Boron has an average atomic mass of 10.81. One isotope of boron has a mass of 10.012938 and a relative abundance of 19.80%. The other isotope has a relative abundance of 80.20%. What is the mass of that isotope? Report to two decimal places. amu

The question is incomplete, the complete question is;

A certain liquid X has a normal freezing point of 5.40 °C and a freezing point depression constant K=3.05 ?kg mol solution made of 46.1g of alanine (C3H,NO2) dissolved in 750. g of i. Round your answer to 3 significant digits.

Answer:

3.3 °C

Explanation:

If ∆T= K m I

Where;

∆T = freezing point depression

K = freezing point constant

m= morality of solution

i= Van't Hoff factor

Number of moles of solute = 46.1 g/89.09 g/mol = 0.52 moles

Molality of solution = 0.52 moles /750 ×10-3Kg

= 0.69 m

∆T= 3.05 × 0.69 × 1

∆T= 2.10 °C

Freezing point of solution the solution = freezing point of pure solvent - freezing point depression

= 5.40°C - 2.10 °C

= 3.3 °C

Answer:

moles of water in 1 ml = 1/18 mol.

take 1 ml and calculate it by 30

1 ml x 30= 30 ml

Explanation:

Answer:

Explanation:

Answer:

6.02×10^23 I hope it helps you

Explanation:

I hope it helps you

The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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We have the concentration of H+ ions, from these concentrations we can find the pH values of the solutions with the following equation:

Where [H+] is the concentration of H+ ions.

Now, the acidity or basicity of a solution depends on the pH value. A solution above 7 will be basic, below 7 will be acidic, and equal to 7 will be neutral.

Let's determine the pH value for each solution:

So, we have that:

A. [H+] = 4.3 × 10-3 mol/L. pH=2.4. Acidic

B. [H+] = 9.8 × 10-12 mol/L pH = 11.0 Basic

C. [OH-] = 4.8 × 10-2 mol/L pH=1.3 Acidic



Answer:

2-bromopentane

Explanation:

In this case, we have a substitution. An Sn2 reaction. With this in mind, we have to identify the leaving group in this case "OH" from the 2-pentanol. The nucleophile is a "Br" atom provided by the PBr3. So, the "OH" would be replaced by "Br". If we have an Sn2 reaction we will have an inversion in the configuration. If we start with a wedge bond for "OH" we will have a dashed bond for "Br", if we have a dashed bond for "OH" we will have a wedge bond for "Br". In the 2-pentanol we have any special configuration because we don't have a chiral carbon, so we can have both options (wedge and dashed) for the product (See figure 1).

When the reaction of  Grignard reagent reacted with methanol will yield a tertiary alcohol. Therefore, Option C tertiary alcohol is correct.

Contains a carbon-metal link, Grignard reagents are chemicals used in catalysis. They generally result from the anhydrous reaction of magnesium metal with an alkyl or aryl halide. Because of their high reactivity, Grignard reagents frequently act as nucleophiles in organic reactions.

An alkyl group from a Grignard reagent binds to the oxygen atom of methanol (CH3OH) when it interacts with the methanol, breaking the carbon-metal connection. A precursor alkoxide is created as a result. The equivalent alcohol is then produced by protonating the intermediate alkoxide.

The reaction of a Grignard reagent with methanol leads to the formation of a tertiary alcohol.

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Answer:

The answer is B "circulate and move within a liquid or gas"

Answer:

Store the genetic instructions needed to specify traits.

In DNA, the primary function of chromosome is store the genetic instructions needed to specify traits.

DNA is a hereditary material  which is present in human beings as well as all other living organisms.  Every cell which is present in an organism's body has DNA  which is the same. Most of the DNA is situated in the cell's nucleus and small amount of it can be found in the cell's mitochondria as well.

Information which is stored in DNA is stored as codes made up of four chemical bases namely, adenine, thymine , cytosine and guanine.Human DNA consists of 3 billion bases .The order of the bases determines information which is required for building and maintaining an organism.

DNA bases are capable of pairing up with each other. Adenine pairs with thymine and guanine pairs up with cytosine .Each base is also attached to a sugar molecule  and a phosphate group. A base, phosphate  sugar are together called as nucleotides.

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Answer:

Single replacement reaction

Explanation:

Let us try to write down the reaction equation for the reaction of a magnesium  ribbon with hydrochloric acid.

Mg(s) + 2HCl(aq) ------> MgCl2(aq) + H2(g)

A single replacement reaction is a type of chemical reaction in which one element is replaced by another element in a compound.

In this reaction, magnesium replaced hydrogen to form the product. Hence it is a single replacement reaction.

Answer:

d=m/

Explanation:

d is density, m is mass, v is volume

Given: m =10.4g, v=12.2mL

substituting in equation,

d=10.4/ 12.2

d=0.8524g/mL

To learn more about density:

The density of the liquid is 0.852 g/mL.

To calculate the density of the liquid, we need to use the formula:

Density = Mass / Volume

Given that the mass of the liquid is 10.4 g and the volume is 12.2 mL, we can substitute these values into the formula:

Density = 10.4 g / 12.2 mL

Simplifying this expression, we find:

Density = 0.852 g/mL

Density is a physical property of a substance and is defined as the amount of mass per unit volume. In this case, the density tells us that for every milliliter of the liquid, there is 0.852 grams of mass. The units of grams per milliliter (g/mL) indicate that the density is a ratio of mass to volume.It is important to note that the density of a substance can vary with temperature, so this value is only valid under the conditions at which the measurement was made. Additionally, the density can provide valuable information about the identity of a substance, as different substances have different densities.

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Answer:

magma

Explanation:

brainly me and il give reason in comment

Answer:

Presence of impurities in the product.

Explanation:

Laboratory experience has shown that the percent yield obtained from a reaction may be greater than 100% if the product obtained from the reaction contains impurities that causes its mass to be greater than it actually would be if the product was pure.

A typical impurity that may be present in a product is the solvent used. This can be removed by evaporation of the solvent or by washing the product thoroughly.

Reaction of solid products with gases may also increase the percentage yield above 100%.

Answer:

true

Explanation:

...................

Answer:

(8.3×40)+(8.3×71)

921.3grames

Answer:

\(\Large \boxed{\sf 921.3 \ g}\)

Explanation:

Use formula

\(\displaystyle moles=\frac{mass}{M_r}\)

\(M_r=40+35.5 \times 2 = 111\)

Solve for mass

\(mass=8.3 \times 111=921.3\)

The terrain can have a significant impact on the behavior and spread of forest fires. Understanding the terrain and its effect on fires can help firefighters and land managers develop effective strategies for preventing and managing wildfires.

Terrain plays a significant role in the behavior and spread of forest fires. Here are some ways that terrain can affect forest fires:

Slope: The slope of the terrain can affect the speed and direction of the fire. Fires tend to spread faster uphill due to the preheating effect of the rising heat, which dries out the fuel and ignites it more easily. Steep slopes can also create a chimney effect, where hot gases and flames rise rapidly, increasing the intensity of the fire and making it more difficult to control.

Aspect: The aspect, or the direction that a slope faces, can also impact the behavior of a forest fire. South-facing slopes tend to be warmer and drier, and may ignite more easily. North-facing slopes, on the other hand, may be cooler and moister, and may not burn as easily.

Topography: The topography of the terrain can affect the spread of fire by creating wind patterns, funneling the fire, or obstructing firefighting efforts. For example, canyons, ridges, and valleys can channel and accelerate the spread of the fire, while cliffs, boulders, and waterways can create natural fire breaks that help to contain the fire.

Fuel type and density: The type and density of vegetation in a forest can vary depending on the terrain. For example, steep slopes may have thinner vegetation cover, while flat areas may have thicker vegetation. The type of vegetation can also vary by elevation, with lower elevations having more grasses and shrubs, and higher elevations having more trees. Different types of vegetation burn at different rates and temperatures, and can affect the intensity and behavior of the fire.

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The net ionic equation of the reaction is as follows:

4 Al3+(aq) + 12 NO3-(aq) + 3 Ag(s) = 4 Al(s) + 12 Ag+(aq) + 12 NO3-(aq)

Ions which remain in their ground state and do not take part in the reaction are called spectator ions. The net ionic equation cancels out these ions, which are present on both the reactant and product sides of the equation.

Spectator ions, which can be found on both the reactant and product sides, but are not included in the finished reaction from the net ionic equation. The \(NO^3^-\) ions are spectator ions in this example, thus taking them out of the equation. The net ionic equation makes up the rest of the species.

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Density of neutron is 3.9868×10¹⁷kg/m³

Here given data is radius of a neutron=1.0×10⁻¹³ we have to calculate density of neutron=?

Density=mass/volume

For calculations of density of neutron volume is not given here so volume of sphere is 4/3πr³

So ,neutron stars are composed of solid nuclear matter, primarily neutrons

Vₙ=4/3πr³

= 4/3π(1.0×10⁻¹³ × 10⁻²)³

= 4/3π((1.0×10⁻¹⁵)³

= 4.1888×10⁻⁴⁵m³ this is the volume of neutron

Neutron stars are composed of solid nuclear matter, primarily neutrons.

Assuming that a neutron star has the same density as a neutron then,

Density=mass/volume

mass of neutron=1.67×10⁻²⁷

Density=1.67×10⁻²⁷kg/4.1888×10⁻⁴⁵m³

= 3.9868×10¹⁷kg/m³ is the density of neutron

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The standard enthalpy of formation (Δ\(H_f\)) is a measure of the energy released or consumed when one mole of a substance is created under standard conditions from its pure elements.

Standard enthalpies (Δ\(H_f\)) of formation for given reaction is 978.3 kJ

The standard enthalpy of formation is defined as the enthalpy change when one mole of a substance in the standard state (1 atm of pressure and 298.15 K) is formed from its pure elements under the same conditions.

Given reaction ;

\(N_2O_4(g) + 4H_2 (g) - > N_2(g) + 4H_2O(g)\)

To Find : Δ\(H_f\)

Δ\(H_f\) = ∑np Δ\(H_f\) (products) – ∑np Δ\(H_f\) (reactants)

Δ\(H_f\) = [1(Δ\(H_f\) \(N_2\)) + 4(Δ\(H_f\) \(H_2O\))] – [1(Δ\(H_f\) \(N_2O_4\)) + 4(Δ\(H_f\) \(H_2\))]

Δ\(H_f\) = [1(0) + 4(-241.8)] – [1(+9.16) + 4(0)]

Δ\(H_f\)  = [4(-241.8)] – [1(+9.16)] = 978.3 kJ

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Answer:

2.8 moles BrO₃⁻

Explanation:

To find the amount of moles, you need to convert moles Br₂ to moles BrO₃⁻ using the mole-to-mole ratio. This ratio is made up of the balanced equation coefficients in front of the relevant molecules.

3 Br₂ + 6 OH⁻ -----> 5 Br⁻ + 1 BrO₃⁻ + 3 H₂O

8.5 moles Br₂           1 mole BrO₃⁻
-----------------------  x  ----------------------  =  2.8 moles BrO₃⁻
                                  3 moles Br₂

Precision relates to the consistency and reproducibility of measurements, while accuracy reflects how close measurements are to the true value.

Precision and accuracy are two important concepts in the context of errors in measurements. While they both pertain to the quality of data, they refer to different aspects.

Precision refers to the degree of consistency or reproducibility in a series of measurements. It reflects the scatter or spread of data points around the average value. If the measurements have low scatter and are tightly clustered, they are considered precise. On the other hand, if the measurements have a high scatter and are widely dispersed, they are considered imprecise.

Accuracy, on the other hand, refers to the closeness of measurements to the true or target value. It represents how well the measured values align with the actual value. Accuracy is achieved when measurements have a small systematic or constant error, which is the difference between the average measured value and the true value.

Errors in measurements can be classified into two types: random errors and systematic errors.

Random errors are associated with the inherent limitations of measurement instruments or fluctuations in the measurement process. They lead to imprecise data and affect the precision of measurements. Random errors can be reduced by repeating measurements and calculating the average to minimize the effect of individual errors.

Systematic errors, on the other hand, are caused by consistent biases or inaccuracies in the measurement process. They affect the accuracy of measurements and lead to a deviation from the true value. Systematic errors can arise from factors such as instrumental calibration issues, environmental conditions, or experimental techniques. These errors need to be identified and minimized to improve the accuracy of measurements.

In summary, precision refers to the degree of consistency or reproducibility of measurements, while accuracy refers to the closeness of measurements to the true value. Random errors affect precision, while systematic errors affect accuracy. To ensure high-quality measurements, both precision and accuracy need to be considered and appropriate techniques should be employed to minimize errors.

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Titrations in the Redox Titration lab carried out in an acidic solution because the presence of an acid is necessary to facilitate this transfer of electrons.  the hydrogen ions (H+) in the solution act as a catalyst.

Redox titrations involve the transfer of electrons between the reactants, and the presence of an acid is necessary to facilitate this transfer of electrons. In an acidic solution, the hydrogen ions (H+) in the solution act as a catalyst for the oxidation-reduction reactions.

In particular, the acid helps to dissolve and ionize the substance being titrated, and also provides a source of protons and a low pH that favor the reduction or oxidation of the analyte. For example, in the titration of iron with potassium permanganate, the iron reacts with permanganate ion (MnO4-) in the acidic solution to produce a reddish-brown precipitate of iron(III) oxide, Fe2O3.

Fe2+ + MnO4- + 8H+ → Mn2+ + Fe2O3 + 4H2O

If the solution were not acidic, the permanganate ion would be reduced by water instead of by the iron, which would make the reaction difficult to follow and less precise.

Furthermore, the acidic solution also helps to prevent the reduction of the oxidizing agent by atmospheric oxygen, which could cause errors in the titration.

Therefore, the presence of an acid is essential for the success of a redox titration, and the type and concentration of acid used should be carefully chosen based on the analyte and oxidizing agent being used.

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Answer:

14.9 mol

Explanation:

To find the number of moles in a given mass of a sample of sodium chloride (NaCl), we can multiply the number of grams in the sample by the molar mass of sodium chloride, which is 58.44 g/mol.

871 g × (1 mol / 58.44 g)

= 871/58.44 mol

≈ 14.9 mol

Note that we rounded to 3 significant figures in the final answer because that is how many significant figures were given in the mass measurement of the sodium chloride sample.

Answer:

B.

Explanation:

There are the same amount of black circles in the reactant and product. There are also the same amount of white circles in the product and reactant.

C) Their structure is related to their function

DNA (deoxyribonucleic acid) is the genetic material of humans and almost all other organisms. mostly every cell in the human body has the same DNA. Most DNA is found in the nucleus of cells, but small amounts of DNA can also be found in the mitochondria, also called mtDNA. Mitochondria are structures within cells that convert food energy into a form the cell can use

Mutation is one of the functions of DNA.  A mutation is a change in the DNA sequence of an organism. Mutation can occur because of many circumstances. Our DNA has gone through mutations that created humans out of monkeys. the evolution of mankind is because of mutation in DNA.

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Answer:

NH₃

M = n/V(L)

0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)

Explanation:

Step 1: Given and required data

Step 2: Calculate the moles (n) of ammonia (solute)

Molarity is equal to the moles of solute divided by the liters of solution.

M = n/V(L)

n = M × V(L)

n = 2.25 mol/L × 0.375 L = 0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)

The term that refers to the passing of a wave through an object is "transmission."

Transmission refers to the process by which a wave passes through an object or medium. In the context of sound, transmission occurs when sound waves travel through different substances, such as air, water, or solids.

When a sound wave encounters an object, it can be transmitted through it, reflected off it, or absorbed by it, depending on the properties of the object and the medium through which the sound is traveling.

For example, when you speak into a microphone, the sound waves produced by your voice travel through the air and are transmitted to the microphone's diaphragm. The diaphragm converts the sound waves into electrical signals, which can then be amplified and reproduced as sound through speakers.

In summary, transmission is the term used to describe the passage of a wave, such as a sound wave, through an object or medium. It is an essential concept in understanding how waves interact with their surroundings and how sound propagates through different materials.

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