned on?
When the switch is turned on the lightbulb flashes on once, and then no current passes through it, the correct option is E.
When the switch is turned on, the circuit on the left will experience a brief period of changing current as the current ramps up to its final value. This changing current produces a changing magnetic field, which in turn induces an emf in the inner solenoid.
This induced emf causes a brief current to flow in the outer solenoid, which is connected to the lightbulb circuit. As a result, the lightbulb will flash on momentarily. However, once the current in the left circuit reaches its final value, the magnetic flux through the inner solenoid will stop changing, and thus the induced emf in the outer solenoid will drop to zero, the correct option is E.
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The complete question is:
Consider the two concentric solenoids shown in Figure, one of which is attached to a battery, a resistor, and a switch and the other of which is attached to a lightbulb. (No current passes directly between the two circuits.) When the switch is turned on, what is expected to happen?
A. No current passes through the lightbulb.
B. The intensity of the lightbulb increases and quickly reaches its maximum, final intensity.
C. The lightbulb flickers on and off with a regular frequency and constant intensity.
D. The lightbulb flickers on and off with a regular frequency and decreasing intensity.
E. The lightbulb flashes on once, and then no current passes through it.
Circular Motion A 650-kg car moving at 8.5 m/s takes a turn around a circle with a radius of 48.0 m. Determine the acceleration acting upon the car. Use a = v2/ r
Answer:
Explanation:
The mass of the car doesn't matter because On a flat curve the mass of the car does not affect the speed at which it can stay on the curve. You would need the mass if you were solving the the centripetal force acting on the car, but not the acceleration.
\(a=\frac{v^2}{r}\) and filling in
\(a=\frac{(8.5)^2}{48.0}\) and we need 2 significant digits in our answer. That means that
a = 1.5 m/sec²
a 2-n force is applied to a spring, and there is displacement of 0.4 m. how much would the spring be displaced if a 5-n force was applied?
Answer:1m
Explanation:
2n=0.4m
5n=?
5n×0.4/2n=1m
positron emission tomography (pet) studies of patients with schizophrenia have found
Positron emission tomography (PET) studies of patients with schizophrenia have found various patterns of brain activity and neurotransmitter abnormalities associated with the condition. Some key findings from PET studies in schizophrenia include:
Dopamine Dysregulation: PET studies have revealed an imbalance in dopamine neurotransmission in the brains of individuals with schizophrenia. Excessive dopamine activity in certain brain regions, such as the mesolimbic pathway, is associated with positive symptoms of schizophrenia, including hallucinations and delusions.Hypofrontality: PET scans have shown reduced metabolic activity in the frontal cortex of individuals with schizophrenia. This "hypofrontality" may be related to cognitive impairments and negative symptoms experienced by patients, such as decreased motivation and social withdrawal.
Abnormal Glutamate Levels: PET studies have suggested alterations in glutamate neurotransmission in individuals with schizophrenia. Glutamate is an excitatory neurotransmitter involved in various cognitive processes. Disruptions in glutamate signaling may contribute to cognitive deficits observed in schizophrenia.Brain Connectivity: PET imaging has also provided insights into altered functional connectivity in the brains of individuals with schizophrenia. Aberrant patterns of connectivity between different brain regions have been associated with symptoms and cognitive impairments in the disorder.
It is important to note that findings from PET studies in schizophrenia can vary across individuals and may not be consistent across all patients. More research is needed to fully understand the complex neurobiological mechanisms underlying schizophrenia
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A 8. 43-newton force was applied for an unknown displacement; however, it is known that 376 joules of work was done. What is the value of the mystery displacement?(1 point).
Answer:
8.74 m
Explanation:
W = FΔx
376 = 43(Δx)
8.74 = Δx
Hey there everyone!
_____________________________________________________
Answer:
So, if you have the following to choose from:
O 368 m
O 44.6 m
O 384 m
O 3170 m
44.6 m (aka. Option B) is correct.
_______________________________________________________
Step By Step Explanation:
1. F = 8.43 N
2. W = 376 J
3. W = F x d
4. 376 J = 8.43 N × d
5. d = 44.6 m ← Our Final Solution
_______________________________________________________
Hope this helps! If you still need help on this, feel free to check out the flash cards I made below.
h t t p s : / / q u i z l e t . c o m / 7 6 4 3 6 7 9 6 0 / p h y s i c a l - s c i e n c e - 2 2 - f o r c e - a n d - w o r k - r e l a t i o n s h i p s - f l a s h - c a r d s / ? n e w
.
A sample of an ideal gas is contained at initial volume 34 L, temperature 450 K, and pressure 7.7 × 104 Pa. It then is allowed to expand to a volume of 40 L. To calculate the work involved in the expansion, which additional information, if any, must be known about the gas? Assume that known information includes the values of physical constants, such as the ideal-gas constant R.
A.the final pressure of the gas
B.The path of the change from initial to final conditions
C. the final temperature of the gas
Answer:
it have to be a
Explanation:
2.
The morning of a birthday party, a balloon is filled with 8.5 L of helium (He) when the temperature is
294 kelvin. The party starts at 4:00 p.m., at which time, the temperature has risen to 305 kelvin. What is
the new volume of the balloon?
Answer:
the balloon is filled with the 8.5 litre of helium. temperature is 294 kelvin.
party starts at 4 p.m.
the temperature rises 305 kelvin.
the new volume = 4 litres
A car and a train each make a trip that is 120 km. The average speed of a train is 40 km/h faster than a car. If the train covers the same distance in 30 min less time, find the average speed of the car.
Given that a car and a train each make a trip that is 120 km and the average speed of a train is 40 km/h faster than a car. We need to find the average speed of the car.Let the average speed of a car be x km/hour.So the average speed of the train is (x + 40) km/hour. According to the question, time taken by the train is 30 minutes less than the car, so time taken by the car is:
t = d/swhere t = time taken, d = distance covered, and s = speed of the carThe time taken by the train is:t - 0.5h = d/(x + 40)Here, 0.5 hour is equal to 30 minutes.Now, both the car and the train covered the same distance. Hence we have:t = d/xUsing the formulae for t in both equations, we have:d/x - 0.5 = d/(x + 40)Cross-multiplying the above equation, we get:d(x + 40) - 0.5x(x + 40) = dxSimplifying the above expression, we get:x² - 80x - 2400 = 0We can solve the above quadratic equation to get the values of x.
Using the main answer, the average speed of the car is 60 km/h.The explanation to find the average speed of the car:Given, a car and a train each make a trip that is 120 km. Let the average speed of a car be x km/h. Therefore, the average speed of the train is (x + 40) km/hour.The time taken by the train is t - 0.5h = d/(x + 40).Using the formulae for t in both equations, we have:d/x - 0.5 = d/(x + 40)Cross-multiplying the above equation, we get:d(x + 40) - 0.5x(x + 40) = dxSimplifying the above expression, we get:x² - 80x - 2400 = 0We can solve the above quadratic equation to get the values of x.Using the main answer, the average speed of the car is 60 km/h.
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Constants The current I in a long, straight wire is constant and is directed toward the right as in (Figure 1). Conducting loops A, B, C and D are moving in the directions shown, near the wire. Part A For each loop, is the direction of the induced current clockwise or counterclockwise, or is the induced current zero? Drag the appropriate items to their respective bins. Reset Help 100 A 1609 E 1o C (150D Figure 1 of 1 Clockwise Counterclockwise No current The current I in a long, straight wire is constant and is directed toward the right as in (Figure 1). Conducting loops A.B.C. and D are moving in the directions shown, near the wire. Part B For each loop, what is the direction of the net force that the wire exerts on the loop? Drag the appropriate items to their respective bins.
The route of the net force that the wire exerts on the loop.
Loop A: counterclockwise Loop
B: clockwise Loop
C: no current Loop
D: counterclockwise
B) For A and B, the force may be in the direction of the cord the pressure might be inside the path in order to oppose the exchange.
For C there might be no force
For D the force could be away from the loop.
The net force is the gravitational force directed towards the immediately twine. current flows clockwise through the round loop of cord. again, a hand ruler can be used to determine the course of the pressure acting at the electron. on the grounds that electrons are negatively charged, the left-hand rule applies.
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a trolley A of mass 2kg at 5 meter per second collide with a stationary trolley B of mass 3kg after the collision the two travel together at 2 meter per second find (a) what is the momentum of A before the collision (b) what is the momentum of A after the collision (c) what is the kinetic energy of A before collision (d) what is the kinetic energy of each trolley after collision (e) during the collision A kinetic energy gained by B is less than the kinetic energy gained by A, how much kinetic energy is un accounted for?
a) The momentum of trolley A before the collision is (2 kg) * (5 m/s) = 10 kg*m/s.
b) The momentum of trolley A after the collision is (2 kg) * (2 m/s) = 4 kg*m/s.
c) The kinetic energy of trolley A before the collision is 1/2 * (2 kg) * (5 m/s)^2 = 25 J.
d) The kinetic energy of trolley A after the collision is 1/2 * (2 kg) * (2 m/s)^2 = 2 J. And the kinetic energy of trolley B after the collision is 1/2 * (3 kg) * (2 m/s)^2 = 3 J.
e) The amount of kinetic energy that is unaccounted for is the difference between the initial kinetic energy of trolley A and the final kinetic energy of trolley A and trolley B. This is 25J - (2J + 3J) = 20 J.
It's important to note that the total momentum of the system is conserved during the collision, meaning that the momentum of trolley A before the collision is equal to the total momentum of trolley A and B after the collision. Also the total kinetic energy of the system is not conserved during the collision as some of the energy is transferred to internal energy of the system and other forms of energy.
Which of these is true about pure substances?
A. They can only contain one type of molecule.
B. They can contain different types of atoms and molecules.
C. They may contain one type of atom or one type of molecule.
D. They can only contain one type of atom.
Answer:
the answer is c bc to be pure it must be the same atom or molecule
The propeller in the previous problem slows from 475 rev/min to 187 rev/min in 4.00 s. What is its angular acceleration?
The angular acceleration of the propeller is 7.54 rad/s²
Angular acceleration:This can be defined as the rate of change of angular velocity. The S.I unit of angular acceleration is rad/s.
The angular acceleration of the propeller can be calculated using the formula below.
⇒ Formular:
∝ = (ω-ω')/t................. Equation 1⇒ Where:
∝ = angular acceleration of the propellerω = final angular velocityω' = initial angular velocityt = time.From the question,
⇒ Given:
ω' = 475 rev/min = (475×0.10472) rad/s = 49.742 rad/sω = 187 rev/min = (187×0.10472) = 19.583 rad/st = 4 s⇒ Substitute these values into equation 1
∝ = (19.583-49.742)/4∝ = -30.159/4∝ = -7.54 rad/s².Note: The negative sign tells that the propeller is slowing down.
Hence, The angular acceleration of the propeller is 7.54 rad/s²
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in this problem one fringe shift is defined to mean from a bright pattern to the next dark pattern and not bright to dark and back again to a bright, which would be two fringe shifts. these fringe shifts occur because the wavelength of the light changes inside the gas filled tube. assume that 502 nm light is used, the tube is 3.99 cm long, and that 221 fringe shifts occur as the pressure of the gas in the tube increases to atmospheric pressure. calculate ngas, the index of refraction of the gas.
The gas has a 1.0037 refractive index. Moving from one bright pattern to the next dark pattern constitutes one fringe shift; going from bright to dark and back to brilliant constitutes two fringe shifts.
The refractive index, often known as the refraction index, is a dimensionless number used in optics to describe how well a medium bends light.
The refractive index of a substance determines how much of it is bent or refracted when it absorbs light.
There are 365 fringes.
527 * 10-9 m is the laser's wavelength.
Tube diameter: 2.57 cm (0.02 m).
Ngas = 1 + N(lamda)/2L = 1 + (365*527*10-9/2*0.026 = 1 + 0.000192355/0.052 1 + 0.00369 1 + 0.0037 1.0037 This formula can be used to determine a gas's refractive index.
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A boat uses its motor to increase its speed from 5 m/s to 7 m/s. If the boat has a mass of
250 kg, what was the impulse applied by the motor?
Answer:
J = 500 kg-m/s
Explanation:
Given that,
Initial speed of the motor, u = 5 m/s
Final speed of the motor, v = 7 m/s
Mass of the boat, m = 250 kg
We need to find the impulse applied by the motor. We know that impulse is equal to the change in momentum. It is represented by letter J.
J = m(v-u)
J = 250 (7-5)
J = 500 kg-m/s
Hence, the impulse applied by the motor is 500 kg-m/s.
PLEASE ANSWER THE QUESTION AS SOON AS POSSIBLE
Answer: the answer is (1) B only
Explanation: In A the ball is being acted upon by the ground. In B in order for the ball to move upwards the ball had to have force acted upon at R. In C from U to V the ball has been acted upon by the ground
lf a negative charge is initially al rest in an electric field, will it move toward a region of higher potential or lower potential? what about a positive charge? how does the potential energy the charge change in each instance?
A negative charge will move towards a region of lower potential, while a positive charge will move towards a region of higher potential.
When a charge is in an electric field, its potential energy is determined by its relative position in the field. When a negative charge is initially at rest in an electric field, its potential energy is at its highest. As it moves towards a region of lower potential, the electric field exerts a force that is directed opposite to its motion, causing it to lose potential energy. The electric field does work on the charge, transferring energy from the field to the charge. This work done on the charge results in a decrease in its potential energy. Conversely, when a positive charge is initially at rest in an electric field, its potential energy is at its lowest. As it moves towards a region of higher potential, the electric field exerts a force that is directed in the same direction as its motion, causing it to gain potential energy. The electric field does work on the charge, transferring energy from the charge to the field. This work done on the charge results in an increase in its potential energy.
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A spiral spring extends from a length of 10.00cm when a force of 20n is applied to it calculate the force constant of the spring
Answer:
200 N/m
Explanation:
Hooke's Law: F = -kx
x = 10 cm = 0.10 m
k = F/x = -(-20 N)/0.10 m = 200 N/m
hydrolysis is more common in a(n) _____ climate
Hydrolysis is a chemical reaction in which water is used to break down complex molecules into simpler ones.
This process is more common in a humid or wet climate. In such climates, water is readily available and tends to accumulate in soils and rocks, leading to the formation of aqueous solutions. These solutions can then react with various minerals and organic compounds, promoting hydrolysis. Moreover, the presence of high temperatures and abundant vegetation in tropical climates accelerates the process of hydrolysis.
This results in the decomposition of organic matter, which releases nutrients and minerals that can support plant growth. Overall, hydrolysis plays a crucial role in many environmental processes and is particularly important in regions with high moisture levels.
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Water is utilised in a chemical procedure called hydrolysis to convert complicated molecules into simpler ones.
A humid or moist climate favours this procedure more frequently. In such environments, water is easily accessible and has a propensity to build up in rocks and soils, resulting in the creation of aqueous solutions. The subsequent reactions between these solutions and different minerals and organic molecules can encourage hydrolysis. Additionally, tropical areas' high temperatures and plenty of flora hasten the hydrolysis process.
This causes organic materials to decompose, releasing nutrients and minerals that can help plants flourish. Overall, hydrolysis is critical to many environmental processes and is especially significant in areas with high levels of moisture.
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explain how potential and kinetic energy are at play when we talk about Newton's second law of motion
Potential and kinetic energy are at play when we talk about Newton's second law of motion through the various positions in relation to the bodies involved.
What is Newton's second law of motion?This law states that force is equal to the rate of change of momentum and is denoted as F = mv where m is mass and v is velocity.
Potential energy is the energy is possessed by a body by virtue of its position while kinetic energy is possessed by a body by virtue of its motion. Both forms of energy are influenced by forces and are equal to the total momentum.
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find the magnitude of the torque on a circular loop in a uniform magnetic field of 0.021 tt . the radius of the loop is 5.0 cmcm , the current is 18.5 aa , and the angle between the magnetic field and a normal to the loop is 90
The magnitude of the torque on the circular loop in the given conditions is 0.003877 Nm.
The formula for the torque on a circular loop in a magnetic field is τ = NIABsinθ, where τ represents the torque, N is the number of turns in the loop, I is the current flowing through the loop, A is the area of the loop, B is the magnetic field strength, and θ is the angle between the magnetic field and a normal to the loop.
Given the values provided:
N = 1 (since it is a single loop)
I = 18.5 A
A = πr² = π(0.05 m)² = 0.00785 m²
B = 0.021 T
θ = 90 degrees
Plugging these values into the formula, we can calculate the magnitude of the torque:
τ = NIABsinθ
= (1)(18.5 A)(0.00785 m²)(0.021 T)(sin 90°)
= 0.003877 Nm
Therefore, the magnitude of the torque on the circular loop in the given conditions is 0.003877 Nm.
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What is the distance between two wave front?
The distance between two wavefronts is termed as wavelength.
The wavelength of a sound wave is defined as the space between two adjacent wavefronts. The number of wavefronts the observer detects during a period of time can be used to calculate the wave's frequency.
The medium (such as a vacuum, air, or body of water) through which a wave travels determines its wavelength. Waves can be anything from music to light to water to periodic electrical signals. While light and other electromagnetic radiation use variations in electric and magnetic field strength, sound waves are variations in air pressure. Water waves are fluctuations in a body of water's height. Atomic locations change during the shaking of a crystal lattice.
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PLZ Help Me I give you brainlist also NO LONKS OR I REPORT and Have a gr8 day my peeps
Healthy human lungs look pink and spongy from the outside. The left lung is a little smaller than the right lung to make room for the heart. The lungs and heart are both protected by the rib cage. In the lungs, each main bronchus branches off into many smaller bronchi. The bronchi become smaller and smaller, and the smallest bronchi are called bronchioles. There are about 30,000 bronchioles in each lung, each about the same thickness as a strand of hair. The inhaled air eventually ends up in tiny air sacs called alveoli at the end of each bronchiole. There are about 300 million alveoli in each lung. They are covered with capillaries, tiny blood vessels that are only one cell thick. Oxygen travels from the alveoli through the capillaries to the bloodstream, heart and other cells
Which of these best represents the progression of bronchi, bronchioles and alveoli in the lungs?
A tree trunks that become smaller branches and twigs
B a tight flower bud that has opened into a full bloom
C whole apples that are sliced into separate wedges
D a bridge that crosses two rivers
Answer:
the answer is a because I saw it in a syllabus
Answer:
just doing this so you can give brainliest to the other person
have a great day!
Explanation:
The wind blows a jay bird south with a force of 300 Newtons. The
jay bird flies north, against the wind, with a force of 100
newtons. What is the net force on the jay bird?
Answer:
F = 316.22 N
Explanation:
Given that,
The wind blows a jay bird south with a force of 300 Newtons.
The jay bird flies north, against the wind, with a force of 100 newtons.
Both the forces are acting perpendicular to each other. The net force is given by the resultant of forces as follows :
\(F=\sqrt{300^2+100^2} \\\\F=316.22\ N\)
Hence, the net force on the jay bird is 316.22 N.
what is technology?
Answer:
Technology is the application of scientific knowledge to the practical aims of human life or, as it is sometimes phrased, to the change and manipulation of the human environment.
Please Mark it as brainlist answer.