Based on the given heating curve, the boiling point of the substance is 75°C. Thus, the correct option is D.
A heating curve depicts the changes that occur in the physical state of matter with temperature as a result of absorbing the increasing amount of heat. The plateaus in the curve indicate phase transitions of the substance.
A heating curve depicting such phase transitions is shown in the image attached below.
In this case, the heating curve of the substance depicts the following:
A - solid phase
B - melting transition of solid into liquid
C- liquid phase
D- boiling transition of liquid into gas
E- gas phase
The transitional phases are depicted by the two plateau regions B and D. B depicts the melting point and D depicts the boiling point.
Thus, the correct answer is 75°C that is option D.
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The oxygen used for preheating and the fuel gas are combined in the ____ chamber before burning.
Answer:
Mixing chamber
Are all the wax rings melting at the same time?
Answer:yes
Explanation:
this is because the distance doesnt matter
Most of the weather of the world is based upon changes in the moisture, pressure, and/or temperature of the.
Most of the weather of the world is based upon changes in the moisture, pressure or temperature of the troposphere.
What is the importance of troposphere?The layer closest to the surface of the Earth is troposphere. This layer goes up to twenty kilometers above the Earth. The troposphere is very essential as it contains the weather of the Earth and also greenhouse gases to maintain the temperature on Earth.
Troposphere layer has the air humans breathe and the clouds in the sky. The air is densest in this lowest layer and the troposphere has three-quarters of the mass of the entire atmosphere. The air in troposphere is 78% nitrogen and 21% oxygen.
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In which method should starch indicator not be added until right before the endpoint?
The method in which starch indicator should not be added until right before the endpoint is the iodometric titration method.
In the iodometric titration method, iodine (I2) is generated as one of the products during the titration. The reaction involves the oxidation of iodide ions (I-) by an oxidizing agent. Starch is commonly used as an indicator in iodometric titrations to detect the endpoint, which is indicated by the formation of a blue-black starch-iodine complex.
Starch indicator should not be added too early in the titration because it can react with the iodine that is being generated, leading to inaccurate results. The presence of starch can cause premature color change, making it difficult to determine the actual endpoint of the titration.
Therefore, to ensure accurate results, starch indicator is added near the endpoint of the titration when the solution is nearly decolorized, indicating that the reaction between the analyte and the oxidizing agent is nearly complete.
Adding starch indicator at this stage allows for precise detection of the endpoint, providing more reliable and accurate titration results.
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Since the density of air is less than the density of water what will happen to the air if you take a jar of air under water and
open it?
Answer:
the air will escape from the jar
Explanation:
Due to its low density air in the jar will be displaced and be replaced by water.
it is desired to inflate a baggie with a volume of 836 milliliters by filling it with nitrogen gas at a pressure of 1.05 atm and a temperature of 301 k. how many grams of n2 gas are needed
To inflate the baggie with a volume of 836 milliliters using nitrogen gas at a pressure of 1.05 atm and a temperature of 301 K, we can apply the ideal gas law. Using the equation PV = nRT and rearranging it to solve for the number of moles (n), we find that n = PV / RT, which yields approximately 0.08757 moles of nitrogen gas. By multiplying this value by the molar mass of nitrogen (28.02 g/mol for N₂), we can determine the mass of nitrogen gas needed, which comes out to be approximately 2.453 grams. Thus, around 2.453 grams of nitrogen gas are required to inflate the baggie to the desired volume.
To determine the mass of nitrogen gas needed to inflate the baggie, we can use the ideal gas law equation:
PV = nRT
Where:
P = Pressure = 1.05 atm
V = Volume = 836 mL = 0.836 L (converted from milliliters to liters)
n = Number of moles of gas (what we want to find)
R = Ideal gas constant = 0.0821 L·atm/(mol·K)
T = Temperature = 301 K
Rearranging the equation, we can solve for the number of moles (n):
n = PV / RT
n = (1.05 atm * 0.836 L) / (0.0821 L·atm/(mol·K) * 301 K)
n = 0.08757 mol (rounded to 5 decimal places)
Now, we can calculate the mass of nitrogen gas using the molar mass of nitrogen (N₂):
Molar mass of N₂ = 2 * atomic mass of nitrogen (N)
Atomic mass of N = 14.01 g/mol
Molar mass of N₂ = 2 * 14.01 g/mol
Molar mass of N₂ = 28.02 g/mol
Finally, we can calculate the mass of nitrogen gas (m) using the number of moles (n) and the molar mass (M):
m = n * M
m = 0.08757 mol * 28.02 g/mol
m = 2.453 g (rounded to 3 decimal places)
Therefore, approximately 2.453 grams of nitrogen gas are needed to inflate the baggie.
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When 0.0030mol of HCL is added to 100ml of a 0.10M solution of a weak base, R2NH, the solution has a ph of 11.10. What is Kb for the weak base?
Therefore, Kb for the weak base solution R2NH is 4.5 x \(10^{-10.\)
Use the Henderson-Hasselbalch equation, which relates the pH of a buffer solution to the pKa of the weak acid and the ratio of the concentrations of the weak acid and its conjugate base.
First, we need to determine the concentration of the weak base, R2NH, before the addition of HCl. We can use the equation:
Kb = Kw / Ka
here Kw is the ion product constant of water (1.0 x 10^-14) and Ka is the acid dissociation constant of the conjugate acid of the weak base. Since the weak base is unknown, we need to use the given pH to calculate the pKa and then use that to find Ka.
pH = pKa + log([A-]/[HA])
where [A-] is the concentration of the conjugate base (R2N-) and [HA] is the concentration of the weak acid (R2NH).
We can rearrange this equation to solve for pKa:
pKa = pH - log([A-]/[HA])
Substituting the given values, we get:
11.10 = pKa + log([R2N-]/[R2NH])
We can then solve for pKa:
pKa = 11.10 - log([R2N-]/[R2NH])
Now that we know the pKa, we can find Ka:
Next, we need to determine the concentration of the weak base after the addition of HCl. We can use the equation:
moles of HCl = moles of R2NH
0.0030 mol HCl = (100/1000) L x (0.10 mol R2NH/L - [R2NH])
Solving for [R2NH], we get:
[R2NH] = 0.099 - (0.0030/0.1) = 0.069 M
Finally, we can use the equation for Kb:
Kb = Kw / Ka = \(1.0 * 10^{-14} / (2.2 * 10^{-5)\)
= 4.5 x \(10^{-10.\)
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A student was asked to find the density of an unknown object. The student found that the mass of the object was 35.49 g. The student used water displacement to find the volume of the object. The graduated cylinder originally contained 45.1 mL of water. After the object was placed in the graduated cylinder, the volume was 52.3 mL. What is the density of the unknown object? Remember to round your answer to the correct number of significant figures and include the correct units. (Note: 1 mL = 1 cm3)
Answer:
4.29 /mL
Explanation:
density= mass/volume
The density of the unknown object is 4.929 centimeter cube ( cm³ ).
What is density?Density is the mass of an object in the per unit volume of liquid and can be calculated by dividing the mass of an object to the volume of the object and the unit of density is centimeter cube.
Here, mass of object is 35.49 g and the water displacement to find the volume is 52.3 mL- 45.1 mL = 7.2 ml.
Density = mass of object / volume of object
Substituting the value in formula,
density = 35.49 / 7.2
Density = 4.929 centimeter cube ( cm³ )
Therefore, 4.929 centimeter cube ( cm³ ) is the density of a given object.
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Can you show me the answer and explain?
Answer:
C
Explanation:
looking at a periodic table X is fluorine and Y is potassium
Fluorine is in group 7 and forms a 1- charge (which gains electrons) and potassium is in group 1 and forms a 1+ charge (which loses electrons)
Fluorine (X) has an electronic structure of 2,7 and needs to gain an electron from Potassium (Y) to have a full outer shell and potassium has an electronic structure of 2,8,8,1 so needs to lose an electron to have a full outer shell as well. This means that the electron that potassium (Y) has lost is given away to fluorine (X), so both elements become stable.
This is known as ionic bonding where metals (like potassium) lose electrons and non-metals (like fluorine) gain electrons to become more stable, forming ions
Any further clarification let me know
What are the functions of the sori found on the leaves? Pls list like three.
Sori are specialized structures found on the leaves of ferns and some other plants. They serve several important functions, including spore production, dispersal, and reproduction.
Spore Production: Sori are responsible for the production and release of spores. Spores are reproductive structures that can develop into new individuals. Within the sori, sporangia (spore-bearing structures) produce and store spores until they are ready for dispersal.
Dispersal: Sori aid in the dispersal of spores. Once the spores are mature, the sporangia rupture or open, releasing the spores into the environment. The spores are lightweight and can be carried by wind, water, or other means to new locations where they can germinate and grow into new fern plants.
Reproduction: Sori play a vital role in the reproduction of ferns. The spores released from the sori can germinate under favorable conditions to produce a gametophyte stage, which eventually develops into a new fern plant. Ferns ensure the efficient production and dispersal of spores, facilitating the fern's reproductive cycle.
Overall, the functions of sori on the leaves of ferns include spore production, dispersal, and reproduction, contributing to the survival and proliferation of fern populations.
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it was determined by spectrophotometry that the moles of fescn2 present at equilibrium was 2.00 x 10-4 moles (2.00 times 10 to the minus 4th power moles). if the sample was prepared using 4.00 x 10-3 moles (4.00 times 10 to the minus 3rd power moles) of fe3 , how many moles of fe3 were present at equilibrium? question 2 options: 4.2 x 10-3 moles (4.2 times 10 to the minus 3rd power moles) 3.8 x 10-3 moles (3.8 times 10 to the minus 3rd power moles) 3.8 x 10-4 moles (3.8 times 10 to the minus 4th power moles) 2.00 x 10-3 moles (2.00 times 10 to the minus 3rd power moles) 4.00 x 10-3 moles (4.00 times 10 to the minus 3rd power moles) 4.2 x 10-4 moles (4.2 times 10 to the minus 4th power moles) 4.00 x 10-4 moles (4.00 times 10 to the minus 4th power moles)
The moles of Fe³⁺ present at equilibrium is 3.8 × 10⁻³ moles and the correct option is option 2.
What is Chemical equilibrium?
Chemical equilibrium is the state of a system in which the rate of the forward reaction is equal to the rate of the reverse reaction.
Chemical equilibrium is a dynamic process. The forward and reverse reactions continue to occur even after equilibrium has been reached. However, because the rates of the reactions are the same, there is no change in the relative concentrations of reactants and products for a reaction that is at equilibrium.
Given,
The reaction of [Fe(SCN)]²⁺ :
Fe³⁺ + SCN⁻ ⇆ [Fe(SCN)]²⁺
The initial number of moles of Fe³⁺ = 4 × 10⁻³
Number of moles of [Fe(SCN)]²⁺ at equilibrium = 2 × 10⁻⁴
Number of moles of Fe³⁺ at equilibrium =
(initial number of moles of Fe³⁺ - moles of [Fe(SCN)]²⁺ at equilibrium)
= ( 4 × 10⁻³ - 2 × 10⁻⁴)
= 3.8 × 10⁻³ moles
Therefore, the number of moles of Fe³⁺ of at equilibrium is 3.8 × 10⁻³ moles.
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which of the following is not true of an atom that has an atomic number of 19 and a mass number of 41? group of answer choices the atom contains 22 neutrons. the atom is potassium. the atom contains 19 neutrons. the atom contains 19 electrons. the atom contains 19 protons.
The atom contains 19 neutrons is not true of an atom that has an atomic number of 19 and a mass number of 41.
Atomic Composition of Potassium-41
An atom with an atomic number of 19 and a mass number of 41 refers to the element potassium. The atomic number of an element refers to the number of protons in the nucleus of an atom, and in the case of potassium, it has 19 protons. The mass number of an atom refers to the sum of the number of protons and neutrons in its nucleus, and in the case of potassium-41, it has 41 - 19 = 22 neutrons.
It is not true that the atom contains 19 neutrons, but 22 neutrons instead. The number of electrons in an atom is equal to its atomic number, meaning that potassium-41 contains 19 electrons. This information allows us to conclude that potassium-41 has a stable atomic structure with 19 protons, 19 electrons, and 22 neutrons.
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does your product contain newly created alkenes? if so, should they be e or z? for Adol condensation
The Adol condensation reaction may form a product with a newly created alkene, which can exist as either E or Z isomers, depending on the stereochemistry of the starting materials used in the reaction.
What is the configuration of newly created alkenes in the Adol condensation reaction?
In the Adol condensation reaction, the reactants are an aldehyde or ketone and a carbonyl compound (aldehyde or ketone). The reaction results in the formation of a β-hydroxyketone or aldehyde. The product may contain an alkene depending on the reaction conditions and the reactants used.
If the product contains a newly created alkene, the configuration of the double bond would depend on the stereochemistry of the starting materials. If the carbonyl compounds used in the reaction have different substituents on the carbonyl carbon, the resulting alkene can exist as either E or Z isomers, depending on the relative orientation of the substituents on either side of the double bond.
The stereochemistry of the product can be predicted using Zaitsev's rule, which states that the more substituted alkene is formed as the major product. However, the stereochemistry of the alkene in the product can also be influenced by factors such as steric hindrance and the reaction conditions used.
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what two events are part of the rock cycle
Answer:
i dont answer this question only explain
Explanation:
Several processes can turn one type of rock into another type of rock. The key processes of the rock cycle are crystallization, erosion and sedimentation, and metamorphis
What is the heat of combustion of ethane, c2h6, in kilojoules per mole of ethane?.
Combustion is the process in which CO₂ is react with reactant. Heat of combustion of ethane is 1560 kilo joule per mole.
What is combustion ?Combustion is the process in which oxygen is react to form heat or energy. There are three types of combustion as follows
spontaneous combustion
rapid combustion
explosive combustion
Combustion is a chemical reaction between substances, mostly including oxygen and usually followed by the generation of heat and light in the form of flame.
Combustion is the other word for burning. In a combustion reaction, a fuel is heated and it reacts with oxygen and their is energy released.. The fire triangle require the three things for combustion - a fuel, heat and oxygen.
Thus, combustion of ethane gives 1560 kilo per joule energy.
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BRAINLIEST !!! HELP PLZ
Answer:
Hcl Answer
Explanation:
may be this helpful!
A backdraft explosion can occur when
- There is a lack of fuel in a partially-burned room
- There is a lack of oxygen in a partially-burned room
- A door is opened into a room instead of opening into a hallway or outside
- A fire is very smoky
A backdraft explosion can occur when there is a lack of oxygen in a partially-burned room. This situation can be exacerbated if a door is opened into the room, introducing a sudden supply of oxygen, which then leads to a rapid combustion of the remaining fuel, causing the explosion. A fire being very smoky may also indicate a lack of oxygen, increasing the risk of a backdraft explosion.
A backdraft explosion can occur under certain conditions such as when there is a lack of fuel in a partially-burned room or a lack of oxygen in a partially-burned room. Additionally, if a door is opened into a room instead of opening into a hallway or outside, it can create a draft that can lead to a backdraft explosion. Furthermore, a fire that is very smoky can also lead to a backdraft explosion as the smoke can build up and ignite when oxygen is suddenly introduced. It is important to be aware of these potential dangers and to take necessary precautions to prevent a backdraft explosion from occurring.
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The enthalpy of vaporization of Subtance X i 17. 0kJmol and it normal boiling point i 90. °C. Calculate the vapor preure of X at −92. °C. Round your anwer to 2 ignificant digit
At −92°C, the vapour pressure of the substance X is 5.5 atm
According to Clausius Clapeyron equation,
ln (P₂/P₁) = -ΔHvap /R (1/T₂ - 1/T₁) -------> (i)
Here,
P₁ = 1 atm
T₁ = 90°C = (90 +273)K = 363K
T₂= -92°C = (-92+ 273)K = 181 K
ΔHvap = 17 KJ/mol
R = 8.314 J/K/mol
To find: P₂
Substituting the above given values in equation (i) we get,
ln (P₂/P₁) = -ΔHvap /R (1/T₂ - 1/T₁)
ln(P₂/ 1 atm)= -17 KJmol⁻¹ / 8.314 JK⁻¹mol⁻¹ ( 1/181K -1/363K)
ln P₂ = -17 KJmol⁻¹ / 0.008314 KJK⁻¹mol⁻¹ ( 0.0028K)
2.303 log (P₂) = - 730240.55 atm
log (P₂) = - 730240.55 atm/ 2.303
log (P₂) = -317082.306 atm
P₂ = antilog (-317082.306)
P₂ = 5.5 atm (upto two significant figures)
Thus, the vapour pressure of X at −92°C is 5.5 atm.
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Which of the following best describes an ethogram?
1) a graphical way to display the behaviour of an animal
2) a description of the behaviour performed by an animal at one point in time
3) an inventory of the behaviour of a particular species
4) the behaviour observed in response to an experimental intervention
Option 3 accurately represents the essence of an ethogram as an inventory of species-specific behaviors.
An ethogram can be best described as an inventory of the behavior of a particular species. It is a systematic catalog or list of behaviors exhibited by a specific animal species.
An ethogram provides a comprehensive overview of the behaviors displayed by the animals under study, documenting various activities, actions, and patterns of behavior.
While options 1 and 2 are related to visual representations or descriptions of behavior, they do not capture the comprehensive nature of an ethogram. Option 4 refers specifically to behaviors observed in response to an experimental intervention, which is more narrow in scope compared to an ethogram. Therefore, option 3 accurately represents the essence of an ethogram as an inventory of species-specific behaviors.
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How many grams of barium sulfate can be produced from 150.0 mL of0.35 M sodium sulfate and 90 mL of 0.90 M barium nitrate according to the reaction below: Na2SO4 Ba(NO3)2 BaSO4 (s) 2NaNO3 2. (1 point) Calculate the enthalpy change when 1.0 g of methane is burned in excess oxygen according to the reaction below: CHa(g) 202 (g) 7CO2 (g) HzO() AH--891kJlmol
To answer both questions, we need to use stoichiometry and the given reaction equations to calculate the desired quantities.
We can see that one mole of sodium sulfate (Na2SO4) reacts with one mole of barium nitrate (Ba(NO3)2) to produce one mole of barium sulfate (BaSO4).First, we calculate the moles of sodium sulfate (Na2SO4) and barium nitrate (Ba(NO3)2) in the given volumes Next, we determine the limiting reactant. The reactant that produces the least amount of the product (barium sulfate) will be the limiting reactant.From the balanced equation, we can see that the stoichiometric ratio between Na2SO4 and BaSO4 is 1:1. Therefore, the moles of barium sulfate produced will be equal to the moles of the limiting reactant.Now, let's compare the moles of Na2SO4 and Ba(NO3)2 to identify the limiting reactant.
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Be + O2 --> BeO
Balance this and what's the type of reaction?
Answer:
2Be + O2 = 2BeO
its a synthesis
Explanation:
A medical researcher finds a high incidence of covalent bonds between thymine and other nucleotides in the dna of skin cells of a patient. The most likely cause is.
The reason for the high covalent bonding is exposure to UV radiation
What is thymine?We know that DNA is the deox ribo nucleic acid. This is the unit of inhertiance that is contained in the genes. The ways that the amino acids in the DNA are coded is what passes genetic information on in the cells of living organisms.
This DNA is composed of some bases and the bases that do make up the DNA are also composed of nucleobases. One of the nucleobases that we can find in the DNA molecule is the thymine which is quite common in the DNA.
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Missing parts;
A medical researcher finds a high incidence of covalent bonds between thymine and other nucleotides in the DNA of skin cells of a patient. The most likely cause is O A exposure to cigarette smoke B a defective DNA polymerase nitrous oxide exposure exposure to UV radiation O E unknown as these bonds likely formed spontaneously
The ionic salt kbr is dissolved in water, much like the experiments given in the simulation. A mass of 91.0 g of salt is added to 100. g of water. Both start at a temperature of 23.0°C. AHol for KBr is 8.00 kJ/mol. Given this information calculate the final temperature (TO) Express your answer to three significant figures. View Available Hints)
The final temperature of the solution from the calculation is 37°C.
What is the molar enthalpy of solution?The molar enthalpy of solution depends on various factors such as the nature of the solute and solvent, the concentration of the solute, and the temperature and pressure at which the dissolution occurs. It can be determined experimentally using calorimetry techniques or estimated based on thermodynamic data.
We know that;
Number of moles of salt = 91.0 g/119 g/mol
= 0.76 moles
Heat of by water = 8.00 kJ/mol * 0.76 moles
= 6.08 kJ or 6080 J
H = mcdT
6080 = 100 * 4.2 * (T2 - 23)
6080 = 420T2 - 9660
6080 + 9660 = 420T2
T2 = 37°C
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Which of the following chemical reactions will produce a precipitate?
Answer:
naclo4+koh naoh+kclo4
Explanation:
if you know your cemestry
Answer:
it's A
Explanation:
A container has an unknown quantity of gas at a pressure of 121.6kPa, a volume of 31L and a temperature of 87oC. How many moles of gas are present ?
Answer:
1.26mol
Explanation:
Using the general gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K).
Based on the information provided in this question,
P = 121.6kPa = 121.6 × 0.00987atm = 1.2001 atm
V = 31L
T = 87°C = 87 + 273 = 360K
R = 0.0821 Latm/molK
Using PV = nRT
n = PV/RT
n = (1.2001 × 31) ÷ (0.0821 × 360)
n = 37.2031 ÷ 29.556
n = 1.258
n = 1.26mol
DISCUSSION QUESTIONS:
1) Distinguish how P-waves and S-waves travel differently with illustrations and
labels.
2) What type of seismic wave will reach a recording station 500 miles away from the epicenter first
Answer:
P-waves compression waves while S-waves are shear waves.
Explanation:
P- waves has the ability to travels through solid, liquid and gaseous medium while S-waves travels through only solid medium and restricted by liquid and gaseous medium. P-waves is a type of seismic wave that will reach first to the recording station as compared to S-waves because P-waves moves faster that S-waves that moves slower so that's why P-waves reach first on the recording station that is located 500 miles away.
Which of the following compounds has a C-H bond with the lowest bond dissociation energy?
A) C2H6
B) C6H6
C) C2H2
D) CH3CH=CH2
C₂H₆, compound has a C-H bond with the lowest bond dissociation energy, hence option A is correct.
Toluene has the lowest bond dissociation energy because it undergoes hyper conjugation with the C-H protons.
The energy needed to break a bond and create two atomic or molecular fragments, each containing one of the original shared pair of electrons, is known as the bond dissociation energy.
As a result, an extremely stable bond has a high bond dissociation energy, meaning additional energy is required to break the binding.
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When Mg bonds with S, which of the following is true?a. Mg and S are in a "sea of electrons."b.Mg and S share two electrons.c. Mg gains two electrons, while S loses two electrons.d. Mg loses two electrons, while S gains two electrons.
Answer: Magnesium loses two electrons whilst sulfur gains tw
What is the correct order of processes in the accretion of planetesimals?
Masses of matter form around dust grain, masses of matter collide, and atoms and molecules are added to dust grain.
Masses of matter collide, masses of matter form around dust grain, and atoms and molecules are added to dust grain.
Atoms and molecules are added to dust grain, masses of matter form around dust grain, and masses of matter collide.
Masses of matter collide, atoms and molecules are added to dust grain, and masses of matter form around dust grain.
Answer:
Atoms and molecules are added to dust grain, masses of matter form around dust grain, and masses of matter collide.
Explanation:
Planetesimals are the foundation or fundamentals of planet formation. The mode of the formation is called accretion. In this process, dust grains or particles mixes with atoms and molecules to form a massive mass which later coalesce or collide to form planets.
The size of the planet formed is determined by the amount of masses of matter that collide.
Answer:
c
Explanation:
What would be the final temperature when 100 g of 25 degree Celsius water is mixed with 75 g of 40 degree Celsius water?
The final temperature when 100 g of 25°C water is mixed with 75 g of 40°C water is 31.4°C.
To calculate the final temperature when 100 g of 25°C water is mixed with 75 g of 40°C water, we can use the principle of heat exchange. This principle is also known as the law of thermal equilibrium. It is represented by the formula:
Q = m × c × ΔT
where Q is the amount of heat transferred, m is the mass of the object, c is the specific heat capacity of the material, and ΔT is the change in temperature.
Using the above formula, we can find the final temperature when 100 g of 25°C water is mixed with 75 g of 40°C water as follows:
The heat lost by 75 g of water at 40°C is:
Q1 = m1 × c1 × ΔT1 = 75 g × 1 cal/g°C × (40°C - T f)
where T f is the final temperature of the mixture.
The heat gained by 100 g of water at 25°C is:
Q2 = m2 × c2 × ΔT2 = 100 g × 1 cal/g°C × (T f - 25°C)
Since Q1 = Q2 (heat lost = heat gained), we can equate the two equations above and solve for T f as follows:
75 g × 1 cal/g°C × (40°C - T f) = 100 g × 1 cal/g°C × (T f - 25°C)
Simplifying the above equation, we get:
3000 - 75T f = 100T f - 2500
175T f = 5500
T f = 31.4°C
Therefore, the final temperature when 100 g of 25°C water is mixed with 75 g of 40°C water is 31.4°C.
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