Billy is in physical science class and starts out with 12 grams of sodium hydroxide (baking soda) as part of an experiment the class is doing. Based on your knowledge of the law of conservation of mass, how many grams should Billy have after the experiment is finished?

Answers

Answer 1

Answer:

Explanation:

Please do not confuse Baking soda, also known as Sodium bicarbonate NaHCO₃ with Sodium hydroxide  NaOH which is also known as Lye, and is a very corrosive chemical used in drain and oven cleaners, soaps and bleaches.

One is generally considered safe for cooking, the other not so much.

There should be the same mass of reactants and products in each experiment.

If you start with 12 grams of reactants, you will have 12 grams of products.


Related Questions

Energy of a wave is measured in terms of the wave's Choose... .

Answers

The energy of a wave is measured in terms of the wave's amplitude.

What is the energy of a wave?

The energy of a wave depends on the amplitude and the frequency of of the wave.

The energy of a wave is directly proportional to the square of the wave's amplitude.

Mathematically, the formula for energy of a wave is given as;

E = ¹/₂μω²A²

where;

μ is the mass per unit length of the stringω is the angular velocity of the waveA is the amplitude of the waveE is the energy of the wave

So based on the formula given above, energy of a wave is proportional to the square of wave's amplitude and square of angular frequency of the wave.

Thus, we can conclude that the energy of a wave is measured in terms of the wave's amplitude because the energy of the wave is function of maximum displacement of the wave (wave amplitude).

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The diagram below shows a star map. Which position would a planet most likely be at? A, B, C, or D?

The diagram below shows a star map. Which position would a planet most likely be at? A, B, C, or D?

Answers

I think c but I’m not sure so don’t use mine

How do supersonic flights create sonic boom? Please explain in detail.

Answers

Supersonic flights are moving with speed greater than that of sound. This speed through air will combine the pressure waves and creates shock waves. Continuation of shock waves leads to sonic boom in air.

What is sonic boom ?

Sonic booms are sound created on the ground by overpressure in the air generated by fastly moving objects. Similar to someone dumping goods from a moving car, an aircraft travelling at supersonic speeds continuously produces shock waves that cause sonic booms to travel throughout its flight path.

The boom seems to be swept rearward as it moves away from the aeroplane from its point of view. The boom will strike the ground in front of the aircraft if the aircraft makes a rapid turn or pulls up.

The abrupt start and release of pressure following the building by the shock wave or "peak overpressure" is what is heard as a "sonic boom" on the ground. Only a few pounds per square foot change in pressure results from a sonic boom, which is about equivalent to the pressure shift we experience in an elevator.

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A 1000 kg rollercoaster requires a braking force of 8780N from point D to point E in order to stop. Find
a) The Total Mechanical Energy of the rollercoaster at Point A. b) The velocity of the coaster at point A. c)
The velocity of the coaster at point B. d) The highest hill the coaster could have gotten over before point A
with no additional mechanical energy. (Ans. a) 591,100 J b) 2.5 m/s c) 34.4 m/s d) 60.3 m)

A 1000 kg rollercoaster requires a braking force of 8780N from point D to point E in order to stop. Finda)

Answers

On the rollercoaster:

a) The Total Mechanical Energy at Point A: 591,100 Jb) The velocity of the coaster at Point A: 34.4 m/sc) The velocity of the coaster at Point B: 34.4 m/sd) The highest hill the coaster could have gotten over before Point A with no additional mechanical energy: 60.3 m

How to solve conservation of energy?

To solve this problem, apply the principles of conservation of energy. Use the following equations:

a) The Total Mechanical Energy (TME) at any point can be calculated using the formula: TME = Potential Energy + Kinetic Energy.

b) The velocity of the coaster can be calculated using the equation: Kinetic Energy = (1/2)mv², where m = mass of the rollercoaster.

c) The velocity of the coaster at point B can be calculated using the conservation of energy principle. So, equate the Potential Energy + Kinetic Energy at point A to the Potential Energy + Kinetic Energy at point B and solve for velocity at point B.

d) Calculate the height of point A using the formula: Potential Energy = mgh, where m is the mass of the rollercoaster, g is the acceleration due to gravity, and h is the height.

Given:

Mass of rollercoaster (m) = 1000 kg

Braking force (F) = 8780 N

Let's calculate each part of the problem:

a) The Total Mechanical Energy at Point A:

TME = Potential Energy + Kinetic Energy

Since the rollercoaster is at the highest point (A) and it's not moving, the Kinetic Energy is zero.

Potential Energy = mgh

Potential Energy at Point A = (1000 kg)(9.8 m/s²)(h) = TME

TME = 591,100 J

b) The velocity of the coaster at Point A:

Using the Total Mechanical Energy calculated in part a, calculate the velocity using the formula:

TME = (1/2)mv²

591,100 J = (1/2)(1000 kg)(v²)

v² = (2 × 591,100 J) / (1000 kg)

v² = 1182.2 m²/s²

v = √(1182.2) ≈ 34.4 m/s

c) The velocity of the coaster at Point B:

Using the conservation of energy principle, equate the TME at Point A to the TME at Point B:

Potential Energy at Point A + Kinetic Energy at Point A = Potential Energy at Point B + Kinetic Energy at Point B

mgh + (1/2)mv² = mgh' + (1/2)mv'²

Since the coaster starts from rest at Point A, the Kinetic Energy is zero.

mgh = mgh' + 0

gh = gh'

34.4 m/s = √(2 × 9.8 m/s² × h')

h' = (34.4 m/s)² / (2 × 9.8 m/s²) ≈ 60.3 m

d) The highest hill the coaster could have gotten over before Point A with no additional mechanical energy is the height at Point A, is calculated to be approximately 60.3 meters.

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Action and reacion forces are described by which of Newton's laws of motion?
O first
O second
Othird
O fourth

Answers

third
every action has an opposite and equal reaction

What are the most promising theoretical models for describing the strong force interactions between quarks and gluons within a proton and how do these models address the challenge of non-perturbative effects such as confinement and chiral symmetry breaking in Quantum Chromodynamics?

Answers

The models provide important tools for understanding the strong force interactions within a proton.

What is Quantum Chromodynamics?

The strong force interactions between quarks and gluons within a proton are described by Quantum Chromodynamics (QCD), which is a fundamental theory of the strong nuclear force in particle physics. QCD is a non-Abelian gauge theory, meaning that the interactions between the quarks and gluons are highly nonlinear and non-perturbative.

What is Lattice QCD?

One of the most promising theoretical models for describing the strong force interactions within a proton is lattice QCD, which is a numerical approach that uses a discrete grid to represent the space-time continuum. Lattice QCD allows for the calculation of QCD observables from first principles, without resorting to perturbative expansions. This method can handle non-perturbative effects such as confinement and chiral symmetry breaking by allowing for the simulation of the strong interactions on a discrete space-time grid

What is Effective Field Theory?

Another promising model is effective field theory, which provides a way to describe the low-energy behavior of QCD by constructing an effective Lagrangian that contains only the degrees of freedom relevant to a particular energy scale. This allows for the calculation of QCD observables in a systematic expansion in powers of a small parameter, such as the ratio of the quark mass to the QCD energy scale.

What is Chiral perturbation theory?

Chiral perturbation theory is another effective field theory that focuses on the dynamics of light quarks, which are the building blocks of pions, the lightest hadrons. Chiral perturbation theory provides a systematic expansion for the interactions between pions and nucleons, and can be used to calculate the properties of these particles at low energies.

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Given vector A with magnitude 2N and vector B magnitude 4N, what are the minimum and maximum magnitudes of A+B?​

Answers

-- If A and B are pointing in exactly opposite directions, then their sum A+B is the minimum possible value.  A+B = 2 N in the same direction as B.

-- If A and B are pointing in exactly the same direction, then their sum A+B is the maximum possible value.  A+B = 6 N in that same direction.  

Melvina has a mass of 70 kg and is about to jump from the window ledge of a burning building.
The ledge is 80 m above the ground. What is Melvina's potential energy?

Answers

Melvina's potential energy is 54,880 Joules.

To calculate Melvina's potential energy, we need to use the formula for gravitational potential energy:

Potential energy = mass × gravitational acceleration × height

Potential energy is a measure of the energy an object possesses due to its position relative to other objects. In this case, Melvina's potential energy is a result of her height above the ground. As she stands on the ledge of the burning building, her potential energy is stored and can be converted into other forms of energy if she were to jump or fall. The potential energy will decrease as she descends, and it will be converted into kinetic energy (energy of motion).

Given that Melvina has a mass of 70 kg and the ledge is 80 m above the ground, we can substitute the values into the formula:

Potential energy = 70 kg × 9.8 m/s² × 80 m

Calculating this, we find:

Potential energy = 54,880 Joules

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explain melting and freezing using the kinetic theory of matter​

Answers

As a liquid is cooled its molecules lose kinetic energy and their motion slows. When they've slowed to where intermolecular attractive forces exceed the collisional forces from random motion, then a phase transition from liquid to solid state takes place and the material freezes

Hope it helps u

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A rigid body is rotating with constant angular speed 3 radians per second about a fixed axis through the points A. (4, 1, 1), B. (2, -1; 0), distances being measured in centimeters. The rotation is in the left-handed sense relative to the direction AB
1, Determine the unit vector pointing in the direction BA.
2, What is the angular velocity () of the of the body?
3, Write the position vector of point P: P .
Find the instantaneous velocity of particle P [hint v = w×r)
4, What is meant by left-handed rotation (left-handed coordinate system)?
5, Write the position vectors of points A and B The rotation axis AB has direction BA. Write the direction BA in terms of the components given above. ​

Answers

1.Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)

2.The angular velocity (ω) of the body is given as 3 radians per second.

3.Without the position of point P given, it is not possible to write the position vector of P.

4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule.

5.Position vector of point A: (4, 1, 1)

Position vector of point B: (2, -1, 0)

The direction vector BA = (-2, -2, -1)

1.To determine the unit vector pointing in the direction BA, we subtract the coordinates of point B from the coordinates of point A and normalize the resulting vector.

The direction vector BA is given by:

BA = (4 - 2, 1 - (-1), 1 - 0) = (2, 2, 1)

To obtain the unit vector in the direction of BA, we divide the direction vector by its magnitude:

|BA| = √(2^2 + 2^2 + 1^2) = √(4 + 4 + 1) = √9 = 3

Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)

2.The angular velocity (ω) of the body is given as 3 radians per second.

3.Without the position of point P given, it is not possible to write the position vector of P. Please provide the position of point P to proceed with the calculation.

4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule. In a left-handed coordinate system, if you curl the fingers of your left hand in the direction of rotation, your thumb will point in the direction of the rotation axis. It is the opposite direction to a right-handed rotation.

5.The position vectors of points A and B are:

Position vector of point A: (4, 1, 1)

Position vector of point B: (2, -1, 0)

The direction vector BA can be obtained by subtracting the coordinates of point A from the coordinates of point B:

BA = (2 - 4, -1 - 1, 0 - 1) = (-2, -2, -1)

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at a construction site a crane lift a steel beam with a mass of 330 KG iii. while it is being lifted the steel beam is at a height of 20 m and is moving with the speed of 1.3 m/s what is the total mechanical energy of the steel beam at this moment

Answers

Answer:

TME= 65,000J

Explanation:

TME=mgh+1/2mv^2=300kg

(9.8m/s^220m+1/2mv^2(1.3m/s)^2)

At a construction site a crane lift a steel beam with a mass of 330 KG iii. while it is being lifted the steel beam is at a height of 20 m and is moving with the speed of 1.3 m/s,the total mechanical energy of the steel beam at this moment would be 65024.85 Joules.

What is mechanical energy?

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.

As total mechanical energy is the sum of all the kinetic as well potential energy stored in the system.

ME = KE + PE


The total kinetic energy of blue green would be
KE = 1/2*m*v²

KE = 0.5*330*1.3²

KE = 278.85 Joules


Similarly the total potential energy of the crane lift would be

PE = m*g*h

PE = 330*9.81*20

PE = 64746 Joules


As we know that the total mechanical energy of the system at a given moment is the sum of the total kinetic energy added to the total potential energy therefore The total mechanical energy of the crane  lift at this moment would be


ME = 278.85 + 64746

ME =65024.85

Thus, the total mechanical energy of the steel beam at this moment would be 65024.85 Joules.

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Calculate the height of an image in a converging lens with a height of 6.1 cm, an image location of 6.2 cm, and a distance of 3.6 cm for the object's placement from the lens. Final answer will have 2 decimal places and might not follow sig fig rules.

Answers

the formula we will use is

1/f = 1/p + 1/q

where f is = focal length

p is the distance away (distance from the lens to the object)

and q is the image distance

What will the reading of the voltmeter be at the instant the switch returns to position a if the inertia of the d'Arsonval movement is negligible

Answers

Answer:

hello your question is incomplete attached below is the complete question

answer :

20.16 v

Explanation:

The reading of the voltmeter at the instant the switch returns  to position a

L = 5H

i ( current through inductor ) = 1/L ∫ V(t) d(t) + Vo

                                               = 1/5 ∫ 3*10^-3  d(t)  + 0 = 0.6 * 10^-3 t

iL ( 1.6 s ) = 0.6 * 10^-3 * 1.6 = 0.96 mA

Rm ( resistance ) = 21 * 1000 = 21 kΩ

 The reading of the voltmeter ( V )

V = IR

   = 0.96 mA * 21 k Ω  = 20.16 v

What will the reading of the voltmeter be at the instant the switch returns to position a if the inertia

A new planet has been discovered and given the name Planet X . The mass of Planet X is estimated to be one-half that of Earth, and the radius of Planet X is estimated to be twice that of Earth. The estimated mass and radius of Planet X are used to calculate the minimum escape speed, vc , for an object launched from the surface of the planet. If the actual mass and/or radius of the planet are slightly different from the estimated values.

Required:
How will the actual escape speed va for the surface of Planet X compare to vc?

Answers

Answer:

    vₐ = v_c  \(( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )\)

Explanation:

To calculate the escape velocity let's use the conservation of energy

starting point. On the surface of the planet

          Em₀ = K + U = ½ m v_c² - G Mm / R

final point. At a very distant point

         Em_f = U = - G Mm / R₂

energy is conserved

           Em₀ = Em_f

           ½ m v_c² - G Mm / R = - G Mm / R₂

           v_c² = 2 G M (1 /R -  1 /R₂)

if we consider the speed so that it reaches an infinite position R₂ = ∞

           v_c = \(\sqrt{\frac{2GM}{R} }\)

now indicates that the mass and radius of the planet changes slightly

            M ’= M + ΔM = M ( \(1+ \frac{\Delta M}{M}\) )

            R ’= R + ΔR = R ( \(1 + \frac{\Delta R}{R}\) )

we substitute

           vₐ = \(\sqrt{\frac{2GM}{R} } \ \frac{\sqrt{1+ \frac{\Delta M}{M} } }{ \sqrt{1+ \frac{ \Delta R}{R} } }\)

         

let's use a serial expansion

           √(1 ±x) = 1 ± ½ x +…

we substitute

         vₐ = v_ c ( \((1 + \frac{1}{2} \frac{\Delta M}{M} ) \ ( 1 - \frac{1}{2} \frac{\Delta R}{R} )\))

we make the product and keep the terms linear

        vₐ = v_c  \(( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )\)

The minimum escape speed, vc , for an object launched from the surface of the planet will be    \(v_a=v_c(1+\dfrac{1}{2}(\dfrac{\Delta M}{M}-\dfrac{\Delta R}{R})\)

What is escape velocity of the planet?

The escape velocity is defined as the velocity required to send the object out of the gravitational influence of the earth.

To calculate the escape velocity let's use the conservation of energy

starting point. On the surface of the planet

    \(E_{mo} = K + U = \dfrac{1}{2} m v_c^2 - \dfrac{G Mm} { R}\)

final point. At a very distant point

      \(E_{mf} = U = \dfrac{- G Mm }{ R_2}\)

energy is conserved

         \(E{mo} = E{mf}\)

          \(\dfrac{1}{2}m v_c^2 - \dfrac{G Mm} {R} = \dfrac{- G Mm }{ R_2}\)

\(v_c^2 = 2 G M (\dfrac{1} {R} - \dfrac{ 1 }{R_2})\)

if we consider the speed so that it reaches an infinite position R₂ = ∞

\(v_c = \sqrt{\dfrac{2GM}{R}\)

         

now indicates that the mass and radius of the planet changes slightly

\(M ’= M + \Delta M = M(1+\dfrac{\Delta M}{M})\)  

\(R ’= R + \Delta R = R (1+\dfrac{\Delta R}{R} )\)

we substitute

   \(vₐ = \sqrt{\dfrac{2GM}{R} }\dfrac{\sqrt{1+\dfrac{\Delta M}{M}}} {\sqrt{1+\dfrac{\Delta R}{R}}}\)

let's use a serial expansion

√(1 ±x) = 1 ± ½ x +…

we substitute

      \(v_a=v_c(1+\dfrac{1}{2}\dfrac{\Delta M}{M})(1-\dfrac{1}{2}\dfrac\Delta R}{R})\)

Hence the minimum escape speed, vc , for an object launched from the surface of the planet will be    \(v_a=v_c(1+\dfrac{1}{2}(\dfrac{\Delta M}{M}-\dfrac{\Delta R}{R})\)

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define standard atmospheric pressure ​

Answers

Standard atmospheric pressure is the average pressure exerted by the Earth's atmosphere at sea level under normal conditions. It is defined as 101.325 kPa or 1 atm and serves as a reference point for scientific measurements and comparisons related to atmospheric pressure.

Standard atmospheric pressure is the average pressure exerted by the Earth's atmosphere at sea level under normal conditions. It is defined as 101.325 kilopascals (kPa) or 1 atmosphere (atm). This pressure is used as a reference point for various scientific measurements and is crucial in fields such as meteorology, physics, and engineering.

Atmospheric pressure is caused by the weight of the air above a given point on the Earth's surface. The air is composed of molecules, mainly nitrogen (approximately 78%) and oxygen (approximately 21%), along with other trace gases. These molecules are in constant motion and exert a force on the surfaces they come into contact with, including the Earth's surface.

The standard atmospheric pressure of 101.325 kPa is equivalent to the pressure exerted by a column of mercury 760 millimeters (mm) in height in a barometer at sea level. This measurement was established as a reference point for atmospheric pressure, providing a consistent value for scientific calculations and comparisons.

It is important to note that atmospheric pressure can vary with altitude and weather conditions. As altitude increases, the atmospheric pressure decreases because the column of air above becomes thinner. In areas of high or low pressure systems associated with weather patterns, the atmospheric pressure deviates from the standard value.

The standard atmospheric pressure is a valuable reference in many applications. For instance, it is used as a standard for measuring gas pressure in laboratories and industrial processes. It is also used in meteorology to calculate and compare pressure systems and to study atmospheric phenomena such as wind patterns and weather changes.

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Final Answer:

If there is lower air pressure being "pushed" onto the surface of the water, then the water molecules do not need as much energy to overcome the force of atmospheric pressure pushing on the surface, and they can more easily escape and become a vapor. When the vapor pressure of the liquid is equal to the air pressure surrounding the liquid, it will boil. If you lower the air pressure, you will lower the temperature that water will boil at.

Explanation:

The boiling point of a liquid depends on the balance between the vapor pressure of the liquid and the external pressure, which is typically atmospheric pressure. When the external pressure is reduced, such as at higher altitudes or in a vacuum, the liquid molecules require less energy to escape the surface and become vapor. This is because there is less force pushing down on the liquid's surface, allowing for easier vaporization.

At lower air pressure, the water molecules can overcome the diminished force of atmospheric pressure more readily, requiring less heat energy to transition from liquid to vapor. When the vapor pressure of the liquid equals the surrounding air pressure, the liquid will start to boil.

Boiling point and vapor pressure are fundamental concepts in thermodynamics and phase transitions. Understanding how pressure affects the boiling point of liquids is crucial in various scientific and engineering applications, such as cooking, chemical processes, and high-altitude cooking.

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Calculate the molar heat capacity at pressure and volume constant ( ) when knowing = = 1.4 and the gas density: 0 = 1.3 /3 .

Answers

(a) The molar heat capacity at pressure is 29.1 J/K.mol.

(b) The molar heat capacity at volume is 20.785 J/K.mol.

Molar heat capacity of gas at volume

Molar heat capacity of a gas at constant volume is defined as the quantity of heat required to raise the temperature of one mole of the gas by 1 degree Kelvin when its volume is constant.

Cv = R/(γ - 1)

where;

R is universal gas constant = 8.314 J/K.mol.γ is heat ratio = 1.4

Cv = (8.314) / (1.4 - 1)

Cv = 20.785 J/K.mol

Molar heat capacity of gas at pressure

Molar heat capacity of a gas at constant volume is defined as the quantity of heat required to raise the temperature of one mole of the gas by 1 degree Kelvin when its pressure is constant.

γ = Cp/Cv

Cp = γCv

Cp = 1.4 x 20.785

Cp = 29.1 J/K.mol

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For this question you will be designing an investigation Carefully read the information below and respond to the prompt
Does the temperature of a liquid affect the amount of sugar it will dissolve? In other words, if you change the temperature of a liquid, is there a
relationship between the temperature and how much sugar can dissolve at that specific temperature?
Tell how you would test this question, being as scientific as possible (including the different variables, constants, hypothesis, safety considerations, data
tables, etc.) when you write about your test. Write down the steps you would take to find out if the temperature of a liquid affects the amount of sugar it
can dissolve

Answers

Answer:

See Explanation

Explanation:

Temperature affects the amount of sugar that will be dissolved in a liquid. It is general knowledge in chemistry that solutes tend to dissolve in hot solvents compared to cold solvents.

Hence, there is a positive relationship between dissolution of sugar in a liquid and increase in temperature.

To test this hypothesis, the variables are temperature and amount of solute. The volume of solvent and type of solvent must be held constant.

Different amounts of solute are dissolved in the same volume of solvent and heated to a constant temperature and the extent of dissolution of the sugar is observed for each experimental unit.

A control experiment is also set up in which different amount of sugar is dissolved in the same volume of solvent as above without heating and the results are compared.

A box with mass 40.7 kg (m) is pulled up a 14.5° (0₁) incline with a coefficient of kinetic friction (H) of .17. The force pulling the box (Fp) is 173 N and is applied at a 25.7° (0₂) above the parallel to the plane. What is the boxes acceleration up the ramp?
thanks !!​

Answers

The boxes acceleration up the ramp is approximately 0.109 m/s².

The forces acting on the box can be resolved into two components: one parallel to the incline (F_parallel) and one perpendicular to the incline (F_perpendicular).

Given:

Mass of the box (m) = 40.7 kg

Coefficient of kinetic friction (μ) = 0.17

The force pulling the box (F_p) = 173 N

Incline angle (θ₁) = 14.5°

Force angle (θ₂) = 25.7°

First, we need to calculate the components of the force pulling the box:

F_parallel = F_p * sin(θ₂)

F_perpendicular = F_p * cos(θ₂)

Next, let's calculate the force of friction:

F_friction = μ * (mass of the box) * g, where g is the acceleration due to gravity (approximately 9.8 m/s²)

The force component parallel to the incline is opposed by the force of friction, so:

Net force parallel to the incline (F_net_parallel) = F_parallel - F_friction

Now, we can calculate the acceleration using Newton's second law:

F_net_parallel = (mass of the box) * acceleration

Rearranging the equation, we get:

acceleration = F_net_parallel / (mass of the box)

Now we can substitute the values into the equations and calculate the acceleration

F_parallel = 173 N * sin(25.7°) ≈ 73.88 N

F_perpendicular = 173 N * cos(25.7°) ≈ 154.37 N

F_friction = 0.17 * (40.7 kg) * 9.8 m/s² ≈ 69.44 N

F_net_parallel = F_parallel - F_friction ≈ 73.88 N - 69.44 N ≈ 4.44 N

acceleration = (4.44 N) / (40.7 kg) ≈ 0.109 m/s²

Therefore, the box's acceleration up the ramp is approximately 0.109 m/s².

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Water flows at speed v in a pipe of radius r. Neglecting viscosity, at what speed does the water flow through a constriction in which the radius of the pipe is r/3

Answers

Answer:

9v

Explanation:

Given that the water flows at speed v in a pipe of radius r.

Let \(v_2\) is the speed of water flow where the radius of the pipe is r/3.

By using the continuity equation, the mass flow rate of water is the same at all the cross-sections of the pipe, wh have

\(\rho_1A_1_v_1 =\rho_2A_2_v_2\)

Where \(\rho_1, A_1\) and \(v_1\) are the density, area of the cross-section and speed at cross-section 1 and  \(\rho_2, A_2\) and \(v_2\) are the density, area of the cross-section and speed at cross-section 2.

As the density of the water remains constant. so \(\rho_1=\rho_2\).

\(\Rightarrow A_1_v_1 =A_2_v_2 \\\\\Rightarrow (\pi r^2)v=(\pi (r/3)^2v_2 \\\\\Rightarrow r^2v=\frac {r^2}{9}\times v_2 \\\\\Rightarrow v= \frac {v_2}{9} \\\\\Rightarrow v_2=9v.\)

Hence, the speed of the water flow where the radius is r/3 is \(9v\).

Dimensional Analysis
9.52 x 104 m to um

Answers

the calculated answer in micrometer is 9.52 x 10⁻²

Dimensional analysis is the analysis of the relationships between different physical quantities by identifying their base quantities (such as length, mass, time, and electric current) and units of measure (such as miles vs. kilometers, or pounds vs. kilograms) and tracking these dimensions as calculations or comparisons are performed. The conversion of units from one dimensional unit to another is often easier within the metric or SI system than in others, due to the regular 10-base in all units.

9.52x 10⁴

1 m= 10⁶ μm

dimensional analysis = 9.52 x 10⁴ x 10⁻⁶

                                   =9.52 x 10⁻² μm

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1 If electromagnetic radiation acted like particles in the double-slit experiment, what would be observed?

a The screen would remain dark because no radiation would reach the screen.
b One bright band would appear in the center of the screen.
c A series of light and dark bands would appear on the screen.
d Two bright bands would appear on the screen in line with the slits.

2 Which statement about the interference behavior of electromagnetic radiation seen in the double-slit test experiment is true?

a Waves that make up the radiation collide with each other so that they add together or cancel each other out.
b Particles that make up the radiation collide with each other and scatter randomly.
c Particles that make up the radiation collide with each other so that they add together or cancel each other out.
d Waves that make up the radiation do not interact with each other.

3 Which statement about the observed results of the double-slit experiment is true?

a Waves that are out of phase constructively interfere to create bright bands.
b Waves that are in phase destructively interfere to create bright bands.
c Waves that are out of phase constructively interfere to create bright bands.
d Waves that are in phase constructively interfere to create bright bands.

4 Which statement about the observed results of the double-slit experiment is true?

a Waves that are in phase constructively interfere to form dark bands.
b Waves that are out of phase constructively interfere to form dark bands.
c Waves that are in phase destructively interfere to form dark bands.
d Waves that are out of phase destructively interfere to form dark bands.

5 A scientist decreases the wavelength of the light used in a double-slit experiment and keeps every other aspect the same. What will be true about the new interference pattern seen on the screen compared to the original interference pattern?

a The spacing between the dark fringes will increase.
b The spacing between the bright fringes will increase.
c The spacing between the bright fringes will decrease.
d The spacing between the dark fringes will remain the same.

6 Consider the two-slit interference experiment. Electromagnetic radiation passes through the two slits that are a distance of 0.0170 nm apart. A fourth-order bright fringe forms at an angle of 8.0 degrees relative to the incident beam. What is the wavelength of the light?

a 789 nm
b 420 nm
c 581 nm
d 591 nm

Answers

Answer:

1. Two bright bands would appear on the screen in line with the slits.

2. Waves that make up the radiation collide with each other so that they add together or cancel each other out.

3. Waves that are in phase constructively interfere to create bright bands.

4. Waves that are out of phase destructively interfere to form dark bands.

5. The spacing between the bright fringes will decrease.

6. 581 nm

Explanation:

Before a collision, a 25 kg object is moving at 12 m/s to the right. After a collision with stationary box, the 25 kg object moves at 8 m/s to the right. What is the resulting momentum of the box?

Answers

The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.

Question 4 of 10
Which of the following describes the reactants of a chemical reaction?
OA. The chemicals on the right side of a chemical equation
B. The substances that are formed
OC. The substances that are made
O D. The chemicals on the left side of a chemical equation

Answers

The substances that are altered and the chemicals on the right side of a chemical equation are the results of a chemical reaction. B and D are the appropriate choices.

Reactants are the substance(s) in a chemical equation to the left of the arrow. A component that is present at the outset of a chemical reaction is known as a reactant. Products are the substance(s) to the right of the arrow. A substance that remains after a chemical reaction is complete is known as a product. The creation of products from the reaction of two reactants is known as a chemical reaction. The compounds that result from a reaction are called products. The substances that are original materials are the reactants.

On the left side of the reaction are the reactants, and on the right are the products. B and D are the proper choices as a result.

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A physics student was studying falling bodies and decided to drop a water balloon from an outdoor stairwell to measure its speed. If the balloon was dropped a distance of 6 meters and it only took 1.1 seconds to fall, how fast was the balloon traveling on average? A. 0.2 m/s B. 6.6 m/s C. 5.5 m/s D. 66 m/s

WILL NAME BRAINLIEST

Answers

Answer:

C. 5.5 m/s

Explanation:

How fast the balloon travels is determined from the velocity or v

The formula is v = s/t or velocity equals distance divided by time

So, v = 6 meters divided by 1.1 seconds = 5.5 meters per second

Answer:

C. 5.5 m/s

Explanation:

How fast the balloon travels is determined from the velocity or v

The formula is v = s/t or velocity equals distance divided by time

So, v = 6 meters divided by 1.1 seconds = 5.5 meters per second

The force of static friction is

Answers

Static friction is the frictional force that opposes the motion of stationary objects when an external force is acting upon them. It is the force of friction that prevents an object from sliding or moving when a force is applied to it. Static friction is different from kinetic friction, which is the force of friction between two objects that are in motion relative to each other.

The force of static friction depends on two factors: the normal force acting on the object and the coefficient of static friction between the object and the surface it is in contact with. The normal force is the perpendicular force that acts on an object in contact with a surface, such as the force of a book resting on a table.

The coefficient of static friction is a dimensionless quantity that represents the frictional force between two objects in contact with each other. It is dependent on the materials of the objects in contact with each other and is always greater than or equal to the coefficient of kinetic friction.

Static friction is an important force in many areas of physics and engineering. It plays a role in the design of machines, the movement of vehicles, and the behavior of materials under different conditions. Understanding static friction is crucial for engineers and scientists to design efficient and effective systems and structures.

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The kinetic energy
as the roller coaster goes downhil

Answers

Answer:

Increases

Explanation:

The kinetic energy _____ (Increses)

as the roller coaster goes downhill

your answer is A, the kinetic energy increases. :))

a
Why do you need a reference
point to determine if an object
has moved?
A. The object will stop moving if you don't
compare it.
B. The object could run into another object.
C. Motion is a change in position relative to a
fixed point.

Answers

Answer:

An object is in motion when its distance from another object is changing. A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point.

option C is your CORRECT answer

Explain the light detection technique of photovoltaic detection​

Answers

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

Learn more about Photovoltaic detection

The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?

Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.

Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!

Answers

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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(round to 3 significant figures pls) A block of iron at 415 degrees C is put into a 0.625 kg tub of water at 15.0 degrees C. They come to equilibrium at 100 degrees C, and 0.144 kg of the water boils off to steam. What was the mass of the iron block?​

(round to 3 significant figures pls) A block of iron at 415 degrees C is put into a 0.625 kg tub of water

Answers

Temperature of iron (Ti) = 415 °C Temperature of water (Tw) = 15.0 °CTemperature at equilibrium (Te) = 100 °CMass of water (m) = 0.625 kgMass of steam evaporated (ms) = 0.144 kgHeat lost by iron (Q1) = Heat gained by water (Q2) + Heat required to evaporate steam .

Heat lost by iron  = (mass of iron (m) x specific heat capacity of iron (c) x change in temperature of iron (ΔT1))Heat gained by water = (mass of water (m) x specific heat capacity of water (c) x change in temperature of water (ΔT2))Heat required to evaporate steam  = (mass of steam (ms) x specific latent heat of vaporization of water (L))Now, using the above formula we can calculate the mass of the iron block as:

Q3m x c x ΔT1 = m x c x ΔT2 + ms x L

Let's calculate the value of Q1 first.

Q1 = m x c x ΔT1m = Q1 / (c x ΔT1)

We know that

c = 450 J/kg °C and ΔT1 = Ti - Te = 415 - 100 = 315°CQ1 = m x c x ΔT1= m x 450 J/kg

°C x 315°C= 141750 m Jm = Q1 / (c x ΔT1)= 141750 / (450 x 315)= 1.002 kg

Now, let's calculate the value of Q3.Q3 = ms x L= 0.144 kg x 2.26 x 10^6 J/kg= 325440 J

Now, let's calculate the value of Q2

.Q2 = m x c x ΔT2m = (Q2 + Q3) / (c x ΔT2)

We know that ΔT2 = Te - Tw = 100 - 15 = 85°CQ2 = m x c x ΔT2= 0.625 kg x 4186 J/kg °C x 85°C= 276981.25 JNow, let's calculate the mass of the iron block.m =

(Q2 + Q3) / (c x ΔT2)= (276981.25 + 325440) / (450 x 85)= 1.003 kg

Hence, the mass of the iron block is 1.003 kg rounded off to 3 significant figures.

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